# 拓撲邊界基礎 · 脈衝 R04

本批已通過 Schema、去重、來源快照與獨立答案重算；仍未標記為人工審定。

本題庫已有對應的中英逐步詳解。原題的 candidate 與英文 ai_candidate 狀態保留；AI 覆核、有限計算與 Lean 形式證明分開標示。

batch-20261014-advance-20261102-r04-topological-boundary-foundations · 2026-10-14 · 100 題



## 1. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-exact；資料={"n":5,"topology":[[],[0],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4]],"subset":[1,2]}。請依 [subset,closure,interior,boundary] 欄序回答。

查看答案與解釋([1, 2], [1, 2, 3, 4], [], [1, 2, 3, 4])

Wave5第二層核對=([1, 2], [1, 2, 3, 4], [], [1, 2, 3, 4])；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0001/)

拓撲邊界 · qf-mod33-boundary-exact · candidate





## 2. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-exact；資料={"n":5,"topology":[[],[0],[0,1],[0,1,2],[0,1,2,4],[0,1,2,3,4]],"subset":[1,2]}。請依 [subset,closure,interior,boundary] 欄序回答。

查看答案與解釋([1, 2], [1, 2, 3, 4], [], [1, 2, 3, 4])

Wave5第二層核對=([1, 2], [1, 2, 3, 4], [], [1, 2, 3, 4])；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0002/)

拓撲邊界 · qf-mod33-boundary-exact · candidate





## 3. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-exact；資料={"n":5,"topology":[[],[0],[0,1],[0,1,3],[0,1,2,3],[0,1,2,3,4]],"subset":[1,3]}。請依 [subset,closure,interior,boundary] 欄序回答。

查看答案與解釋([1, 3], [1, 2, 3, 4], [], [1, 2, 3, 4])

Wave5第二層核對=([1, 3], [1, 2, 3, 4], [], [1, 2, 3, 4])；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0003/)

拓撲邊界 · qf-mod33-boundary-exact · candidate





## 4. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-exact；資料={"n":5,"topology":[[],[0],[0,1],[0,1,3],[0,1,3,4],[0,1,2,3,4]],"subset":[1,3]}。請依 [subset,closure,interior,boundary] 欄序回答。

查看答案與解釋([1, 3], [1, 2, 3, 4], [], [1, 2, 3, 4])

Wave5第二層核對=([1, 3], [1, 2, 3, 4], [], [1, 2, 3, 4])；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0004/)

拓撲邊界 · qf-mod33-boundary-exact · candidate





## 5. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-exact；資料={"n":5,"topology":[[],[0],[0,1],[0,1,4],[0,1,2,4],[0,1,2,3,4]],"subset":[1,4]}。請依 [subset,closure,interior,boundary] 欄序回答。

查看答案與解釋([1, 4], [1, 2, 3, 4], [], [1, 2, 3, 4])

Wave5第二層核對=([1, 4], [1, 2, 3, 4], [], [1, 2, 3, 4])；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0005/)

拓撲邊界 · qf-mod33-boundary-exact · candidate





## 6. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-exact；資料={"n":5,"topology":[[],[0],[0,1],[0,1,4],[0,1,3,4],[0,1,2,3,4]],"subset":[1,4]}。請依 [subset,closure,interior,boundary] 欄序回答。

查看答案與解釋([1, 4], [1, 2, 3, 4], [], [1, 2, 3, 4])

Wave5第二層核對=([1, 4], [1, 2, 3, 4], [], [1, 2, 3, 4])；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0006/)

拓撲邊界 · qf-mod33-boundary-exact · candidate





## 7. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-exact；資料={"n":5,"topology":[[],[0],[0,2],[0,1,2],[0,1,2,3],[0,1,2,3,4]],"subset":[1,2]}。請依 [subset,closure,interior,boundary] 欄序回答。

查看答案與解釋([1, 2], [1, 2, 3, 4], [], [1, 2, 3, 4])

Wave5第二層核對=([1, 2], [1, 2, 3, 4], [], [1, 2, 3, 4])；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0007/)

拓撲邊界 · qf-mod33-boundary-exact · candidate





## 8. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-exact；資料={"n":5,"topology":[[],[0],[0,2],[0,1,2],[0,1,2,4],[0,1,2,3,4]],"subset":[1,2]}。請依 [subset,closure,interior,boundary] 欄序回答。

查看答案與解釋([1, 2], [1, 2, 3, 4], [], [1, 2, 3, 4])

Wave5第二層核對=([1, 2], [1, 2, 3, 4], [], [1, 2, 3, 4])；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0008/)

拓撲邊界 · qf-mod33-boundary-exact · candidate





## 9. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-exact；資料={"n":5,"topology":[[],[0],[0,2],[0,2,3],[0,1,2,3],[0,1,2,3,4]],"subset":[2,3]}。請依 [subset,closure,interior,boundary] 欄序回答。

查看答案與解釋([2, 3], [1, 2, 3, 4], [], [1, 2, 3, 4])

Wave5第二層核對=([2, 3], [1, 2, 3, 4], [], [1, 2, 3, 4])；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0009/)

拓撲邊界 · qf-mod33-boundary-exact · candidate





## 10. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-exact；資料={"n":5,"topology":[[],[0],[0,2],[0,2,3],[0,2,3,4],[0,1,2,3,4]],"subset":[2,3]}。請依 [subset,closure,interior,boundary] 欄序回答。

查看答案與解釋([2, 3], [1, 2, 3, 4], [], [1, 2, 3, 4])

Wave5第二層核對=([2, 3], [1, 2, 3, 4], [], [1, 2, 3, 4])；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0010/)

拓撲邊界 · qf-mod33-boundary-exact · candidate





## 11. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-exact；資料={"n":5,"topology":[[],[0],[0,2],[0,2,4],[0,1,2,4],[0,1,2,3,4]],"subset":[2,4]}。請依 [subset,closure,interior,boundary] 欄序回答。

查看答案與解釋([2, 4], [1, 2, 3, 4], [], [1, 2, 3, 4])

Wave5第二層核對=([2, 4], [1, 2, 3, 4], [], [1, 2, 3, 4])；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0011/)

拓撲邊界 · qf-mod33-boundary-exact · candidate





## 12. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-exact；資料={"n":5,"topology":[[],[0],[0,2],[0,2,4],[0,2,3,4],[0,1,2,3,4]],"subset":[2,4]}。請依 [subset,closure,interior,boundary] 欄序回答。

查看答案與解釋([2, 4], [1, 2, 3, 4], [], [1, 2, 3, 4])

Wave5第二層核對=([2, 4], [1, 2, 3, 4], [], [1, 2, 3, 4])；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0012/)

拓撲邊界 · qf-mod33-boundary-exact · candidate





## 13. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-exact；資料={"n":5,"topology":[[],[0],[0,3],[0,1,3],[0,1,2,3],[0,1,2,3,4]],"subset":[1,3]}。請依 [subset,closure,interior,boundary] 欄序回答。

查看答案與解釋([1, 3], [1, 2, 3, 4], [], [1, 2, 3, 4])

Wave5第二層核對=([1, 3], [1, 2, 3, 4], [], [1, 2, 3, 4])；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0013/)

拓撲邊界 · qf-mod33-boundary-exact · candidate





## 14. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-exact；資料={"n":5,"topology":[[],[0],[0,3],[0,1,3],[0,1,3,4],[0,1,2,3,4]],"subset":[1,3]}。請依 [subset,closure,interior,boundary] 欄序回答。

查看答案與解釋([1, 3], [1, 2, 3, 4], [], [1, 2, 3, 4])

Wave5第二層核對=([1, 3], [1, 2, 3, 4], [], [1, 2, 3, 4])；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0014/)

拓撲邊界 · qf-mod33-boundary-exact · candidate





## 15. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-exact；資料={"n":5,"topology":[[],[0],[0,3],[0,2,3],[0,1,2,3],[0,1,2,3,4]],"subset":[2,3]}。請依 [subset,closure,interior,boundary] 欄序回答。

查看答案與解釋([2, 3], [1, 2, 3, 4], [], [1, 2, 3, 4])

Wave5第二層核對=([2, 3], [1, 2, 3, 4], [], [1, 2, 3, 4])；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0015/)

拓撲邊界 · qf-mod33-boundary-exact · candidate





## 16. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-exact；資料={"n":5,"topology":[[],[0],[0,3],[0,2,3],[0,2,3,4],[0,1,2,3,4]],"subset":[2,3]}。請依 [subset,closure,interior,boundary] 欄序回答。

查看答案與解釋([2, 3], [1, 2, 3, 4], [], [1, 2, 3, 4])

Wave5第二層核對=([2, 3], [1, 2, 3, 4], [], [1, 2, 3, 4])；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0016/)

拓撲邊界 · qf-mod33-boundary-exact · candidate





## 17. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-exact；資料={"n":5,"topology":[[],[0],[0,3],[0,3,4],[0,1,3,4],[0,1,2,3,4]],"subset":[3,4]}。請依 [subset,closure,interior,boundary] 欄序回答。

查看答案與解釋([3, 4], [1, 2, 3, 4], [], [1, 2, 3, 4])

Wave5第二層核對=([3, 4], [1, 2, 3, 4], [], [1, 2, 3, 4])；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0017/)

拓撲邊界 · qf-mod33-boundary-exact · candidate





## 18. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-exact；資料={"n":5,"topology":[[],[0],[0,3],[0,3,4],[0,2,3,4],[0,1,2,3,4]],"subset":[3,4]}。請依 [subset,closure,interior,boundary] 欄序回答。

查看答案與解釋([3, 4], [1, 2, 3, 4], [], [1, 2, 3, 4])

Wave5第二層核對=([3, 4], [1, 2, 3, 4], [], [1, 2, 3, 4])；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0018/)

拓撲邊界 · qf-mod33-boundary-exact · candidate





## 19. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-exact；資料={"n":5,"topology":[[],[0],[0,4],[0,1,4],[0,1,2,4],[0,1,2,3,4]],"subset":[1,4]}。請依 [subset,closure,interior,boundary] 欄序回答。

查看答案與解釋([1, 4], [1, 2, 3, 4], [], [1, 2, 3, 4])

Wave5第二層核對=([1, 4], [1, 2, 3, 4], [], [1, 2, 3, 4])；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0019/)

拓撲邊界 · qf-mod33-boundary-exact · candidate





## 20. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-exact；資料={"n":5,"topology":[[],[0],[0,4],[0,1,4],[0,1,3,4],[0,1,2,3,4]],"subset":[1,4]}。請依 [subset,closure,interior,boundary] 欄序回答。

查看答案與解釋([1, 4], [1, 2, 3, 4], [], [1, 2, 3, 4])

Wave5第二層核對=([1, 4], [1, 2, 3, 4], [], [1, 2, 3, 4])；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0020/)

拓撲邊界 · qf-mod33-boundary-exact · candidate





## 21. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-exact；資料={"n":5,"topology":[[],[0],[0,4],[0,2,4],[0,1,2,4],[0,1,2,3,4]],"subset":[2,4]}。請依 [subset,closure,interior,boundary] 欄序回答。

查看答案與解釋([2, 4], [1, 2, 3, 4], [], [1, 2, 3, 4])

Wave5第二層核對=([2, 4], [1, 2, 3, 4], [], [1, 2, 3, 4])；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0021/)

拓撲邊界 · qf-mod33-boundary-exact · candidate





## 22. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-exact；資料={"n":5,"topology":[[],[0],[0,4],[0,2,4],[0,2,3,4],[0,1,2,3,4]],"subset":[2,4]}。請依 [subset,closure,interior,boundary] 欄序回答。

查看答案與解釋([2, 4], [1, 2, 3, 4], [], [1, 2, 3, 4])

Wave5第二層核對=([2, 4], [1, 2, 3, 4], [], [1, 2, 3, 4])；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0022/)

拓撲邊界 · qf-mod33-boundary-exact · candidate





## 23. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-exact；資料={"n":5,"topology":[[],[0],[0,4],[0,3,4],[0,1,3,4],[0,1,2,3,4]],"subset":[3,4]}。請依 [subset,closure,interior,boundary] 欄序回答。

查看答案與解釋([3, 4], [1, 2, 3, 4], [], [1, 2, 3, 4])

Wave5第二層核對=([3, 4], [1, 2, 3, 4], [], [1, 2, 3, 4])；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0023/)

拓撲邊界 · qf-mod33-boundary-exact · candidate





## 24. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-exact；資料={"n":5,"topology":[[],[0],[0,4],[0,3,4],[0,2,3,4],[0,1,2,3,4]],"subset":[3,4]}。請依 [subset,closure,interior,boundary] 欄序回答。

查看答案與解釋([3, 4], [1, 2, 3, 4], [], [1, 2, 3, 4])

Wave5第二層核對=([3, 4], [1, 2, 3, 4], [], [1, 2, 3, 4])；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0024/)

拓撲邊界 · qf-mod33-boundary-exact · candidate





## 25. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-exact；資料={"n":5,"topology":[[],[1],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4]],"subset":[0,2]}。請依 [subset,closure,interior,boundary] 欄序回答。

查看答案與解釋([0, 2], [0, 2, 3, 4], [], [0, 2, 3, 4])

Wave5第二層核對=([0, 2], [0, 2, 3, 4], [], [0, 2, 3, 4])；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0025/)

拓撲邊界 · qf-mod33-boundary-exact · candidate





## 26. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-membership；資料={"n":5,"topology":[[],[0],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4]],"subset":[1,2],"point":0}。請依 [point,boundary,in_boundary,scope] 欄序回答。

查看答案與解釋(0, [1, 2, 3, 4], 否, topology_relative_boundary)

Wave5第二層核對=(0, [1, 2, 3, 4], 否, topology_relative_boundary)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0026/)

拓撲邊界 · qf-mod33-boundary-membership · candidate





## 27. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-membership；資料={"n":5,"topology":[[],[0],[0,1],[0,1,2],[0,1,2,4],[0,1,2,3,4]],"subset":[1,2],"point":1}。請依 [point,boundary,in_boundary,scope] 欄序回答。

查看答案與解釋(1, [1, 2, 3, 4], 是, topology_relative_boundary)

Wave5第二層核對=(1, [1, 2, 3, 4], 是, topology_relative_boundary)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0027/)

拓撲邊界 · qf-mod33-boundary-membership · candidate





## 28. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-membership；資料={"n":5,"topology":[[],[0],[0,1],[0,1,3],[0,1,2,3],[0,1,2,3,4]],"subset":[1,3],"point":3}。請依 [point,boundary,in_boundary,scope] 欄序回答。

查看答案與解釋(3, [1, 2, 3, 4], 是, topology_relative_boundary)

Wave5第二層核對=(3, [1, 2, 3, 4], 是, topology_relative_boundary)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0028/)

拓撲邊界 · qf-mod33-boundary-membership · candidate





## 29. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-membership；資料={"n":5,"topology":[[],[0],[0,1],[0,1,3],[0,1,3,4],[0,1,2,3,4]],"subset":[1,3],"point":4}。請依 [point,boundary,in_boundary,scope] 欄序回答。

查看答案與解釋(4, [1, 2, 3, 4], 是, topology_relative_boundary)

Wave5第二層核對=(4, [1, 2, 3, 4], 是, topology_relative_boundary)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0029/)

拓撲邊界 · qf-mod33-boundary-membership · candidate





## 30. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-membership；資料={"n":5,"topology":[[],[0],[0,1],[0,1,4],[0,1,2,4],[0,1,2,3,4]],"subset":[1,4],"point":3}。請依 [point,boundary,in_boundary,scope] 欄序回答。

查看答案與解釋(3, [1, 2, 3, 4], 是, topology_relative_boundary)

Wave5第二層核對=(3, [1, 2, 3, 4], 是, topology_relative_boundary)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0030/)

拓撲邊界 · qf-mod33-boundary-membership · candidate





## 31. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-membership；資料={"n":5,"topology":[[],[0],[0,1],[0,1,4],[0,1,3,4],[0,1,2,3,4]],"subset":[1,4],"point":0}。請依 [point,boundary,in_boundary,scope] 欄序回答。

查看答案與解釋(0, [1, 2, 3, 4], 否, topology_relative_boundary)

Wave5第二層核對=(0, [1, 2, 3, 4], 否, topology_relative_boundary)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0031/)

拓撲邊界 · qf-mod33-boundary-membership · candidate





## 32. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-membership；資料={"n":5,"topology":[[],[0],[0,2],[0,1,2],[0,1,2,3],[0,1,2,3,4]],"subset":[1,2],"point":2}。請依 [point,boundary,in_boundary,scope] 欄序回答。

查看答案與解釋(2, [1, 2, 3, 4], 是, topology_relative_boundary)

Wave5第二層核對=(2, [1, 2, 3, 4], 是, topology_relative_boundary)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0032/)

拓撲邊界 · qf-mod33-boundary-membership · candidate





## 33. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-membership；資料={"n":5,"topology":[[],[0],[0,2],[0,1,2],[0,1,2,4],[0,1,2,3,4]],"subset":[1,2],"point":1}。請依 [point,boundary,in_boundary,scope] 欄序回答。

查看答案與解釋(1, [1, 2, 3, 4], 是, topology_relative_boundary)

Wave5第二層核對=(1, [1, 2, 3, 4], 是, topology_relative_boundary)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0033/)

拓撲邊界 · qf-mod33-boundary-membership · candidate





## 34. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-membership；資料={"n":5,"topology":[[],[0],[0,2],[0,2,3],[0,1,2,3],[0,1,2,3,4]],"subset":[2,3],"point":1}。請依 [point,boundary,in_boundary,scope] 欄序回答。

查看答案與解釋(1, [1, 2, 3, 4], 是, topology_relative_boundary)

Wave5第二層核對=(1, [1, 2, 3, 4], 是, topology_relative_boundary)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0034/)

拓撲邊界 · qf-mod33-boundary-membership · candidate





## 35. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-membership；資料={"n":5,"topology":[[],[0],[0,2],[0,2,3],[0,2,3,4],[0,1,2,3,4]],"subset":[2,3],"point":1}。請依 [point,boundary,in_boundary,scope] 欄序回答。

查看答案與解釋(1, [1, 2, 3, 4], 是, topology_relative_boundary)

Wave5第二層核對=(1, [1, 2, 3, 4], 是, topology_relative_boundary)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0035/)

拓撲邊界 · qf-mod33-boundary-membership · candidate





## 36. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-membership；資料={"n":5,"topology":[[],[0],[0,2],[0,2,4],[0,1,2,4],[0,1,2,3,4]],"subset":[2,4],"point":0}。請依 [point,boundary,in_boundary,scope] 欄序回答。

查看答案與解釋(0, [1, 2, 3, 4], 否, topology_relative_boundary)

Wave5第二層核對=(0, [1, 2, 3, 4], 否, topology_relative_boundary)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0036/)

拓撲邊界 · qf-mod33-boundary-membership · candidate





## 37. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-membership；資料={"n":5,"topology":[[],[0],[0,2],[0,2,4],[0,2,3,4],[0,1,2,3,4]],"subset":[2,4],"point":2}。請依 [point,boundary,in_boundary,scope] 欄序回答。

查看答案與解釋(2, [1, 2, 3, 4], 是, topology_relative_boundary)

Wave5第二層核對=(2, [1, 2, 3, 4], 是, topology_relative_boundary)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0037/)

拓撲邊界 · qf-mod33-boundary-membership · candidate





## 38. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-membership；資料={"n":5,"topology":[[],[0],[0,3],[0,1,3],[0,1,2,3],[0,1,2,3,4]],"subset":[1,3],"point":1}。請依 [point,boundary,in_boundary,scope] 欄序回答。

查看答案與解釋(1, [1, 2, 3, 4], 是, topology_relative_boundary)

Wave5第二層核對=(1, [1, 2, 3, 4], 是, topology_relative_boundary)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0038/)

拓撲邊界 · qf-mod33-boundary-membership · candidate





## 39. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-membership；資料={"n":5,"topology":[[],[0],[0,3],[0,1,3],[0,1,3,4],[0,1,2,3,4]],"subset":[1,3],"point":4}。請依 [point,boundary,in_boundary,scope] 欄序回答。

查看答案與解釋(4, [1, 2, 3, 4], 是, topology_relative_boundary)

Wave5第二層核對=(4, [1, 2, 3, 4], 是, topology_relative_boundary)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0039/)

拓撲邊界 · qf-mod33-boundary-membership · candidate





## 40. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-membership；資料={"n":5,"topology":[[],[0],[0,3],[0,2,3],[0,1,2,3],[0,1,2,3,4]],"subset":[2,3],"point":4}。請依 [point,boundary,in_boundary,scope] 欄序回答。

查看答案與解釋(4, [1, 2, 3, 4], 是, topology_relative_boundary)

Wave5第二層核對=(4, [1, 2, 3, 4], 是, topology_relative_boundary)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0040/)

拓撲邊界 · qf-mod33-boundary-membership · candidate





## 41. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-membership；資料={"n":5,"topology":[[],[0],[0,3],[0,2,3],[0,2,3,4],[0,1,2,3,4]],"subset":[2,3],"point":0}。請依 [point,boundary,in_boundary,scope] 欄序回答。

查看答案與解釋(0, [1, 2, 3, 4], 否, topology_relative_boundary)

Wave5第二層核對=(0, [1, 2, 3, 4], 否, topology_relative_boundary)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0041/)

拓撲邊界 · qf-mod33-boundary-membership · candidate





## 42. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-membership；資料={"n":5,"topology":[[],[0],[0,3],[0,3,4],[0,1,3,4],[0,1,2,3,4]],"subset":[3,4],"point":3}。請依 [point,boundary,in_boundary,scope] 欄序回答。

查看答案與解釋(3, [1, 2, 3, 4], 是, topology_relative_boundary)

Wave5第二層核對=(3, [1, 2, 3, 4], 是, topology_relative_boundary)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0042/)

拓撲邊界 · qf-mod33-boundary-membership · candidate





## 43. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-membership；資料={"n":5,"topology":[[],[0],[0,3],[0,3,4],[0,2,3,4],[0,1,2,3,4]],"subset":[3,4],"point":4}。請依 [point,boundary,in_boundary,scope] 欄序回答。

查看答案與解釋(4, [1, 2, 3, 4], 是, topology_relative_boundary)

Wave5第二層核對=(4, [1, 2, 3, 4], 是, topology_relative_boundary)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0043/)

拓撲邊界 · qf-mod33-boundary-membership · candidate





## 44. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-membership；資料={"n":5,"topology":[[],[0],[0,4],[0,1,4],[0,1,2,4],[0,1,2,3,4]],"subset":[1,4],"point":2}。請依 [point,boundary,in_boundary,scope] 欄序回答。

查看答案與解釋(2, [1, 2, 3, 4], 是, topology_relative_boundary)

Wave5第二層核對=(2, [1, 2, 3, 4], 是, topology_relative_boundary)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0044/)

拓撲邊界 · qf-mod33-boundary-membership · candidate





## 45. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-membership；資料={"n":5,"topology":[[],[0],[0,4],[0,1,4],[0,1,3,4],[0,1,2,3,4]],"subset":[1,4],"point":2}。請依 [point,boundary,in_boundary,scope] 欄序回答。

查看答案與解釋(2, [1, 2, 3, 4], 是, topology_relative_boundary)

Wave5第二層核對=(2, [1, 2, 3, 4], 是, topology_relative_boundary)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0045/)

拓撲邊界 · qf-mod33-boundary-membership · candidate





## 46. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-membership；資料={"n":5,"topology":[[],[0],[0,4],[0,2,4],[0,1,2,4],[0,1,2,3,4]],"subset":[2,4],"point":0}。請依 [point,boundary,in_boundary,scope] 欄序回答。

查看答案與解釋(0, [1, 2, 3, 4], 否, topology_relative_boundary)

Wave5第二層核對=(0, [1, 2, 3, 4], 否, topology_relative_boundary)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0046/)

拓撲邊界 · qf-mod33-boundary-membership · candidate





## 47. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-membership；資料={"n":5,"topology":[[],[0],[0,4],[0,2,4],[0,2,3,4],[0,1,2,3,4]],"subset":[2,4],"point":4}。請依 [point,boundary,in_boundary,scope] 欄序回答。

查看答案與解釋(4, [1, 2, 3, 4], 是, topology_relative_boundary)

Wave5第二層核對=(4, [1, 2, 3, 4], 是, topology_relative_boundary)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0047/)

拓撲邊界 · qf-mod33-boundary-membership · candidate





## 48. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-membership；資料={"n":5,"topology":[[],[0],[0,4],[0,3,4],[0,1,3,4],[0,1,2,3,4]],"subset":[3,4],"point":3}。請依 [point,boundary,in_boundary,scope] 欄序回答。

查看答案與解釋(3, [1, 2, 3, 4], 是, topology_relative_boundary)

Wave5第二層核對=(3, [1, 2, 3, 4], 是, topology_relative_boundary)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0048/)

拓撲邊界 · qf-mod33-boundary-membership · candidate





## 49. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-membership；資料={"n":5,"topology":[[],[0],[0,4],[0,3,4],[0,2,3,4],[0,1,2,3,4]],"subset":[3,4],"point":2}。請依 [point,boundary,in_boundary,scope] 欄序回答。

查看答案與解釋(2, [1, 2, 3, 4], 是, topology_relative_boundary)

Wave5第二層核對=(2, [1, 2, 3, 4], 是, topology_relative_boundary)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0049/)

拓撲邊界 · qf-mod33-boundary-membership · candidate





## 50. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-membership；資料={"n":5,"topology":[[],[1],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4]],"subset":[0,2],"point":4}。請依 [point,boundary,in_boundary,scope] 欄序回答。

查看答案與解釋(4, [0, 2, 3, 4], 是, topology_relative_boundary)

Wave5第二層核對=(4, [0, 2, 3, 4], 是, topology_relative_boundary)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0050/)

拓撲邊界 · qf-mod33-boundary-membership · candidate





## 51. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-complement-invariance；資料={"n":5,"topology":[[],[0],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4]],"subset":[1,2]}。請依 [subset,complement,boundary_a,boundary_complement,equal] 欄序回答。

查看答案與解釋([1, 2], [0, 3, 4], [1, 2, 3, 4], [1, 2, 3, 4], 是)

Wave5第二層核對=([1, 2], [0, 3, 4], [1, 2, 3, 4], [1, 2, 3, 4], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0051/)

拓撲邊界 · qf-mod33-boundary-complement-invariance · candidate





## 52. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-complement-invariance；資料={"n":5,"topology":[[],[0],[0,1],[0,1,2],[0,1,2,4],[0,1,2,3,4]],"subset":[1,2]}。請依 [subset,complement,boundary_a,boundary_complement,equal] 欄序回答。

查看答案與解釋([1, 2], [0, 3, 4], [1, 2, 3, 4], [1, 2, 3, 4], 是)

Wave5第二層核對=([1, 2], [0, 3, 4], [1, 2, 3, 4], [1, 2, 3, 4], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0052/)

拓撲邊界 · qf-mod33-boundary-complement-invariance · candidate





## 53. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-complement-invariance；資料={"n":5,"topology":[[],[0],[0,1],[0,1,3],[0,1,2,3],[0,1,2,3,4]],"subset":[1,3]}。請依 [subset,complement,boundary_a,boundary_complement,equal] 欄序回答。

查看答案與解釋([1, 3], [0, 2, 4], [1, 2, 3, 4], [1, 2, 3, 4], 是)

Wave5第二層核對=([1, 3], [0, 2, 4], [1, 2, 3, 4], [1, 2, 3, 4], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0053/)

拓撲邊界 · qf-mod33-boundary-complement-invariance · candidate





## 54. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-complement-invariance；資料={"n":5,"topology":[[],[0],[0,1],[0,1,3],[0,1,3,4],[0,1,2,3,4]],"subset":[1,3]}。請依 [subset,complement,boundary_a,boundary_complement,equal] 欄序回答。

查看答案與解釋([1, 3], [0, 2, 4], [1, 2, 3, 4], [1, 2, 3, 4], 是)

Wave5第二層核對=([1, 3], [0, 2, 4], [1, 2, 3, 4], [1, 2, 3, 4], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0054/)

拓撲邊界 · qf-mod33-boundary-complement-invariance · candidate





## 55. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-complement-invariance；資料={"n":5,"topology":[[],[0],[0,1],[0,1,4],[0,1,2,4],[0,1,2,3,4]],"subset":[1,4]}。請依 [subset,complement,boundary_a,boundary_complement,equal] 欄序回答。

查看答案與解釋([1, 4], [0, 2, 3], [1, 2, 3, 4], [1, 2, 3, 4], 是)

Wave5第二層核對=([1, 4], [0, 2, 3], [1, 2, 3, 4], [1, 2, 3, 4], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0055/)

拓撲邊界 · qf-mod33-boundary-complement-invariance · candidate





## 56. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-complement-invariance；資料={"n":5,"topology":[[],[0],[0,1],[0,1,4],[0,1,3,4],[0,1,2,3,4]],"subset":[1,4]}。請依 [subset,complement,boundary_a,boundary_complement,equal] 欄序回答。

查看答案與解釋([1, 4], [0, 2, 3], [1, 2, 3, 4], [1, 2, 3, 4], 是)

Wave5第二層核對=([1, 4], [0, 2, 3], [1, 2, 3, 4], [1, 2, 3, 4], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0056/)

拓撲邊界 · qf-mod33-boundary-complement-invariance · candidate





## 57. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-complement-invariance；資料={"n":5,"topology":[[],[0],[0,2],[0,1,2],[0,1,2,3],[0,1,2,3,4]],"subset":[1,2]}。請依 [subset,complement,boundary_a,boundary_complement,equal] 欄序回答。

查看答案與解釋([1, 2], [0, 3, 4], [1, 2, 3, 4], [1, 2, 3, 4], 是)

Wave5第二層核對=([1, 2], [0, 3, 4], [1, 2, 3, 4], [1, 2, 3, 4], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0057/)

拓撲邊界 · qf-mod33-boundary-complement-invariance · candidate





## 58. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-complement-invariance；資料={"n":5,"topology":[[],[0],[0,2],[0,1,2],[0,1,2,4],[0,1,2,3,4]],"subset":[1,2]}。請依 [subset,complement,boundary_a,boundary_complement,equal] 欄序回答。

查看答案與解釋([1, 2], [0, 3, 4], [1, 2, 3, 4], [1, 2, 3, 4], 是)

Wave5第二層核對=([1, 2], [0, 3, 4], [1, 2, 3, 4], [1, 2, 3, 4], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0058/)

拓撲邊界 · qf-mod33-boundary-complement-invariance · candidate





## 59. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-complement-invariance；資料={"n":5,"topology":[[],[0],[0,2],[0,2,3],[0,1,2,3],[0,1,2,3,4]],"subset":[2,3]}。請依 [subset,complement,boundary_a,boundary_complement,equal] 欄序回答。

查看答案與解釋([2, 3], [0, 1, 4], [1, 2, 3, 4], [1, 2, 3, 4], 是)

Wave5第二層核對=([2, 3], [0, 1, 4], [1, 2, 3, 4], [1, 2, 3, 4], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0059/)

拓撲邊界 · qf-mod33-boundary-complement-invariance · candidate





## 60. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-complement-invariance；資料={"n":5,"topology":[[],[0],[0,2],[0,2,3],[0,2,3,4],[0,1,2,3,4]],"subset":[2,3]}。請依 [subset,complement,boundary_a,boundary_complement,equal] 欄序回答。

查看答案與解釋([2, 3], [0, 1, 4], [1, 2, 3, 4], [1, 2, 3, 4], 是)

Wave5第二層核對=([2, 3], [0, 1, 4], [1, 2, 3, 4], [1, 2, 3, 4], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0060/)

拓撲邊界 · qf-mod33-boundary-complement-invariance · candidate





## 61. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-complement-invariance；資料={"n":5,"topology":[[],[0],[0,2],[0,2,4],[0,1,2,4],[0,1,2,3,4]],"subset":[2,4]}。請依 [subset,complement,boundary_a,boundary_complement,equal] 欄序回答。

查看答案與解釋([2, 4], [0, 1, 3], [1, 2, 3, 4], [1, 2, 3, 4], 是)

Wave5第二層核對=([2, 4], [0, 1, 3], [1, 2, 3, 4], [1, 2, 3, 4], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0061/)

拓撲邊界 · qf-mod33-boundary-complement-invariance · candidate





## 62. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-complement-invariance；資料={"n":5,"topology":[[],[0],[0,2],[0,2,4],[0,2,3,4],[0,1,2,3,4]],"subset":[2,4]}。請依 [subset,complement,boundary_a,boundary_complement,equal] 欄序回答。

查看答案與解釋([2, 4], [0, 1, 3], [1, 2, 3, 4], [1, 2, 3, 4], 是)

Wave5第二層核對=([2, 4], [0, 1, 3], [1, 2, 3, 4], [1, 2, 3, 4], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0062/)

拓撲邊界 · qf-mod33-boundary-complement-invariance · candidate





## 63. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-complement-invariance；資料={"n":5,"topology":[[],[0],[0,3],[0,1,3],[0,1,2,3],[0,1,2,3,4]],"subset":[1,3]}。請依 [subset,complement,boundary_a,boundary_complement,equal] 欄序回答。

查看答案與解釋([1, 3], [0, 2, 4], [1, 2, 3, 4], [1, 2, 3, 4], 是)

Wave5第二層核對=([1, 3], [0, 2, 4], [1, 2, 3, 4], [1, 2, 3, 4], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0063/)

拓撲邊界 · qf-mod33-boundary-complement-invariance · candidate





## 64. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-complement-invariance；資料={"n":5,"topology":[[],[0],[0,3],[0,1,3],[0,1,3,4],[0,1,2,3,4]],"subset":[1,3]}。請依 [subset,complement,boundary_a,boundary_complement,equal] 欄序回答。

查看答案與解釋([1, 3], [0, 2, 4], [1, 2, 3, 4], [1, 2, 3, 4], 是)

Wave5第二層核對=([1, 3], [0, 2, 4], [1, 2, 3, 4], [1, 2, 3, 4], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0064/)

拓撲邊界 · qf-mod33-boundary-complement-invariance · candidate





## 65. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-complement-invariance；資料={"n":5,"topology":[[],[0],[0,3],[0,2,3],[0,1,2,3],[0,1,2,3,4]],"subset":[2,3]}。請依 [subset,complement,boundary_a,boundary_complement,equal] 欄序回答。

查看答案與解釋([2, 3], [0, 1, 4], [1, 2, 3, 4], [1, 2, 3, 4], 是)

Wave5第二層核對=([2, 3], [0, 1, 4], [1, 2, 3, 4], [1, 2, 3, 4], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0065/)

拓撲邊界 · qf-mod33-boundary-complement-invariance · candidate





## 66. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-complement-invariance；資料={"n":5,"topology":[[],[0],[0,3],[0,2,3],[0,2,3,4],[0,1,2,3,4]],"subset":[2,3]}。請依 [subset,complement,boundary_a,boundary_complement,equal] 欄序回答。

查看答案與解釋([2, 3], [0, 1, 4], [1, 2, 3, 4], [1, 2, 3, 4], 是)

Wave5第二層核對=([2, 3], [0, 1, 4], [1, 2, 3, 4], [1, 2, 3, 4], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0066/)

拓撲邊界 · qf-mod33-boundary-complement-invariance · candidate





## 67. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-complement-invariance；資料={"n":5,"topology":[[],[0],[0,3],[0,3,4],[0,1,3,4],[0,1,2,3,4]],"subset":[3,4]}。請依 [subset,complement,boundary_a,boundary_complement,equal] 欄序回答。

查看答案與解釋([3, 4], [0, 1, 2], [1, 2, 3, 4], [1, 2, 3, 4], 是)

Wave5第二層核對=([3, 4], [0, 1, 2], [1, 2, 3, 4], [1, 2, 3, 4], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0067/)

拓撲邊界 · qf-mod33-boundary-complement-invariance · candidate





## 68. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-complement-invariance；資料={"n":5,"topology":[[],[0],[0,3],[0,3,4],[0,2,3,4],[0,1,2,3,4]],"subset":[3,4]}。請依 [subset,complement,boundary_a,boundary_complement,equal] 欄序回答。

查看答案與解釋([3, 4], [0, 1, 2], [1, 2, 3, 4], [1, 2, 3, 4], 是)

Wave5第二層核對=([3, 4], [0, 1, 2], [1, 2, 3, 4], [1, 2, 3, 4], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0068/)

拓撲邊界 · qf-mod33-boundary-complement-invariance · candidate





## 69. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-complement-invariance；資料={"n":5,"topology":[[],[0],[0,4],[0,1,4],[0,1,2,4],[0,1,2,3,4]],"subset":[1,4]}。請依 [subset,complement,boundary_a,boundary_complement,equal] 欄序回答。

查看答案與解釋([1, 4], [0, 2, 3], [1, 2, 3, 4], [1, 2, 3, 4], 是)

Wave5第二層核對=([1, 4], [0, 2, 3], [1, 2, 3, 4], [1, 2, 3, 4], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0069/)

拓撲邊界 · qf-mod33-boundary-complement-invariance · candidate





## 70. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-complement-invariance；資料={"n":5,"topology":[[],[0],[0,4],[0,1,4],[0,1,3,4],[0,1,2,3,4]],"subset":[1,4]}。請依 [subset,complement,boundary_a,boundary_complement,equal] 欄序回答。

查看答案與解釋([1, 4], [0, 2, 3], [1, 2, 3, 4], [1, 2, 3, 4], 是)

Wave5第二層核對=([1, 4], [0, 2, 3], [1, 2, 3, 4], [1, 2, 3, 4], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0070/)

拓撲邊界 · qf-mod33-boundary-complement-invariance · candidate





## 71. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-complement-invariance；資料={"n":5,"topology":[[],[0],[0,4],[0,2,4],[0,1,2,4],[0,1,2,3,4]],"subset":[2,4]}。請依 [subset,complement,boundary_a,boundary_complement,equal] 欄序回答。

查看答案與解釋([2, 4], [0, 1, 3], [1, 2, 3, 4], [1, 2, 3, 4], 是)

Wave5第二層核對=([2, 4], [0, 1, 3], [1, 2, 3, 4], [1, 2, 3, 4], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0071/)

拓撲邊界 · qf-mod33-boundary-complement-invariance · candidate





## 72. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-complement-invariance；資料={"n":5,"topology":[[],[0],[0,4],[0,2,4],[0,2,3,4],[0,1,2,3,4]],"subset":[2,4]}。請依 [subset,complement,boundary_a,boundary_complement,equal] 欄序回答。

查看答案與解釋([2, 4], [0, 1, 3], [1, 2, 3, 4], [1, 2, 3, 4], 是)

Wave5第二層核對=([2, 4], [0, 1, 3], [1, 2, 3, 4], [1, 2, 3, 4], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0072/)

拓撲邊界 · qf-mod33-boundary-complement-invariance · candidate





## 73. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-complement-invariance；資料={"n":5,"topology":[[],[0],[0,4],[0,3,4],[0,1,3,4],[0,1,2,3,4]],"subset":[3,4]}。請依 [subset,complement,boundary_a,boundary_complement,equal] 欄序回答。

查看答案與解釋([3, 4], [0, 1, 2], [1, 2, 3, 4], [1, 2, 3, 4], 是)

Wave5第二層核對=([3, 4], [0, 1, 2], [1, 2, 3, 4], [1, 2, 3, 4], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0073/)

拓撲邊界 · qf-mod33-boundary-complement-invariance · candidate





## 74. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-complement-invariance；資料={"n":5,"topology":[[],[0],[0,4],[0,3,4],[0,2,3,4],[0,1,2,3,4]],"subset":[3,4]}。請依 [subset,complement,boundary_a,boundary_complement,equal] 欄序回答。

查看答案與解釋([3, 4], [0, 1, 2], [1, 2, 3, 4], [1, 2, 3, 4], 是)

Wave5第二層核對=([3, 4], [0, 1, 2], [1, 2, 3, 4], [1, 2, 3, 4], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0074/)

拓撲邊界 · qf-mod33-boundary-complement-invariance · candidate





## 75. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-complement-invariance；資料={"n":5,"topology":[[],[1],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4]],"subset":[0,2]}。請依 [subset,complement,boundary_a,boundary_complement,equal] 欄序回答。

查看答案與解釋([0, 2], [1, 3, 4], [0, 2, 3, 4], [0, 2, 3, 4], 是)

Wave5第二層核對=([0, 2], [1, 3, 4], [0, 2, 3, 4], [0, 2, 3, 4], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0075/)

拓撲邊界 · qf-mod33-boundary-complement-invariance · candidate





## 76. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-empty-whole；資料={"n":5,"topology":[[],[0],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4]],"which":"empty"}。請依 [which,subset,boundary,empty] 欄序回答。

查看答案與解釋(empty, [], [], 是)

Wave5第二層核對=(empty, [], [], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0076/)

拓撲邊界 · qf-mod33-boundary-empty-whole · candidate





## 77. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-empty-whole；資料={"n":5,"topology":[[],[0],[0,1],[0,1,2],[0,1,2,4],[0,1,2,3,4]],"which":"whole"}。請依 [which,subset,boundary,empty] 欄序回答。

查看答案與解釋(whole, [0, 1, 2, 3, 4], [], 是)

Wave5第二層核對=(whole, [0, 1, 2, 3, 4], [], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0077/)

拓撲邊界 · qf-mod33-boundary-empty-whole · candidate





## 78. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-empty-whole；資料={"n":5,"topology":[[],[0],[0,1],[0,1,3],[0,1,2,3],[0,1,2,3,4]],"which":"empty"}。請依 [which,subset,boundary,empty] 欄序回答。

查看答案與解釋(empty, [], [], 是)

Wave5第二層核對=(empty, [], [], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0078/)

拓撲邊界 · qf-mod33-boundary-empty-whole · candidate





## 79. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-empty-whole；資料={"n":5,"topology":[[],[0],[0,1],[0,1,3],[0,1,3,4],[0,1,2,3,4]],"which":"whole"}。請依 [which,subset,boundary,empty] 欄序回答。

查看答案與解釋(whole, [0, 1, 2, 3, 4], [], 是)

Wave5第二層核對=(whole, [0, 1, 2, 3, 4], [], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0079/)

拓撲邊界 · qf-mod33-boundary-empty-whole · candidate





## 80. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-empty-whole；資料={"n":5,"topology":[[],[0],[0,1],[0,1,4],[0,1,2,4],[0,1,2,3,4]],"which":"empty"}。請依 [which,subset,boundary,empty] 欄序回答。

查看答案與解釋(empty, [], [], 是)

Wave5第二層核對=(empty, [], [], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0080/)

拓撲邊界 · qf-mod33-boundary-empty-whole · candidate





## 81. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-empty-whole；資料={"n":5,"topology":[[],[0],[0,1],[0,1,4],[0,1,3,4],[0,1,2,3,4]],"which":"whole"}。請依 [which,subset,boundary,empty] 欄序回答。

查看答案與解釋(whole, [0, 1, 2, 3, 4], [], 是)

Wave5第二層核對=(whole, [0, 1, 2, 3, 4], [], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0081/)

拓撲邊界 · qf-mod33-boundary-empty-whole · candidate





## 82. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-empty-whole；資料={"n":5,"topology":[[],[0],[0,2],[0,1,2],[0,1,2,3],[0,1,2,3,4]],"which":"empty"}。請依 [which,subset,boundary,empty] 欄序回答。

查看答案與解釋(empty, [], [], 是)

Wave5第二層核對=(empty, [], [], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0082/)

拓撲邊界 · qf-mod33-boundary-empty-whole · candidate





## 83. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-empty-whole；資料={"n":5,"topology":[[],[0],[0,2],[0,1,2],[0,1,2,4],[0,1,2,3,4]],"which":"whole"}。請依 [which,subset,boundary,empty] 欄序回答。

查看答案與解釋(whole, [0, 1, 2, 3, 4], [], 是)

Wave5第二層核對=(whole, [0, 1, 2, 3, 4], [], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0083/)

拓撲邊界 · qf-mod33-boundary-empty-whole · candidate





## 84. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-empty-whole；資料={"n":5,"topology":[[],[0],[0,2],[0,2,3],[0,1,2,3],[0,1,2,3,4]],"which":"empty"}。請依 [which,subset,boundary,empty] 欄序回答。

查看答案與解釋(empty, [], [], 是)

Wave5第二層核對=(empty, [], [], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0084/)

拓撲邊界 · qf-mod33-boundary-empty-whole · candidate





## 85. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-empty-whole；資料={"n":5,"topology":[[],[0],[0,2],[0,2,3],[0,2,3,4],[0,1,2,3,4]],"which":"whole"}。請依 [which,subset,boundary,empty] 欄序回答。

查看答案與解釋(whole, [0, 1, 2, 3, 4], [], 是)

Wave5第二層核對=(whole, [0, 1, 2, 3, 4], [], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0085/)

拓撲邊界 · qf-mod33-boundary-empty-whole · candidate





## 86. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-empty-whole；資料={"n":5,"topology":[[],[0],[0,2],[0,2,4],[0,1,2,4],[0,1,2,3,4]],"which":"empty"}。請依 [which,subset,boundary,empty] 欄序回答。

查看答案與解釋(empty, [], [], 是)

Wave5第二層核對=(empty, [], [], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0086/)

拓撲邊界 · qf-mod33-boundary-empty-whole · candidate





## 87. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-empty-whole；資料={"n":5,"topology":[[],[0],[0,2],[0,2,4],[0,2,3,4],[0,1,2,3,4]],"which":"whole"}。請依 [which,subset,boundary,empty] 欄序回答。

查看答案與解釋(whole, [0, 1, 2, 3, 4], [], 是)

Wave5第二層核對=(whole, [0, 1, 2, 3, 4], [], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0087/)

拓撲邊界 · qf-mod33-boundary-empty-whole · candidate





## 88. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-empty-whole；資料={"n":5,"topology":[[],[0],[0,3],[0,1,3],[0,1,2,3],[0,1,2,3,4]],"which":"empty"}。請依 [which,subset,boundary,empty] 欄序回答。

查看答案與解釋(empty, [], [], 是)

Wave5第二層核對=(empty, [], [], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0088/)

拓撲邊界 · qf-mod33-boundary-empty-whole · candidate





## 89. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-empty-whole；資料={"n":5,"topology":[[],[0],[0,3],[0,1,3],[0,1,3,4],[0,1,2,3,4]],"which":"whole"}。請依 [which,subset,boundary,empty] 欄序回答。

查看答案與解釋(whole, [0, 1, 2, 3, 4], [], 是)

Wave5第二層核對=(whole, [0, 1, 2, 3, 4], [], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0089/)

拓撲邊界 · qf-mod33-boundary-empty-whole · candidate





## 90. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-empty-whole；資料={"n":5,"topology":[[],[0],[0,3],[0,2,3],[0,1,2,3],[0,1,2,3,4]],"which":"empty"}。請依 [which,subset,boundary,empty] 欄序回答。

查看答案與解釋(empty, [], [], 是)

Wave5第二層核對=(empty, [], [], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0090/)

拓撲邊界 · qf-mod33-boundary-empty-whole · candidate





## 91. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-empty-whole；資料={"n":5,"topology":[[],[0],[0,3],[0,2,3],[0,2,3,4],[0,1,2,3,4]],"which":"whole"}。請依 [which,subset,boundary,empty] 欄序回答。

查看答案與解釋(whole, [0, 1, 2, 3, 4], [], 是)

Wave5第二層核對=(whole, [0, 1, 2, 3, 4], [], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0091/)

拓撲邊界 · qf-mod33-boundary-empty-whole · candidate





## 92. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-empty-whole；資料={"n":5,"topology":[[],[0],[0,3],[0,3,4],[0,1,3,4],[0,1,2,3,4]],"which":"empty"}。請依 [which,subset,boundary,empty] 欄序回答。

查看答案與解釋(empty, [], [], 是)

Wave5第二層核對=(empty, [], [], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0092/)

拓撲邊界 · qf-mod33-boundary-empty-whole · candidate





## 93. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-empty-whole；資料={"n":5,"topology":[[],[0],[0,3],[0,3,4],[0,2,3,4],[0,1,2,3,4]],"which":"whole"}。請依 [which,subset,boundary,empty] 欄序回答。

查看答案與解釋(whole, [0, 1, 2, 3, 4], [], 是)

Wave5第二層核對=(whole, [0, 1, 2, 3, 4], [], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0093/)

拓撲邊界 · qf-mod33-boundary-empty-whole · candidate





## 94. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-empty-whole；資料={"n":5,"topology":[[],[0],[0,4],[0,1,4],[0,1,2,4],[0,1,2,3,4]],"which":"empty"}。請依 [which,subset,boundary,empty] 欄序回答。

查看答案與解釋(empty, [], [], 是)

Wave5第二層核對=(empty, [], [], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0094/)

拓撲邊界 · qf-mod33-boundary-empty-whole · candidate





## 95. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-empty-whole；資料={"n":5,"topology":[[],[0],[0,4],[0,1,4],[0,1,3,4],[0,1,2,3,4]],"which":"whole"}。請依 [which,subset,boundary,empty] 欄序回答。

查看答案與解釋(whole, [0, 1, 2, 3, 4], [], 是)

Wave5第二層核對=(whole, [0, 1, 2, 3, 4], [], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0095/)

拓撲邊界 · qf-mod33-boundary-empty-whole · candidate





## 96. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-empty-whole；資料={"n":5,"topology":[[],[0],[0,4],[0,2,4],[0,1,2,4],[0,1,2,3,4]],"which":"empty"}。請依 [which,subset,boundary,empty] 欄序回答。

查看答案與解釋(empty, [], [], 是)

Wave5第二層核對=(empty, [], [], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0096/)

拓撲邊界 · qf-mod33-boundary-empty-whole · candidate





## 97. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-empty-whole；資料={"n":5,"topology":[[],[0],[0,4],[0,2,4],[0,2,3,4],[0,1,2,3,4]],"which":"whole"}。請依 [which,subset,boundary,empty] 欄序回答。

查看答案與解釋(whole, [0, 1, 2, 3, 4], [], 是)

Wave5第二層核對=(whole, [0, 1, 2, 3, 4], [], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0097/)

拓撲邊界 · qf-mod33-boundary-empty-whole · candidate





## 98. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-empty-whole；資料={"n":5,"topology":[[],[0],[0,4],[0,3,4],[0,1,3,4],[0,1,2,3,4]],"which":"empty"}。請依 [which,subset,boundary,empty] 欄序回答。

查看答案與解釋(empty, [], [], 是)

Wave5第二層核對=(empty, [], [], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0098/)

拓撲邊界 · qf-mod33-boundary-empty-whole · candidate





## 99. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-empty-whole；資料={"n":5,"topology":[[],[0],[0,4],[0,3,4],[0,2,3,4],[0,1,2,3,4]],"which":"whole"}。請依 [which,subset,boundary,empty] 欄序回答。

查看答案與解釋(whole, [0, 1, 2, 3, 4], [], 是)

Wave5第二層核對=(whole, [0, 1, 2, 3, 4], [], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0099/)

拓撲邊界 · qf-mod33-boundary-empty-whole · candidate





## 100. 拓撲邊界

完整有限拓撲與同一載體子集。操作=boundary-empty-whole；資料={"n":5,"topology":[[],[1],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4]],"which":"empty"}。請依 [which,subset,boundary,empty] 欄序回答。

查看答案與解釋(empty, [], [], 是)

Wave5第二層核對=(empty, [], [], 是)；依完整明示資料重算；boundary等於closure扣除interior且與補集boundary相同；空集與全空間boundary為空；結果相對拓撲而非圖形外觀。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261102-r04-topological-boundary-0100/)

拓撲邊界 · qf-mod33-boundary-empty-whole · candidate



[原始題目 JSONL](https://ocme.evemisslab.com/data/questions/batches/batch-20261014-advance-20261102-r04-topological-boundary-foundations/questions.jsonl) · [驗收報告](https://ocme.evemisslab.com/data/questions/batches/batch-20261014-advance-20261102-r04-topological-boundary-foundations/validation-report.json)