# 第 24779 題：Turing機判定模型

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本頁是已完成第二對話 AI 數理與中英語義覆核的教學詳解，只支持本題明示的模型與前提。沒有人工審查或新 Lean 證明，也不提升原題或 MKO 的 Canonical 真值狀態。

R0048-24779 · q-20261015-advance-20261113-r05-turing-machine-decision-model-0004



## 原題與已知條件

deterministic single-tape signature、exact configuration semantics與decider total-correctness boundary。操作=tm-signature-qualification；資料={"states":["q03","q13","qa3","qr3"],"input_alphabet":["03"],"tape_alphabet":["03","X3","_3"],"blank":"_3","start_state":"q03","accept_state":"qa3","reject_state":"qr3","transitions":[["q03","03","q13","X3","R"],["q03","_3","qr3","_3","S"],["q13","_3","qa3","_3","L"]]}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。


- G001 — deterministic single-tape signature、exact configuration semantics與decider total-correctness boundary。操作=tm-signature-qualification；資料={"states":["q03","q13","qa3","qr3"],"input_alphabet":["03"],"tape_alphabet":["03","X3","_3"],"blank":"_3","start_state":"q03","accept_state":"qa3","reject_state":"qr3","transitions":[["q03","03","q13","X3","R"],["q03","_3","qr3","_3","S"],["q13","_3","qa3","_3","L"]]}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。





## 定義與適用範圍

沿用原題明示的論域、假設與來源 MKO 定義。本題已完成第二對話數理與中英語義覆核，並由原始參數逐題獨立重算模型、答案與每個算術步驟；原題仍為 candidate。


- [mko-turing-machine-decision-model](https://ocme.evemisslab.com/zh-Hant/mko/mko-turing-machine-decision-model/)





## 逐步推導

S001 · implies操作前

source roles = [tm-signature-qualification]

操作後

derived = [[states, input_alphabet, tape_alphabet, blank, start, accept, reject, transitions, qualified, convention]]

條件：無

直接列來源完整欄序，不需JavaScript；原題、布林旗標、數學物件與非聲稱保持分層。

步驟識別與依賴規則：source_ordered_fields_without_JS · 依賴：G001





S002 · implies操作前

source roles = [[q03, q13, qa3, qr3], [03], [03, X3, _3], _3, q03, qa3, qr3, [[q03, 03, q13, X3, R], [q03, _3, qr3, _3, S], [q13, _3, qa3, _3, L]]]

操作後

derived = [[q03, q13, qa3, qr3], [03], [03, X3, _3], [[q03, _3, qr3, _3, S], [q03, 03, q13, X3, R], [q13, _3, qa3, _3, L]], 是]

條件：無

三個清單皆非空且唯一；input是blank-free tape子集，但state與字母標籤不要求不相交。每個(from,read)的來源NUL-joined key唯一、halt無出邊。partial table合法，不補reject規則；canonical transition序與UTF16集合序分開。

步驟識別與依賴規則：TM_complete_signature_partial_transition_table_allowed · 依賴：G001, S001









## 逐步反向核對


- S002 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
- S001 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。





## 結論

([q03, q13, qa3, qr3], [03], [03, X3, _3], _3, q03, qa3, qr3, [[q03, _3, qr3, _3, S], [q03, 03, q13, X3, R], [q13, _3, qa3, _3, L]], 是, deterministic_single_tape_signature_with_halting_states_without_outgoing_transitions)

依上列完整代值及條件核對得到原題答案；原題編號、格式與狀態保持不變。





## 本題覆核與來源綁定

覆核日期：2026-10-26

原題、答案、步驟表達式、數值 AST 與既有歷史保持原樣；原來的候選狀態屬於來源歷史，不覆寫為形式化證明。

來源雜湊與覆核憑證
- input commit: 0f7be61e2c22317a4075561dc822c87d881a50db
- original question SHA-256: 09fa76f4bd8b621980021487c7178c3157bf9929fed916092a91dbd86167107a
- candidate record SHA-256: 10bc22b1a32a353c4b096af836a44df6ab32746ba4a9f130ce6347361113e2d2
- semantic review receipt SHA-256: 049a9e07e69fead88d93b34f0937b9470a06d71c1a8d097058fc83554529bdd0
- question-first witness SHA-256: 0c71ebb418f3de347d232d159fc25e93036f4ab9166bcfb5ee5b4be86d5c55b9
- Lean: NOT_RUN · human review: NOT_PERFORMED

[同源完整 JSON](https://ocme.evemisslab.com/data/question-derivations/questions/q-20261015-advance-20261113-r05-turing-machine-decision-model-0004.json)