# σ-代數與測度空間基礎 · 脈衝 R05

本批已通過 Schema、去重、來源快照與獨立答案重算；仍未標記為人工審定。

本題庫已有對應的中英逐步詳解。原題的 candidate 與英文 ai_candidate 狀態保留；AI 覆核、有限計算與 Lean 形式證明分開標示。

batch-20261013-advance-20261023-r05-sigma-algebra-measure-space-foundations · 2026-10-13 · 100 題



## 1. 有限測度空間

完整有限載體與canonical集合族。操作=measure-sigma-qualification；資料={"n":7,"family":[[],[0],[1,2,3,4,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,has_empty,has_full,missing_complements,missing_unions,finite_countable_reduction,sigma] 欄序回答。

查看答案與解釋(7, [[], [0], [1, 2, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)

現代橋梁核對=(7, [[], [0], [1, 2, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0001/)

σ-代數與測度空間 · qf-mod23-measure-sigma-qualification · candidate





## 2. 有限測度空間

完整有限載體與canonical集合族。操作=measure-sigma-qualification；資料={"n":7,"family":[[],[1],[0,2,3,4,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,has_empty,has_full,missing_complements,missing_unions,finite_countable_reduction,sigma] 欄序回答。

查看答案與解釋(7, [[], [1], [0, 2, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)

現代橋梁核對=(7, [[], [1], [0, 2, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0002/)

σ-代數與測度空間 · qf-mod23-measure-sigma-qualification · candidate





## 3. 有限測度空間

完整有限載體與canonical集合族。操作=measure-sigma-qualification；資料={"n":7,"family":[[],[0,1],[2,3,4,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,has_empty,has_full,missing_complements,missing_unions,finite_countable_reduction,sigma] 欄序回答。

查看答案與解釋(7, [[], [0, 1], [2, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)

現代橋梁核對=(7, [[], [0, 1], [2, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0003/)

σ-代數與測度空間 · qf-mod23-measure-sigma-qualification · candidate





## 4. 有限測度空間

完整有限載體與canonical集合族。操作=measure-sigma-qualification；資料={"n":7,"family":[[],[2],[0,1,3,4,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,has_empty,has_full,missing_complements,missing_unions,finite_countable_reduction,sigma] 欄序回答。

查看答案與解釋(7, [[], [2], [0, 1, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)

現代橋梁核對=(7, [[], [2], [0, 1, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0004/)

σ-代數與測度空間 · qf-mod23-measure-sigma-qualification · candidate





## 5. 有限測度空間

完整有限載體與canonical集合族。操作=measure-sigma-qualification；資料={"n":7,"family":[[],[0,2],[1,3,4,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,has_empty,has_full,missing_complements,missing_unions,finite_countable_reduction,sigma] 欄序回答。

查看答案與解釋(7, [[], [0, 2], [1, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)

現代橋梁核對=(7, [[], [0, 2], [1, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0005/)

σ-代數與測度空間 · qf-mod23-measure-sigma-qualification · candidate





## 6. 有限測度空間

完整有限載體與canonical集合族。操作=measure-sigma-qualification；資料={"n":7,"family":[[],[1,2],[0,3,4,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,has_empty,has_full,missing_complements,missing_unions,finite_countable_reduction,sigma] 欄序回答。

查看答案與解釋(7, [[], [1, 2], [0, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)

現代橋梁核對=(7, [[], [1, 2], [0, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0006/)

σ-代數與測度空間 · qf-mod23-measure-sigma-qualification · candidate





## 7. 有限測度空間

完整有限載體與canonical集合族。操作=measure-sigma-qualification；資料={"n":7,"family":[[],[0,1,2],[3,4,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,has_empty,has_full,missing_complements,missing_unions,finite_countable_reduction,sigma] 欄序回答。

查看答案與解釋(7, [[], [0, 1, 2], [3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)

現代橋梁核對=(7, [[], [0, 1, 2], [3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0007/)

σ-代數與測度空間 · qf-mod23-measure-sigma-qualification · candidate





## 8. 有限測度空間

完整有限載體與canonical集合族。操作=measure-sigma-qualification；資料={"n":7,"family":[[],[3],[0,1,2,4,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,has_empty,has_full,missing_complements,missing_unions,finite_countable_reduction,sigma] 欄序回答。

查看答案與解釋(7, [[], [3], [0, 1, 2, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)

現代橋梁核對=(7, [[], [3], [0, 1, 2, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0008/)

σ-代數與測度空間 · qf-mod23-measure-sigma-qualification · candidate





## 9. 有限測度空間

完整有限載體與canonical集合族。操作=measure-sigma-qualification；資料={"n":7,"family":[[],[0,3],[1,2,4,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,has_empty,has_full,missing_complements,missing_unions,finite_countable_reduction,sigma] 欄序回答。

查看答案與解釋(7, [[], [0, 3], [1, 2, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)

現代橋梁核對=(7, [[], [0, 3], [1, 2, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0009/)

σ-代數與測度空間 · qf-mod23-measure-sigma-qualification · candidate





## 10. 有限測度空間

完整有限載體與canonical集合族。操作=measure-sigma-qualification；資料={"n":7,"family":[[],[1,3],[0,2,4,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,has_empty,has_full,missing_complements,missing_unions,finite_countable_reduction,sigma] 欄序回答。

查看答案與解釋(7, [[], [1, 3], [0, 2, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)

現代橋梁核對=(7, [[], [1, 3], [0, 2, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0010/)

σ-代數與測度空間 · qf-mod23-measure-sigma-qualification · candidate





## 11. 有限測度空間

完整有限載體與canonical集合族。操作=measure-sigma-qualification；資料={"n":7,"family":[[],[0,1,3],[2,4,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,has_empty,has_full,missing_complements,missing_unions,finite_countable_reduction,sigma] 欄序回答。

查看答案與解釋(7, [[], [0, 1, 3], [2, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)

現代橋梁核對=(7, [[], [0, 1, 3], [2, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0011/)

σ-代數與測度空間 · qf-mod23-measure-sigma-qualification · candidate





## 12. 有限測度空間

完整有限載體與canonical集合族。操作=measure-sigma-qualification；資料={"n":7,"family":[[],[2,3],[0,1,4,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,has_empty,has_full,missing_complements,missing_unions,finite_countable_reduction,sigma] 欄序回答。

查看答案與解釋(7, [[], [2, 3], [0, 1, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)

現代橋梁核對=(7, [[], [2, 3], [0, 1, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0012/)

σ-代數與測度空間 · qf-mod23-measure-sigma-qualification · candidate





## 13. 有限測度空間

完整有限載體與canonical集合族。操作=measure-sigma-qualification；資料={"n":7,"family":[[],[0,2,3],[1,4,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,has_empty,has_full,missing_complements,missing_unions,finite_countable_reduction,sigma] 欄序回答。

查看答案與解釋(7, [[], [0, 2, 3], [1, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)

現代橋梁核對=(7, [[], [0, 2, 3], [1, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0013/)

σ-代數與測度空間 · qf-mod23-measure-sigma-qualification · candidate





## 14. 有限測度空間

完整有限載體與canonical集合族。操作=measure-sigma-qualification；資料={"n":7,"family":[[],[1,2,3],[0,4,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,has_empty,has_full,missing_complements,missing_unions,finite_countable_reduction,sigma] 欄序回答。

查看答案與解釋(7, [[], [1, 2, 3], [0, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)

現代橋梁核對=(7, [[], [1, 2, 3], [0, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0014/)

σ-代數與測度空間 · qf-mod23-measure-sigma-qualification · candidate





## 15. 有限測度空間

完整有限載體與canonical集合族。操作=measure-sigma-qualification；資料={"n":7,"family":[[],[0,1,2,3],[4,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,has_empty,has_full,missing_complements,missing_unions,finite_countable_reduction,sigma] 欄序回答。

查看答案與解釋(7, [[], [0, 1, 2, 3], [4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)

現代橋梁核對=(7, [[], [0, 1, 2, 3], [4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0015/)

σ-代數與測度空間 · qf-mod23-measure-sigma-qualification · candidate





## 16. 有限測度空間

完整有限載體與canonical集合族。操作=measure-sigma-qualification；資料={"n":7,"family":[[],[4],[0,1,2,3,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,has_empty,has_full,missing_complements,missing_unions,finite_countable_reduction,sigma] 欄序回答。

查看答案與解釋(7, [[], [4], [0, 1, 2, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)

現代橋梁核對=(7, [[], [4], [0, 1, 2, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0016/)

σ-代數與測度空間 · qf-mod23-measure-sigma-qualification · candidate





## 17. 有限測度空間

完整有限載體與canonical集合族。操作=measure-sigma-qualification；資料={"n":7,"family":[[],[0,4],[1,2,3,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,has_empty,has_full,missing_complements,missing_unions,finite_countable_reduction,sigma] 欄序回答。

查看答案與解釋(7, [[], [0, 4], [1, 2, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)

現代橋梁核對=(7, [[], [0, 4], [1, 2, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0017/)

σ-代數與測度空間 · qf-mod23-measure-sigma-qualification · candidate





## 18. 有限測度空間

完整有限載體與canonical集合族。操作=measure-sigma-qualification；資料={"n":7,"family":[[],[1,4],[0,2,3,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,has_empty,has_full,missing_complements,missing_unions,finite_countable_reduction,sigma] 欄序回答。

查看答案與解釋(7, [[], [1, 4], [0, 2, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)

現代橋梁核對=(7, [[], [1, 4], [0, 2, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0018/)

σ-代數與測度空間 · qf-mod23-measure-sigma-qualification · candidate





## 19. 有限測度空間

完整有限載體與canonical集合族。操作=measure-sigma-qualification；資料={"n":7,"family":[[],[0,1,4],[2,3,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,has_empty,has_full,missing_complements,missing_unions,finite_countable_reduction,sigma] 欄序回答。

查看答案與解釋(7, [[], [0, 1, 4], [2, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)

現代橋梁核對=(7, [[], [0, 1, 4], [2, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0019/)

σ-代數與測度空間 · qf-mod23-measure-sigma-qualification · candidate





## 20. 有限測度空間

完整有限載體與canonical集合族。操作=measure-sigma-qualification；資料={"n":7,"family":[[],[2,4],[0,1,3,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,has_empty,has_full,missing_complements,missing_unions,finite_countable_reduction,sigma] 欄序回答。

查看答案與解釋(7, [[], [2, 4], [0, 1, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)

現代橋梁核對=(7, [[], [2, 4], [0, 1, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0020/)

σ-代數與測度空間 · qf-mod23-measure-sigma-qualification · candidate





## 21. 有限測度空間

完整有限載體與canonical集合族。操作=measure-sigma-qualification；資料={"n":7,"family":[[],[0,2,4],[1,3,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,has_empty,has_full,missing_complements,missing_unions,finite_countable_reduction,sigma] 欄序回答。

查看答案與解釋(7, [[], [0, 2, 4], [1, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)

現代橋梁核對=(7, [[], [0, 2, 4], [1, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0021/)

σ-代數與測度空間 · qf-mod23-measure-sigma-qualification · candidate





## 22. 有限測度空間

完整有限載體與canonical集合族。操作=measure-sigma-qualification；資料={"n":7,"family":[[],[1,2,4],[0,3,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,has_empty,has_full,missing_complements,missing_unions,finite_countable_reduction,sigma] 欄序回答。

查看答案與解釋(7, [[], [1, 2, 4], [0, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)

現代橋梁核對=(7, [[], [1, 2, 4], [0, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0022/)

σ-代數與測度空間 · qf-mod23-measure-sigma-qualification · candidate





## 23. 有限測度空間

完整有限載體與canonical集合族。操作=measure-sigma-qualification；資料={"n":7,"family":[[],[0,1,2,4],[3,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,has_empty,has_full,missing_complements,missing_unions,finite_countable_reduction,sigma] 欄序回答。

查看答案與解釋(7, [[], [0, 1, 2, 4], [3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)

現代橋梁核對=(7, [[], [0, 1, 2, 4], [3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0023/)

σ-代數與測度空間 · qf-mod23-measure-sigma-qualification · candidate





## 24. 有限測度空間

完整有限載體與canonical集合族。操作=measure-sigma-qualification；資料={"n":7,"family":[[],[3,4],[0,1,2,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,has_empty,has_full,missing_complements,missing_unions,finite_countable_reduction,sigma] 欄序回答。

查看答案與解釋(7, [[], [3, 4], [0, 1, 2, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)

現代橋梁核對=(7, [[], [3, 4], [0, 1, 2, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0024/)

σ-代數與測度空間 · qf-mod23-measure-sigma-qualification · candidate





## 25. 有限測度空間

完整有限載體與canonical集合族。操作=measure-sigma-qualification；資料={"n":7,"family":[[],[0,3,4],[1,2,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,has_empty,has_full,missing_complements,missing_unions,finite_countable_reduction,sigma] 欄序回答。

查看答案與解釋(7, [[], [0, 3, 4], [1, 2, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)

現代橋梁核對=(7, [[], [0, 3, 4], [1, 2, 5, 6], [0, 1, 2, 3, 4, 5, 6]], 是, 是, [], [], 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0025/)

σ-代數與測度空間 · qf-mod23-measure-sigma-qualification · candidate





## 26. 有限測度空間

完整有限載體與canonical集合族。操作=measure-closure-inventory；資料={"n":7,"family":[[],[0],[1,2,3,4,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,missing_complements,missing_unions,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [0], [1, 2, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)

現代橋梁核對=(7, [[], [0], [1, 2, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0026/)

σ-代數與測度空間 · qf-mod23-measure-closure-inventory · candidate





## 27. 有限測度空間

完整有限載體與canonical集合族。操作=measure-closure-inventory；資料={"n":7,"family":[[],[1],[0,2,3,4,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,missing_complements,missing_unions,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [1], [0, 2, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)

現代橋梁核對=(7, [[], [1], [0, 2, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0027/)

σ-代數與測度空間 · qf-mod23-measure-closure-inventory · candidate





## 28. 有限測度空間

完整有限載體與canonical集合族。操作=measure-closure-inventory；資料={"n":7,"family":[[],[0,1],[2,3,4,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,missing_complements,missing_unions,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [0, 1], [2, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)

現代橋梁核對=(7, [[], [0, 1], [2, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0028/)

σ-代數與測度空間 · qf-mod23-measure-closure-inventory · candidate





## 29. 有限測度空間

完整有限載體與canonical集合族。操作=measure-closure-inventory；資料={"n":7,"family":[[],[2],[0,1,3,4,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,missing_complements,missing_unions,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [2], [0, 1, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)

現代橋梁核對=(7, [[], [2], [0, 1, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0029/)

σ-代數與測度空間 · qf-mod23-measure-closure-inventory · candidate





## 30. 有限測度空間

完整有限載體與canonical集合族。操作=measure-closure-inventory；資料={"n":7,"family":[[],[0,2],[1,3,4,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,missing_complements,missing_unions,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [0, 2], [1, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)

現代橋梁核對=(7, [[], [0, 2], [1, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0030/)

σ-代數與測度空間 · qf-mod23-measure-closure-inventory · candidate





## 31. 有限測度空間

完整有限載體與canonical集合族。操作=measure-closure-inventory；資料={"n":7,"family":[[],[1,2],[0,3,4,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,missing_complements,missing_unions,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [1, 2], [0, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)

現代橋梁核對=(7, [[], [1, 2], [0, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0031/)

σ-代數與測度空間 · qf-mod23-measure-closure-inventory · candidate





## 32. 有限測度空間

完整有限載體與canonical集合族。操作=measure-closure-inventory；資料={"n":7,"family":[[],[0,1,2],[3,4,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,missing_complements,missing_unions,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [0, 1, 2], [3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)

現代橋梁核對=(7, [[], [0, 1, 2], [3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0032/)

σ-代數與測度空間 · qf-mod23-measure-closure-inventory · candidate





## 33. 有限測度空間

完整有限載體與canonical集合族。操作=measure-closure-inventory；資料={"n":7,"family":[[],[3],[0,1,2,4,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,missing_complements,missing_unions,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [3], [0, 1, 2, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)

現代橋梁核對=(7, [[], [3], [0, 1, 2, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0033/)

σ-代數與測度空間 · qf-mod23-measure-closure-inventory · candidate





## 34. 有限測度空間

完整有限載體與canonical集合族。操作=measure-closure-inventory；資料={"n":7,"family":[[],[0,3],[1,2,4,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,missing_complements,missing_unions,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [0, 3], [1, 2, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)

現代橋梁核對=(7, [[], [0, 3], [1, 2, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0034/)

σ-代數與測度空間 · qf-mod23-measure-closure-inventory · candidate





## 35. 有限測度空間

完整有限載體與canonical集合族。操作=measure-closure-inventory；資料={"n":7,"family":[[],[1,3],[0,2,4,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,missing_complements,missing_unions,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [1, 3], [0, 2, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)

現代橋梁核對=(7, [[], [1, 3], [0, 2, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0035/)

σ-代數與測度空間 · qf-mod23-measure-closure-inventory · candidate





## 36. 有限測度空間

完整有限載體與canonical集合族。操作=measure-closure-inventory；資料={"n":7,"family":[[],[0,1,3],[2,4,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,missing_complements,missing_unions,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [0, 1, 3], [2, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)

現代橋梁核對=(7, [[], [0, 1, 3], [2, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0036/)

σ-代數與測度空間 · qf-mod23-measure-closure-inventory · candidate





## 37. 有限測度空間

完整有限載體與canonical集合族。操作=measure-closure-inventory；資料={"n":7,"family":[[],[2,3],[0,1,4,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,missing_complements,missing_unions,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [2, 3], [0, 1, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)

現代橋梁核對=(7, [[], [2, 3], [0, 1, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0037/)

σ-代數與測度空間 · qf-mod23-measure-closure-inventory · candidate





## 38. 有限測度空間

完整有限載體與canonical集合族。操作=measure-closure-inventory；資料={"n":7,"family":[[],[0,2,3],[1,4,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,missing_complements,missing_unions,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [0, 2, 3], [1, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)

現代橋梁核對=(7, [[], [0, 2, 3], [1, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0038/)

σ-代數與測度空間 · qf-mod23-measure-closure-inventory · candidate





## 39. 有限測度空間

完整有限載體與canonical集合族。操作=measure-closure-inventory；資料={"n":7,"family":[[],[1,2,3],[0,4,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,missing_complements,missing_unions,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [1, 2, 3], [0, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)

現代橋梁核對=(7, [[], [1, 2, 3], [0, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0039/)

σ-代數與測度空間 · qf-mod23-measure-closure-inventory · candidate





## 40. 有限測度空間

完整有限載體與canonical集合族。操作=measure-closure-inventory；資料={"n":7,"family":[[],[0,1,2,3],[4,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,missing_complements,missing_unions,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [0, 1, 2, 3], [4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)

現代橋梁核對=(7, [[], [0, 1, 2, 3], [4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0040/)

σ-代數與測度空間 · qf-mod23-measure-closure-inventory · candidate





## 41. 有限測度空間

完整有限載體與canonical集合族。操作=measure-closure-inventory；資料={"n":7,"family":[[],[4],[0,1,2,3,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,missing_complements,missing_unions,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [4], [0, 1, 2, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)

現代橋梁核對=(7, [[], [4], [0, 1, 2, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0041/)

σ-代數與測度空間 · qf-mod23-measure-closure-inventory · candidate





## 42. 有限測度空間

完整有限載體與canonical集合族。操作=measure-closure-inventory；資料={"n":7,"family":[[],[0,4],[1,2,3,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,missing_complements,missing_unions,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [0, 4], [1, 2, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)

現代橋梁核對=(7, [[], [0, 4], [1, 2, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0042/)

σ-代數與測度空間 · qf-mod23-measure-closure-inventory · candidate





## 43. 有限測度空間

完整有限載體與canonical集合族。操作=measure-closure-inventory；資料={"n":7,"family":[[],[1,4],[0,2,3,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,missing_complements,missing_unions,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [1, 4], [0, 2, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)

現代橋梁核對=(7, [[], [1, 4], [0, 2, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0043/)

σ-代數與測度空間 · qf-mod23-measure-closure-inventory · candidate





## 44. 有限測度空間

完整有限載體與canonical集合族。操作=measure-closure-inventory；資料={"n":7,"family":[[],[0,1,4],[2,3,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,missing_complements,missing_unions,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [0, 1, 4], [2, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)

現代橋梁核對=(7, [[], [0, 1, 4], [2, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0044/)

σ-代數與測度空間 · qf-mod23-measure-closure-inventory · candidate





## 45. 有限測度空間

完整有限載體與canonical集合族。操作=measure-closure-inventory；資料={"n":7,"family":[[],[2,4],[0,1,3,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,missing_complements,missing_unions,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [2, 4], [0, 1, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)

現代橋梁核對=(7, [[], [2, 4], [0, 1, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0045/)

σ-代數與測度空間 · qf-mod23-measure-closure-inventory · candidate





## 46. 有限測度空間

完整有限載體與canonical集合族。操作=measure-closure-inventory；資料={"n":7,"family":[[],[0,2,4],[1,3,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,missing_complements,missing_unions,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [0, 2, 4], [1, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)

現代橋梁核對=(7, [[], [0, 2, 4], [1, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0046/)

σ-代數與測度空間 · qf-mod23-measure-closure-inventory · candidate





## 47. 有限測度空間

完整有限載體與canonical集合族。操作=measure-closure-inventory；資料={"n":7,"family":[[],[1,2,4],[0,3,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,missing_complements,missing_unions,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [1, 2, 4], [0, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)

現代橋梁核對=(7, [[], [1, 2, 4], [0, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0047/)

σ-代數與測度空間 · qf-mod23-measure-closure-inventory · candidate





## 48. 有限測度空間

完整有限載體與canonical集合族。操作=measure-closure-inventory；資料={"n":7,"family":[[],[0,1,2,4],[3,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,missing_complements,missing_unions,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [0, 1, 2, 4], [3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)

現代橋梁核對=(7, [[], [0, 1, 2, 4], [3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0048/)

σ-代數與測度空間 · qf-mod23-measure-closure-inventory · candidate





## 49. 有限測度空間

完整有限載體與canonical集合族。操作=measure-closure-inventory；資料={"n":7,"family":[[],[3,4],[0,1,2,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,missing_complements,missing_unions,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [3, 4], [0, 1, 2, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)

現代橋梁核對=(7, [[], [3, 4], [0, 1, 2, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0049/)

σ-代數與測度空間 · qf-mod23-measure-closure-inventory · candidate





## 50. 有限測度空間

完整有限載體與canonical集合族。操作=measure-closure-inventory；資料={"n":7,"family":[[],[0,3,4],[1,2,5,6],[0,1,2,3,4,5,6]]}。請依 [n,family,missing_complements,missing_unions,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [0, 3, 4], [1, 2, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)

現代橋梁核對=(7, [[], [0, 3, 4], [1, 2, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [], [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0050/)

σ-代數與測度空間 · qf-mod23-measure-closure-inventory · candidate





## 51. 有限測度空間

完整有限載體與canonical集合族。操作=measure-measure-additivity-audit；資料={"n":7,"family":[[],[0],[1,2,3,4,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[1,3],[2,3],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [0], [1, 2, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 1/3, 2/3, 1], 是, [], 是)

現代橋梁核對=(7, [[], [0], [1, 2, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 1/3, 2/3, 1], 是, [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0051/)

σ-代數與測度空間 · qf-mod23-measure-measure-additivity-audit · candidate





## 52. 有限測度空間

完整有限載體與canonical集合族。操作=measure-measure-additivity-audit；資料={"n":7,"family":[[],[1],[0,2,3,4,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[2,5],[3,5],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [1], [0, 2, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 2/5, 3/5, 1], 是, [], 是)

現代橋梁核對=(7, [[], [1], [0, 2, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 2/5, 3/5, 1], 是, [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0052/)

σ-代數與測度空間 · qf-mod23-measure-measure-additivity-audit · candidate





## 53. 有限測度空間

完整有限載體與canonical集合族。操作=measure-measure-additivity-audit；資料={"n":7,"family":[[],[0,1],[2,3,4,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[3,7],[4,7],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [0, 1], [2, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 3/7, 4/7, 1], 是, [], 是)

現代橋梁核對=(7, [[], [0, 1], [2, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 3/7, 4/7, 1], 是, [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0053/)

σ-代數與測度空間 · qf-mod23-measure-measure-additivity-audit · candidate





## 54. 有限測度空間

完整有限載體與canonical集合族。操作=measure-measure-additivity-audit；資料={"n":7,"family":[[],[2],[0,1,3,4,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[4,9],[5,9],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [2], [0, 1, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 4/9, 5/9, 1], 是, [], 是)

現代橋梁核對=(7, [[], [2], [0, 1, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 4/9, 5/9, 1], 是, [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0054/)

σ-代數與測度空間 · qf-mod23-measure-measure-additivity-audit · candidate





## 55. 有限測度空間

完整有限載體與canonical集合族。操作=measure-measure-additivity-audit；資料={"n":7,"family":[[],[0,2],[1,3,4,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[5,11],[6,11],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [0, 2], [1, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 5/11, 6/11, 1], 是, [], 是)

現代橋梁核對=(7, [[], [0, 2], [1, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 5/11, 6/11, 1], 是, [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0055/)

σ-代數與測度空間 · qf-mod23-measure-measure-additivity-audit · candidate





## 56. 有限測度空間

完整有限載體與canonical集合族。操作=measure-measure-additivity-audit；資料={"n":7,"family":[[],[1,2],[0,3,4,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[6,13],[7,13],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [1, 2], [0, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 6/13, 7/13, 1], 是, [], 是)

現代橋梁核對=(7, [[], [1, 2], [0, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 6/13, 7/13, 1], 是, [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0056/)

σ-代數與測度空間 · qf-mod23-measure-measure-additivity-audit · candidate





## 57. 有限測度空間

完整有限載體與canonical集合族。操作=measure-measure-additivity-audit；資料={"n":7,"family":[[],[0,1,2],[3,4,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[7,15],[8,15],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [0, 1, 2], [3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 7/15, 8/15, 1], 是, [], 是)

現代橋梁核對=(7, [[], [0, 1, 2], [3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 7/15, 8/15, 1], 是, [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0057/)

σ-代數與測度空間 · qf-mod23-measure-measure-additivity-audit · candidate





## 58. 有限測度空間

完整有限載體與canonical集合族。操作=measure-measure-additivity-audit；資料={"n":7,"family":[[],[3],[0,1,2,4,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[8,17],[9,17],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [3], [0, 1, 2, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 8/17, 9/17, 1], 是, [], 是)

現代橋梁核對=(7, [[], [3], [0, 1, 2, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 8/17, 9/17, 1], 是, [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0058/)

σ-代數與測度空間 · qf-mod23-measure-measure-additivity-audit · candidate





## 59. 有限測度空間

完整有限載體與canonical集合族。操作=measure-measure-additivity-audit；資料={"n":7,"family":[[],[0,3],[1,2,4,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[9,19],[10,19],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [0, 3], [1, 2, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 9/19, 10/19, 1], 是, [], 是)

現代橋梁核對=(7, [[], [0, 3], [1, 2, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 9/19, 10/19, 1], 是, [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0059/)

σ-代數與測度空間 · qf-mod23-measure-measure-additivity-audit · candidate





## 60. 有限測度空間

完整有限載體與canonical集合族。操作=measure-measure-additivity-audit；資料={"n":7,"family":[[],[1,3],[0,2,4,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[10,21],[11,21],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [1, 3], [0, 2, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 10/21, 11/21, 1], 是, [], 是)

現代橋梁核對=(7, [[], [1, 3], [0, 2, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 10/21, 11/21, 1], 是, [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0060/)

σ-代數與測度空間 · qf-mod23-measure-measure-additivity-audit · candidate





## 61. 有限測度空間

完整有限載體與canonical集合族。操作=measure-measure-additivity-audit；資料={"n":7,"family":[[],[0,1,3],[2,4,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[11,23],[12,23],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [0, 1, 3], [2, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 11/23, 12/23, 1], 是, [], 是)

現代橋梁核對=(7, [[], [0, 1, 3], [2, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 11/23, 12/23, 1], 是, [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0061/)

σ-代數與測度空間 · qf-mod23-measure-measure-additivity-audit · candidate





## 62. 有限測度空間

完整有限載體與canonical集合族。操作=measure-measure-additivity-audit；資料={"n":7,"family":[[],[2,3],[0,1,4,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[12,25],[13,25],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [2, 3], [0, 1, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 12/25, 13/25, 1], 是, [], 是)

現代橋梁核對=(7, [[], [2, 3], [0, 1, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 12/25, 13/25, 1], 是, [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0062/)

σ-代數與測度空間 · qf-mod23-measure-measure-additivity-audit · candidate





## 63. 有限測度空間

完整有限載體與canonical集合族。操作=measure-measure-additivity-audit；資料={"n":7,"family":[[],[0,2,3],[1,4,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[13,27],[14,27],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [0, 2, 3], [1, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 13/27, 14/27, 1], 是, [], 是)

現代橋梁核對=(7, [[], [0, 2, 3], [1, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 13/27, 14/27, 1], 是, [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0063/)

σ-代數與測度空間 · qf-mod23-measure-measure-additivity-audit · candidate





## 64. 有限測度空間

完整有限載體與canonical集合族。操作=measure-measure-additivity-audit；資料={"n":7,"family":[[],[1,2,3],[0,4,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[14,29],[15,29],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [1, 2, 3], [0, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 14/29, 15/29, 1], 是, [], 是)

現代橋梁核對=(7, [[], [1, 2, 3], [0, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 14/29, 15/29, 1], 是, [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0064/)

σ-代數與測度空間 · qf-mod23-measure-measure-additivity-audit · candidate





## 65. 有限測度空間

完整有限載體與canonical集合族。操作=measure-measure-additivity-audit；資料={"n":7,"family":[[],[0,1,2,3],[4,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[15,31],[16,31],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [0, 1, 2, 3], [4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 15/31, 16/31, 1], 是, [], 是)

現代橋梁核對=(7, [[], [0, 1, 2, 3], [4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 15/31, 16/31, 1], 是, [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0065/)

σ-代數與測度空間 · qf-mod23-measure-measure-additivity-audit · candidate





## 66. 有限測度空間

完整有限載體與canonical集合族。操作=measure-measure-additivity-audit；資料={"n":7,"family":[[],[4],[0,1,2,3,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[16,33],[17,33],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [4], [0, 1, 2, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 16/33, 17/33, 1], 是, [], 是)

現代橋梁核對=(7, [[], [4], [0, 1, 2, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 16/33, 17/33, 1], 是, [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0066/)

σ-代數與測度空間 · qf-mod23-measure-measure-additivity-audit · candidate





## 67. 有限測度空間

完整有限載體與canonical集合族。操作=measure-measure-additivity-audit；資料={"n":7,"family":[[],[0,4],[1,2,3,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[17,35],[18,35],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [0, 4], [1, 2, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 17/35, 18/35, 1], 是, [], 是)

現代橋梁核對=(7, [[], [0, 4], [1, 2, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 17/35, 18/35, 1], 是, [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0067/)

σ-代數與測度空間 · qf-mod23-measure-measure-additivity-audit · candidate





## 68. 有限測度空間

完整有限載體與canonical集合族。操作=measure-measure-additivity-audit；資料={"n":7,"family":[[],[1,4],[0,2,3,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[18,37],[19,37],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [1, 4], [0, 2, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 18/37, 19/37, 1], 是, [], 是)

現代橋梁核對=(7, [[], [1, 4], [0, 2, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 18/37, 19/37, 1], 是, [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0068/)

σ-代數與測度空間 · qf-mod23-measure-measure-additivity-audit · candidate





## 69. 有限測度空間

完整有限載體與canonical集合族。操作=measure-measure-additivity-audit；資料={"n":7,"family":[[],[0,1,4],[2,3,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[19,39],[20,39],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [0, 1, 4], [2, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 19/39, 20/39, 1], 是, [], 是)

現代橋梁核對=(7, [[], [0, 1, 4], [2, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 19/39, 20/39, 1], 是, [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0069/)

σ-代數與測度空間 · qf-mod23-measure-measure-additivity-audit · candidate





## 70. 有限測度空間

完整有限載體與canonical集合族。操作=measure-measure-additivity-audit；資料={"n":7,"family":[[],[2,4],[0,1,3,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[20,41],[21,41],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [2, 4], [0, 1, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 20/41, 21/41, 1], 是, [], 是)

現代橋梁核對=(7, [[], [2, 4], [0, 1, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 20/41, 21/41, 1], 是, [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0070/)

σ-代數與測度空間 · qf-mod23-measure-measure-additivity-audit · candidate





## 71. 有限測度空間

完整有限載體與canonical集合族。操作=measure-measure-additivity-audit；資料={"n":7,"family":[[],[0,2,4],[1,3,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[21,43],[22,43],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [0, 2, 4], [1, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 21/43, 22/43, 1], 是, [], 是)

現代橋梁核對=(7, [[], [0, 2, 4], [1, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 21/43, 22/43, 1], 是, [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0071/)

σ-代數與測度空間 · qf-mod23-measure-measure-additivity-audit · candidate





## 72. 有限測度空間

完整有限載體與canonical集合族。操作=measure-measure-additivity-audit；資料={"n":7,"family":[[],[1,2,4],[0,3,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[22,45],[23,45],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [1, 2, 4], [0, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 22/45, 23/45, 1], 是, [], 是)

現代橋梁核對=(7, [[], [1, 2, 4], [0, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 22/45, 23/45, 1], 是, [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0072/)

σ-代數與測度空間 · qf-mod23-measure-measure-additivity-audit · candidate





## 73. 有限測度空間

完整有限載體與canonical集合族。操作=measure-measure-additivity-audit；資料={"n":7,"family":[[],[0,1,2,4],[3,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[23,47],[24,47],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [0, 1, 2, 4], [3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 23/47, 24/47, 1], 是, [], 是)

現代橋梁核對=(7, [[], [0, 1, 2, 4], [3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 23/47, 24/47, 1], 是, [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0073/)

σ-代數與測度空間 · qf-mod23-measure-measure-additivity-audit · candidate





## 74. 有限測度空間

完整有限載體與canonical集合族。操作=measure-measure-additivity-audit；資料={"n":7,"family":[[],[3,4],[0,1,2,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[24,49],[25,49],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [3, 4], [0, 1, 2, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 24/49, 25/49, 1], 是, [], 是)

現代橋梁核對=(7, [[], [3, 4], [0, 1, 2, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 24/49, 25/49, 1], 是, [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0074/)

σ-代數與測度空間 · qf-mod23-measure-measure-additivity-audit · candidate





## 75. 有限測度空間

完整有限載體與canonical集合族。操作=measure-measure-additivity-audit；資料={"n":7,"family":[[],[0,3,4],[1,2,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[25,51],[26,51],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,finite_countable_reduction] 欄序回答。

查看答案與解釋(7, [[], [0, 3, 4], [1, 2, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 25/51, 26/51, 1], 是, [], 是)

現代橋梁核對=(7, [[], [0, 3, 4], [1, 2, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 25/51, 26/51, 1], 是, [], 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0075/)

σ-代數與測度空間 · qf-mod23-measure-measure-additivity-audit · candidate





## 76. 有限測度空間

完整有限載體與canonical集合族。操作=measure-probability-measure-audit；資料={"n":7,"family":[[],[0],[1,2,3,4,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[1,3],[2,3],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,total,finite_countable_reduction,probability_measure] 欄序回答。

查看答案與解釋(7, [[], [0], [1, 2, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 1/3, 2/3, 1], 是, [], 1, 是, 是)

現代橋梁核對=(7, [[], [0], [1, 2, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 1/3, 2/3, 1], 是, [], 1, 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0076/)

σ-代數與測度空間 · qf-mod23-measure-probability-measure-audit · candidate





## 77. 有限測度空間

完整有限載體與canonical集合族。操作=measure-probability-measure-audit；資料={"n":7,"family":[[],[1],[0,2,3,4,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[2,5],[3,5],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,total,finite_countable_reduction,probability_measure] 欄序回答。

查看答案與解釋(7, [[], [1], [0, 2, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 2/5, 3/5, 1], 是, [], 1, 是, 是)

現代橋梁核對=(7, [[], [1], [0, 2, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 2/5, 3/5, 1], 是, [], 1, 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0077/)

σ-代數與測度空間 · qf-mod23-measure-probability-measure-audit · candidate





## 78. 有限測度空間

完整有限載體與canonical集合族。操作=measure-probability-measure-audit；資料={"n":7,"family":[[],[0,1],[2,3,4,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[3,7],[4,7],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,total,finite_countable_reduction,probability_measure] 欄序回答。

查看答案與解釋(7, [[], [0, 1], [2, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 3/7, 4/7, 1], 是, [], 1, 是, 是)

現代橋梁核對=(7, [[], [0, 1], [2, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 3/7, 4/7, 1], 是, [], 1, 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0078/)

σ-代數與測度空間 · qf-mod23-measure-probability-measure-audit · candidate





## 79. 有限測度空間

完整有限載體與canonical集合族。操作=measure-probability-measure-audit；資料={"n":7,"family":[[],[2],[0,1,3,4,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[4,9],[5,9],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,total,finite_countable_reduction,probability_measure] 欄序回答。

查看答案與解釋(7, [[], [2], [0, 1, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 4/9, 5/9, 1], 是, [], 1, 是, 是)

現代橋梁核對=(7, [[], [2], [0, 1, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 4/9, 5/9, 1], 是, [], 1, 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0079/)

σ-代數與測度空間 · qf-mod23-measure-probability-measure-audit · candidate





## 80. 有限測度空間

完整有限載體與canonical集合族。操作=measure-probability-measure-audit；資料={"n":7,"family":[[],[0,2],[1,3,4,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[5,11],[6,11],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,total,finite_countable_reduction,probability_measure] 欄序回答。

查看答案與解釋(7, [[], [0, 2], [1, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 5/11, 6/11, 1], 是, [], 1, 是, 是)

現代橋梁核對=(7, [[], [0, 2], [1, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 5/11, 6/11, 1], 是, [], 1, 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0080/)

σ-代數與測度空間 · qf-mod23-measure-probability-measure-audit · candidate





## 81. 有限測度空間

完整有限載體與canonical集合族。操作=measure-probability-measure-audit；資料={"n":7,"family":[[],[1,2],[0,3,4,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[6,13],[7,13],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,total,finite_countable_reduction,probability_measure] 欄序回答。

查看答案與解釋(7, [[], [1, 2], [0, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 6/13, 7/13, 1], 是, [], 1, 是, 是)

現代橋梁核對=(7, [[], [1, 2], [0, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 6/13, 7/13, 1], 是, [], 1, 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0081/)

σ-代數與測度空間 · qf-mod23-measure-probability-measure-audit · candidate





## 82. 有限測度空間

完整有限載體與canonical集合族。操作=measure-probability-measure-audit；資料={"n":7,"family":[[],[0,1,2],[3,4,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[7,15],[8,15],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,total,finite_countable_reduction,probability_measure] 欄序回答。

查看答案與解釋(7, [[], [0, 1, 2], [3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 7/15, 8/15, 1], 是, [], 1, 是, 是)

現代橋梁核對=(7, [[], [0, 1, 2], [3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 7/15, 8/15, 1], 是, [], 1, 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0082/)

σ-代數與測度空間 · qf-mod23-measure-probability-measure-audit · candidate





## 83. 有限測度空間

完整有限載體與canonical集合族。操作=measure-probability-measure-audit；資料={"n":7,"family":[[],[3],[0,1,2,4,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[8,17],[9,17],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,total,finite_countable_reduction,probability_measure] 欄序回答。

查看答案與解釋(7, [[], [3], [0, 1, 2, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 8/17, 9/17, 1], 是, [], 1, 是, 是)

現代橋梁核對=(7, [[], [3], [0, 1, 2, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 8/17, 9/17, 1], 是, [], 1, 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0083/)

σ-代數與測度空間 · qf-mod23-measure-probability-measure-audit · candidate





## 84. 有限測度空間

完整有限載體與canonical集合族。操作=measure-probability-measure-audit；資料={"n":7,"family":[[],[0,3],[1,2,4,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[9,19],[10,19],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,total,finite_countable_reduction,probability_measure] 欄序回答。

查看答案與解釋(7, [[], [0, 3], [1, 2, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 9/19, 10/19, 1], 是, [], 1, 是, 是)

現代橋梁核對=(7, [[], [0, 3], [1, 2, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 9/19, 10/19, 1], 是, [], 1, 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0084/)

σ-代數與測度空間 · qf-mod23-measure-probability-measure-audit · candidate





## 85. 有限測度空間

完整有限載體與canonical集合族。操作=measure-probability-measure-audit；資料={"n":7,"family":[[],[1,3],[0,2,4,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[10,21],[11,21],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,total,finite_countable_reduction,probability_measure] 欄序回答。

查看答案與解釋(7, [[], [1, 3], [0, 2, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 10/21, 11/21, 1], 是, [], 1, 是, 是)

現代橋梁核對=(7, [[], [1, 3], [0, 2, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 10/21, 11/21, 1], 是, [], 1, 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0085/)

σ-代數與測度空間 · qf-mod23-measure-probability-measure-audit · candidate





## 86. 有限測度空間

完整有限載體與canonical集合族。操作=measure-probability-measure-audit；資料={"n":7,"family":[[],[0,1,3],[2,4,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[11,23],[12,23],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,total,finite_countable_reduction,probability_measure] 欄序回答。

查看答案與解釋(7, [[], [0, 1, 3], [2, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 11/23, 12/23, 1], 是, [], 1, 是, 是)

現代橋梁核對=(7, [[], [0, 1, 3], [2, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 11/23, 12/23, 1], 是, [], 1, 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0086/)

σ-代數與測度空間 · qf-mod23-measure-probability-measure-audit · candidate





## 87. 有限測度空間

完整有限載體與canonical集合族。操作=measure-probability-measure-audit；資料={"n":7,"family":[[],[2,3],[0,1,4,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[12,25],[13,25],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,total,finite_countable_reduction,probability_measure] 欄序回答。

查看答案與解釋(7, [[], [2, 3], [0, 1, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 12/25, 13/25, 1], 是, [], 1, 是, 是)

現代橋梁核對=(7, [[], [2, 3], [0, 1, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 12/25, 13/25, 1], 是, [], 1, 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0087/)

σ-代數與測度空間 · qf-mod23-measure-probability-measure-audit · candidate





## 88. 有限測度空間

完整有限載體與canonical集合族。操作=measure-probability-measure-audit；資料={"n":7,"family":[[],[0,2,3],[1,4,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[13,27],[14,27],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,total,finite_countable_reduction,probability_measure] 欄序回答。

查看答案與解釋(7, [[], [0, 2, 3], [1, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 13/27, 14/27, 1], 是, [], 1, 是, 是)

現代橋梁核對=(7, [[], [0, 2, 3], [1, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 13/27, 14/27, 1], 是, [], 1, 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0088/)

σ-代數與測度空間 · qf-mod23-measure-probability-measure-audit · candidate





## 89. 有限測度空間

完整有限載體與canonical集合族。操作=measure-probability-measure-audit；資料={"n":7,"family":[[],[1,2,3],[0,4,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[14,29],[15,29],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,total,finite_countable_reduction,probability_measure] 欄序回答。

查看答案與解釋(7, [[], [1, 2, 3], [0, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 14/29, 15/29, 1], 是, [], 1, 是, 是)

現代橋梁核對=(7, [[], [1, 2, 3], [0, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 14/29, 15/29, 1], 是, [], 1, 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0089/)

σ-代數與測度空間 · qf-mod23-measure-probability-measure-audit · candidate





## 90. 有限測度空間

完整有限載體與canonical集合族。操作=measure-probability-measure-audit；資料={"n":7,"family":[[],[0,1,2,3],[4,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[15,31],[16,31],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,total,finite_countable_reduction,probability_measure] 欄序回答。

查看答案與解釋(7, [[], [0, 1, 2, 3], [4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 15/31, 16/31, 1], 是, [], 1, 是, 是)

現代橋梁核對=(7, [[], [0, 1, 2, 3], [4, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 15/31, 16/31, 1], 是, [], 1, 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0090/)

σ-代數與測度空間 · qf-mod23-measure-probability-measure-audit · candidate





## 91. 有限測度空間

完整有限載體與canonical集合族。操作=measure-probability-measure-audit；資料={"n":7,"family":[[],[4],[0,1,2,3,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[16,33],[17,33],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,total,finite_countable_reduction,probability_measure] 欄序回答。

查看答案與解釋(7, [[], [4], [0, 1, 2, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 16/33, 17/33, 1], 是, [], 1, 是, 是)

現代橋梁核對=(7, [[], [4], [0, 1, 2, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 16/33, 17/33, 1], 是, [], 1, 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0091/)

σ-代數與測度空間 · qf-mod23-measure-probability-measure-audit · candidate





## 92. 有限測度空間

完整有限載體與canonical集合族。操作=measure-probability-measure-audit；資料={"n":7,"family":[[],[0,4],[1,2,3,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[17,35],[18,35],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,total,finite_countable_reduction,probability_measure] 欄序回答。

查看答案與解釋(7, [[], [0, 4], [1, 2, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 17/35, 18/35, 1], 是, [], 1, 是, 是)

現代橋梁核對=(7, [[], [0, 4], [1, 2, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 17/35, 18/35, 1], 是, [], 1, 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0092/)

σ-代數與測度空間 · qf-mod23-measure-probability-measure-audit · candidate





## 93. 有限測度空間

完整有限載體與canonical集合族。操作=measure-probability-measure-audit；資料={"n":7,"family":[[],[1,4],[0,2,3,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[18,37],[19,37],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,total,finite_countable_reduction,probability_measure] 欄序回答。

查看答案與解釋(7, [[], [1, 4], [0, 2, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 18/37, 19/37, 1], 是, [], 1, 是, 是)

現代橋梁核對=(7, [[], [1, 4], [0, 2, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 18/37, 19/37, 1], 是, [], 1, 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0093/)

σ-代數與測度空間 · qf-mod23-measure-probability-measure-audit · candidate





## 94. 有限測度空間

完整有限載體與canonical集合族。操作=measure-probability-measure-audit；資料={"n":7,"family":[[],[0,1,4],[2,3,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[19,39],[20,39],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,total,finite_countable_reduction,probability_measure] 欄序回答。

查看答案與解釋(7, [[], [0, 1, 4], [2, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 19/39, 20/39, 1], 是, [], 1, 是, 是)

現代橋梁核對=(7, [[], [0, 1, 4], [2, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 19/39, 20/39, 1], 是, [], 1, 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0094/)

σ-代數與測度空間 · qf-mod23-measure-probability-measure-audit · candidate





## 95. 有限測度空間

完整有限載體與canonical集合族。操作=measure-probability-measure-audit；資料={"n":7,"family":[[],[2,4],[0,1,3,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[20,41],[21,41],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,total,finite_countable_reduction,probability_measure] 欄序回答。

查看答案與解釋(7, [[], [2, 4], [0, 1, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 20/41, 21/41, 1], 是, [], 1, 是, 是)

現代橋梁核對=(7, [[], [2, 4], [0, 1, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 20/41, 21/41, 1], 是, [], 1, 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0095/)

σ-代數與測度空間 · qf-mod23-measure-probability-measure-audit · candidate





## 96. 有限測度空間

完整有限載體與canonical集合族。操作=measure-probability-measure-audit；資料={"n":7,"family":[[],[0,2,4],[1,3,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[21,43],[22,43],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,total,finite_countable_reduction,probability_measure] 欄序回答。

查看答案與解釋(7, [[], [0, 2, 4], [1, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 21/43, 22/43, 1], 是, [], 1, 是, 是)

現代橋梁核對=(7, [[], [0, 2, 4], [1, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 21/43, 22/43, 1], 是, [], 1, 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0096/)

σ-代數與測度空間 · qf-mod23-measure-probability-measure-audit · candidate





## 97. 有限測度空間

完整有限載體與canonical集合族。操作=measure-probability-measure-audit；資料={"n":7,"family":[[],[1,2,4],[0,3,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[22,45],[23,45],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,total,finite_countable_reduction,probability_measure] 欄序回答。

查看答案與解釋(7, [[], [1, 2, 4], [0, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 22/45, 23/45, 1], 是, [], 1, 是, 是)

現代橋梁核對=(7, [[], [1, 2, 4], [0, 3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 22/45, 23/45, 1], 是, [], 1, 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0097/)

σ-代數與測度空間 · qf-mod23-measure-probability-measure-audit · candidate





## 98. 有限測度空間

完整有限載體與canonical集合族。操作=measure-probability-measure-audit；資料={"n":7,"family":[[],[0,1,2,4],[3,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[23,47],[24,47],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,total,finite_countable_reduction,probability_measure] 欄序回答。

查看答案與解釋(7, [[], [0, 1, 2, 4], [3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 23/47, 24/47, 1], 是, [], 1, 是, 是)

現代橋梁核對=(7, [[], [0, 1, 2, 4], [3, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 23/47, 24/47, 1], 是, [], 1, 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0098/)

σ-代數與測度空間 · qf-mod23-measure-probability-measure-audit · candidate





## 99. 有限測度空間

完整有限載體與canonical集合族。操作=measure-probability-measure-audit；資料={"n":7,"family":[[],[3,4],[0,1,2,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[24,49],[25,49],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,total,finite_countable_reduction,probability_measure] 欄序回答。

查看答案與解釋(7, [[], [3, 4], [0, 1, 2, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 24/49, 25/49, 1], 是, [], 1, 是, 是)

現代橋梁核對=(7, [[], [3, 4], [0, 1, 2, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 24/49, 25/49, 1], 是, [], 1, 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0099/)

σ-代數與測度空間 · qf-mod23-measure-probability-measure-audit · candidate





## 100. 有限測度空間

完整有限載體與canonical集合族。操作=measure-probability-measure-audit；資料={"n":7,"family":[[],[0,3,4],[1,2,5,6],[0,1,2,3,4,5,6]],"values":[[0,1],[25,51],[26,51],[1,1]]}。請依 [n,family,values,empty_zero,bad_disjoint_pairs,total,finite_countable_reduction,probability_measure] 欄序回答。

查看答案與解釋(7, [[], [0, 3, 4], [1, 2, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 25/51, 26/51, 1], 是, [], 1, 是, 是)

現代橋梁核對=(7, [[], [0, 3, 4], [1, 2, 5, 6], [0, 1, 2, 3, 4, 5, 6]], [0, 25/51, 26/51, 1], 是, [], 1, 是, 是)；依完整明示資料重算；完整明示的有限／精確切片不自動升格為一般無限結論；可數語義只由指定有限載體歸約；不外推任意無限測度空間。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261013-advance-20261023-r05-sigma-algebra-measure-space-0100/)

σ-代數與測度空間 · qf-mod23-measure-probability-measure-audit · candidate



[原始題目 JSONL](https://ocme.evemisslab.com/data/questions/batches/batch-20261013-advance-20261023-r05-sigma-algebra-measure-space-foundations/questions.jsonl) · [驗收報告](https://ocme.evemisslab.com/data/questions/batches/batch-20261013-advance-20261023-r05-sigma-algebra-measure-space-foundations/validation-report.json)