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Question 7141: Five Prefix Sums and Four Ordered Differences

On this page
  1. Original question and givens
  2. Definition and scope
  3. Step-by-step derivation
  4. Reverse checks
  5. Result
  6. This question review and source binding

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R0013-07141 · q-20261011-advance-20261015-r05-sequence-0091

Original question and givens

N begins at 0; retain sequence order and repeated values. A finite prefix does not determine a unique infinite rule, convergence, or infinite series. Five ordered values=[3, 0, 3, -1, 1]. Give (five inclusive prefix sums, four following-minus-previous differences, are all five values equal?).

  • G001 — N begins at 0; retain sequence order and repeated values. A finite prefix does not determine a unique infinite rule, convergence, or infinite series. Five ordered values=[3, 0, 3, -1, 1]. Give (five inclusive prefix sums, four following-minus-previous differences, are all five values equal?).

Definition and scope

Use the original question domain, assumptions and cited MKO definitions. This item has second-context mathematical and bilingual review, with the model, answer and every arithmetic step independently recomputed from the original parameters; the source question remains a candidate.

Step-by-step derivation

S001 · implies

Before

N starts at0;ordered finite indices and repeated values retained

After

given recurrences differ from guessing an infinite rule from observations

Conditions: none

Sequences are ordered and may repeat.A finite observed prefix alone does not determine a unique infinite rule;when a recurrence is explicitly supplied,use that rule rather than inventing one.

Step identifiers and dependencies

Rule: finite_ordered_sequence_scope · Uses: G001

S002 · calculation

Before

finite prefix sum through0 := sum(0, 3)

After

finite prefix sum through0 = 3

Conditions: none

Add the current term to the preceding prefix sum in original order,including repeats.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S001

S003 · calculation

Before

finite prefix sum through1 := sum(3, 0)

After

finite prefix sum through1 = 3

Conditions: none

Add the current term to the preceding prefix sum in original order,including repeats.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S002

S004 · calculation

Before

finite prefix sum through2 := sum(3, 3)

After

finite prefix sum through2 = 6

Conditions: none

Add the current term to the preceding prefix sum in original order,including repeats.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S003

S005 · calculation

Before

finite prefix sum through3 := sum(6, -1)

After

finite prefix sum through3 = 5

Conditions: none

Add the current term to the preceding prefix sum in original order,including repeats.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S004

S006 · calculation

Before

finite prefix sum through4 := sum(5, 1)

After

finite prefix sum through4 = 6

Conditions: none

Add the current term to the preceding prefix sum in original order,including repeats.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S005

S007 · calculation

Before

finite adjacent delta0 := sub(0, 3)

After

finite adjacent delta0 = -3

Conditions: none

Take each ordered next-minus-previous difference without sorting or deduplication.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S006

S008 · calculation

Before

finite adjacent delta1 := sub(3, 0)

After

finite adjacent delta1 = 3

Conditions: none

Take each ordered next-minus-previous difference without sorting or deduplication.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S007

S009 · calculation

Before

finite adjacent delta2 := sub(-1, 3)

After

finite adjacent delta2 = -4

Conditions: none

Take each ordered next-minus-previous difference without sorting or deduplication.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S008

S010 · calculation

Before

finite adjacent delta3 := sub(1, -1)

After

finite adjacent delta3 = 2

Conditions: none

Take each ordered next-minus-previous difference without sorting or deduplication.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S009

S011 · implies

Before

[3, 0, 3, -1, 1]

After

all five values equal=No

Conditions: none

These prefix sums are finite accumulations of five terms,not an infinite series or limit.The constant-value verdict concerns only these five terms.

Step identifiers and dependencies

Rule: finite_prefix_not_infinite_sum · Uses: G001, S010

Reverse checks

  • S011 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.
  • S010 · premise_and_result_audit — Recompute finite adjacent delta3 with exact rational arithmetic, not rounded decimals.
  • S009 · premise_and_result_audit — Recompute finite adjacent delta2 with exact rational arithmetic, not rounded decimals.
  • S008 · premise_and_result_audit — Recompute finite adjacent delta1 with exact rational arithmetic, not rounded decimals.
  • S007 · premise_and_result_audit — Recompute finite adjacent delta0 with exact rational arithmetic, not rounded decimals.
  • S006 · premise_and_result_audit — Recompute finite prefix sum through4 with exact rational arithmetic, not rounded decimals.
  • S005 · premise_and_result_audit — Recompute finite prefix sum through3 with exact rational arithmetic, not rounded decimals.
  • S004 · premise_and_result_audit — Recompute finite prefix sum through2 with exact rational arithmetic, not rounded decimals.
  • S003 · premise_and_result_audit — Recompute finite prefix sum through1 with exact rational arithmetic, not rounded decimals.
  • S002 · premise_and_result_audit — Recompute finite prefix sum through0 with exact rational arithmetic, not rounded decimals.
  • S001 · premise_and_result_audit — Check against the original data and this step's premises; a one-way implication is not an equivalence.

Result

([3, 3, 6, 5, 6], [-3, 3, -4, 2], No)

The full substitutions and premise checks give the original answer; source identity,format and status are unchanged.

This question review and source binding

Review date: 2026-10-26

Original questions, answers, step expressions, numeric ASTs and historical records are retained. Source candidate labels remain historical and are not overwritten as formal proof.

Source hashes and review receipts
  • input commit: 0f7be61e2c22317a4075561dc822c87d881a50db
  • original question SHA-256: e5316cc7d2f3da5f6d67e10147e0f7caef0a24ccad1a0b4e526f523f276feba0
  • candidate record SHA-256: c37f30e0ee1d7475c9ed17a18c6fd1782b30e3b6335ab6bfee3f1a39c81d7b6b
  • semantic review receipt SHA-256: e89fc6d4a50a4a7fc942c6c8939a92f835e30105a9a5850e37dd198f31c1ed59
  • question-first witness SHA-256: 0e1039f4cf022bf35af4e5531651c9a2b7ca7a5fdacac34fb1e4bcd9a81f6299
  • Lean: NOT_RUN · human review: NOT_PERFORMED
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