# 第 13713 題：有限雙邊理想 [返回所在分頁 69](https://ocme.evemisslab.com/zh-Hant/questions/page/69/) [← 逐題詳解目錄](https://ocme.evemisslab.com/zh-Hant/questions/) · [原題批次](https://ocme.evemisslab.com/zh-Hant/practice/batch-20261014-advance-20261028-r02-finite-two-sided-ideal-foundations/#q-20261014-advance-20261028-r02-finite-two-sided-ideal-0038) 本頁是已完成第二對話 AI 數理與中英語義覆核的教學詳解，只支持本題明示的模型與前提。沒有人工審查或新 Lean 證明，也不提升原題或 MKO 的 Canonical 真值狀態。 R0026-13713 · q-20261014-advance-20261028-r02-finite-two-sided-ideal-0038 ## 原題與已知條件 子集綁定同一完整有限父環。操作=ideal-additive-subgroup；資料={"n":8,"addition":[[0,1,2,3,4,5,6,7],[1,2,3,6,5,7,4,0],[2,3,6,4,7,0,5,1],[3,6,4,5,0,1,7,2],[4,5,7,0,2,3,1,6],[5,7,0,1,3,6,2,4],[6,4,5,7,1,2,0,3],[7,0,1,2,6,4,3,5]],"multiplication":[[0,0,0,0,0,0,0,0],[0,1,2,3,4,5,6,7],[0,2,6,5,2,6,0,5],[0,3,5,1,7,2,6,4],[0,4,2,7,1,5,6,3],[0,5,6,2,5,6,0,2],[0,6,0,6,6,0,0,6],[0,7,5,4,3,2,6,1]],"subset":[0]}。請依 [subset,zero,missing_additions,missing_inverses,additive_subgroup] 欄序回答。 - G001 — 子集綁定同一完整有限父環。操作=ideal-additive-subgroup；資料={"n":8,"addition":[[0,1,2,3,4,5,6,7],[1,2,3,6,5,7,4,0],[2,3,6,4,7,0,5,1],[3,6,4,5,0,1,7,2],[4,5,7,0,2,3,1,6],[5,7,0,1,3,6,2,4],[6,4,5,7,1,2,0,3],[7,0,1,2,6,4,3,5]],"multiplication":[[0,0,0,0,0,0,0,0],[0,1,2,3,4,5,6,7],[0,2,6,5,2,6,0,5],[0,3,5,1,7,2,6,4],[0,4,2,7,1,5,6,3],[0,5,6,2,5,6,0,2],[0,6,0,6,6,0,0,6],[0,7,5,4,3,2,6,1]],"subset":[0]}。請依 [subset,zero,missing_additions,missing_inverses,additive_subgroup] 欄序回答。 ## 定義與適用範圍 沿用原題明示的論域、假設與來源 MKO 定義。本題已完成第二對話數理與中英語義覆核，並由原始參數逐題獨立重算模型、答案與每個算術步驟；原題仍為 candidate。 - [mko-finite-two-sided-ideal](https://ocme.evemisslab.com/zh-Hant/mko/mko-finite-two-sided-ideal/) ## 逐步推導 S001 · implies操作前 same parent carrier Fin(8);addition=[[0, 1, 2, 3, 4, 5, 6, 7], [1, 2, 3, 6, 5, 7, 4, 0], [2, 3, 6, 4, 7, 0, 5, 1], [3, 6, 4, 5, 0, 1, 7, 2], [4, 5, 7, 0, 2, 3, 1, 6], [5, 7, 0, 1, 3, 6, 2, 4], [6, 4, 5, 7, 1, 2, 0, 3], [7, 0, 1, 2, 6, 4, 3, 5]];multiplication=[[0, 0, 0, 0, 0, 0, 0, 0], [0, 1, 2, 3, 4, 5, 6, 7], [0, 2, 6, 5, 2, 6, 0, 5], [0, 3, 5, 1, 7, 2, 6, 4], [0, 4, 2, 7, 1, 5, 6, 3], [0, 5, 6, 2, 5, 6, 0, 2], [0, 6, 0, 6, 6, 0, 0, 6], [0, 7, 5, 4, 3, 2, 6, 1]] 操作後 both complete operation tables typed and closed 條件：無 以下理想或交換律綁定同一父環；此處保留完整原表，不把元素標籤當成整數值。 步驟識別與依賴規則：parent_ring_original_complete_tables · 依賴：G001 S002 · implies操作前 every additive triple checked;first associativity failure=null;all additive pairs commute=是 操作後 additive zero candidates=[0];actual zero=0;two-sided additive inverses in label order=[0, 7, 5, 4, 3, 2, 6, 1] 條件：無 逐完整載體核加法結合、交換、兩側零與每個逆元；父環是題目使用的已合格前提，核查完整有限條件，不靠幾個樣本。 步驟識別與依賴規則：parent_additive_abelian_group_complete_audit · 依賴：G001, S001 S003 · implies操作前 every multiplicative triple checked;first associativity failure=null 操作後 multiplicative identity candidates=[1];actual one=1 條件：無 乘法只先要求結合與兩側one，不在此假設交換或非零元素可逆。 步驟識別與依賴規則：parent_multiplicative_monoid_complete_audit · 依賴：G001, S002 S004 · implies操作前 all 512 left and 512 right distributivity triples checked 操作後 first left failure=null;first right failure=null;zero=0;one=1;distinct=是 條件：無 左右分配責任分開完整核對，0與1必是不同實際元素；不因含一就宣稱交換環、整環或域。 步驟識別與依賴規則：parent_both_distributivities_and_distinct_identities · 依賴：G001, S003 S005 · implies操作前 raw subset=[0];same qualified parent zero=0 操作後 sorted distinct parent labels=[0] 條件：無 此子集按集合去重排序，但所有運算與逆元都來自同一父環，不另換加乘或把標籤當整數。 步驟識別與依賴規則：ideal_subset_same_parent_normalization · 依賴：G001, S004 S006 · implies操作前 subset element=0;parent additive inverse=0 操作後 inverse belongs to subset=是 條件：無 加法子群需每個成員的父環加法逆元仍在子集中；不是乘法逆元條件。 步驟識別與依賴規則：ideal_each_parent_additive_inverse · 依賴：G001, S005 S007 · implies操作前 subset ordered pair=[0, 0];parent sum=0 操作後 sum belongs to subset=是 條件：無 逐一核所有有序加法對，沒有抽樣替代閉包。 步驟識別與依賴規則：ideal_all_additive_closure_pairs · 依賴：G001, S006 S008 · implies操作前 subset nonempty=是;actual zero belongs=是;missing sums=[];missing inverses=[] 操作後 additive subgroup=是 條件：無 非空、含實際零、加法閉包與逆元閉包同時成立才合格；空集合不能因閉包空泛成立而成加法子群。 步驟識別與依賴規則：ideal_additive_subgroup_nonempty_zero_and_closure · 依賴：G001, S007 ## 逐步反向核對 - S008 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。 - S007 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。 - S006 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。 - S005 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。 - S004 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。 - S003 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。 - S002 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。 - S001 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。 ## 結論 ([0], 0, [], [], 是) 依上列完整代值及條件核對得到原題答案；原題編號、格式與狀態保持不變。 ## 本題覆核與來源綁定 覆核日期：2026-10-26 原題、答案、步驟表達式、數值 AST 與既有歷史保持原樣；原來的候選狀態屬於來源歷史，不覆寫為形式化證明。 來源雜湊與覆核憑證 - input commit: 0f7be61e2c22317a4075561dc822c87d881a50db - original question SHA-256: e74fb58ac8ac8dfbd057863b0297f92a3b4e953ed05f78b71f7aaf588093107a - candidate record SHA-256: 15739249f4c923fc925b16ade29449a96eb5795af77af515675a2e563da6e505 - semantic review receipt SHA-256: f335caca08574c9f949c141083c66655fee51c227d45d80a3ddb7d78f862d798 - question-first witness SHA-256: cc7ba54738af91a6871fc1c20e45ad8f2b434392273fa334bd16a3b2238f4a77 - Lean: NOT_RUN · human review: NOT_PERFORMED [同源完整 JSON](https://ocme.evemisslab.com/data/question-derivations/questions/q-20261014-advance-20261028-r02-finite-two-sided-ideal-0038.json)