# 依機率收斂基礎 · 脈衝 R07

本批已通過 Schema、去重、來源快照與獨立答案重算；仍未標記為人工審定。

本題庫已有對應的中英逐步詳解。原題的 candidate 與英文 ai_candidate 狀態保留；AI 覆核、有限計算與 Lean 形式證明分開標示。

batch-20261014-advance-20261030-r07-convergence-in-probability-foundations · 2026-10-14 · 100 題



## 1. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability；資料={"numerator":1,"shift":2,"n":1}。請依 [numerator,shift,n,probability] 欄序回答。

查看答案與解釋(1, 2, 1, 1/3)

Wave4第四層核對=(1, 2, 1, 1/3)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0001/)

依機率收斂 · qf-mod30-convprob-deviation-probability · candidate





## 2. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability；資料={"numerator":2,"shift":3,"n":2}。請依 [numerator,shift,n,probability] 欄序回答。

查看答案與解釋(2, 3, 2, 2/5)

Wave4第四層核對=(2, 3, 2, 2/5)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0002/)

依機率收斂 · qf-mod30-convprob-deviation-probability · candidate





## 3. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability；資料={"numerator":3,"shift":4,"n":3}。請依 [numerator,shift,n,probability] 欄序回答。

查看答案與解釋(3, 4, 3, 3/7)

Wave4第四層核對=(3, 4, 3, 3/7)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0003/)

依機率收斂 · qf-mod30-convprob-deviation-probability · candidate





## 4. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability；資料={"numerator":4,"shift":5,"n":4}。請依 [numerator,shift,n,probability] 欄序回答。

查看答案與解釋(4, 5, 4, 4/9)

Wave4第四層核對=(4, 5, 4, 4/9)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0004/)

依機率收斂 · qf-mod30-convprob-deviation-probability · candidate





## 5. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability；資料={"numerator":5,"shift":6,"n":5}。請依 [numerator,shift,n,probability] 欄序回答。

查看答案與解釋(5, 6, 5, 5/11)

Wave4第四層核對=(5, 6, 5, 5/11)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0005/)

依機率收斂 · qf-mod30-convprob-deviation-probability · candidate





## 6. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability；資料={"numerator":1,"shift":7,"n":6}。請依 [numerator,shift,n,probability] 欄序回答。

查看答案與解釋(1, 7, 6, 1/13)

Wave4第四層核對=(1, 7, 6, 1/13)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0006/)

依機率收斂 · qf-mod30-convprob-deviation-probability · candidate





## 7. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability；資料={"numerator":2,"shift":8,"n":7}。請依 [numerator,shift,n,probability] 欄序回答。

查看答案與解釋(2, 8, 7, 2/15)

Wave4第四層核對=(2, 8, 7, 2/15)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0007/)

依機率收斂 · qf-mod30-convprob-deviation-probability · candidate





## 8. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability；資料={"numerator":3,"shift":2,"n":8}。請依 [numerator,shift,n,probability] 欄序回答。

查看答案與解釋(3, 2, 8, 3/10)

Wave4第四層核對=(3, 2, 8, 3/10)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0008/)

依機率收斂 · qf-mod30-convprob-deviation-probability · candidate





## 9. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability；資料={"numerator":4,"shift":3,"n":9}。請依 [numerator,shift,n,probability] 欄序回答。

查看答案與解釋(4, 3, 9, 1/3)

Wave4第四層核對=(4, 3, 9, 1/3)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0009/)

依機率收斂 · qf-mod30-convprob-deviation-probability · candidate





## 10. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability；資料={"numerator":5,"shift":4,"n":10}。請依 [numerator,shift,n,probability] 欄序回答。

查看答案與解釋(5, 4, 10, 5/14)

Wave4第四層核對=(5, 4, 10, 5/14)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0010/)

依機率收斂 · qf-mod30-convprob-deviation-probability · candidate





## 11. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability；資料={"numerator":1,"shift":5,"n":11}。請依 [numerator,shift,n,probability] 欄序回答。

查看答案與解釋(1, 5, 11, 1/16)

Wave4第四層核對=(1, 5, 11, 1/16)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0011/)

依機率收斂 · qf-mod30-convprob-deviation-probability · candidate





## 12. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability；資料={"numerator":2,"shift":6,"n":12}。請依 [numerator,shift,n,probability] 欄序回答。

查看答案與解釋(2, 6, 12, 1/9)

Wave4第四層核對=(2, 6, 12, 1/9)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0012/)

依機率收斂 · qf-mod30-convprob-deviation-probability · candidate





## 13. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability；資料={"numerator":3,"shift":7,"n":13}。請依 [numerator,shift,n,probability] 欄序回答。

查看答案與解釋(3, 7, 13, 3/20)

Wave4第四層核對=(3, 7, 13, 3/20)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0013/)

依機率收斂 · qf-mod30-convprob-deviation-probability · candidate





## 14. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability；資料={"numerator":4,"shift":8,"n":14}。請依 [numerator,shift,n,probability] 欄序回答。

查看答案與解釋(4, 8, 14, 2/11)

Wave4第四層核對=(4, 8, 14, 2/11)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0014/)

依機率收斂 · qf-mod30-convprob-deviation-probability · candidate





## 15. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability；資料={"numerator":5,"shift":2,"n":15}。請依 [numerator,shift,n,probability] 欄序回答。

查看答案與解釋(5, 2, 15, 5/17)

Wave4第四層核對=(5, 2, 15, 5/17)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0015/)

依機率收斂 · qf-mod30-convprob-deviation-probability · candidate





## 16. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability；資料={"numerator":1,"shift":3,"n":16}。請依 [numerator,shift,n,probability] 欄序回答。

查看答案與解釋(1, 3, 16, 1/19)

Wave4第四層核對=(1, 3, 16, 1/19)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0016/)

依機率收斂 · qf-mod30-convprob-deviation-probability · candidate





## 17. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability；資料={"numerator":2,"shift":4,"n":17}。請依 [numerator,shift,n,probability] 欄序回答。

查看答案與解釋(2, 4, 17, 2/21)

Wave4第四層核對=(2, 4, 17, 2/21)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0017/)

依機率收斂 · qf-mod30-convprob-deviation-probability · candidate





## 18. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability；資料={"numerator":3,"shift":5,"n":18}。請依 [numerator,shift,n,probability] 欄序回答。

查看答案與解釋(3, 5, 18, 3/23)

Wave4第四層核對=(3, 5, 18, 3/23)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0018/)

依機率收斂 · qf-mod30-convprob-deviation-probability · candidate





## 19. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability；資料={"numerator":4,"shift":6,"n":19}。請依 [numerator,shift,n,probability] 欄序回答。

查看答案與解釋(4, 6, 19, 4/25)

Wave4第四層核對=(4, 6, 19, 4/25)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0019/)

依機率收斂 · qf-mod30-convprob-deviation-probability · candidate





## 20. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability；資料={"numerator":5,"shift":7,"n":20}。請依 [numerator,shift,n,probability] 欄序回答。

查看答案與解釋(5, 7, 20, 5/27)

Wave4第四層核對=(5, 7, 20, 5/27)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0020/)

依機率收斂 · qf-mod30-convprob-deviation-probability · candidate





## 21. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability；資料={"numerator":1,"shift":8,"n":21}。請依 [numerator,shift,n,probability] 欄序回答。

查看答案與解釋(1, 8, 21, 1/29)

Wave4第四層核對=(1, 8, 21, 1/29)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0021/)

依機率收斂 · qf-mod30-convprob-deviation-probability · candidate





## 22. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability；資料={"numerator":2,"shift":2,"n":22}。請依 [numerator,shift,n,probability] 欄序回答。

查看答案與解釋(2, 2, 22, 1/12)

Wave4第四層核對=(2, 2, 22, 1/12)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0022/)

依機率收斂 · qf-mod30-convprob-deviation-probability · candidate





## 23. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability；資料={"numerator":3,"shift":3,"n":23}。請依 [numerator,shift,n,probability] 欄序回答。

查看答案與解釋(3, 3, 23, 3/26)

Wave4第四層核對=(3, 3, 23, 3/26)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0023/)

依機率收斂 · qf-mod30-convprob-deviation-probability · candidate





## 24. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability；資料={"numerator":4,"shift":4,"n":24}。請依 [numerator,shift,n,probability] 欄序回答。

查看答案與解釋(4, 4, 24, 1/7)

Wave4第四層核對=(4, 4, 24, 1/7)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0024/)

依機率收斂 · qf-mod30-convprob-deviation-probability · candidate





## 25. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability；資料={"numerator":5,"shift":5,"n":25}。請依 [numerator,shift,n,probability] 欄序回答。

查看答案與解釋(5, 5, 25, 1/6)

Wave4第四層核對=(5, 5, 25, 1/6)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0025/)

依機率收斂 · qf-mod30-convprob-deviation-probability · candidate





## 26. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness；資料={"numerator":1,"shift":2,"delta":[1,10]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。

查看答案與解釋(1, 2, 1/10, 9, 1/11, 是, forall_n_ge_N_tail_bound)

Wave4第四層核對=(1, 2, 1/10, 9, 1/11, 是, forall_n_ge_N_tail_bound)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0026/)

依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate





## 27. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness；資料={"numerator":2,"shift":3,"delta":[1,11]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。

查看答案與解釋(2, 3, 1/11, 20, 2/23, 是, forall_n_ge_N_tail_bound)

Wave4第四層核對=(2, 3, 1/11, 20, 2/23, 是, forall_n_ge_N_tail_bound)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0027/)

依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate





## 28. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness；資料={"numerator":3,"shift":4,"delta":[1,12]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。

查看答案與解釋(3, 4, 1/12, 33, 3/37, 是, forall_n_ge_N_tail_bound)

Wave4第四層核對=(3, 4, 1/12, 33, 3/37, 是, forall_n_ge_N_tail_bound)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0028/)

依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate





## 29. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness；資料={"numerator":4,"shift":5,"delta":[1,13]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。

查看答案與解釋(4, 5, 1/13, 48, 4/53, 是, forall_n_ge_N_tail_bound)

Wave4第四層核對=(4, 5, 1/13, 48, 4/53, 是, forall_n_ge_N_tail_bound)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0029/)

依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate





## 30. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness；資料={"numerator":5,"shift":6,"delta":[1,14]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。

查看答案與解釋(5, 6, 1/14, 65, 5/71, 是, forall_n_ge_N_tail_bound)

Wave4第四層核對=(5, 6, 1/14, 65, 5/71, 是, forall_n_ge_N_tail_bound)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0030/)

依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate





## 31. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness；資料={"numerator":1,"shift":7,"delta":[1,15]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。

查看答案與解釋(1, 7, 1/15, 9, 1/16, 是, forall_n_ge_N_tail_bound)

Wave4第四層核對=(1, 7, 1/15, 9, 1/16, 是, forall_n_ge_N_tail_bound)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0031/)

依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate





## 32. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness；資料={"numerator":2,"shift":8,"delta":[1,16]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。

查看答案與解釋(2, 8, 1/16, 25, 2/33, 是, forall_n_ge_N_tail_bound)

Wave4第四層核對=(2, 8, 1/16, 25, 2/33, 是, forall_n_ge_N_tail_bound)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0032/)

依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate





## 33. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness；資料={"numerator":3,"shift":2,"delta":[1,17]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。

查看答案與解釋(3, 2, 1/17, 50, 3/52, 是, forall_n_ge_N_tail_bound)

Wave4第四層核對=(3, 2, 1/17, 50, 3/52, 是, forall_n_ge_N_tail_bound)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0033/)

依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate





## 34. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness；資料={"numerator":4,"shift":3,"delta":[1,18]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。

查看答案與解釋(4, 3, 1/18, 70, 4/73, 是, forall_n_ge_N_tail_bound)

Wave4第四層核對=(4, 3, 1/18, 70, 4/73, 是, forall_n_ge_N_tail_bound)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0034/)

依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate





## 35. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness；資料={"numerator":5,"shift":4,"delta":[1,19]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。

查看答案與解釋(5, 4, 1/19, 92, 5/96, 是, forall_n_ge_N_tail_bound)

Wave4第四層核對=(5, 4, 1/19, 92, 5/96, 是, forall_n_ge_N_tail_bound)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0035/)

依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate





## 36. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness；資料={"numerator":1,"shift":5,"delta":[1,20]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。

查看答案與解釋(1, 5, 1/20, 16, 1/21, 是, forall_n_ge_N_tail_bound)

Wave4第四層核對=(1, 5, 1/20, 16, 1/21, 是, forall_n_ge_N_tail_bound)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0036/)

依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate





## 37. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness；資料={"numerator":2,"shift":6,"delta":[1,21]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。

查看答案與解釋(2, 6, 1/21, 37, 2/43, 是, forall_n_ge_N_tail_bound)

Wave4第四層核對=(2, 6, 1/21, 37, 2/43, 是, forall_n_ge_N_tail_bound)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0037/)

依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate





## 38. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness；資料={"numerator":3,"shift":7,"delta":[1,22]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。

查看答案與解釋(3, 7, 1/22, 60, 3/67, 是, forall_n_ge_N_tail_bound)

Wave4第四層核對=(3, 7, 1/22, 60, 3/67, 是, forall_n_ge_N_tail_bound)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0038/)

依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate





## 39. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness；資料={"numerator":4,"shift":8,"delta":[1,23]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。

查看答案與解釋(4, 8, 1/23, 85, 4/93, 是, forall_n_ge_N_tail_bound)

Wave4第四層核對=(4, 8, 1/23, 85, 4/93, 是, forall_n_ge_N_tail_bound)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0039/)

依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate





## 40. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness；資料={"numerator":5,"shift":2,"delta":[1,24]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。

查看答案與解釋(5, 2, 1/24, 119, 5/121, 是, forall_n_ge_N_tail_bound)

Wave4第四層核對=(5, 2, 1/24, 119, 5/121, 是, forall_n_ge_N_tail_bound)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0040/)

依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate





## 41. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness；資料={"numerator":1,"shift":3,"delta":[1,25]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。

查看答案與解釋(1, 3, 1/25, 23, 1/26, 是, forall_n_ge_N_tail_bound)

Wave4第四層核對=(1, 3, 1/25, 23, 1/26, 是, forall_n_ge_N_tail_bound)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0041/)

依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate





## 42. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness；資料={"numerator":2,"shift":4,"delta":[1,26]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。

查看答案與解釋(2, 4, 1/26, 49, 2/53, 是, forall_n_ge_N_tail_bound)

Wave4第四層核對=(2, 4, 1/26, 49, 2/53, 是, forall_n_ge_N_tail_bound)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0042/)

依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate





## 43. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness；資料={"numerator":3,"shift":5,"delta":[1,27]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。

查看答案與解釋(3, 5, 1/27, 77, 3/82, 是, forall_n_ge_N_tail_bound)

Wave4第四層核對=(3, 5, 1/27, 77, 3/82, 是, forall_n_ge_N_tail_bound)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0043/)

依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate





## 44. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness；資料={"numerator":4,"shift":6,"delta":[1,28]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。

查看答案與解釋(4, 6, 1/28, 107, 4/113, 是, forall_n_ge_N_tail_bound)

Wave4第四層核對=(4, 6, 1/28, 107, 4/113, 是, forall_n_ge_N_tail_bound)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0044/)

依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate





## 45. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness；資料={"numerator":5,"shift":7,"delta":[1,29]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。

查看答案與解釋(5, 7, 1/29, 139, 5/146, 是, forall_n_ge_N_tail_bound)

Wave4第四層核對=(5, 7, 1/29, 139, 5/146, 是, forall_n_ge_N_tail_bound)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0045/)

依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate





## 46. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness；資料={"numerator":1,"shift":8,"delta":[1,30]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。

查看答案與解釋(1, 8, 1/30, 23, 1/31, 是, forall_n_ge_N_tail_bound)

Wave4第四層核對=(1, 8, 1/30, 23, 1/31, 是, forall_n_ge_N_tail_bound)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0046/)

依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate





## 47. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness；資料={"numerator":2,"shift":2,"delta":[1,31]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。

查看答案與解釋(2, 2, 1/31, 61, 2/63, 是, forall_n_ge_N_tail_bound)

Wave4第四層核對=(2, 2, 1/31, 61, 2/63, 是, forall_n_ge_N_tail_bound)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0047/)

依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate





## 48. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness；資料={"numerator":3,"shift":3,"delta":[1,32]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。

查看答案與解釋(3, 3, 1/32, 94, 3/97, 是, forall_n_ge_N_tail_bound)

Wave4第四層核對=(3, 3, 1/32, 94, 3/97, 是, forall_n_ge_N_tail_bound)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0048/)

依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate





## 49. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness；資料={"numerator":4,"shift":4,"delta":[1,33]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。

查看答案與解釋(4, 4, 1/33, 129, 4/133, 是, forall_n_ge_N_tail_bound)

Wave4第四層核對=(4, 4, 1/33, 129, 4/133, 是, forall_n_ge_N_tail_bound)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0049/)

依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate





## 50. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness；資料={"numerator":5,"shift":5,"delta":[1,34]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。

查看答案與解釋(5, 5, 1/34, 166, 5/171, 是, forall_n_ge_N_tail_bound)

Wave4第四層核對=(5, 5, 1/34, 166, 5/171, 是, forall_n_ge_N_tail_bound)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0050/)

依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate





## 51. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary；資料={"numerator":1,"shift":2,"prefix_length":1}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。

查看答案與解釋(1, 2, 1, [1/2], 否, finite_prefix_not_convergence_certificate)

Wave4第四層核對=(1, 2, 1, [1/2], 否, finite_prefix_not_convergence_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0051/)

依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate





## 52. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary；資料={"numerator":2,"shift":3,"prefix_length":2}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。

查看答案與解釋(2, 3, 2, [2/3, 1/2], 否, finite_prefix_not_convergence_certificate)

Wave4第四層核對=(2, 3, 2, [2/3, 1/2], 否, finite_prefix_not_convergence_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0052/)

依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate





## 53. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary；資料={"numerator":3,"shift":4,"prefix_length":3}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。

查看答案與解釋(3, 4, 3, [3/4, 3/5, 1/2], 否, finite_prefix_not_convergence_certificate)

Wave4第四層核對=(3, 4, 3, [3/4, 3/5, 1/2], 否, finite_prefix_not_convergence_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0053/)

依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate





## 54. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary；資料={"numerator":4,"shift":5,"prefix_length":4}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。

查看答案與解釋(4, 5, 4, [4/5, 2/3, 4/7, 1/2], 否, finite_prefix_not_convergence_certificate)

Wave4第四層核對=(4, 5, 4, [4/5, 2/3, 4/7, 1/2], 否, finite_prefix_not_convergence_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0054/)

依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate





## 55. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary；資料={"numerator":5,"shift":6,"prefix_length":5}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。

查看答案與解釋(5, 6, 5, [5/6, 5/7, 5/8, 5/9, 1/2], 否, finite_prefix_not_convergence_certificate)

Wave4第四層核對=(5, 6, 5, [5/6, 5/7, 5/8, 5/9, 1/2], 否, finite_prefix_not_convergence_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0055/)

依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate





## 56. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary；資料={"numerator":1,"shift":7,"prefix_length":6}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。

查看答案與解釋(1, 7, 6, [1/7, 1/8, 1/9, 1/10, 1/11, 1/12], 否, finite_prefix_not_convergence_certificate)

Wave4第四層核對=(1, 7, 6, [1/7, 1/8, 1/9, 1/10, 1/11, 1/12], 否, finite_prefix_not_convergence_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0056/)

依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate





## 57. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary；資料={"numerator":2,"shift":8,"prefix_length":7}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。

查看答案與解釋(2, 8, 7, [1/4, 2/9, 1/5, 2/11, 1/6, 2/13, 1/7], 否, finite_prefix_not_convergence_certificate)

Wave4第四層核對=(2, 8, 7, [1/4, 2/9, 1/5, 2/11, 1/6, 2/13, 1/7], 否, finite_prefix_not_convergence_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0057/)

依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate





## 58. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary；資料={"numerator":3,"shift":3,"prefix_length":8}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。

查看答案與解釋(3, 3, 8, [1, 3/4, 3/5, 1/2, 3/7, 3/8, 1/3, 3/10], 否, finite_prefix_not_convergence_certificate)

Wave4第四層核對=(3, 3, 8, [1, 3/4, 3/5, 1/2, 3/7, 3/8, 1/3, 3/10], 否, finite_prefix_not_convergence_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0058/)

依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate





## 59. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary；資料={"numerator":4,"shift":4,"prefix_length":9}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。

查看答案與解釋(4, 4, 9, [1, 4/5, 2/3, 4/7, 1/2, 4/9, 2/5, 4/11, 1/3], 否, finite_prefix_not_convergence_certificate)

Wave4第四層核對=(4, 4, 9, [1, 4/5, 2/3, 4/7, 1/2, 4/9, 2/5, 4/11, 1/3], 否, finite_prefix_not_convergence_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0059/)

依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate





## 60. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary；資料={"numerator":5,"shift":5,"prefix_length":10}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。

查看答案與解釋(5, 5, 10, [1, 5/6, 5/7, 5/8, 5/9, 1/2, 5/11, 5/12, 5/13, 5/14], 否, finite_prefix_not_convergence_certificate)

Wave4第四層核對=(5, 5, 10, [1, 5/6, 5/7, 5/8, 5/9, 1/2, 5/11, 5/12, 5/13, 5/14], 否, finite_prefix_not_convergence_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0060/)

依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate





## 61. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary；資料={"numerator":1,"shift":5,"prefix_length":11}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。

查看答案與解釋(1, 5, 11, [1/5, 1/6, 1/7, 1/8, 1/9, 1/10, 1/11, 1/12, 1/13, 1/14, 1/15], 否, finite_prefix_not_convergence_certificate)

Wave4第四層核對=(1, 5, 11, [1/5, 1/6, 1/7, 1/8, 1/9, 1/10, 1/11, 1/12, 1/13, 1/14, 1/15], 否, finite_prefix_not_convergence_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0061/)

依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate





## 62. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary；資料={"numerator":2,"shift":6,"prefix_length":12}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。

查看答案與解釋(2, 6, 12, [1/3, 2/7, 1/4, 2/9, 1/5, 2/11, 1/6, 2/13, 1/7, 2/15, 1/8, 2/17], 否, finite_prefix_not_convergence_certificate)

Wave4第四層核對=(2, 6, 12, [1/3, 2/7, 1/4, 2/9, 1/5, 2/11, 1/6, 2/13, 1/7, 2/15, 1/8, 2/17], 否, finite_prefix_not_convergence_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0062/)

依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate





## 63. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary；資料={"numerator":3,"shift":7,"prefix_length":13}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。

查看答案與解釋(3, 7, 13, [3/7, 3/8, 1/3, 3/10, 3/11, 1/4, 3/13, 3/14, 1/5, 3/16, 3/17, 1/6, 3/19], 否, finite_prefix_not_convergence_certificate)

Wave4第四層核對=(3, 7, 13, [3/7, 3/8, 1/3, 3/10, 3/11, 1/4, 3/13, 3/14, 1/5, 3/16, 3/17, 1/6, 3/19], 否, finite_prefix_not_convergence_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0063/)

依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate





## 64. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary；資料={"numerator":4,"shift":8,"prefix_length":14}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。

查看答案與解釋(4, 8, 14, [1/2, 4/9, 2/5, 4/11, 1/3, 4/13, 2/7, 4/15, 1/4, 4/17, 2/9, 4/19, 1/5, 4/21], 否, finite_prefix_not_convergence_certificate)

Wave4第四層核對=(4, 8, 14, [1/2, 4/9, 2/5, 4/11, 1/3, 4/13, 2/7, 4/15, 1/4, 4/17, 2/9, 4/19, 1/5, 4/21], 否, finite_prefix_not_convergence_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0064/)

依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate





## 65. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary；資料={"numerator":5,"shift":5,"prefix_length":15}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。

查看答案與解釋(5, 5, 15, [1, 5/6, 5/7, 5/8, 5/9, 1/2, 5/11, 5/12, 5/13, 5/14, 1/3, 5/16, 5/17, 5/18, 5/19], 否, finite_prefix_not_convergence_certificate)

Wave4第四層核對=(5, 5, 15, [1, 5/6, 5/7, 5/8, 5/9, 1/2, 5/11, 5/12, 5/13, 5/14, 1/3, 5/16, 5/17, 5/18, 5/19], 否, finite_prefix_not_convergence_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0065/)

依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate





## 66. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary；資料={"numerator":1,"shift":3,"prefix_length":16}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。

查看答案與解釋(1, 3, 16, [1/3, 1/4, 1/5, 1/6, 1/7, 1/8, 1/9, 1/10, 1/11, 1/12, 1/13, 1/14, 1/15, 1/16, 1/17, 1/18], 否, finite_prefix_not_convergence_certificate)

Wave4第四層核對=(1, 3, 16, [1/3, 1/4, 1/5, 1/6, 1/7, 1/8, 1/9, 1/10, 1/11, 1/12, 1/13, 1/14, 1/15, 1/16, 1/17, 1/18], 否, finite_prefix_not_convergence_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0066/)

依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate





## 67. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary；資料={"numerator":2,"shift":4,"prefix_length":17}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。

查看答案與解釋(2, 4, 17, [1/2, 2/5, 1/3, 2/7, 1/4, 2/9, 1/5, 2/11, 1/6, 2/13, 1/7, 2/15, 1/8, 2/17, 1/9, 2/19, 1/10], 否, finite_prefix_not_convergence_certificate)

Wave4第四層核對=(2, 4, 17, [1/2, 2/5, 1/3, 2/7, 1/4, 2/9, 1/5, 2/11, 1/6, 2/13, 1/7, 2/15, 1/8, 2/17, 1/9, 2/19, 1/10], 否, finite_prefix_not_convergence_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0067/)

依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate





## 68. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary；資料={"numerator":3,"shift":5,"prefix_length":18}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。

查看答案與解釋(3, 5, 18, [3/5, 1/2, 3/7, 3/8, 1/3, 3/10, 3/11, 1/4, 3/13, 3/14, 1/5, 3/16, 3/17, 1/6, 3/19, 3/20, 1/7, 3/22], 否, finite_prefix_not_convergence_certificate)

Wave4第四層核對=(3, 5, 18, [3/5, 1/2, 3/7, 3/8, 1/3, 3/10, 3/11, 1/4, 3/13, 3/14, 1/5, 3/16, 3/17, 1/6, 3/19, 3/20, 1/7, 3/22], 否, finite_prefix_not_convergence_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0068/)

依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate





## 69. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary；資料={"numerator":4,"shift":6,"prefix_length":19}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。

查看答案與解釋(4, 6, 19, [2/3, 4/7, 1/2, 4/9, 2/5, 4/11, 1/3, 4/13, 2/7, 4/15, 1/4, 4/17, 2/9, 4/19, 1/5, 4/21, 2/11, 4/23, 1/6], 否, finite_prefix_not_convergence_certificate)

Wave4第四層核對=(4, 6, 19, [2/3, 4/7, 1/2, 4/9, 2/5, 4/11, 1/3, 4/13, 2/7, 4/15, 1/4, 4/17, 2/9, 4/19, 1/5, 4/21, 2/11, 4/23, 1/6], 否, finite_prefix_not_convergence_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0069/)

依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate





## 70. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary；資料={"numerator":5,"shift":7,"prefix_length":20}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。

查看答案與解釋(5, 7, 20, [5/7, 5/8, 5/9, 1/2, 5/11, 5/12, 5/13, 5/14, 1/3, 5/16, 5/17, 5/18, 5/19, 1/4, 5/21, 5/22, 5/23, 5/24, 1/5, 5/26], 否, finite_prefix_not_convergence_certificate)

Wave4第四層核對=(5, 7, 20, [5/7, 5/8, 5/9, 1/2, 5/11, 5/12, 5/13, 5/14, 1/3, 5/16, 5/17, 5/18, 5/19, 1/4, 5/21, 5/22, 5/23, 5/24, 1/5, 5/26], 否, finite_prefix_not_convergence_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0070/)

依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate





## 71. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary；資料={"numerator":1,"shift":8,"prefix_length":21}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。

查看答案與解釋(1, 8, 21, [1/8, 1/9, 1/10, 1/11, 1/12, 1/13, 1/14, 1/15, 1/16, 1/17, 1/18, 1/19, 1/20, 1/21, 1/22, 1/23, 1/24, 1/25, 1/26, 1/27, 1/28], 否, finite_prefix_not_convergence_certificate)

Wave4第四層核對=(1, 8, 21, [1/8, 1/9, 1/10, 1/11, 1/12, 1/13, 1/14, 1/15, 1/16, 1/17, 1/18, 1/19, 1/20, 1/21, 1/22, 1/23, 1/24, 1/25, 1/26, 1/27, 1/28], 否, finite_prefix_not_convergence_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0071/)

依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate





## 72. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary；資料={"numerator":2,"shift":2,"prefix_length":22}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。

查看答案與解釋(2, 2, 22, [1, 2/3, 1/2, 2/5, 1/3, 2/7, 1/4, 2/9, 1/5, 2/11, 1/6, 2/13, 1/7, 2/15, 1/8, 2/17, 1/9, 2/19, 1/10, 2/21, 1/11, 2/23], 否, finite_prefix_not_convergence_certificate)

Wave4第四層核對=(2, 2, 22, [1, 2/3, 1/2, 2/5, 1/3, 2/7, 1/4, 2/9, 1/5, 2/11, 1/6, 2/13, 1/7, 2/15, 1/8, 2/17, 1/9, 2/19, 1/10, 2/21, 1/11, 2/23], 否, finite_prefix_not_convergence_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0072/)

依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate





## 73. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary；資料={"numerator":3,"shift":3,"prefix_length":23}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。

查看答案與解釋(3, 3, 23, [1, 3/4, 3/5, 1/2, 3/7, 3/8, 1/3, 3/10, 3/11, 1/4, 3/13, 3/14, 1/5, 3/16, 3/17, 1/6, 3/19, 3/20, 1/7, 3/22, 3/23, 1/8, 3/25], 否, finite_prefix_not_convergence_certificate)

Wave4第四層核對=(3, 3, 23, [1, 3/4, 3/5, 1/2, 3/7, 3/8, 1/3, 3/10, 3/11, 1/4, 3/13, 3/14, 1/5, 3/16, 3/17, 1/6, 3/19, 3/20, 1/7, 3/22, 3/23, 1/8, 3/25], 否, finite_prefix_not_convergence_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0073/)

依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate





## 74. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary；資料={"numerator":4,"shift":4,"prefix_length":24}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。

查看答案與解釋(4, 4, 24, [1, 4/5, 2/3, 4/7, 1/2, 4/9, 2/5, 4/11, 1/3, 4/13, 2/7, 4/15, 1/4, 4/17, 2/9, 4/19, 1/5, 4/21, 2/11, 4/23, 1/6, 4/25, 2/13, 4/27], 否, finite_prefix_not_convergence_certificate)

Wave4第四層核對=(4, 4, 24, [1, 4/5, 2/3, 4/7, 1/2, 4/9, 2/5, 4/11, 1/3, 4/13, 2/7, 4/15, 1/4, 4/17, 2/9, 4/19, 1/5, 4/21, 2/11, 4/23, 1/6, 4/25, 2/13, 4/27], 否, finite_prefix_not_convergence_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0074/)

依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate





## 75. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary；資料={"numerator":5,"shift":5,"prefix_length":25}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。

查看答案與解釋(5, 5, 25, [1, 5/6, 5/7, 5/8, 5/9, 1/2, 5/11, 5/12, 5/13, 5/14, 1/3, 5/16, 5/17, 5/18, 5/19, 1/4, 5/21, 5/22, 5/23, 5/24, 1/5, 5/26, 5/27, 5/28, 5/29], 否, finite_prefix_not_convergence_certificate)

Wave4第四層核對=(5, 5, 25, [1, 5/6, 5/7, 5/8, 5/9, 1/2, 5/11, 5/12, 5/13, 5/14, 1/3, 5/16, 5/17, 5/18, 5/19, 1/4, 5/21, 5/22, 5/23, 5/24, 1/5, 5/26, 5/27, 5/28, 5/29], 否, finite_prefix_not_convergence_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0075/)

依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate





## 76. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality；資料={"settling_index":1,"n":0}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。

查看答案與解釋(1, 0, not_yet_zero, 是, eventual_equality_universal_tail_certificate)

Wave4第四層核對=(1, 0, not_yet_zero, 是, eventual_equality_universal_tail_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0076/)

依機率收斂 · qf-mod30-convprob-eventual-equality · candidate





## 77. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality；資料={"settling_index":2,"n":1}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。

查看答案與解釋(2, 1, not_yet_zero, 是, eventual_equality_universal_tail_certificate)

Wave4第四層核對=(2, 1, not_yet_zero, 是, eventual_equality_universal_tail_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0077/)

依機率收斂 · qf-mod30-convprob-eventual-equality · candidate





## 78. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality；資料={"settling_index":3,"n":2}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。

查看答案與解釋(3, 2, not_yet_zero, 是, eventual_equality_universal_tail_certificate)

Wave4第四層核對=(3, 2, not_yet_zero, 是, eventual_equality_universal_tail_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0078/)

依機率收斂 · qf-mod30-convprob-eventual-equality · candidate





## 79. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality；資料={"settling_index":4,"n":4}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。

查看答案與解釋(4, 4, 0, 是, eventual_equality_universal_tail_certificate)

Wave4第四層核對=(4, 4, 0, 是, eventual_equality_universal_tail_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0079/)

依機率收斂 · qf-mod30-convprob-eventual-equality · candidate





## 80. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality；資料={"settling_index":5,"n":5}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。

查看答案與解釋(5, 5, 0, 是, eventual_equality_universal_tail_certificate)

Wave4第四層核對=(5, 5, 0, 是, eventual_equality_universal_tail_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0080/)

依機率收斂 · qf-mod30-convprob-eventual-equality · candidate





## 81. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality；資料={"settling_index":6,"n":6}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。

查看答案與解釋(6, 6, 0, 是, eventual_equality_universal_tail_certificate)

Wave4第四層核對=(6, 6, 0, 是, eventual_equality_universal_tail_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0081/)

依機率收斂 · qf-mod30-convprob-eventual-equality · candidate





## 82. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality；資料={"settling_index":7,"n":8}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。

查看答案與解釋(7, 8, 0, 是, eventual_equality_universal_tail_certificate)

Wave4第四層核對=(7, 8, 0, 是, eventual_equality_universal_tail_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0082/)

依機率收斂 · qf-mod30-convprob-eventual-equality · candidate





## 83. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality；資料={"settling_index":8,"n":9}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。

查看答案與解釋(8, 9, 0, 是, eventual_equality_universal_tail_certificate)

Wave4第四層核對=(8, 9, 0, 是, eventual_equality_universal_tail_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0083/)

依機率收斂 · qf-mod30-convprob-eventual-equality · candidate





## 84. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality；資料={"settling_index":9,"n":10}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。

查看答案與解釋(9, 10, 0, 是, eventual_equality_universal_tail_certificate)

Wave4第四層核對=(9, 10, 0, 是, eventual_equality_universal_tail_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0084/)

依機率收斂 · qf-mod30-convprob-eventual-equality · candidate





## 85. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality；資料={"settling_index":10,"n":12}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。

查看答案與解釋(10, 12, 0, 是, eventual_equality_universal_tail_certificate)

Wave4第四層核對=(10, 12, 0, 是, eventual_equality_universal_tail_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0085/)

依機率收斂 · qf-mod30-convprob-eventual-equality · candidate





## 86. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality；資料={"settling_index":11,"n":13}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。

查看答案與解釋(11, 13, 0, 是, eventual_equality_universal_tail_certificate)

Wave4第四層核對=(11, 13, 0, 是, eventual_equality_universal_tail_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0086/)

依機率收斂 · qf-mod30-convprob-eventual-equality · candidate





## 87. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality；資料={"settling_index":12,"n":14}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。

查看答案與解釋(12, 14, 0, 是, eventual_equality_universal_tail_certificate)

Wave4第四層核對=(12, 14, 0, 是, eventual_equality_universal_tail_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0087/)

依機率收斂 · qf-mod30-convprob-eventual-equality · candidate





## 88. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality；資料={"settling_index":13,"n":16}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。

查看答案與解釋(13, 16, 0, 是, eventual_equality_universal_tail_certificate)

Wave4第四層核對=(13, 16, 0, 是, eventual_equality_universal_tail_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0088/)

依機率收斂 · qf-mod30-convprob-eventual-equality · candidate





## 89. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality；資料={"settling_index":14,"n":17}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。

查看答案與解釋(14, 17, 0, 是, eventual_equality_universal_tail_certificate)

Wave4第四層核對=(14, 17, 0, 是, eventual_equality_universal_tail_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0089/)

依機率收斂 · qf-mod30-convprob-eventual-equality · candidate





## 90. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality；資料={"settling_index":15,"n":18}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。

查看答案與解釋(15, 18, 0, 是, eventual_equality_universal_tail_certificate)

Wave4第四層核對=(15, 18, 0, 是, eventual_equality_universal_tail_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0090/)

依機率收斂 · qf-mod30-convprob-eventual-equality · candidate





## 91. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality；資料={"settling_index":16,"n":20}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。

查看答案與解釋(16, 20, 0, 是, eventual_equality_universal_tail_certificate)

Wave4第四層核對=(16, 20, 0, 是, eventual_equality_universal_tail_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0091/)

依機率收斂 · qf-mod30-convprob-eventual-equality · candidate





## 92. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality；資料={"settling_index":17,"n":21}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。

查看答案與解釋(17, 21, 0, 是, eventual_equality_universal_tail_certificate)

Wave4第四層核對=(17, 21, 0, 是, eventual_equality_universal_tail_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0092/)

依機率收斂 · qf-mod30-convprob-eventual-equality · candidate





## 93. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality；資料={"settling_index":18,"n":22}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。

查看答案與解釋(18, 22, 0, 是, eventual_equality_universal_tail_certificate)

Wave4第四層核對=(18, 22, 0, 是, eventual_equality_universal_tail_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0093/)

依機率收斂 · qf-mod30-convprob-eventual-equality · candidate





## 94. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality；資料={"settling_index":19,"n":24}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。

查看答案與解釋(19, 24, 0, 是, eventual_equality_universal_tail_certificate)

Wave4第四層核對=(19, 24, 0, 是, eventual_equality_universal_tail_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0094/)

依機率收斂 · qf-mod30-convprob-eventual-equality · candidate





## 95. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality；資料={"settling_index":20,"n":25}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。

查看答案與解釋(20, 25, 0, 是, eventual_equality_universal_tail_certificate)

Wave4第四層核對=(20, 25, 0, 是, eventual_equality_universal_tail_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0095/)

依機率收斂 · qf-mod30-convprob-eventual-equality · candidate





## 96. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality；資料={"settling_index":21,"n":26}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。

查看答案與解釋(21, 26, 0, 是, eventual_equality_universal_tail_certificate)

Wave4第四層核對=(21, 26, 0, 是, eventual_equality_universal_tail_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0096/)

依機率收斂 · qf-mod30-convprob-eventual-equality · candidate





## 97. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality；資料={"settling_index":22,"n":28}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。

查看答案與解釋(22, 28, 0, 是, eventual_equality_universal_tail_certificate)

Wave4第四層核對=(22, 28, 0, 是, eventual_equality_universal_tail_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0097/)

依機率收斂 · qf-mod30-convprob-eventual-equality · candidate





## 98. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality；資料={"settling_index":23,"n":29}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。

查看答案與解釋(23, 29, 0, 是, eventual_equality_universal_tail_certificate)

Wave4第四層核對=(23, 29, 0, 是, eventual_equality_universal_tail_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0098/)

依機率收斂 · qf-mod30-convprob-eventual-equality · candidate





## 99. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality；資料={"settling_index":24,"n":30}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。

查看答案與解釋(24, 30, 0, 是, eventual_equality_universal_tail_certificate)

Wave4第四層核對=(24, 30, 0, 是, eventual_equality_universal_tail_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0099/)

依機率收斂 · qf-mod30-convprob-eventual-equality · candidate





## 100. 依機率收斂

共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality；資料={"settling_index":25,"n":32}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。

查看答案與解釋(25, 32, 0, 是, eventual_equality_universal_tail_certificate)

Wave4第四層核對=(25, 32, 0, 是, eventual_equality_universal_tail_certificate)；依完整明示資料重算；完整有限／symbolic tail證書不自動升格為未聲明的一般定理；finite prefix不足且只接受symbolic tail或eventual equality；不混同almost sure Lp或distribution convergence。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261030-r07-convergence-in-probability-0100/)

依機率收斂 · qf-mod30-convprob-eventual-equality · candidate



[原始題目 JSONL](https://ocme.evemisslab.com/data/questions/revisions/ocme-parameter-revision-20261017/batch-20261014-advance-20261030-r07-convergence-in-probability-foundations/questions.jsonl) · [驗收報告](https://ocme.evemisslab.com/data/questions/revisions/ocme-parameter-revision-20261017/batch-20261014-advance-20261030-r07-convergence-in-probability-foundations/validation-report.json)