Carrier Coverage, Local Refinement and Complete Topology Generation
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This question bank has corresponding bilingual step-by-step derivations. Source candidate and English ai_candidate states are retained. AI review, finite computation and Lean formal proof are labelled separately.
batch-20261014-advance-20261107-r03-topological-basis-foundations · 2026-10-14 · 100 questions
This English edition is an AI candidate and does not yet have an OCME Atlas (GPT-6) Twin closure receipt.
Field order uses a source-bound presentation supplement; canonical JSONL and mathematical answers are unchanged.
Field-order and source-binding data
1. Coverage and Pointwise Intersection Refinement Are Separate Axioms
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).
View answer and explanation
(Yes, Yes, null, Yes)
Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-basis-qualification · candidate
2. Coverage and Pointwise Intersection Refinement Are Separate Axioms
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [1], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).
View answer and explanation
(Yes, Yes, null, Yes)
Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-basis-qualification · candidate
3. Coverage and Pointwise Intersection Refinement Are Separate Axioms
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 2], [1], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).
View answer and explanation
(Yes, Yes, null, Yes)
Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-basis-qualification · candidate
4. Coverage and Pointwise Intersection Refinement Are Separate Axioms
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [0, 2], [1], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).
View answer and explanation
(Yes, Yes, null, Yes)
Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-basis-qualification · candidate
5. Coverage and Pointwise Intersection Refinement Are Separate Axioms
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [1, 2], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).
View answer and explanation
(Yes, Yes, null, Yes)
Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-basis-qualification · candidate
6. Coverage and Pointwise Intersection Refinement Are Separate Axioms
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [1], [1, 2], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).
View answer and explanation
(Yes, Yes, null, Yes)
Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-basis-qualification · candidate
7. Coverage and Pointwise Intersection Refinement Are Separate Axioms
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 2], [1], [1, 2], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).
View answer and explanation
(Yes, Yes, null, Yes)
Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-basis-qualification · candidate
8. Coverage and Pointwise Intersection Refinement Are Separate Axioms
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [0, 2], [1], [1, 2], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).
View answer and explanation
(Yes, Yes, null, Yes)
Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-basis-qualification · candidate
9. Coverage and Pointwise Intersection Refinement Are Separate Axioms
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).
View answer and explanation
(Yes, Yes, null, Yes)
Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-basis-qualification · candidate
10. Coverage and Pointwise Intersection Refinement Are Separate Axioms
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [1], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).
View answer and explanation
(Yes, Yes, null, Yes)
Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-basis-qualification · candidate
11. Coverage and Pointwise Intersection Refinement Are Separate Axioms
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 2], [1], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).
View answer and explanation
(Yes, Yes, null, Yes)
Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-basis-qualification · candidate
12. Coverage and Pointwise Intersection Refinement Are Separate Axioms
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [0, 2], [1], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).
View answer and explanation
(Yes, Yes, null, Yes)
Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-basis-qualification · candidate
13. Coverage and Pointwise Intersection Refinement Are Separate Axioms
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [1, 2], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).
View answer and explanation
(Yes, Yes, null, Yes)
Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-basis-qualification · candidate
14. Coverage and Pointwise Intersection Refinement Are Separate Axioms
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [1], [1, 2], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).
View answer and explanation
(Yes, Yes, null, Yes)
Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-basis-qualification · candidate
15. Coverage and Pointwise Intersection Refinement Are Separate Axioms
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 2], [1], [1, 2], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).
View answer and explanation
(Yes, Yes, null, Yes)
Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-basis-qualification · candidate
16. Coverage and Pointwise Intersection Refinement Are Separate Axioms
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [0, 2], [1], [1, 2], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).
View answer and explanation
(Yes, Yes, null, Yes)
Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-basis-qualification · candidate
17. Coverage and Pointwise Intersection Refinement Are Separate Axioms
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).
View answer and explanation
(Yes, Yes, null, Yes)
Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-basis-qualification · candidate
18. Coverage and Pointwise Intersection Refinement Are Separate Axioms
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [1], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).
View answer and explanation
(Yes, Yes, null, Yes)
Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-basis-qualification · candidate
19. Coverage and Pointwise Intersection Refinement Are Separate Axioms
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 2], [1], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).
View answer and explanation
(Yes, Yes, null, Yes)
Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-basis-qualification · candidate
20. Coverage and Pointwise Intersection Refinement Are Separate Axioms
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [0, 2], [1], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).
View answer and explanation
(Yes, Yes, null, Yes)
Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-basis-qualification · candidate
21. Coverage and Pointwise Intersection Refinement Are Separate Axioms
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [1, 2], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).
View answer and explanation
(Yes, Yes, null, Yes)
Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-basis-qualification · candidate
22. Coverage and Pointwise Intersection Refinement Are Separate Axioms
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [1], [1, 2], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).
View answer and explanation
(Yes, Yes, null, Yes)
Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-basis-qualification · candidate
23. Coverage and Pointwise Intersection Refinement Are Separate Axioms
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 2], [1], [1, 2], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).
View answer and explanation
(Yes, Yes, null, Yes)
Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-basis-qualification · candidate
24. Coverage and Pointwise Intersection Refinement Are Separate Axioms
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [0, 2], [1], [1, 2], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).
View answer and explanation
(Yes, Yes, null, Yes)
Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-basis-qualification · candidate
25. Coverage and Pointwise Intersection Refinement Are Separate Axioms
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [2], [2, 3], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, first_failure, is_basis).
View answer and explanation
(Yes, Yes, null, Yes)
Return coverage, full local refinement, the first failed [left_family_index,right_family_index,point,intersection] or null, then their joint basis-validity flag. A covering family can fail refinement. The exact result, retaining the requested order, is (Yes, Yes, null, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-basis-qualification · candidate
26. Generate All Unions Only after the Basis Axioms Pass
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).
View answer and explanation
([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)
Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-generated-topology · candidate
27. Generate All Unions Only after the Basis Axioms Pass
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [1], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).
View answer and explanation
([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)
Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-generated-topology · candidate
28. Generate All Unions Only after the Basis Axioms Pass
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 2], [1], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).
View answer and explanation
([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)
Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-generated-topology · candidate
29. Generate All Unions Only after the Basis Axioms Pass
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [0, 2], [1], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).
View answer and explanation
([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)
Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-generated-topology · candidate
30. Generate All Unions Only after the Basis Axioms Pass
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [1, 2], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).
View answer and explanation
([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)
Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-generated-topology · candidate
31. Generate All Unions Only after the Basis Axioms Pass
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [1], [1, 2], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).
View answer and explanation
([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)
Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-generated-topology · candidate
32. Generate All Unions Only after the Basis Axioms Pass
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 2], [1], [1, 2], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).
View answer and explanation
([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)
Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-generated-topology · candidate
33. Generate All Unions Only after the Basis Axioms Pass
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [0, 2], [1], [1, 2], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).
View answer and explanation
([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)
Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-generated-topology · candidate
34. Generate All Unions Only after the Basis Axioms Pass
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).
View answer and explanation
([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)
Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-generated-topology · candidate
35. Generate All Unions Only after the Basis Axioms Pass
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [1], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).
View answer and explanation
([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)
Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-generated-topology · candidate
36. Generate All Unions Only after the Basis Axioms Pass
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 2], [1], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).
View answer and explanation
([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)
Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-generated-topology · candidate
37. Generate All Unions Only after the Basis Axioms Pass
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [0, 2], [1], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).
View answer and explanation
([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)
Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-generated-topology · candidate
38. Generate All Unions Only after the Basis Axioms Pass
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [1, 2], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).
View answer and explanation
([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)
Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-generated-topology · candidate
39. Generate All Unions Only after the Basis Axioms Pass
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [1], [1, 2], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).
View answer and explanation
([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)
Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-generated-topology · candidate
40. Generate All Unions Only after the Basis Axioms Pass
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 2], [1], [1, 2], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).
View answer and explanation
([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)
Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-generated-topology · candidate
41. Generate All Unions Only after the Basis Axioms Pass
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [0, 2], [1], [1, 2], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).
View answer and explanation
([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)
Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-generated-topology · candidate
42. Generate All Unions Only after the Basis Axioms Pass
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).
View answer and explanation
([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)
Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-generated-topology · candidate
43. Generate All Unions Only after the Basis Axioms Pass
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [1], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).
View answer and explanation
([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)
Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-generated-topology · candidate
44. Generate All Unions Only after the Basis Axioms Pass
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 2], [1], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).
View answer and explanation
([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)
Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-generated-topology · candidate
45. Generate All Unions Only after the Basis Axioms Pass
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [0, 2], [1], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).
View answer and explanation
([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)
Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-generated-topology · candidate
46. Generate All Unions Only after the Basis Axioms Pass
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [1, 2], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).
View answer and explanation
([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)
Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-generated-topology · candidate
47. Generate All Unions Only after the Basis Axioms Pass
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [1], [1, 2], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).
View answer and explanation
([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)
Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-generated-topology · candidate
48. Generate All Unions Only after the Basis Axioms Pass
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 2], [1], [1, 2], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).
View answer and explanation
([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)
Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-generated-topology · candidate
49. Generate All Unions Only after the Basis Axioms Pass
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [0, 2], [1], [1, 2], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).
View answer and explanation
([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)
Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-generated-topology · candidate
50. Generate All Unions Only after the Basis Axioms Pass
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [2], [2, 3], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (topology, open_count, topology_certificate, certificate).
View answer and explanation
([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements)
Require a valid basis and enumerate every distinct union, including the empty union. Retain the source canonical set-family order and exact open-set count. This is an exact certificate for the stated finite carrier, not an arbitrary-space sampling proof. The exact result, retaining the requested order, is ([[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]], 32, Yes, all_unions_of_basis_elements).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-generated-topology · candidate
51. A Basis for Some Topology Need Not Generate This Given Topology
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).
View answer and explanation
(Yes, Yes, Yes, Yes, Yes)
Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate
52. A Basis for Some Topology Need Not Generate This Given Topology
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [1], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).
View answer and explanation
(Yes, Yes, Yes, Yes, Yes)
Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate
53. A Basis for Some Topology Need Not Generate This Given Topology
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 2], [1], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).
View answer and explanation
(Yes, Yes, Yes, Yes, Yes)
Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate
54. A Basis for Some Topology Need Not Generate This Given Topology
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [0, 2], [1], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).
View answer and explanation
(Yes, Yes, Yes, Yes, Yes)
Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate
55. A Basis for Some Topology Need Not Generate This Given Topology
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [1, 2], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).
View answer and explanation
(Yes, Yes, Yes, Yes, Yes)
Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate
56. A Basis for Some Topology Need Not Generate This Given Topology
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [1], [1, 2], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).
View answer and explanation
(Yes, Yes, Yes, Yes, Yes)
Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate
57. A Basis for Some Topology Need Not Generate This Given Topology
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 2], [1], [1, 2], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).
View answer and explanation
(Yes, Yes, Yes, Yes, Yes)
Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate
58. A Basis for Some Topology Need Not Generate This Given Topology
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [0, 2], [1], [1, 2], [2], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).
View answer and explanation
(Yes, Yes, Yes, Yes, Yes)
Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate
59. A Basis for Some Topology Need Not Generate This Given Topology
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).
View answer and explanation
(Yes, Yes, Yes, Yes, Yes)
Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate
60. A Basis for Some Topology Need Not Generate This Given Topology
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [1], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).
View answer and explanation
(Yes, Yes, Yes, Yes, Yes)
Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate
61. A Basis for Some Topology Need Not Generate This Given Topology
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 2], [1], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).
View answer and explanation
(Yes, Yes, Yes, Yes, Yes)
Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate
62. A Basis for Some Topology Need Not Generate This Given Topology
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [0, 2], [1], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).
View answer and explanation
(Yes, Yes, Yes, Yes, Yes)
Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate
63. A Basis for Some Topology Need Not Generate This Given Topology
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [1, 2], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).
View answer and explanation
(Yes, Yes, Yes, Yes, Yes)
Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate
64. A Basis for Some Topology Need Not Generate This Given Topology
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [1], [1, 2], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).
View answer and explanation
(Yes, Yes, Yes, Yes, Yes)
Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate
65. A Basis for Some Topology Need Not Generate This Given Topology
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 2], [1], [1, 2], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).
View answer and explanation
(Yes, Yes, Yes, Yes, Yes)
Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate
66. A Basis for Some Topology Need Not Generate This Given Topology
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [0, 2], [1], [1, 2], [2], [2, 3], [3], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).
View answer and explanation
(Yes, Yes, Yes, Yes, Yes)
Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate
67. A Basis for Some Topology Need Not Generate This Given Topology
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).
View answer and explanation
(Yes, Yes, Yes, Yes, Yes)
Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate
68. A Basis for Some Topology Need Not Generate This Given Topology
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [1], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).
View answer and explanation
(Yes, Yes, Yes, Yes, Yes)
Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate
69. A Basis for Some Topology Need Not Generate This Given Topology
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 2], [1], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).
View answer and explanation
(Yes, Yes, Yes, Yes, Yes)
Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate
70. A Basis for Some Topology Need Not Generate This Given Topology
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [0, 2], [1], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).
View answer and explanation
(Yes, Yes, Yes, Yes, Yes)
Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate
71. A Basis for Some Topology Need Not Generate This Given Topology
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [1, 2], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).
View answer and explanation
(Yes, Yes, Yes, Yes, Yes)
Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate
72. A Basis for Some Topology Need Not Generate This Given Topology
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [1], [1, 2], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).
View answer and explanation
(Yes, Yes, Yes, Yes, Yes)
Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate
73. A Basis for Some Topology Need Not Generate This Given Topology
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 2], [1], [1, 2], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).
View answer and explanation
(Yes, Yes, Yes, Yes, Yes)
Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate
74. A Basis for Some Topology Need Not Generate This Given Topology
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [0, 1], [0, 2], [1], [1, 2], [2], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).
View answer and explanation
(Yes, Yes, Yes, Yes, Yes)
Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate
75. A Basis for Some Topology Need Not Generate This Given Topology
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0], [1], [2], [2, 3], [3], [3, 4], [4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Supplied complete topology=[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 4], [0, 1, 3], [0, 1, 3, 4], [0, 1, 4], [0, 2], [0, 2, 3], [0, 2, 3, 4], [0, 2, 4], [0, 3], [0, 3, 4], [0, 4], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 4], [1, 3], [1, 3, 4], [1, 4], [2], [2, 3], [2, 3, 4], [2, 4], [3], [3, 4], [4]]. Give (topology_valid, abstract_basis_valid, basis_elements_open, every_open_is_basis_union, basis_for_given_topology).
View answer and explanation
(Yes, Yes, Yes, Yes, Yes)
Check topology axioms, abstract basis axioms, openness of every basis element, and that every supplied open set is a basis union. Their conjunction establishes a basis for this topology; the abstract basis flag alone does not. The exact result, retaining the requested order, is (Yes, Yes, Yes, Yes, Yes).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-existing-topology-audit · candidate
76. A Cover Alone Does Not Supply the Local Basis Axiom
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [1, 2], [2, 3], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).
The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.
View answer and explanation
(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)
Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate
77. A Cover Alone Does Not Supply the Local Basis Axiom
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [0, 2], [1, 2], [2, 3], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).
The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.
View answer and explanation
(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)
Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate
78. A Cover Alone Does Not Supply the Local Basis Axiom
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [1, 2], [1, 3], [2, 3], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).
The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.
View answer and explanation
(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)
Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate
79. A Cover Alone Does Not Supply the Local Basis Axiom
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [0, 2], [1, 2], [1, 3], [2, 3], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).
The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.
View answer and explanation
(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)
Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate
80. A Cover Alone Does Not Supply the Local Basis Axiom
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [1, 2], [2, 3], [2, 4], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).
The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.
View answer and explanation
(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)
Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate
81. A Cover Alone Does Not Supply the Local Basis Axiom
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [0, 2], [1, 2], [2, 3], [2, 4], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).
The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.
View answer and explanation
(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)
Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate
82. A Cover Alone Does Not Supply the Local Basis Axiom
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [1, 2], [1, 3], [2, 3], [2, 4], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).
The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.
View answer and explanation
(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)
Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate
83. A Cover Alone Does Not Supply the Local Basis Axiom
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [0, 2], [1, 2], [1, 3], [2, 3], [2, 4], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).
The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.
View answer and explanation
(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)
Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate
84. A Cover Alone Does Not Supply the Local Basis Axiom
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [0, 3], [1, 2], [2, 3], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).
The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.
View answer and explanation
(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)
Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate
85. A Cover Alone Does Not Supply the Local Basis Axiom
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [0, 2], [0, 3], [1, 2], [2, 3], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).
The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.
View answer and explanation
(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)
Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate
86. A Cover Alone Does Not Supply the Local Basis Axiom
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [0, 3], [1, 2], [1, 3], [2, 3], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).
The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.
View answer and explanation
(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)
Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate
87. A Cover Alone Does Not Supply the Local Basis Axiom
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [0, 2], [0, 3], [1, 2], [1, 3], [2, 3], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).
The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.
View answer and explanation
(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)
Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate
88. A Cover Alone Does Not Supply the Local Basis Axiom
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [0, 3], [1, 2], [2, 3], [2, 4], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).
The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.
View answer and explanation
(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)
Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate
89. A Cover Alone Does Not Supply the Local Basis Axiom
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [0, 2], [0, 3], [1, 2], [2, 3], [2, 4], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).
The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.
View answer and explanation
(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)
Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate
90. A Cover Alone Does Not Supply the Local Basis Axiom
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [0, 3], [1, 2], [1, 3], [2, 3], [2, 4], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).
The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.
View answer and explanation
(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)
Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate
91. A Cover Alone Does Not Supply the Local Basis Axiom
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [0, 2], [0, 3], [1, 2], [1, 3], [2, 3], [2, 4], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).
The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.
View answer and explanation
(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)
Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate
92. A Cover Alone Does Not Supply the Local Basis Axiom
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [1, 2], [1, 4], [2, 3], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).
The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.
View answer and explanation
(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)
Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate
93. A Cover Alone Does Not Supply the Local Basis Axiom
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [0, 2], [1, 2], [1, 4], [2, 3], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).
The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.
View answer and explanation
(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)
Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate
94. A Cover Alone Does Not Supply the Local Basis Axiom
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [1, 2], [1, 3], [1, 4], [2, 3], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).
The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.
View answer and explanation
(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)
Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate
95. A Cover Alone Does Not Supply the Local Basis Axiom
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [0, 2], [1, 2], [1, 3], [1, 4], [2, 3], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).
The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.
View answer and explanation
(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)
Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate
96. A Cover Alone Does Not Supply the Local Basis Axiom
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [1, 2], [1, 4], [2, 3], [2, 4], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).
The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.
View answer and explanation
(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)
Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate
97. A Cover Alone Does Not Supply the Local Basis Axiom
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [0, 2], [1, 2], [1, 4], [2, 3], [2, 4], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).
The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.
View answer and explanation
(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)
Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate
98. A Cover Alone Does Not Supply the Local Basis Axiom
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [1, 2], [1, 3], [1, 4], [2, 3], [2, 4], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).
The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.
View answer and explanation
(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)
Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate
99. A Cover Alone Does Not Supply the Local Basis Axiom
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [0, 2], [1, 2], [1, 3], [1, 4], [2, 3], [2, 4], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).
The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.
View answer and explanation
(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)
Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate
100. A Cover Alone Does Not Supply the Local Basis Axiom
Use finite carrier Fin(5)={0,…,4} and the complete canonical candidate family basis=[[0, 1], [0, 3], [1, 2], [1, 4], [2, 3], [3, 4]]. Its union must cover the carrier; for every point in each pairwise intersection a candidate element containing that point must lie inside the intersection. Complete finite data, not sampled intersections, supply this audit. Give (covers_carrier, local_refinement, is_basis, cover_alone_suffices_general_claim, boundary).
The final No withholds the general cover-only implication; it does not negate the separately computed is_basis flag or disprove subbasis status.
View answer and explanation
(Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis)
Retain coverage, refinement and actual basis validity, then No for the general claim that cover alone suffices. The final No does not negate an independently valid basis or test whether this family is a subbasis. Generating from a subbasis generally needs finite intersections before unions. The exact result, retaining the requested order, is (Yes, No, No, No, cover_without_local_intersection_refinement_is_not_a_basis_and_may_only_be_a_subbasis).
Reviewed step-by-step derivation
Topological basis · qf-mod38-topbasis-subbasis-boundary · candidate
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