S01 · implies
Before
1/20+1/20+9/100+81/100
After
1
Conditions: none
Rule: work · Uses: G1, work
Leaf basis: work
First qualify the four-atom law as nonnegative and normalized.
derivation-mko-bayes-theorem-01 · ocme-new142-reader-adoption-20261021
Compute priors, likelihoods and posteriors from a complete joint law.
A synthetic finite model, with no medical or causal inference.
workG1 — Omega={D+,D-,N+,N-} has masses 1/20,1/20,9/100,81/100; D={D+,D-}, N is its complement, E={D+,N+}.D,N — disjoint hypothesesE — evidence eventmko_definition · cited — Use exact rational masses in one complete finite atomic law. Both the two-event and partition forms require positive conditioning denominators. Partition hypotheses must be disjoint and exhaustive, and the evidence mass obtained by total probability must be positive. Bayes conditioning is not causation. · mko-bayes-theoremwork · prerequisite — For positive denominators P(A|B)=P(A∩B)/P(B); finite additivity over a complete disjoint partition gives total probability.Before
1/20+1/20+9/100+81/100
After
1
Conditions: none
Rule: work · Uses: G1, work
Leaf basis: work
First qualify the four-atom law as nonnegative and normalized.
Before
D\cap N=\varnothing,\quad D\cup N=\Omega
After
P(D)=1/10,\quad P(N)=9/10
Conditions: none
Rule: work · Uses: G1, S01, work
Leaf basis: work
D,N form a complete disjoint partition with positive priors.
Before
P(E\cap D)=1/20
After
P(E\mid D)=(1/20)/(1/10)=1/2
Conditions: none
Rule: work · Uses: G1, S02, work
Leaf basis: work
Normalize by the D mass to obtain the first likelihood.
Before
P(E\cap N)=9/100
After
P(E\mid N)=(9/100)/(9/10)=1/10
Conditions: none
Rule: work · Uses: G1, S03, work
Leaf basis: work
Compute the likelihood on the other partition cell too.
Before
P(E)=P(E\mid D)P(D)+P(E\mid N)P(N)
After
P(E)=1/20+9/100=7/50>0
Conditions: none
Rule: work · Uses: G1, S04, work
Leaf basis: work
Total probability over the complete partition gives the evidence denominator.
Before
P(D\mid E)=P(D\cap E)/P(E)
After
P(D\mid E)=(1/20)/(7/50)=5/14
Conditions: none
Rule: work · Uses: G1, S05, work
Leaf basis: work
The same intersection with the new conditioning denominator completes the reversal.
Before
P(N\mid E)=(9/100)/(7/50)
After
P(N\mid E)=9/14,\quad5/14+9/14=1
Conditions: none
Rule: work · Uses: G1, S06, work
Leaf basis: work
Complete the posterior table and verify normalization.
Before
P(E\mid D)P(D)/P(E)
After
\frac{(1/2)(1/10)}{7/50}=5/14Conditions: none
Rule: work · Uses: G1, S07, work
Leaf basis: work
Cross-check the direct joint quotient against the Bayes product form.
No substeps in this guide.
S08 · premise_audit · G1, S07, work — The result describes a conditional law, not a causal effect.S07 · premise_audit · G1, S06, work — Both posterior entries condition on the same evidence event.S06 · premise_audit · G1, S05, work — The posterior 5/14 differs from likelihood 1/2; direction was not silently equated.S05 · premise_audit · G1, S04, work — Both likelihoods retain their priors, and positivity is established.S04 · premise_audit · G1, S03, work — N has prior 9/10, not D's1/10.S03 · premise_audit · G1, S02, work — The denominator 1/10 is strictly positive.S02 · premise_audit · G1, S01, work — The atom sets certify a partition, not independence.S01 · premise_audit · G1, work — Listing only positive-test atoms would omit part of the law.Audit disjointness and exhaustiveness before total probability.
Use the common joint numerator and distinct positive denominators to distinguish directions.
reject — The priors and evidence give 5/14.reject — The unequal priors 1/10 and 9/10 cannot be omitted.reject — The conditioning denominator must be strictly positive.P(D|E)=5/14 and P(N|E)=9/14; neither is a causal conclusion.
3 declared checks for this guide; only the listed expressions are covered.
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