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Question 27911: Regular Equality Conditions Are Necessary, Not Sufficient, and Not Inequality KKT

On this page
  1. Original question and givens
  2. Definition and scope
  3. Step-by-step derivation
  4. Reverse checks
  5. Result
  6. This question review and source binding

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← Question derivation index · Original question batch

R0054-27911 · q-20261015-pulse-20261119-r04-0086

Original question and givens

Use mode=infeasible_point, complete model={"constraint_gradient":[1,11],"constraint_rhs":10,"point":[11,0]}. Give (mode, constraint_gradient, constraint_rhs, point, constraint_value, feasible, boundary).

  • G001 — Use mode=infeasible_point, complete model={"constraint_gradient":[1,11],"constraint_rhs":10,"point":[11,0]}. Give (mode, constraint_gradient, constraint_rhs, point, constraint_value, feasible, boundary).

Definition and scope

Use the original question domain, assumptions and cited MKO definitions. This item has second-context mathematical and bilingual review, with the model, answer and every arithmetic step independently recomputed from the original parameters; the source question remains a candidate.

Step-by-step derivation

S001 · implies

Before

source roles = [lagrange-boundary]

After

derived = [[mode, constraint_gradient, constraint_rhs, point, constraint_value, feasible, boundary]]

Conditions: none

List the complete operation/mode field order without JavaScript or answer-shape inference;Boolean,string,null and an unclaimed result remain distinct.

Step identifiers and dependencies

Rule: source_ordered_fields_without_JS · Uses: G001

S002 · calculation

Before

Lagrange boundary ORIGINAL constraint value ORIGINAL product0 := mul(1, 11)

After

Lagrange boundary ORIGINAL constraint value ORIGINAL product0 = 11

Conditions: none

Substitute original roles and established intermediates exactly,not approximations or internally consistent changed operands;extra teaching algebra adds no source-domain gate.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S001

S003 · calculation

Before

Lagrange boundary ORIGINAL constraint value ORIGINAL running sum0 := sum(0, 11)

After

Lagrange boundary ORIGINAL constraint value ORIGINAL running sum0 = 11

Conditions: none

Substitute original roles and established intermediates exactly,not approximations or internally consistent changed operands;extra teaching algebra adds no source-domain gate.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S002

S004 · calculation

Before

Lagrange boundary ORIGINAL constraint value ORIGINAL product1 := mul(11, 0)

After

Lagrange boundary ORIGINAL constraint value ORIGINAL product1 = 0

Conditions: none

Substitute original roles and established intermediates exactly,not approximations or internally consistent changed operands;extra teaching algebra adds no source-domain gate.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S003

S005 · calculation

Before

Lagrange boundary ORIGINAL constraint value ORIGINAL running sum1 := sum(11, 0)

After

Lagrange boundary ORIGINAL constraint value ORIGINAL running sum1 = 11

Conditions: none

Substitute original roles and established intermediates exactly,not approximations or internally consistent changed operands;extra teaching algebra adds no source-domain gate.

Step identifiers and dependencies

Rule: exact_rational_arithmetic · Uses: G001, S004

S006 · implies

Before

source roles = [[1, 11], 10, [11, 0]]

After

derived = [11, No]

Conditions: none

The complete dot product actually differs from rhs,hence infeasibility.This mode adds no nonzero-normal condition;a zero normal with nonzero rhs is also a witness.Stationarity cannot repair missing feasibility.

Step identifiers and dependencies

Rule: Lagrange_ACTUAL_infeasibility_not_repaired_by_stationarity · Uses: G001, S005

Reverse checks

  • S006 · premise_and_result_audit — Reverse-check original data,operands,complete scope and premises;finite witnesses,conditional theorem use and formal proof remain distinct.
  • S005 · premise_and_result_audit — Recompute Lagrange boundary ORIGINAL constraint value ORIGINAL running sum1 with exact rational arithmetic, not rounded decimals.
  • S004 · premise_and_result_audit — Recompute Lagrange boundary ORIGINAL constraint value ORIGINAL product1 with exact rational arithmetic, not rounded decimals.
  • S003 · premise_and_result_audit — Recompute Lagrange boundary ORIGINAL constraint value ORIGINAL running sum0 with exact rational arithmetic, not rounded decimals.
  • S002 · premise_and_result_audit — Recompute Lagrange boundary ORIGINAL constraint value ORIGINAL product0 with exact rational arithmetic, not rounded decimals.
  • S001 · premise_and_result_audit — Reverse-check original data,operands,complete scope and premises;finite witnesses,conditional theorem use and formal proof remain distinct.

Result

(infeasible_point, [1, 11], 10, [11, 0], 11, No, stationarity_never_repairs_missing_feasibility)

The full substitutions and premise checks give the original answer; source identity,format and status are unchanged.

This question review and source binding

Review date: 2026-10-26

Original questions, answers, step expressions, numeric ASTs and historical records are retained. Source candidate labels remain historical and are not overwritten as formal proof.

Source hashes and review receipts
  • input commit: 0f7be61e2c22317a4075561dc822c87d881a50db
  • original question SHA-256: d1485a2d7ee1ecd6851f327a4cc8e5a3c1ba8facd7cb8663496783805c739ce4
  • candidate record SHA-256: f5277ff2c166530f3a6044a1340a1ca6cd07200c4a6233a701366d21f4f7fb1f
  • semantic review receipt SHA-256: 0a76d8e93c08bb16998a0483f3dfc0504f269fc3e1982e6cd868cab0a2856d54
  • question-first witness SHA-256: 09127b736c225714dfa0b7ceb0e6a6e66df27438b480cad8217d3c2f99ce9437
  • Lean: NOT_RUN · human review: NOT_PERFORMED
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