{"schema_version":"ocme-site-results-v1","locale":"zh-Hant","page_type":"derivations","facts":{"questions":36000,"reviewed":36000,"display_candidates":0,"knowledge":302,"guides":299,"paths":59,"batches":360,"families":1441,"atlas":302,"core":80,"evidence":9,"formal_evidence":5,"formal_subjects":4,"lean_files":6,"lean_toolchain":"leanprover/lean4:v4.30.0","question_state":"candidate","english_state":"ai_candidate","question_Lean":"NOT_RUN","canonical_truth_promotion":false},"filters":{"q":"mko-finite-convex-combination"},"kind":"guides","total":1,"pages":1,"page":1,"entries":[{"id":"derivation-mko-finite-convex-combination-01","title":{"zh-Hant":"有限凸組合：以精確權重核對見證，並區分負權重、近似權重與唯一性","en":"Finite convex combination: checking a witness with exact weights, and separating negative weights, approximate weights and uniqueness"},"summary":{"zh-Hant":"在 ℝ² 中令 v_1=(0,0)、v_2=(6,0)、v_3=(0,6)。(1) 核對 λ=(1/6,1/3,1/2) 是凸權重並重建 w=(2,3)；(2) 說明零權重允許、兩點凸組合是線段點；(3) 證明 u=(4,4) 不是 v_1、v_2、v_3 的凸組合（唯一的仿射權重含 −1/3），並以線性泛函上界給第二個證明；(4) 說明 0.333 三個權重不合格；(5) 加入 v_4=(3,3) 後，同一點有兩組不同的凸權重。","en":"In ℝ² let v_1=(0,0), v_2=(6,0), v_3=(0,6). (1) Check that λ=(1/6,1/3,1/2) are convex weights and reconstruct w=(2,3); (2) show that zero weights are allowed and that two-point convex combinations are segment points; (3) prove that u=(4,4) is not a convex combination of v_1, v_2, v_3 (its only affine weights include −1/3), with a second proof by a linear-functional bound; (4) show that three weights of 0.333 do not qualify; (5) after adding v_4=(3,3), exhibit two different convex weight vectors for the same point."},"mko_ids":["mko-finite-convex-combination"]}],"title":"概念推導導讀"}