級數絕對收斂基礎 · 脈衝 R03
本批已通過 Schema、去重、來源快照與獨立答案重算;仍未標記為人工審定。
本題庫已有對應的中英逐步詳解。原題的 candidate 與英文 ai_candidate 狀態保留;AI 覆核、有限計算與 Lean 形式證明分開標示。
batch-20261014-advance-20261104-r03-absolute-convergence-of-series-foundations · 2026-10-14 · 100 題
欄序為來源綁定的呈現補充;原始 JSONL 與數學答案不變。
欄序與來源綁定資料
1. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-geometric;資料={"a":[1,2],"r":[-1,2]}。請依 [a, r, absolute_series_sum, absolutely_convergent, certificate] 欄序回答。
查看答案與解釋
(1/2, -1/2, 1, 是, absolute_geometric_certificate)
Wave5第四層核對=(1/2, -1/2, 1, 是, absolute_geometric_certificate);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-geometric · candidate
2. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-geometric;資料={"a":[2,3],"r":[-1,2]}。請依 [a, r, absolute_series_sum, absolutely_convergent, certificate] 欄序回答。
查看答案與解釋
(2/3, -1/2, 4/3, 是, absolute_geometric_certificate)
Wave5第四層核對=(2/3, -1/2, 4/3, 是, absolute_geometric_certificate);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-geometric · candidate
3. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-geometric;資料={"a":[3,4],"r":[-1,2]}。請依 [a, r, absolute_series_sum, absolutely_convergent, certificate] 欄序回答。
查看答案與解釋
(3/4, -1/2, 3/2, 是, absolute_geometric_certificate)
Wave5第四層核對=(3/4, -1/2, 3/2, 是, absolute_geometric_certificate);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-geometric · candidate
4. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-geometric;資料={"a":[4,5],"r":[-1,2]}。請依 [a, r, absolute_series_sum, absolutely_convergent, certificate] 欄序回答。
查看答案與解釋
(4/5, -1/2, 8/5, 是, absolute_geometric_certificate)
Wave5第四層核對=(4/5, -1/2, 8/5, 是, absolute_geometric_certificate);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-geometric · candidate
5. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-geometric;資料={"a":[5,6],"r":[-1,2]}。請依 [a, r, absolute_series_sum, absolutely_convergent, certificate] 欄序回答。
查看答案與解釋
(5/6, -1/2, 5/3, 是, absolute_geometric_certificate)
Wave5第四層核對=(5/6, -1/2, 5/3, 是, absolute_geometric_certificate);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-geometric · candidate
6. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-geometric;資料={"a":[6,7],"r":[-1,2]}。請依 [a, r, absolute_series_sum, absolutely_convergent, certificate] 欄序回答。
查看答案與解釋
(6/7, -1/2, 12/7, 是, absolute_geometric_certificate)
Wave5第四層核對=(6/7, -1/2, 12/7, 是, absolute_geometric_certificate);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-geometric · candidate
7. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-geometric;資料={"a":[7,8],"r":[-1,2]}。請依 [a, r, absolute_series_sum, absolutely_convergent, certificate] 欄序回答。
查看答案與解釋
(7/8, -1/2, 7/4, 是, absolute_geometric_certificate)
Wave5第四層核對=(7/8, -1/2, 7/4, 是, absolute_geometric_certificate);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-geometric · candidate
8. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-geometric;資料={"a":[8,9],"r":[-1,2]}。請依 [a, r, absolute_series_sum, absolutely_convergent, certificate] 欄序回答。
查看答案與解釋
(8/9, -1/2, 16/9, 是, absolute_geometric_certificate)
Wave5第四層核對=(8/9, -1/2, 16/9, 是, absolute_geometric_certificate);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-geometric · candidate
9. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-geometric;資料={"a":[9,10],"r":[-1,2]}。請依 [a, r, absolute_series_sum, absolutely_convergent, certificate] 欄序回答。
查看答案與解釋
(9/10, -1/2, 9/5, 是, absolute_geometric_certificate)
Wave5第四層核對=(9/10, -1/2, 9/5, 是, absolute_geometric_certificate);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-geometric · candidate
10. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-geometric;資料={"a":[10,11],"r":[-1,2]}。請依 [a, r, absolute_series_sum, absolutely_convergent, certificate] 欄序回答。
查看答案與解釋
(10/11, -1/2, 20/11, 是, absolute_geometric_certificate)
Wave5第四層核對=(10/11, -1/2, 20/11, 是, absolute_geometric_certificate);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-geometric · candidate
11. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-geometric;資料={"a":[11,12],"r":[-1,2]}。請依 [a, r, absolute_series_sum, absolutely_convergent, certificate] 欄序回答。
查看答案與解釋
(11/12, -1/2, 11/6, 是, absolute_geometric_certificate)
Wave5第四層核對=(11/12, -1/2, 11/6, 是, absolute_geometric_certificate);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-geometric · candidate
12. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-geometric;資料={"a":[12,13],"r":[-1,2]}。請依 [a, r, absolute_series_sum, absolutely_convergent, certificate] 欄序回答。
查看答案與解釋
(12/13, -1/2, 24/13, 是, absolute_geometric_certificate)
Wave5第四層核對=(12/13, -1/2, 24/13, 是, absolute_geometric_certificate);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-geometric · candidate
13. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-geometric;資料={"a":[13,14],"r":[-1,2]}。請依 [a, r, absolute_series_sum, absolutely_convergent, certificate] 欄序回答。
查看答案與解釋
(13/14, -1/2, 13/7, 是, absolute_geometric_certificate)
Wave5第四層核對=(13/14, -1/2, 13/7, 是, absolute_geometric_certificate);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-geometric · candidate
14. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-geometric;資料={"a":[14,15],"r":[-1,2]}。請依 [a, r, absolute_series_sum, absolutely_convergent, certificate] 欄序回答。
查看答案與解釋
(14/15, -1/2, 28/15, 是, absolute_geometric_certificate)
Wave5第四層核對=(14/15, -1/2, 28/15, 是, absolute_geometric_certificate);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-geometric · candidate
15. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-geometric;資料={"a":[15,16],"r":[-1,2]}。請依 [a, r, absolute_series_sum, absolutely_convergent, certificate] 欄序回答。
查看答案與解釋
(15/16, -1/2, 15/8, 是, absolute_geometric_certificate)
Wave5第四層核對=(15/16, -1/2, 15/8, 是, absolute_geometric_certificate);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-geometric · candidate
16. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-geometric;資料={"a":[16,17],"r":[-1,2]}。請依 [a, r, absolute_series_sum, absolutely_convergent, certificate] 欄序回答。
查看答案與解釋
(16/17, -1/2, 32/17, 是, absolute_geometric_certificate)
Wave5第四層核對=(16/17, -1/2, 32/17, 是, absolute_geometric_certificate);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-geometric · candidate
17. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-geometric;資料={"a":[17,18],"r":[-1,2]}。請依 [a, r, absolute_series_sum, absolutely_convergent, certificate] 欄序回答。
查看答案與解釋
(17/18, -1/2, 17/9, 是, absolute_geometric_certificate)
Wave5第四層核對=(17/18, -1/2, 17/9, 是, absolute_geometric_certificate);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-geometric · candidate
18. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-geometric;資料={"a":[18,19],"r":[-1,2]}。請依 [a, r, absolute_series_sum, absolutely_convergent, certificate] 欄序回答。
查看答案與解釋
(18/19, -1/2, 36/19, 是, absolute_geometric_certificate)
Wave5第四層核對=(18/19, -1/2, 36/19, 是, absolute_geometric_certificate);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-geometric · candidate
19. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-geometric;資料={"a":[19,20],"r":[-1,2]}。請依 [a, r, absolute_series_sum, absolutely_convergent, certificate] 欄序回答。
查看答案與解釋
(19/20, -1/2, 19/10, 是, absolute_geometric_certificate)
Wave5第四層核對=(19/20, -1/2, 19/10, 是, absolute_geometric_certificate);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-geometric · candidate
20. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-geometric;資料={"a":[20,21],"r":[-1,2]}。請依 [a, r, absolute_series_sum, absolutely_convergent, certificate] 欄序回答。
查看答案與解釋
(20/21, -1/2, 40/21, 是, absolute_geometric_certificate)
Wave5第四層核對=(20/21, -1/2, 40/21, 是, absolute_geometric_certificate);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-geometric · candidate
21. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-geometric;資料={"a":[21,22],"r":[-1,2]}。請依 [a, r, absolute_series_sum, absolutely_convergent, certificate] 欄序回答。
查看答案與解釋
(21/22, -1/2, 21/11, 是, absolute_geometric_certificate)
Wave5第四層核對=(21/22, -1/2, 21/11, 是, absolute_geometric_certificate);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-geometric · candidate
22. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-geometric;資料={"a":[22,23],"r":[-1,2]}。請依 [a, r, absolute_series_sum, absolutely_convergent, certificate] 欄序回答。
查看答案與解釋
(22/23, -1/2, 44/23, 是, absolute_geometric_certificate)
Wave5第四層核對=(22/23, -1/2, 44/23, 是, absolute_geometric_certificate);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-geometric · candidate
23. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-geometric;資料={"a":[23,24],"r":[-1,2]}。請依 [a, r, absolute_series_sum, absolutely_convergent, certificate] 欄序回答。
查看答案與解釋
(23/24, -1/2, 23/12, 是, absolute_geometric_certificate)
Wave5第四層核對=(23/24, -1/2, 23/12, 是, absolute_geometric_certificate);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-geometric · candidate
24. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-geometric;資料={"a":[24,25],"r":[-1,2]}。請依 [a, r, absolute_series_sum, absolutely_convergent, certificate] 欄序回答。
查看答案與解釋
(24/25, -1/2, 48/25, 是, absolute_geometric_certificate)
Wave5第四層核對=(24/25, -1/2, 48/25, 是, absolute_geometric_certificate);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-geometric · candidate
25. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-geometric;資料={"a":[25,26],"r":[-1,2]}。請依 [a, r, absolute_series_sum, absolutely_convergent, certificate] 欄序回答。
查看答案與解釋
(25/26, -1/2, 25/13, 是, absolute_geometric_certificate)
Wave5第四層核對=(25/26, -1/2, 25/13, 是, absolute_geometric_certificate);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-geometric · candidate
26. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-conditional-alternating;資料={"shift":1,"n":5}。請依 [shift, n, terms, series_converges, absolutely_converges, certificate] 欄序回答。
查看答案與解釋
(1, 5, [1, -1/2, 1/3, -1/4, 1/5], 是, 否, alternating_remainder_and_harmonic_absolute_divergence)
Wave5第四層核對=(1, 5, [1, -1/2, 1/3, -1/4, 1/5], 是, 否, alternating_remainder_and_harmonic_absolute_divergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-conditional-alternating · candidate
27. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-conditional-alternating;資料={"shift":2,"n":5}。請依 [shift, n, terms, series_converges, absolutely_converges, certificate] 欄序回答。
查看答案與解釋
(2, 5, [1/2, -1/3, 1/4, -1/5, 1/6], 是, 否, alternating_remainder_and_harmonic_absolute_divergence)
Wave5第四層核對=(2, 5, [1/2, -1/3, 1/4, -1/5, 1/6], 是, 否, alternating_remainder_and_harmonic_absolute_divergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-conditional-alternating · candidate
28. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-conditional-alternating;資料={"shift":3,"n":5}。請依 [shift, n, terms, series_converges, absolutely_converges, certificate] 欄序回答。
查看答案與解釋
(3, 5, [1/3, -1/4, 1/5, -1/6, 1/7], 是, 否, alternating_remainder_and_harmonic_absolute_divergence)
Wave5第四層核對=(3, 5, [1/3, -1/4, 1/5, -1/6, 1/7], 是, 否, alternating_remainder_and_harmonic_absolute_divergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-conditional-alternating · candidate
29. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-conditional-alternating;資料={"shift":4,"n":5}。請依 [shift, n, terms, series_converges, absolutely_converges, certificate] 欄序回答。
查看答案與解釋
(4, 5, [1/4, -1/5, 1/6, -1/7, 1/8], 是, 否, alternating_remainder_and_harmonic_absolute_divergence)
Wave5第四層核對=(4, 5, [1/4, -1/5, 1/6, -1/7, 1/8], 是, 否, alternating_remainder_and_harmonic_absolute_divergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-conditional-alternating · candidate
30. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-conditional-alternating;資料={"shift":5,"n":5}。請依 [shift, n, terms, series_converges, absolutely_converges, certificate] 欄序回答。
查看答案與解釋
(5, 5, [1/5, -1/6, 1/7, -1/8, 1/9], 是, 否, alternating_remainder_and_harmonic_absolute_divergence)
Wave5第四層核對=(5, 5, [1/5, -1/6, 1/7, -1/8, 1/9], 是, 否, alternating_remainder_and_harmonic_absolute_divergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-conditional-alternating · candidate
31. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-conditional-alternating;資料={"shift":6,"n":5}。請依 [shift, n, terms, series_converges, absolutely_converges, certificate] 欄序回答。
查看答案與解釋
(6, 5, [1/6, -1/7, 1/8, -1/9, 1/10], 是, 否, alternating_remainder_and_harmonic_absolute_divergence)
Wave5第四層核對=(6, 5, [1/6, -1/7, 1/8, -1/9, 1/10], 是, 否, alternating_remainder_and_harmonic_absolute_divergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-conditional-alternating · candidate
32. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-conditional-alternating;資料={"shift":7,"n":5}。請依 [shift, n, terms, series_converges, absolutely_converges, certificate] 欄序回答。
查看答案與解釋
(7, 5, [1/7, -1/8, 1/9, -1/10, 1/11], 是, 否, alternating_remainder_and_harmonic_absolute_divergence)
Wave5第四層核對=(7, 5, [1/7, -1/8, 1/9, -1/10, 1/11], 是, 否, alternating_remainder_and_harmonic_absolute_divergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-conditional-alternating · candidate
33. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-conditional-alternating;資料={"shift":8,"n":5}。請依 [shift, n, terms, series_converges, absolutely_converges, certificate] 欄序回答。
查看答案與解釋
(8, 5, [1/8, -1/9, 1/10, -1/11, 1/12], 是, 否, alternating_remainder_and_harmonic_absolute_divergence)
Wave5第四層核對=(8, 5, [1/8, -1/9, 1/10, -1/11, 1/12], 是, 否, alternating_remainder_and_harmonic_absolute_divergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-conditional-alternating · candidate
34. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-conditional-alternating;資料={"shift":9,"n":5}。請依 [shift, n, terms, series_converges, absolutely_converges, certificate] 欄序回答。
查看答案與解釋
(9, 5, [1/9, -1/10, 1/11, -1/12, 1/13], 是, 否, alternating_remainder_and_harmonic_absolute_divergence)
Wave5第四層核對=(9, 5, [1/9, -1/10, 1/11, -1/12, 1/13], 是, 否, alternating_remainder_and_harmonic_absolute_divergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-conditional-alternating · candidate
35. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-conditional-alternating;資料={"shift":10,"n":5}。請依 [shift, n, terms, series_converges, absolutely_converges, certificate] 欄序回答。
查看答案與解釋
(10, 5, [1/10, -1/11, 1/12, -1/13, 1/14], 是, 否, alternating_remainder_and_harmonic_absolute_divergence)
Wave5第四層核對=(10, 5, [1/10, -1/11, 1/12, -1/13, 1/14], 是, 否, alternating_remainder_and_harmonic_absolute_divergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-conditional-alternating · candidate
36. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-conditional-alternating;資料={"shift":11,"n":5}。請依 [shift, n, terms, series_converges, absolutely_converges, certificate] 欄序回答。
查看答案與解釋
(11, 5, [1/11, -1/12, 1/13, -1/14, 1/15], 是, 否, alternating_remainder_and_harmonic_absolute_divergence)
Wave5第四層核對=(11, 5, [1/11, -1/12, 1/13, -1/14, 1/15], 是, 否, alternating_remainder_and_harmonic_absolute_divergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-conditional-alternating · candidate
37. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-conditional-alternating;資料={"shift":12,"n":5}。請依 [shift, n, terms, series_converges, absolutely_converges, certificate] 欄序回答。
查看答案與解釋
(12, 5, [1/12, -1/13, 1/14, -1/15, 1/16], 是, 否, alternating_remainder_and_harmonic_absolute_divergence)
Wave5第四層核對=(12, 5, [1/12, -1/13, 1/14, -1/15, 1/16], 是, 否, alternating_remainder_and_harmonic_absolute_divergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-conditional-alternating · candidate
38. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-conditional-alternating;資料={"shift":13,"n":5}。請依 [shift, n, terms, series_converges, absolutely_converges, certificate] 欄序回答。
查看答案與解釋
(13, 5, [1/13, -1/14, 1/15, -1/16, 1/17], 是, 否, alternating_remainder_and_harmonic_absolute_divergence)
Wave5第四層核對=(13, 5, [1/13, -1/14, 1/15, -1/16, 1/17], 是, 否, alternating_remainder_and_harmonic_absolute_divergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-conditional-alternating · candidate
39. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-conditional-alternating;資料={"shift":14,"n":5}。請依 [shift, n, terms, series_converges, absolutely_converges, certificate] 欄序回答。
查看答案與解釋
(14, 5, [1/14, -1/15, 1/16, -1/17, 1/18], 是, 否, alternating_remainder_and_harmonic_absolute_divergence)
Wave5第四層核對=(14, 5, [1/14, -1/15, 1/16, -1/17, 1/18], 是, 否, alternating_remainder_and_harmonic_absolute_divergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-conditional-alternating · candidate
40. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-conditional-alternating;資料={"shift":15,"n":5}。請依 [shift, n, terms, series_converges, absolutely_converges, certificate] 欄序回答。
查看答案與解釋
(15, 5, [1/15, -1/16, 1/17, -1/18, 1/19], 是, 否, alternating_remainder_and_harmonic_absolute_divergence)
Wave5第四層核對=(15, 5, [1/15, -1/16, 1/17, -1/18, 1/19], 是, 否, alternating_remainder_and_harmonic_absolute_divergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-conditional-alternating · candidate
41. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-conditional-alternating;資料={"shift":16,"n":5}。請依 [shift, n, terms, series_converges, absolutely_converges, certificate] 欄序回答。
查看答案與解釋
(16, 5, [1/16, -1/17, 1/18, -1/19, 1/20], 是, 否, alternating_remainder_and_harmonic_absolute_divergence)
Wave5第四層核對=(16, 5, [1/16, -1/17, 1/18, -1/19, 1/20], 是, 否, alternating_remainder_and_harmonic_absolute_divergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-conditional-alternating · candidate
42. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-conditional-alternating;資料={"shift":17,"n":5}。請依 [shift, n, terms, series_converges, absolutely_converges, certificate] 欄序回答。
查看答案與解釋
(17, 5, [1/17, -1/18, 1/19, -1/20, 1/21], 是, 否, alternating_remainder_and_harmonic_absolute_divergence)
Wave5第四層核對=(17, 5, [1/17, -1/18, 1/19, -1/20, 1/21], 是, 否, alternating_remainder_and_harmonic_absolute_divergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-conditional-alternating · candidate
43. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-conditional-alternating;資料={"shift":18,"n":5}。請依 [shift, n, terms, series_converges, absolutely_converges, certificate] 欄序回答。
查看答案與解釋
(18, 5, [1/18, -1/19, 1/20, -1/21, 1/22], 是, 否, alternating_remainder_and_harmonic_absolute_divergence)
Wave5第四層核對=(18, 5, [1/18, -1/19, 1/20, -1/21, 1/22], 是, 否, alternating_remainder_and_harmonic_absolute_divergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-conditional-alternating · candidate
44. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-conditional-alternating;資料={"shift":19,"n":5}。請依 [shift, n, terms, series_converges, absolutely_converges, certificate] 欄序回答。
查看答案與解釋
(19, 5, [1/19, -1/20, 1/21, -1/22, 1/23], 是, 否, alternating_remainder_and_harmonic_absolute_divergence)
Wave5第四層核對=(19, 5, [1/19, -1/20, 1/21, -1/22, 1/23], 是, 否, alternating_remainder_and_harmonic_absolute_divergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-conditional-alternating · candidate
45. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-conditional-alternating;資料={"shift":20,"n":5}。請依 [shift, n, terms, series_converges, absolutely_converges, certificate] 欄序回答。
查看答案與解釋
(20, 5, [1/20, -1/21, 1/22, -1/23, 1/24], 是, 否, alternating_remainder_and_harmonic_absolute_divergence)
Wave5第四層核對=(20, 5, [1/20, -1/21, 1/22, -1/23, 1/24], 是, 否, alternating_remainder_and_harmonic_absolute_divergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-conditional-alternating · candidate
46. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-conditional-alternating;資料={"shift":21,"n":5}。請依 [shift, n, terms, series_converges, absolutely_converges, certificate] 欄序回答。
查看答案與解釋
(21, 5, [1/21, -1/22, 1/23, -1/24, 1/25], 是, 否, alternating_remainder_and_harmonic_absolute_divergence)
Wave5第四層核對=(21, 5, [1/21, -1/22, 1/23, -1/24, 1/25], 是, 否, alternating_remainder_and_harmonic_absolute_divergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-conditional-alternating · candidate
47. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-conditional-alternating;資料={"shift":22,"n":5}。請依 [shift, n, terms, series_converges, absolutely_converges, certificate] 欄序回答。
查看答案與解釋
(22, 5, [1/22, -1/23, 1/24, -1/25, 1/26], 是, 否, alternating_remainder_and_harmonic_absolute_divergence)
Wave5第四層核對=(22, 5, [1/22, -1/23, 1/24, -1/25, 1/26], 是, 否, alternating_remainder_and_harmonic_absolute_divergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-conditional-alternating · candidate
48. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-conditional-alternating;資料={"shift":23,"n":5}。請依 [shift, n, terms, series_converges, absolutely_converges, certificate] 欄序回答。
查看答案與解釋
(23, 5, [1/23, -1/24, 1/25, -1/26, 1/27], 是, 否, alternating_remainder_and_harmonic_absolute_divergence)
Wave5第四層核對=(23, 5, [1/23, -1/24, 1/25, -1/26, 1/27], 是, 否, alternating_remainder_and_harmonic_absolute_divergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-conditional-alternating · candidate
49. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-conditional-alternating;資料={"shift":24,"n":5}。請依 [shift, n, terms, series_converges, absolutely_converges, certificate] 欄序回答。
查看答案與解釋
(24, 5, [1/24, -1/25, 1/26, -1/27, 1/28], 是, 否, alternating_remainder_and_harmonic_absolute_divergence)
Wave5第四層核對=(24, 5, [1/24, -1/25, 1/26, -1/27, 1/28], 是, 否, alternating_remainder_and_harmonic_absolute_divergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-conditional-alternating · candidate
50. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-conditional-alternating;資料={"shift":25,"n":5}。請依 [shift, n, terms, series_converges, absolutely_converges, certificate] 欄序回答。
查看答案與解釋
(25, 5, [1/25, -1/26, 1/27, -1/28, 1/29], 是, 否, alternating_remainder_and_harmonic_absolute_divergence)
Wave5第四層核對=(25, 5, [1/25, -1/26, 1/27, -1/28, 1/29], 是, 否, alternating_remainder_and_harmonic_absolute_divergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-conditional-alternating · candidate
51. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-absolute-partial;資料={"terms":[[1,2],[-1,3]]}。請依 [terms, absolute_terms, absolute_partial_sum, boundary] 欄序回答。
查看答案與解釋
([1/2, -1/3], [1/2, 1/3], 5/6, finite_absolute_partial_sum_only)
Wave5第四層核對=([1/2, -1/3], [1/2, 1/3], 5/6, finite_absolute_partial_sum_only);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-absolute-partial · candidate
52. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-absolute-partial;資料={"terms":[[1,3],[-1,4]]}。請依 [terms, absolute_terms, absolute_partial_sum, boundary] 欄序回答。
查看答案與解釋
([1/3, -1/4], [1/3, 1/4], 7/12, finite_absolute_partial_sum_only)
Wave5第四層核對=([1/3, -1/4], [1/3, 1/4], 7/12, finite_absolute_partial_sum_only);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-absolute-partial · candidate
53. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-absolute-partial;資料={"terms":[[1,4],[-1,5]]}。請依 [terms, absolute_terms, absolute_partial_sum, boundary] 欄序回答。
查看答案與解釋
([1/4, -1/5], [1/4, 1/5], 9/20, finite_absolute_partial_sum_only)
Wave5第四層核對=([1/4, -1/5], [1/4, 1/5], 9/20, finite_absolute_partial_sum_only);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-absolute-partial · candidate
54. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-absolute-partial;資料={"terms":[[1,5],[-1,6]]}。請依 [terms, absolute_terms, absolute_partial_sum, boundary] 欄序回答。
查看答案與解釋
([1/5, -1/6], [1/5, 1/6], 11/30, finite_absolute_partial_sum_only)
Wave5第四層核對=([1/5, -1/6], [1/5, 1/6], 11/30, finite_absolute_partial_sum_only);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-absolute-partial · candidate
55. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-absolute-partial;資料={"terms":[[1,6],[-1,7]]}。請依 [terms, absolute_terms, absolute_partial_sum, boundary] 欄序回答。
查看答案與解釋
([1/6, -1/7], [1/6, 1/7], 13/42, finite_absolute_partial_sum_only)
Wave5第四層核對=([1/6, -1/7], [1/6, 1/7], 13/42, finite_absolute_partial_sum_only);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-absolute-partial · candidate
56. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-absolute-partial;資料={"terms":[[1,7],[-1,8]]}。請依 [terms, absolute_terms, absolute_partial_sum, boundary] 欄序回答。
查看答案與解釋
([1/7, -1/8], [1/7, 1/8], 15/56, finite_absolute_partial_sum_only)
Wave5第四層核對=([1/7, -1/8], [1/7, 1/8], 15/56, finite_absolute_partial_sum_only);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-absolute-partial · candidate
57. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-absolute-partial;資料={"terms":[[1,8],[-1,9]]}。請依 [terms, absolute_terms, absolute_partial_sum, boundary] 欄序回答。
查看答案與解釋
([1/8, -1/9], [1/8, 1/9], 17/72, finite_absolute_partial_sum_only)
Wave5第四層核對=([1/8, -1/9], [1/8, 1/9], 17/72, finite_absolute_partial_sum_only);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-absolute-partial · candidate
58. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-absolute-partial;資料={"terms":[[1,9],[-1,10]]}。請依 [terms, absolute_terms, absolute_partial_sum, boundary] 欄序回答。
查看答案與解釋
([1/9, -1/10], [1/9, 1/10], 19/90, finite_absolute_partial_sum_only)
Wave5第四層核對=([1/9, -1/10], [1/9, 1/10], 19/90, finite_absolute_partial_sum_only);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-absolute-partial · candidate
59. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-absolute-partial;資料={"terms":[[1,10],[-1,11]]}。請依 [terms, absolute_terms, absolute_partial_sum, boundary] 欄序回答。
查看答案與解釋
([1/10, -1/11], [1/10, 1/11], 21/110, finite_absolute_partial_sum_only)
Wave5第四層核對=([1/10, -1/11], [1/10, 1/11], 21/110, finite_absolute_partial_sum_only);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-absolute-partial · candidate
60. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-absolute-partial;資料={"terms":[[1,11],[-1,12]]}。請依 [terms, absolute_terms, absolute_partial_sum, boundary] 欄序回答。
查看答案與解釋
([1/11, -1/12], [1/11, 1/12], 23/132, finite_absolute_partial_sum_only)
Wave5第四層核對=([1/11, -1/12], [1/11, 1/12], 23/132, finite_absolute_partial_sum_only);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-absolute-partial · candidate
61. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-absolute-partial;資料={"terms":[[1,12],[-1,13]]}。請依 [terms, absolute_terms, absolute_partial_sum, boundary] 欄序回答。
查看答案與解釋
([1/12, -1/13], [1/12, 1/13], 25/156, finite_absolute_partial_sum_only)
Wave5第四層核對=([1/12, -1/13], [1/12, 1/13], 25/156, finite_absolute_partial_sum_only);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-absolute-partial · candidate
62. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-absolute-partial;資料={"terms":[[1,13],[-1,14]]}。請依 [terms, absolute_terms, absolute_partial_sum, boundary] 欄序回答。
查看答案與解釋
([1/13, -1/14], [1/13, 1/14], 27/182, finite_absolute_partial_sum_only)
Wave5第四層核對=([1/13, -1/14], [1/13, 1/14], 27/182, finite_absolute_partial_sum_only);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-absolute-partial · candidate
63. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-absolute-partial;資料={"terms":[[1,14],[-1,15]]}。請依 [terms, absolute_terms, absolute_partial_sum, boundary] 欄序回答。
查看答案與解釋
([1/14, -1/15], [1/14, 1/15], 29/210, finite_absolute_partial_sum_only)
Wave5第四層核對=([1/14, -1/15], [1/14, 1/15], 29/210, finite_absolute_partial_sum_only);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-absolute-partial · candidate
64. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-absolute-partial;資料={"terms":[[1,15],[-1,16]]}。請依 [terms, absolute_terms, absolute_partial_sum, boundary] 欄序回答。
查看答案與解釋
([1/15, -1/16], [1/15, 1/16], 31/240, finite_absolute_partial_sum_only)
Wave5第四層核對=([1/15, -1/16], [1/15, 1/16], 31/240, finite_absolute_partial_sum_only);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-absolute-partial · candidate
65. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-absolute-partial;資料={"terms":[[1,16],[-1,17]]}。請依 [terms, absolute_terms, absolute_partial_sum, boundary] 欄序回答。
查看答案與解釋
([1/16, -1/17], [1/16, 1/17], 33/272, finite_absolute_partial_sum_only)
Wave5第四層核對=([1/16, -1/17], [1/16, 1/17], 33/272, finite_absolute_partial_sum_only);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-absolute-partial · candidate
66. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-absolute-partial;資料={"terms":[[1,17],[-1,18]]}。請依 [terms, absolute_terms, absolute_partial_sum, boundary] 欄序回答。
查看答案與解釋
([1/17, -1/18], [1/17, 1/18], 35/306, finite_absolute_partial_sum_only)
Wave5第四層核對=([1/17, -1/18], [1/17, 1/18], 35/306, finite_absolute_partial_sum_only);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-absolute-partial · candidate
67. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-absolute-partial;資料={"terms":[[1,18],[-1,19]]}。請依 [terms, absolute_terms, absolute_partial_sum, boundary] 欄序回答。
查看答案與解釋
([1/18, -1/19], [1/18, 1/19], 37/342, finite_absolute_partial_sum_only)
Wave5第四層核對=([1/18, -1/19], [1/18, 1/19], 37/342, finite_absolute_partial_sum_only);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-absolute-partial · candidate
68. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-absolute-partial;資料={"terms":[[1,19],[-1,20]]}。請依 [terms, absolute_terms, absolute_partial_sum, boundary] 欄序回答。
查看答案與解釋
([1/19, -1/20], [1/19, 1/20], 39/380, finite_absolute_partial_sum_only)
Wave5第四層核對=([1/19, -1/20], [1/19, 1/20], 39/380, finite_absolute_partial_sum_only);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-absolute-partial · candidate
69. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-absolute-partial;資料={"terms":[[1,20],[-1,21]]}。請依 [terms, absolute_terms, absolute_partial_sum, boundary] 欄序回答。
查看答案與解釋
([1/20, -1/21], [1/20, 1/21], 41/420, finite_absolute_partial_sum_only)
Wave5第四層核對=([1/20, -1/21], [1/20, 1/21], 41/420, finite_absolute_partial_sum_only);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-absolute-partial · candidate
70. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-absolute-partial;資料={"terms":[[1,21],[-1,22]]}。請依 [terms, absolute_terms, absolute_partial_sum, boundary] 欄序回答。
查看答案與解釋
([1/21, -1/22], [1/21, 1/22], 43/462, finite_absolute_partial_sum_only)
Wave5第四層核對=([1/21, -1/22], [1/21, 1/22], 43/462, finite_absolute_partial_sum_only);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-absolute-partial · candidate
71. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-absolute-partial;資料={"terms":[[1,22],[-1,23]]}。請依 [terms, absolute_terms, absolute_partial_sum, boundary] 欄序回答。
查看答案與解釋
([1/22, -1/23], [1/22, 1/23], 45/506, finite_absolute_partial_sum_only)
Wave5第四層核對=([1/22, -1/23], [1/22, 1/23], 45/506, finite_absolute_partial_sum_only);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-absolute-partial · candidate
72. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-absolute-partial;資料={"terms":[[1,23],[-1,24]]}。請依 [terms, absolute_terms, absolute_partial_sum, boundary] 欄序回答。
查看答案與解釋
([1/23, -1/24], [1/23, 1/24], 47/552, finite_absolute_partial_sum_only)
Wave5第四層核對=([1/23, -1/24], [1/23, 1/24], 47/552, finite_absolute_partial_sum_only);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-absolute-partial · candidate
73. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-absolute-partial;資料={"terms":[[1,24],[-1,25]]}。請依 [terms, absolute_terms, absolute_partial_sum, boundary] 欄序回答。
查看答案與解釋
([1/24, -1/25], [1/24, 1/25], 49/600, finite_absolute_partial_sum_only)
Wave5第四層核對=([1/24, -1/25], [1/24, 1/25], 49/600, finite_absolute_partial_sum_only);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-absolute-partial · candidate
74. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-absolute-partial;資料={"terms":[[1,25],[-1,26]]}。請依 [terms, absolute_terms, absolute_partial_sum, boundary] 欄序回答。
查看答案與解釋
([1/25, -1/26], [1/25, 1/26], 51/650, finite_absolute_partial_sum_only)
Wave5第四層核對=([1/25, -1/26], [1/25, 1/26], 51/650, finite_absolute_partial_sum_only);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-absolute-partial · candidate
75. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-absolute-partial;資料={"terms":[[1,26],[-1,27]]}。請依 [terms, absolute_terms, absolute_partial_sum, boundary] 欄序回答。
查看答案與解釋
([1/26, -1/27], [1/26, 1/27], 53/702, finite_absolute_partial_sum_only)
Wave5第四層核對=([1/26, -1/27], [1/26, 1/27], 53/702, finite_absolute_partial_sum_only);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-absolute-partial · candidate
76. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-term-zero-boundary;資料={"shift":1,"prefix_length":5}。請依 [shift, prefix_length, terms_tend_to_zero, term_zero_suffices_for_absolute_convergence, boundary] 欄序回答。
查看答案與解釋
(1, 5, 是, 否, term_zero_not_absolute_convergence)
Wave5第四層核對=(1, 5, 是, 否, term_zero_not_absolute_convergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-term-zero-boundary · candidate
77. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-term-zero-boundary;資料={"shift":2,"prefix_length":5}。請依 [shift, prefix_length, terms_tend_to_zero, term_zero_suffices_for_absolute_convergence, boundary] 欄序回答。
查看答案與解釋
(2, 5, 是, 否, term_zero_not_absolute_convergence)
Wave5第四層核對=(2, 5, 是, 否, term_zero_not_absolute_convergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-term-zero-boundary · candidate
78. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-term-zero-boundary;資料={"shift":3,"prefix_length":5}。請依 [shift, prefix_length, terms_tend_to_zero, term_zero_suffices_for_absolute_convergence, boundary] 欄序回答。
查看答案與解釋
(3, 5, 是, 否, term_zero_not_absolute_convergence)
Wave5第四層核對=(3, 5, 是, 否, term_zero_not_absolute_convergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-term-zero-boundary · candidate
79. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-term-zero-boundary;資料={"shift":4,"prefix_length":5}。請依 [shift, prefix_length, terms_tend_to_zero, term_zero_suffices_for_absolute_convergence, boundary] 欄序回答。
查看答案與解釋
(4, 5, 是, 否, term_zero_not_absolute_convergence)
Wave5第四層核對=(4, 5, 是, 否, term_zero_not_absolute_convergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-term-zero-boundary · candidate
80. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-term-zero-boundary;資料={"shift":5,"prefix_length":5}。請依 [shift, prefix_length, terms_tend_to_zero, term_zero_suffices_for_absolute_convergence, boundary] 欄序回答。
查看答案與解釋
(5, 5, 是, 否, term_zero_not_absolute_convergence)
Wave5第四層核對=(5, 5, 是, 否, term_zero_not_absolute_convergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-term-zero-boundary · candidate
81. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-term-zero-boundary;資料={"shift":6,"prefix_length":5}。請依 [shift, prefix_length, terms_tend_to_zero, term_zero_suffices_for_absolute_convergence, boundary] 欄序回答。
查看答案與解釋
(6, 5, 是, 否, term_zero_not_absolute_convergence)
Wave5第四層核對=(6, 5, 是, 否, term_zero_not_absolute_convergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-term-zero-boundary · candidate
82. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-term-zero-boundary;資料={"shift":7,"prefix_length":5}。請依 [shift, prefix_length, terms_tend_to_zero, term_zero_suffices_for_absolute_convergence, boundary] 欄序回答。
查看答案與解釋
(7, 5, 是, 否, term_zero_not_absolute_convergence)
Wave5第四層核對=(7, 5, 是, 否, term_zero_not_absolute_convergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-term-zero-boundary · candidate
83. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-term-zero-boundary;資料={"shift":8,"prefix_length":5}。請依 [shift, prefix_length, terms_tend_to_zero, term_zero_suffices_for_absolute_convergence, boundary] 欄序回答。
查看答案與解釋
(8, 5, 是, 否, term_zero_not_absolute_convergence)
Wave5第四層核對=(8, 5, 是, 否, term_zero_not_absolute_convergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-term-zero-boundary · candidate
84. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-term-zero-boundary;資料={"shift":9,"prefix_length":5}。請依 [shift, prefix_length, terms_tend_to_zero, term_zero_suffices_for_absolute_convergence, boundary] 欄序回答。
查看答案與解釋
(9, 5, 是, 否, term_zero_not_absolute_convergence)
Wave5第四層核對=(9, 5, 是, 否, term_zero_not_absolute_convergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-term-zero-boundary · candidate
85. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-term-zero-boundary;資料={"shift":10,"prefix_length":5}。請依 [shift, prefix_length, terms_tend_to_zero, term_zero_suffices_for_absolute_convergence, boundary] 欄序回答。
查看答案與解釋
(10, 5, 是, 否, term_zero_not_absolute_convergence)
Wave5第四層核對=(10, 5, 是, 否, term_zero_not_absolute_convergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-term-zero-boundary · candidate
86. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-term-zero-boundary;資料={"shift":11,"prefix_length":5}。請依 [shift, prefix_length, terms_tend_to_zero, term_zero_suffices_for_absolute_convergence, boundary] 欄序回答。
查看答案與解釋
(11, 5, 是, 否, term_zero_not_absolute_convergence)
Wave5第四層核對=(11, 5, 是, 否, term_zero_not_absolute_convergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-term-zero-boundary · candidate
87. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-term-zero-boundary;資料={"shift":12,"prefix_length":5}。請依 [shift, prefix_length, terms_tend_to_zero, term_zero_suffices_for_absolute_convergence, boundary] 欄序回答。
查看答案與解釋
(12, 5, 是, 否, term_zero_not_absolute_convergence)
Wave5第四層核對=(12, 5, 是, 否, term_zero_not_absolute_convergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-term-zero-boundary · candidate
88. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-term-zero-boundary;資料={"shift":13,"prefix_length":5}。請依 [shift, prefix_length, terms_tend_to_zero, term_zero_suffices_for_absolute_convergence, boundary] 欄序回答。
查看答案與解釋
(13, 5, 是, 否, term_zero_not_absolute_convergence)
Wave5第四層核對=(13, 5, 是, 否, term_zero_not_absolute_convergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-term-zero-boundary · candidate
89. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-term-zero-boundary;資料={"shift":14,"prefix_length":5}。請依 [shift, prefix_length, terms_tend_to_zero, term_zero_suffices_for_absolute_convergence, boundary] 欄序回答。
查看答案與解釋
(14, 5, 是, 否, term_zero_not_absolute_convergence)
Wave5第四層核對=(14, 5, 是, 否, term_zero_not_absolute_convergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-term-zero-boundary · candidate
90. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-term-zero-boundary;資料={"shift":15,"prefix_length":5}。請依 [shift, prefix_length, terms_tend_to_zero, term_zero_suffices_for_absolute_convergence, boundary] 欄序回答。
查看答案與解釋
(15, 5, 是, 否, term_zero_not_absolute_convergence)
Wave5第四層核對=(15, 5, 是, 否, term_zero_not_absolute_convergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-term-zero-boundary · candidate
91. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-term-zero-boundary;資料={"shift":16,"prefix_length":5}。請依 [shift, prefix_length, terms_tend_to_zero, term_zero_suffices_for_absolute_convergence, boundary] 欄序回答。
查看答案與解釋
(16, 5, 是, 否, term_zero_not_absolute_convergence)
Wave5第四層核對=(16, 5, 是, 否, term_zero_not_absolute_convergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-term-zero-boundary · candidate
92. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-term-zero-boundary;資料={"shift":17,"prefix_length":5}。請依 [shift, prefix_length, terms_tend_to_zero, term_zero_suffices_for_absolute_convergence, boundary] 欄序回答。
查看答案與解釋
(17, 5, 是, 否, term_zero_not_absolute_convergence)
Wave5第四層核對=(17, 5, 是, 否, term_zero_not_absolute_convergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-term-zero-boundary · candidate
93. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-term-zero-boundary;資料={"shift":18,"prefix_length":5}。請依 [shift, prefix_length, terms_tend_to_zero, term_zero_suffices_for_absolute_convergence, boundary] 欄序回答。
查看答案與解釋
(18, 5, 是, 否, term_zero_not_absolute_convergence)
Wave5第四層核對=(18, 5, 是, 否, term_zero_not_absolute_convergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-term-zero-boundary · candidate
94. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-term-zero-boundary;資料={"shift":19,"prefix_length":5}。請依 [shift, prefix_length, terms_tend_to_zero, term_zero_suffices_for_absolute_convergence, boundary] 欄序回答。
查看答案與解釋
(19, 5, 是, 否, term_zero_not_absolute_convergence)
Wave5第四層核對=(19, 5, 是, 否, term_zero_not_absolute_convergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-term-zero-boundary · candidate
95. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-term-zero-boundary;資料={"shift":20,"prefix_length":5}。請依 [shift, prefix_length, terms_tend_to_zero, term_zero_suffices_for_absolute_convergence, boundary] 欄序回答。
查看答案與解釋
(20, 5, 是, 否, term_zero_not_absolute_convergence)
Wave5第四層核對=(20, 5, 是, 否, term_zero_not_absolute_convergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-term-zero-boundary · candidate
96. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-term-zero-boundary;資料={"shift":21,"prefix_length":5}。請依 [shift, prefix_length, terms_tend_to_zero, term_zero_suffices_for_absolute_convergence, boundary] 欄序回答。
查看答案與解釋
(21, 5, 是, 否, term_zero_not_absolute_convergence)
Wave5第四層核對=(21, 5, 是, 否, term_zero_not_absolute_convergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-term-zero-boundary · candidate
97. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-term-zero-boundary;資料={"shift":22,"prefix_length":5}。請依 [shift, prefix_length, terms_tend_to_zero, term_zero_suffices_for_absolute_convergence, boundary] 欄序回答。
查看答案與解釋
(22, 5, 是, 否, term_zero_not_absolute_convergence)
Wave5第四層核對=(22, 5, 是, 否, term_zero_not_absolute_convergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-term-zero-boundary · candidate
98. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-term-zero-boundary;資料={"shift":23,"prefix_length":5}。請依 [shift, prefix_length, terms_tend_to_zero, term_zero_suffices_for_absolute_convergence, boundary] 欄序回答。
查看答案與解釋
(23, 5, 是, 否, term_zero_not_absolute_convergence)
Wave5第四層核對=(23, 5, 是, 否, term_zero_not_absolute_convergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-term-zero-boundary · candidate
99. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-term-zero-boundary;資料={"shift":24,"prefix_length":5}。請依 [shift, prefix_length, terms_tend_to_zero, term_zero_suffices_for_absolute_convergence, boundary] 欄序回答。
查看答案與解釋
(24, 5, 是, 否, term_zero_not_absolute_convergence)
Wave5第四層核對=(24, 5, 是, 否, term_zero_not_absolute_convergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-term-zero-boundary · candidate
100. 絕對收斂
partial sums與absolute-series exact convergence certificate。操作=absseries-term-zero-boundary;資料={"shift":25,"prefix_length":5}。請依 [shift, prefix_length, terms_tend_to_zero, term_zero_suffices_for_absolute_convergence, boundary] 欄序回答。
查看答案與解釋
(25, 5, 是, 否, term_zero_not_absolute_convergence)
Wave5第四層核對=(25, 5, 是, 否, term_zero_not_absolute_convergence);依完整明示資料重算;absolute convergence核sum absolute values並推出原級數收斂;term趨零 bounded或alternation不足;conditional需雙證書。
本題逐步詳解(AI 二次覆核)
級數絕對收斂 · qf-mod35-absseries-term-zero-boundary · candidate
原始題目 JSONL · 驗收報告