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第 24705 題:Turing機判定模型

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  1. 原題與已知條件
  2. 定義與適用範圍
  3. 逐步推導
  4. 逐步反向核對
  5. 結論
  6. 本題覆核與來源綁定

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← 逐題詳解目錄 · 原題批次

R0048-24705 · q-20261015-advance-20261113-r05-turing-machine-decision-model-0030

原題與已知條件

deterministic single-tape signature、exact configuration semantics與decider total-correctness boundary。操作=tm-exact-step-trace;資料={"states":["q04","q14","qa4","qr4"],"input_alphabet":["04"],"tape_alphabet":["04","X4","_4"],"blank":"_4","start_state":"q04","accept_state":"qa4","reject_state":"qr4","transitions":[["q04","04","q14","X4","R"],["q04","_4","qr4","_4","S"],["q14","_4","qa4","_4","L"]],"input":["04"],"steps":2}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。

  • G001 — deterministic single-tape signature、exact configuration semantics與decider total-correctness boundary。操作=tm-exact-step-trace;資料={"states":["q04","q14","qa4","qr4"],"input_alphabet":["04"],"tape_alphabet":["04","X4","_4"],"blank":"_4","start_state":"q04","accept_state":"qa4","reject_state":"qr4","transitions":[["q04","04","q14","X4","R"],["q04","_4","qr4","_4","S"],["q14","_4","qa4","_4","L"]],"input":["04"],"steps":2}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。

定義與適用範圍

沿用原題明示的論域、假設與來源 MKO 定義。本題已完成第二對話數理與中英語義覆核,並由原始參數逐題獨立重算模型、答案與每個算術步驟;原題仍為 candidate。

逐步推導

S001 · implies

操作前

source roles = [tm-exact-step-trace]

操作後

derived = [[input, step_budget, configurations, step_outcomes, final_state, local_outcome, global_decider_certificate, boundary]]

條件:無

直接列來源完整欄序,不需JavaScript;原題、布林旗標、數學物件與非聲稱保持分層。

步驟識別與依賴

規則:source_ordered_fields_without_JS · 依賴:G001

S002 · implies

操作前

source roles = [[q04, q14, qa4, qr4], [04], [04, X4, _4], _4, q04, qa4, qr4, [[q04, 04, q14, X4, R], [q04, _4, qr4, _4, S], [q14, _4, qa4, _4, L]]]

操作後

derived = [[q04, q14, qa4, qr4], [04], [04, X4, _4], [[q04, _4, qr4, _4, S], [q04, 04, q14, X4, R], [q14, _4, qa4, _4, L]], 是]

條件:無

三個清單皆非空且唯一;input是blank-free tape子集,但state與字母標籤不要求不相交。每個(from,read)的來源NUL-joined key唯一、halt無出邊。partial table合法,不補reject規則;canonical transition序與UTF16集合序分開。

步驟識別與依賴

規則:TM_complete_signature_partial_transition_table_allowed · 依賴:G001, S001

S003 · implies

操作前

source roles = [[04], q04, _4]

操作後

derived = [[q04, 0, [[0, 04]]]]

條件:無

初始head0、input放0起的整數格,其餘全blank;稀疏記錄僅保非blank。tape可往負index伸展。

步驟識別與依賴

規則:TM_exact_initial_configuration_blank_elsewhere · 依賴:G001, S002

S004 · calculation

操作前

TM exact integer head move0 := sum(0, 1)

操作後

TM exact integer head move0 = 1

條件:無

依原始角色與已證中間量精確代值,分母先核非零,不用浮點近似。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S003

S005 · implies

操作前

source roles = [0, [q04, 0, [[0, 04]]], 04, [q04, 04, q14, X4, R]]

操作後

derived = [step, [q14, 1, [[0, X4]]]]

條件:無

先在舊head寫字(blank刪格),再換state及移head;全部L/R/S按原rule,不混成停機語意。

步驟識別與依賴

規則:TM_source_rule_exact_read_write_state_move · 依賴:G001, S004

S006 · calculation

操作前

TM exact integer head move1 := sum(1, -1)

操作後

TM exact integer head move1 = 0

條件:無

依原始角色與已證中間量精確代值,分母先核非零,不用浮點近似。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S005

S007 · implies

操作前

source roles = [1, [q14, 1, [[0, X4]]], _4, [q14, _4, qa4, _4, L]]

操作後

derived = [step, [qa4, 0, [[0, X4]]]]

條件:無

先在舊head寫字(blank刪格),再換state及移head;全部L/R/S按原rule,不混成停機語意。

步驟識別與依賴

規則:TM_source_rule_exact_read_write_state_move · 依賴:G001, S006

S008 · implies

操作前

source roles = [[04], 2, [[q04, 0, [[0, 04]]], [q14, 1, [[0, X4]]], [qa4, 0, [[0, X4]]]], [step, step]]

操作後

derived = [qa4, accept, 否]

條件:無

已halt才接受/拒絕;budget用盡或stuck不是普通reject,也不證永久不停止。一個input的有限trace不提供all-input decider證書。

步驟識別與依賴

規則:TM_finite_trace_input_budget_scope_NOT_global_decider · 依賴:G001, S007

逐步反向核對

  • S008 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。
  • S007 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。
  • S006 · premise_and_result_audit — 以精確有理數重算 TM exact integer head move1,不以小數近似替代。
  • S005 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。
  • S004 · premise_and_result_audit — 以精確有理數重算 TM exact integer head move0,不以小數近似替代。
  • S003 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。
  • S002 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。
  • S001 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。

結論

([04], 2, [[q04, 0, [[0, 04]]], [q14, 1, [[0, X4]]], [qa4, 0, [[0, X4]]]], [step, step], qa4, accept, 否, finite_trace_is_input_local_and_does_not_certify_a_global_decider)

依上列完整代值及條件核對得到原題答案;原題編號、格式與狀態保持不變。

本題覆核與來源綁定

覆核日期:2026-10-26

原題、答案、步驟表達式、數值 AST 與既有歷史保持原樣;原來的候選狀態屬於來源歷史,不覆寫為形式化證明。

來源雜湊與覆核憑證
  • input commit: 0f7be61e2c22317a4075561dc822c87d881a50db
  • original question SHA-256: 4a625d88b1a98dff41c20c141b629ee1c1dd76ecd833872af238472d6972486e
  • candidate record SHA-256: 3dec5175a9396d861bb451e210a181d487625848333d9abba5c81ed40fdcfdeb
  • semantic review receipt SHA-256: 049a9e07e69fead88d93b34f0937b9470a06d71c1a8d097058fc83554529bdd0
  • question-first witness SHA-256: 0c71ebb418f3de347d232d159fc25e93036f4ab9166bcfb5ee5b4be86d5c55b9
  • Lean: NOT_RUN · human review: NOT_PERFORMED
同源完整 JSON