Explore related knowledge and questions →

Question 83: The Finite Expansion Includes Every k from Zero through n

On this page
  1. Original question and givens
  2. Definition and scope
  3. Step-by-step derivation
  4. Reverse checks
  5. Result
  6. This question review and source binding

Return to catalogue page 1

← Question derivation index · Original question batch

P250-0083 · q-20261014-advance-20261109-r05-binomial-theorem-0033

Original question and givens

Use natural exponent n=7, including0, in a commutative coefficient setting. Give (n, coefficient_exponent_rows, boundary).

  • G001 — Use natural exponent n=7, including0, in a commutative coefficient setting. Give (n, coefficient_exponent_rows, boundary).

Definition and scope

n is a nonnegative integer and x,y commute. For n=0 use the polynomial empty-product identity.

Step-by-step derivation

S001 · implies

Before

n=7≥0; x,y commute

After

(x+y)^7 is a finite product of 7 factors

Conditions: none

Choose x or y from each factor; commutativity permits grouping products by the number of y choices.

Step identifiers and dependencies

Rule: finite_product · Uses: G001

S002 · implies

Before

choose exactly 0 of 7 factors to contribute y

After

C(7,0)=5040/(1·5040)=1

Conditions: none

Count orderings of 7 positions and divide by reorderings within the 0 y positions and 7 x positions, giving coefficient 1.

Step identifiers and dependencies

Rule: subset_count · Uses: G001, S001

S003 · implies

Before

C(7,0)=1; choose y 0 times

After

1·x^7·y^0

Conditions: none

The x exponent is 7-0=7; the two exponents still sum to 7.

Step identifiers and dependencies

Rule: group_like_terms · Uses: G001, S002

S004 · implies

Before

choose exactly 1 of 7 factors to contribute y

After

C(7,1)=5040/(1·720)=7

Conditions: none

Count orderings of 7 positions and divide by reorderings within the 1 y positions and 6 x positions, giving coefficient 7.

Step identifiers and dependencies

Rule: subset_count · Uses: G001, S003

S005 · implies

Before

C(7,1)=7; choose y 1 times

After

7·x^6·y^1

Conditions: none

The x exponent is 7-1=6; the two exponents still sum to 7.

Step identifiers and dependencies

Rule: group_like_terms · Uses: G001, S004

S006 · implies

Before

choose exactly 2 of 7 factors to contribute y

After

C(7,2)=5040/(2·120)=21

Conditions: none

Count orderings of 7 positions and divide by reorderings within the 2 y positions and 5 x positions, giving coefficient 21.

Step identifiers and dependencies

Rule: subset_count · Uses: G001, S005

S007 · implies

Before

C(7,2)=21; choose y 2 times

After

21·x^5·y^2

Conditions: none

The x exponent is 7-2=5; the two exponents still sum to 7.

Step identifiers and dependencies

Rule: group_like_terms · Uses: G001, S006

S008 · implies

Before

choose exactly 3 of 7 factors to contribute y

After

C(7,3)=5040/(6·24)=35

Conditions: none

Count orderings of 7 positions and divide by reorderings within the 3 y positions and 4 x positions, giving coefficient 35.

Step identifiers and dependencies

Rule: subset_count · Uses: G001, S007

S009 · implies

Before

C(7,3)=35; choose y 3 times

After

35·x^4·y^3

Conditions: none

The x exponent is 7-3=4; the two exponents still sum to 7.

Step identifiers and dependencies

Rule: group_like_terms · Uses: G001, S008

S010 · implies

Before

choose exactly 4 of 7 factors to contribute y

After

C(7,4)=5040/(24·6)=35

Conditions: none

Count orderings of 7 positions and divide by reorderings within the 4 y positions and 3 x positions, giving coefficient 35.

Step identifiers and dependencies

Rule: subset_count · Uses: G001, S009

S011 · implies

Before

C(7,4)=35; choose y 4 times

After

35·x^3·y^4

Conditions: none

The x exponent is 7-4=3; the two exponents still sum to 7.

Step identifiers and dependencies

Rule: group_like_terms · Uses: G001, S010

S012 · implies

Before

choose exactly 5 of 7 factors to contribute y

After

C(7,5)=5040/(120·2)=21

Conditions: none

Count orderings of 7 positions and divide by reorderings within the 5 y positions and 2 x positions, giving coefficient 21.

Step identifiers and dependencies

Rule: subset_count · Uses: G001, S011

S013 · implies

Before

C(7,5)=21; choose y 5 times

After

21·x^2·y^5

Conditions: none

The x exponent is 7-5=2; the two exponents still sum to 7.

Step identifiers and dependencies

Rule: group_like_terms · Uses: G001, S012

S014 · implies

Before

choose exactly 6 of 7 factors to contribute y

After

C(7,6)=5040/(720·1)=7

Conditions: none

Count orderings of 7 positions and divide by reorderings within the 6 y positions and 1 x positions, giving coefficient 7.

Step identifiers and dependencies

Rule: subset_count · Uses: G001, S013

S015 · implies

Before

C(7,6)=7; choose y 6 times

After

7·x^1·y^6

Conditions: none

The x exponent is 7-6=1; the two exponents still sum to 7.

Step identifiers and dependencies

Rule: group_like_terms · Uses: G001, S014

S016 · implies

Before

choose exactly 7 of 7 factors to contribute y

After

C(7,7)=5040/(5040·1)=1

Conditions: none

Count orderings of 7 positions and divide by reorderings within the 7 y positions and 0 x positions, giving coefficient 1.

Step identifiers and dependencies

Rule: subset_count · Uses: G001, S015

S017 · implies

Before

C(7,7)=1; choose y 7 times

After

1·x^0·y^7

Conditions: none

The x exponent is 7-7=0; the two exponents still sum to 7.

Step identifiers and dependencies

Rule: group_like_terms · Uses: G001, S016

S018 · implies

Before

all k=0 through 7 have been accounted for

After

(x+y)^7=1·x^7·y^0 + 7·x^6·y^1 + 21·x^5·y^2 + 35·x^4·y^3 + 35·x^3·y^4 + 21·x^2·y^5 + 7·x^1·y^6 + 1·x^0·y^7

Conditions: none

Every x/y choice belongs to exactly one k class, so this is the complete finite expansion, not just endpoint terms.

Step identifiers and dependencies

Rule: collect_all_terms · Uses: G001, S017

Reverse checks

  • S018 · premise_and_result_audit — There are n+1 coefficient positions, with the complete range of k retained.
  • S017 · premise_and_result_audit — The answer row is [k,coefficient,x exponent,y exponent]; do not swap the exponent columns.
  • S016 · premise_and_result_audit — Check the coefficient independently with the integer Pascal recurrence, not approximate factorials.
  • S015 · premise_and_result_audit — The answer row is [k,coefficient,x exponent,y exponent]; do not swap the exponent columns.
  • S014 · premise_and_result_audit — Check the coefficient independently with the integer Pascal recurrence, not approximate factorials.
  • S013 · premise_and_result_audit — The answer row is [k,coefficient,x exponent,y exponent]; do not swap the exponent columns.
  • S012 · premise_and_result_audit — Check the coefficient independently with the integer Pascal recurrence, not approximate factorials.
  • S011 · premise_and_result_audit — The answer row is [k,coefficient,x exponent,y exponent]; do not swap the exponent columns.
  • S010 · premise_and_result_audit — Check the coefficient independently with the integer Pascal recurrence, not approximate factorials.
  • S009 · premise_and_result_audit — The answer row is [k,coefficient,x exponent,y exponent]; do not swap the exponent columns.
  • S008 · premise_and_result_audit — Check the coefficient independently with the integer Pascal recurrence, not approximate factorials.
  • S007 · premise_and_result_audit — The answer row is [k,coefficient,x exponent,y exponent]; do not swap the exponent columns.
  • S006 · premise_and_result_audit — Check the coefficient independently with the integer Pascal recurrence, not approximate factorials.
  • S005 · premise_and_result_audit — The answer row is [k,coefficient,x exponent,y exponent]; do not swap the exponent columns.
  • S004 · premise_and_result_audit — Check the coefficient independently with the integer Pascal recurrence, not approximate factorials.
  • S003 · premise_and_result_audit — The answer row is [k,coefficient,x exponent,y exponent]; do not swap the exponent columns.
  • S002 · premise_and_result_audit — Check the coefficient independently with the integer Pascal recurrence, not approximate factorials.
  • S001 · premise_and_result_audit — This is not an infinite expansion for a noninteger power or a claim for noncommuting multiplication.

Result

(7, [[0, 1, 7, 0], [1, 7, 6, 1], [2, 21, 5, 2], [3, 35, 4, 3], [4, 35, 3, 4], [5, 21, 2, 5], [6, 7, 1, 6], [7, 1, 0, 7]], complete_k_zero_through_n_coefficients)

The full expansion consists of all displayed monomials, in the same order as the answer rows.

This question review and source binding

Review date: 2026-10-24

Original questions, answers, step expressions, numeric ASTs and historical records are retained. Source candidate labels remain historical and are not overwritten as formal proof.

Source hashes and review receipts
  • input commit: 0f7be61e2c22317a4075561dc822c87d881a50db
  • original question SHA-256: f438c1c6546cfeb2051dba9f214004bdc8d20956d93d4bcf689a8c5b1088d7b5
  • candidate record SHA-256: 8f86e2b5e0f61e15db12b08e5bfba3f3384be4c7fd8093ce693ec87232464866
  • semantic review receipt SHA-256: 4727d1bd957a9b7f6cadb7972ddb5ab80a31f5259dc5394c1dff2b71944ed36b
  • question-first witness SHA-256: 51e18649133238ac992229f6e16542a5f3af53ca73b2262ab0524508ea937dee
  • Lean: NOT_RUN · human review: NOT_PERFORMED
Same-source full JSON