S01 · implies
Before
X_i\sim\operatorname{Bernoulli}(1/2)After
\mu=1/2,\quad\sigma^2=1/4\in(0,\infty)
Conditions: none
Rule: work · Uses: G1, work
Leaf basis: work
Recompute the complete marginal moments and check nondegeneracy.
derivation-mko-central-limit-theorem-finite-variance-iid-01 · ocme-new142-reader-adoption-20261021
Separate finite-n moments from the named CLT application.
The CLT is an explicit named theorem prerequisite, not proved here.
workG1 — On a supplied probability space, (X_i)_{i≥1} is an infinite IID sequence: every finite distinct-index joint law factors into Bernoulli(1/2) marginals. This is a whole-process premise, not inferred from finite data.S_n — partial sumZ_n — correct standardizationΦ — standard-normal CDFSome rule statements have reader clarifications in this revision: they are paraphrases, not verbatim quotations. Referenced original source bytes and hashes are unchanged.
mko_definition · cited — Assume an infinite IID process with common mean mu and 0<sigma^2<infinity. For S_n=sum_(i=1)^n X_i define Z_n=(S_n−n*mu)/(sigma*sqrt(n)). Then P(Z_n≤z) tends to Phi(z) at every continuity point of the standard normal CDF. The exact families use a finite common marginal law, recalculate its moments, the fixed-n standardized moments0 and 1, and a complete Bernoulli sum lattice. A symbolic branch conditionally invokes the named theorem under declared hypotheses. The infinite_iid token declares a premise; it does not construct or prove a whole process. A finite binomial table or histogram is not a normal approximation or convergence proof. Non-IID excludes this particular theorem; zero variance and n*sigma scaling do not qualify this normalization. · mko-central-limit-theorem-finite-variance-iidwork · prerequisite — Explicit named theorem prerequisite: infinite IID with 0<sigma²<infinity gives convergence of centered sums divided by sigma sqrt(n) to standard normal; also assume independent variance addition and the binomial law.Before
X_i\sim\operatorname{Bernoulli}(1/2)After
\mu=1/2,\quad\sigma^2=1/4\in(0,\infty)
Conditions: none
Rule: work · Uses: G1, work
Leaf basis: work
Recompute the complete marginal moments and check nondegeneracy.
Before
S_n=\sum_{i=1}^nX_iAfter
E[S_n]=n/2,\quad\operatorname{Var}(S_n)=n/4Conditions: none
Rule: work · Uses: G1, S01, work
Leaf basis: work
Linearity and independent variance addition give moments of the sum.
Before
Z_n=(S_n-n\mu)/(\sigma\sqrt n)
After
Z_n=\frac{S_n-n/2}{\sqrt n/2}Conditions: none
Rule: work · Uses: G1, S02, work
Leaf basis: work
Sigma=1/2, so the denominator is sqrt(n)/2.
Before
E[Z_n],\quad\operatorname{Var}(Z_n)After
E[Z_n]=0,\quad\operatorname{Var}(Z_n)=\frac{n/4}{n/4}=1Conditions: none
Rule: work · Uses: G1, S03, work
Leaf basis: work
The standardized moments hold exactly for every n≥1.
Before
n=4,\quad k\in\{0,1,2,3,4\}After
P(S_4=k)=\binom4k/16=(1,4,6,4,1)_k/16
Conditions: none
Rule: work · Uses: G1, S04, work
Leaf basis: work
List all five lattice probabilities without omitting tail points.
Before
Z_4=S_4-2
After
Z_4\in\{-2,-1,0,1,2\},\quad P(Z_4=0)=3/8Conditions: none
Rule: work · Uses: G1, S05, work
Leaf basis: work
At n=4 the standardized law is still discrete with positive singleton mass.
Before
\text{infinite IID},\ E[X_i]=\mu,\ 0<\sigma^2<\inftyAfter
\forall z\in\mathbb R:\lim_{n\to\infty}P(Z_n\le z)=\Phi(z)\quad\text{(named CLT)}Conditions: none
Rule: work · Uses: G1, S06, work
Leaf basis: work
Invoke the assumed named CLT after matching IID and positive finite variance; Phi is continuous everywhere.
Before
P(Z_4=0)=3/8,\quad P(Z=0)=0\ (Z\sim N(0,1))
After
Z_n\Rightarrow N(0,1),\quad Z_4\not\sim N(0,1)
Conditions: none
Rule: work · Uses: G1, S07, work
Leaf basis: work
Retain both the limit conclusion and the finite-n nonidentity boundary.
No substeps in this guide.
S08 · premise_audit · G1, S07, work — No normal-approximation error rate or formal CLT proof is supplied.S07 · premise_audit · G1, S06, work — This limit comes from the named theorem, not the five-point table.S06 · premise_audit · G1, S05, work — The standard normal is atomless, ruling out exact equality of laws.S05 · premise_audit · G1, S04, work — The coefficients sum to 16 from the four-fold Bernoulli product.S04 · premise_audit · G1, S03, work — Moments0 and 1 alone do not identify a normal law.S03 · premise_audit · G1, S02, work — It is not n/2, and centering must subtract n/2.S02 · premise_audit · G1, S01, work — Variance addition uses the declared whole-sequence independence.S01 · premise_audit · G1, work — Zero variance invalidates normalization, so positivity cannot be omitted.Declare infinite IID as a premise, not a process-construction proof.
Use sigma²=1/4>0 and denominator sigma sqrt(n); retain finite-n discreteness.
reject — It has mass 3/8 at 0; a normal law has zero singleton mass.reject — It gives variance 1/n instead of 1.reject — Finite-n data does not establish the infinite CDF limit; that uses the named theorem.The named CLT applies, so Z_n⇒N(0,1); the n=4 lattice neither proves the limit nor equals a normal law.
3 declared checks for this guide; only the listed expressions are covered.
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