第 21444 題：實數列Bolzano－Weierstrass定理

原題與已知條件

whole-sequence bounded certificate與symbolic strictly increasing infinite index。操作=bw-oscillatory-tail；資料={"limit":[19,20],"coefficient":19,"shift":20,"parity":0,"epsilon":[1,28]}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。

• G001 — whole-sequence bounded certificate與symbolic strictly increasing infinite index。操作=bw-oscillatory-tail；資料={"limit":[19,20],"coefficient":19,"shift":20,"parity":0,"epsilon":[1,28]}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。

定義與適用範圍

沿用原題明示的論域、假設與來源 MKO 定義。本題已完成第二對話數理與中英語義覆核，並由原始參數逐題獨立重算模型、答案與每個算術步驟；原題仍為 candidate。

• mko-bolzano-weierstrass-theorem-real

逐步推導

source operation=bw-oscillatory-tail;original snapshot and mathematics retained

explicit ordered source output fields=[parity, index_rule, limit, epsilon, J, value_at_k_J, strict_tail_certificate, certificate]

ORIGINAL a_n=19/20+(-1)^n*(19)/(n+20) for EVERY n>=0;parity=0

k(j)=2j+0 for ALL j>=0;k(j+1)-k(j)=2>0;selected sign=1;whole sequence bounded by |L|+c/shift

bw c over epsilon := div(19, 1/28)

bw c over epsilon = 532

bw index multiple := mul(2, 257)

bw index multiple = 514

bw actual source index := sum(0, 514)

bw actual source index = 514

bw witness denominator := sum(514, 20)

bw witness denominator = 534

bw witness distance := div(19, 534)

bw witness distance = 19/534

bw predecessor distance := div(19, 532)

bw predecessor distance = 1/28

bw:c=19,shift=20,epsilon=1/28;index(q)=2q+0;c/epsilon=532;floor=532

least nonnegative witness=257;actual source index=514;distance=19/534<epsilon;predecessor distance=1/28;no predecessor evaluated when witness0

bw:positive c=19,epsilon=1/28,shift=20,stride=2,offset=0;least witness=257

for EVERY integer q>=257,denominator=2q+0+20>=witness denominator>0,so 0<distance<=(19/534)<epsilon

bw at selected k(J) denominator := sum(514, 20)

bw at selected k(J) denominator = 534

bw at selected k(J) unsigned tail := div(19, 534)

bw at selected k(J) unsigned tail = 19/534

bw at selected k(J) signed value := sum(19/20, 19/534)

bw at selected k(J) signed value = 5263/5340

逐步反向核對

• S013 · premise_and_result_audit — 以精確有理數重算 bw at selected k(J) signed value，不以小數近似替代。
• S012 · premise_and_result_audit — 以精確有理數重算 bw at selected k(J) unsigned tail，不以小數近似替代。
• S011 · premise_and_result_audit — 以精確有理數重算 bw at selected k(J) denominator，不以小數近似替代。
• S010 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S009 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S008 · premise_and_result_audit — 以精確有理數重算 bw predecessor distance，不以小數近似替代。
• S007 · premise_and_result_audit — 以精確有理數重算 bw witness distance，不以小數近似替代。
• S006 · premise_and_result_audit — 以精確有理數重算 bw witness denominator，不以小數近似替代。
• S005 · premise_and_result_audit — 以精確有理數重算 bw actual source index，不以小數近似替代。
• S004 · premise_and_result_audit — 以精確有理數重算 bw index multiple，不以小數近似替代。
• S003 · premise_and_result_audit — 以精確有理數重算 bw c over epsilon，不以小數近似替代。
• S002 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S001 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。

結論

(0, k(j)=2j+0, 19/20, 1/28, 257, 5263/5340, 是, forall_j_ge_J_symbolic_subsequence_tail)

依上列完整代值及條件核對得到原題答案；原題編號、格式與狀態保持不變。

本題覆核與來源綁定

覆核日期：2026-10-26

原題、答案、步驟表達式、數值 AST 與既有歷史保持原樣；原來的候選狀態屬於來源歷史，不覆寫為形式化證明。