第 27339 題：正規語言Pumping引理

原題與已知條件

exists p forall w exists split forall i量詞與split constraints責任。操作=pump-boundary；資料={"mode":"wrong_quantifiers","model":{"p":14,"word":["a","a","a","a","a","a","a","a","a","a","a","a","a","a","b"]}}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。

• G001 — exists p forall w exists split forall i量詞與split constraints責任。操作=pump-boundary；資料={"mode":"wrong_quantifiers","model":{"p":14,"word":["a","a","a","a","a","a","a","a","a","a","a","a","a","a","b"]}}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。

定義與適用範圍

沿用原題明示的論域、假設與來源 MKO 定義。本題已完成第二對話數理與中英語義覆核，並由原始參數逐題獨立重算模型、答案與每個算術步驟；原題仍為 candidate。

• mko-pumping-lemma-regular-languages

逐步推導

source roles = [pump-boundary]

derived = [[mode, p, word, legal_split_count, adversarial_choice_order, reversed_quantifier_claim]]

source roles = [wrong_quantifiers, 14, [a, a, a, a, a, a, a, a, a, a, a, a, a, a, b]]

derived = [105, adversary_word_then_prover_split_then_adversary_i, 否]

逐步反向核對

• S002 · premise_and_result_audit — 回查原始完整資料、步驟操作數與本步前提；有限核對、條件式定理引用與一般形式證明分開。
• S001 · premise_and_result_audit — 回查原始完整資料、步驟操作數與本步前提；有限核對、條件式定理引用與一般形式證明分開。

結論

(wrong_quantifiers, 14, [a, a, a, a, a, a, a, a, a, a, a, a, a, a, b], 105, adversary_word_then_prover_split_then_adversary_i, 否)

依上列完整代值及條件核對得到原題答案；原題編號、格式與狀態保持不變。

本題覆核與來源綁定

覆核日期：2026-10-26

原題、答案、步驟表達式、數值 AST 與既有歷史保持原樣；原來的候選狀態屬於來源歷史，不覆寫為形式化證明。