{"schema_version":"ocme-site-results-v1","locale":"zh-Hant","page_type":"derivations","facts":{"questions":36000,"reviewed":36000,"display_candidates":0,"knowledge":302,"guides":299,"paths":59,"batches":360,"families":1441,"atlas":302,"core":80,"evidence":9,"formal_evidence":5,"formal_subjects":4,"lean_files":6,"lean_toolchain":"leanprover/lean4:v4.30.0","question_state":"candidate","english_state":"ai_candidate","question_Lean":"NOT_RUN","canonical_truth_promotion":false},"filters":{"q":"mko-integer"},"kind":"guides","total":1,"pages":1,"page":1,"entries":[{"id":"derivation-mko-integer-01","title":{"zh-Hant":"整數：判定成員、負號的意義與對負號的封閉性","en":"Integer: deciding membership, the meaning of the minus sign, and closure under negation"},"summary":{"zh-Hant":"在實數中，取 Z={0}∪N⁺∪{−n ∣ n∈N⁺}（N 依 OCME 慣例含 0，N⁺=N∖{0}，−n 是 n 的加法反元素）。證明 −7∈Z；說明十進位符號「3.0」表示整數 3；證明 −2.5∉Z；由加法反元素的唯一性證明 −(−a)=a，特別是 −(−4)=4；對所有 z∈Z 證明 −z∈Z；並以 5−8=5+(−8)=−3 分辨二元減法與一元負號。","en":"Inside the reals, take Z={0}∪N⁺∪{−n ∣ n∈N⁺} (N contains 0 by the OCME convention, N⁺=N∖{0}, and −n is the additive inverse of n). Prove −7∈Z; show that the decimal numeral '3.0' denotes the integer 3; prove −2.5∉Z; prove −(−a)=a from uniqueness of additive inverses, in particular −(−4)=4; prove −z∈Z for every z∈Z; and use 5−8=5+(−8)=−3 to tell binary subtraction from the unary minus sign."},"mko_ids":["mko-integer"]}],"title":"概念推導導讀"}