原題與已知條件
transition=[from,input-or-null,required-top,to,replacement-bottom-to-top]的finite nondeterministic PDA。操作=pda-qualification;資料={"states":["push0","pop0","accept0"],"input_alphabet":["a0","b0"],"stack_alphabet":["Z0","A0"],"start_state":"push0","bottom_symbol":"Z0","final_states":["accept0"],"transitions":[["push0","a0","Z0","push0",["Z0","A0"]],["push0","a0","A0","push0",["A0","A0"]],["push0","b0","A0","pop0",[]],["pop0","b0","A0","pop0",[]],["push0",null,"Z0","accept0",["Z0"]],["pop0",null,"Z0","accept0",["Z0"]]]}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。
G001 — transition=[from,input-or-null,required-top,to,replacement-bottom-to-top]的finite nondeterministic PDA。操作=pda-qualification;資料={"states":["push0","pop0","accept0"],"input_alphabet":["a0","b0"],"stack_alphabet":["Z0","A0"],"start_state":"push0","bottom_symbol":"Z0","final_states":["accept0"],"transitions":[["push0","a0","Z0","push0",["Z0","A0"]],["push0","a0","A0","push0",["A0","A0"]],["push0","b0","A0","pop0",[]],["pop0","b0","A0","pop0",[]],["push0",null,"Z0","accept0",["Z0"]],["pop0",null,"Z0","accept0",["Z0"]]]}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。
逐步推導
S001 · implies
操作前
source operation=pda-qualification;original snapshot and mathematics retained
操作後
explicit ordered source output fields=[states, input_alphabet, stack_alphabet, start_state, bottom_symbol, final_states, transition_count, qualified, convention]
條件:無
原題歷史介面標記保留,直接列來源有序欄位,不需JavaScript;MVT由原mode選欄序,不補空欄或看答案形狀猜。tag與固定No保原聲稱範圍。
步驟識別與依賴
規則:source_ordered_interface_explicit_without_javascript · 依賴:G001
S002 · implies
操作前
ORIGINAL transition index=0;[from,input_or_null,required_top,to,replacement_bottom_to_top]=[push0, a0, Z0, push0, [Z0, A0]];bottom=Z0
操作後
states/input/stack symbols legal;null input consumes0;top=bottom requires replacement first bottom,otherwise replacement contains NO bottom;ORIGINAL transition position retained
條件:無
逐原transition核state、input與stack角色,不把字母表混用;null是epsilon而不是一個字母。stack bottom-first/top-last,pop一個top再按原replacement順序append;只施來源明示bottom guard,不另加更強慣例。
步驟識別與依賴
規則:pda_EVERY_original_transition_roles_epsilon_bottom_guard · 依賴:G001, S001
S003 · implies
操作前
ORIGINAL transition index=1;[from,input_or_null,required_top,to,replacement_bottom_to_top]=[push0, a0, A0, push0, [A0, A0]];bottom=Z0
操作後
states/input/stack symbols legal;null input consumes0;top=bottom requires replacement first bottom,otherwise replacement contains NO bottom;ORIGINAL transition position retained
條件:無
逐原transition核state、input與stack角色,不把字母表混用;null是epsilon而不是一個字母。stack bottom-first/top-last,pop一個top再按原replacement順序append;只施來源明示bottom guard,不另加更強慣例。
步驟識別與依賴
規則:pda_EVERY_original_transition_roles_epsilon_bottom_guard · 依賴:G001, S002
S004 · implies
操作前
ORIGINAL transition index=2;[from,input_or_null,required_top,to,replacement_bottom_to_top]=[push0, b0, A0, pop0, []];bottom=Z0
操作後
states/input/stack symbols legal;null input consumes0;top=bottom requires replacement first bottom,otherwise replacement contains NO bottom;ORIGINAL transition position retained
條件:無
逐原transition核state、input與stack角色,不把字母表混用;null是epsilon而不是一個字母。stack bottom-first/top-last,pop一個top再按原replacement順序append;只施來源明示bottom guard,不另加更強慣例。
步驟識別與依賴
規則:pda_EVERY_original_transition_roles_epsilon_bottom_guard · 依賴:G001, S003
S005 · implies
操作前
ORIGINAL transition index=3;[from,input_or_null,required_top,to,replacement_bottom_to_top]=[pop0, b0, A0, pop0, []];bottom=Z0
操作後
states/input/stack symbols legal;null input consumes0;top=bottom requires replacement first bottom,otherwise replacement contains NO bottom;ORIGINAL transition position retained
條件:無
逐原transition核state、input與stack角色,不把字母表混用;null是epsilon而不是一個字母。stack bottom-first/top-last,pop一個top再按原replacement順序append;只施來源明示bottom guard,不另加更強慣例。
步驟識別與依賴
規則:pda_EVERY_original_transition_roles_epsilon_bottom_guard · 依賴:G001, S004
S006 · implies
操作前
ORIGINAL transition index=4;[from,input_or_null,required_top,to,replacement_bottom_to_top]=[push0, null, Z0, accept0, [Z0]];bottom=Z0
操作後
states/input/stack symbols legal;null input consumes0;top=bottom requires replacement first bottom,otherwise replacement contains NO bottom;ORIGINAL transition position retained
條件:無
逐原transition核state、input與stack角色,不把字母表混用;null是epsilon而不是一個字母。stack bottom-first/top-last,pop一個top再按原replacement順序append;只施來源明示bottom guard,不另加更強慣例。
步驟識別與依賴
規則:pda_EVERY_original_transition_roles_epsilon_bottom_guard · 依賴:G001, S005
S007 · implies
操作前
ORIGINAL transition index=5;[from,input_or_null,required_top,to,replacement_bottom_to_top]=[pop0, null, Z0, accept0, [Z0]];bottom=Z0
操作後
states/input/stack symbols legal;null input consumes0;top=bottom requires replacement first bottom,otherwise replacement contains NO bottom;ORIGINAL transition position retained
條件:無
逐原transition核state、input與stack角色,不把字母表混用;null是epsilon而不是一個字母。stack bottom-first/top-last,pop一個top再按原replacement順序append;只施來源明示bottom guard,不另加更強慣例。
步驟識別與依賴
規則:pda_EVERY_original_transition_roles_epsilon_bottom_guard · 依賴:G001, S006
S008 · calculation
操作前
PDA complete ORIGINAL transition count := sum(1, 1, 1, 1, 1, 1)
操作後
PDA complete ORIGINAL transition count = 6
條件:無
依原始角色、次序與已核中間量精確代值;不改source binding或用浮點近似。
步驟識別與依賴
規則:exact_rational_arithmetic · 依賴:G001, S007
S009 · implies
操作前
ORIGINAL states=[push0, pop0, accept0],input alphabet=[a0, b0],stack alphabet=[Z0, A0];start=push0,bottom=Z0,final states=[accept0]
操作後
finite unique pairwise-disjoint alphabets qualified;transition count=6;acceptance convention FULL input in final state,NOT empty stack;qualification alone proves NO run,determinism or CFG equivalence
條件:無
有限完整定義的資格不等於存在接受run,也不推deterministic或CFG等價。接受時可保非空stack(至少bottom),但必須讀完整input到final。
步驟識別與依賴
規則:pda_complete_definition_not_determinism_or_accepting_run · 依賴:G001, S008
結論
([push0, pop0, accept0], [a0, b0], [Z0, A0], push0, Z0, [accept0], 6, 是, accept_only_after_full_input_in_final_state_bottom_marker_preserved)
依上列完整代值及條件核對得到原題答案;原題編號、格式與狀態保持不變。