# 子數列基礎 · 脈衝 R07

本批已通過 Schema、去重、來源快照與獨立答案重算；仍未標記為人工審定。

本題庫已有對應的中英逐步詳解。原題的 candidate 與英文 ai_candidate 狀態保留；AI 覆核、有限計算與 Lean 形式證明分開標示。

batch-20261014-advance-20261107-r07-subsequence-foundations · 2026-10-14 · 100 題

欄序為來源綁定的呈現補充；原始 JSONL 與數學答案不變。

[欄序與來源綁定資料](https://ocme.evemisslab.com/data/i18n/question-output-protocols.json)



## 1. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-index-certificate；資料={"index_start":0,"index_step":1}。請依 [index_start, index_step, index_formula, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(0, 1, k(j)=0+1j, 是, strictly_increasing_for_all_natural_j)

Wave6根層核對=(0, 1, k(j)=0+1j, 是, strictly_increasing_for_all_natural_j)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0001/)

子數列 · qf-mod38-subseq-index-certificate · candidate





## 2. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-index-certificate；資料={"index_start":1,"index_step":2}。請依 [index_start, index_step, index_formula, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(1, 2, k(j)=1+2j, 是, strictly_increasing_for_all_natural_j)

Wave6根層核對=(1, 2, k(j)=1+2j, 是, strictly_increasing_for_all_natural_j)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0002/)

子數列 · qf-mod38-subseq-index-certificate · candidate





## 3. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-index-certificate；資料={"index_start":2,"index_step":3}。請依 [index_start, index_step, index_formula, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(2, 3, k(j)=2+3j, 是, strictly_increasing_for_all_natural_j)

Wave6根層核對=(2, 3, k(j)=2+3j, 是, strictly_increasing_for_all_natural_j)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0003/)

子數列 · qf-mod38-subseq-index-certificate · candidate





## 4. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-index-certificate；資料={"index_start":3,"index_step":4}。請依 [index_start, index_step, index_formula, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(3, 4, k(j)=3+4j, 是, strictly_increasing_for_all_natural_j)

Wave6根層核對=(3, 4, k(j)=3+4j, 是, strictly_increasing_for_all_natural_j)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0004/)

子數列 · qf-mod38-subseq-index-certificate · candidate





## 5. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-index-certificate；資料={"index_start":4,"index_step":5}。請依 [index_start, index_step, index_formula, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(4, 5, k(j)=4+5j, 是, strictly_increasing_for_all_natural_j)

Wave6根層核對=(4, 5, k(j)=4+5j, 是, strictly_increasing_for_all_natural_j)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0005/)

子數列 · qf-mod38-subseq-index-certificate · candidate





## 6. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-index-certificate；資料={"index_start":5,"index_step":1}。請依 [index_start, index_step, index_formula, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(5, 1, k(j)=5+1j, 是, strictly_increasing_for_all_natural_j)

Wave6根層核對=(5, 1, k(j)=5+1j, 是, strictly_increasing_for_all_natural_j)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0006/)

子數列 · qf-mod38-subseq-index-certificate · candidate





## 7. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-index-certificate；資料={"index_start":6,"index_step":2}。請依 [index_start, index_step, index_formula, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(6, 2, k(j)=6+2j, 是, strictly_increasing_for_all_natural_j)

Wave6根層核對=(6, 2, k(j)=6+2j, 是, strictly_increasing_for_all_natural_j)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0007/)

子數列 · qf-mod38-subseq-index-certificate · candidate





## 8. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-index-certificate；資料={"index_start":7,"index_step":3}。請依 [index_start, index_step, index_formula, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(7, 3, k(j)=7+3j, 是, strictly_increasing_for_all_natural_j)

Wave6根層核對=(7, 3, k(j)=7+3j, 是, strictly_increasing_for_all_natural_j)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0008/)

子數列 · qf-mod38-subseq-index-certificate · candidate





## 9. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-index-certificate；資料={"index_start":8,"index_step":4}。請依 [index_start, index_step, index_formula, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(8, 4, k(j)=8+4j, 是, strictly_increasing_for_all_natural_j)

Wave6根層核對=(8, 4, k(j)=8+4j, 是, strictly_increasing_for_all_natural_j)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0009/)

子數列 · qf-mod38-subseq-index-certificate · candidate





## 10. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-index-certificate；資料={"index_start":9,"index_step":5}。請依 [index_start, index_step, index_formula, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(9, 5, k(j)=9+5j, 是, strictly_increasing_for_all_natural_j)

Wave6根層核對=(9, 5, k(j)=9+5j, 是, strictly_increasing_for_all_natural_j)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0010/)

子數列 · qf-mod38-subseq-index-certificate · candidate





## 11. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-index-certificate；資料={"index_start":10,"index_step":1}。請依 [index_start, index_step, index_formula, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(10, 1, k(j)=10+1j, 是, strictly_increasing_for_all_natural_j)

Wave6根層核對=(10, 1, k(j)=10+1j, 是, strictly_increasing_for_all_natural_j)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0011/)

子數列 · qf-mod38-subseq-index-certificate · candidate





## 12. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-index-certificate；資料={"index_start":11,"index_step":2}。請依 [index_start, index_step, index_formula, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(11, 2, k(j)=11+2j, 是, strictly_increasing_for_all_natural_j)

Wave6根層核對=(11, 2, k(j)=11+2j, 是, strictly_increasing_for_all_natural_j)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0012/)

子數列 · qf-mod38-subseq-index-certificate · candidate





## 13. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-index-certificate；資料={"index_start":12,"index_step":3}。請依 [index_start, index_step, index_formula, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(12, 3, k(j)=12+3j, 是, strictly_increasing_for_all_natural_j)

Wave6根層核對=(12, 3, k(j)=12+3j, 是, strictly_increasing_for_all_natural_j)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0013/)

子數列 · qf-mod38-subseq-index-certificate · candidate





## 14. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-index-certificate；資料={"index_start":13,"index_step":4}。請依 [index_start, index_step, index_formula, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(13, 4, k(j)=13+4j, 是, strictly_increasing_for_all_natural_j)

Wave6根層核對=(13, 4, k(j)=13+4j, 是, strictly_increasing_for_all_natural_j)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0014/)

子數列 · qf-mod38-subseq-index-certificate · candidate





## 15. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-index-certificate；資料={"index_start":14,"index_step":5}。請依 [index_start, index_step, index_formula, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(14, 5, k(j)=14+5j, 是, strictly_increasing_for_all_natural_j)

Wave6根層核對=(14, 5, k(j)=14+5j, 是, strictly_increasing_for_all_natural_j)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0015/)

子數列 · qf-mod38-subseq-index-certificate · candidate





## 16. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-index-certificate；資料={"index_start":15,"index_step":1}。請依 [index_start, index_step, index_formula, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(15, 1, k(j)=15+1j, 是, strictly_increasing_for_all_natural_j)

Wave6根層核對=(15, 1, k(j)=15+1j, 是, strictly_increasing_for_all_natural_j)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0016/)

子數列 · qf-mod38-subseq-index-certificate · candidate





## 17. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-index-certificate；資料={"index_start":16,"index_step":2}。請依 [index_start, index_step, index_formula, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(16, 2, k(j)=16+2j, 是, strictly_increasing_for_all_natural_j)

Wave6根層核對=(16, 2, k(j)=16+2j, 是, strictly_increasing_for_all_natural_j)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0017/)

子數列 · qf-mod38-subseq-index-certificate · candidate





## 18. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-index-certificate；資料={"index_start":17,"index_step":3}。請依 [index_start, index_step, index_formula, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(17, 3, k(j)=17+3j, 是, strictly_increasing_for_all_natural_j)

Wave6根層核對=(17, 3, k(j)=17+3j, 是, strictly_increasing_for_all_natural_j)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0018/)

子數列 · qf-mod38-subseq-index-certificate · candidate





## 19. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-index-certificate；資料={"index_start":18,"index_step":4}。請依 [index_start, index_step, index_formula, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(18, 4, k(j)=18+4j, 是, strictly_increasing_for_all_natural_j)

Wave6根層核對=(18, 4, k(j)=18+4j, 是, strictly_increasing_for_all_natural_j)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0019/)

子數列 · qf-mod38-subseq-index-certificate · candidate





## 20. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-index-certificate；資料={"index_start":19,"index_step":5}。請依 [index_start, index_step, index_formula, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(19, 5, k(j)=19+5j, 是, strictly_increasing_for_all_natural_j)

Wave6根層核對=(19, 5, k(j)=19+5j, 是, strictly_increasing_for_all_natural_j)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0020/)

子數列 · qf-mod38-subseq-index-certificate · candidate





## 21. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-index-certificate；資料={"index_start":20,"index_step":1}。請依 [index_start, index_step, index_formula, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(20, 1, k(j)=20+1j, 是, strictly_increasing_for_all_natural_j)

Wave6根層核對=(20, 1, k(j)=20+1j, 是, strictly_increasing_for_all_natural_j)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0021/)

子數列 · qf-mod38-subseq-index-certificate · candidate





## 22. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-index-certificate；資料={"index_start":21,"index_step":2}。請依 [index_start, index_step, index_formula, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(21, 2, k(j)=21+2j, 是, strictly_increasing_for_all_natural_j)

Wave6根層核對=(21, 2, k(j)=21+2j, 是, strictly_increasing_for_all_natural_j)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0022/)

子數列 · qf-mod38-subseq-index-certificate · candidate





## 23. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-index-certificate；資料={"index_start":22,"index_step":3}。請依 [index_start, index_step, index_formula, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(22, 3, k(j)=22+3j, 是, strictly_increasing_for_all_natural_j)

Wave6根層核對=(22, 3, k(j)=22+3j, 是, strictly_increasing_for_all_natural_j)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0023/)

子數列 · qf-mod38-subseq-index-certificate · candidate





## 24. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-index-certificate；資料={"index_start":23,"index_step":4}。請依 [index_start, index_step, index_formula, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(23, 4, k(j)=23+4j, 是, strictly_increasing_for_all_natural_j)

Wave6根層核對=(23, 4, k(j)=23+4j, 是, strictly_increasing_for_all_natural_j)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0024/)

子數列 · qf-mod38-subseq-index-certificate · candidate





## 25. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-index-certificate；資料={"index_start":24,"index_step":5}。請依 [index_start, index_step, index_formula, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(24, 5, k(j)=24+5j, 是, strictly_increasing_for_all_natural_j)

Wave6根層核對=(24, 5, k(j)=24+5j, 是, strictly_increasing_for_all_natural_j)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0025/)

子數列 · qf-mod38-subseq-index-certificate · candidate





## 26. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-arithmetic-term；資料={"source_start":1,"source_step":1,"index_start":0,"index_step":1,"j":2}。請依 [j, source_index, subsequence_term, certificate] 欄序回答。

查看答案與解釋(2, 2, 3, a_of_k_j_preserves_original_order)

Wave6根層核對=(2, 2, 3, a_of_k_j_preserves_original_order)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0026/)

子數列 · qf-mod38-subseq-arithmetic-term · candidate





## 27. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-arithmetic-term；資料={"source_start":2,"source_step":2,"index_start":1,"index_step":2,"j":3}。請依 [j, source_index, subsequence_term, certificate] 欄序回答。

查看答案與解釋(3, 7, 16, a_of_k_j_preserves_original_order)

Wave6根層核對=(3, 7, 16, a_of_k_j_preserves_original_order)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0027/)

子數列 · qf-mod38-subseq-arithmetic-term · candidate





## 28. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-arithmetic-term；資料={"source_start":3,"source_step":3,"index_start":2,"index_step":3,"j":4}。請依 [j, source_index, subsequence_term, certificate] 欄序回答。

查看答案與解釋(4, 14, 45, a_of_k_j_preserves_original_order)

Wave6根層核對=(4, 14, 45, a_of_k_j_preserves_original_order)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0028/)

子數列 · qf-mod38-subseq-arithmetic-term · candidate





## 29. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-arithmetic-term；資料={"source_start":4,"source_step":4,"index_start":3,"index_step":4,"j":5}。請依 [j, source_index, subsequence_term, certificate] 欄序回答。

查看答案與解釋(5, 23, 96, a_of_k_j_preserves_original_order)

Wave6根層核對=(5, 23, 96, a_of_k_j_preserves_original_order)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0029/)

子數列 · qf-mod38-subseq-arithmetic-term · candidate





## 30. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-arithmetic-term；資料={"source_start":5,"source_step":5,"index_start":0,"index_step":5,"j":6}。請依 [j, source_index, subsequence_term, certificate] 欄序回答。

查看答案與解釋(6, 30, 155, a_of_k_j_preserves_original_order)

Wave6根層核對=(6, 30, 155, a_of_k_j_preserves_original_order)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0030/)

子數列 · qf-mod38-subseq-arithmetic-term · candidate





## 31. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-arithmetic-term；資料={"source_start":6,"source_step":6,"index_start":1,"index_step":1,"j":7}。請依 [j, source_index, subsequence_term, certificate] 欄序回答。

查看答案與解釋(7, 8, 54, a_of_k_j_preserves_original_order)

Wave6根層核對=(7, 8, 54, a_of_k_j_preserves_original_order)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0031/)

子數列 · qf-mod38-subseq-arithmetic-term · candidate





## 32. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-arithmetic-term；資料={"source_start":7,"source_step":7,"index_start":2,"index_step":2,"j":8}。請依 [j, source_index, subsequence_term, certificate] 欄序回答。

查看答案與解釋(8, 18, 133, a_of_k_j_preserves_original_order)

Wave6根層核對=(8, 18, 133, a_of_k_j_preserves_original_order)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0032/)

子數列 · qf-mod38-subseq-arithmetic-term · candidate





## 33. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-arithmetic-term；資料={"source_start":8,"source_step":1,"index_start":3,"index_step":3,"j":9}。請依 [j, source_index, subsequence_term, certificate] 欄序回答。

查看答案與解釋(9, 30, 38, a_of_k_j_preserves_original_order)

Wave6根層核對=(9, 30, 38, a_of_k_j_preserves_original_order)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0033/)

子數列 · qf-mod38-subseq-arithmetic-term · candidate





## 34. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-arithmetic-term；資料={"source_start":9,"source_step":2,"index_start":0,"index_step":4,"j":10}。請依 [j, source_index, subsequence_term, certificate] 欄序回答。

查看答案與解釋(10, 40, 89, a_of_k_j_preserves_original_order)

Wave6根層核對=(10, 40, 89, a_of_k_j_preserves_original_order)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0034/)

子數列 · qf-mod38-subseq-arithmetic-term · candidate





## 35. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-arithmetic-term；資料={"source_start":10,"source_step":3,"index_start":1,"index_step":5,"j":11}。請依 [j, source_index, subsequence_term, certificate] 欄序回答。

查看答案與解釋(11, 56, 178, a_of_k_j_preserves_original_order)

Wave6根層核對=(11, 56, 178, a_of_k_j_preserves_original_order)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0035/)

子數列 · qf-mod38-subseq-arithmetic-term · candidate





## 36. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-arithmetic-term；資料={"source_start":11,"source_step":4,"index_start":2,"index_step":1,"j":12}。請依 [j, source_index, subsequence_term, certificate] 欄序回答。

查看答案與解釋(12, 14, 67, a_of_k_j_preserves_original_order)

Wave6根層核對=(12, 14, 67, a_of_k_j_preserves_original_order)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0036/)

子數列 · qf-mod38-subseq-arithmetic-term · candidate





## 37. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-arithmetic-term；資料={"source_start":12,"source_step":5,"index_start":3,"index_step":2,"j":13}。請依 [j, source_index, subsequence_term, certificate] 欄序回答。

查看答案與解釋(13, 29, 157, a_of_k_j_preserves_original_order)

Wave6根層核對=(13, 29, 157, a_of_k_j_preserves_original_order)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0037/)

子數列 · qf-mod38-subseq-arithmetic-term · candidate





## 38. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-arithmetic-term；資料={"source_start":13,"source_step":6,"index_start":0,"index_step":3,"j":14}。請依 [j, source_index, subsequence_term, certificate] 欄序回答。

查看答案與解釋(14, 42, 265, a_of_k_j_preserves_original_order)

Wave6根層核對=(14, 42, 265, a_of_k_j_preserves_original_order)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0038/)

子數列 · qf-mod38-subseq-arithmetic-term · candidate





## 39. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-arithmetic-term；資料={"source_start":14,"source_step":7,"index_start":1,"index_step":4,"j":15}。請依 [j, source_index, subsequence_term, certificate] 欄序回答。

查看答案與解釋(15, 61, 441, a_of_k_j_preserves_original_order)

Wave6根層核對=(15, 61, 441, a_of_k_j_preserves_original_order)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0039/)

子數列 · qf-mod38-subseq-arithmetic-term · candidate





## 40. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-arithmetic-term；資料={"source_start":15,"source_step":1,"index_start":2,"index_step":5,"j":16}。請依 [j, source_index, subsequence_term, certificate] 欄序回答。

查看答案與解釋(16, 82, 97, a_of_k_j_preserves_original_order)

Wave6根層核對=(16, 82, 97, a_of_k_j_preserves_original_order)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0040/)

子數列 · qf-mod38-subseq-arithmetic-term · candidate





## 41. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-arithmetic-term；資料={"source_start":16,"source_step":2,"index_start":3,"index_step":1,"j":17}。請依 [j, source_index, subsequence_term, certificate] 欄序回答。

查看答案與解釋(17, 20, 56, a_of_k_j_preserves_original_order)

Wave6根層核對=(17, 20, 56, a_of_k_j_preserves_original_order)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0041/)

子數列 · qf-mod38-subseq-arithmetic-term · candidate





## 42. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-arithmetic-term；資料={"source_start":17,"source_step":3,"index_start":0,"index_step":2,"j":18}。請依 [j, source_index, subsequence_term, certificate] 欄序回答。

查看答案與解釋(18, 36, 125, a_of_k_j_preserves_original_order)

Wave6根層核對=(18, 36, 125, a_of_k_j_preserves_original_order)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0042/)

子數列 · qf-mod38-subseq-arithmetic-term · candidate





## 43. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-arithmetic-term；資料={"source_start":18,"source_step":4,"index_start":1,"index_step":3,"j":19}。請依 [j, source_index, subsequence_term, certificate] 欄序回答。

查看答案與解釋(19, 58, 250, a_of_k_j_preserves_original_order)

Wave6根層核對=(19, 58, 250, a_of_k_j_preserves_original_order)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0043/)

子數列 · qf-mod38-subseq-arithmetic-term · candidate





## 44. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-arithmetic-term；資料={"source_start":19,"source_step":5,"index_start":2,"index_step":4,"j":20}。請依 [j, source_index, subsequence_term, certificate] 欄序回答。

查看答案與解釋(20, 82, 429, a_of_k_j_preserves_original_order)

Wave6根層核對=(20, 82, 429, a_of_k_j_preserves_original_order)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0044/)

子數列 · qf-mod38-subseq-arithmetic-term · candidate





## 45. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-arithmetic-term；資料={"source_start":20,"source_step":6,"index_start":3,"index_step":5,"j":21}。請依 [j, source_index, subsequence_term, certificate] 欄序回答。

查看答案與解釋(21, 108, 668, a_of_k_j_preserves_original_order)

Wave6根層核對=(21, 108, 668, a_of_k_j_preserves_original_order)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0045/)

子數列 · qf-mod38-subseq-arithmetic-term · candidate





## 46. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-arithmetic-term；資料={"source_start":21,"source_step":7,"index_start":0,"index_step":1,"j":22}。請依 [j, source_index, subsequence_term, certificate] 欄序回答。

查看答案與解釋(22, 22, 175, a_of_k_j_preserves_original_order)

Wave6根層核對=(22, 22, 175, a_of_k_j_preserves_original_order)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0046/)

子數列 · qf-mod38-subseq-arithmetic-term · candidate





## 47. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-arithmetic-term；資料={"source_start":22,"source_step":1,"index_start":1,"index_step":2,"j":23}。請依 [j, source_index, subsequence_term, certificate] 欄序回答。

查看答案與解釋(23, 47, 69, a_of_k_j_preserves_original_order)

Wave6根層核對=(23, 47, 69, a_of_k_j_preserves_original_order)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0047/)

子數列 · qf-mod38-subseq-arithmetic-term · candidate





## 48. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-arithmetic-term；資料={"source_start":23,"source_step":2,"index_start":2,"index_step":3,"j":24}。請依 [j, source_index, subsequence_term, certificate] 欄序回答。

查看答案與解釋(24, 74, 171, a_of_k_j_preserves_original_order)

Wave6根層核對=(24, 74, 171, a_of_k_j_preserves_original_order)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0048/)

子數列 · qf-mod38-subseq-arithmetic-term · candidate





## 49. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-arithmetic-term；資料={"source_start":24,"source_step":3,"index_start":3,"index_step":4,"j":25}。請依 [j, source_index, subsequence_term, certificate] 欄序回答。

查看答案與解釋(25, 103, 333, a_of_k_j_preserves_original_order)

Wave6根層核對=(25, 103, 333, a_of_k_j_preserves_original_order)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0049/)

子數列 · qf-mod38-subseq-arithmetic-term · candidate





## 50. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-arithmetic-term；資料={"source_start":25,"source_step":4,"index_start":0,"index_step":5,"j":26}。請依 [j, source_index, subsequence_term, certificate] 欄序回答。

查看答案與解釋(26, 130, 545, a_of_k_j_preserves_original_order)

Wave6根層核對=(26, 130, 545, a_of_k_j_preserves_original_order)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0050/)

子數列 · qf-mod38-subseq-arithmetic-term · candidate





## 51. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-composed-index；資料={"outer_start":0,"outer_step":1,"inner_start":0,"inner_step":1,"j":1}。請依 [j, inner_index, source_index, composed_step, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(1, 1, 1, 1, 是, composition_remains_strictly_increasing)

Wave6根層核對=(1, 1, 1, 1, 是, composition_remains_strictly_increasing)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0051/)

子數列 · qf-mod38-subseq-composed-index · candidate





## 52. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-composed-index；資料={"outer_start":1,"outer_step":2,"inner_start":1,"inner_step":2,"j":2}。請依 [j, inner_index, source_index, composed_step, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(2, 5, 11, 4, 是, composition_remains_strictly_increasing)

Wave6根層核對=(2, 5, 11, 4, 是, composition_remains_strictly_increasing)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0052/)

子數列 · qf-mod38-subseq-composed-index · candidate





## 53. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-composed-index；資料={"outer_start":2,"outer_step":3,"inner_start":2,"inner_step":3,"j":3}。請依 [j, inner_index, source_index, composed_step, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(3, 11, 35, 9, 是, composition_remains_strictly_increasing)

Wave6根層核對=(3, 11, 35, 9, 是, composition_remains_strictly_increasing)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0053/)

子數列 · qf-mod38-subseq-composed-index · candidate





## 54. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-composed-index；資料={"outer_start":0,"outer_step":4,"inner_start":3,"inner_step":4,"j":4}。請依 [j, inner_index, source_index, composed_step, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(4, 19, 76, 16, 是, composition_remains_strictly_increasing)

Wave6根層核對=(4, 19, 76, 16, 是, composition_remains_strictly_increasing)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0054/)

子數列 · qf-mod38-subseq-composed-index · candidate





## 55. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-composed-index；資料={"outer_start":1,"outer_step":5,"inner_start":0,"inner_step":5,"j":5}。請依 [j, inner_index, source_index, composed_step, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(5, 25, 126, 25, 是, composition_remains_strictly_increasing)

Wave6根層核對=(5, 25, 126, 25, 是, composition_remains_strictly_increasing)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0055/)

子數列 · qf-mod38-subseq-composed-index · candidate





## 56. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-composed-index；資料={"outer_start":2,"outer_step":1,"inner_start":1,"inner_step":6,"j":6}。請依 [j, inner_index, source_index, composed_step, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(6, 37, 39, 6, 是, composition_remains_strictly_increasing)

Wave6根層核對=(6, 37, 39, 6, 是, composition_remains_strictly_increasing)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0056/)

子數列 · qf-mod38-subseq-composed-index · candidate





## 57. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-composed-index；資料={"outer_start":0,"outer_step":2,"inner_start":2,"inner_step":1,"j":7}。請依 [j, inner_index, source_index, composed_step, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(7, 9, 18, 2, 是, composition_remains_strictly_increasing)

Wave6根層核對=(7, 9, 18, 2, 是, composition_remains_strictly_increasing)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0057/)

子數列 · qf-mod38-subseq-composed-index · candidate





## 58. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-composed-index；資料={"outer_start":1,"outer_step":3,"inner_start":3,"inner_step":2,"j":8}。請依 [j, inner_index, source_index, composed_step, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(8, 19, 58, 6, 是, composition_remains_strictly_increasing)

Wave6根層核對=(8, 19, 58, 6, 是, composition_remains_strictly_increasing)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0058/)

子數列 · qf-mod38-subseq-composed-index · candidate





## 59. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-composed-index；資料={"outer_start":2,"outer_step":4,"inner_start":0,"inner_step":3,"j":9}。請依 [j, inner_index, source_index, composed_step, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(9, 27, 110, 12, 是, composition_remains_strictly_increasing)

Wave6根層核對=(9, 27, 110, 12, 是, composition_remains_strictly_increasing)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0059/)

子數列 · qf-mod38-subseq-composed-index · candidate





## 60. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-composed-index；資料={"outer_start":0,"outer_step":5,"inner_start":1,"inner_step":4,"j":10}。請依 [j, inner_index, source_index, composed_step, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(10, 41, 205, 20, 是, composition_remains_strictly_increasing)

Wave6根層核對=(10, 41, 205, 20, 是, composition_remains_strictly_increasing)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0060/)

子數列 · qf-mod38-subseq-composed-index · candidate





## 61. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-composed-index；資料={"outer_start":1,"outer_step":1,"inner_start":2,"inner_step":5,"j":11}。請依 [j, inner_index, source_index, composed_step, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(11, 57, 58, 5, 是, composition_remains_strictly_increasing)

Wave6根層核對=(11, 57, 58, 5, 是, composition_remains_strictly_increasing)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0061/)

子數列 · qf-mod38-subseq-composed-index · candidate





## 62. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-composed-index；資料={"outer_start":2,"outer_step":2,"inner_start":3,"inner_step":6,"j":12}。請依 [j, inner_index, source_index, composed_step, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(12, 75, 152, 12, 是, composition_remains_strictly_increasing)

Wave6根層核對=(12, 75, 152, 12, 是, composition_remains_strictly_increasing)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0062/)

子數列 · qf-mod38-subseq-composed-index · candidate





## 63. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-composed-index；資料={"outer_start":0,"outer_step":3,"inner_start":0,"inner_step":1,"j":13}。請依 [j, inner_index, source_index, composed_step, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(13, 13, 39, 3, 是, composition_remains_strictly_increasing)

Wave6根層核對=(13, 13, 39, 3, 是, composition_remains_strictly_increasing)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0063/)

子數列 · qf-mod38-subseq-composed-index · candidate





## 64. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-composed-index；資料={"outer_start":1,"outer_step":4,"inner_start":1,"inner_step":2,"j":14}。請依 [j, inner_index, source_index, composed_step, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(14, 29, 117, 8, 是, composition_remains_strictly_increasing)

Wave6根層核對=(14, 29, 117, 8, 是, composition_remains_strictly_increasing)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0064/)

子數列 · qf-mod38-subseq-composed-index · candidate





## 65. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-composed-index；資料={"outer_start":2,"outer_step":5,"inner_start":2,"inner_step":3,"j":15}。請依 [j, inner_index, source_index, composed_step, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(15, 47, 237, 15, 是, composition_remains_strictly_increasing)

Wave6根層核對=(15, 47, 237, 15, 是, composition_remains_strictly_increasing)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0065/)

子數列 · qf-mod38-subseq-composed-index · candidate





## 66. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-composed-index；資料={"outer_start":0,"outer_step":1,"inner_start":3,"inner_step":4,"j":16}。請依 [j, inner_index, source_index, composed_step, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(16, 67, 67, 4, 是, composition_remains_strictly_increasing)

Wave6根層核對=(16, 67, 67, 4, 是, composition_remains_strictly_increasing)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0066/)

子數列 · qf-mod38-subseq-composed-index · candidate





## 67. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-composed-index；資料={"outer_start":1,"outer_step":2,"inner_start":0,"inner_step":5,"j":17}。請依 [j, inner_index, source_index, composed_step, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(17, 85, 171, 10, 是, composition_remains_strictly_increasing)

Wave6根層核對=(17, 85, 171, 10, 是, composition_remains_strictly_increasing)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0067/)

子數列 · qf-mod38-subseq-composed-index · candidate





## 68. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-composed-index；資料={"outer_start":2,"outer_step":3,"inner_start":1,"inner_step":6,"j":18}。請依 [j, inner_index, source_index, composed_step, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(18, 109, 329, 18, 是, composition_remains_strictly_increasing)

Wave6根層核對=(18, 109, 329, 18, 是, composition_remains_strictly_increasing)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0068/)

子數列 · qf-mod38-subseq-composed-index · candidate





## 69. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-composed-index；資料={"outer_start":0,"outer_step":4,"inner_start":2,"inner_step":1,"j":19}。請依 [j, inner_index, source_index, composed_step, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(19, 21, 84, 4, 是, composition_remains_strictly_increasing)

Wave6根層核對=(19, 21, 84, 4, 是, composition_remains_strictly_increasing)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0069/)

子數列 · qf-mod38-subseq-composed-index · candidate





## 70. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-composed-index；資料={"outer_start":1,"outer_step":5,"inner_start":3,"inner_step":2,"j":20}。請依 [j, inner_index, source_index, composed_step, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(20, 43, 216, 10, 是, composition_remains_strictly_increasing)

Wave6根層核對=(20, 43, 216, 10, 是, composition_remains_strictly_increasing)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0070/)

子數列 · qf-mod38-subseq-composed-index · candidate





## 71. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-composed-index；資料={"outer_start":2,"outer_step":1,"inner_start":0,"inner_step":3,"j":21}。請依 [j, inner_index, source_index, composed_step, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(21, 63, 65, 3, 是, composition_remains_strictly_increasing)

Wave6根層核對=(21, 63, 65, 3, 是, composition_remains_strictly_increasing)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0071/)

子數列 · qf-mod38-subseq-composed-index · candidate





## 72. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-composed-index；資料={"outer_start":0,"outer_step":2,"inner_start":1,"inner_step":4,"j":22}。請依 [j, inner_index, source_index, composed_step, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(22, 89, 178, 8, 是, composition_remains_strictly_increasing)

Wave6根層核對=(22, 89, 178, 8, 是, composition_remains_strictly_increasing)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0072/)

子數列 · qf-mod38-subseq-composed-index · candidate





## 73. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-composed-index；資料={"outer_start":1,"outer_step":3,"inner_start":2,"inner_step":5,"j":23}。請依 [j, inner_index, source_index, composed_step, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(23, 117, 352, 15, 是, composition_remains_strictly_increasing)

Wave6根層核對=(23, 117, 352, 15, 是, composition_remains_strictly_increasing)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0073/)

子數列 · qf-mod38-subseq-composed-index · candidate





## 74. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-composed-index；資料={"outer_start":2,"outer_step":4,"inner_start":3,"inner_step":6,"j":24}。請依 [j, inner_index, source_index, composed_step, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(24, 147, 590, 24, 是, composition_remains_strictly_increasing)

Wave6根層核對=(24, 147, 590, 24, 是, composition_remains_strictly_increasing)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0074/)

子數列 · qf-mod38-subseq-composed-index · candidate





## 75. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-composed-index；資料={"outer_start":0,"outer_step":5,"inner_start":0,"inner_step":1,"j":25}。請依 [j, inner_index, source_index, composed_step, strictly_increasing, certificate] 欄序回答。

查看答案與解釋(25, 25, 125, 5, 是, composition_remains_strictly_increasing)

Wave6根層核對=(25, 25, 125, 5, 是, composition_remains_strictly_increasing)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0075/)

子數列 · qf-mod38-subseq-composed-index · candidate





## 76. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-finite-prefix-boundary；資料={"indices":[0,1,2,3]}。請依 [indices, finite_prefix_increasing, infinite_certificate_supplied, boundary] 欄序回答。

沒有提供無限索引證書，不等於不能把遞增有限prefix延伸為無限遞增索引。

查看答案與解釋([0, 1, 2, 3], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)

Wave6根層核對=([0, 1, 2, 3], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0076/)

子數列 · qf-mod38-subseq-finite-prefix-boundary · candidate





## 77. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-finite-prefix-boundary；資料={"indices":[1,3,5,7,9]}。請依 [indices, finite_prefix_increasing, infinite_certificate_supplied, boundary] 欄序回答。

沒有提供無限索引證書，不等於不能把遞增有限prefix延伸為無限遞增索引。

查看答案與解釋([1, 3, 5, 7, 9], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)

Wave6根層核對=([1, 3, 5, 7, 9], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0077/)

子數列 · qf-mod38-subseq-finite-prefix-boundary · candidate





## 78. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-finite-prefix-boundary；資料={"indices":[2,5,8,11,14,17]}。請依 [indices, finite_prefix_increasing, infinite_certificate_supplied, boundary] 欄序回答。

沒有提供無限索引證書，不等於不能把遞增有限prefix延伸為無限遞增索引。

查看答案與解釋([2, 5, 8, 11, 14, 17], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)

Wave6根層核對=([2, 5, 8, 11, 14, 17], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0078/)

子數列 · qf-mod38-subseq-finite-prefix-boundary · candidate





## 79. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-finite-prefix-boundary；資料={"indices":[3,7,11,15]}。請依 [indices, finite_prefix_increasing, infinite_certificate_supplied, boundary] 欄序回答。

沒有提供無限索引證書，不等於不能把遞增有限prefix延伸為無限遞增索引。

查看答案與解釋([3, 7, 11, 15], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)

Wave6根層核對=([3, 7, 11, 15], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0079/)

子數列 · qf-mod38-subseq-finite-prefix-boundary · candidate





## 80. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-finite-prefix-boundary；資料={"indices":[4,9,14,19,24]}。請依 [indices, finite_prefix_increasing, infinite_certificate_supplied, boundary] 欄序回答。

沒有提供無限索引證書，不等於不能把遞增有限prefix延伸為無限遞增索引。

查看答案與解釋([4, 9, 14, 19, 24], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)

Wave6根層核對=([4, 9, 14, 19, 24], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0080/)

子數列 · qf-mod38-subseq-finite-prefix-boundary · candidate





## 81. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-finite-prefix-boundary；資料={"indices":[5,6,7,8,9,10]}。請依 [indices, finite_prefix_increasing, infinite_certificate_supplied, boundary] 欄序回答。

沒有提供無限索引證書，不等於不能把遞增有限prefix延伸為無限遞增索引。

查看答案與解釋([5, 6, 7, 8, 9, 10], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)

Wave6根層核對=([5, 6, 7, 8, 9, 10], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0081/)

子數列 · qf-mod38-subseq-finite-prefix-boundary · candidate





## 82. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-finite-prefix-boundary；資料={"indices":[6,8,10,12]}。請依 [indices, finite_prefix_increasing, infinite_certificate_supplied, boundary] 欄序回答。

沒有提供無限索引證書，不等於不能把遞增有限prefix延伸為無限遞增索引。

查看答案與解釋([6, 8, 10, 12], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)

Wave6根層核對=([6, 8, 10, 12], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0082/)

子數列 · qf-mod38-subseq-finite-prefix-boundary · candidate





## 83. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-finite-prefix-boundary；資料={"indices":[7,10,13,16,19]}。請依 [indices, finite_prefix_increasing, infinite_certificate_supplied, boundary] 欄序回答。

沒有提供無限索引證書，不等於不能把遞增有限prefix延伸為無限遞增索引。

查看答案與解釋([7, 10, 13, 16, 19], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)

Wave6根層核對=([7, 10, 13, 16, 19], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0083/)

子數列 · qf-mod38-subseq-finite-prefix-boundary · candidate





## 84. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-finite-prefix-boundary；資料={"indices":[8,12,16,20,24,28]}。請依 [indices, finite_prefix_increasing, infinite_certificate_supplied, boundary] 欄序回答。

沒有提供無限索引證書，不等於不能把遞增有限prefix延伸為無限遞增索引。

查看答案與解釋([8, 12, 16, 20, 24, 28], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)

Wave6根層核對=([8, 12, 16, 20, 24, 28], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0084/)

子數列 · qf-mod38-subseq-finite-prefix-boundary · candidate





## 85. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-finite-prefix-boundary；資料={"indices":[9,14,19,24]}。請依 [indices, finite_prefix_increasing, infinite_certificate_supplied, boundary] 欄序回答。

沒有提供無限索引證書，不等於不能把遞增有限prefix延伸為無限遞增索引。

查看答案與解釋([9, 14, 19, 24], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)

Wave6根層核對=([9, 14, 19, 24], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0085/)

子數列 · qf-mod38-subseq-finite-prefix-boundary · candidate





## 86. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-finite-prefix-boundary；資料={"indices":[10,11,12,13,14]}。請依 [indices, finite_prefix_increasing, infinite_certificate_supplied, boundary] 欄序回答。

沒有提供無限索引證書，不等於不能把遞增有限prefix延伸為無限遞增索引。

查看答案與解釋([10, 11, 12, 13, 14], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)

Wave6根層核對=([10, 11, 12, 13, 14], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0086/)

子數列 · qf-mod38-subseq-finite-prefix-boundary · candidate





## 87. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-finite-prefix-boundary；資料={"indices":[11,13,15,17,19,21]}。請依 [indices, finite_prefix_increasing, infinite_certificate_supplied, boundary] 欄序回答。

沒有提供無限索引證書，不等於不能把遞增有限prefix延伸為無限遞增索引。

查看答案與解釋([11, 13, 15, 17, 19, 21], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)

Wave6根層核對=([11, 13, 15, 17, 19, 21], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0087/)

子數列 · qf-mod38-subseq-finite-prefix-boundary · candidate





## 88. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-finite-prefix-boundary；資料={"indices":[12,15,18,21]}。請依 [indices, finite_prefix_increasing, infinite_certificate_supplied, boundary] 欄序回答。

沒有提供無限索引證書，不等於不能把遞增有限prefix延伸為無限遞增索引。

查看答案與解釋([12, 15, 18, 21], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)

Wave6根層核對=([12, 15, 18, 21], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0088/)

子數列 · qf-mod38-subseq-finite-prefix-boundary · candidate





## 89. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-finite-prefix-boundary；資料={"indices":[13,17,21,25,29]}。請依 [indices, finite_prefix_increasing, infinite_certificate_supplied, boundary] 欄序回答。

沒有提供無限索引證書，不等於不能把遞增有限prefix延伸為無限遞增索引。

查看答案與解釋([13, 17, 21, 25, 29], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)

Wave6根層核對=([13, 17, 21, 25, 29], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0089/)

子數列 · qf-mod38-subseq-finite-prefix-boundary · candidate





## 90. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-finite-prefix-boundary；資料={"indices":[14,19,24,29,34,39]}。請依 [indices, finite_prefix_increasing, infinite_certificate_supplied, boundary] 欄序回答。

沒有提供無限索引證書，不等於不能把遞增有限prefix延伸為無限遞增索引。

查看答案與解釋([14, 19, 24, 29, 34, 39], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)

Wave6根層核對=([14, 19, 24, 29, 34, 39], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0090/)

子數列 · qf-mod38-subseq-finite-prefix-boundary · candidate





## 91. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-finite-prefix-boundary；資料={"indices":[15,16,17,18]}。請依 [indices, finite_prefix_increasing, infinite_certificate_supplied, boundary] 欄序回答。

沒有提供無限索引證書，不等於不能把遞增有限prefix延伸為無限遞增索引。

查看答案與解釋([15, 16, 17, 18], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)

Wave6根層核對=([15, 16, 17, 18], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0091/)

子數列 · qf-mod38-subseq-finite-prefix-boundary · candidate





## 92. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-finite-prefix-boundary；資料={"indices":[16,18,20,22,24]}。請依 [indices, finite_prefix_increasing, infinite_certificate_supplied, boundary] 欄序回答。

沒有提供無限索引證書，不等於不能把遞增有限prefix延伸為無限遞增索引。

查看答案與解釋([16, 18, 20, 22, 24], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)

Wave6根層核對=([16, 18, 20, 22, 24], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0092/)

子數列 · qf-mod38-subseq-finite-prefix-boundary · candidate





## 93. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-finite-prefix-boundary；資料={"indices":[17,20,23,26,29,32]}。請依 [indices, finite_prefix_increasing, infinite_certificate_supplied, boundary] 欄序回答。

沒有提供無限索引證書，不等於不能把遞增有限prefix延伸為無限遞增索引。

查看答案與解釋([17, 20, 23, 26, 29, 32], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)

Wave6根層核對=([17, 20, 23, 26, 29, 32], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0093/)

子數列 · qf-mod38-subseq-finite-prefix-boundary · candidate





## 94. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-finite-prefix-boundary；資料={"indices":[18,22,26,30]}。請依 [indices, finite_prefix_increasing, infinite_certificate_supplied, boundary] 欄序回答。

沒有提供無限索引證書，不等於不能把遞增有限prefix延伸為無限遞增索引。

查看答案與解釋([18, 22, 26, 30], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)

Wave6根層核對=([18, 22, 26, 30], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0094/)

子數列 · qf-mod38-subseq-finite-prefix-boundary · candidate





## 95. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-finite-prefix-boundary；資料={"indices":[19,24,29,34,39]}。請依 [indices, finite_prefix_increasing, infinite_certificate_supplied, boundary] 欄序回答。

沒有提供無限索引證書，不等於不能把遞增有限prefix延伸為無限遞增索引。

查看答案與解釋([19, 24, 29, 34, 39], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)

Wave6根層核對=([19, 24, 29, 34, 39], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0095/)

子數列 · qf-mod38-subseq-finite-prefix-boundary · candidate





## 96. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-finite-prefix-boundary；資料={"indices":[20,21,22,23,24,25]}。請依 [indices, finite_prefix_increasing, infinite_certificate_supplied, boundary] 欄序回答。

沒有提供無限索引證書，不等於不能把遞增有限prefix延伸為無限遞增索引。

查看答案與解釋([20, 21, 22, 23, 24, 25], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)

Wave6根層核對=([20, 21, 22, 23, 24, 25], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0096/)

子數列 · qf-mod38-subseq-finite-prefix-boundary · candidate





## 97. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-finite-prefix-boundary；資料={"indices":[21,23,25,27]}。請依 [indices, finite_prefix_increasing, infinite_certificate_supplied, boundary] 欄序回答。

沒有提供無限索引證書，不等於不能把遞增有限prefix延伸為無限遞增索引。

查看答案與解釋([21, 23, 25, 27], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)

Wave6根層核對=([21, 23, 25, 27], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0097/)

子數列 · qf-mod38-subseq-finite-prefix-boundary · candidate





## 98. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-finite-prefix-boundary；資料={"indices":[22,25,28,31,34]}。請依 [indices, finite_prefix_increasing, infinite_certificate_supplied, boundary] 欄序回答。

沒有提供無限索引證書，不等於不能把遞增有限prefix延伸為無限遞增索引。

查看答案與解釋([22, 25, 28, 31, 34], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)

Wave6根層核對=([22, 25, 28, 31, 34], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0098/)

子數列 · qf-mod38-subseq-finite-prefix-boundary · candidate





## 99. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-finite-prefix-boundary；資料={"indices":[23,27,31,35,39,43]}。請依 [indices, finite_prefix_increasing, infinite_certificate_supplied, boundary] 欄序回答。

沒有提供無限索引證書，不等於不能把遞增有限prefix延伸為無限遞增索引。

查看答案與解釋([23, 27, 31, 35, 39, 43], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)

Wave6根層核對=([23, 27, 31, 35, 39, 43], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0099/)

子數列 · qf-mod38-subseq-finite-prefix-boundary · candidate





## 100. 子數列

自然數索引與symbolic嚴格遞增證書。操作=subseq-finite-prefix-boundary；資料={"indices":[24,29,34,39]}。請依 [indices, finite_prefix_increasing, infinite_certificate_supplied, boundary] 欄序回答。

沒有提供無限索引證書，不等於不能把遞增有限prefix延伸為無限遞增索引。

查看答案與解釋([24, 29, 34, 39], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)

Wave6根層核對=([24, 29, 34, 39], 是, 否, finite_increasing_prefix_not_infinite_subsequence_certificate)；依完整明示資料獨立重算；subsequence索引必須嚴格遞增並保留原數列次序，不是重排或任意子集合；有限索引列表只證finite prefix；無限subsequence需要通用increasing-index certificate。



[本題逐步詳解（AI 二次覆核）](https://ocme.evemisslab.com/zh-Hant/questions/q-20261014-advance-20261107-r07-subsequence-0100/)

子數列 · qf-mod38-subseq-finite-prefix-boundary · candidate



[原始題目 JSONL](https://ocme.evemisslab.com/data/questions/batches/batch-20261014-advance-20261107-r07-subsequence-foundations/questions.jsonl) · [驗收報告](https://ocme.evemisslab.com/data/questions/batches/batch-20261014-advance-20261107-r07-subsequence-foundations/validation-report.json)