Carrier Coverage, Local Refinement and Complete Topology Generation

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batch-20261014-advance-20261107-r03-topological-basis-foundations · 2026-10-14 · 100 questions

This English edition is an AI candidate and does not yet have an OCME Atlas (GPT-6) Twin closure receipt.

Field order uses a source-bound presentation supplement; canonical JSONL and mathematical answers are unchanged.

Field-order and source-binding data

1. Coverage and Pointwise Intersection Refinement Are Separate Axioms

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).

View answer and explanation

(Yes, Yes, null, Yes)

Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-basis-qualification · candidate

2. Coverage and Pointwise Intersection Refinement Are Separate Axioms

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [1], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).

View answer and explanation

(Yes, Yes, null, Yes)

Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-basis-qualification · candidate

3. Coverage and Pointwise Intersection Refinement Are Separate Axioms

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 2], [1], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).

View answer and explanation

(Yes, Yes, null, Yes)

Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-basis-qualification · candidate

4. Coverage and Pointwise Intersection Refinement Are Separate Axioms

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [0, 2], [1], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).

View answer and explanation

(Yes, Yes, null, Yes)

Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-basis-qualification · candidate

5. Coverage and Pointwise Intersection Refinement Are Separate Axioms

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [1, 2], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).

View answer and explanation

(Yes, Yes, null, Yes)

Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-basis-qualification · candidate

6. Coverage and Pointwise Intersection Refinement Are Separate Axioms

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [1], [1, 2], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).

View answer and explanation

(Yes, Yes, null, Yes)

Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-basis-qualification · candidate

7. Coverage and Pointwise Intersection Refinement Are Separate Axioms

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 2], [1], [1, 2], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).

View answer and explanation

(Yes, Yes, null, Yes)

Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-basis-qualification · candidate

8. Coverage and Pointwise Intersection Refinement Are Separate Axioms

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [0, 2], [1], [1, 2], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).

View answer and explanation

(Yes, Yes, null, Yes)

Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-basis-qualification · candidate

9. Coverage and Pointwise Intersection Refinement Are Separate Axioms

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).

View answer and explanation

(Yes, Yes, null, Yes)

Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-basis-qualification · candidate

10. Coverage and Pointwise Intersection Refinement Are Separate Axioms

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [1], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).

View answer and explanation

(Yes, Yes, null, Yes)

Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-basis-qualification · candidate

11. Coverage and Pointwise Intersection Refinement Are Separate Axioms

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 2], [1], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).

View answer and explanation

(Yes, Yes, null, Yes)

Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-basis-qualification · candidate

12. Coverage and Pointwise Intersection Refinement Are Separate Axioms

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [0, 2], [1], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).

View answer and explanation

(Yes, Yes, null, Yes)

Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-basis-qualification · candidate

13. Coverage and Pointwise Intersection Refinement Are Separate Axioms

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [1, 2], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).

View answer and explanation

(Yes, Yes, null, Yes)

Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-basis-qualification · candidate

14. Coverage and Pointwise Intersection Refinement Are Separate Axioms

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [1], [1, 2], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).

View answer and explanation

(Yes, Yes, null, Yes)

Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-basis-qualification · candidate

15. Coverage and Pointwise Intersection Refinement Are Separate Axioms

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 2], [1], [1, 2], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).

View answer and explanation

(Yes, Yes, null, Yes)

Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-basis-qualification · candidate

16. Coverage and Pointwise Intersection Refinement Are Separate Axioms

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [0, 2], [1], [1, 2], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).

View answer and explanation

(Yes, Yes, null, Yes)

Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-basis-qualification · candidate

17. Coverage and Pointwise Intersection Refinement Are Separate Axioms

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).

View answer and explanation

(Yes, Yes, null, Yes)

Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-basis-qualification · candidate

18. Coverage and Pointwise Intersection Refinement Are Separate Axioms

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [1], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).

View answer and explanation

(Yes, Yes, null, Yes)

Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-basis-qualification · candidate

19. Coverage and Pointwise Intersection Refinement Are Separate Axioms

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 2], [1], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).

View answer and explanation

(Yes, Yes, null, Yes)

Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-basis-qualification · candidate

20. Coverage and Pointwise Intersection Refinement Are Separate Axioms

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [0, 2], [1], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).

View answer and explanation

(Yes, Yes, null, Yes)

Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-basis-qualification · candidate

21. Coverage and Pointwise Intersection Refinement Are Separate Axioms

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [1, 2], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).

View answer and explanation

(Yes, Yes, null, Yes)

Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-basis-qualification · candidate

22. Coverage and Pointwise Intersection Refinement Are Separate Axioms

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [1], [1, 2], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).

View answer and explanation

(Yes, Yes, null, Yes)

Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-basis-qualification · candidate

23. Coverage and Pointwise Intersection Refinement Are Separate Axioms

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 2], [1], [1, 2], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).

View answer and explanation

(Yes, Yes, null, Yes)

Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-basis-qualification · candidate

24. Coverage and Pointwise Intersection Refinement Are Separate Axioms

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [0, 2], [1], [1, 2], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).

View answer and explanation

(Yes, Yes, null, Yes)

Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-basis-qualification · candidate

25. Coverage and Pointwise Intersection Refinement Are Separate Axioms

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [2], [2, 3], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).

View answer and explanation

(Yes, Yes, null, Yes)

Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-basis-qualification · candidate

26. Generate All Unions Only after the Basis Axioms Pass

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).

View answer and explanation

([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)

Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-generated-topology · candidate

27. Generate All Unions Only after the Basis Axioms Pass

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [1], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).

View answer and explanation

([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)

Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-generated-topology · candidate

28. Generate All Unions Only after the Basis Axioms Pass

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 2], [1], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).

View answer and explanation

([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)

Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-generated-topology · candidate

29. Generate All Unions Only after the Basis Axioms Pass

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [0, 2], [1], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).

View answer and explanation

([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)

Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-generated-topology · candidate

30. Generate All Unions Only after the Basis Axioms Pass

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [1, 2], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).

View answer and explanation

([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)

Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-generated-topology · candidate

31. Generate All Unions Only after the Basis Axioms Pass

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [1], [1, 2], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).

View answer and explanation

([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)

Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-generated-topology · candidate

32. Generate All Unions Only after the Basis Axioms Pass

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 2], [1], [1, 2], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).

View answer and explanation

([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)

Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-generated-topology · candidate

33. Generate All Unions Only after the Basis Axioms Pass

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [0, 2], [1], [1, 2], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).

View answer and explanation

([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)

Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-generated-topology · candidate

34. Generate All Unions Only after the Basis Axioms Pass

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).

View answer and explanation

([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)

Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-generated-topology · candidate

35. Generate All Unions Only after the Basis Axioms Pass

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [1], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).

View answer and explanation

([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)

Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-generated-topology · candidate

36. Generate All Unions Only after the Basis Axioms Pass

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 2], [1], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).

View answer and explanation

([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)

Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-generated-topology · candidate

37. Generate All Unions Only after the Basis Axioms Pass

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [0, 2], [1], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).

View answer and explanation

([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)

Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-generated-topology · candidate

38. Generate All Unions Only after the Basis Axioms Pass

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [1, 2], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).

View answer and explanation

([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)

Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-generated-topology · candidate

39. Generate All Unions Only after the Basis Axioms Pass

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [1], [1, 2], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).

View answer and explanation

([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)

Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-generated-topology · candidate

40. Generate All Unions Only after the Basis Axioms Pass

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 2], [1], [1, 2], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).

View answer and explanation

([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)

Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-generated-topology · candidate

41. Generate All Unions Only after the Basis Axioms Pass

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [0, 2], [1], [1, 2], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).

View answer and explanation

([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)

Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-generated-topology · candidate

42. Generate All Unions Only after the Basis Axioms Pass

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).

View answer and explanation

([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)

Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-generated-topology · candidate

43. Generate All Unions Only after the Basis Axioms Pass

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [1], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).

View answer and explanation

([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)

Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-generated-topology · candidate

44. Generate All Unions Only after the Basis Axioms Pass

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 2], [1], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).

View answer and explanation

([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)

Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-generated-topology · candidate

45. Generate All Unions Only after the Basis Axioms Pass

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [0, 2], [1], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).

View answer and explanation

([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)

Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-generated-topology · candidate

46. Generate All Unions Only after the Basis Axioms Pass

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [1, 2], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).

View answer and explanation

([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)

Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-generated-topology · candidate

47. Generate All Unions Only after the Basis Axioms Pass

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [1], [1, 2], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).

View answer and explanation

([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)

Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-generated-topology · candidate

48. Generate All Unions Only after the Basis Axioms Pass

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 2], [1], [1, 2], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).

View answer and explanation

([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)

Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-generated-topology · candidate

49. Generate All Unions Only after the Basis Axioms Pass

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [0, 2], [1], [1, 2], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).

View answer and explanation

([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)

Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-generated-topology · candidate

50. Generate All Unions Only after the Basis Axioms Pass

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [2], [2, 3], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).

View answer and explanation

([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)

Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-generated-topology · candidate

51. A Basis for Some Topology Need Not Generate This Given Topology

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).

View answer and explanation

(Yes, Yes, Yes, Yes, Yes)

Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate

52. A Basis for Some Topology Need Not Generate This Given Topology

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [1], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).

View answer and explanation

(Yes, Yes, Yes, Yes, Yes)

Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate

53. A Basis for Some Topology Need Not Generate This Given Topology

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 2], [1], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).

View answer and explanation

(Yes, Yes, Yes, Yes, Yes)

Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate

54. A Basis for Some Topology Need Not Generate This Given Topology

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [0, 2], [1], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).

View answer and explanation

(Yes, Yes, Yes, Yes, Yes)

Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate

55. A Basis for Some Topology Need Not Generate This Given Topology

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [1, 2], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).

View answer and explanation

(Yes, Yes, Yes, Yes, Yes)

Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate

56. A Basis for Some Topology Need Not Generate This Given Topology

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [1], [1, 2], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).

View answer and explanation

(Yes, Yes, Yes, Yes, Yes)

Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate

57. A Basis for Some Topology Need Not Generate This Given Topology

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 2], [1], [1, 2], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).

View answer and explanation

(Yes, Yes, Yes, Yes, Yes)

Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate

58. A Basis for Some Topology Need Not Generate This Given Topology

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [0, 2], [1], [1, 2], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).

View answer and explanation

(Yes, Yes, Yes, Yes, Yes)

Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate

59. A Basis for Some Topology Need Not Generate This Given Topology

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).

View answer and explanation

(Yes, Yes, Yes, Yes, Yes)

Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate

60. A Basis for Some Topology Need Not Generate This Given Topology

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [1], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).

View answer and explanation

(Yes, Yes, Yes, Yes, Yes)

Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate

61. A Basis for Some Topology Need Not Generate This Given Topology

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 2], [1], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).

View answer and explanation

(Yes, Yes, Yes, Yes, Yes)

Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate

62. A Basis for Some Topology Need Not Generate This Given Topology

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [0, 2], [1], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).

View answer and explanation

(Yes, Yes, Yes, Yes, Yes)

Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate

63. A Basis for Some Topology Need Not Generate This Given Topology

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [1, 2], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).

View answer and explanation

(Yes, Yes, Yes, Yes, Yes)

Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate

64. A Basis for Some Topology Need Not Generate This Given Topology

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [1], [1, 2], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).

View answer and explanation

(Yes, Yes, Yes, Yes, Yes)

Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate

65. A Basis for Some Topology Need Not Generate This Given Topology

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 2], [1], [1, 2], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).

View answer and explanation

(Yes, Yes, Yes, Yes, Yes)

Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate

66. A Basis for Some Topology Need Not Generate This Given Topology

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [0, 2], [1], [1, 2], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).

View answer and explanation

(Yes, Yes, Yes, Yes, Yes)

Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate

67. A Basis for Some Topology Need Not Generate This Given Topology

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).

View answer and explanation

(Yes, Yes, Yes, Yes, Yes)

Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate

68. A Basis for Some Topology Need Not Generate This Given Topology

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [1], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).

View answer and explanation

(Yes, Yes, Yes, Yes, Yes)

Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate

69. A Basis for Some Topology Need Not Generate This Given Topology

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 2], [1], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).

View answer and explanation

(Yes, Yes, Yes, Yes, Yes)

Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate

70. A Basis for Some Topology Need Not Generate This Given Topology

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [0, 2], [1], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).

View answer and explanation

(Yes, Yes, Yes, Yes, Yes)

Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate

71. A Basis for Some Topology Need Not Generate This Given Topology

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [1, 2], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).

View answer and explanation

(Yes, Yes, Yes, Yes, Yes)

Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate

72. A Basis for Some Topology Need Not Generate This Given Topology

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [1], [1, 2], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).

View answer and explanation

(Yes, Yes, Yes, Yes, Yes)

Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate

73. A Basis for Some Topology Need Not Generate This Given Topology

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 2], [1], [1, 2], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).

View answer and explanation

(Yes, Yes, Yes, Yes, Yes)

Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate

74. A Basis for Some Topology Need Not Generate This Given Topology

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [0, 2], [1], [1, 2], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).

View answer and explanation

(Yes, Yes, Yes, Yes, Yes)

Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate

75. A Basis for Some Topology Need Not Generate This Given Topology

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [2], [2, 3], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).

View answer and explanation

(Yes, Yes, Yes, Yes, Yes)

Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate

76. A Cover Alone Does Not Supply the Local Basis Axiom

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [1, 2], [2, 3], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).

The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.

View answer and explanation

(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)

Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate

77. A Cover Alone Does Not Supply the Local Basis Axiom

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [0, 2], [1, 2], [2, 3], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).

The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.

View answer and explanation

(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)

Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate

78. A Cover Alone Does Not Supply the Local Basis Axiom

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [1, 2], [1, 3], [2, 3], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).

The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.

View answer and explanation

(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)

Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate

79. A Cover Alone Does Not Supply the Local Basis Axiom

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [0, 2], [1, 2], [1, 3], [2, 3], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).

The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.

View answer and explanation

(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)

Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate

80. A Cover Alone Does Not Supply the Local Basis Axiom

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [1, 2], [2, 3], [2, 4], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).

The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.

View answer and explanation

(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)

Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate

81. A Cover Alone Does Not Supply the Local Basis Axiom

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [0, 2], [1, 2], [2, 3], [2, 4], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).

The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.

View answer and explanation

(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)

Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate

82. A Cover Alone Does Not Supply the Local Basis Axiom

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [1, 2], [1, 3], [2, 3], [2, 4], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).

The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.

View answer and explanation

(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)

Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate

83. A Cover Alone Does Not Supply the Local Basis Axiom

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [0, 2], [1, 2], [1, 3], [2, 3], [2, 4], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).

The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.

View answer and explanation

(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)

Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate

84. A Cover Alone Does Not Supply the Local Basis Axiom

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [0, 3], [1, 2], [2, 3], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).

The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.

View answer and explanation

(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)

Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate

85. A Cover Alone Does Not Supply the Local Basis Axiom

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [0, 2], [0, 3], [1, 2], [2, 3], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).

The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.

View answer and explanation

(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)

Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate

86. A Cover Alone Does Not Supply the Local Basis Axiom

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [0, 3], [1, 2], [1, 3], [2, 3], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).

The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.

View answer and explanation

(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)

Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate

87. A Cover Alone Does Not Supply the Local Basis Axiom

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [0, 2], [0, 3], [1, 2], [1, 3], [2, 3], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).

The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.

View answer and explanation

(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)

Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate

88. A Cover Alone Does Not Supply the Local Basis Axiom

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [0, 3], [1, 2], [2, 3], [2, 4], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).

The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.

View answer and explanation

(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)

Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate

89. A Cover Alone Does Not Supply the Local Basis Axiom

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [0, 2], [0, 3], [1, 2], [2, 3], [2, 4], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).

The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.

View answer and explanation

(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)

Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate

90. A Cover Alone Does Not Supply the Local Basis Axiom

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [0, 3], [1, 2], [1, 3], [2, 3], [2, 4], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).

The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.

View answer and explanation

(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)

Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate

91. A Cover Alone Does Not Supply the Local Basis Axiom

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [0, 2], [0, 3], [1, 2], [1, 3], [2, 3], [2, 4], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).

The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.

View answer and explanation

(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)

Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate

92. A Cover Alone Does Not Supply the Local Basis Axiom

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [1, 2], [1, 4], [2, 3], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).

The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.

View answer and explanation

(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)

Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate

93. A Cover Alone Does Not Supply the Local Basis Axiom

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [0, 2], [1, 2], [1, 4], [2, 3], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).

The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.

View answer and explanation

(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)

Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate

94. A Cover Alone Does Not Supply the Local Basis Axiom

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [1, 2], [1, 3], [1, 4], [2, 3], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).

The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.

View answer and explanation

(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)

Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate

95. A Cover Alone Does Not Supply the Local Basis Axiom

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [0, 2], [1, 2], [1, 3], [1, 4], [2, 3], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).

The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.

View answer and explanation

(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)

Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate

96. A Cover Alone Does Not Supply the Local Basis Axiom

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [1, 2], [1, 4], [2, 3], [2, 4], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).

The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.

View answer and explanation

(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)

Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate

97. A Cover Alone Does Not Supply the Local Basis Axiom

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [0, 2], [1, 2], [1, 4], [2, 3], [2, 4], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).

The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.

View answer and explanation

(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)

Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate

98. A Cover Alone Does Not Supply the Local Basis Axiom

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [1, 2], [1, 3], [1, 4], [2, 3], [2, 4], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).

The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.

View answer and explanation

(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)

Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate

99. A Cover Alone Does Not Supply the Local Basis Axiom

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [0, 2], [1, 2], [1, 3], [1, 4], [2, 3], [2, 4], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).

The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.

View answer and explanation

(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)

Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate

100. A Cover Alone Does Not Supply the Local Basis Axiom

Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [0, 3], [1, 2], [1, 4], [2, 3], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).

The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.

View answer and explanation

(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)

Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).

Reviewed step-by-step derivation

Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate

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