{"schema_version":"ocme-site-results-v1","locale":"zh-Hant","page_type":"derivations","facts":{"questions":36000,"reviewed":36000,"display_candidates":0,"knowledge":302,"guides":299,"paths":59,"batches":360,"families":1441,"atlas":302,"core":80,"evidence":9,"formal_evidence":5,"formal_subjects":4,"lean_files":6,"lean_toolchain":"leanprover/lean4:v4.30.0","question_state":"candidate","english_state":"ai_candidate","question_Lean":"NOT_RUN","canonical_truth_promotion":false},"filters":{"q":"mko-natural-number"},"kind":"guides","total":1,"pages":1,"page":1,"entries":[{"id":"derivation-mko-natural-number-01","title":{"zh-Hant":"自然數：以最小歸納集判定成員，並分辨數與數字符號","en":"Natural number: deciding membership through the smallest inductive set, and telling numbers from numerals"},"summary":{"zh-Hant":"依 OCME 慣例（0∈N），把 MKO 的「0 以及由 0 經有限次後繼所得的數」讀成「實數中包含 0 且對 x↦x+1 封閉的最小集合」。據此證明 0∈N、3∈N；說明二進位符號「11」與十進位符號「3」表示同一個自然數；證明 −1∉N 與 1/2∉N；並與「自然數從 1 開始」的慣例 N⁺=N∖{0} 比較最小元素。","en":"Under the OCME convention (0∈N), read the MKO's '0 and the numbers obtained from 0 by finitely many successor steps' as 'the smallest set of reals that contains 0 and is closed under x↦x+1'. On this basis prove 0∈N and 3∈N; show that the binary numeral '11' and the decimal numeral '3' denote the same natural number; prove −1∉N and 1/2∉N; and compare least elements with the convention N⁺=N∖{0}, in which natural numbers start at 1."},"mko_ids":["mko-natural-number"]}],"title":"概念推導導讀"}