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Question 83: The Finite Expansion Includes Every k from Zero through n On this page Original question and givens Definition and scope Step-by-step derivation Reverse checks Result This question review and source binding Return to catalogue page 1
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P250-0083 · q-20261014-advance-20261109-r05-binomial-theorem-0033
Original question and givens Use natural exponent n=7, including0, in a commutative coefficient setting. Give (n, coefficient_exponent_rows, boundary).
G001 — Use natural exponent n=7, including0, in a commutative coefficient setting. Give (n, coefficient_exponent_rows, boundary).Definition and scope n is a nonnegative integer and x,y commute. For n=0 use the polynomial empty-product identity.
Step-by-step derivation S001 · implies Before
n=7≥0; x,y commute After
(x+y)^7 is a finite product of 7 factors Conditions: none
Choose x or y from each factor; commutativity permits grouping products by the number of y choices.
Step identifiers and dependencies Rule: finite_product · Uses: G001
S002 · implies Before
choose exactly 0 of 7 factors to contribute y After
C(7,0)=5040/(1·5040)=1 Conditions: none
Count orderings of 7 positions and divide by reorderings within the 0 y positions and 7 x positions, giving coefficient 1.
Step identifiers and dependencies Rule: subset_count · Uses: G001, S001
S003 · implies Before
C(7,0)=1; choose y 0 times After
1·x^7·y^0 Conditions: none
The x exponent is 7-0=7; the two exponents still sum to 7.
Step identifiers and dependencies Rule: group_like_terms · Uses: G001, S002
S004 · implies Before
choose exactly 1 of 7 factors to contribute y After
C(7,1)=5040/(1·720)=7 Conditions: none
Count orderings of 7 positions and divide by reorderings within the 1 y positions and 6 x positions, giving coefficient 7.
Step identifiers and dependencies Rule: subset_count · Uses: G001, S003
S005 · implies Before
C(7,1)=7; choose y 1 times After
7·x^6·y^1 Conditions: none
The x exponent is 7-1=6; the two exponents still sum to 7.
Step identifiers and dependencies Rule: group_like_terms · Uses: G001, S004
S006 · implies Before
choose exactly 2 of 7 factors to contribute y After
C(7,2)=5040/(2·120)=21 Conditions: none
Count orderings of 7 positions and divide by reorderings within the 2 y positions and 5 x positions, giving coefficient 21.
Step identifiers and dependencies Rule: subset_count · Uses: G001, S005
S007 · implies Before
C(7,2)=21; choose y 2 times After
21·x^5·y^2 Conditions: none
The x exponent is 7-2=5; the two exponents still sum to 7.
Step identifiers and dependencies Rule: group_like_terms · Uses: G001, S006
S008 · implies Before
choose exactly 3 of 7 factors to contribute y After
C(7,3)=5040/(6·24)=35 Conditions: none
Count orderings of 7 positions and divide by reorderings within the 3 y positions and 4 x positions, giving coefficient 35.
Step identifiers and dependencies Rule: subset_count · Uses: G001, S007
S009 · implies Before
C(7,3)=35; choose y 3 times After
35·x^4·y^3 Conditions: none
The x exponent is 7-3=4; the two exponents still sum to 7.
Step identifiers and dependencies Rule: group_like_terms · Uses: G001, S008
S010 · implies Before
choose exactly 4 of 7 factors to contribute y After
C(7,4)=5040/(24·6)=35 Conditions: none
Count orderings of 7 positions and divide by reorderings within the 4 y positions and 3 x positions, giving coefficient 35.
Step identifiers and dependencies Rule: subset_count · Uses: G001, S009
S011 · implies Before
C(7,4)=35; choose y 4 times After
35·x^3·y^4 Conditions: none
The x exponent is 7-4=3; the two exponents still sum to 7.
Step identifiers and dependencies Rule: group_like_terms · Uses: G001, S010
S012 · implies Before
choose exactly 5 of 7 factors to contribute y After
C(7,5)=5040/(120·2)=21 Conditions: none
Count orderings of 7 positions and divide by reorderings within the 5 y positions and 2 x positions, giving coefficient 21.
Step identifiers and dependencies Rule: subset_count · Uses: G001, S011
S013 · implies Before
C(7,5)=21; choose y 5 times After
21·x^2·y^5 Conditions: none
The x exponent is 7-5=2; the two exponents still sum to 7.
Step identifiers and dependencies Rule: group_like_terms · Uses: G001, S012
S014 · implies Before
choose exactly 6 of 7 factors to contribute y After
C(7,6)=5040/(720·1)=7 Conditions: none
Count orderings of 7 positions and divide by reorderings within the 6 y positions and 1 x positions, giving coefficient 7.
Step identifiers and dependencies Rule: subset_count · Uses: G001, S013
S015 · implies Before
C(7,6)=7; choose y 6 times After
7·x^1·y^6 Conditions: none
The x exponent is 7-6=1; the two exponents still sum to 7.
Step identifiers and dependencies Rule: group_like_terms · Uses: G001, S014
S016 · implies Before
choose exactly 7 of 7 factors to contribute y After
C(7,7)=5040/(5040·1)=1 Conditions: none
Count orderings of 7 positions and divide by reorderings within the 7 y positions and 0 x positions, giving coefficient 1.
Step identifiers and dependencies Rule: subset_count · Uses: G001, S015
S017 · implies Before
C(7,7)=1; choose y 7 times After
1·x^0·y^7 Conditions: none
The x exponent is 7-7=0; the two exponents still sum to 7.
Step identifiers and dependencies Rule: group_like_terms · Uses: G001, S016
S018 · implies Before
all k=0 through 7 have been accounted for After
(x+y)^7=1·x^7·y^0 + 7·x^6·y^1 + 21·x^5·y^2 + 35·x^4·y^3 + 35·x^3·y^4 + 21·x^2·y^5 + 7·x^1·y^6 + 1·x^0·y^7 Conditions: none
Every x/y choice belongs to exactly one k class, so this is the complete finite expansion, not just endpoint terms.
Step identifiers and dependencies Rule: collect_all_terms · Uses: G001, S017
Reverse checks S018 · premise_and_result_audit — There are n+1 coefficient positions, with the complete range of k retained.S017 · premise_and_result_audit — The answer row is [k,coefficient,x exponent,y exponent]; do not swap the exponent columns.S016 · premise_and_result_audit — Check the coefficient independently with the integer Pascal recurrence, not approximate factorials.S015 · premise_and_result_audit — The answer row is [k,coefficient,x exponent,y exponent]; do not swap the exponent columns.S014 · premise_and_result_audit — Check the coefficient independently with the integer Pascal recurrence, not approximate factorials.S013 · premise_and_result_audit — The answer row is [k,coefficient,x exponent,y exponent]; do not swap the exponent columns.S012 · premise_and_result_audit — Check the coefficient independently with the integer Pascal recurrence, not approximate factorials.S011 · premise_and_result_audit — The answer row is [k,coefficient,x exponent,y exponent]; do not swap the exponent columns.S010 · premise_and_result_audit — Check the coefficient independently with the integer Pascal recurrence, not approximate factorials.S009 · premise_and_result_audit — The answer row is [k,coefficient,x exponent,y exponent]; do not swap the exponent columns.S008 · premise_and_result_audit — Check the coefficient independently with the integer Pascal recurrence, not approximate factorials.S007 · premise_and_result_audit — The answer row is [k,coefficient,x exponent,y exponent]; do not swap the exponent columns.S006 · premise_and_result_audit — Check the coefficient independently with the integer Pascal recurrence, not approximate factorials.S005 · premise_and_result_audit — The answer row is [k,coefficient,x exponent,y exponent]; do not swap the exponent columns.S004 · premise_and_result_audit — Check the coefficient independently with the integer Pascal recurrence, not approximate factorials.S003 · premise_and_result_audit — The answer row is [k,coefficient,x exponent,y exponent]; do not swap the exponent columns.S002 · premise_and_result_audit — Check the coefficient independently with the integer Pascal recurrence, not approximate factorials.S001 · premise_and_result_audit — This is not an infinite expansion for a noninteger power or a claim for noncommuting multiplication.Result (7, [[0, 1, 7, 0], [1, 7, 6, 1], [2, 21, 5, 2], [3, 35, 4, 3], [4, 35, 3, 4], [5, 21, 2, 5], [6, 7, 1, 6], [7, 1, 0, 7]], complete_k_zero_through_n_coefficients) The full expansion consists of all displayed monomials, in the same order as the answer rows.
This question review and source binding Review date: 2026-10-24
Original questions, answers, step expressions, numeric ASTs and historical records are retained. Source candidate labels remain historical and are not overwritten as formal proof.
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