S01 · implies
Before
|(-1)^n|=1,\quad0<1/(n+1)\le1
After
|a_n|\le2\quad\forall n\ge0
Conditions: none
Rule: algebra · Uses: G1
Leaf basis: algebra
The triangle bound gives one M=2 controlling every term.
derivation-mko-bolzano-weierstrass-theorem-real-01 · ocme-new142-reader-adoption-20261021
For a_n=(-1)^n+1/(n+1), provide boundedness and two complete convergent subsequences.
Only the declared symbolic sequence, not a replacement for the general BW theorem.
algebraepsilonG1 — a_n=(-1)^n+1/(n+1), n≥0; take k(j)=2j and ell(j)=2j+1.k,\ell — parity indicesM — whole-sequence boundSome rule statements have reader clarifications in this revision: they are paraphrases, not verbatim quotations. Referenced original source bytes and hashes are unchanged.
mko_definition · cited — Boundedness means there exists M bounding all terms, not just a finite prefix. A subsequence has an infinite strictly increasing index map, and convergence has an all-later epsilon-tail witness. Periodic sequences and symbolic oscillatory rational tails give exact instances here. A finite prefix or finite cluster search is insufficient. The theorem does not require the original sequence to converge or guarantee that every convergent subsequence has the same limit. · mko-bolzano-weierstrass-theorem-realalgebra · prerequisite — Use real-field identities; division requires a nonzero denominator and multiplication by a positive number preserves inequalities.epsilon · prerequisite — Convergence requires for every positive epsilon an integer N controlling every n≥N by a strict error bound; use the Archimedean property of the reals.Before
|(-1)^n|=1,\quad0<1/(n+1)\le1
After
|a_n|\le2\quad\forall n\ge0
Conditions: none
Rule: algebra · Uses: G1
Leaf basis: algebra
The triangle bound gives one M=2 controlling every term.
Before
k(j+1)-k(j)=2,\quad\ell(j+1)-\ell(j)=2
After
k,\ell:\mathbb N_0\to\mathbb N_0\text{ strictly increasing}Conditions: none
Rule: algebra · Uses: G1
Leaf basis: algebra
Both complete affine indices have positive step and nonnegative start.
Before
a_{k(j)}=a_{2j}After
a_{2j}=1+1/(2j+1)Conditions: none
Rule: algebra · Uses: G1, S02
Leaf basis: algebra
Even parity gives a positive sign; substitute the index before evaluating.
Before
\varepsilon>0,\quad J=\lfloor1/\varepsilon\rfloor+1
After
j\ge J\Longrightarrow |a_{2j}-1|=1/(2j+1)<\varepsilonConditions: none
Rule: epsilon · Uses: S03
Leaf basis: epsilon
The denominator lower bound proves the whole even-subsequence tail tends to 1.
Before
a_{\ell(j)}=a_{2j+1}After
a_{2j+1}=-1+1/(2j+2)Conditions: none
Rule: algebra · Uses: G1, S02
Leaf basis: algebra
Odd parity gives a negative sign while retaining the positive rational perturbation.
Before
j\ge J=\lfloor1/\varepsilon\rfloor+1
After
|a_{2j+1}+1|=1/(2j+2)<\varepsilonConditions: none
Rule: epsilon · Uses: S05
Leaf basis: epsilon
The same J also controls every term in the odd-subsequence tail.
Before
a_{2j}\to1,\quad a_{2j+1}\to-1After
(a_n)\text{ has convergent subsequences with different limits}Conditions: none
Rule: epsilon · Uses: S01, S02, S04, S06
Leaf basis: epsilon
This supplies the existence promised by BW in this instance, and in fact gives two subsequences.
Before
1\ne-1
After
(a_n)\text{ does not converge}Conditions: none
Rule: epsilon · Uses: S04, S06
Leaf basis: epsilon
If the original converged to L, every strictly increasing index would eventually exceed its tail N, forcing both subsequences to L; uniqueness of limits contradicts this.
No substeps in this guide.
S08 · premise_audit · S04, S06 — Nonconvergence follows from different proved subsequential limits, not visual oscillation.S07 · premise_audit · S01, S02, S04, S06 — The instance does not claim the theorem for all bounded sequences from finite tests.S06 · premise_audit · S05 — This independently checks the odd subsequence, rather than inferring the even limit for it.S05 · inverse_equivalence · G1, S02 — The limit is -1, not its magnitude 1.S04 · premise_audit · S03 — The strict bound holds for every j≥J.S03 · inverse_equivalence · G1, S02 — The denominator is 2j+1, not 2j.S02 · premise_audit · G1 — The infinite index domain is specified, not a finite list.S01 · premise_audit · G1 — A prefix maximum is not substituted for whole-sequence boundedness.M must hold for every n.
Indices must be strictly increasing and infinite, with an all-tail convergence bound.
reject — This example has two different proved subsequential limits.reject — The limits 1 and -1 here differ.reject — Complete infinite indices, a whole-sequence bound and an all-tail certificate are required.The whole sequence is bounded; the even subsequence tends to 1 and the odd to -1, so the original does not converge.
2 declared checks for this guide; only the listed expressions are covered.
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