# 第 24364 題：有限流網路

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本頁是已完成第二對話 AI 數理與中英語義覆核的教學詳解，只支持本題明示的模型與前提。沒有人工審查或新 Lean 證明，也不提升原題或 MKO 的 Canonical 真值狀態。

R0047-24364 · q-20261015-advance-20261113-r07-finite-flow-network-0014



## 原題與已知條件

finite loop-free directed network、逐edge capacity與逐internal-vertex conservation。操作=flow-network-qualification；資料={"vertices":["s13","a13","t13","u13"],"edges":[["s13","a13"],["a13","s13"],["a13","t13"],["t13","a13"]],"source":"s13","sink":"t13","capacities":[70,70,70,70],"flows":[56,28,42,14]}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。


- G001 — finite loop-free directed network、逐edge capacity與逐internal-vertex conservation。操作=flow-network-qualification；資料={"vertices":["s13","a13","t13","u13"],"edges":[["s13","a13"],["a13","s13"],["a13","t13"],["t13","a13"]],"source":"s13","sink":"t13","capacities":[70,70,70,70],"flows":[56,28,42,14]}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。





## 定義與適用範圍

沿用原題明示的論域、假設與來源 MKO 定義。本題已完成第二對話數理與中英語義覆核，並由原始參數逐題獨立重算模型、答案與每個算術步驟；原題仍為 candidate。


- [mko-finite-flow-network](https://ocme.evemisslab.com/zh-Hant/mko/mko-finite-flow-network/)





## 逐步推導

S001 · implies操作前

source roles = [flow-network-qualification]

操作後

derived = [[vertices, source, sink, edge_capacity_flow_rows, antiparallel_pair_count, network_qualified, convention]]

條件：無

本頁列完整來源欄序，不需JavaScript；gradient boundary依原mode選6／8／7欄，不補欄也不由答案猜mode。

步驟識別與依賴規則：source_ordered_fields_without_JS · 依賴：G001





S002 · implies操作前

source roles = [[s13, a13, t13, u13], [[s13, a13], [a13, s13], [a13, t13], [t13, a13]], [70, 70, 70, 70], [56, 28, 42, 14], s13, t13]

操作後

derived = [[a13, s13, t13, u13], [[[a13, s13], 70, 28], [[a13, t13], 70, 42], [[s13, a13], 70, 56], [[t13, a13], 70, 14]], 2, 是]

條件：無

先依原index配好edge／capacity／flow，再按來源English canonical(edge)序排；vertices用UTF16。反向邊是不同edge，zero容量與孤立點合法，負flow保留供容量判失敗，不修改。

步驟識別與依賴規則：Flow_zip_source_edges_capacities_flows_BEFORE_order · 依賴：G001, S001





S003 · implies操作前

source roles = [0, [a13, s13], 28, 70]

操作後

derived = [是, 是, 是]

條件：無

每條有向邊都要0<=flow<=capacity；網路signature合格並不保證候選flow可行。

步驟識別與依賴規則：Flow_EACH_edge_two_sided_capacity_obligation · 依賴：G001, S002





S004 · implies操作前

source roles = [1, [a13, t13], 42, 70]

操作後

derived = [是, 是, 是]

條件：無

每條有向邊都要0<=flow<=capacity；網路signature合格並不保證候選flow可行。

步驟識別與依賴規則：Flow_EACH_edge_two_sided_capacity_obligation · 依賴：G001, S003





S005 · implies操作前

source roles = [2, [s13, a13], 56, 70]

操作後

derived = [是, 是, 是]

條件：無

每條有向邊都要0<=flow<=capacity；網路signature合格並不保證候選flow可行。

步驟識別與依賴規則：Flow_EACH_edge_two_sided_capacity_obligation · 依賴：G001, S004





S006 · implies操作前

source roles = [3, [t13, a13], 14, 70]

操作後

derived = [是, 是, 是]

條件：無

每條有向邊都要0<=flow<=capacity；網路signature合格並不保證候選flow可行。

步驟識別與依賴規則：Flow_EACH_edge_two_sided_capacity_obligation · 依賴：G001, S005





S007 · calculation操作前

Flow ALL incoming at vertex a13 := sum(56, 14)

操作後

Flow ALL incoming at vertex a13 = 70

條件：無

依原題角色與已證中間量精確代值；分母先核非零，不以近似數替代。

步驟識別與依賴規則：exact_rational_arithmetic · 依賴：G001, S006





S008 · calculation操作前

Flow ALL outgoing at vertex a13 := sum(28, 42)

操作後

Flow ALL outgoing at vertex a13 = 70

條件：無

依原題角色與已證中間量精確代值；分母先核非零，不以近似數替代。

步驟識別與依賴規則：exact_rational_arithmetic · 依賴：G001, S007





S009 · implies操作前

source roles = [a13, [2, 3], [0, 1]]

操作後

derived = [70, 70, 是, 是]

條件：無

入邊／出邊各依完整清單加總；孤立點是0=0。守恆只要求internal vertices，源匯仍計完整balance以求net值。

步驟識別與依賴規則：Flow_EACH_vertex_complete_directional_incidence · 依賴：G001, S008





S010 · calculation操作前

Flow ALL incoming at vertex s13 := sum(28)

操作後

Flow ALL incoming at vertex s13 = 28

條件：無

依原題角色與已證中間量精確代值；分母先核非零，不以近似數替代。

步驟識別與依賴規則：exact_rational_arithmetic · 依賴：G001, S009





S011 · calculation操作前

Flow ALL outgoing at vertex s13 := sum(56)

操作後

Flow ALL outgoing at vertex s13 = 56

條件：無

依原題角色與已證中間量精確代值；分母先核非零，不以近似數替代。

步驟識別與依賴規則：exact_rational_arithmetic · 依賴：G001, S010





S012 · implies操作前

source roles = [s13, [0], [2]]

操作後

derived = [28, 56, 否, 否]

條件：無

入邊／出邊各依完整清單加總；孤立點是0=0。守恆只要求internal vertices，源匯仍計完整balance以求net值。

步驟識別與依賴規則：Flow_EACH_vertex_complete_directional_incidence · 依賴：G001, S011





S013 · calculation操作前

Flow ALL incoming at vertex t13 := sum(42)

操作後

Flow ALL incoming at vertex t13 = 42

條件：無

依原題角色與已證中間量精確代值；分母先核非零，不以近似數替代。

步驟識別與依賴規則：exact_rational_arithmetic · 依賴：G001, S012





S014 · calculation操作前

Flow ALL outgoing at vertex t13 := sum(14)

操作後

Flow ALL outgoing at vertex t13 = 14

條件：無

依原題角色與已證中間量精確代值；分母先核非零，不以近似數替代。

步驟識別與依賴規則：exact_rational_arithmetic · 依賴：G001, S013





S015 · implies操作前

source roles = [t13, [1], [3]]

操作後

derived = [42, 14, 否, 否]

條件：無

入邊／出邊各依完整清單加總；孤立點是0=0。守恆只要求internal vertices，源匯仍計完整balance以求net值。

步驟識別與依賴規則：Flow_EACH_vertex_complete_directional_incidence · 依賴：G001, S014





S016 · calculation操作前

Flow ALL incoming at vertex u13 := sum()

操作後

Flow ALL incoming at vertex u13 = 0

條件：無

依原題角色與已證中間量精確代值；分母先核非零，不以近似數替代。

步驟識別與依賴規則：exact_rational_arithmetic · 依賴：G001, S015





S017 · calculation操作前

Flow ALL outgoing at vertex u13 := sum()

操作後

Flow ALL outgoing at vertex u13 = 0

條件：無

依原題角色與已證中間量精確代值；分母先核非零，不以近似數替代。

步驟識別與依賴規則：exact_rational_arithmetic · 依賴：G001, S016





S018 · implies操作前

source roles = [u13, [], []]

操作後

derived = [0, 0, 是, 是]

條件：無

入邊／出邊各依完整清單加總；孤立點是0=0。守恆只要求internal vertices，源匯仍計完整balance以求net值。

步驟識別與依賴規則：Flow_EACH_vertex_complete_directional_incidence · 依賴：G001, S017





S019 · calculation操作前

Flow source NET outflow not gross outgoing := sub(56, 28)

操作後

Flow source NET outflow not gross outgoing = 28

條件：無

依原題角色與已證中間量精確代值；分母先核非零，不以近似數替代。

步驟識別與依賴規則：exact_rational_arithmetic · 依賴：G001, S018





S020 · calculation操作前

Flow sink NET inflow not gross incoming := sub(42, 14)

操作後

Flow sink NET inflow not gross incoming = 28

條件：無

依原題角色與已證中間量精確代值；分母先核非零，不以近似數替代。

步驟識別與依賴規則：exact_rational_arithmetic · 依賴：G001, S019





S021 · implies操作前

source roles = [s13, t13, [[[a13, s13], 28, 70, 是], [[a13, t13], 42, 70, 是], [[s13, a13], 56, 70, 是], [[t13, a13], 14, 70, 是]], [[a13, 70, 70, 是], [u13, 0, 0, 是]], 28, 28]

操作後

derived = [是, 是, 是, 是, 否]

條件：無

全vertex總in−out中每edge相消，故全部internal守恆必得兩net相等；反向不成立，internal imbalance可互抵。容量、逐點守恆、兩net值分別核，feasible不推出maximum/min-cut。最後No是不提供最優證書，不否定特例恰好最優。

步驟識別與依賴規則：Flow_value_capacity_conservation_and_maximum_separate · 依賴：G001, S020









## 逐步反向核對


- S021 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
- S020 · premise_and_result_audit — 以精確有理數重算 Flow sink NET inflow not gross incoming，不以小數近似替代。
- S019 · premise_and_result_audit — 以精確有理數重算 Flow source NET outflow not gross outgoing，不以小數近似替代。
- S018 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
- S017 · premise_and_result_audit — 以精確有理數重算 Flow ALL outgoing at vertex u13，不以小數近似替代。
- S016 · premise_and_result_audit — 以精確有理數重算 Flow ALL incoming at vertex u13，不以小數近似替代。
- S015 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
- S014 · premise_and_result_audit — 以精確有理數重算 Flow ALL outgoing at vertex t13，不以小數近似替代。
- S013 · premise_and_result_audit — 以精確有理數重算 Flow ALL incoming at vertex t13，不以小數近似替代。
- S012 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
- S011 · premise_and_result_audit — 以精確有理數重算 Flow ALL outgoing at vertex s13，不以小數近似替代。
- S010 · premise_and_result_audit — 以精確有理數重算 Flow ALL incoming at vertex s13，不以小數近似替代。
- S009 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
- S008 · premise_and_result_audit — 以精確有理數重算 Flow ALL outgoing at vertex a13，不以小數近似替代。
- S007 · premise_and_result_audit — 以精確有理數重算 Flow ALL incoming at vertex a13，不以小數近似替代。
- S006 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
- S005 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
- S004 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
- S003 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
- S002 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
- S001 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。





## 結論

([a13, s13, t13, u13], s13, t13, [[[a13, s13], 70, 28], [[a13, t13], 70, 42], [[s13, a13], 70, 56], [[t13, a13], 70, 14]], 2, 是, finite_loop_free_simple_digraph_with_explicit_antiparallel_convention_zero_capacities_and_disconnected_vertices_allowed)

依上列完整代值及條件核對得到原題答案；原題編號、格式與狀態保持不變。





## 本題覆核與來源綁定

覆核日期：2026-10-26

原題、答案、步驟表達式、數值 AST 與既有歷史保持原樣；原來的候選狀態屬於來源歷史，不覆寫為形式化證明。

來源雜湊與覆核憑證
- input commit: 0f7be61e2c22317a4075561dc822c87d881a50db
- original question SHA-256: ce7d53fba5944509648c794303815f391bdf5b5c2efb9912dc24241e89de48c0
- candidate record SHA-256: 01e6e522b928537f87a985295191cde868ad3a5fc2279a87a44d7b82ca26f7a7
- semantic review receipt SHA-256: 9b43b9823e9bd2478d6caa5b57ffed161c2c8956af86974e901d5662ad994386
- question-first witness SHA-256: eb97596068e2d5648033bab2b8f6ca9b653bbe8cb77c0f8e1d16d0c40e46f50b
- Lean: NOT_RUN · human review: NOT_PERFORMED

[同源完整 JSON](https://ocme.evemisslab.com/data/question-derivations/questions/q-20261015-advance-20261113-r07-finite-flow-network-0014.json)




