Zero-Target Kernels, Full Real Bases and Bounded-Search Boundaries

This batch has passed Schema, deduplication, source-snapshot, and independent-answer recomputation checks; it is still not marked as human-reviewed.

This question bank has corresponding bilingual step-by-step derivations. Source candidate and English ai_candidate states are retained. AI review, finite computation and Lean formal proof are labelled separately.

batch-20261014-advance-20261102-r02-linear-map-kernel-foundations · 2026-10-14 · 100 questions

This English edition is an AI candidate and does not yet have an OCME Atlas (GPT-6) Twin closure receipt.

1. Kernel Membership Has the Zero Vector as Its Target

Use this same exact integer matrix A=[[1, 1], [2, 2]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Selected vector=[-1, 1]. Give (vector,image,in_kernel?,kernel_target_is_zero_vector).

View answer and explanation

([-1, 1], [0, 0], Yes, kernel_target_is_zero_vector)

Compute A*x exactly and compare every component with zero. A vector mapping to a nonzero target belongs to that target fiber, not to the kernel. The exact result, retaining the requested order, is ([-1, 1], [0, 0], Yes, kernel_target_is_zero_vector).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-membership · candidate

2. Kernel Membership Has the Zero Vector as Its Target

Use this same exact integer matrix A=[[1, 2], [2, 4]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Selected vector=[-2, 1]. Give (vector,image,in_kernel?,kernel_target_is_zero_vector).

View answer and explanation

([-2, 1], [0, 0], Yes, kernel_target_is_zero_vector)

Compute A*x exactly and compare every component with zero. A vector mapping to a nonzero target belongs to that target fiber, not to the kernel. The exact result, retaining the requested order, is ([-2, 1], [0, 0], Yes, kernel_target_is_zero_vector).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-membership · candidate

3. Kernel Membership Has the Zero Vector as Its Target

Use this same exact integer matrix A=[[1, 3], [2, 6]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Selected vector=[-3, 1]. Give (vector,image,in_kernel?,kernel_target_is_zero_vector).

View answer and explanation

([-3, 1], [0, 0], Yes, kernel_target_is_zero_vector)

Compute A*x exactly and compare every component with zero. A vector mapping to a nonzero target belongs to that target fiber, not to the kernel. The exact result, retaining the requested order, is ([-3, 1], [0, 0], Yes, kernel_target_is_zero_vector).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-membership · candidate

4. Kernel Membership Has the Zero Vector as Its Target

Use this same exact integer matrix A=[[1, 4], [2, 8]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Selected vector=[-4, 1]. Give (vector,image,in_kernel?,kernel_target_is_zero_vector).

View answer and explanation

([-4, 1], [0, 0], Yes, kernel_target_is_zero_vector)

Compute A*x exactly and compare every component with zero. A vector mapping to a nonzero target belongs to that target fiber, not to the kernel. The exact result, retaining the requested order, is ([-4, 1], [0, 0], Yes, kernel_target_is_zero_vector).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-membership · candidate

5. Kernel Membership Has the Zero Vector as Its Target

Use this same exact integer matrix A=[[1, 5], [2, 10]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Selected vector=[-5, 1]. Give (vector,image,in_kernel?,kernel_target_is_zero_vector).

View answer and explanation

([-5, 1], [0, 0], Yes, kernel_target_is_zero_vector)

Compute A*x exactly and compare every component with zero. A vector mapping to a nonzero target belongs to that target fiber, not to the kernel. The exact result, retaining the requested order, is ([-5, 1], [0, 0], Yes, kernel_target_is_zero_vector).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-membership · candidate

6. Kernel Membership Has the Zero Vector as Its Target

Use this same exact integer matrix A=[[1, 6], [2, 12]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Selected vector=[-6, 1]. Give (vector,image,in_kernel?,kernel_target_is_zero_vector).

View answer and explanation

([-6, 1], [0, 0], Yes, kernel_target_is_zero_vector)

Compute A*x exactly and compare every component with zero. A vector mapping to a nonzero target belongs to that target fiber, not to the kernel. The exact result, retaining the requested order, is ([-6, 1], [0, 0], Yes, kernel_target_is_zero_vector).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-membership · candidate

7. Kernel Membership Has the Zero Vector as Its Target

Use this same exact integer matrix A=[[1, 7], [2, 14]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Selected vector=[-7, 1]. Give (vector,image,in_kernel?,kernel_target_is_zero_vector).

View answer and explanation

([-7, 1], [0, 0], Yes, kernel_target_is_zero_vector)

Compute A*x exactly and compare every component with zero. A vector mapping to a nonzero target belongs to that target fiber, not to the kernel. The exact result, retaining the requested order, is ([-7, 1], [0, 0], Yes, kernel_target_is_zero_vector).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-membership · candidate

8. Kernel Membership Has the Zero Vector as Its Target

Use this same exact integer matrix A=[[1, 8], [2, 16]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Selected vector=[-8, 1]. Give (vector,image,in_kernel?,kernel_target_is_zero_vector).

View answer and explanation

([-8, 1], [0, 0], Yes, kernel_target_is_zero_vector)

Compute A*x exactly and compare every component with zero. A vector mapping to a nonzero target belongs to that target fiber, not to the kernel. The exact result, retaining the requested order, is ([-8, 1], [0, 0], Yes, kernel_target_is_zero_vector).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-membership · candidate

9. Kernel Membership Has the Zero Vector as Its Target

Use this same exact integer matrix A=[[1, 9], [2, 18]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Selected vector=[-9, 1]. Give (vector,image,in_kernel?,kernel_target_is_zero_vector).

View answer and explanation

([-9, 1], [0, 0], Yes, kernel_target_is_zero_vector)

Compute A*x exactly and compare every component with zero. A vector mapping to a nonzero target belongs to that target fiber, not to the kernel. The exact result, retaining the requested order, is ([-9, 1], [0, 0], Yes, kernel_target_is_zero_vector).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-membership · candidate

10. Kernel Membership Has the Zero Vector as Its Target

Use this same exact integer matrix A=[[1, 10], [2, 20]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Selected vector=[-10, 1]. Give (vector,image,in_kernel?,kernel_target_is_zero_vector).

View answer and explanation

([-10, 1], [0, 0], Yes, kernel_target_is_zero_vector)

Compute A*x exactly and compare every component with zero. A vector mapping to a nonzero target belongs to that target fiber, not to the kernel. The exact result, retaining the requested order, is ([-10, 1], [0, 0], Yes, kernel_target_is_zero_vector).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-membership · candidate

11. Kernel Membership Has the Zero Vector as Its Target

Use this same exact integer matrix A=[[1, 11], [2, 22]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Selected vector=[-11, 1]. Give (vector,image,in_kernel?,kernel_target_is_zero_vector).

View answer and explanation

([-11, 1], [0, 0], Yes, kernel_target_is_zero_vector)

Compute A*x exactly and compare every component with zero. A vector mapping to a nonzero target belongs to that target fiber, not to the kernel. The exact result, retaining the requested order, is ([-11, 1], [0, 0], Yes, kernel_target_is_zero_vector).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-membership · candidate

12. Kernel Membership Has the Zero Vector as Its Target

Use this same exact integer matrix A=[[1, 12], [2, 24]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Selected vector=[-12, 1]. Give (vector,image,in_kernel?,kernel_target_is_zero_vector).

View answer and explanation

([-12, 1], [0, 0], Yes, kernel_target_is_zero_vector)

Compute A*x exactly and compare every component with zero. A vector mapping to a nonzero target belongs to that target fiber, not to the kernel. The exact result, retaining the requested order, is ([-12, 1], [0, 0], Yes, kernel_target_is_zero_vector).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-membership · candidate

13. Kernel Membership Has the Zero Vector as Its Target

Use this same exact integer matrix A=[[1, 13], [2, 26]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Selected vector=[-13, 1]. Give (vector,image,in_kernel?,kernel_target_is_zero_vector).

View answer and explanation

([-13, 1], [0, 0], Yes, kernel_target_is_zero_vector)

Compute A*x exactly and compare every component with zero. A vector mapping to a nonzero target belongs to that target fiber, not to the kernel. The exact result, retaining the requested order, is ([-13, 1], [0, 0], Yes, kernel_target_is_zero_vector).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-membership · candidate

14. Kernel Membership Has the Zero Vector as Its Target

Use this same exact integer matrix A=[[1, 14], [2, 28]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Selected vector=[-14, 1]. Give (vector,image,in_kernel?,kernel_target_is_zero_vector).

View answer and explanation

([-14, 1], [0, 0], Yes, kernel_target_is_zero_vector)

Compute A*x exactly and compare every component with zero. A vector mapping to a nonzero target belongs to that target fiber, not to the kernel. The exact result, retaining the requested order, is ([-14, 1], [0, 0], Yes, kernel_target_is_zero_vector).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-membership · candidate

15. Kernel Membership Has the Zero Vector as Its Target

Use this same exact integer matrix A=[[1, 15], [2, 30]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Selected vector=[-15, 1]. Give (vector,image,in_kernel?,kernel_target_is_zero_vector).

View answer and explanation

([-15, 1], [0, 0], Yes, kernel_target_is_zero_vector)

Compute A*x exactly and compare every component with zero. A vector mapping to a nonzero target belongs to that target fiber, not to the kernel. The exact result, retaining the requested order, is ([-15, 1], [0, 0], Yes, kernel_target_is_zero_vector).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-membership · candidate

16. Kernel Membership Has the Zero Vector as Its Target

Use this same exact integer matrix A=[[1, 16], [2, 32]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Selected vector=[-16, 1]. Give (vector,image,in_kernel?,kernel_target_is_zero_vector).

View answer and explanation

([-16, 1], [0, 0], Yes, kernel_target_is_zero_vector)

Compute A*x exactly and compare every component with zero. A vector mapping to a nonzero target belongs to that target fiber, not to the kernel. The exact result, retaining the requested order, is ([-16, 1], [0, 0], Yes, kernel_target_is_zero_vector).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-membership · candidate

17. Kernel Membership Has the Zero Vector as Its Target

Use this same exact integer matrix A=[[1, 17], [2, 34]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Selected vector=[-17, 1]. Give (vector,image,in_kernel?,kernel_target_is_zero_vector).

View answer and explanation

([-17, 1], [0, 0], Yes, kernel_target_is_zero_vector)

Compute A*x exactly and compare every component with zero. A vector mapping to a nonzero target belongs to that target fiber, not to the kernel. The exact result, retaining the requested order, is ([-17, 1], [0, 0], Yes, kernel_target_is_zero_vector).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-membership · candidate

18. Kernel Membership Has the Zero Vector as Its Target

Use this same exact integer matrix A=[[1, 18], [2, 36]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Selected vector=[-18, 1]. Give (vector,image,in_kernel?,kernel_target_is_zero_vector).

View answer and explanation

([-18, 1], [0, 0], Yes, kernel_target_is_zero_vector)

Compute A*x exactly and compare every component with zero. A vector mapping to a nonzero target belongs to that target fiber, not to the kernel. The exact result, retaining the requested order, is ([-18, 1], [0, 0], Yes, kernel_target_is_zero_vector).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-membership · candidate

19. Kernel Membership Has the Zero Vector as Its Target

Use this same exact integer matrix A=[[1, 19], [2, 38]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Selected vector=[-19, 1]. Give (vector,image,in_kernel?,kernel_target_is_zero_vector).

View answer and explanation

([-19, 1], [0, 0], Yes, kernel_target_is_zero_vector)

Compute A*x exactly and compare every component with zero. A vector mapping to a nonzero target belongs to that target fiber, not to the kernel. The exact result, retaining the requested order, is ([-19, 1], [0, 0], Yes, kernel_target_is_zero_vector).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-membership · candidate

20. Kernel Membership Has the Zero Vector as Its Target

Use this same exact integer matrix A=[[1, 20], [2, 40]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Selected vector=[-20, 1]. Give (vector,image,in_kernel?,kernel_target_is_zero_vector).

View answer and explanation

([-20, 1], [0, 0], Yes, kernel_target_is_zero_vector)

Compute A*x exactly and compare every component with zero. A vector mapping to a nonzero target belongs to that target fiber, not to the kernel. The exact result, retaining the requested order, is ([-20, 1], [0, 0], Yes, kernel_target_is_zero_vector).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-membership · candidate

21. Kernel Membership Has the Zero Vector as Its Target

Use this same exact integer matrix A=[[1, 21], [2, 42]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Selected vector=[-21, 1]. Give (vector,image,in_kernel?,kernel_target_is_zero_vector).

View answer and explanation

([-21, 1], [0, 0], Yes, kernel_target_is_zero_vector)

Compute A*x exactly and compare every component with zero. A vector mapping to a nonzero target belongs to that target fiber, not to the kernel. The exact result, retaining the requested order, is ([-21, 1], [0, 0], Yes, kernel_target_is_zero_vector).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-membership · candidate

22. Kernel Membership Has the Zero Vector as Its Target

Use this same exact integer matrix A=[[1, 22], [2, 44]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Selected vector=[-22, 1]. Give (vector,image,in_kernel?,kernel_target_is_zero_vector).

View answer and explanation

([-22, 1], [0, 0], Yes, kernel_target_is_zero_vector)

Compute A*x exactly and compare every component with zero. A vector mapping to a nonzero target belongs to that target fiber, not to the kernel. The exact result, retaining the requested order, is ([-22, 1], [0, 0], Yes, kernel_target_is_zero_vector).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-membership · candidate

23. Kernel Membership Has the Zero Vector as Its Target

Use this same exact integer matrix A=[[1, 23], [2, 46]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Selected vector=[-23, 1]. Give (vector,image,in_kernel?,kernel_target_is_zero_vector).

View answer and explanation

([-23, 1], [0, 0], Yes, kernel_target_is_zero_vector)

Compute A*x exactly and compare every component with zero. A vector mapping to a nonzero target belongs to that target fiber, not to the kernel. The exact result, retaining the requested order, is ([-23, 1], [0, 0], Yes, kernel_target_is_zero_vector).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-membership · candidate

24. Kernel Membership Has the Zero Vector as Its Target

Use this same exact integer matrix A=[[1, 24], [2, 48]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Selected vector=[-24, 1]. Give (vector,image,in_kernel?,kernel_target_is_zero_vector).

View answer and explanation

([-24, 1], [0, 0], Yes, kernel_target_is_zero_vector)

Compute A*x exactly and compare every component with zero. A vector mapping to a nonzero target belongs to that target fiber, not to the kernel. The exact result, retaining the requested order, is ([-24, 1], [0, 0], Yes, kernel_target_is_zero_vector).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-membership · candidate

25. Kernel Membership Has the Zero Vector as Its Target

Use this same exact integer matrix A=[[1, 25], [2, 50]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Selected vector=[-25, 1]. Give (vector,image,in_kernel?,kernel_target_is_zero_vector).

View answer and explanation

([-25, 1], [0, 0], Yes, kernel_target_is_zero_vector)

Compute A*x exactly and compare every component with zero. A vector mapping to a nonzero target belongs to that target fiber, not to the kernel. The exact result, retaining the requested order, is ([-25, 1], [0, 0], Yes, kernel_target_is_zero_vector).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-membership · candidate

26. Give a Basis of the Entire Real Kernel, Not a Finite Search Result

Use this same exact integer matrix A=[[1, 1], [2, 2]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (matrix,rank,kernel_basis,nullity,symbolic_full_real_kernel).

View answer and explanation

([[1, 1], [2, 2]], 1, [[1, -1]], 1, symbolic_full_real_kernel)

Solve the homogeneous equations over the reals using the rank cases and the stated canonical basis convention. The displayed basis represents all real linear combinations, not merely its integer multiples. The exact result, retaining the requested order, is ([[1, 1], [2, 2]], 1, [[1, -1]], 1, symbolic_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-basis · candidate

27. Give a Basis of the Entire Real Kernel, Not a Finite Search Result

Use this same exact integer matrix A=[[1, 2], [2, 4]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (matrix,rank,kernel_basis,nullity,symbolic_full_real_kernel).

View answer and explanation

([[1, 2], [2, 4]], 1, [[2, -1]], 1, symbolic_full_real_kernel)

Solve the homogeneous equations over the reals using the rank cases and the stated canonical basis convention. The displayed basis represents all real linear combinations, not merely its integer multiples. The exact result, retaining the requested order, is ([[1, 2], [2, 4]], 1, [[2, -1]], 1, symbolic_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-basis · candidate

28. Give a Basis of the Entire Real Kernel, Not a Finite Search Result

Use this same exact integer matrix A=[[1, 3], [2, 6]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (matrix,rank,kernel_basis,nullity,symbolic_full_real_kernel).

View answer and explanation

([[1, 3], [2, 6]], 1, [[3, -1]], 1, symbolic_full_real_kernel)

Solve the homogeneous equations over the reals using the rank cases and the stated canonical basis convention. The displayed basis represents all real linear combinations, not merely its integer multiples. The exact result, retaining the requested order, is ([[1, 3], [2, 6]], 1, [[3, -1]], 1, symbolic_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-basis · candidate

29. Give a Basis of the Entire Real Kernel, Not a Finite Search Result

Use this same exact integer matrix A=[[1, 4], [2, 8]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (matrix,rank,kernel_basis,nullity,symbolic_full_real_kernel).

View answer and explanation

([[1, 4], [2, 8]], 1, [[4, -1]], 1, symbolic_full_real_kernel)

Solve the homogeneous equations over the reals using the rank cases and the stated canonical basis convention. The displayed basis represents all real linear combinations, not merely its integer multiples. The exact result, retaining the requested order, is ([[1, 4], [2, 8]], 1, [[4, -1]], 1, symbolic_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-basis · candidate

30. Give a Basis of the Entire Real Kernel, Not a Finite Search Result

Use this same exact integer matrix A=[[1, 5], [2, 10]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (matrix,rank,kernel_basis,nullity,symbolic_full_real_kernel).

View answer and explanation

([[1, 5], [2, 10]], 1, [[5, -1]], 1, symbolic_full_real_kernel)

Solve the homogeneous equations over the reals using the rank cases and the stated canonical basis convention. The displayed basis represents all real linear combinations, not merely its integer multiples. The exact result, retaining the requested order, is ([[1, 5], [2, 10]], 1, [[5, -1]], 1, symbolic_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-basis · candidate

31. Give a Basis of the Entire Real Kernel, Not a Finite Search Result

Use this same exact integer matrix A=[[1, 6], [2, 12]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (matrix,rank,kernel_basis,nullity,symbolic_full_real_kernel).

View answer and explanation

([[1, 6], [2, 12]], 1, [[6, -1]], 1, symbolic_full_real_kernel)

Solve the homogeneous equations over the reals using the rank cases and the stated canonical basis convention. The displayed basis represents all real linear combinations, not merely its integer multiples. The exact result, retaining the requested order, is ([[1, 6], [2, 12]], 1, [[6, -1]], 1, symbolic_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-basis · candidate

32. Give a Basis of the Entire Real Kernel, Not a Finite Search Result

Use this same exact integer matrix A=[[1, 7], [2, 14]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (matrix,rank,kernel_basis,nullity,symbolic_full_real_kernel).

View answer and explanation

([[1, 7], [2, 14]], 1, [[7, -1]], 1, symbolic_full_real_kernel)

Solve the homogeneous equations over the reals using the rank cases and the stated canonical basis convention. The displayed basis represents all real linear combinations, not merely its integer multiples. The exact result, retaining the requested order, is ([[1, 7], [2, 14]], 1, [[7, -1]], 1, symbolic_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-basis · candidate

33. Give a Basis of the Entire Real Kernel, Not a Finite Search Result

Use this same exact integer matrix A=[[1, 8], [2, 16]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (matrix,rank,kernel_basis,nullity,symbolic_full_real_kernel).

View answer and explanation

([[1, 8], [2, 16]], 1, [[8, -1]], 1, symbolic_full_real_kernel)

Solve the homogeneous equations over the reals using the rank cases and the stated canonical basis convention. The displayed basis represents all real linear combinations, not merely its integer multiples. The exact result, retaining the requested order, is ([[1, 8], [2, 16]], 1, [[8, -1]], 1, symbolic_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-basis · candidate

34. Give a Basis of the Entire Real Kernel, Not a Finite Search Result

Use this same exact integer matrix A=[[1, 9], [2, 18]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (matrix,rank,kernel_basis,nullity,symbolic_full_real_kernel).

View answer and explanation

([[1, 9], [2, 18]], 1, [[9, -1]], 1, symbolic_full_real_kernel)

Solve the homogeneous equations over the reals using the rank cases and the stated canonical basis convention. The displayed basis represents all real linear combinations, not merely its integer multiples. The exact result, retaining the requested order, is ([[1, 9], [2, 18]], 1, [[9, -1]], 1, symbolic_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-basis · candidate

35. Give a Basis of the Entire Real Kernel, Not a Finite Search Result

Use this same exact integer matrix A=[[1, 10], [2, 20]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (matrix,rank,kernel_basis,nullity,symbolic_full_real_kernel).

View answer and explanation

([[1, 10], [2, 20]], 1, [[10, -1]], 1, symbolic_full_real_kernel)

Solve the homogeneous equations over the reals using the rank cases and the stated canonical basis convention. The displayed basis represents all real linear combinations, not merely its integer multiples. The exact result, retaining the requested order, is ([[1, 10], [2, 20]], 1, [[10, -1]], 1, symbolic_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-basis · candidate

36. Give a Basis of the Entire Real Kernel, Not a Finite Search Result

Use this same exact integer matrix A=[[1, 11], [2, 22]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (matrix,rank,kernel_basis,nullity,symbolic_full_real_kernel).

View answer and explanation

([[1, 11], [2, 22]], 1, [[11, -1]], 1, symbolic_full_real_kernel)

Solve the homogeneous equations over the reals using the rank cases and the stated canonical basis convention. The displayed basis represents all real linear combinations, not merely its integer multiples. The exact result, retaining the requested order, is ([[1, 11], [2, 22]], 1, [[11, -1]], 1, symbolic_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-basis · candidate

37. Give a Basis of the Entire Real Kernel, Not a Finite Search Result

Use this same exact integer matrix A=[[1, 12], [2, 24]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (matrix,rank,kernel_basis,nullity,symbolic_full_real_kernel).

View answer and explanation

([[1, 12], [2, 24]], 1, [[12, -1]], 1, symbolic_full_real_kernel)

Solve the homogeneous equations over the reals using the rank cases and the stated canonical basis convention. The displayed basis represents all real linear combinations, not merely its integer multiples. The exact result, retaining the requested order, is ([[1, 12], [2, 24]], 1, [[12, -1]], 1, symbolic_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-basis · candidate

38. Give a Basis of the Entire Real Kernel, Not a Finite Search Result

Use this same exact integer matrix A=[[1, 13], [2, 26]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (matrix,rank,kernel_basis,nullity,symbolic_full_real_kernel).

View answer and explanation

([[1, 13], [2, 26]], 1, [[13, -1]], 1, symbolic_full_real_kernel)

Solve the homogeneous equations over the reals using the rank cases and the stated canonical basis convention. The displayed basis represents all real linear combinations, not merely its integer multiples. The exact result, retaining the requested order, is ([[1, 13], [2, 26]], 1, [[13, -1]], 1, symbolic_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-basis · candidate

39. Give a Basis of the Entire Real Kernel, Not a Finite Search Result

Use this same exact integer matrix A=[[1, 14], [2, 28]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (matrix,rank,kernel_basis,nullity,symbolic_full_real_kernel).

View answer and explanation

([[1, 14], [2, 28]], 1, [[14, -1]], 1, symbolic_full_real_kernel)

Solve the homogeneous equations over the reals using the rank cases and the stated canonical basis convention. The displayed basis represents all real linear combinations, not merely its integer multiples. The exact result, retaining the requested order, is ([[1, 14], [2, 28]], 1, [[14, -1]], 1, symbolic_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-basis · candidate

40. Give a Basis of the Entire Real Kernel, Not a Finite Search Result

Use this same exact integer matrix A=[[1, 15], [2, 30]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (matrix,rank,kernel_basis,nullity,symbolic_full_real_kernel).

View answer and explanation

([[1, 15], [2, 30]], 1, [[15, -1]], 1, symbolic_full_real_kernel)

Solve the homogeneous equations over the reals using the rank cases and the stated canonical basis convention. The displayed basis represents all real linear combinations, not merely its integer multiples. The exact result, retaining the requested order, is ([[1, 15], [2, 30]], 1, [[15, -1]], 1, symbolic_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-basis · candidate

41. Give a Basis of the Entire Real Kernel, Not a Finite Search Result

Use this same exact integer matrix A=[[1, 16], [2, 32]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (matrix,rank,kernel_basis,nullity,symbolic_full_real_kernel).

View answer and explanation

([[1, 16], [2, 32]], 1, [[16, -1]], 1, symbolic_full_real_kernel)

Solve the homogeneous equations over the reals using the rank cases and the stated canonical basis convention. The displayed basis represents all real linear combinations, not merely its integer multiples. The exact result, retaining the requested order, is ([[1, 16], [2, 32]], 1, [[16, -1]], 1, symbolic_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-basis · candidate

42. Give a Basis of the Entire Real Kernel, Not a Finite Search Result

Use this same exact integer matrix A=[[1, 17], [2, 34]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (matrix,rank,kernel_basis,nullity,symbolic_full_real_kernel).

View answer and explanation

([[1, 17], [2, 34]], 1, [[17, -1]], 1, symbolic_full_real_kernel)

Solve the homogeneous equations over the reals using the rank cases and the stated canonical basis convention. The displayed basis represents all real linear combinations, not merely its integer multiples. The exact result, retaining the requested order, is ([[1, 17], [2, 34]], 1, [[17, -1]], 1, symbolic_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-basis · candidate

43. Give a Basis of the Entire Real Kernel, Not a Finite Search Result

Use this same exact integer matrix A=[[1, 18], [2, 36]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (matrix,rank,kernel_basis,nullity,symbolic_full_real_kernel).

View answer and explanation

([[1, 18], [2, 36]], 1, [[18, -1]], 1, symbolic_full_real_kernel)

Solve the homogeneous equations over the reals using the rank cases and the stated canonical basis convention. The displayed basis represents all real linear combinations, not merely its integer multiples. The exact result, retaining the requested order, is ([[1, 18], [2, 36]], 1, [[18, -1]], 1, symbolic_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-basis · candidate

44. Give a Basis of the Entire Real Kernel, Not a Finite Search Result

Use this same exact integer matrix A=[[1, 19], [2, 38]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (matrix,rank,kernel_basis,nullity,symbolic_full_real_kernel).

View answer and explanation

([[1, 19], [2, 38]], 1, [[19, -1]], 1, symbolic_full_real_kernel)

Solve the homogeneous equations over the reals using the rank cases and the stated canonical basis convention. The displayed basis represents all real linear combinations, not merely its integer multiples. The exact result, retaining the requested order, is ([[1, 19], [2, 38]], 1, [[19, -1]], 1, symbolic_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-basis · candidate

45. Give a Basis of the Entire Real Kernel, Not a Finite Search Result

Use this same exact integer matrix A=[[1, 20], [2, 40]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (matrix,rank,kernel_basis,nullity,symbolic_full_real_kernel).

View answer and explanation

([[1, 20], [2, 40]], 1, [[20, -1]], 1, symbolic_full_real_kernel)

Solve the homogeneous equations over the reals using the rank cases and the stated canonical basis convention. The displayed basis represents all real linear combinations, not merely its integer multiples. The exact result, retaining the requested order, is ([[1, 20], [2, 40]], 1, [[20, -1]], 1, symbolic_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-basis · candidate

46. Give a Basis of the Entire Real Kernel, Not a Finite Search Result

Use this same exact integer matrix A=[[1, 21], [2, 42]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (matrix,rank,kernel_basis,nullity,symbolic_full_real_kernel).

View answer and explanation

([[1, 21], [2, 42]], 1, [[21, -1]], 1, symbolic_full_real_kernel)

Solve the homogeneous equations over the reals using the rank cases and the stated canonical basis convention. The displayed basis represents all real linear combinations, not merely its integer multiples. The exact result, retaining the requested order, is ([[1, 21], [2, 42]], 1, [[21, -1]], 1, symbolic_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-basis · candidate

47. Give a Basis of the Entire Real Kernel, Not a Finite Search Result

Use this same exact integer matrix A=[[1, 22], [2, 44]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (matrix,rank,kernel_basis,nullity,symbolic_full_real_kernel).

View answer and explanation

([[1, 22], [2, 44]], 1, [[22, -1]], 1, symbolic_full_real_kernel)

Solve the homogeneous equations over the reals using the rank cases and the stated canonical basis convention. The displayed basis represents all real linear combinations, not merely its integer multiples. The exact result, retaining the requested order, is ([[1, 22], [2, 44]], 1, [[22, -1]], 1, symbolic_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-basis · candidate

48. Give a Basis of the Entire Real Kernel, Not a Finite Search Result

Use this same exact integer matrix A=[[1, 23], [2, 46]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (matrix,rank,kernel_basis,nullity,symbolic_full_real_kernel).

View answer and explanation

([[1, 23], [2, 46]], 1, [[23, -1]], 1, symbolic_full_real_kernel)

Solve the homogeneous equations over the reals using the rank cases and the stated canonical basis convention. The displayed basis represents all real linear combinations, not merely its integer multiples. The exact result, retaining the requested order, is ([[1, 23], [2, 46]], 1, [[23, -1]], 1, symbolic_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-basis · candidate

49. Give a Basis of the Entire Real Kernel, Not a Finite Search Result

Use this same exact integer matrix A=[[1, 24], [2, 48]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (matrix,rank,kernel_basis,nullity,symbolic_full_real_kernel).

View answer and explanation

([[1, 24], [2, 48]], 1, [[24, -1]], 1, symbolic_full_real_kernel)

Solve the homogeneous equations over the reals using the rank cases and the stated canonical basis convention. The displayed basis represents all real linear combinations, not merely its integer multiples. The exact result, retaining the requested order, is ([[1, 24], [2, 48]], 1, [[24, -1]], 1, symbolic_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-basis · candidate

50. Give a Basis of the Entire Real Kernel, Not a Finite Search Result

Use this same exact integer matrix A=[[1, 25], [2, 50]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (matrix,rank,kernel_basis,nullity,symbolic_full_real_kernel).

View answer and explanation

([[1, 25], [2, 50]], 1, [[25, -1]], 1, symbolic_full_real_kernel)

Solve the homogeneous equations over the reals using the rank cases and the stated canonical basis convention. The displayed basis represents all real linear combinations, not merely its integer multiples. The exact result, retaining the requested order, is ([[1, 25], [2, 50]], 1, [[25, -1]], 1, symbolic_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-basis · candidate

51. Nullity Counts a Full Kernel Basis

Use this same exact integer matrix A=[[1, 1], [2, 2]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (rank,nullity,kernel_basis).

View answer and explanation

(1, 1, [[1, -1]])

Use nullity=2−rank for this two-dimensional source and retain the full symbolic real-kernel basis. The number of sampled grid points is not nullity. The exact result, retaining the requested order, is (1, 1, [[1, -1]]).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-nullity · candidate

52. Nullity Counts a Full Kernel Basis

Use this same exact integer matrix A=[[1, 2], [2, 4]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (rank,nullity,kernel_basis).

View answer and explanation

(1, 1, [[2, -1]])

Use nullity=2−rank for this two-dimensional source and retain the full symbolic real-kernel basis. The number of sampled grid points is not nullity. The exact result, retaining the requested order, is (1, 1, [[2, -1]]).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-nullity · candidate

53. Nullity Counts a Full Kernel Basis

Use this same exact integer matrix A=[[1, 3], [2, 6]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (rank,nullity,kernel_basis).

View answer and explanation

(1, 1, [[3, -1]])

Use nullity=2−rank for this two-dimensional source and retain the full symbolic real-kernel basis. The number of sampled grid points is not nullity. The exact result, retaining the requested order, is (1, 1, [[3, -1]]).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-nullity · candidate

54. Nullity Counts a Full Kernel Basis

Use this same exact integer matrix A=[[1, 4], [2, 8]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (rank,nullity,kernel_basis).

View answer and explanation

(1, 1, [[4, -1]])

Use nullity=2−rank for this two-dimensional source and retain the full symbolic real-kernel basis. The number of sampled grid points is not nullity. The exact result, retaining the requested order, is (1, 1, [[4, -1]]).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-nullity · candidate

55. Nullity Counts a Full Kernel Basis

Use this same exact integer matrix A=[[1, 5], [2, 10]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (rank,nullity,kernel_basis).

View answer and explanation

(1, 1, [[5, -1]])

Use nullity=2−rank for this two-dimensional source and retain the full symbolic real-kernel basis. The number of sampled grid points is not nullity. The exact result, retaining the requested order, is (1, 1, [[5, -1]]).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-nullity · candidate

56. Nullity Counts a Full Kernel Basis

Use this same exact integer matrix A=[[1, 6], [2, 12]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (rank,nullity,kernel_basis).

View answer and explanation

(1, 1, [[6, -1]])

Use nullity=2−rank for this two-dimensional source and retain the full symbolic real-kernel basis. The number of sampled grid points is not nullity. The exact result, retaining the requested order, is (1, 1, [[6, -1]]).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-nullity · candidate

57. Nullity Counts a Full Kernel Basis

Use this same exact integer matrix A=[[1, 7], [2, 14]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (rank,nullity,kernel_basis).

View answer and explanation

(1, 1, [[7, -1]])

Use nullity=2−rank for this two-dimensional source and retain the full symbolic real-kernel basis. The number of sampled grid points is not nullity. The exact result, retaining the requested order, is (1, 1, [[7, -1]]).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-nullity · candidate

58. Nullity Counts a Full Kernel Basis

Use this same exact integer matrix A=[[1, 8], [2, 16]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (rank,nullity,kernel_basis).

View answer and explanation

(1, 1, [[8, -1]])

Use nullity=2−rank for this two-dimensional source and retain the full symbolic real-kernel basis. The number of sampled grid points is not nullity. The exact result, retaining the requested order, is (1, 1, [[8, -1]]).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-nullity · candidate

59. Nullity Counts a Full Kernel Basis

Use this same exact integer matrix A=[[1, 9], [2, 18]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (rank,nullity,kernel_basis).

View answer and explanation

(1, 1, [[9, -1]])

Use nullity=2−rank for this two-dimensional source and retain the full symbolic real-kernel basis. The number of sampled grid points is not nullity. The exact result, retaining the requested order, is (1, 1, [[9, -1]]).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-nullity · candidate

60. Nullity Counts a Full Kernel Basis

Use this same exact integer matrix A=[[1, 10], [2, 20]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (rank,nullity,kernel_basis).

View answer and explanation

(1, 1, [[10, -1]])

Use nullity=2−rank for this two-dimensional source and retain the full symbolic real-kernel basis. The number of sampled grid points is not nullity. The exact result, retaining the requested order, is (1, 1, [[10, -1]]).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-nullity · candidate

61. Nullity Counts a Full Kernel Basis

Use this same exact integer matrix A=[[1, 11], [2, 22]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (rank,nullity,kernel_basis).

View answer and explanation

(1, 1, [[11, -1]])

Use nullity=2−rank for this two-dimensional source and retain the full symbolic real-kernel basis. The number of sampled grid points is not nullity. The exact result, retaining the requested order, is (1, 1, [[11, -1]]).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-nullity · candidate

62. Nullity Counts a Full Kernel Basis

Use this same exact integer matrix A=[[1, 12], [2, 24]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (rank,nullity,kernel_basis).

View answer and explanation

(1, 1, [[12, -1]])

Use nullity=2−rank for this two-dimensional source and retain the full symbolic real-kernel basis. The number of sampled grid points is not nullity. The exact result, retaining the requested order, is (1, 1, [[12, -1]]).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-nullity · candidate

63. Nullity Counts a Full Kernel Basis

Use this same exact integer matrix A=[[1, 13], [2, 26]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (rank,nullity,kernel_basis).

View answer and explanation

(1, 1, [[13, -1]])

Use nullity=2−rank for this two-dimensional source and retain the full symbolic real-kernel basis. The number of sampled grid points is not nullity. The exact result, retaining the requested order, is (1, 1, [[13, -1]]).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-nullity · candidate

64. Nullity Counts a Full Kernel Basis

Use this same exact integer matrix A=[[1, 14], [2, 28]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (rank,nullity,kernel_basis).

View answer and explanation

(1, 1, [[14, -1]])

Use nullity=2−rank for this two-dimensional source and retain the full symbolic real-kernel basis. The number of sampled grid points is not nullity. The exact result, retaining the requested order, is (1, 1, [[14, -1]]).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-nullity · candidate

65. Nullity Counts a Full Kernel Basis

Use this same exact integer matrix A=[[1, 15], [2, 30]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (rank,nullity,kernel_basis).

View answer and explanation

(1, 1, [[15, -1]])

Use nullity=2−rank for this two-dimensional source and retain the full symbolic real-kernel basis. The number of sampled grid points is not nullity. The exact result, retaining the requested order, is (1, 1, [[15, -1]]).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-nullity · candidate

66. Nullity Counts a Full Kernel Basis

Use this same exact integer matrix A=[[1, 16], [2, 32]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (rank,nullity,kernel_basis).

View answer and explanation

(1, 1, [[16, -1]])

Use nullity=2−rank for this two-dimensional source and retain the full symbolic real-kernel basis. The number of sampled grid points is not nullity. The exact result, retaining the requested order, is (1, 1, [[16, -1]]).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-nullity · candidate

67. Nullity Counts a Full Kernel Basis

Use this same exact integer matrix A=[[1, 17], [2, 34]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (rank,nullity,kernel_basis).

View answer and explanation

(1, 1, [[17, -1]])

Use nullity=2−rank for this two-dimensional source and retain the full symbolic real-kernel basis. The number of sampled grid points is not nullity. The exact result, retaining the requested order, is (1, 1, [[17, -1]]).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-nullity · candidate

68. Nullity Counts a Full Kernel Basis

Use this same exact integer matrix A=[[1, 18], [2, 36]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (rank,nullity,kernel_basis).

View answer and explanation

(1, 1, [[18, -1]])

Use nullity=2−rank for this two-dimensional source and retain the full symbolic real-kernel basis. The number of sampled grid points is not nullity. The exact result, retaining the requested order, is (1, 1, [[18, -1]]).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-nullity · candidate

69. Nullity Counts a Full Kernel Basis

Use this same exact integer matrix A=[[1, 19], [2, 38]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (rank,nullity,kernel_basis).

View answer and explanation

(1, 1, [[19, -1]])

Use nullity=2−rank for this two-dimensional source and retain the full symbolic real-kernel basis. The number of sampled grid points is not nullity. The exact result, retaining the requested order, is (1, 1, [[19, -1]]).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-nullity · candidate

70. Nullity Counts a Full Kernel Basis

Use this same exact integer matrix A=[[1, 20], [2, 40]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (rank,nullity,kernel_basis).

View answer and explanation

(1, 1, [[20, -1]])

Use nullity=2−rank for this two-dimensional source and retain the full symbolic real-kernel basis. The number of sampled grid points is not nullity. The exact result, retaining the requested order, is (1, 1, [[20, -1]]).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-nullity · candidate

71. Nullity Counts a Full Kernel Basis

Use this same exact integer matrix A=[[1, 21], [2, 42]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (rank,nullity,kernel_basis).

View answer and explanation

(1, 1, [[21, -1]])

Use nullity=2−rank for this two-dimensional source and retain the full symbolic real-kernel basis. The number of sampled grid points is not nullity. The exact result, retaining the requested order, is (1, 1, [[21, -1]]).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-nullity · candidate

72. Nullity Counts a Full Kernel Basis

Use this same exact integer matrix A=[[1, 22], [2, 44]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (rank,nullity,kernel_basis).

View answer and explanation

(1, 1, [[22, -1]])

Use nullity=2−rank for this two-dimensional source and retain the full symbolic real-kernel basis. The number of sampled grid points is not nullity. The exact result, retaining the requested order, is (1, 1, [[22, -1]]).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-nullity · candidate

73. Nullity Counts a Full Kernel Basis

Use this same exact integer matrix A=[[1, 23], [2, 46]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (rank,nullity,kernel_basis).

View answer and explanation

(1, 1, [[23, -1]])

Use nullity=2−rank for this two-dimensional source and retain the full symbolic real-kernel basis. The number of sampled grid points is not nullity. The exact result, retaining the requested order, is (1, 1, [[23, -1]]).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-nullity · candidate

74. Nullity Counts a Full Kernel Basis

Use this same exact integer matrix A=[[1, 24], [2, 48]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (rank,nullity,kernel_basis).

View answer and explanation

(1, 1, [[24, -1]])

Use nullity=2−rank for this two-dimensional source and retain the full symbolic real-kernel basis. The number of sampled grid points is not nullity. The exact result, retaining the requested order, is (1, 1, [[24, -1]]).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-nullity · candidate

75. Nullity Counts a Full Kernel Basis

Use this same exact integer matrix A=[[1, 25], [2, 50]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Give (rank,nullity,kernel_basis).

View answer and explanation

(1, 1, [[25, -1]])

Use nullity=2−rank for this two-dimensional source and retain the full symbolic real-kernel basis. The number of sampled grid points is not nullity. The exact result, retaining the requested order, is (1, 1, [[25, -1]]).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-nullity · candidate

76. A Bounded Integer Box Is Not the Full Real Kernel

Use this same exact integer matrix A=[[1, 1], [2, 2]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Nonnegative integer bound=1. Search x,y in [−bound,bound]∩Z, with x outer increasing and y inner increasing. Give (bound,integer_kernel_points,global_kernel_basis,complete?,bounded_integer_search_not_full_real_kernel).

View answer and explanation

(1, [[-1, 1], [0, 0], [1, -1]], [[1, -1]], No, bounded_integer_search_not_full_real_kernel)

List exactly the zero-target points in this box and retain the separately derived global basis. The No complete flag concerns the bounded enumeration as a general full-real certificate, not denial of the symbolic basis already supplied. The exact result, retaining the requested order, is (1, [[-1, 1], [0, 0], [1, -1]], [[1, -1]], No, bounded_integer_search_not_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-bounded-search-boundary · candidate

77. A Bounded Integer Box Is Not the Full Real Kernel

Use this same exact integer matrix A=[[1, 2], [2, 4]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Nonnegative integer bound=2. Search x,y in [−bound,bound]∩Z, with x outer increasing and y inner increasing. Give (bound,integer_kernel_points,global_kernel_basis,complete?,bounded_integer_search_not_full_real_kernel).

View answer and explanation

(2, [[-2, 1], [0, 0], [2, -1]], [[2, -1]], No, bounded_integer_search_not_full_real_kernel)

List exactly the zero-target points in this box and retain the separately derived global basis. The No complete flag concerns the bounded enumeration as a general full-real certificate, not denial of the symbolic basis already supplied. The exact result, retaining the requested order, is (2, [[-2, 1], [0, 0], [2, -1]], [[2, -1]], No, bounded_integer_search_not_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-bounded-search-boundary · candidate

78. A Bounded Integer Box Is Not the Full Real Kernel

Use this same exact integer matrix A=[[1, 3], [2, 6]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Nonnegative integer bound=3. Search x,y in [−bound,bound]∩Z, with x outer increasing and y inner increasing. Give (bound,integer_kernel_points,global_kernel_basis,complete?,bounded_integer_search_not_full_real_kernel).

View answer and explanation

(3, [[-3, 1], [0, 0], [3, -1]], [[3, -1]], No, bounded_integer_search_not_full_real_kernel)

List exactly the zero-target points in this box and retain the separately derived global basis. The No complete flag concerns the bounded enumeration as a general full-real certificate, not denial of the symbolic basis already supplied. The exact result, retaining the requested order, is (3, [[-3, 1], [0, 0], [3, -1]], [[3, -1]], No, bounded_integer_search_not_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-bounded-search-boundary · candidate

79. A Bounded Integer Box Is Not the Full Real Kernel

Use this same exact integer matrix A=[[1, 4], [2, 8]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Nonnegative integer bound=4. Search x,y in [−bound,bound]∩Z, with x outer increasing and y inner increasing. Give (bound,integer_kernel_points,global_kernel_basis,complete?,bounded_integer_search_not_full_real_kernel).

View answer and explanation

(4, [[-4, 1], [0, 0], [4, -1]], [[4, -1]], No, bounded_integer_search_not_full_real_kernel)

List exactly the zero-target points in this box and retain the separately derived global basis. The No complete flag concerns the bounded enumeration as a general full-real certificate, not denial of the symbolic basis already supplied. The exact result, retaining the requested order, is (4, [[-4, 1], [0, 0], [4, -1]], [[4, -1]], No, bounded_integer_search_not_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-bounded-search-boundary · candidate

80. A Bounded Integer Box Is Not the Full Real Kernel

Use this same exact integer matrix A=[[1, 5], [2, 10]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Nonnegative integer bound=5. Search x,y in [−bound,bound]∩Z, with x outer increasing and y inner increasing. Give (bound,integer_kernel_points,global_kernel_basis,complete?,bounded_integer_search_not_full_real_kernel).

View answer and explanation

(5, [[-5, 1], [0, 0], [5, -1]], [[5, -1]], No, bounded_integer_search_not_full_real_kernel)

List exactly the zero-target points in this box and retain the separately derived global basis. The No complete flag concerns the bounded enumeration as a general full-real certificate, not denial of the symbolic basis already supplied. The exact result, retaining the requested order, is (5, [[-5, 1], [0, 0], [5, -1]], [[5, -1]], No, bounded_integer_search_not_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-bounded-search-boundary · candidate

81. A Bounded Integer Box Is Not the Full Real Kernel

Use this same exact integer matrix A=[[1, 6], [2, 12]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Nonnegative integer bound=1. Search x,y in [−bound,bound]∩Z, with x outer increasing and y inner increasing. Give (bound,integer_kernel_points,global_kernel_basis,complete?,bounded_integer_search_not_full_real_kernel).

View answer and explanation

(1, [[0, 0]], [[6, -1]], No, bounded_integer_search_not_full_real_kernel)

List exactly the zero-target points in this box and retain the separately derived global basis. The No complete flag concerns the bounded enumeration as a general full-real certificate, not denial of the symbolic basis already supplied. The exact result, retaining the requested order, is (1, [[0, 0]], [[6, -1]], No, bounded_integer_search_not_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-bounded-search-boundary · candidate

82. A Bounded Integer Box Is Not the Full Real Kernel

Use this same exact integer matrix A=[[1, 7], [2, 14]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Nonnegative integer bound=2. Search x,y in [−bound,bound]∩Z, with x outer increasing and y inner increasing. Give (bound,integer_kernel_points,global_kernel_basis,complete?,bounded_integer_search_not_full_real_kernel).

View answer and explanation

(2, [[0, 0]], [[7, -1]], No, bounded_integer_search_not_full_real_kernel)

List exactly the zero-target points in this box and retain the separately derived global basis. The No complete flag concerns the bounded enumeration as a general full-real certificate, not denial of the symbolic basis already supplied. The exact result, retaining the requested order, is (2, [[0, 0]], [[7, -1]], No, bounded_integer_search_not_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-bounded-search-boundary · candidate

83. A Bounded Integer Box Is Not the Full Real Kernel

Use this same exact integer matrix A=[[1, 8], [2, 16]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Nonnegative integer bound=3. Search x,y in [−bound,bound]∩Z, with x outer increasing and y inner increasing. Give (bound,integer_kernel_points,global_kernel_basis,complete?,bounded_integer_search_not_full_real_kernel).

View answer and explanation

(3, [[0, 0]], [[8, -1]], No, bounded_integer_search_not_full_real_kernel)

List exactly the zero-target points in this box and retain the separately derived global basis. The No complete flag concerns the bounded enumeration as a general full-real certificate, not denial of the symbolic basis already supplied. The exact result, retaining the requested order, is (3, [[0, 0]], [[8, -1]], No, bounded_integer_search_not_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-bounded-search-boundary · candidate

84. A Bounded Integer Box Is Not the Full Real Kernel

Use this same exact integer matrix A=[[1, 9], [2, 18]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Nonnegative integer bound=4. Search x,y in [−bound,bound]∩Z, with x outer increasing and y inner increasing. Give (bound,integer_kernel_points,global_kernel_basis,complete?,bounded_integer_search_not_full_real_kernel).

View answer and explanation

(4, [[0, 0]], [[9, -1]], No, bounded_integer_search_not_full_real_kernel)

List exactly the zero-target points in this box and retain the separately derived global basis. The No complete flag concerns the bounded enumeration as a general full-real certificate, not denial of the symbolic basis already supplied. The exact result, retaining the requested order, is (4, [[0, 0]], [[9, -1]], No, bounded_integer_search_not_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-bounded-search-boundary · candidate

85. A Bounded Integer Box Is Not the Full Real Kernel

Use this same exact integer matrix A=[[1, 10], [2, 20]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Nonnegative integer bound=5. Search x,y in [−bound,bound]∩Z, with x outer increasing and y inner increasing. Give (bound,integer_kernel_points,global_kernel_basis,complete?,bounded_integer_search_not_full_real_kernel).

View answer and explanation

(5, [[0, 0]], [[10, -1]], No, bounded_integer_search_not_full_real_kernel)

List exactly the zero-target points in this box and retain the separately derived global basis. The No complete flag concerns the bounded enumeration as a general full-real certificate, not denial of the symbolic basis already supplied. The exact result, retaining the requested order, is (5, [[0, 0]], [[10, -1]], No, bounded_integer_search_not_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-bounded-search-boundary · candidate

86. A Bounded Integer Box Is Not the Full Real Kernel

Use this same exact integer matrix A=[[1, 11], [2, 22]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Nonnegative integer bound=1. Search x,y in [−bound,bound]∩Z, with x outer increasing and y inner increasing. Give (bound,integer_kernel_points,global_kernel_basis,complete?,bounded_integer_search_not_full_real_kernel).

View answer and explanation

(1, [[0, 0]], [[11, -1]], No, bounded_integer_search_not_full_real_kernel)

List exactly the zero-target points in this box and retain the separately derived global basis. The No complete flag concerns the bounded enumeration as a general full-real certificate, not denial of the symbolic basis already supplied. The exact result, retaining the requested order, is (1, [[0, 0]], [[11, -1]], No, bounded_integer_search_not_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-bounded-search-boundary · candidate

87. A Bounded Integer Box Is Not the Full Real Kernel

Use this same exact integer matrix A=[[1, 12], [2, 24]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Nonnegative integer bound=2. Search x,y in [−bound,bound]∩Z, with x outer increasing and y inner increasing. Give (bound,integer_kernel_points,global_kernel_basis,complete?,bounded_integer_search_not_full_real_kernel).

View answer and explanation

(2, [[0, 0]], [[12, -1]], No, bounded_integer_search_not_full_real_kernel)

List exactly the zero-target points in this box and retain the separately derived global basis. The No complete flag concerns the bounded enumeration as a general full-real certificate, not denial of the symbolic basis already supplied. The exact result, retaining the requested order, is (2, [[0, 0]], [[12, -1]], No, bounded_integer_search_not_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-bounded-search-boundary · candidate

88. A Bounded Integer Box Is Not the Full Real Kernel

Use this same exact integer matrix A=[[1, 13], [2, 26]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Nonnegative integer bound=3. Search x,y in [−bound,bound]∩Z, with x outer increasing and y inner increasing. Give (bound,integer_kernel_points,global_kernel_basis,complete?,bounded_integer_search_not_full_real_kernel).

View answer and explanation

(3, [[0, 0]], [[13, -1]], No, bounded_integer_search_not_full_real_kernel)

List exactly the zero-target points in this box and retain the separately derived global basis. The No complete flag concerns the bounded enumeration as a general full-real certificate, not denial of the symbolic basis already supplied. The exact result, retaining the requested order, is (3, [[0, 0]], [[13, -1]], No, bounded_integer_search_not_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-bounded-search-boundary · candidate

89. A Bounded Integer Box Is Not the Full Real Kernel

Use this same exact integer matrix A=[[1, 14], [2, 28]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Nonnegative integer bound=4. Search x,y in [−bound,bound]∩Z, with x outer increasing and y inner increasing. Give (bound,integer_kernel_points,global_kernel_basis,complete?,bounded_integer_search_not_full_real_kernel).

View answer and explanation

(4, [[0, 0]], [[14, -1]], No, bounded_integer_search_not_full_real_kernel)

List exactly the zero-target points in this box and retain the separately derived global basis. The No complete flag concerns the bounded enumeration as a general full-real certificate, not denial of the symbolic basis already supplied. The exact result, retaining the requested order, is (4, [[0, 0]], [[14, -1]], No, bounded_integer_search_not_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-bounded-search-boundary · candidate

90. A Bounded Integer Box Is Not the Full Real Kernel

Use this same exact integer matrix A=[[1, 15], [2, 30]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Nonnegative integer bound=5. Search x,y in [−bound,bound]∩Z, with x outer increasing and y inner increasing. Give (bound,integer_kernel_points,global_kernel_basis,complete?,bounded_integer_search_not_full_real_kernel).

View answer and explanation

(5, [[0, 0]], [[15, -1]], No, bounded_integer_search_not_full_real_kernel)

List exactly the zero-target points in this box and retain the separately derived global basis. The No complete flag concerns the bounded enumeration as a general full-real certificate, not denial of the symbolic basis already supplied. The exact result, retaining the requested order, is (5, [[0, 0]], [[15, -1]], No, bounded_integer_search_not_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-bounded-search-boundary · candidate

91. A Bounded Integer Box Is Not the Full Real Kernel

Use this same exact integer matrix A=[[1, 16], [2, 32]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Nonnegative integer bound=1. Search x,y in [−bound,bound]∩Z, with x outer increasing and y inner increasing. Give (bound,integer_kernel_points,global_kernel_basis,complete?,bounded_integer_search_not_full_real_kernel).

View answer and explanation

(1, [[0, 0]], [[16, -1]], No, bounded_integer_search_not_full_real_kernel)

List exactly the zero-target points in this box and retain the separately derived global basis. The No complete flag concerns the bounded enumeration as a general full-real certificate, not denial of the symbolic basis already supplied. The exact result, retaining the requested order, is (1, [[0, 0]], [[16, -1]], No, bounded_integer_search_not_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-bounded-search-boundary · candidate

92. A Bounded Integer Box Is Not the Full Real Kernel

Use this same exact integer matrix A=[[1, 17], [2, 34]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Nonnegative integer bound=2. Search x,y in [−bound,bound]∩Z, with x outer increasing and y inner increasing. Give (bound,integer_kernel_points,global_kernel_basis,complete?,bounded_integer_search_not_full_real_kernel).

View answer and explanation

(2, [[0, 0]], [[17, -1]], No, bounded_integer_search_not_full_real_kernel)

List exactly the zero-target points in this box and retain the separately derived global basis. The No complete flag concerns the bounded enumeration as a general full-real certificate, not denial of the symbolic basis already supplied. The exact result, retaining the requested order, is (2, [[0, 0]], [[17, -1]], No, bounded_integer_search_not_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-bounded-search-boundary · candidate

93. A Bounded Integer Box Is Not the Full Real Kernel

Use this same exact integer matrix A=[[1, 18], [2, 36]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Nonnegative integer bound=3. Search x,y in [−bound,bound]∩Z, with x outer increasing and y inner increasing. Give (bound,integer_kernel_points,global_kernel_basis,complete?,bounded_integer_search_not_full_real_kernel).

View answer and explanation

(3, [[0, 0]], [[18, -1]], No, bounded_integer_search_not_full_real_kernel)

List exactly the zero-target points in this box and retain the separately derived global basis. The No complete flag concerns the bounded enumeration as a general full-real certificate, not denial of the symbolic basis already supplied. The exact result, retaining the requested order, is (3, [[0, 0]], [[18, -1]], No, bounded_integer_search_not_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-bounded-search-boundary · candidate

94. A Bounded Integer Box Is Not the Full Real Kernel

Use this same exact integer matrix A=[[1, 19], [2, 38]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Nonnegative integer bound=4. Search x,y in [−bound,bound]∩Z, with x outer increasing and y inner increasing. Give (bound,integer_kernel_points,global_kernel_basis,complete?,bounded_integer_search_not_full_real_kernel).

View answer and explanation

(4, [[0, 0]], [[19, -1]], No, bounded_integer_search_not_full_real_kernel)

List exactly the zero-target points in this box and retain the separately derived global basis. The No complete flag concerns the bounded enumeration as a general full-real certificate, not denial of the symbolic basis already supplied. The exact result, retaining the requested order, is (4, [[0, 0]], [[19, -1]], No, bounded_integer_search_not_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-bounded-search-boundary · candidate

95. A Bounded Integer Box Is Not the Full Real Kernel

Use this same exact integer matrix A=[[1, 20], [2, 40]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Nonnegative integer bound=5. Search x,y in [−bound,bound]∩Z, with x outer increasing and y inner increasing. Give (bound,integer_kernel_points,global_kernel_basis,complete?,bounded_integer_search_not_full_real_kernel).

View answer and explanation

(5, [[0, 0]], [[20, -1]], No, bounded_integer_search_not_full_real_kernel)

List exactly the zero-target points in this box and retain the separately derived global basis. The No complete flag concerns the bounded enumeration as a general full-real certificate, not denial of the symbolic basis already supplied. The exact result, retaining the requested order, is (5, [[0, 0]], [[20, -1]], No, bounded_integer_search_not_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-bounded-search-boundary · candidate

96. A Bounded Integer Box Is Not the Full Real Kernel

Use this same exact integer matrix A=[[1, 21], [2, 42]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Nonnegative integer bound=1. Search x,y in [−bound,bound]∩Z, with x outer increasing and y inner increasing. Give (bound,integer_kernel_points,global_kernel_basis,complete?,bounded_integer_search_not_full_real_kernel).

View answer and explanation

(1, [[0, 0]], [[21, -1]], No, bounded_integer_search_not_full_real_kernel)

List exactly the zero-target points in this box and retain the separately derived global basis. The No complete flag concerns the bounded enumeration as a general full-real certificate, not denial of the symbolic basis already supplied. The exact result, retaining the requested order, is (1, [[0, 0]], [[21, -1]], No, bounded_integer_search_not_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-bounded-search-boundary · candidate

97. A Bounded Integer Box Is Not the Full Real Kernel

Use this same exact integer matrix A=[[1, 22], [2, 44]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Nonnegative integer bound=2. Search x,y in [−bound,bound]∩Z, with x outer increasing and y inner increasing. Give (bound,integer_kernel_points,global_kernel_basis,complete?,bounded_integer_search_not_full_real_kernel).

View answer and explanation

(2, [[0, 0]], [[22, -1]], No, bounded_integer_search_not_full_real_kernel)

List exactly the zero-target points in this box and retain the separately derived global basis. The No complete flag concerns the bounded enumeration as a general full-real certificate, not denial of the symbolic basis already supplied. The exact result, retaining the requested order, is (2, [[0, 0]], [[22, -1]], No, bounded_integer_search_not_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-bounded-search-boundary · candidate

98. A Bounded Integer Box Is Not the Full Real Kernel

Use this same exact integer matrix A=[[1, 23], [2, 46]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Nonnegative integer bound=3. Search x,y in [−bound,bound]∩Z, with x outer increasing and y inner increasing. Give (bound,integer_kernel_points,global_kernel_basis,complete?,bounded_integer_search_not_full_real_kernel).

View answer and explanation

(3, [[0, 0]], [[23, -1]], No, bounded_integer_search_not_full_real_kernel)

List exactly the zero-target points in this box and retain the separately derived global basis. The No complete flag concerns the bounded enumeration as a general full-real certificate, not denial of the symbolic basis already supplied. The exact result, retaining the requested order, is (3, [[0, 0]], [[23, -1]], No, bounded_integer_search_not_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-bounded-search-boundary · candidate

99. A Bounded Integer Box Is Not the Full Real Kernel

Use this same exact integer matrix A=[[1, 24], [2, 48]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Nonnegative integer bound=4. Search x,y in [−bound,bound]∩Z, with x outer increasing and y inner increasing. Give (bound,integer_kernel_points,global_kernel_basis,complete?,bounded_integer_search_not_full_real_kernel).

View answer and explanation

(4, [[0, 0]], [[24, -1]], No, bounded_integer_search_not_full_real_kernel)

List exactly the zero-target points in this box and retain the separately derived global basis. The No complete flag concerns the bounded enumeration as a general full-real certificate, not denial of the symbolic basis already supplied. The exact result, retaining the requested order, is (4, [[0, 0]], [[24, -1]], No, bounded_integer_search_not_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-bounded-search-boundary · candidate

100. A Bounded Integer Box Is Not the Full Real Kernel

Use this same exact integer matrix A=[[1, 25], [2, 50]] for the usual linear map T:R²→R², with rows and columns in the supplied order. Kernel means all real x solving A*x=0; image means the full real column span, not automatically the whole codomain. An empty basis spans the zero space. Rank2 has zero-dimensional kernel and both original columns as an image basis; rank0 has the standard kernel basis and empty image basis. At rank1 the kernel uses a primitive integer normal-equation solution, with its first nonzero coordinate positive, and the image uses the first nonzero original column. All divisions are exact rational operations. Nonnegative integer bound=5. Search x,y in [−bound,bound]∩Z, with x outer increasing and y inner increasing. Give (bound,integer_kernel_points,global_kernel_basis,complete?,bounded_integer_search_not_full_real_kernel).

View answer and explanation

(5, [[0, 0]], [[25, -1]], No, bounded_integer_search_not_full_real_kernel)

List exactly the zero-target points in this box and retain the separately derived global basis. The No complete flag concerns the bounded enumeration as a general full-real certificate, not denial of the symbolic basis already supplied. The exact result, retaining the requested order, is (5, [[0, 0]], [[25, -1]], No, bounded_integer_search_not_full_real_kernel).

Reviewed step-by-step derivation

Kernel of a linear map · qf-mod33-kernel-bounded-search-boundary · candidate

Canonical question JSONL · English JSONL · Validation report