{"schema_version":"ocme-site-results-v1","locale":"zh-Hant","page_type":"derivations","facts":{"questions":36000,"reviewed":36000,"display_candidates":0,"knowledge":302,"guides":299,"paths":59,"batches":360,"families":1441,"atlas":302,"core":80,"evidence":9,"formal_evidence":5,"formal_subjects":4,"lean_files":6,"lean_toolchain":"leanprover/lean4:v4.30.0","question_state":"candidate","english_state":"ai_candidate","question_Lean":"NOT_RUN","canonical_truth_promotion":false},"filters":{"q":"mko-multivariable-real-function"},"kind":"guides","total":1,"pages":1,"page":1,"entries":[{"id":"derivation-mko-multivariable-real-function-01","title":{"zh-Hant":"多變數實函數：二變數二次多項式的係數次序、宣告定義域、切片與點值","en":"Multivariable real-valued function: coefficient order, declared domain, slices and point values of a bivariate quadratic"},"summary":{"zh-Hant":"係數向量依 [1,x,y,x²,xy,y²] 次序為 c=(1,−2,3,1,2,−1)，宣告定義域為閉矩形 R=[−1,2]×[0,3]。(1) 寫出 f 並確認 f:R→ℝ 是函數；(2) 分別核對 x、y 邊界，判定 (2,3)、(3,1)、(0,−1) 是否在 R 中；(3) 計算 f(2,1) 與 f(1,2)，並證明交換 x、y 係數得到的 g 是不同的函數；(4) 求 y=1 的 x-切片，並說明給定的 y=1 切片與指定四個點值各自都不足以決定 f。","en":"The coefficient vector in the order [1,x,y,x²,xy,y²] is c=(1,−2,3,1,2,−1), and the declared domain is the closed rectangle R=[−1,2]×[0,3]. (1) Write f and confirm that f:R→ℝ is a function; (2) check the x and y bounds separately to decide whether (2,3), (3,1), (0,−1) lie in R; (3) compute f(2,1) and f(1,2), and prove that g, obtained by swapping the x and y coefficients, is a different function; (4) find the x-slice at y=1 and show that neither the given y=1 slice nor the four specified point values determine f."},"mko_ids":["mko-multivariable-real-function"]}],"title":"概念推導導讀"}