{"schema_version":"ocme-site-results-v1","locale":"zh-Hant","page_type":"derivations","facts":{"questions":36000,"reviewed":36000,"display_candidates":0,"knowledge":302,"guides":299,"paths":59,"batches":360,"families":1441,"atlas":302,"core":80,"evidence":9,"formal_evidence":5,"formal_subjects":4,"lean_files":6,"lean_toolchain":"leanprover/lean4:v4.30.0","question_state":"candidate","english_state":"ai_candidate","question_Lean":"NOT_RUN","canonical_truth_promotion":false},"filters":{"q":"mko-euclid-pythagorean-theorem"},"kind":"guides","total":1,"pages":1,"page":1,"entries":[{"id":"derivation-mko-euclid-pythagorean-theorem-01","title":{"zh-Hant":"畢達哥拉斯定理：在座標模型中以內積證明","en":"Pythagorean theorem: a proof by dot products in the coordinate model"},"summary":{"zh-Hant":"在以 ℝ² 表示的歐幾里得平面中（距離為歐幾里得長度），證明：對任何直角三角形 ABC，若直角在 C，兩股長 a=d(C,B)、b=d(C,A)，斜邊長 c=d(B,A)，則 a²+b²=c²。再以 C=(1,2)、B=(4,6)、A=(−7,8) 驗算（25+100=125），並以非直角三角形 E=(0,0)、F=(4,0)、H=(1,2) 說明沒有直角時關係一般不成立。","en":"In the Euclidean plane represented by ℝ² (with Euclidean length as distance), prove: for every right triangle ABC with the right angle at C, legs of lengths a=d(C,B) and b=d(C,A), and hypotenuse of length c=d(B,A), a²+b²=c². Then check the example C=(1,2), B=(4,6), A=(−7,8) (25+100=125), and use the non-right triangle E=(0,0), F=(4,0), H=(1,2) to show that without a right angle the relation fails in general."},"mko_ids":["mko-euclid-pythagorean-theorem"]}],"title":"概念推導導讀"}