第 25476 題：頂點覆蓋

原題與已知條件

有限simple undirected graph的全部edges與candidate subset完整核對。操作=vcover-uncovered-edge-witness；資料={"vertices":["v0","v1","v2","v3"],"edges":[["v0","v1"],["v1","v2"],["v2","v3"]],"candidate":[]}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。

• G001 — 有限simple undirected graph的全部edges與candidate subset完整核對。操作=vcover-uncovered-edge-witness；資料={"vertices":["v0","v1","v2","v3"],"edges":[["v0","v1"],["v1","v2"],["v2","v3"]],"candidate":[]}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。

定義與適用範圍

沿用原題明示的論域、假設與來源 MKO 定義。本題已完成第二對話數理與中英語義覆核，並由原始參數逐題獨立重算模型、答案與每個算術步驟；原題仍為 candidate。

• mko-vertex-cover

逐步推導

source roles = [vcover-uncovered-edge-witness]

derived = [[candidate, edge_coverage_rows, uncovered_edge, cover, boundary]]

source roles = [[v0, v1, v2, v3], [[v0, v1], [v1, v2], [v2, v3]], []]

derived = [[v0, v1, v2, v3], [[v0, v1], [v1, v2], [v2, v3]], []]

source roles = [0, [v0, v1], []]

derived = [[否, 否], 否]

source roles = [1, [v1, v2], []]

derived = [[否, 否], 否]

source roles = [2, [v2, v3], []]

derived = [[否, 否], 否]

source roles = [[[[v0, v1], 否], [[v1, v2], 否], [[v2, v3], 否]]]

derived = [否, [v0, v1], []]

source roles = [[v0, v1], []]

derived = [否]

逐步反向核對

• S007 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S006 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S005 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S004 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S003 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S002 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S001 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。

結論

([], [[[v0, v1], 否], [[v1, v2], 否], [[v2, v3], 否]], [v0, v1], 否, one_edge_with_both_endpoints_outside_C_refutes_vertex_cover)

依上列完整代值及條件核對得到原題答案；原題編號、格式與狀態保持不變。

本題覆核與來源綁定

覆核日期：2026-10-26

原題、答案、步驟表達式、數值 AST 與既有歷史保持原樣；原來的候選狀態屬於來源歷史，不覆寫為形式化證明。