連續實值分布函數基礎 · 脈衝 R04
本批已通過 Schema、去重、來源快照與獨立答案重算；仍未標記為人工審定。
本題庫已有對應的中英逐步詳解。原題的 candidate 與英文 ai_candidate 狀態保留；AI 覆核、有限計算與 Lean 形式證明分開標示。
batch-20261014-advance-20261111-r04-continuous-real-distribution-function-foundations · 2026-10-14 · 100 題
欄序為來源綁定的呈現補充；原始 JSONL 與數學答案不變。
欄序與來源綁定資料
1. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-piecewise-linear-qualification；資料={"knots":[-2,0,2],"values":[0,[1,2],1]}。請依 [knots, values, continuous, nondecreasing, right_continuous, endpoint_limits_0_1, certificate] 欄序回答。
查看答案與解釋
([-2, 0, 2], [0, 1/2, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)
Wave6第五層核對=([-2, 0, 2], [0, 1/2, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-piecewise-linear-qualification · candidate
2. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-piecewise-linear-qualification；資料={"knots":[-3,0,3],"values":[0,[2,3],1]}。請依 [knots, values, continuous, nondecreasing, right_continuous, endpoint_limits_0_1, certificate] 欄序回答。
查看答案與解釋
([-3, 0, 3], [0, 2/3, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)
Wave6第五層核對=([-3, 0, 3], [0, 2/3, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-piecewise-linear-qualification · candidate
3. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-piecewise-linear-qualification；資料={"knots":[-4,0,4],"values":[0,[3,4],1]}。請依 [knots, values, continuous, nondecreasing, right_continuous, endpoint_limits_0_1, certificate] 欄序回答。
查看答案與解釋
([-4, 0, 4], [0, 3/4, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)
Wave6第五層核對=([-4, 0, 4], [0, 3/4, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-piecewise-linear-qualification · candidate
4. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-piecewise-linear-qualification；資料={"knots":[-5,0,5],"values":[0,[4,5],1]}。請依 [knots, values, continuous, nondecreasing, right_continuous, endpoint_limits_0_1, certificate] 欄序回答。
查看答案與解釋
([-5, 0, 5], [0, 4/5, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)
Wave6第五層核對=([-5, 0, 5], [0, 4/5, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-piecewise-linear-qualification · candidate
5. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-piecewise-linear-qualification；資料={"knots":[-6,0,6],"values":[0,[5,6],1]}。請依 [knots, values, continuous, nondecreasing, right_continuous, endpoint_limits_0_1, certificate] 欄序回答。
查看答案與解釋
([-6, 0, 6], [0, 5/6, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)
Wave6第五層核對=([-6, 0, 6], [0, 5/6, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-piecewise-linear-qualification · candidate
6. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-piecewise-linear-qualification；資料={"knots":[-7,0,7],"values":[0,[6,7],1]}。請依 [knots, values, continuous, nondecreasing, right_continuous, endpoint_limits_0_1, certificate] 欄序回答。
查看答案與解釋
([-7, 0, 7], [0, 6/7, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)
Wave6第五層核對=([-7, 0, 7], [0, 6/7, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-piecewise-linear-qualification · candidate
7. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-piecewise-linear-qualification；資料={"knots":[-8,0,8],"values":[0,[7,8],1]}。請依 [knots, values, continuous, nondecreasing, right_continuous, endpoint_limits_0_1, certificate] 欄序回答。
查看答案與解釋
([-8, 0, 8], [0, 7/8, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)
Wave6第五層核對=([-8, 0, 8], [0, 7/8, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-piecewise-linear-qualification · candidate
8. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-piecewise-linear-qualification；資料={"knots":[-9,0,9],"values":[0,[8,9],1]}。請依 [knots, values, continuous, nondecreasing, right_continuous, endpoint_limits_0_1, certificate] 欄序回答。
查看答案與解釋
([-9, 0, 9], [0, 8/9, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)
Wave6第五層核對=([-9, 0, 9], [0, 8/9, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-piecewise-linear-qualification · candidate
9. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-piecewise-linear-qualification；資料={"knots":[-10,0,10],"values":[0,[9,10],1]}。請依 [knots, values, continuous, nondecreasing, right_continuous, endpoint_limits_0_1, certificate] 欄序回答。
查看答案與解釋
([-10, 0, 10], [0, 9/10, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)
Wave6第五層核對=([-10, 0, 10], [0, 9/10, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-piecewise-linear-qualification · candidate
10. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-piecewise-linear-qualification；資料={"knots":[-11,0,11],"values":[0,[10,11],1]}。請依 [knots, values, continuous, nondecreasing, right_continuous, endpoint_limits_0_1, certificate] 欄序回答。
查看答案與解釋
([-11, 0, 11], [0, 10/11, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)
Wave6第五層核對=([-11, 0, 11], [0, 10/11, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-piecewise-linear-qualification · candidate
11. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-piecewise-linear-qualification；資料={"knots":[-12,0,12],"values":[0,[11,12],1]}。請依 [knots, values, continuous, nondecreasing, right_continuous, endpoint_limits_0_1, certificate] 欄序回答。
查看答案與解釋
([-12, 0, 12], [0, 11/12, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)
Wave6第五層核對=([-12, 0, 12], [0, 11/12, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-piecewise-linear-qualification · candidate
12. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-piecewise-linear-qualification；資料={"knots":[-13,0,13],"values":[0,[12,13],1]}。請依 [knots, values, continuous, nondecreasing, right_continuous, endpoint_limits_0_1, certificate] 欄序回答。
查看答案與解釋
([-13, 0, 13], [0, 12/13, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)
Wave6第五層核對=([-13, 0, 13], [0, 12/13, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-piecewise-linear-qualification · candidate
13. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-piecewise-linear-qualification；資料={"knots":[-14,0,14],"values":[0,[13,14],1]}。請依 [knots, values, continuous, nondecreasing, right_continuous, endpoint_limits_0_1, certificate] 欄序回答。
查看答案與解釋
([-14, 0, 14], [0, 13/14, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)
Wave6第五層核對=([-14, 0, 14], [0, 13/14, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-piecewise-linear-qualification · candidate
14. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-piecewise-linear-qualification；資料={"knots":[-15,0,15],"values":[0,[14,15],1]}。請依 [knots, values, continuous, nondecreasing, right_continuous, endpoint_limits_0_1, certificate] 欄序回答。
查看答案與解釋
([-15, 0, 15], [0, 14/15, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)
Wave6第五層核對=([-15, 0, 15], [0, 14/15, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-piecewise-linear-qualification · candidate
15. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-piecewise-linear-qualification；資料={"knots":[-16,0,16],"values":[0,[15,16],1]}。請依 [knots, values, continuous, nondecreasing, right_continuous, endpoint_limits_0_1, certificate] 欄序回答。
查看答案與解釋
([-16, 0, 16], [0, 15/16, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)
Wave6第五層核對=([-16, 0, 16], [0, 15/16, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-piecewise-linear-qualification · candidate
16. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-piecewise-linear-qualification；資料={"knots":[-17,0,17],"values":[0,[16,17],1]}。請依 [knots, values, continuous, nondecreasing, right_continuous, endpoint_limits_0_1, certificate] 欄序回答。
查看答案與解釋
([-17, 0, 17], [0, 16/17, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)
Wave6第五層核對=([-17, 0, 17], [0, 16/17, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-piecewise-linear-qualification · candidate
17. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-piecewise-linear-qualification；資料={"knots":[-18,0,18],"values":[0,[17,18],1]}。請依 [knots, values, continuous, nondecreasing, right_continuous, endpoint_limits_0_1, certificate] 欄序回答。
查看答案與解釋
([-18, 0, 18], [0, 17/18, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)
Wave6第五層核對=([-18, 0, 18], [0, 17/18, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-piecewise-linear-qualification · candidate
18. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-piecewise-linear-qualification；資料={"knots":[-19,0,19],"values":[0,[18,19],1]}。請依 [knots, values, continuous, nondecreasing, right_continuous, endpoint_limits_0_1, certificate] 欄序回答。
查看答案與解釋
([-19, 0, 19], [0, 18/19, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)
Wave6第五層核對=([-19, 0, 19], [0, 18/19, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-piecewise-linear-qualification · candidate
19. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-piecewise-linear-qualification；資料={"knots":[-20,0,20],"values":[0,[19,20],1]}。請依 [knots, values, continuous, nondecreasing, right_continuous, endpoint_limits_0_1, certificate] 欄序回答。
查看答案與解釋
([-20, 0, 20], [0, 19/20, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)
Wave6第五層核對=([-20, 0, 20], [0, 19/20, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-piecewise-linear-qualification · candidate
20. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-piecewise-linear-qualification；資料={"knots":[-21,0,21],"values":[0,[20,21],1]}。請依 [knots, values, continuous, nondecreasing, right_continuous, endpoint_limits_0_1, certificate] 欄序回答。
查看答案與解釋
([-21, 0, 21], [0, 20/21, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)
Wave6第五層核對=([-21, 0, 21], [0, 20/21, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-piecewise-linear-qualification · candidate
21. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-piecewise-linear-qualification；資料={"knots":[-22,0,22],"values":[0,[21,22],1]}。請依 [knots, values, continuous, nondecreasing, right_continuous, endpoint_limits_0_1, certificate] 欄序回答。
查看答案與解釋
([-22, 0, 22], [0, 21/22, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)
Wave6第五層核對=([-22, 0, 22], [0, 21/22, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-piecewise-linear-qualification · candidate
22. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-piecewise-linear-qualification；資料={"knots":[-23,0,23],"values":[0,[22,23],1]}。請依 [knots, values, continuous, nondecreasing, right_continuous, endpoint_limits_0_1, certificate] 欄序回答。
查看答案與解釋
([-23, 0, 23], [0, 22/23, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)
Wave6第五層核對=([-23, 0, 23], [0, 22/23, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-piecewise-linear-qualification · candidate
23. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-piecewise-linear-qualification；資料={"knots":[-24,0,24],"values":[0,[23,24],1]}。請依 [knots, values, continuous, nondecreasing, right_continuous, endpoint_limits_0_1, certificate] 欄序回答。
查看答案與解釋
([-24, 0, 24], [0, 23/24, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)
Wave6第五層核對=([-24, 0, 24], [0, 23/24, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-piecewise-linear-qualification · candidate
24. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-piecewise-linear-qualification；資料={"knots":[-25,0,25],"values":[0,[24,25],1]}。請依 [knots, values, continuous, nondecreasing, right_continuous, endpoint_limits_0_1, certificate] 欄序回答。
查看答案與解釋
([-25, 0, 25], [0, 24/25, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)
Wave6第五層核對=([-25, 0, 25], [0, 24/25, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-piecewise-linear-qualification · candidate
25. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-piecewise-linear-qualification；資料={"knots":[-26,0,26],"values":[0,[25,26],1]}。請依 [knots, values, continuous, nondecreasing, right_continuous, endpoint_limits_0_1, certificate] 欄序回答。
查看答案與解釋
([-26, 0, 26], [0, 25/26, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)
Wave6第五層核對=([-26, 0, 26], [0, 25/26, 1], 是, 是, 是, 是, linear_interpolation_is_continuous_and_flat_intervals_are_allowed)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-piecewise-linear-qualification · candidate
26. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-monotone-endpoint-audit；資料={"knots":[-2,0,2],"values":[0,[1,2],1],"query_points":[-3,0,3]}。請依 [query_value_rows, nondecreasing_sample, left_tail_value, right_tail_value, certificate] 欄序回答。
查看答案與解釋
([[-3, 0], [0, 1/2], [3, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)
Wave6第五層核對=([[-3, 0], [0, 1/2], [3, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-monotone-endpoint-audit · candidate
27. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-monotone-endpoint-audit；資料={"knots":[-3,0,3],"values":[0,[2,3],1],"query_points":[-4,0,4]}。請依 [query_value_rows, nondecreasing_sample, left_tail_value, right_tail_value, certificate] 欄序回答。
查看答案與解釋
([[-4, 0], [0, 2/3], [4, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)
Wave6第五層核對=([[-4, 0], [0, 2/3], [4, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-monotone-endpoint-audit · candidate
28. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-monotone-endpoint-audit；資料={"knots":[-4,0,4],"values":[0,[3,4],1],"query_points":[-5,0,5]}。請依 [query_value_rows, nondecreasing_sample, left_tail_value, right_tail_value, certificate] 欄序回答。
查看答案與解釋
([[-5, 0], [0, 3/4], [5, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)
Wave6第五層核對=([[-5, 0], [0, 3/4], [5, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-monotone-endpoint-audit · candidate
29. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-monotone-endpoint-audit；資料={"knots":[-5,0,5],"values":[0,[4,5],1],"query_points":[-6,0,6]}。請依 [query_value_rows, nondecreasing_sample, left_tail_value, right_tail_value, certificate] 欄序回答。
查看答案與解釋
([[-6, 0], [0, 4/5], [6, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)
Wave6第五層核對=([[-6, 0], [0, 4/5], [6, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-monotone-endpoint-audit · candidate
30. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-monotone-endpoint-audit；資料={"knots":[-6,0,6],"values":[0,[5,6],1],"query_points":[-7,0,7]}。請依 [query_value_rows, nondecreasing_sample, left_tail_value, right_tail_value, certificate] 欄序回答。
查看答案與解釋
([[-7, 0], [0, 5/6], [7, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)
Wave6第五層核對=([[-7, 0], [0, 5/6], [7, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-monotone-endpoint-audit · candidate
31. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-monotone-endpoint-audit；資料={"knots":[-7,0,7],"values":[0,[6,7],1],"query_points":[-8,0,8]}。請依 [query_value_rows, nondecreasing_sample, left_tail_value, right_tail_value, certificate] 欄序回答。
查看答案與解釋
([[-8, 0], [0, 6/7], [8, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)
Wave6第五層核對=([[-8, 0], [0, 6/7], [8, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-monotone-endpoint-audit · candidate
32. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-monotone-endpoint-audit；資料={"knots":[-8,0,8],"values":[0,[7,8],1],"query_points":[-9,0,9]}。請依 [query_value_rows, nondecreasing_sample, left_tail_value, right_tail_value, certificate] 欄序回答。
查看答案與解釋
([[-9, 0], [0, 7/8], [9, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)
Wave6第五層核對=([[-9, 0], [0, 7/8], [9, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-monotone-endpoint-audit · candidate
33. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-monotone-endpoint-audit；資料={"knots":[-9,0,9],"values":[0,[8,9],1],"query_points":[-10,0,10]}。請依 [query_value_rows, nondecreasing_sample, left_tail_value, right_tail_value, certificate] 欄序回答。
查看答案與解釋
([[-10, 0], [0, 8/9], [10, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)
Wave6第五層核對=([[-10, 0], [0, 8/9], [10, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-monotone-endpoint-audit · candidate
34. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-monotone-endpoint-audit；資料={"knots":[-10,0,10],"values":[0,[9,10],1],"query_points":[-11,0,11]}。請依 [query_value_rows, nondecreasing_sample, left_tail_value, right_tail_value, certificate] 欄序回答。
查看答案與解釋
([[-11, 0], [0, 9/10], [11, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)
Wave6第五層核對=([[-11, 0], [0, 9/10], [11, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-monotone-endpoint-audit · candidate
35. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-monotone-endpoint-audit；資料={"knots":[-11,0,11],"values":[0,[10,11],1],"query_points":[-12,0,12]}。請依 [query_value_rows, nondecreasing_sample, left_tail_value, right_tail_value, certificate] 欄序回答。
查看答案與解釋
([[-12, 0], [0, 10/11], [12, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)
Wave6第五層核對=([[-12, 0], [0, 10/11], [12, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-monotone-endpoint-audit · candidate
36. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-monotone-endpoint-audit；資料={"knots":[-12,0,12],"values":[0,[11,12],1],"query_points":[-13,0,13]}。請依 [query_value_rows, nondecreasing_sample, left_tail_value, right_tail_value, certificate] 欄序回答。
查看答案與解釋
([[-13, 0], [0, 11/12], [13, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)
Wave6第五層核對=([[-13, 0], [0, 11/12], [13, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-monotone-endpoint-audit · candidate
37. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-monotone-endpoint-audit；資料={"knots":[-13,0,13],"values":[0,[12,13],1],"query_points":[-14,0,14]}。請依 [query_value_rows, nondecreasing_sample, left_tail_value, right_tail_value, certificate] 欄序回答。
查看答案與解釋
([[-14, 0], [0, 12/13], [14, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)
Wave6第五層核對=([[-14, 0], [0, 12/13], [14, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-monotone-endpoint-audit · candidate
38. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-monotone-endpoint-audit；資料={"knots":[-14,0,14],"values":[0,[13,14],1],"query_points":[-15,0,15]}。請依 [query_value_rows, nondecreasing_sample, left_tail_value, right_tail_value, certificate] 欄序回答。
查看答案與解釋
([[-15, 0], [0, 13/14], [15, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)
Wave6第五層核對=([[-15, 0], [0, 13/14], [15, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-monotone-endpoint-audit · candidate
39. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-monotone-endpoint-audit；資料={"knots":[-15,0,15],"values":[0,[14,15],1],"query_points":[-16,0,16]}。請依 [query_value_rows, nondecreasing_sample, left_tail_value, right_tail_value, certificate] 欄序回答。
查看答案與解釋
([[-16, 0], [0, 14/15], [16, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)
Wave6第五層核對=([[-16, 0], [0, 14/15], [16, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-monotone-endpoint-audit · candidate
40. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-monotone-endpoint-audit；資料={"knots":[-16,0,16],"values":[0,[15,16],1],"query_points":[-17,0,17]}。請依 [query_value_rows, nondecreasing_sample, left_tail_value, right_tail_value, certificate] 欄序回答。
查看答案與解釋
([[-17, 0], [0, 15/16], [17, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)
Wave6第五層核對=([[-17, 0], [0, 15/16], [17, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-monotone-endpoint-audit · candidate
41. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-monotone-endpoint-audit；資料={"knots":[-17,0,17],"values":[0,[16,17],1],"query_points":[-18,0,18]}。請依 [query_value_rows, nondecreasing_sample, left_tail_value, right_tail_value, certificate] 欄序回答。
查看答案與解釋
([[-18, 0], [0, 16/17], [18, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)
Wave6第五層核對=([[-18, 0], [0, 16/17], [18, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-monotone-endpoint-audit · candidate
42. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-monotone-endpoint-audit；資料={"knots":[-18,0,18],"values":[0,[17,18],1],"query_points":[-19,0,19]}。請依 [query_value_rows, nondecreasing_sample, left_tail_value, right_tail_value, certificate] 欄序回答。
查看答案與解釋
([[-19, 0], [0, 17/18], [19, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)
Wave6第五層核對=([[-19, 0], [0, 17/18], [19, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-monotone-endpoint-audit · candidate
43. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-monotone-endpoint-audit；資料={"knots":[-19,0,19],"values":[0,[18,19],1],"query_points":[-20,0,20]}。請依 [query_value_rows, nondecreasing_sample, left_tail_value, right_tail_value, certificate] 欄序回答。
查看答案與解釋
([[-20, 0], [0, 18/19], [20, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)
Wave6第五層核對=([[-20, 0], [0, 18/19], [20, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-monotone-endpoint-audit · candidate
44. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-monotone-endpoint-audit；資料={"knots":[-20,0,20],"values":[0,[19,20],1],"query_points":[-21,0,21]}。請依 [query_value_rows, nondecreasing_sample, left_tail_value, right_tail_value, certificate] 欄序回答。
查看答案與解釋
([[-21, 0], [0, 19/20], [21, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)
Wave6第五層核對=([[-21, 0], [0, 19/20], [21, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-monotone-endpoint-audit · candidate
45. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-monotone-endpoint-audit；資料={"knots":[-21,0,21],"values":[0,[20,21],1],"query_points":[-22,0,22]}。請依 [query_value_rows, nondecreasing_sample, left_tail_value, right_tail_value, certificate] 欄序回答。
查看答案與解釋
([[-22, 0], [0, 20/21], [22, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)
Wave6第五層核對=([[-22, 0], [0, 20/21], [22, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-monotone-endpoint-audit · candidate
46. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-monotone-endpoint-audit；資料={"knots":[-22,0,22],"values":[0,[21,22],1],"query_points":[-23,0,23]}。請依 [query_value_rows, nondecreasing_sample, left_tail_value, right_tail_value, certificate] 欄序回答。
查看答案與解釋
([[-23, 0], [0, 21/22], [23, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)
Wave6第五層核對=([[-23, 0], [0, 21/22], [23, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-monotone-endpoint-audit · candidate
47. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-monotone-endpoint-audit；資料={"knots":[-23,0,23],"values":[0,[22,23],1],"query_points":[-24,0,24]}。請依 [query_value_rows, nondecreasing_sample, left_tail_value, right_tail_value, certificate] 欄序回答。
查看答案與解釋
([[-24, 0], [0, 22/23], [24, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)
Wave6第五層核對=([[-24, 0], [0, 22/23], [24, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-monotone-endpoint-audit · candidate
48. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-monotone-endpoint-audit；資料={"knots":[-24,0,24],"values":[0,[23,24],1],"query_points":[-25,0,25]}。請依 [query_value_rows, nondecreasing_sample, left_tail_value, right_tail_value, certificate] 欄序回答。
查看答案與解釋
([[-25, 0], [0, 23/24], [25, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)
Wave6第五層核對=([[-25, 0], [0, 23/24], [25, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-monotone-endpoint-audit · candidate
49. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-monotone-endpoint-audit；資料={"knots":[-25,0,25],"values":[0,[24,25],1],"query_points":[-26,0,26]}。請依 [query_value_rows, nondecreasing_sample, left_tail_value, right_tail_value, certificate] 欄序回答。
查看答案與解釋
([[-26, 0], [0, 24/25], [26, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)
Wave6第五層核對=([[-26, 0], [0, 24/25], [26, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-monotone-endpoint-audit · candidate
50. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-monotone-endpoint-audit；資料={"knots":[-26,0,26],"values":[0,[25,26],1],"query_points":[-27,0,27]}。請依 [query_value_rows, nondecreasing_sample, left_tail_value, right_tail_value, certificate] 欄序回答。
查看答案與解釋
([[-27, 0], [0, 25/26], [27, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)
Wave6第五層核對=([[-27, 0], [0, 25/26], [27, 1]], 是, 0, 1, nondecreasing_with_left_zero_and_right_one_limits)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-monotone-endpoint-audit · candidate
51. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-zero-jump-atomlessness；資料={"knots":[-2,0,2],"values":[0,[1,2],1],"point":0}。請依 [point, F_at_point, F_left_limit, singleton_probability, zero_jump, certificate] 欄序回答。
查看答案與解釋
(0, 1/2, 1/2, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)
Wave6第五層核對=(0, 1/2, 1/2, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-zero-jump-atomlessness · candidate
52. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-zero-jump-atomlessness；資料={"knots":[-3,0,3],"values":[0,[2,3],1],"point":0}。請依 [point, F_at_point, F_left_limit, singleton_probability, zero_jump, certificate] 欄序回答。
查看答案與解釋
(0, 2/3, 2/3, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)
Wave6第五層核對=(0, 2/3, 2/3, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-zero-jump-atomlessness · candidate
53. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-zero-jump-atomlessness；資料={"knots":[-4,0,4],"values":[0,[3,4],1],"point":0}。請依 [point, F_at_point, F_left_limit, singleton_probability, zero_jump, certificate] 欄序回答。
查看答案與解釋
(0, 3/4, 3/4, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)
Wave6第五層核對=(0, 3/4, 3/4, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-zero-jump-atomlessness · candidate
54. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-zero-jump-atomlessness；資料={"knots":[-5,0,5],"values":[0,[4,5],1],"point":0}。請依 [point, F_at_point, F_left_limit, singleton_probability, zero_jump, certificate] 欄序回答。
查看答案與解釋
(0, 4/5, 4/5, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)
Wave6第五層核對=(0, 4/5, 4/5, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-zero-jump-atomlessness · candidate
55. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-zero-jump-atomlessness；資料={"knots":[-6,0,6],"values":[0,[5,6],1],"point":0}。請依 [point, F_at_point, F_left_limit, singleton_probability, zero_jump, certificate] 欄序回答。
查看答案與解釋
(0, 5/6, 5/6, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)
Wave6第五層核對=(0, 5/6, 5/6, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-zero-jump-atomlessness · candidate
56. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-zero-jump-atomlessness；資料={"knots":[-7,0,7],"values":[0,[6,7],1],"point":0}。請依 [point, F_at_point, F_left_limit, singleton_probability, zero_jump, certificate] 欄序回答。
查看答案與解釋
(0, 6/7, 6/7, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)
Wave6第五層核對=(0, 6/7, 6/7, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-zero-jump-atomlessness · candidate
57. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-zero-jump-atomlessness；資料={"knots":[-8,0,8],"values":[0,[7,8],1],"point":0}。請依 [point, F_at_point, F_left_limit, singleton_probability, zero_jump, certificate] 欄序回答。
查看答案與解釋
(0, 7/8, 7/8, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)
Wave6第五層核對=(0, 7/8, 7/8, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-zero-jump-atomlessness · candidate
58. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-zero-jump-atomlessness；資料={"knots":[-9,0,9],"values":[0,[8,9],1],"point":0}。請依 [point, F_at_point, F_left_limit, singleton_probability, zero_jump, certificate] 欄序回答。
查看答案與解釋
(0, 8/9, 8/9, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)
Wave6第五層核對=(0, 8/9, 8/9, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-zero-jump-atomlessness · candidate
59. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-zero-jump-atomlessness；資料={"knots":[-10,0,10],"values":[0,[9,10],1],"point":0}。請依 [point, F_at_point, F_left_limit, singleton_probability, zero_jump, certificate] 欄序回答。
查看答案與解釋
(0, 9/10, 9/10, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)
Wave6第五層核對=(0, 9/10, 9/10, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-zero-jump-atomlessness · candidate
60. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-zero-jump-atomlessness；資料={"knots":[-11,0,11],"values":[0,[10,11],1],"point":0}。請依 [point, F_at_point, F_left_limit, singleton_probability, zero_jump, certificate] 欄序回答。
查看答案與解釋
(0, 10/11, 10/11, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)
Wave6第五層核對=(0, 10/11, 10/11, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-zero-jump-atomlessness · candidate
61. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-zero-jump-atomlessness；資料={"knots":[-12,0,12],"values":[0,[11,12],1],"point":0}。請依 [point, F_at_point, F_left_limit, singleton_probability, zero_jump, certificate] 欄序回答。
查看答案與解釋
(0, 11/12, 11/12, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)
Wave6第五層核對=(0, 11/12, 11/12, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-zero-jump-atomlessness · candidate
62. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-zero-jump-atomlessness；資料={"knots":[-13,0,13],"values":[0,[12,13],1],"point":0}。請依 [point, F_at_point, F_left_limit, singleton_probability, zero_jump, certificate] 欄序回答。
查看答案與解釋
(0, 12/13, 12/13, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)
Wave6第五層核對=(0, 12/13, 12/13, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-zero-jump-atomlessness · candidate
63. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-zero-jump-atomlessness；資料={"knots":[-14,0,14],"values":[0,[13,14],1],"point":0}。請依 [point, F_at_point, F_left_limit, singleton_probability, zero_jump, certificate] 欄序回答。
查看答案與解釋
(0, 13/14, 13/14, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)
Wave6第五層核對=(0, 13/14, 13/14, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-zero-jump-atomlessness · candidate
64. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-zero-jump-atomlessness；資料={"knots":[-15,0,15],"values":[0,[14,15],1],"point":0}。請依 [point, F_at_point, F_left_limit, singleton_probability, zero_jump, certificate] 欄序回答。
查看答案與解釋
(0, 14/15, 14/15, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)
Wave6第五層核對=(0, 14/15, 14/15, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-zero-jump-atomlessness · candidate
65. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-zero-jump-atomlessness；資料={"knots":[-16,0,16],"values":[0,[15,16],1],"point":0}。請依 [point, F_at_point, F_left_limit, singleton_probability, zero_jump, certificate] 欄序回答。
查看答案與解釋
(0, 15/16, 15/16, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)
Wave6第五層核對=(0, 15/16, 15/16, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-zero-jump-atomlessness · candidate
66. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-zero-jump-atomlessness；資料={"knots":[-17,0,17],"values":[0,[16,17],1],"point":0}。請依 [point, F_at_point, F_left_limit, singleton_probability, zero_jump, certificate] 欄序回答。
查看答案與解釋
(0, 16/17, 16/17, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)
Wave6第五層核對=(0, 16/17, 16/17, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-zero-jump-atomlessness · candidate
67. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-zero-jump-atomlessness；資料={"knots":[-18,0,18],"values":[0,[17,18],1],"point":0}。請依 [point, F_at_point, F_left_limit, singleton_probability, zero_jump, certificate] 欄序回答。
查看答案與解釋
(0, 17/18, 17/18, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)
Wave6第五層核對=(0, 17/18, 17/18, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-zero-jump-atomlessness · candidate
68. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-zero-jump-atomlessness；資料={"knots":[-19,0,19],"values":[0,[18,19],1],"point":0}。請依 [point, F_at_point, F_left_limit, singleton_probability, zero_jump, certificate] 欄序回答。
查看答案與解釋
(0, 18/19, 18/19, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)
Wave6第五層核對=(0, 18/19, 18/19, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-zero-jump-atomlessness · candidate
69. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-zero-jump-atomlessness；資料={"knots":[-20,0,20],"values":[0,[19,20],1],"point":0}。請依 [point, F_at_point, F_left_limit, singleton_probability, zero_jump, certificate] 欄序回答。
查看答案與解釋
(0, 19/20, 19/20, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)
Wave6第五層核對=(0, 19/20, 19/20, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-zero-jump-atomlessness · candidate
70. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-zero-jump-atomlessness；資料={"knots":[-21,0,21],"values":[0,[20,21],1],"point":0}。請依 [point, F_at_point, F_left_limit, singleton_probability, zero_jump, certificate] 欄序回答。
查看答案與解釋
(0, 20/21, 20/21, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)
Wave6第五層核對=(0, 20/21, 20/21, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-zero-jump-atomlessness · candidate
71. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-zero-jump-atomlessness；資料={"knots":[-22,0,22],"values":[0,[21,22],1],"point":0}。請依 [point, F_at_point, F_left_limit, singleton_probability, zero_jump, certificate] 欄序回答。
查看答案與解釋
(0, 21/22, 21/22, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)
Wave6第五層核對=(0, 21/22, 21/22, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-zero-jump-atomlessness · candidate
72. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-zero-jump-atomlessness；資料={"knots":[-23,0,23],"values":[0,[22,23],1],"point":0}。請依 [point, F_at_point, F_left_limit, singleton_probability, zero_jump, certificate] 欄序回答。
查看答案與解釋
(0, 22/23, 22/23, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)
Wave6第五層核對=(0, 22/23, 22/23, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-zero-jump-atomlessness · candidate
73. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-zero-jump-atomlessness；資料={"knots":[-24,0,24],"values":[0,[23,24],1],"point":0}。請依 [point, F_at_point, F_left_limit, singleton_probability, zero_jump, certificate] 欄序回答。
查看答案與解釋
(0, 23/24, 23/24, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)
Wave6第五層核對=(0, 23/24, 23/24, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-zero-jump-atomlessness · candidate
74. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-zero-jump-atomlessness；資料={"knots":[-25,0,25],"values":[0,[24,25],1],"point":0}。請依 [point, F_at_point, F_left_limit, singleton_probability, zero_jump, certificate] 欄序回答。
查看答案與解釋
(0, 24/25, 24/25, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)
Wave6第五層核對=(0, 24/25, 24/25, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-zero-jump-atomlessness · candidate
75. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-zero-jump-atomlessness；資料={"knots":[-26,0,26],"values":[0,[25,26],1],"point":0}。請依 [point, F_at_point, F_left_limit, singleton_probability, zero_jump, certificate] 欄序回答。
查看答案與解釋
(0, 25/26, 25/26, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)
Wave6第五層核對=(0, 25/26, 25/26, 0, 是, continuous_CDF_has_zero_singleton_mass_but_need_not_have_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-zero-jump-atomlessness · candidate
76. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-singular-no-density-boundary；資料={"left":-1,"right":2}。請依 [left, right, CDF_continuous, atomless, has_density, singular, boundary] 欄序回答。
此為明示affine Cantor law的標準邊界；continuous、atomless與singular不等於有density，也不是由有限CDF samples推得的證明。
查看答案與解釋
(-1, 2, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)
Wave6第五層核對=(-1, 2, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-singular-no-density-boundary · candidate
77. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-singular-no-density-boundary；資料={"left":-2,"right":3}。請依 [left, right, CDF_continuous, atomless, has_density, singular, boundary] 欄序回答。
此為明示affine Cantor law的標準邊界；continuous、atomless與singular不等於有density，也不是由有限CDF samples推得的證明。
查看答案與解釋
(-2, 3, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)
Wave6第五層核對=(-2, 3, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-singular-no-density-boundary · candidate
78. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-singular-no-density-boundary；資料={"left":-3,"right":4}。請依 [left, right, CDF_continuous, atomless, has_density, singular, boundary] 欄序回答。
此為明示affine Cantor law的標準邊界；continuous、atomless與singular不等於有density，也不是由有限CDF samples推得的證明。
查看答案與解釋
(-3, 4, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)
Wave6第五層核對=(-3, 4, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-singular-no-density-boundary · candidate
79. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-singular-no-density-boundary；資料={"left":-4,"right":5}。請依 [left, right, CDF_continuous, atomless, has_density, singular, boundary] 欄序回答。
此為明示affine Cantor law的標準邊界；continuous、atomless與singular不等於有density，也不是由有限CDF samples推得的證明。
查看答案與解釋
(-4, 5, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)
Wave6第五層核對=(-4, 5, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-singular-no-density-boundary · candidate
80. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-singular-no-density-boundary；資料={"left":-5,"right":6}。請依 [left, right, CDF_continuous, atomless, has_density, singular, boundary] 欄序回答。
此為明示affine Cantor law的標準邊界；continuous、atomless與singular不等於有density，也不是由有限CDF samples推得的證明。
查看答案與解釋
(-5, 6, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)
Wave6第五層核對=(-5, 6, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-singular-no-density-boundary · candidate
81. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-singular-no-density-boundary；資料={"left":-6,"right":7}。請依 [left, right, CDF_continuous, atomless, has_density, singular, boundary] 欄序回答。
此為明示affine Cantor law的標準邊界；continuous、atomless與singular不等於有density，也不是由有限CDF samples推得的證明。
查看答案與解釋
(-6, 7, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)
Wave6第五層核對=(-6, 7, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-singular-no-density-boundary · candidate
82. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-singular-no-density-boundary；資料={"left":-7,"right":8}。請依 [left, right, CDF_continuous, atomless, has_density, singular, boundary] 欄序回答。
此為明示affine Cantor law的標準邊界；continuous、atomless與singular不等於有density，也不是由有限CDF samples推得的證明。
查看答案與解釋
(-7, 8, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)
Wave6第五層核對=(-7, 8, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-singular-no-density-boundary · candidate
83. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-singular-no-density-boundary；資料={"left":-8,"right":9}。請依 [left, right, CDF_continuous, atomless, has_density, singular, boundary] 欄序回答。
此為明示affine Cantor law的標準邊界；continuous、atomless與singular不等於有density，也不是由有限CDF samples推得的證明。
查看答案與解釋
(-8, 9, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)
Wave6第五層核對=(-8, 9, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-singular-no-density-boundary · candidate
84. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-singular-no-density-boundary；資料={"left":-9,"right":10}。請依 [left, right, CDF_continuous, atomless, has_density, singular, boundary] 欄序回答。
此為明示affine Cantor law的標準邊界；continuous、atomless與singular不等於有density，也不是由有限CDF samples推得的證明。
查看答案與解釋
(-9, 10, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)
Wave6第五層核對=(-9, 10, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-singular-no-density-boundary · candidate
85. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-singular-no-density-boundary；資料={"left":-10,"right":11}。請依 [left, right, CDF_continuous, atomless, has_density, singular, boundary] 欄序回答。
此為明示affine Cantor law的標準邊界；continuous、atomless與singular不等於有density，也不是由有限CDF samples推得的證明。
查看答案與解釋
(-10, 11, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)
Wave6第五層核對=(-10, 11, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-singular-no-density-boundary · candidate
86. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-singular-no-density-boundary；資料={"left":-11,"right":12}。請依 [left, right, CDF_continuous, atomless, has_density, singular, boundary] 欄序回答。
此為明示affine Cantor law的標準邊界；continuous、atomless與singular不等於有density，也不是由有限CDF samples推得的證明。
查看答案與解釋
(-11, 12, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)
Wave6第五層核對=(-11, 12, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-singular-no-density-boundary · candidate
87. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-singular-no-density-boundary；資料={"left":-12,"right":13}。請依 [left, right, CDF_continuous, atomless, has_density, singular, boundary] 欄序回答。
此為明示affine Cantor law的標準邊界；continuous、atomless與singular不等於有density，也不是由有限CDF samples推得的證明。
查看答案與解釋
(-12, 13, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)
Wave6第五層核對=(-12, 13, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-singular-no-density-boundary · candidate
88. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-singular-no-density-boundary；資料={"left":-13,"right":14}。請依 [left, right, CDF_continuous, atomless, has_density, singular, boundary] 欄序回答。
此為明示affine Cantor law的標準邊界；continuous、atomless與singular不等於有density，也不是由有限CDF samples推得的證明。
查看答案與解釋
(-13, 14, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)
Wave6第五層核對=(-13, 14, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-singular-no-density-boundary · candidate
89. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-singular-no-density-boundary；資料={"left":-14,"right":15}。請依 [left, right, CDF_continuous, atomless, has_density, singular, boundary] 欄序回答。
此為明示affine Cantor law的標準邊界；continuous、atomless與singular不等於有density，也不是由有限CDF samples推得的證明。
查看答案與解釋
(-14, 15, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)
Wave6第五層核對=(-14, 15, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-singular-no-density-boundary · candidate
90. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-singular-no-density-boundary；資料={"left":-15,"right":16}。請依 [left, right, CDF_continuous, atomless, has_density, singular, boundary] 欄序回答。
此為明示affine Cantor law的標準邊界；continuous、atomless與singular不等於有density，也不是由有限CDF samples推得的證明。
查看答案與解釋
(-15, 16, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)
Wave6第五層核對=(-15, 16, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-singular-no-density-boundary · candidate
91. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-singular-no-density-boundary；資料={"left":-16,"right":17}。請依 [left, right, CDF_continuous, atomless, has_density, singular, boundary] 欄序回答。
此為明示affine Cantor law的標準邊界；continuous、atomless與singular不等於有density，也不是由有限CDF samples推得的證明。
查看答案與解釋
(-16, 17, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)
Wave6第五層核對=(-16, 17, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-singular-no-density-boundary · candidate
92. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-singular-no-density-boundary；資料={"left":-17,"right":18}。請依 [left, right, CDF_continuous, atomless, has_density, singular, boundary] 欄序回答。
此為明示affine Cantor law的標準邊界；continuous、atomless與singular不等於有density，也不是由有限CDF samples推得的證明。
查看答案與解釋
(-17, 18, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)
Wave6第五層核對=(-17, 18, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-singular-no-density-boundary · candidate
93. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-singular-no-density-boundary；資料={"left":-18,"right":19}。請依 [left, right, CDF_continuous, atomless, has_density, singular, boundary] 欄序回答。
此為明示affine Cantor law的標準邊界；continuous、atomless與singular不等於有density，也不是由有限CDF samples推得的證明。
查看答案與解釋
(-18, 19, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)
Wave6第五層核對=(-18, 19, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-singular-no-density-boundary · candidate
94. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-singular-no-density-boundary；資料={"left":-19,"right":20}。請依 [left, right, CDF_continuous, atomless, has_density, singular, boundary] 欄序回答。
此為明示affine Cantor law的標準邊界；continuous、atomless與singular不等於有density，也不是由有限CDF samples推得的證明。
查看答案與解釋
(-19, 20, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)
Wave6第五層核對=(-19, 20, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-singular-no-density-boundary · candidate
95. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-singular-no-density-boundary；資料={"left":-20,"right":21}。請依 [left, right, CDF_continuous, atomless, has_density, singular, boundary] 欄序回答。
此為明示affine Cantor law的標準邊界；continuous、atomless與singular不等於有density，也不是由有限CDF samples推得的證明。
查看答案與解釋
(-20, 21, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)
Wave6第五層核對=(-20, 21, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-singular-no-density-boundary · candidate
96. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-singular-no-density-boundary；資料={"left":-21,"right":22}。請依 [left, right, CDF_continuous, atomless, has_density, singular, boundary] 欄序回答。
此為明示affine Cantor law的標準邊界；continuous、atomless與singular不等於有density，也不是由有限CDF samples推得的證明。
查看答案與解釋
(-21, 22, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)
Wave6第五層核對=(-21, 22, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-singular-no-density-boundary · candidate
97. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-singular-no-density-boundary；資料={"left":-22,"right":23}。請依 [left, right, CDF_continuous, atomless, has_density, singular, boundary] 欄序回答。
此為明示affine Cantor law的標準邊界；continuous、atomless與singular不等於有density，也不是由有限CDF samples推得的證明。
查看答案與解釋
(-22, 23, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)
Wave6第五層核對=(-22, 23, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-singular-no-density-boundary · candidate
98. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-singular-no-density-boundary；資料={"left":-23,"right":24}。請依 [left, right, CDF_continuous, atomless, has_density, singular, boundary] 欄序回答。
此為明示affine Cantor law的標準邊界；continuous、atomless與singular不等於有density，也不是由有限CDF samples推得的證明。
查看答案與解釋
(-23, 24, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)
Wave6第五層核對=(-23, 24, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-singular-no-density-boundary · candidate
99. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-singular-no-density-boundary；資料={"left":-24,"right":25}。請依 [left, right, CDF_continuous, atomless, has_density, singular, boundary] 欄序回答。
此為明示affine Cantor law的標準邊界；continuous、atomless與singular不等於有density，也不是由有限CDF samples推得的證明。
查看答案與解釋
(-24, 25, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)
Wave6第五層核對=(-24, 25, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-singular-no-density-boundary · candidate
100. 連續實值分布函數
CDF本身continuous、nondecreasing、right-continuous且audit query_points嚴格遞增。操作=contcdf-singular-no-density-boundary；資料={"left":-25,"right":26}。請依 [left, right, CDF_continuous, atomless, has_density, singular, boundary] 欄序回答。
此為明示affine Cantor law的標準邊界；continuous、atomless與singular不等於有density，也不是由有限CDF samples推得的證明。
查看答案與解釋
(-25, 26, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)
Wave6第五層核對=(-25, 26, 是, 是, 否, 是, affine_Cantor_distribution_is_continuous_atomless_and_singular_without_a_density)；依完整明示資料獨立重算；continuous CDF無jumps所以singletons質量0，flat intervals仍允許且兩端limits為0與1；continuous或atomless不推出density或absolute continuity；singular Cantor law是boundary。
本題逐步詳解（AI 二次覆核）
連續實值分布函數 · qf-mod42-contcdf-singular-no-density-boundary · candidate
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