# 函數列一致收斂基礎 · 脈衝 R02

本批已通過 Schema、去重、來源快照與獨立答案重算；仍未標記為人工審定。

本題庫已有對應的中英逐步詳解。原題的 candidate 與英文 ai_candidate 狀態保留；AI 覆核、有限計算與 Lean 形式證明分開標示。

batch-20261014-advance-20261104-r02-uniform-convergence-of-functions-foundations · 2026-10-14 · 100 題

欄序為來源綁定的呈現補充；原始 JSONL 與數學答案不變。

[欄序與來源綁定資料](https://ocme.evemisslab.com/data/i18n/question-output-protocols.json)



## 1. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-domain-witness；資料={"limit":[0,1],"coefficients":[1,-2],"shift":2,"epsilon":[1,10]}。請依 [epsilon, pointwise_witnesses, N, same_N_for_all_points, certificate] 欄序回答。

查看答案與解釋(1/10, [[0, 9], [1, 19]], 19, 是, same_N_for_all_finite_domain_points)

Wave5第四層核對=(1/10, [[0, 9], [1, 19]], 19, 是, same_N_for_all_finite_domain_points)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0001/)

函數列一致收斂 · qf-mod35-uniform-finite-domain-witness · candidate





## 2. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-domain-witness；資料={"limit":[1,2],"coefficients":[2,-3],"shift":2,"epsilon":[1,11]}。請依 [epsilon, pointwise_witnesses, N, same_N_for_all_points, certificate] 欄序回答。

查看答案與解釋(1/11, [[0, 21], [1, 32]], 32, 是, same_N_for_all_finite_domain_points)

Wave5第四層核對=(1/11, [[0, 21], [1, 32]], 32, 是, same_N_for_all_finite_domain_points)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0002/)

函數列一致收斂 · qf-mod35-uniform-finite-domain-witness · candidate





## 3. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-domain-witness；資料={"limit":[2,3],"coefficients":[3,-4],"shift":2,"epsilon":[1,12]}。請依 [epsilon, pointwise_witnesses, N, same_N_for_all_points, certificate] 欄序回答。

查看答案與解釋(1/12, [[0, 35], [1, 47]], 47, 是, same_N_for_all_finite_domain_points)

Wave5第四層核對=(1/12, [[0, 35], [1, 47]], 47, 是, same_N_for_all_finite_domain_points)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0003/)

函數列一致收斂 · qf-mod35-uniform-finite-domain-witness · candidate





## 4. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-domain-witness；資料={"limit":[3,4],"coefficients":[4,-5],"shift":2,"epsilon":[1,13]}。請依 [epsilon, pointwise_witnesses, N, same_N_for_all_points, certificate] 欄序回答。

查看答案與解釋(1/13, [[0, 51], [1, 64]], 64, 是, same_N_for_all_finite_domain_points)

Wave5第四層核對=(1/13, [[0, 51], [1, 64]], 64, 是, same_N_for_all_finite_domain_points)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0004/)

函數列一致收斂 · qf-mod35-uniform-finite-domain-witness · candidate





## 5. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-domain-witness；資料={"limit":[4,5],"coefficients":[5,-6],"shift":2,"epsilon":[1,14]}。請依 [epsilon, pointwise_witnesses, N, same_N_for_all_points, certificate] 欄序回答。

查看答案與解釋(1/14, [[0, 69], [1, 83]], 83, 是, same_N_for_all_finite_domain_points)

Wave5第四層核對=(1/14, [[0, 69], [1, 83]], 83, 是, same_N_for_all_finite_domain_points)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0005/)

函數列一致收斂 · qf-mod35-uniform-finite-domain-witness · candidate





## 6. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-domain-witness；資料={"limit":[5,6],"coefficients":[6,-7],"shift":2,"epsilon":[1,15]}。請依 [epsilon, pointwise_witnesses, N, same_N_for_all_points, certificate] 欄序回答。

查看答案與解釋(1/15, [[0, 89], [1, 104]], 104, 是, same_N_for_all_finite_domain_points)

Wave5第四層核對=(1/15, [[0, 89], [1, 104]], 104, 是, same_N_for_all_finite_domain_points)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0006/)

函數列一致收斂 · qf-mod35-uniform-finite-domain-witness · candidate





## 7. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-domain-witness；資料={"limit":[6,7],"coefficients":[7,-8],"shift":2,"epsilon":[1,16]}。請依 [epsilon, pointwise_witnesses, N, same_N_for_all_points, certificate] 欄序回答。

查看答案與解釋(1/16, [[0, 111], [1, 127]], 127, 是, same_N_for_all_finite_domain_points)

Wave5第四層核對=(1/16, [[0, 111], [1, 127]], 127, 是, same_N_for_all_finite_domain_points)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0007/)

函數列一致收斂 · qf-mod35-uniform-finite-domain-witness · candidate





## 8. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-domain-witness；資料={"limit":[7,8],"coefficients":[8,-9],"shift":2,"epsilon":[1,17]}。請依 [epsilon, pointwise_witnesses, N, same_N_for_all_points, certificate] 欄序回答。

查看答案與解釋(1/17, [[0, 135], [1, 152]], 152, 是, same_N_for_all_finite_domain_points)

Wave5第四層核對=(1/17, [[0, 135], [1, 152]], 152, 是, same_N_for_all_finite_domain_points)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0008/)

函數列一致收斂 · qf-mod35-uniform-finite-domain-witness · candidate





## 9. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-domain-witness；資料={"limit":[8,9],"coefficients":[9,-10],"shift":2,"epsilon":[1,18]}。請依 [epsilon, pointwise_witnesses, N, same_N_for_all_points, certificate] 欄序回答。

查看答案與解釋(1/18, [[0, 161], [1, 179]], 179, 是, same_N_for_all_finite_domain_points)

Wave5第四層核對=(1/18, [[0, 161], [1, 179]], 179, 是, same_N_for_all_finite_domain_points)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0009/)

函數列一致收斂 · qf-mod35-uniform-finite-domain-witness · candidate





## 10. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-domain-witness；資料={"limit":[9,10],"coefficients":[10,-11],"shift":2,"epsilon":[1,19]}。請依 [epsilon, pointwise_witnesses, N, same_N_for_all_points, certificate] 欄序回答。

查看答案與解釋(1/19, [[0, 189], [1, 208]], 208, 是, same_N_for_all_finite_domain_points)

Wave5第四層核對=(1/19, [[0, 189], [1, 208]], 208, 是, same_N_for_all_finite_domain_points)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0010/)

函數列一致收斂 · qf-mod35-uniform-finite-domain-witness · candidate





## 11. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-domain-witness；資料={"limit":[10,11],"coefficients":[11,-12],"shift":2,"epsilon":[1,20]}。請依 [epsilon, pointwise_witnesses, N, same_N_for_all_points, certificate] 欄序回答。

查看答案與解釋(1/20, [[0, 219], [1, 239]], 239, 是, same_N_for_all_finite_domain_points)

Wave5第四層核對=(1/20, [[0, 219], [1, 239]], 239, 是, same_N_for_all_finite_domain_points)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0011/)

函數列一致收斂 · qf-mod35-uniform-finite-domain-witness · candidate





## 12. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-domain-witness；資料={"limit":[11,12],"coefficients":[12,-13],"shift":2,"epsilon":[1,21]}。請依 [epsilon, pointwise_witnesses, N, same_N_for_all_points, certificate] 欄序回答。

查看答案與解釋(1/21, [[0, 251], [1, 272]], 272, 是, same_N_for_all_finite_domain_points)

Wave5第四層核對=(1/21, [[0, 251], [1, 272]], 272, 是, same_N_for_all_finite_domain_points)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0012/)

函數列一致收斂 · qf-mod35-uniform-finite-domain-witness · candidate





## 13. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-domain-witness；資料={"limit":[12,13],"coefficients":[13,-14],"shift":2,"epsilon":[1,22]}。請依 [epsilon, pointwise_witnesses, N, same_N_for_all_points, certificate] 欄序回答。

查看答案與解釋(1/22, [[0, 285], [1, 307]], 307, 是, same_N_for_all_finite_domain_points)

Wave5第四層核對=(1/22, [[0, 285], [1, 307]], 307, 是, same_N_for_all_finite_domain_points)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0013/)

函數列一致收斂 · qf-mod35-uniform-finite-domain-witness · candidate





## 14. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-domain-witness；資料={"limit":[13,14],"coefficients":[14,-15],"shift":2,"epsilon":[1,23]}。請依 [epsilon, pointwise_witnesses, N, same_N_for_all_points, certificate] 欄序回答。

查看答案與解釋(1/23, [[0, 321], [1, 344]], 344, 是, same_N_for_all_finite_domain_points)

Wave5第四層核對=(1/23, [[0, 321], [1, 344]], 344, 是, same_N_for_all_finite_domain_points)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0014/)

函數列一致收斂 · qf-mod35-uniform-finite-domain-witness · candidate





## 15. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-domain-witness；資料={"limit":[14,15],"coefficients":[15,-16],"shift":2,"epsilon":[1,24]}。請依 [epsilon, pointwise_witnesses, N, same_N_for_all_points, certificate] 欄序回答。

查看答案與解釋(1/24, [[0, 359], [1, 383]], 383, 是, same_N_for_all_finite_domain_points)

Wave5第四層核對=(1/24, [[0, 359], [1, 383]], 383, 是, same_N_for_all_finite_domain_points)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0015/)

函數列一致收斂 · qf-mod35-uniform-finite-domain-witness · candidate





## 16. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-domain-witness；資料={"limit":[15,16],"coefficients":[16,-17],"shift":2,"epsilon":[1,25]}。請依 [epsilon, pointwise_witnesses, N, same_N_for_all_points, certificate] 欄序回答。

查看答案與解釋(1/25, [[0, 399], [1, 424]], 424, 是, same_N_for_all_finite_domain_points)

Wave5第四層核對=(1/25, [[0, 399], [1, 424]], 424, 是, same_N_for_all_finite_domain_points)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0016/)

函數列一致收斂 · qf-mod35-uniform-finite-domain-witness · candidate





## 17. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-domain-witness；資料={"limit":[16,17],"coefficients":[17,-18],"shift":2,"epsilon":[1,26]}。請依 [epsilon, pointwise_witnesses, N, same_N_for_all_points, certificate] 欄序回答。

查看答案與解釋(1/26, [[0, 441], [1, 467]], 467, 是, same_N_for_all_finite_domain_points)

Wave5第四層核對=(1/26, [[0, 441], [1, 467]], 467, 是, same_N_for_all_finite_domain_points)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0017/)

函數列一致收斂 · qf-mod35-uniform-finite-domain-witness · candidate





## 18. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-domain-witness；資料={"limit":[17,18],"coefficients":[18,-19],"shift":2,"epsilon":[1,27]}。請依 [epsilon, pointwise_witnesses, N, same_N_for_all_points, certificate] 欄序回答。

查看答案與解釋(1/27, [[0, 485], [1, 512]], 512, 是, same_N_for_all_finite_domain_points)

Wave5第四層核對=(1/27, [[0, 485], [1, 512]], 512, 是, same_N_for_all_finite_domain_points)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0018/)

函數列一致收斂 · qf-mod35-uniform-finite-domain-witness · candidate





## 19. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-domain-witness；資料={"limit":[18,19],"coefficients":[19,-20],"shift":2,"epsilon":[1,28]}。請依 [epsilon, pointwise_witnesses, N, same_N_for_all_points, certificate] 欄序回答。

查看答案與解釋(1/28, [[0, 531], [1, 559]], 559, 是, same_N_for_all_finite_domain_points)

Wave5第四層核對=(1/28, [[0, 531], [1, 559]], 559, 是, same_N_for_all_finite_domain_points)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0019/)

函數列一致收斂 · qf-mod35-uniform-finite-domain-witness · candidate





## 20. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-domain-witness；資料={"limit":[19,20],"coefficients":[20,-21],"shift":2,"epsilon":[1,29]}。請依 [epsilon, pointwise_witnesses, N, same_N_for_all_points, certificate] 欄序回答。

查看答案與解釋(1/29, [[0, 579], [1, 608]], 608, 是, same_N_for_all_finite_domain_points)

Wave5第四層核對=(1/29, [[0, 579], [1, 608]], 608, 是, same_N_for_all_finite_domain_points)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0020/)

函數列一致收斂 · qf-mod35-uniform-finite-domain-witness · candidate





## 21. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-domain-witness；資料={"limit":[20,21],"coefficients":[21,-22],"shift":2,"epsilon":[1,30]}。請依 [epsilon, pointwise_witnesses, N, same_N_for_all_points, certificate] 欄序回答。

查看答案與解釋(1/30, [[0, 629], [1, 659]], 659, 是, same_N_for_all_finite_domain_points)

Wave5第四層核對=(1/30, [[0, 629], [1, 659]], 659, 是, same_N_for_all_finite_domain_points)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0021/)

函數列一致收斂 · qf-mod35-uniform-finite-domain-witness · candidate





## 22. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-domain-witness；資料={"limit":[21,22],"coefficients":[22,-23],"shift":2,"epsilon":[1,31]}。請依 [epsilon, pointwise_witnesses, N, same_N_for_all_points, certificate] 欄序回答。

查看答案與解釋(1/31, [[0, 681], [1, 712]], 712, 是, same_N_for_all_finite_domain_points)

Wave5第四層核對=(1/31, [[0, 681], [1, 712]], 712, 是, same_N_for_all_finite_domain_points)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0022/)

函數列一致收斂 · qf-mod35-uniform-finite-domain-witness · candidate





## 23. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-domain-witness；資料={"limit":[22,23],"coefficients":[23,-24],"shift":2,"epsilon":[1,32]}。請依 [epsilon, pointwise_witnesses, N, same_N_for_all_points, certificate] 欄序回答。

查看答案與解釋(1/32, [[0, 735], [1, 767]], 767, 是, same_N_for_all_finite_domain_points)

Wave5第四層核對=(1/32, [[0, 735], [1, 767]], 767, 是, same_N_for_all_finite_domain_points)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0023/)

函數列一致收斂 · qf-mod35-uniform-finite-domain-witness · candidate





## 24. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-domain-witness；資料={"limit":[23,24],"coefficients":[24,-25],"shift":2,"epsilon":[1,33]}。請依 [epsilon, pointwise_witnesses, N, same_N_for_all_points, certificate] 欄序回答。

查看答案與解釋(1/33, [[0, 791], [1, 824]], 824, 是, same_N_for_all_finite_domain_points)

Wave5第四層核對=(1/33, [[0, 791], [1, 824]], 824, 是, same_N_for_all_finite_domain_points)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0024/)

函數列一致收斂 · qf-mod35-uniform-finite-domain-witness · candidate





## 25. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-domain-witness；資料={"limit":[24,25],"coefficients":[25,-26],"shift":2,"epsilon":[1,34]}。請依 [epsilon, pointwise_witnesses, N, same_N_for_all_points, certificate] 欄序回答。

查看答案與解釋(1/34, [[0, 849], [1, 883]], 883, 是, same_N_for_all_finite_domain_points)

Wave5第四層核對=(1/34, [[0, 849], [1, 883]], 883, 是, same_N_for_all_finite_domain_points)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0025/)

函數列一致收斂 · qf-mod35-uniform-finite-domain-witness · candidate





## 26. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-sup-gap；資料={"limit":[0,1],"coefficients":[1,-2],"shift":2,"n":1}。請依 [n, sup_gap, certificate] 欄序回答。

查看答案與解釋(1, 2/3, exact_finite_domain_supremum)

Wave5第四層核對=(1, 2/3, exact_finite_domain_supremum)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0026/)

函數列一致收斂 · qf-mod35-uniform-sup-gap · candidate





## 27. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-sup-gap；資料={"limit":[1,2],"coefficients":[2,-3],"shift":2,"n":2}。請依 [n, sup_gap, certificate] 欄序回答。

查看答案與解釋(2, 3/4, exact_finite_domain_supremum)

Wave5第四層核對=(2, 3/4, exact_finite_domain_supremum)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0027/)

函數列一致收斂 · qf-mod35-uniform-sup-gap · candidate





## 28. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-sup-gap；資料={"limit":[2,3],"coefficients":[3,-4],"shift":2,"n":3}。請依 [n, sup_gap, certificate] 欄序回答。

查看答案與解釋(3, 4/5, exact_finite_domain_supremum)

Wave5第四層核對=(3, 4/5, exact_finite_domain_supremum)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0028/)

函數列一致收斂 · qf-mod35-uniform-sup-gap · candidate





## 29. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-sup-gap；資料={"limit":[3,4],"coefficients":[4,-5],"shift":2,"n":4}。請依 [n, sup_gap, certificate] 欄序回答。

查看答案與解釋(4, 5/6, exact_finite_domain_supremum)

Wave5第四層核對=(4, 5/6, exact_finite_domain_supremum)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0029/)

函數列一致收斂 · qf-mod35-uniform-sup-gap · candidate





## 30. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-sup-gap；資料={"limit":[4,5],"coefficients":[5,-6],"shift":2,"n":5}。請依 [n, sup_gap, certificate] 欄序回答。

查看答案與解釋(5, 6/7, exact_finite_domain_supremum)

Wave5第四層核對=(5, 6/7, exact_finite_domain_supremum)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0030/)

函數列一致收斂 · qf-mod35-uniform-sup-gap · candidate





## 31. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-sup-gap；資料={"limit":[5,6],"coefficients":[6,-7],"shift":2,"n":6}。請依 [n, sup_gap, certificate] 欄序回答。

查看答案與解釋(6, 7/8, exact_finite_domain_supremum)

Wave5第四層核對=(6, 7/8, exact_finite_domain_supremum)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0031/)

函數列一致收斂 · qf-mod35-uniform-sup-gap · candidate





## 32. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-sup-gap；資料={"limit":[6,7],"coefficients":[7,-8],"shift":2,"n":7}。請依 [n, sup_gap, certificate] 欄序回答。

查看答案與解釋(7, 8/9, exact_finite_domain_supremum)

Wave5第四層核對=(7, 8/9, exact_finite_domain_supremum)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0032/)

函數列一致收斂 · qf-mod35-uniform-sup-gap · candidate





## 33. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-sup-gap；資料={"limit":[7,8],"coefficients":[8,-9],"shift":2,"n":8}。請依 [n, sup_gap, certificate] 欄序回答。

查看答案與解釋(8, 9/10, exact_finite_domain_supremum)

Wave5第四層核對=(8, 9/10, exact_finite_domain_supremum)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0033/)

函數列一致收斂 · qf-mod35-uniform-sup-gap · candidate





## 34. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-sup-gap；資料={"limit":[8,9],"coefficients":[9,-10],"shift":2,"n":9}。請依 [n, sup_gap, certificate] 欄序回答。

查看答案與解釋(9, 10/11, exact_finite_domain_supremum)

Wave5第四層核對=(9, 10/11, exact_finite_domain_supremum)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0034/)

函數列一致收斂 · qf-mod35-uniform-sup-gap · candidate





## 35. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-sup-gap；資料={"limit":[9,10],"coefficients":[10,-11],"shift":2,"n":10}。請依 [n, sup_gap, certificate] 欄序回答。

查看答案與解釋(10, 11/12, exact_finite_domain_supremum)

Wave5第四層核對=(10, 11/12, exact_finite_domain_supremum)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0035/)

函數列一致收斂 · qf-mod35-uniform-sup-gap · candidate





## 36. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-sup-gap；資料={"limit":[10,11],"coefficients":[11,-12],"shift":2,"n":11}。請依 [n, sup_gap, certificate] 欄序回答。

查看答案與解釋(11, 12/13, exact_finite_domain_supremum)

Wave5第四層核對=(11, 12/13, exact_finite_domain_supremum)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0036/)

函數列一致收斂 · qf-mod35-uniform-sup-gap · candidate





## 37. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-sup-gap；資料={"limit":[11,12],"coefficients":[12,-13],"shift":2,"n":12}。請依 [n, sup_gap, certificate] 欄序回答。

查看答案與解釋(12, 13/14, exact_finite_domain_supremum)

Wave5第四層核對=(12, 13/14, exact_finite_domain_supremum)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0037/)

函數列一致收斂 · qf-mod35-uniform-sup-gap · candidate





## 38. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-sup-gap；資料={"limit":[12,13],"coefficients":[13,-14],"shift":2,"n":13}。請依 [n, sup_gap, certificate] 欄序回答。

查看答案與解釋(13, 14/15, exact_finite_domain_supremum)

Wave5第四層核對=(13, 14/15, exact_finite_domain_supremum)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0038/)

函數列一致收斂 · qf-mod35-uniform-sup-gap · candidate





## 39. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-sup-gap；資料={"limit":[13,14],"coefficients":[14,-15],"shift":2,"n":14}。請依 [n, sup_gap, certificate] 欄序回答。

查看答案與解釋(14, 15/16, exact_finite_domain_supremum)

Wave5第四層核對=(14, 15/16, exact_finite_domain_supremum)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0039/)

函數列一致收斂 · qf-mod35-uniform-sup-gap · candidate





## 40. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-sup-gap；資料={"limit":[14,15],"coefficients":[15,-16],"shift":2,"n":15}。請依 [n, sup_gap, certificate] 欄序回答。

查看答案與解釋(15, 16/17, exact_finite_domain_supremum)

Wave5第四層核對=(15, 16/17, exact_finite_domain_supremum)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0040/)

函數列一致收斂 · qf-mod35-uniform-sup-gap · candidate





## 41. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-sup-gap；資料={"limit":[15,16],"coefficients":[16,-17],"shift":2,"n":16}。請依 [n, sup_gap, certificate] 欄序回答。

查看答案與解釋(16, 17/18, exact_finite_domain_supremum)

Wave5第四層核對=(16, 17/18, exact_finite_domain_supremum)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0041/)

函數列一致收斂 · qf-mod35-uniform-sup-gap · candidate





## 42. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-sup-gap；資料={"limit":[16,17],"coefficients":[17,-18],"shift":2,"n":17}。請依 [n, sup_gap, certificate] 欄序回答。

查看答案與解釋(17, 18/19, exact_finite_domain_supremum)

Wave5第四層核對=(17, 18/19, exact_finite_domain_supremum)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0042/)

函數列一致收斂 · qf-mod35-uniform-sup-gap · candidate





## 43. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-sup-gap；資料={"limit":[17,18],"coefficients":[18,-19],"shift":2,"n":18}。請依 [n, sup_gap, certificate] 欄序回答。

查看答案與解釋(18, 19/20, exact_finite_domain_supremum)

Wave5第四層核對=(18, 19/20, exact_finite_domain_supremum)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0043/)

函數列一致收斂 · qf-mod35-uniform-sup-gap · candidate





## 44. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-sup-gap；資料={"limit":[18,19],"coefficients":[19,-20],"shift":2,"n":19}。請依 [n, sup_gap, certificate] 欄序回答。

查看答案與解釋(19, 20/21, exact_finite_domain_supremum)

Wave5第四層核對=(19, 20/21, exact_finite_domain_supremum)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0044/)

函數列一致收斂 · qf-mod35-uniform-sup-gap · candidate





## 45. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-sup-gap；資料={"limit":[19,20],"coefficients":[20,-21],"shift":2,"n":20}。請依 [n, sup_gap, certificate] 欄序回答。

查看答案與解釋(20, 21/22, exact_finite_domain_supremum)

Wave5第四層核對=(20, 21/22, exact_finite_domain_supremum)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0045/)

函數列一致收斂 · qf-mod35-uniform-sup-gap · candidate





## 46. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-sup-gap；資料={"limit":[20,21],"coefficients":[21,-22],"shift":2,"n":21}。請依 [n, sup_gap, certificate] 欄序回答。

查看答案與解釋(21, 22/23, exact_finite_domain_supremum)

Wave5第四層核對=(21, 22/23, exact_finite_domain_supremum)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0046/)

函數列一致收斂 · qf-mod35-uniform-sup-gap · candidate





## 47. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-sup-gap；資料={"limit":[21,22],"coefficients":[22,-23],"shift":2,"n":22}。請依 [n, sup_gap, certificate] 欄序回答。

查看答案與解釋(22, 23/24, exact_finite_domain_supremum)

Wave5第四層核對=(22, 23/24, exact_finite_domain_supremum)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0047/)

函數列一致收斂 · qf-mod35-uniform-sup-gap · candidate





## 48. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-sup-gap；資料={"limit":[22,23],"coefficients":[23,-24],"shift":2,"n":23}。請依 [n, sup_gap, certificate] 欄序回答。

查看答案與解釋(23, 24/25, exact_finite_domain_supremum)

Wave5第四層核對=(23, 24/25, exact_finite_domain_supremum)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0048/)

函數列一致收斂 · qf-mod35-uniform-sup-gap · candidate





## 49. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-sup-gap；資料={"limit":[23,24],"coefficients":[24,-25],"shift":2,"n":24}。請依 [n, sup_gap, certificate] 欄序回答。

查看答案與解釋(24, 25/26, exact_finite_domain_supremum)

Wave5第四層核對=(24, 25/26, exact_finite_domain_supremum)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0049/)

函數列一致收斂 · qf-mod35-uniform-sup-gap · candidate





## 50. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-sup-gap；資料={"limit":[24,25],"coefficients":[25,-26],"shift":2,"n":25}。請依 [n, sup_gap, certificate] 欄序回答。

查看答案與解釋(25, 26/27, exact_finite_domain_supremum)

Wave5第四層核對=(25, 26/27, exact_finite_domain_supremum)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0050/)

函數列一致收斂 · qf-mod35-uniform-sup-gap · candidate





## 51. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-pointwise-max；資料={"limit":[0,1],"coefficients":[1,-2],"shift":2,"epsilon":[1,10]}。請依 [pointwise_witnesses, N, uniform_on_this_finite_domain, boundary] 欄序回答。

查看答案與解釋([[0, 9], [1, 19]], 19, 是, finite_maximum_only_not_infinite_domain_implication)

Wave5第四層核對=([[0, 9], [1, 19]], 19, 是, finite_maximum_only_not_infinite_domain_implication)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0051/)

函數列一致收斂 · qf-mod35-uniform-pointwise-max · candidate





## 52. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-pointwise-max；資料={"limit":[1,2],"coefficients":[2,-3],"shift":2,"epsilon":[1,11]}。請依 [pointwise_witnesses, N, uniform_on_this_finite_domain, boundary] 欄序回答。

查看答案與解釋([[0, 21], [1, 32]], 32, 是, finite_maximum_only_not_infinite_domain_implication)

Wave5第四層核對=([[0, 21], [1, 32]], 32, 是, finite_maximum_only_not_infinite_domain_implication)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0052/)

函數列一致收斂 · qf-mod35-uniform-pointwise-max · candidate





## 53. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-pointwise-max；資料={"limit":[2,3],"coefficients":[3,-4],"shift":2,"epsilon":[1,12]}。請依 [pointwise_witnesses, N, uniform_on_this_finite_domain, boundary] 欄序回答。

查看答案與解釋([[0, 35], [1, 47]], 47, 是, finite_maximum_only_not_infinite_domain_implication)

Wave5第四層核對=([[0, 35], [1, 47]], 47, 是, finite_maximum_only_not_infinite_domain_implication)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0053/)

函數列一致收斂 · qf-mod35-uniform-pointwise-max · candidate





## 54. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-pointwise-max；資料={"limit":[3,4],"coefficients":[4,-5],"shift":2,"epsilon":[1,13]}。請依 [pointwise_witnesses, N, uniform_on_this_finite_domain, boundary] 欄序回答。

查看答案與解釋([[0, 51], [1, 64]], 64, 是, finite_maximum_only_not_infinite_domain_implication)

Wave5第四層核對=([[0, 51], [1, 64]], 64, 是, finite_maximum_only_not_infinite_domain_implication)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0054/)

函數列一致收斂 · qf-mod35-uniform-pointwise-max · candidate





## 55. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-pointwise-max；資料={"limit":[4,5],"coefficients":[5,-6],"shift":2,"epsilon":[1,14]}。請依 [pointwise_witnesses, N, uniform_on_this_finite_domain, boundary] 欄序回答。

查看答案與解釋([[0, 69], [1, 83]], 83, 是, finite_maximum_only_not_infinite_domain_implication)

Wave5第四層核對=([[0, 69], [1, 83]], 83, 是, finite_maximum_only_not_infinite_domain_implication)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0055/)

函數列一致收斂 · qf-mod35-uniform-pointwise-max · candidate





## 56. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-pointwise-max；資料={"limit":[5,6],"coefficients":[6,-7],"shift":2,"epsilon":[1,15]}。請依 [pointwise_witnesses, N, uniform_on_this_finite_domain, boundary] 欄序回答。

查看答案與解釋([[0, 89], [1, 104]], 104, 是, finite_maximum_only_not_infinite_domain_implication)

Wave5第四層核對=([[0, 89], [1, 104]], 104, 是, finite_maximum_only_not_infinite_domain_implication)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0056/)

函數列一致收斂 · qf-mod35-uniform-pointwise-max · candidate





## 57. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-pointwise-max；資料={"limit":[6,7],"coefficients":[7,-8],"shift":2,"epsilon":[1,16]}。請依 [pointwise_witnesses, N, uniform_on_this_finite_domain, boundary] 欄序回答。

查看答案與解釋([[0, 111], [1, 127]], 127, 是, finite_maximum_only_not_infinite_domain_implication)

Wave5第四層核對=([[0, 111], [1, 127]], 127, 是, finite_maximum_only_not_infinite_domain_implication)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0057/)

函數列一致收斂 · qf-mod35-uniform-pointwise-max · candidate





## 58. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-pointwise-max；資料={"limit":[7,8],"coefficients":[8,-9],"shift":2,"epsilon":[1,17]}。請依 [pointwise_witnesses, N, uniform_on_this_finite_domain, boundary] 欄序回答。

查看答案與解釋([[0, 135], [1, 152]], 152, 是, finite_maximum_only_not_infinite_domain_implication)

Wave5第四層核對=([[0, 135], [1, 152]], 152, 是, finite_maximum_only_not_infinite_domain_implication)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0058/)

函數列一致收斂 · qf-mod35-uniform-pointwise-max · candidate





## 59. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-pointwise-max；資料={"limit":[8,9],"coefficients":[9,-10],"shift":2,"epsilon":[1,18]}。請依 [pointwise_witnesses, N, uniform_on_this_finite_domain, boundary] 欄序回答。

查看答案與解釋([[0, 161], [1, 179]], 179, 是, finite_maximum_only_not_infinite_domain_implication)

Wave5第四層核對=([[0, 161], [1, 179]], 179, 是, finite_maximum_only_not_infinite_domain_implication)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0059/)

函數列一致收斂 · qf-mod35-uniform-pointwise-max · candidate





## 60. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-pointwise-max；資料={"limit":[9,10],"coefficients":[10,-11],"shift":2,"epsilon":[1,19]}。請依 [pointwise_witnesses, N, uniform_on_this_finite_domain, boundary] 欄序回答。

查看答案與解釋([[0, 189], [1, 208]], 208, 是, finite_maximum_only_not_infinite_domain_implication)

Wave5第四層核對=([[0, 189], [1, 208]], 208, 是, finite_maximum_only_not_infinite_domain_implication)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0060/)

函數列一致收斂 · qf-mod35-uniform-pointwise-max · candidate





## 61. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-pointwise-max；資料={"limit":[10,11],"coefficients":[11,-12],"shift":2,"epsilon":[1,20]}。請依 [pointwise_witnesses, N, uniform_on_this_finite_domain, boundary] 欄序回答。

查看答案與解釋([[0, 219], [1, 239]], 239, 是, finite_maximum_only_not_infinite_domain_implication)

Wave5第四層核對=([[0, 219], [1, 239]], 239, 是, finite_maximum_only_not_infinite_domain_implication)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0061/)

函數列一致收斂 · qf-mod35-uniform-pointwise-max · candidate





## 62. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-pointwise-max；資料={"limit":[11,12],"coefficients":[12,-13],"shift":2,"epsilon":[1,21]}。請依 [pointwise_witnesses, N, uniform_on_this_finite_domain, boundary] 欄序回答。

查看答案與解釋([[0, 251], [1, 272]], 272, 是, finite_maximum_only_not_infinite_domain_implication)

Wave5第四層核對=([[0, 251], [1, 272]], 272, 是, finite_maximum_only_not_infinite_domain_implication)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0062/)

函數列一致收斂 · qf-mod35-uniform-pointwise-max · candidate





## 63. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-pointwise-max；資料={"limit":[12,13],"coefficients":[13,-14],"shift":2,"epsilon":[1,22]}。請依 [pointwise_witnesses, N, uniform_on_this_finite_domain, boundary] 欄序回答。

查看答案與解釋([[0, 285], [1, 307]], 307, 是, finite_maximum_only_not_infinite_domain_implication)

Wave5第四層核對=([[0, 285], [1, 307]], 307, 是, finite_maximum_only_not_infinite_domain_implication)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0063/)

函數列一致收斂 · qf-mod35-uniform-pointwise-max · candidate





## 64. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-pointwise-max；資料={"limit":[13,14],"coefficients":[14,-15],"shift":2,"epsilon":[1,23]}。請依 [pointwise_witnesses, N, uniform_on_this_finite_domain, boundary] 欄序回答。

查看答案與解釋([[0, 321], [1, 344]], 344, 是, finite_maximum_only_not_infinite_domain_implication)

Wave5第四層核對=([[0, 321], [1, 344]], 344, 是, finite_maximum_only_not_infinite_domain_implication)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0064/)

函數列一致收斂 · qf-mod35-uniform-pointwise-max · candidate





## 65. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-pointwise-max；資料={"limit":[14,15],"coefficients":[15,-16],"shift":2,"epsilon":[1,24]}。請依 [pointwise_witnesses, N, uniform_on_this_finite_domain, boundary] 欄序回答。

查看答案與解釋([[0, 359], [1, 383]], 383, 是, finite_maximum_only_not_infinite_domain_implication)

Wave5第四層核對=([[0, 359], [1, 383]], 383, 是, finite_maximum_only_not_infinite_domain_implication)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0065/)

函數列一致收斂 · qf-mod35-uniform-pointwise-max · candidate





## 66. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-pointwise-max；資料={"limit":[15,16],"coefficients":[16,-17],"shift":2,"epsilon":[1,25]}。請依 [pointwise_witnesses, N, uniform_on_this_finite_domain, boundary] 欄序回答。

查看答案與解釋([[0, 399], [1, 424]], 424, 是, finite_maximum_only_not_infinite_domain_implication)

Wave5第四層核對=([[0, 399], [1, 424]], 424, 是, finite_maximum_only_not_infinite_domain_implication)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0066/)

函數列一致收斂 · qf-mod35-uniform-pointwise-max · candidate





## 67. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-pointwise-max；資料={"limit":[16,17],"coefficients":[17,-18],"shift":2,"epsilon":[1,26]}。請依 [pointwise_witnesses, N, uniform_on_this_finite_domain, boundary] 欄序回答。

查看答案與解釋([[0, 441], [1, 467]], 467, 是, finite_maximum_only_not_infinite_domain_implication)

Wave5第四層核對=([[0, 441], [1, 467]], 467, 是, finite_maximum_only_not_infinite_domain_implication)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0067/)

函數列一致收斂 · qf-mod35-uniform-pointwise-max · candidate





## 68. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-pointwise-max；資料={"limit":[17,18],"coefficients":[18,-19],"shift":2,"epsilon":[1,27]}。請依 [pointwise_witnesses, N, uniform_on_this_finite_domain, boundary] 欄序回答。

查看答案與解釋([[0, 485], [1, 512]], 512, 是, finite_maximum_only_not_infinite_domain_implication)

Wave5第四層核對=([[0, 485], [1, 512]], 512, 是, finite_maximum_only_not_infinite_domain_implication)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0068/)

函數列一致收斂 · qf-mod35-uniform-pointwise-max · candidate





## 69. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-pointwise-max；資料={"limit":[18,19],"coefficients":[19,-20],"shift":2,"epsilon":[1,28]}。請依 [pointwise_witnesses, N, uniform_on_this_finite_domain, boundary] 欄序回答。

查看答案與解釋([[0, 531], [1, 559]], 559, 是, finite_maximum_only_not_infinite_domain_implication)

Wave5第四層核對=([[0, 531], [1, 559]], 559, 是, finite_maximum_only_not_infinite_domain_implication)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0069/)

函數列一致收斂 · qf-mod35-uniform-pointwise-max · candidate





## 70. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-pointwise-max；資料={"limit":[19,20],"coefficients":[20,-21],"shift":2,"epsilon":[1,29]}。請依 [pointwise_witnesses, N, uniform_on_this_finite_domain, boundary] 欄序回答。

查看答案與解釋([[0, 579], [1, 608]], 608, 是, finite_maximum_only_not_infinite_domain_implication)

Wave5第四層核對=([[0, 579], [1, 608]], 608, 是, finite_maximum_only_not_infinite_domain_implication)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0070/)

函數列一致收斂 · qf-mod35-uniform-pointwise-max · candidate





## 71. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-pointwise-max；資料={"limit":[20,21],"coefficients":[21,-22],"shift":2,"epsilon":[1,30]}。請依 [pointwise_witnesses, N, uniform_on_this_finite_domain, boundary] 欄序回答。

查看答案與解釋([[0, 629], [1, 659]], 659, 是, finite_maximum_only_not_infinite_domain_implication)

Wave5第四層核對=([[0, 629], [1, 659]], 659, 是, finite_maximum_only_not_infinite_domain_implication)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0071/)

函數列一致收斂 · qf-mod35-uniform-pointwise-max · candidate





## 72. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-pointwise-max；資料={"limit":[21,22],"coefficients":[22,-23],"shift":2,"epsilon":[1,31]}。請依 [pointwise_witnesses, N, uniform_on_this_finite_domain, boundary] 欄序回答。

查看答案與解釋([[0, 681], [1, 712]], 712, 是, finite_maximum_only_not_infinite_domain_implication)

Wave5第四層核對=([[0, 681], [1, 712]], 712, 是, finite_maximum_only_not_infinite_domain_implication)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0072/)

函數列一致收斂 · qf-mod35-uniform-pointwise-max · candidate





## 73. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-pointwise-max；資料={"limit":[22,23],"coefficients":[23,-24],"shift":2,"epsilon":[1,32]}。請依 [pointwise_witnesses, N, uniform_on_this_finite_domain, boundary] 欄序回答。

查看答案與解釋([[0, 735], [1, 767]], 767, 是, finite_maximum_only_not_infinite_domain_implication)

Wave5第四層核對=([[0, 735], [1, 767]], 767, 是, finite_maximum_only_not_infinite_domain_implication)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0073/)

函數列一致收斂 · qf-mod35-uniform-pointwise-max · candidate





## 74. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-pointwise-max；資料={"limit":[23,24],"coefficients":[24,-25],"shift":2,"epsilon":[1,33]}。請依 [pointwise_witnesses, N, uniform_on_this_finite_domain, boundary] 欄序回答。

查看答案與解釋([[0, 791], [1, 824]], 824, 是, finite_maximum_only_not_infinite_domain_implication)

Wave5第四層核對=([[0, 791], [1, 824]], 824, 是, finite_maximum_only_not_infinite_domain_implication)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0074/)

函數列一致收斂 · qf-mod35-uniform-pointwise-max · candidate





## 75. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-pointwise-max；資料={"limit":[24,25],"coefficients":[25,-26],"shift":2,"epsilon":[1,34]}。請依 [pointwise_witnesses, N, uniform_on_this_finite_domain, boundary] 欄序回答。

查看答案與解釋([[0, 849], [1, 883]], 883, 是, finite_maximum_only_not_infinite_domain_implication)

Wave5第四層核對=([[0, 849], [1, 883]], 883, 是, finite_maximum_only_not_infinite_domain_implication)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0075/)

函數列一致收斂 · qf-mod35-uniform-pointwise-max · candidate





## 76. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-prefix-boundary；資料={"limit":[0,1],"coefficients":[1,-2],"shift":2,"prefix_length":1}。請依 [prefix_length, sufficient, boundary] 欄序回答。

查看答案與解釋(1, 否, finite_prefix_not_uniform_convergence_certificate)

Wave5第四層核對=(1, 否, finite_prefix_not_uniform_convergence_certificate)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0076/)

函數列一致收斂 · qf-mod35-uniform-finite-prefix-boundary · candidate





## 77. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-prefix-boundary；資料={"limit":[1,2],"coefficients":[2,-3],"shift":2,"prefix_length":2}。請依 [prefix_length, sufficient, boundary] 欄序回答。

查看答案與解釋(2, 否, finite_prefix_not_uniform_convergence_certificate)

Wave5第四層核對=(2, 否, finite_prefix_not_uniform_convergence_certificate)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0077/)

函數列一致收斂 · qf-mod35-uniform-finite-prefix-boundary · candidate





## 78. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-prefix-boundary；資料={"limit":[2,3],"coefficients":[3,-4],"shift":2,"prefix_length":3}。請依 [prefix_length, sufficient, boundary] 欄序回答。

查看答案與解釋(3, 否, finite_prefix_not_uniform_convergence_certificate)

Wave5第四層核對=(3, 否, finite_prefix_not_uniform_convergence_certificate)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0078/)

函數列一致收斂 · qf-mod35-uniform-finite-prefix-boundary · candidate





## 79. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-prefix-boundary；資料={"limit":[3,4],"coefficients":[4,-5],"shift":2,"prefix_length":4}。請依 [prefix_length, sufficient, boundary] 欄序回答。

查看答案與解釋(4, 否, finite_prefix_not_uniform_convergence_certificate)

Wave5第四層核對=(4, 否, finite_prefix_not_uniform_convergence_certificate)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0079/)

函數列一致收斂 · qf-mod35-uniform-finite-prefix-boundary · candidate





## 80. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-prefix-boundary；資料={"limit":[4,5],"coefficients":[5,-6],"shift":2,"prefix_length":5}。請依 [prefix_length, sufficient, boundary] 欄序回答。

查看答案與解釋(5, 否, finite_prefix_not_uniform_convergence_certificate)

Wave5第四層核對=(5, 否, finite_prefix_not_uniform_convergence_certificate)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0080/)

函數列一致收斂 · qf-mod35-uniform-finite-prefix-boundary · candidate





## 81. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-prefix-boundary；資料={"limit":[5,6],"coefficients":[6,-7],"shift":2,"prefix_length":6}。請依 [prefix_length, sufficient, boundary] 欄序回答。

查看答案與解釋(6, 否, finite_prefix_not_uniform_convergence_certificate)

Wave5第四層核對=(6, 否, finite_prefix_not_uniform_convergence_certificate)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0081/)

函數列一致收斂 · qf-mod35-uniform-finite-prefix-boundary · candidate





## 82. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-prefix-boundary；資料={"limit":[6,7],"coefficients":[7,-8],"shift":2,"prefix_length":7}。請依 [prefix_length, sufficient, boundary] 欄序回答。

查看答案與解釋(7, 否, finite_prefix_not_uniform_convergence_certificate)

Wave5第四層核對=(7, 否, finite_prefix_not_uniform_convergence_certificate)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0082/)

函數列一致收斂 · qf-mod35-uniform-finite-prefix-boundary · candidate





## 83. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-prefix-boundary；資料={"limit":[7,8],"coefficients":[8,-9],"shift":2,"prefix_length":8}。請依 [prefix_length, sufficient, boundary] 欄序回答。

查看答案與解釋(8, 否, finite_prefix_not_uniform_convergence_certificate)

Wave5第四層核對=(8, 否, finite_prefix_not_uniform_convergence_certificate)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0083/)

函數列一致收斂 · qf-mod35-uniform-finite-prefix-boundary · candidate





## 84. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-prefix-boundary；資料={"limit":[8,9],"coefficients":[9,-10],"shift":2,"prefix_length":9}。請依 [prefix_length, sufficient, boundary] 欄序回答。

查看答案與解釋(9, 否, finite_prefix_not_uniform_convergence_certificate)

Wave5第四層核對=(9, 否, finite_prefix_not_uniform_convergence_certificate)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0084/)

函數列一致收斂 · qf-mod35-uniform-finite-prefix-boundary · candidate





## 85. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-prefix-boundary；資料={"limit":[9,10],"coefficients":[10,-11],"shift":2,"prefix_length":10}。請依 [prefix_length, sufficient, boundary] 欄序回答。

查看答案與解釋(10, 否, finite_prefix_not_uniform_convergence_certificate)

Wave5第四層核對=(10, 否, finite_prefix_not_uniform_convergence_certificate)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0085/)

函數列一致收斂 · qf-mod35-uniform-finite-prefix-boundary · candidate





## 86. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-prefix-boundary；資料={"limit":[10,11],"coefficients":[11,-12],"shift":2,"prefix_length":11}。請依 [prefix_length, sufficient, boundary] 欄序回答。

查看答案與解釋(11, 否, finite_prefix_not_uniform_convergence_certificate)

Wave5第四層核對=(11, 否, finite_prefix_not_uniform_convergence_certificate)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0086/)

函數列一致收斂 · qf-mod35-uniform-finite-prefix-boundary · candidate





## 87. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-prefix-boundary；資料={"limit":[11,12],"coefficients":[12,-13],"shift":2,"prefix_length":12}。請依 [prefix_length, sufficient, boundary] 欄序回答。

查看答案與解釋(12, 否, finite_prefix_not_uniform_convergence_certificate)

Wave5第四層核對=(12, 否, finite_prefix_not_uniform_convergence_certificate)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0087/)

函數列一致收斂 · qf-mod35-uniform-finite-prefix-boundary · candidate





## 88. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-prefix-boundary；資料={"limit":[12,13],"coefficients":[13,-14],"shift":2,"prefix_length":13}。請依 [prefix_length, sufficient, boundary] 欄序回答。

查看答案與解釋(13, 否, finite_prefix_not_uniform_convergence_certificate)

Wave5第四層核對=(13, 否, finite_prefix_not_uniform_convergence_certificate)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0088/)

函數列一致收斂 · qf-mod35-uniform-finite-prefix-boundary · candidate





## 89. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-prefix-boundary；資料={"limit":[13,14],"coefficients":[14,-15],"shift":2,"prefix_length":14}。請依 [prefix_length, sufficient, boundary] 欄序回答。

查看答案與解釋(14, 否, finite_prefix_not_uniform_convergence_certificate)

Wave5第四層核對=(14, 否, finite_prefix_not_uniform_convergence_certificate)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0089/)

函數列一致收斂 · qf-mod35-uniform-finite-prefix-boundary · candidate





## 90. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-prefix-boundary；資料={"limit":[14,15],"coefficients":[15,-16],"shift":2,"prefix_length":15}。請依 [prefix_length, sufficient, boundary] 欄序回答。

查看答案與解釋(15, 否, finite_prefix_not_uniform_convergence_certificate)

Wave5第四層核對=(15, 否, finite_prefix_not_uniform_convergence_certificate)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0090/)

函數列一致收斂 · qf-mod35-uniform-finite-prefix-boundary · candidate





## 91. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-prefix-boundary；資料={"limit":[15,16],"coefficients":[16,-17],"shift":2,"prefix_length":16}。請依 [prefix_length, sufficient, boundary] 欄序回答。

查看答案與解釋(16, 否, finite_prefix_not_uniform_convergence_certificate)

Wave5第四層核對=(16, 否, finite_prefix_not_uniform_convergence_certificate)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0091/)

函數列一致收斂 · qf-mod35-uniform-finite-prefix-boundary · candidate





## 92. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-prefix-boundary；資料={"limit":[16,17],"coefficients":[17,-18],"shift":2,"prefix_length":17}。請依 [prefix_length, sufficient, boundary] 欄序回答。

查看答案與解釋(17, 否, finite_prefix_not_uniform_convergence_certificate)

Wave5第四層核對=(17, 否, finite_prefix_not_uniform_convergence_certificate)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0092/)

函數列一致收斂 · qf-mod35-uniform-finite-prefix-boundary · candidate





## 93. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-prefix-boundary；資料={"limit":[17,18],"coefficients":[18,-19],"shift":2,"prefix_length":18}。請依 [prefix_length, sufficient, boundary] 欄序回答。

查看答案與解釋(18, 否, finite_prefix_not_uniform_convergence_certificate)

Wave5第四層核對=(18, 否, finite_prefix_not_uniform_convergence_certificate)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0093/)

函數列一致收斂 · qf-mod35-uniform-finite-prefix-boundary · candidate





## 94. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-prefix-boundary；資料={"limit":[18,19],"coefficients":[19,-20],"shift":2,"prefix_length":19}。請依 [prefix_length, sufficient, boundary] 欄序回答。

查看答案與解釋(19, 否, finite_prefix_not_uniform_convergence_certificate)

Wave5第四層核對=(19, 否, finite_prefix_not_uniform_convergence_certificate)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0094/)

函數列一致收斂 · qf-mod35-uniform-finite-prefix-boundary · candidate





## 95. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-prefix-boundary；資料={"limit":[19,20],"coefficients":[20,-21],"shift":2,"prefix_length":20}。請依 [prefix_length, sufficient, boundary] 欄序回答。

查看答案與解釋(20, 否, finite_prefix_not_uniform_convergence_certificate)

Wave5第四層核對=(20, 否, finite_prefix_not_uniform_convergence_certificate)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0095/)

函數列一致收斂 · qf-mod35-uniform-finite-prefix-boundary · candidate





## 96. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-prefix-boundary；資料={"limit":[20,21],"coefficients":[21,-22],"shift":2,"prefix_length":21}。請依 [prefix_length, sufficient, boundary] 欄序回答。

查看答案與解釋(21, 否, finite_prefix_not_uniform_convergence_certificate)

Wave5第四層核對=(21, 否, finite_prefix_not_uniform_convergence_certificate)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0096/)

函數列一致收斂 · qf-mod35-uniform-finite-prefix-boundary · candidate





## 97. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-prefix-boundary；資料={"limit":[21,22],"coefficients":[22,-23],"shift":2,"prefix_length":22}。請依 [prefix_length, sufficient, boundary] 欄序回答。

查看答案與解釋(22, 否, finite_prefix_not_uniform_convergence_certificate)

Wave5第四層核對=(22, 否, finite_prefix_not_uniform_convergence_certificate)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0097/)

函數列一致收斂 · qf-mod35-uniform-finite-prefix-boundary · candidate





## 98. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-prefix-boundary；資料={"limit":[22,23],"coefficients":[23,-24],"shift":2,"prefix_length":23}。請依 [prefix_length, sufficient, boundary] 欄序回答。

查看答案與解釋(23, 否, finite_prefix_not_uniform_convergence_certificate)

Wave5第四層核對=(23, 否, finite_prefix_not_uniform_convergence_certificate)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0098/)

函數列一致收斂 · qf-mod35-uniform-finite-prefix-boundary · candidate





## 99. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-prefix-boundary；資料={"limit":[23,24],"coefficients":[24,-25],"shift":2,"prefix_length":24}。請依 [prefix_length, sufficient, boundary] 欄序回答。

查看答案與解釋(24, 否, finite_prefix_not_uniform_convergence_certificate)

Wave5第四層核對=(24, 否, finite_prefix_not_uniform_convergence_certificate)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0099/)

函數列一致收斂 · qf-mod35-uniform-finite-prefix-boundary · candidate





## 100. 一致收斂

共同有限domain的symbolic tail與同一N(epsilon)。操作=uniform-finite-prefix-boundary；資料={"limit":[24,25],"coefficients":[25,-26],"shift":2,"prefix_length":25}。請依 [prefix_length, sufficient, boundary] 欄序回答。

查看答案與解釋(25, 否, finite_prefix_not_uniform_convergence_certificate)

Wave5第四層核對=(25, 否, finite_prefix_not_uniform_convergence_certificate)；依完整明示資料重算；同一N控制所有x且有限domain可取pointwise witnesses最大值；不可外推無限domain且finite prefix不足。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261104-r02-uniform-convergence-of-functions-0100/)

函數列一致收斂 · qf-mod35-uniform-finite-prefix-boundary · candidate



[原始題目 JSONL](https://ocme.evemisslab.com/data/questions/batches/batch-20261014-advance-20261104-r02-uniform-convergence-of-functions-foundations/questions.jsonl) · [驗收報告](https://ocme.evemisslab.com/data/questions/batches/batch-20261014-advance-20261104-r02-uniform-convergence-of-functions-foundations/validation-report.json)