第 19112 題：抽樣分布

原題與已知條件

共同有限樣本空間、逐theta模型law與單一theta-independent total statistic。操作=sampling-family-readback；資料={"parameter_count":2,"outcome_count":4,"laws":[[[1,19],[2,19],[3,19],[13,19]],[[2,23],[3,23],[4,23],[14,23]]],"statistic":[0,0,12,13]}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。

• G001 — 共同有限樣本空間、逐theta模型law與單一theta-independent total statistic。操作=sampling-family-readback；資料={"parameter_count":2,"outcome_count":4,"laws":[[[1,19],[2,19],[3,19],[13,19]],[[2,23],[3,23],[4,23],[14,23]]],"statistic":[0,0,12,13]}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。

定義與適用範圍

沿用原題明示的論域、假設與來源 MKO 定義。本題已完成第二對話數理與中英語義覆核，並由原始參數逐題獨立重算模型、答案與每個算術步驟；原題仍為 candidate。

• mko-sampling-distribution

逐步推導

source operation=sampling-family-readback;original snapshot and mathematics retained

explicit ordered source output fields=[statistic, parameter_laws, model_qualified, certificate]

sampling parameter0 full law mass := sum(1/19, 2/19, 3/19, 13/19)

sampling parameter0 full law mass = 1

sampling:original parameter SLOT=0;same outcome carrier Fin(4);ALL aligned law masses=[1/19, 2/19, 3/19, 13/19]

full sum=1;all masses nonnegative=是;qualified probability law;zero-mass outcomes retained

sampling parameter1 full law mass := sum(2/23, 3/23, 4/23, 14/23)

sampling parameter1 full law mass = 1

sampling:original parameter SLOT=1;same outcome carrier Fin(4);ALL aligned law masses=[2/23, 3/23, 4/23, 14/23]

full sum=1;all masses nonnegative=是;qualified probability law;zero-mass outcomes retained

sampling:parameter SLOT carrier Fin(2);common outcome carrier Fin(4);ONE total original statistic array=[0, 0, 12, 13]

T takes only the observation index,not the unknown parameter;SAME function at all parameter slots;its sampling law may still vary with the slot

sampling parameter0 statistic value0 full fibre mass := sum(1/19, 2/19)

sampling parameter0 statistic value0 full fibre mass = 3/19

FIXED original parameter SLOT=0;statistic value=0;FULL original fibre outcome indices=[0, 1];aligned law masses=[1/19, 2/19]

pushforward mass at value0=3/19;retain this row even if mass0

sampling parameter0 statistic value12 full fibre mass := sum(3/19)

sampling parameter0 statistic value12 full fibre mass = 3/19

FIXED original parameter SLOT=0;statistic value=12;FULL original fibre outcome indices=[2];aligned law masses=[3/19]

pushforward mass at value12=3/19;retain this row even if mass0

sampling parameter0 statistic value13 full fibre mass := sum(13/19)

sampling parameter0 statistic value13 full fibre mass = 13/19

FIXED original parameter SLOT=0;statistic value=13;FULL original fibre outcome indices=[3];aligned law masses=[13/19]

pushforward mass at value13=13/19;retain this row even if mass0

sampling parameter0 complete pushforward mass := sum(3/19, 3/19, 13/19)

sampling parameter0 complete pushforward mass = 1

fixed parameter SLOT=0;ALL increasingly ordered statistic values=[0, 12, 13];disjoint complete fibres=[[0, 1], [2], [3]]

pushforward law=[[0, 3/19], [12, 3/19], [13, 13/19]];total mass=1;ANY set of statistic values has preimage equal to the union of its fibres

sampling parameter1 statistic value0 full fibre mass := sum(2/23, 3/23)

sampling parameter1 statistic value0 full fibre mass = 5/23

FIXED original parameter SLOT=1;statistic value=0;FULL original fibre outcome indices=[0, 1];aligned law masses=[2/23, 3/23]

pushforward mass at value0=5/23;retain this row even if mass0

sampling parameter1 statistic value12 full fibre mass := sum(4/23)

sampling parameter1 statistic value12 full fibre mass = 4/23

FIXED original parameter SLOT=1;statistic value=12;FULL original fibre outcome indices=[2];aligned law masses=[4/23]

pushforward mass at value12=4/23;retain this row even if mass0

sampling parameter1 statistic value13 full fibre mass := sum(14/23)

sampling parameter1 statistic value13 full fibre mass = 14/23

FIXED original parameter SLOT=1;statistic value=13;FULL original fibre outcome indices=[3];aligned law masses=[14/23]

pushforward mass at value13=14/23;retain this row even if mass0

sampling parameter1 complete pushforward mass := sum(5/23, 4/23, 14/23)

sampling parameter1 complete pushforward mass = 1

fixed parameter SLOT=1;ALL increasingly ordered statistic values=[0, 12, 13];disjoint complete fibres=[[0, 1], [2], [3]]

pushforward law=[[0, 5/23], [12, 4/23], [13, 14/23]];total mass=1;ANY set of statistic values has preimage equal to the union of its fibres

ONE original statistic=[0, 0, 12, 13];ALL original parameter slots0..1

ordered full parameter-indexed family=[[0, [[0, 3/19], [12, 3/19], [13, 13/19]]], [1, [[0, 5/23], [12, 4/23], [13, 14/23]]]];NO parameter averaging or unstated prior

逐步反向核對

• S023 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S022 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S021 · premise_and_result_audit — 以精確有理數重算 sampling parameter1 complete pushforward mass，不以小數近似替代。
• S020 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S019 · premise_and_result_audit — 以精確有理數重算 sampling parameter1 statistic value13 full fibre mass，不以小數近似替代。
• S018 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S017 · premise_and_result_audit — 以精確有理數重算 sampling parameter1 statistic value12 full fibre mass，不以小數近似替代。
• S016 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S015 · premise_and_result_audit — 以精確有理數重算 sampling parameter1 statistic value0 full fibre mass，不以小數近似替代。
• S014 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S013 · premise_and_result_audit — 以精確有理數重算 sampling parameter0 complete pushforward mass，不以小數近似替代。
• S012 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S011 · premise_and_result_audit — 以精確有理數重算 sampling parameter0 statistic value13 full fibre mass，不以小數近似替代。
• S010 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S009 · premise_and_result_audit — 以精確有理數重算 sampling parameter0 statistic value12 full fibre mass，不以小數近似替代。
• S008 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S007 · premise_and_result_audit — 以精確有理數重算 sampling parameter0 statistic value0 full fibre mass，不以小數近似替代。
• S006 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S005 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S004 · premise_and_result_audit — 以精確有理數重算 sampling parameter1 full law mass，不以小數近似替代。
• S003 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S002 · premise_and_result_audit — 以精確有理數重算 sampling parameter0 full law mass，不以小數近似替代。
• S001 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。

結論

([0, 0, 12, 13], [[0, [[0, 3/19], [12, 3/19], [13, 13/19]]], [1, [[0, 5/23], [12, 4/23], [13, 14/23]]]], 是, one_theta_independent_total_statistic_family_of_laws)

依上列完整代值及條件核對得到原題答案；原題編號、格式與狀態保持不變。

本題覆核與來源綁定

覆核日期：2026-10-26

原題、答案、步驟表達式、數值 AST 與既有歷史保持原樣；原來的候選狀態屬於來源歷史，不覆寫為形式化證明。