S01 · implies
Before
30=2\cdot15=2\cdot3\cdot5
After
30=2^1 3^1 5^1
Conditions: none
Rule: calc · Uses: G1
Leaf basis: calc
Complete trial extraction removes 2 then 3, leaving prime 5 after testing 2; the product returns 30.
derivation-mko-mobius-function-01 · ocme-new142-reader-adoption-20261021
mu(30)=-1, mu(12)=0, mu(1)=1; the sum over every divisor of 30 is zero.
Complete positive-integer factorization and divisor cross-checks; incomplete factors give no classification.
calcG1 — Main n=30, with 12 and 1; mu is zero for a repeated prime factor and (-1)^k for a squarefree integer with k distinct primes.\mu — Mobius functionD(n) — all positive divisorsSome rule statements have reader clarifications in this revision: they are paraphrases, not verbatim quotations. Referenced original source bytes and hashes are unchanged.
calc · prerequisite — Assume exact integer arithmetic, division with remainder, and definitions of divisibility and gcd; every congruence has an explicit modulus.mko_definition · cited — A complete unique-prime-factorization certificate supplies multiplicities and the distinct-prime count, independently of factor order. The exact divisor-sum cross-check is sum over d dividing n of mu(d)=1 for n=1 and 0 otherwise. Zero and negative integers are outside the domain. Incomplete trial division does not justify classification. · mko-mobius-functionBefore
30=2\cdot15=2\cdot3\cdot5
After
30=2^1 3^1 5^1
Conditions: none
Rule: calc · Uses: G1
Leaf basis: calc
Complete trial extraction removes 2 then 3, leaving prime 5 after testing 2; the product returns 30.
Before
(e_2,e_3,e_5)=(1,1,1)
After
30\text{ squarefree},\quad k=3Conditions: none
Rule: calc · Uses: G1, S01
Leaf basis: calc
Every prime multiplicity is 1, so the square-factor branch does not apply and the distinct-prime count is 3.
Before
k=3
After
\mu(30)=(-1)^3=-1
Conditions: none
Rule: mko_definition · Uses: G1, S02
Leaf basis: mko_definition
The squarefree branch gives sign -1.
Before
30=2^1 3^1 5^1
After
D(30)=\{1,2,3,5,6,10,15,30\}Conditions: none
Rule: calc · Uses: G1, S01
Leaf basis: calc
Each exponent is 0 or 1, and all 2^3=8 choices give the listed positive divisors.
Before
d=1,2,3,5,6,10,15,30
After
\mu(d)=1,-1,-1,-1,1,1,1,-1\text{ respectively}Conditions: none
Rule: calc · Uses: G1, S03, S04
Leaf basis: calc
Each divisor inherits complete multiplicities; the empty product for 1 gives 1.
Before
\sum_{d\mid30}\mu(d)After
1-1-1-1+1+1+1-1=0
Conditions: none
Rule: calc · Uses: G1, S05
Leaf basis: calc
The complete eight-term sum gives the exact n>1 cross-check.
Before
12=2^2\cdot3
After
2^2\mid12\Rightarrow\mu(12)=0
Conditions: none
Rule: calc · Uses: G1, S02
Leaf basis: calc
The repeated factor 2 forces the square-factor branch, not (-1)^2.
Before
D(1)=\{1\},\quad\mu(1)=1After
\sum_{d\mid1}\mu(d)=1;\quad n\le0\text{ outside domain}Conditions: none
Rule: mko_definition · Uses: G1, S05, S07
Leaf basis: mko_definition
Retain the empty prime product and divisor sum 1 at n=1; zero and negatives are outside this definition.
No substeps in this guide.
S08 · premise_audit · G1, S05, S07 — mu(0) is not assigned zero; it is outside the classification domain.S07 · premise_audit · G1, S02 — Complete multiplicities are 2,1; distinct count 2 alone is insufficient.S06 · premise_audit · G1, S05 — This finite check certifies 30, not the general divisor-sum theorem.S05 · premise_audit · G1, S03, S04 — 6 has two primes giving +1 and 30 three giving -1; numerical parity is irrelevant.S04 · premise_audit · G1, S01 — The list includes both 1 and 30, not just prime or proper divisors.S03 · premise_audit · G1, S02 — Reordering factors changes neither the count nor multiplicities.S02 · premise_audit · G1, S01 — Check multiplicities before counting types; three distinct primes alone would not ensure squarefreeness.S01 · premise_audit · G1 — No remaining factor is unclassified, so multiplicities can be read.Any prime multiplicity at least 2 forces zero; distinct count then does not determine a sign.
Do not label a remainder prime before trial division reaches its square-root bound.
reject — 2^2 divides 12, forcing zero.reject — The empty prime product has k=0, so (-1)^0=1.reject — The domain is positive integers; zero is unclassified.mu(30)=-1, mu(12)=0, mu(1)=1; the sum over every divisor of 30 is zero.
2 declared checks for this guide; only the listed expressions are covered.
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