Excluding every two-color assignment on a triangle

On this page
  1. Goal and scope
  2. Givens and symbols
  3. Rules and sources
  4. Main derivation
  5. Substeps and lemmas
  6. Reverse audits
  7. Error controls and negative controls
  8. Result and limitations
  9. Verification and source binding

← Guide index · Original MKO

derivation-mko-chromatic-number-01 · ocme-new142-reader-adoption-20261021

Goal and scope

Prove chi=3 using an upper witness and complete lower-color search.

Exact enumeration at n=3, with no greedy-optimality assumption.

Givens and symbols

  • work
  • G1 — V={0,1,2}, E={01,02,12}; two-color labels are 0,1, with assignment vectors ordered by vertices(0,1,2).
  • V,E — complete vertex and edge sets
  • χ(G) — minimum number of colors

Rules and sources

  • mko_definition · cited — One proper k-coloring proves chi(G)≤k; equality also needs a valid exclusion of (k−1)-colorings. Complete small graphs are checked exhaustively for a lower bound and given an explicit coloring for an upper bound. A greedy result alone is not optimality evidence. The empty vertex graph has chi=0 and a nonempty edgeless graph has chi=1. · mko-chromatic-number
  • work · prerequisite — A finite simple undirected graph has loop-free duplicate-free unordered edges; graph properties are audited on all declared V and E. A proper coloring gives distinct colors across every edge; chi is the minimum used-color count over all total proper colorings, and k-colorable means using at most k colors.

Main derivation

S01 · implies

Before

c=(0,1,2)

After

c(0)\ne c(1),\quad c(0)\ne c(2),\quad c(1)\ne c(2)

Conditions: none

Rule: work · Uses: G1, work

Leaf basis: work

Audit every edge of the three-color witness, giving chi≤3.

S02 · implies

Before

c:V\to\{0,1\}

After

2^3=8\text{ assignments}

Conditions: none

Rule: work · Uses: G1, S01, work

Leaf basis: work

The complete search has eight vectors and includes one-color assignments as subcases.

S03 · implies

Before

000,001

After

c(0)=c(1)=0\implies01\text{ violated}

Conditions: none

Rule: work · Uses: G1, S02, work

Leaf basis: work

The first two assignments both conflict on edge 01.

S04 · implies

Before

010,101

After

c(0)=c(2)\implies02\text{ violated}

Conditions: none

Rule: work · Uses: G1, S03, work

Leaf basis: work

Both alternating assignments conflict on02.

S05 · implies

Before

011,100

After

c(1)=c(2)\implies12\text{ violated}

Conditions: none

Rule: work · Uses: G1, S04, work

Leaf basis: work

These two assignments give equal colors to the last two vertices.

S06 · implies

Before

110,111

After

c(0)=c(1)=1\implies01\text{ violated}

Conditions: none

Rule: work · Uses: G1, S05, work

Leaf basis: work

The final two assignments also fail, exhausting all eight cases.

S07 · implies

Before

\text{no proper map }V\to\{0,1\}

After

\chi(G)>2

Conditions: none

Rule: work · Uses: G1, S06, work

Leaf basis: work

Zero- or one-color assignments cannot evade the two-color exclusion, with V nonempty.

S08 · implies

Before

2<\chi(G)\le3,\quad\chi(G)\in\mathbb N

After

\chi(G)=3

Conditions: none

Rule: work · Uses: G1, S07, work

Leaf basis: work

Integrality combines upper and lower bounds into the exact chromatic number.

Substeps and lemmas

No substeps in this guide.

Reverse audits

  • S08 · premise_audit · G1, S07, work — The separate conventions are chi=0 for no vertices and chi=1 for nonempty edgeless graphs.
  • S07 · premise_audit · G1, S06, work — This is a global lower bound, not one failed candidate.
  • S06 · premise_audit · G1, S05, work — The set is 000,001,010,011,100,101,110,111.
  • S05 · premise_audit · G1, S04, work — Swapping color labels does not remove the violation.
  • S04 · premise_audit · G1, S03, work — Check02 too; it is an edge despite nonconsecutive labels.
  • S03 · premise_audit · G1, S02, work — Both cases are explicitly listed.
  • S02 · premise_audit · G1, S01, work — At most two colors does not require both to appear.
  • S01 · premise_audit · G1, work — Equality still requires excluding fewer colors.

Error controls and negative controls

Complete enumeration

Each of the eight bit assignments appears once.

Bounds

Give three colors, exclude every two-color assignment, then use integrality.

  • A three-coloring alone proves chi=3. → reject — It gives only an upper bound; the eight-case exclusion supplies the lower bound.
  • 010 is proper on the triangle. → reject — Edge 02 has color0 at both ends.
  • A nonempty edgeless graph has chi=0. → reject — Each vertex still needs a color, so the minimum is 1.

Result and limitations

All eight two-color cases fail and a three-color witness exists, hence chi=3.

    Verification and source binding

    2 declared checks for this guide; only the listed expressions are covered.

    • source commit: b1b2f1dcf8c50d67a93fe52d95f8eef7b3abba9f
    • adopted source SHA-256: e067a4fb1baa6f694ba27da6d3b5d80c12c74434d72f796ad27dd14c604b48ad
    • original source SHA-256: 1ca25d8841495fe4e298468a1912e58c28402ed9745e1fee11300a1b7c39f7b5
    • Lean: NOT_RUN · independent AI: SCOPED_LEAD_AND_BILINGUAL_CONTEXT_REVIEW

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