Linear systems in two variables and degenerate constraints
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This English edition is an AI candidate and does not yet have an OCME Atlas (GPT-6) Twin closure receipt.
A solution must satisfy two real linear constraints simultaneously. A nonzero determinant gives a unique solution; singular systems and zero rows require separate consistency checks.
mko-system-linear-equations · definition · v0.10.0
Mathematical statement
For real unknowns x and y, require a x+b y=c and d x+e y=f simultaneously. Define L(x,y)=(a x+b y−c,d x+e y−f) and z=(0,0), so the solution set satisfies L(x,y)=z. If D=ae−bd≠0, the unique solution is x=(ce−bf)/D and y=(af−cd)/D. If D=0, check consistency: there may be no solution or infinitely many solutions.
Representative formula (exact TeX)
L(x,y)=z
Assumptions
- All coefficients and right-side constants are real. Exercises use integer coefficients and exact rational candidates.
- Zero-coefficient rows are allowed as linear-system constraints: 0=0 imposes no restriction, while 0=c≠0 is inconsistent. Do not apply the unique-solution division when D=0.
Symbol scope
L— vector of the two linear-constraint residualsx— first real unknowny— second real unknownz— zero vector (0,0)
Intuition, definition, and misconceptions
To verify a rational candidate pair, first check nonzero denominators and substitute into both rows. Passing only one row does not make it a solution of the system.
Use the unique-solution formula only for D≠0. When D=0, coefficient rank and consistency of the augmented data determine no solution or infinitely many solutions; first check inconsistent zero rows. If all coefficients and right sides are zero, all of R² is the solution set; if all coefficients are zero and any right side is nonzero, there is no solution.
The exercises use exact two-by-two minors and zero-row cases to check consistency. D and both Cramer numerators being zero are insufficient by themselves to establish infinitely many solutions. Exact solutions are not guessed from intersections in a sketch.
Common errors include substituting into only one row, dividing when D=0, or overlooking an inconsistent row 0=nonzero.
Adopted derivation guide
Linear systems in two variables: the unique-solution formula, checking both rows, and consistency when D=0The original MKO is retained. The guide has its own append-only revision and verification boundaries, not a new Lean proof.
Prerequisites
- Linear equation in one variable — Distinguish nonzero coefficients, substitution checks, and degenerate constraints.
- Plane vectors in a fixed basis — Solutions and residuals use ordered pairs of components.
Verification boundary
Explicit two-row systems in two variables can be checked exactly; general rank theorems and formal correctness of a solver await Evidence.
not_formalized
This does not mean the content is false; it means no replayable computational or formal evidence is registered yet.
Next obligation
Bind solution sets of linear constraints, zero rows, the two-by-two determinant, rank and augmented consistency, and the solution formula for nonzero D.
Same-source structured data
This page and the interactive view use the same object and existing language edition; this adds no proof or human review.
Canonical MKO JSON · Plain Markdown