第 19125 題：抽樣分布

原題與已知條件

共同有限樣本空間、逐theta模型law與單一theta-independent total statistic。操作=sampling-family-readback；資料={"parameter_count":2,"outcome_count":4,"laws":[[[1,32],[2,32],[3,32],[26,32]],[[2,36],[3,36],[4,36],[27,36]]],"statistic":[0,0,25,26]}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。

• G001 — 共同有限樣本空間、逐theta模型law與單一theta-independent total statistic。操作=sampling-family-readback；資料={"parameter_count":2,"outcome_count":4,"laws":[[[1,32],[2,32],[3,32],[26,32]],[[2,36],[3,36],[4,36],[27,36]]],"statistic":[0,0,25,26]}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。

定義與適用範圍

沿用原題明示的論域、假設與來源 MKO 定義。本題已完成第二對話數理與中英語義覆核，並由原始參數逐題獨立重算模型、答案與每個算術步驟；原題仍為 candidate。

• mko-sampling-distribution

逐步推導

source operation=sampling-family-readback;original snapshot and mathematics retained

explicit ordered source output fields=[statistic, parameter_laws, model_qualified, certificate]

sampling parameter0 full law mass := sum(1/32, 1/16, 3/32, 13/16)

sampling parameter0 full law mass = 1

sampling:original parameter SLOT=0;same outcome carrier Fin(4);ALL aligned law masses=[1/32, 1/16, 3/32, 13/16]

full sum=1;all masses nonnegative=是;qualified probability law;zero-mass outcomes retained

sampling parameter1 full law mass := sum(1/18, 1/12, 1/9, 3/4)

sampling parameter1 full law mass = 1

sampling:original parameter SLOT=1;same outcome carrier Fin(4);ALL aligned law masses=[1/18, 1/12, 1/9, 3/4]

full sum=1;all masses nonnegative=是;qualified probability law;zero-mass outcomes retained

sampling:parameter SLOT carrier Fin(2);common outcome carrier Fin(4);ONE total original statistic array=[0, 0, 25, 26]

T takes only the observation index,not the unknown parameter;SAME function at all parameter slots;its sampling law may still vary with the slot

sampling parameter0 statistic value0 full fibre mass := sum(1/32, 1/16)

sampling parameter0 statistic value0 full fibre mass = 3/32

FIXED original parameter SLOT=0;statistic value=0;FULL original fibre outcome indices=[0, 1];aligned law masses=[1/32, 1/16]

pushforward mass at value0=3/32;retain this row even if mass0

sampling parameter0 statistic value25 full fibre mass := sum(3/32)

sampling parameter0 statistic value25 full fibre mass = 3/32

FIXED original parameter SLOT=0;statistic value=25;FULL original fibre outcome indices=[2];aligned law masses=[3/32]

pushforward mass at value25=3/32;retain this row even if mass0

sampling parameter0 statistic value26 full fibre mass := sum(13/16)

sampling parameter0 statistic value26 full fibre mass = 13/16

FIXED original parameter SLOT=0;statistic value=26;FULL original fibre outcome indices=[3];aligned law masses=[13/16]

pushforward mass at value26=13/16;retain this row even if mass0

sampling parameter0 complete pushforward mass := sum(3/32, 3/32, 13/16)

sampling parameter0 complete pushforward mass = 1

fixed parameter SLOT=0;ALL increasingly ordered statistic values=[0, 25, 26];disjoint complete fibres=[[0, 1], [2], [3]]

pushforward law=[[0, 3/32], [25, 3/32], [26, 13/16]];total mass=1;ANY set of statistic values has preimage equal to the union of its fibres

sampling parameter1 statistic value0 full fibre mass := sum(1/18, 1/12)

sampling parameter1 statistic value0 full fibre mass = 5/36

FIXED original parameter SLOT=1;statistic value=0;FULL original fibre outcome indices=[0, 1];aligned law masses=[1/18, 1/12]

pushforward mass at value0=5/36;retain this row even if mass0

sampling parameter1 statistic value25 full fibre mass := sum(1/9)

sampling parameter1 statistic value25 full fibre mass = 1/9

FIXED original parameter SLOT=1;statistic value=25;FULL original fibre outcome indices=[2];aligned law masses=[1/9]

pushforward mass at value25=1/9;retain this row even if mass0

sampling parameter1 statistic value26 full fibre mass := sum(3/4)

sampling parameter1 statistic value26 full fibre mass = 3/4

FIXED original parameter SLOT=1;statistic value=26;FULL original fibre outcome indices=[3];aligned law masses=[3/4]

pushforward mass at value26=3/4;retain this row even if mass0

sampling parameter1 complete pushforward mass := sum(5/36, 1/9, 3/4)

sampling parameter1 complete pushforward mass = 1

fixed parameter SLOT=1;ALL increasingly ordered statistic values=[0, 25, 26];disjoint complete fibres=[[0, 1], [2], [3]]

pushforward law=[[0, 5/36], [25, 1/9], [26, 3/4]];total mass=1;ANY set of statistic values has preimage equal to the union of its fibres

ONE original statistic=[0, 0, 25, 26];ALL original parameter slots0..1

ordered full parameter-indexed family=[[0, [[0, 3/32], [25, 3/32], [26, 13/16]]], [1, [[0, 5/36], [25, 1/9], [26, 3/4]]]];NO parameter averaging or unstated prior

逐步反向核對

• S023 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S022 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S021 · premise_and_result_audit — 以精確有理數重算 sampling parameter1 complete pushforward mass，不以小數近似替代。
• S020 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S019 · premise_and_result_audit — 以精確有理數重算 sampling parameter1 statistic value26 full fibre mass，不以小數近似替代。
• S018 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S017 · premise_and_result_audit — 以精確有理數重算 sampling parameter1 statistic value25 full fibre mass，不以小數近似替代。
• S016 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S015 · premise_and_result_audit — 以精確有理數重算 sampling parameter1 statistic value0 full fibre mass，不以小數近似替代。
• S014 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S013 · premise_and_result_audit — 以精確有理數重算 sampling parameter0 complete pushforward mass，不以小數近似替代。
• S012 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S011 · premise_and_result_audit — 以精確有理數重算 sampling parameter0 statistic value26 full fibre mass，不以小數近似替代。
• S010 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S009 · premise_and_result_audit — 以精確有理數重算 sampling parameter0 statistic value25 full fibre mass，不以小數近似替代。
• S008 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S007 · premise_and_result_audit — 以精確有理數重算 sampling parameter0 statistic value0 full fibre mass，不以小數近似替代。
• S006 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S005 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S004 · premise_and_result_audit — 以精確有理數重算 sampling parameter1 full law mass，不以小數近似替代。
• S003 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S002 · premise_and_result_audit — 以精確有理數重算 sampling parameter0 full law mass，不以小數近似替代。
• S001 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。

結論

([0, 0, 25, 26], [[0, [[0, 3/32], [25, 3/32], [26, 13/16]]], [1, [[0, 5/36], [25, 1/9], [26, 3/4]]]], 是, one_theta_independent_total_statistic_family_of_laws)

依上列完整代值及條件核對得到原題答案；原題編號、格式與狀態保持不變。

本題覆核與來源綁定

覆核日期：2026-10-26

原題、答案、步驟表達式、數值 AST 與既有歷史保持原樣；原來的候選狀態屬於來源歷史，不覆寫為形式化證明。