子空間拓撲基礎 · 脈衝 R03
本批已通過 Schema、去重、來源快照與獨立答案重算；仍未標記為人工審定。
本題庫已有對應的中英逐步詳解。原題的 candidate 與英文 ai_candidate 狀態保留；AI 覆核、有限計算與 Lean 形式證明分開標示。
batch-20261014-advance-20261108-r03-subspace-topology-foundations · 2026-10-14 · 100 題
欄序為來源綁定的呈現補充；原始 JSONL 與數學答案不變。
欄序與來源綁定資料
1. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-induced-topology；資料={"n":5,"parent_topology":[[],[0],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4]],"subset":[1,3,4]}。請依 [subset, induced_topology, open_count, topology_certificate, certificate] 欄序回答。
查看答案與解釋
([1, 3, 4], [[], [1], [1, 3], [1, 3, 4]], 4, 是, all_parent_open_intersections_normalized)
Wave6第二層核對=([1, 3, 4], [[], [1], [1, 3], [1, 3, 4]], 4, 是, all_parent_open_intersections_normalized)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-induced-topology · candidate
2. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-induced-topology；資料={"n":5,"parent_topology":[[],[0],[0,1],[0,1,2],[0,1,2,3,4],[0,1,2,4]],"subset":[1,3,4]}。請依 [subset, induced_topology, open_count, topology_certificate, certificate] 欄序回答。
查看答案與解釋
([1, 3, 4], [[], [1], [1, 3, 4], [1, 4]], 4, 是, all_parent_open_intersections_normalized)
Wave6第二層核對=([1, 3, 4], [[], [1], [1, 3, 4], [1, 4]], 4, 是, all_parent_open_intersections_normalized)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-induced-topology · candidate
3. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-induced-topology；資料={"n":5,"parent_topology":[[],[0],[0,1],[0,1,2,3],[0,1,2,3,4],[0,1,3]],"subset":[1,2,4]}。請依 [subset, induced_topology, open_count, topology_certificate, certificate] 欄序回答。
查看答案與解釋
([1, 2, 4], [[], [1], [1, 2], [1, 2, 4]], 4, 是, all_parent_open_intersections_normalized)
Wave6第二層核對=([1, 2, 4], [[], [1], [1, 2], [1, 2, 4]], 4, 是, all_parent_open_intersections_normalized)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-induced-topology · candidate
4. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-induced-topology；資料={"n":5,"parent_topology":[[],[0],[0,1],[0,1,2,3,4],[0,1,3],[0,1,3,4]],"subset":[1,2,4]}。請依 [subset, induced_topology, open_count, topology_certificate, certificate] 欄序回答。
查看答案與解釋
([1, 2, 4], [[], [1], [1, 2, 4], [1, 4]], 4, 是, all_parent_open_intersections_normalized)
Wave6第二層核對=([1, 2, 4], [[], [1], [1, 2, 4], [1, 4]], 4, 是, all_parent_open_intersections_normalized)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-induced-topology · candidate
5. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-induced-topology；資料={"n":5,"parent_topology":[[],[0],[0,1],[0,1,2,3,4],[0,1,2,4],[0,1,4]],"subset":[1,2,3]}。請依 [subset, induced_topology, open_count, topology_certificate, certificate] 欄序回答。
查看答案與解釋
([1, 2, 3], [[], [1], [1, 2], [1, 2, 3]], 4, 是, all_parent_open_intersections_normalized)
Wave6第二層核對=([1, 2, 3], [[], [1], [1, 2], [1, 2, 3]], 4, 是, all_parent_open_intersections_normalized)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-induced-topology · candidate
6. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-induced-topology；資料={"n":5,"parent_topology":[[],[0],[0,1],[0,1,2,3,4],[0,1,3,4],[0,1,4]],"subset":[1,2,3]}。請依 [subset, induced_topology, open_count, topology_certificate, certificate] 欄序回答。
查看答案與解釋
([1, 2, 3], [[], [1], [1, 2, 3], [1, 3]], 4, 是, all_parent_open_intersections_normalized)
Wave6第二層核對=([1, 2, 3], [[], [1], [1, 2, 3], [1, 3]], 4, 是, all_parent_open_intersections_normalized)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-induced-topology · candidate
7. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-induced-topology；資料={"n":5,"parent_topology":[[],[0],[0,1,2],[0,1,2,3],[0,1,2,3,4],[0,2]],"subset":[2,3,4]}。請依 [subset, induced_topology, open_count, topology_certificate, certificate] 欄序回答。
查看答案與解釋
([2, 3, 4], [[], [2], [2, 3], [2, 3, 4]], 4, 是, all_parent_open_intersections_normalized)
Wave6第二層核對=([2, 3, 4], [[], [2], [2, 3], [2, 3, 4]], 4, 是, all_parent_open_intersections_normalized)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-induced-topology · candidate
8. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-induced-topology；資料={"n":5,"parent_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,1,2,4],[0,2]],"subset":[2,3,4]}。請依 [subset, induced_topology, open_count, topology_certificate, certificate] 欄序回答。
查看答案與解釋
([2, 3, 4], [[], [2], [2, 3, 4], [2, 4]], 4, 是, all_parent_open_intersections_normalized)
Wave6第二層核對=([2, 3, 4], [[], [2], [2, 3, 4], [2, 4]], 4, 是, all_parent_open_intersections_normalized)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-induced-topology · candidate
9. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-induced-topology；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3],[0,1,2,3,4],[0,2],[0,2,3]],"subset":[1,2,4]}。請依 [subset, induced_topology, open_count, topology_certificate, certificate] 欄序回答。
查看答案與解釋
([1, 2, 4], [[], [1, 2], [1, 2, 4], [2]], 4, 是, all_parent_open_intersections_normalized)
Wave6第二層核對=([1, 2, 4], [[], [1, 2], [1, 2, 4], [2]], 4, 是, all_parent_open_intersections_normalized)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-induced-topology · candidate
10. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-induced-topology；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,2],[0,2,3],[0,2,3,4]],"subset":[1,2,4]}。請依 [subset, induced_topology, open_count, topology_certificate, certificate] 欄序回答。
查看答案與解釋
([1, 2, 4], [[], [1, 2, 4], [2], [2, 4]], 4, 是, all_parent_open_intersections_normalized)
Wave6第二層核對=([1, 2, 4], [[], [1, 2, 4], [2], [2, 4]], 4, 是, all_parent_open_intersections_normalized)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-induced-topology · candidate
11. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-induced-topology；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,1,2,4],[0,2],[0,2,4]],"subset":[1,2,3]}。請依 [subset, induced_topology, open_count, topology_certificate, certificate] 欄序回答。
查看答案與解釋
([1, 2, 3], [[], [1, 2], [1, 2, 3], [2]], 4, 是, all_parent_open_intersections_normalized)
Wave6第二層核對=([1, 2, 3], [[], [1, 2], [1, 2, 3], [2]], 4, 是, all_parent_open_intersections_normalized)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-induced-topology · candidate
12. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-induced-topology；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,2],[0,2,3,4],[0,2,4]],"subset":[1,2,3]}。請依 [subset, induced_topology, open_count, topology_certificate, certificate] 欄序回答。
查看答案與解釋
([1, 2, 3], [[], [1, 2, 3], [2], [2, 3]], 4, 是, all_parent_open_intersections_normalized)
Wave6第二層核對=([1, 2, 3], [[], [1, 2, 3], [2], [2, 3]], 4, 是, all_parent_open_intersections_normalized)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-induced-topology · candidate
13. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-induced-topology；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3],[0,1,2,3,4],[0,1,3],[0,3]],"subset":[2,3,4]}。請依 [subset, induced_topology, open_count, topology_certificate, certificate] 欄序回答。
查看答案與解釋
([2, 3, 4], [[], [2, 3], [2, 3, 4], [3]], 4, 是, all_parent_open_intersections_normalized)
Wave6第二層核對=([2, 3, 4], [[], [2, 3], [2, 3, 4], [3]], 4, 是, all_parent_open_intersections_normalized)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-induced-topology · candidate
14. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-induced-topology；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,1,3],[0,1,3,4],[0,3]],"subset":[2,3,4]}。請依 [subset, induced_topology, open_count, topology_certificate, certificate] 欄序回答。
查看答案與解釋
([2, 3, 4], [[], [2, 3, 4], [3], [3, 4]], 4, 是, all_parent_open_intersections_normalized)
Wave6第二層核對=([2, 3, 4], [[], [2, 3, 4], [3], [3, 4]], 4, 是, all_parent_open_intersections_normalized)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-induced-topology · candidate
15. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-induced-topology；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3],[0,1,2,3,4],[0,2,3],[0,3]],"subset":[1,3,4]}。請依 [subset, induced_topology, open_count, topology_certificate, certificate] 欄序回答。
查看答案與解釋
([1, 3, 4], [[], [1, 3], [1, 3, 4], [3]], 4, 是, all_parent_open_intersections_normalized)
Wave6第二層核對=([1, 3, 4], [[], [1, 3], [1, 3, 4], [3]], 4, 是, all_parent_open_intersections_normalized)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-induced-topology · candidate
16. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-induced-topology；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,2,3],[0,2,3,4],[0,3]],"subset":[1,3,4]}。請依 [subset, induced_topology, open_count, topology_certificate, certificate] 欄序回答。
查看答案與解釋
([1, 3, 4], [[], [1, 3, 4], [3], [3, 4]], 4, 是, all_parent_open_intersections_normalized)
Wave6第二層核對=([1, 3, 4], [[], [1, 3, 4], [3], [3, 4]], 4, 是, all_parent_open_intersections_normalized)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-induced-topology · candidate
17. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-induced-topology；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,1,3,4],[0,3],[0,3,4]],"subset":[1,2,3]}。請依 [subset, induced_topology, open_count, topology_certificate, certificate] 欄序回答。
查看答案與解釋
([1, 2, 3], [[], [1, 2, 3], [1, 3], [3]], 4, 是, all_parent_open_intersections_normalized)
Wave6第二層核對=([1, 2, 3], [[], [1, 2, 3], [1, 3], [3]], 4, 是, all_parent_open_intersections_normalized)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-induced-topology · candidate
18. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-induced-topology；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,2,3,4],[0,3],[0,3,4]],"subset":[1,2,3]}。請依 [subset, induced_topology, open_count, topology_certificate, certificate] 欄序回答。
查看答案與解釋
([1, 2, 3], [[], [1, 2, 3], [2, 3], [3]], 4, 是, all_parent_open_intersections_normalized)
Wave6第二層核對=([1, 2, 3], [[], [1, 2, 3], [2, 3], [3]], 4, 是, all_parent_open_intersections_normalized)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-induced-topology · candidate
19. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-induced-topology；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,1,2,4],[0,1,4],[0,4]],"subset":[2,3,4]}。請依 [subset, induced_topology, open_count, topology_certificate, certificate] 欄序回答。
查看答案與解釋
([2, 3, 4], [[], [2, 3, 4], [2, 4], [4]], 4, 是, all_parent_open_intersections_normalized)
Wave6第二層核對=([2, 3, 4], [[], [2, 3, 4], [2, 4], [4]], 4, 是, all_parent_open_intersections_normalized)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-induced-topology · candidate
20. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-induced-topology；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,1,3,4],[0,1,4],[0,4]],"subset":[2,3,4]}。請依 [subset, induced_topology, open_count, topology_certificate, certificate] 欄序回答。
查看答案與解釋
([2, 3, 4], [[], [2, 3, 4], [3, 4], [4]], 4, 是, all_parent_open_intersections_normalized)
Wave6第二層核對=([2, 3, 4], [[], [2, 3, 4], [3, 4], [4]], 4, 是, all_parent_open_intersections_normalized)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-induced-topology · candidate
21. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-induced-topology；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,1,2,4],[0,2,4],[0,4]],"subset":[1,3,4]}。請依 [subset, induced_topology, open_count, topology_certificate, certificate] 欄序回答。
查看答案與解釋
([1, 3, 4], [[], [1, 3, 4], [1, 4], [4]], 4, 是, all_parent_open_intersections_normalized)
Wave6第二層核對=([1, 3, 4], [[], [1, 3, 4], [1, 4], [4]], 4, 是, all_parent_open_intersections_normalized)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-induced-topology · candidate
22. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-induced-topology；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,2,3,4],[0,2,4],[0,4]],"subset":[1,3,4]}。請依 [subset, induced_topology, open_count, topology_certificate, certificate] 欄序回答。
查看答案與解釋
([1, 3, 4], [[], [1, 3, 4], [3, 4], [4]], 4, 是, all_parent_open_intersections_normalized)
Wave6第二層核對=([1, 3, 4], [[], [1, 3, 4], [3, 4], [4]], 4, 是, all_parent_open_intersections_normalized)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-induced-topology · candidate
23. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-induced-topology；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,1,3,4],[0,3,4],[0,4]],"subset":[1,2,4]}。請依 [subset, induced_topology, open_count, topology_certificate, certificate] 欄序回答。
查看答案與解釋
([1, 2, 4], [[], [1, 2, 4], [1, 4], [4]], 4, 是, all_parent_open_intersections_normalized)
Wave6第二層核對=([1, 2, 4], [[], [1, 2, 4], [1, 4], [4]], 4, 是, all_parent_open_intersections_normalized)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-induced-topology · candidate
24. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-induced-topology；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,2,3,4],[0,3,4],[0,4]],"subset":[1,2,4]}。請依 [subset, induced_topology, open_count, topology_certificate, certificate] 欄序回答。
查看答案與解釋
([1, 2, 4], [[], [1, 2, 4], [2, 4], [4]], 4, 是, all_parent_open_intersections_normalized)
Wave6第二層核對=([1, 2, 4], [[], [1, 2, 4], [2, 4], [4]], 4, 是, all_parent_open_intersections_normalized)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-induced-topology · candidate
25. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-induced-topology；資料={"n":5,"parent_topology":[[],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4],[1]],"subset":[0,3,4]}。請依 [subset, induced_topology, open_count, topology_certificate, certificate] 欄序回答。
查看答案與解釋
([0, 3, 4], [[], [0], [0, 3], [0, 3, 4]], 4, 是, all_parent_open_intersections_normalized)
Wave6第二層核對=([0, 3, 4], [[], [0], [0, 3], [0, 3, 4]], 4, 是, all_parent_open_intersections_normalized)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-induced-topology · candidate
26. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-open-audit；資料={"n":5,"parent_topology":[[],[0],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4]],"subset":[1,3,4],"candidate":[1]}。請依 [candidate, relative_open, parent_open_witnesses, boundary] 欄序回答。
查看答案與解釋
([1], 是, [[0, 1], [0, 1, 2]], relative_open_need_not_be_ambient_open)
Wave6第二層核對=([1], 是, [[0, 1], [0, 1, 2]], relative_open_need_not_be_ambient_open)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-open-audit · candidate
27. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-open-audit；資料={"n":5,"parent_topology":[[],[0],[0,1],[0,1,2],[0,1,2,3,4],[0,1,2,4]],"subset":[1,3,4],"candidate":[1]}。請依 [candidate, relative_open, parent_open_witnesses, boundary] 欄序回答。
查看答案與解釋
([1], 是, [[0, 1], [0, 1, 2]], relative_open_need_not_be_ambient_open)
Wave6第二層核對=([1], 是, [[0, 1], [0, 1, 2]], relative_open_need_not_be_ambient_open)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-open-audit · candidate
28. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-open-audit；資料={"n":5,"parent_topology":[[],[0],[0,1],[0,1,2,3],[0,1,2,3,4],[0,1,3]],"subset":[1,2,4],"candidate":[1]}。請依 [candidate, relative_open, parent_open_witnesses, boundary] 欄序回答。
查看答案與解釋
([1], 是, [[0, 1], [0, 1, 3]], relative_open_need_not_be_ambient_open)
Wave6第二層核對=([1], 是, [[0, 1], [0, 1, 3]], relative_open_need_not_be_ambient_open)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-open-audit · candidate
29. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-open-audit；資料={"n":5,"parent_topology":[[],[0],[0,1],[0,1,2,3,4],[0,1,3],[0,1,3,4]],"subset":[1,2,4],"candidate":[1]}。請依 [candidate, relative_open, parent_open_witnesses, boundary] 欄序回答。
查看答案與解釋
([1], 是, [[0, 1], [0, 1, 3]], relative_open_need_not_be_ambient_open)
Wave6第二層核對=([1], 是, [[0, 1], [0, 1, 3]], relative_open_need_not_be_ambient_open)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-open-audit · candidate
30. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-open-audit；資料={"n":5,"parent_topology":[[],[0],[0,1],[0,1,2,3,4],[0,1,2,4],[0,1,4]],"subset":[1,2,3],"candidate":[1]}。請依 [candidate, relative_open, parent_open_witnesses, boundary] 欄序回答。
查看答案與解釋
([1], 是, [[0, 1], [0, 1, 4]], relative_open_need_not_be_ambient_open)
Wave6第二層核對=([1], 是, [[0, 1], [0, 1, 4]], relative_open_need_not_be_ambient_open)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-open-audit · candidate
31. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-open-audit；資料={"n":5,"parent_topology":[[],[0],[0,1],[0,1,2,3,4],[0,1,3,4],[0,1,4]],"subset":[1,2,3],"candidate":[1]}。請依 [candidate, relative_open, parent_open_witnesses, boundary] 欄序回答。
查看答案與解釋
([1], 是, [[0, 1], [0, 1, 4]], relative_open_need_not_be_ambient_open)
Wave6第二層核對=([1], 是, [[0, 1], [0, 1, 4]], relative_open_need_not_be_ambient_open)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-open-audit · candidate
32. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-open-audit；資料={"n":5,"parent_topology":[[],[0],[0,1,2],[0,1,2,3],[0,1,2,3,4],[0,2]],"subset":[2,3,4],"candidate":[2]}。請依 [candidate, relative_open, parent_open_witnesses, boundary] 欄序回答。
查看答案與解釋
([2], 是, [[0, 1, 2], [0, 2]], relative_open_need_not_be_ambient_open)
Wave6第二層核對=([2], 是, [[0, 1, 2], [0, 2]], relative_open_need_not_be_ambient_open)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-open-audit · candidate
33. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-open-audit；資料={"n":5,"parent_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,1,2,4],[0,2]],"subset":[2,3,4],"candidate":[2]}。請依 [candidate, relative_open, parent_open_witnesses, boundary] 欄序回答。
查看答案與解釋
([2], 是, [[0, 1, 2], [0, 2]], relative_open_need_not_be_ambient_open)
Wave6第二層核對=([2], 是, [[0, 1, 2], [0, 2]], relative_open_need_not_be_ambient_open)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-open-audit · candidate
34. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-open-audit；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3],[0,1,2,3,4],[0,2],[0,2,3]],"subset":[1,2,4],"candidate":[2]}。請依 [candidate, relative_open, parent_open_witnesses, boundary] 欄序回答。
查看答案與解釋
([2], 是, [[0, 2], [0, 2, 3]], relative_open_need_not_be_ambient_open)
Wave6第二層核對=([2], 是, [[0, 2], [0, 2, 3]], relative_open_need_not_be_ambient_open)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-open-audit · candidate
35. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-open-audit；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,2],[0,2,3],[0,2,3,4]],"subset":[1,2,4],"candidate":[2]}。請依 [candidate, relative_open, parent_open_witnesses, boundary] 欄序回答。
查看答案與解釋
([2], 是, [[0, 2], [0, 2, 3]], relative_open_need_not_be_ambient_open)
Wave6第二層核對=([2], 是, [[0, 2], [0, 2, 3]], relative_open_need_not_be_ambient_open)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-open-audit · candidate
36. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-open-audit；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,1,2,4],[0,2],[0,2,4]],"subset":[1,2,3],"candidate":[2]}。請依 [candidate, relative_open, parent_open_witnesses, boundary] 欄序回答。
查看答案與解釋
([2], 是, [[0, 2], [0, 2, 4]], relative_open_need_not_be_ambient_open)
Wave6第二層核對=([2], 是, [[0, 2], [0, 2, 4]], relative_open_need_not_be_ambient_open)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-open-audit · candidate
37. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-open-audit；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,2],[0,2,3,4],[0,2,4]],"subset":[1,2,3],"candidate":[2]}。請依 [candidate, relative_open, parent_open_witnesses, boundary] 欄序回答。
查看答案與解釋
([2], 是, [[0, 2], [0, 2, 4]], relative_open_need_not_be_ambient_open)
Wave6第二層核對=([2], 是, [[0, 2], [0, 2, 4]], relative_open_need_not_be_ambient_open)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-open-audit · candidate
38. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-open-audit；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3],[0,1,2,3,4],[0,1,3],[0,3]],"subset":[2,3,4],"candidate":[3]}。請依 [candidate, relative_open, parent_open_witnesses, boundary] 欄序回答。
查看答案與解釋
([3], 是, [[0, 1, 3], [0, 3]], relative_open_need_not_be_ambient_open)
Wave6第二層核對=([3], 是, [[0, 1, 3], [0, 3]], relative_open_need_not_be_ambient_open)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-open-audit · candidate
39. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-open-audit；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,1,3],[0,1,3,4],[0,3]],"subset":[2,3,4],"candidate":[3]}。請依 [candidate, relative_open, parent_open_witnesses, boundary] 欄序回答。
查看答案與解釋
([3], 是, [[0, 1, 3], [0, 3]], relative_open_need_not_be_ambient_open)
Wave6第二層核對=([3], 是, [[0, 1, 3], [0, 3]], relative_open_need_not_be_ambient_open)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-open-audit · candidate
40. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-open-audit；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3],[0,1,2,3,4],[0,2,3],[0,3]],"subset":[1,3,4],"candidate":[3]}。請依 [candidate, relative_open, parent_open_witnesses, boundary] 欄序回答。
查看答案與解釋
([3], 是, [[0, 2, 3], [0, 3]], relative_open_need_not_be_ambient_open)
Wave6第二層核對=([3], 是, [[0, 2, 3], [0, 3]], relative_open_need_not_be_ambient_open)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-open-audit · candidate
41. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-open-audit；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,2,3],[0,2,3,4],[0,3]],"subset":[1,3,4],"candidate":[3]}。請依 [candidate, relative_open, parent_open_witnesses, boundary] 欄序回答。
查看答案與解釋
([3], 是, [[0, 2, 3], [0, 3]], relative_open_need_not_be_ambient_open)
Wave6第二層核對=([3], 是, [[0, 2, 3], [0, 3]], relative_open_need_not_be_ambient_open)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-open-audit · candidate
42. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-open-audit；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,1,3,4],[0,3],[0,3,4]],"subset":[1,2,3],"candidate":[3]}。請依 [candidate, relative_open, parent_open_witnesses, boundary] 欄序回答。
查看答案與解釋
([3], 是, [[0, 3], [0, 3, 4]], relative_open_need_not_be_ambient_open)
Wave6第二層核對=([3], 是, [[0, 3], [0, 3, 4]], relative_open_need_not_be_ambient_open)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-open-audit · candidate
43. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-open-audit；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,2,3,4],[0,3],[0,3,4]],"subset":[1,2,3],"candidate":[3]}。請依 [candidate, relative_open, parent_open_witnesses, boundary] 欄序回答。
查看答案與解釋
([3], 是, [[0, 3], [0, 3, 4]], relative_open_need_not_be_ambient_open)
Wave6第二層核對=([3], 是, [[0, 3], [0, 3, 4]], relative_open_need_not_be_ambient_open)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-open-audit · candidate
44. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-open-audit；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,1,2,4],[0,1,4],[0,4]],"subset":[2,3,4],"candidate":[4]}。請依 [candidate, relative_open, parent_open_witnesses, boundary] 欄序回答。
查看答案與解釋
([4], 是, [[0, 1, 4], [0, 4]], relative_open_need_not_be_ambient_open)
Wave6第二層核對=([4], 是, [[0, 1, 4], [0, 4]], relative_open_need_not_be_ambient_open)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-open-audit · candidate
45. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-open-audit；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,1,3,4],[0,1,4],[0,4]],"subset":[2,3,4],"candidate":[4]}。請依 [candidate, relative_open, parent_open_witnesses, boundary] 欄序回答。
查看答案與解釋
([4], 是, [[0, 1, 4], [0, 4]], relative_open_need_not_be_ambient_open)
Wave6第二層核對=([4], 是, [[0, 1, 4], [0, 4]], relative_open_need_not_be_ambient_open)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-open-audit · candidate
46. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-open-audit；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,1,2,4],[0,2,4],[0,4]],"subset":[1,3,4],"candidate":[4]}。請依 [candidate, relative_open, parent_open_witnesses, boundary] 欄序回答。
查看答案與解釋
([4], 是, [[0, 2, 4], [0, 4]], relative_open_need_not_be_ambient_open)
Wave6第二層核對=([4], 是, [[0, 2, 4], [0, 4]], relative_open_need_not_be_ambient_open)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-open-audit · candidate
47. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-open-audit；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,2,3,4],[0,2,4],[0,4]],"subset":[1,3,4],"candidate":[4]}。請依 [candidate, relative_open, parent_open_witnesses, boundary] 欄序回答。
查看答案與解釋
([4], 是, [[0, 2, 4], [0, 4]], relative_open_need_not_be_ambient_open)
Wave6第二層核對=([4], 是, [[0, 2, 4], [0, 4]], relative_open_need_not_be_ambient_open)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-open-audit · candidate
48. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-open-audit；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,1,3,4],[0,3,4],[0,4]],"subset":[1,2,4],"candidate":[4]}。請依 [candidate, relative_open, parent_open_witnesses, boundary] 欄序回答。
查看答案與解釋
([4], 是, [[0, 3, 4], [0, 4]], relative_open_need_not_be_ambient_open)
Wave6第二層核對=([4], 是, [[0, 3, 4], [0, 4]], relative_open_need_not_be_ambient_open)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-open-audit · candidate
49. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-open-audit；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,2,3,4],[0,3,4],[0,4]],"subset":[1,2,4],"candidate":[4]}。請依 [candidate, relative_open, parent_open_witnesses, boundary] 欄序回答。
查看答案與解釋
([4], 是, [[0, 3, 4], [0, 4]], relative_open_need_not_be_ambient_open)
Wave6第二層核對=([4], 是, [[0, 3, 4], [0, 4]], relative_open_need_not_be_ambient_open)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-open-audit · candidate
50. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-open-audit；資料={"n":5,"parent_topology":[[],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4],[1]],"subset":[0,3,4],"candidate":[0]}。請依 [candidate, relative_open, parent_open_witnesses, boundary] 欄序回答。
查看答案與解釋
([0], 是, [[0, 1], [0, 1, 2]], relative_open_need_not_be_ambient_open)
Wave6第二層核對=([0], 是, [[0, 1], [0, 1, 2]], relative_open_need_not_be_ambient_open)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-open-audit · candidate
51. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-closed-audit；資料={"n":5,"parent_topology":[[],[0],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4]],"subset":[1,3,4],"candidate":[3,4]}。請依 [candidate, relative_complement, relative_closed, boundary] 欄序回答。
relative_complement在Y內取，不是在母空間X內取。
查看答案與解釋
([3, 4], [1], 是, complement_taken_inside_Y)
Wave6第二層核對=([3, 4], [1], 是, complement_taken_inside_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-closed-audit · candidate
52. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-closed-audit；資料={"n":5,"parent_topology":[[],[0],[0,1],[0,1,2],[0,1,2,3,4],[0,1,2,4]],"subset":[1,3,4],"candidate":[3,4]}。請依 [candidate, relative_complement, relative_closed, boundary] 欄序回答。
relative_complement在Y內取，不是在母空間X內取。
查看答案與解釋
([3, 4], [1], 是, complement_taken_inside_Y)
Wave6第二層核對=([3, 4], [1], 是, complement_taken_inside_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-closed-audit · candidate
53. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-closed-audit；資料={"n":5,"parent_topology":[[],[0],[0,1],[0,1,2,3],[0,1,2,3,4],[0,1,3]],"subset":[1,2,4],"candidate":[2,4]}。請依 [candidate, relative_complement, relative_closed, boundary] 欄序回答。
relative_complement在Y內取，不是在母空間X內取。
查看答案與解釋
([2, 4], [1], 是, complement_taken_inside_Y)
Wave6第二層核對=([2, 4], [1], 是, complement_taken_inside_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-closed-audit · candidate
54. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-closed-audit；資料={"n":5,"parent_topology":[[],[0],[0,1],[0,1,2,3,4],[0,1,3],[0,1,3,4]],"subset":[1,2,4],"candidate":[2,4]}。請依 [candidate, relative_complement, relative_closed, boundary] 欄序回答。
relative_complement在Y內取，不是在母空間X內取。
查看答案與解釋
([2, 4], [1], 是, complement_taken_inside_Y)
Wave6第二層核對=([2, 4], [1], 是, complement_taken_inside_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-closed-audit · candidate
55. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-closed-audit；資料={"n":5,"parent_topology":[[],[0],[0,1],[0,1,2,3,4],[0,1,2,4],[0,1,4]],"subset":[1,2,3],"candidate":[2,3]}。請依 [candidate, relative_complement, relative_closed, boundary] 欄序回答。
relative_complement在Y內取，不是在母空間X內取。
查看答案與解釋
([2, 3], [1], 是, complement_taken_inside_Y)
Wave6第二層核對=([2, 3], [1], 是, complement_taken_inside_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-closed-audit · candidate
56. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-closed-audit；資料={"n":5,"parent_topology":[[],[0],[0,1],[0,1,2,3,4],[0,1,3,4],[0,1,4]],"subset":[1,2,3],"candidate":[2,3]}。請依 [candidate, relative_complement, relative_closed, boundary] 欄序回答。
relative_complement在Y內取，不是在母空間X內取。
查看答案與解釋
([2, 3], [1], 是, complement_taken_inside_Y)
Wave6第二層核對=([2, 3], [1], 是, complement_taken_inside_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-closed-audit · candidate
57. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-closed-audit；資料={"n":5,"parent_topology":[[],[0],[0,1,2],[0,1,2,3],[0,1,2,3,4],[0,2]],"subset":[2,3,4],"candidate":[3,4]}。請依 [candidate, relative_complement, relative_closed, boundary] 欄序回答。
relative_complement在Y內取，不是在母空間X內取。
查看答案與解釋
([3, 4], [2], 是, complement_taken_inside_Y)
Wave6第二層核對=([3, 4], [2], 是, complement_taken_inside_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-closed-audit · candidate
58. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-closed-audit；資料={"n":5,"parent_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,1,2,4],[0,2]],"subset":[2,3,4],"candidate":[3,4]}。請依 [candidate, relative_complement, relative_closed, boundary] 欄序回答。
relative_complement在Y內取，不是在母空間X內取。
查看答案與解釋
([3, 4], [2], 是, complement_taken_inside_Y)
Wave6第二層核對=([3, 4], [2], 是, complement_taken_inside_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-closed-audit · candidate
59. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-closed-audit；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3],[0,1,2,3,4],[0,2],[0,2,3]],"subset":[1,2,4],"candidate":[1,4]}。請依 [candidate, relative_complement, relative_closed, boundary] 欄序回答。
relative_complement在Y內取，不是在母空間X內取。
查看答案與解釋
([1, 4], [2], 是, complement_taken_inside_Y)
Wave6第二層核對=([1, 4], [2], 是, complement_taken_inside_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-closed-audit · candidate
60. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-closed-audit；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,2],[0,2,3],[0,2,3,4]],"subset":[1,2,4],"candidate":[1,4]}。請依 [candidate, relative_complement, relative_closed, boundary] 欄序回答。
relative_complement在Y內取，不是在母空間X內取。
查看答案與解釋
([1, 4], [2], 是, complement_taken_inside_Y)
Wave6第二層核對=([1, 4], [2], 是, complement_taken_inside_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-closed-audit · candidate
61. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-closed-audit；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,1,2,4],[0,2],[0,2,4]],"subset":[1,2,3],"candidate":[1,3]}。請依 [candidate, relative_complement, relative_closed, boundary] 欄序回答。
relative_complement在Y內取，不是在母空間X內取。
查看答案與解釋
([1, 3], [2], 是, complement_taken_inside_Y)
Wave6第二層核對=([1, 3], [2], 是, complement_taken_inside_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-closed-audit · candidate
62. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-closed-audit；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,2],[0,2,3,4],[0,2,4]],"subset":[1,2,3],"candidate":[1,3]}。請依 [candidate, relative_complement, relative_closed, boundary] 欄序回答。
relative_complement在Y內取，不是在母空間X內取。
查看答案與解釋
([1, 3], [2], 是, complement_taken_inside_Y)
Wave6第二層核對=([1, 3], [2], 是, complement_taken_inside_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-closed-audit · candidate
63. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-closed-audit；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3],[0,1,2,3,4],[0,1,3],[0,3]],"subset":[2,3,4],"candidate":[2,4]}。請依 [candidate, relative_complement, relative_closed, boundary] 欄序回答。
relative_complement在Y內取，不是在母空間X內取。
查看答案與解釋
([2, 4], [3], 是, complement_taken_inside_Y)
Wave6第二層核對=([2, 4], [3], 是, complement_taken_inside_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-closed-audit · candidate
64. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-closed-audit；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,1,3],[0,1,3,4],[0,3]],"subset":[2,3,4],"candidate":[2,4]}。請依 [candidate, relative_complement, relative_closed, boundary] 欄序回答。
relative_complement在Y內取，不是在母空間X內取。
查看答案與解釋
([2, 4], [3], 是, complement_taken_inside_Y)
Wave6第二層核對=([2, 4], [3], 是, complement_taken_inside_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-closed-audit · candidate
65. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-closed-audit；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3],[0,1,2,3,4],[0,2,3],[0,3]],"subset":[1,3,4],"candidate":[1,4]}。請依 [candidate, relative_complement, relative_closed, boundary] 欄序回答。
relative_complement在Y內取，不是在母空間X內取。
查看答案與解釋
([1, 4], [3], 是, complement_taken_inside_Y)
Wave6第二層核對=([1, 4], [3], 是, complement_taken_inside_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-closed-audit · candidate
66. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-closed-audit；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,2,3],[0,2,3,4],[0,3]],"subset":[1,3,4],"candidate":[1,4]}。請依 [candidate, relative_complement, relative_closed, boundary] 欄序回答。
relative_complement在Y內取，不是在母空間X內取。
查看答案與解釋
([1, 4], [3], 是, complement_taken_inside_Y)
Wave6第二層核對=([1, 4], [3], 是, complement_taken_inside_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-closed-audit · candidate
67. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-closed-audit；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,1,3,4],[0,3],[0,3,4]],"subset":[1,2,3],"candidate":[1,2]}。請依 [candidate, relative_complement, relative_closed, boundary] 欄序回答。
relative_complement在Y內取，不是在母空間X內取。
查看答案與解釋
([1, 2], [3], 是, complement_taken_inside_Y)
Wave6第二層核對=([1, 2], [3], 是, complement_taken_inside_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-closed-audit · candidate
68. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-closed-audit；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,2,3,4],[0,3],[0,3,4]],"subset":[1,2,3],"candidate":[1,2]}。請依 [candidate, relative_complement, relative_closed, boundary] 欄序回答。
relative_complement在Y內取，不是在母空間X內取。
查看答案與解釋
([1, 2], [3], 是, complement_taken_inside_Y)
Wave6第二層核對=([1, 2], [3], 是, complement_taken_inside_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-closed-audit · candidate
69. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-closed-audit；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,1,2,4],[0,1,4],[0,4]],"subset":[2,3,4],"candidate":[2,3]}。請依 [candidate, relative_complement, relative_closed, boundary] 欄序回答。
relative_complement在Y內取，不是在母空間X內取。
查看答案與解釋
([2, 3], [4], 是, complement_taken_inside_Y)
Wave6第二層核對=([2, 3], [4], 是, complement_taken_inside_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-closed-audit · candidate
70. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-closed-audit；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,1,3,4],[0,1,4],[0,4]],"subset":[2,3,4],"candidate":[2,3]}。請依 [candidate, relative_complement, relative_closed, boundary] 欄序回答。
relative_complement在Y內取，不是在母空間X內取。
查看答案與解釋
([2, 3], [4], 是, complement_taken_inside_Y)
Wave6第二層核對=([2, 3], [4], 是, complement_taken_inside_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-closed-audit · candidate
71. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-closed-audit；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,1,2,4],[0,2,4],[0,4]],"subset":[1,3,4],"candidate":[1,3]}。請依 [candidate, relative_complement, relative_closed, boundary] 欄序回答。
relative_complement在Y內取，不是在母空間X內取。
查看答案與解釋
([1, 3], [4], 是, complement_taken_inside_Y)
Wave6第二層核對=([1, 3], [4], 是, complement_taken_inside_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-closed-audit · candidate
72. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-closed-audit；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,2,3,4],[0,2,4],[0,4]],"subset":[1,3,4],"candidate":[1,3]}。請依 [candidate, relative_complement, relative_closed, boundary] 欄序回答。
relative_complement在Y內取，不是在母空間X內取。
查看答案與解釋
([1, 3], [4], 是, complement_taken_inside_Y)
Wave6第二層核對=([1, 3], [4], 是, complement_taken_inside_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-closed-audit · candidate
73. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-closed-audit；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,1,3,4],[0,3,4],[0,4]],"subset":[1,2,4],"candidate":[1,2]}。請依 [candidate, relative_complement, relative_closed, boundary] 欄序回答。
relative_complement在Y內取，不是在母空間X內取。
查看答案與解釋
([1, 2], [4], 是, complement_taken_inside_Y)
Wave6第二層核對=([1, 2], [4], 是, complement_taken_inside_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-closed-audit · candidate
74. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-closed-audit；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,2,3,4],[0,3,4],[0,4]],"subset":[1,2,4],"candidate":[1,2]}。請依 [candidate, relative_complement, relative_closed, boundary] 欄序回答。
relative_complement在Y內取，不是在母空間X內取。
查看答案與解釋
([1, 2], [4], 是, complement_taken_inside_Y)
Wave6第二層核對=([1, 2], [4], 是, complement_taken_inside_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-closed-audit · candidate
75. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-relative-closed-audit；資料={"n":5,"parent_topology":[[],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4],[1]],"subset":[0,3,4],"candidate":[3,4]}。請依 [candidate, relative_complement, relative_closed, boundary] 欄序回答。
relative_complement在Y內取，不是在母空間X內取。
查看答案與解釋
([3, 4], [0], 是, complement_taken_inside_Y)
Wave6第二層核對=([3, 4], [0], 是, complement_taken_inside_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-relative-closed-audit · candidate
76. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-ambient-boundary；資料={"n":5,"parent_topology":[[],[0],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4]],"subset":[1,3,4],"candidate":[1,3,4]}。請依 [candidate, relative_open, ambient_open, intersection_certificate, boundary] 欄序回答。
查看答案與解釋
([1, 3, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)
Wave6第二層核對=([1, 3, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-ambient-boundary · candidate
77. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-ambient-boundary；資料={"n":5,"parent_topology":[[],[0],[0,1],[0,1,2],[0,1,2,3,4],[0,1,2,4]],"subset":[1,3,4],"candidate":[1,3,4]}。請依 [candidate, relative_open, ambient_open, intersection_certificate, boundary] 欄序回答。
查看答案與解釋
([1, 3, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)
Wave6第二層核對=([1, 3, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-ambient-boundary · candidate
78. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-ambient-boundary；資料={"n":5,"parent_topology":[[],[0],[0,1],[0,1,2,3],[0,1,2,3,4],[0,1,3]],"subset":[1,2,4],"candidate":[1,2,4]}。請依 [candidate, relative_open, ambient_open, intersection_certificate, boundary] 欄序回答。
查看答案與解釋
([1, 2, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)
Wave6第二層核對=([1, 2, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-ambient-boundary · candidate
79. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-ambient-boundary；資料={"n":5,"parent_topology":[[],[0],[0,1],[0,1,2,3,4],[0,1,3],[0,1,3,4]],"subset":[1,2,4],"candidate":[1,2,4]}。請依 [candidate, relative_open, ambient_open, intersection_certificate, boundary] 欄序回答。
查看答案與解釋
([1, 2, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)
Wave6第二層核對=([1, 2, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-ambient-boundary · candidate
80. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-ambient-boundary；資料={"n":5,"parent_topology":[[],[0],[0,1],[0,1,2,3,4],[0,1,2,4],[0,1,4]],"subset":[1,2,3],"candidate":[1,2,3]}。請依 [candidate, relative_open, ambient_open, intersection_certificate, boundary] 欄序回答。
查看答案與解釋
([1, 2, 3], 是, 否, 是, O_intersect_Y_not_O_subset_Y)
Wave6第二層核對=([1, 2, 3], 是, 否, 是, O_intersect_Y_not_O_subset_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-ambient-boundary · candidate
81. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-ambient-boundary；資料={"n":5,"parent_topology":[[],[0],[0,1],[0,1,2,3,4],[0,1,3,4],[0,1,4]],"subset":[1,2,3],"candidate":[1,2,3]}。請依 [candidate, relative_open, ambient_open, intersection_certificate, boundary] 欄序回答。
查看答案與解釋
([1, 2, 3], 是, 否, 是, O_intersect_Y_not_O_subset_Y)
Wave6第二層核對=([1, 2, 3], 是, 否, 是, O_intersect_Y_not_O_subset_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-ambient-boundary · candidate
82. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-ambient-boundary；資料={"n":5,"parent_topology":[[],[0],[0,1,2],[0,1,2,3],[0,1,2,3,4],[0,2]],"subset":[2,3,4],"candidate":[2,3,4]}。請依 [candidate, relative_open, ambient_open, intersection_certificate, boundary] 欄序回答。
查看答案與解釋
([2, 3, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)
Wave6第二層核對=([2, 3, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-ambient-boundary · candidate
83. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-ambient-boundary；資料={"n":5,"parent_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,1,2,4],[0,2]],"subset":[2,3,4],"candidate":[2,3,4]}。請依 [candidate, relative_open, ambient_open, intersection_certificate, boundary] 欄序回答。
查看答案與解釋
([2, 3, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)
Wave6第二層核對=([2, 3, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-ambient-boundary · candidate
84. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-ambient-boundary；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3],[0,1,2,3,4],[0,2],[0,2,3]],"subset":[1,2,4],"candidate":[1,2,4]}。請依 [candidate, relative_open, ambient_open, intersection_certificate, boundary] 欄序回答。
查看答案與解釋
([1, 2, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)
Wave6第二層核對=([1, 2, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-ambient-boundary · candidate
85. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-ambient-boundary；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,2],[0,2,3],[0,2,3,4]],"subset":[1,2,4],"candidate":[1,2,4]}。請依 [candidate, relative_open, ambient_open, intersection_certificate, boundary] 欄序回答。
查看答案與解釋
([1, 2, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)
Wave6第二層核對=([1, 2, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-ambient-boundary · candidate
86. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-ambient-boundary；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,1,2,4],[0,2],[0,2,4]],"subset":[1,2,3],"candidate":[1,2,3]}。請依 [candidate, relative_open, ambient_open, intersection_certificate, boundary] 欄序回答。
查看答案與解釋
([1, 2, 3], 是, 否, 是, O_intersect_Y_not_O_subset_Y)
Wave6第二層核對=([1, 2, 3], 是, 否, 是, O_intersect_Y_not_O_subset_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-ambient-boundary · candidate
87. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-ambient-boundary；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,2],[0,2,3,4],[0,2,4]],"subset":[1,2,3],"candidate":[1,2,3]}。請依 [candidate, relative_open, ambient_open, intersection_certificate, boundary] 欄序回答。
查看答案與解釋
([1, 2, 3], 是, 否, 是, O_intersect_Y_not_O_subset_Y)
Wave6第二層核對=([1, 2, 3], 是, 否, 是, O_intersect_Y_not_O_subset_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-ambient-boundary · candidate
88. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-ambient-boundary；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3],[0,1,2,3,4],[0,1,3],[0,3]],"subset":[2,3,4],"candidate":[2,3,4]}。請依 [candidate, relative_open, ambient_open, intersection_certificate, boundary] 欄序回答。
查看答案與解釋
([2, 3, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)
Wave6第二層核對=([2, 3, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-ambient-boundary · candidate
89. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-ambient-boundary；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,1,3],[0,1,3,4],[0,3]],"subset":[2,3,4],"candidate":[2,3,4]}。請依 [candidate, relative_open, ambient_open, intersection_certificate, boundary] 欄序回答。
查看答案與解釋
([2, 3, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)
Wave6第二層核對=([2, 3, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-ambient-boundary · candidate
90. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-ambient-boundary；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3],[0,1,2,3,4],[0,2,3],[0,3]],"subset":[1,3,4],"candidate":[1,3,4]}。請依 [candidate, relative_open, ambient_open, intersection_certificate, boundary] 欄序回答。
查看答案與解釋
([1, 3, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)
Wave6第二層核對=([1, 3, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-ambient-boundary · candidate
91. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-ambient-boundary；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,2,3],[0,2,3,4],[0,3]],"subset":[1,3,4],"candidate":[1,3,4]}。請依 [candidate, relative_open, ambient_open, intersection_certificate, boundary] 欄序回答。
查看答案與解釋
([1, 3, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)
Wave6第二層核對=([1, 3, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-ambient-boundary · candidate
92. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-ambient-boundary；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,1,3,4],[0,3],[0,3,4]],"subset":[1,2,3],"candidate":[1,2,3]}。請依 [candidate, relative_open, ambient_open, intersection_certificate, boundary] 欄序回答。
查看答案與解釋
([1, 2, 3], 是, 否, 是, O_intersect_Y_not_O_subset_Y)
Wave6第二層核對=([1, 2, 3], 是, 否, 是, O_intersect_Y_not_O_subset_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-ambient-boundary · candidate
93. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-ambient-boundary；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,2,3,4],[0,3],[0,3,4]],"subset":[1,2,3],"candidate":[1,2,3]}。請依 [candidate, relative_open, ambient_open, intersection_certificate, boundary] 欄序回答。
查看答案與解釋
([1, 2, 3], 是, 否, 是, O_intersect_Y_not_O_subset_Y)
Wave6第二層核對=([1, 2, 3], 是, 否, 是, O_intersect_Y_not_O_subset_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-ambient-boundary · candidate
94. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-ambient-boundary；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,1,2,4],[0,1,4],[0,4]],"subset":[2,3,4],"candidate":[2,3,4]}。請依 [candidate, relative_open, ambient_open, intersection_certificate, boundary] 欄序回答。
查看答案與解釋
([2, 3, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)
Wave6第二層核對=([2, 3, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-ambient-boundary · candidate
95. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-ambient-boundary；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,1,3,4],[0,1,4],[0,4]],"subset":[2,3,4],"candidate":[2,3,4]}。請依 [candidate, relative_open, ambient_open, intersection_certificate, boundary] 欄序回答。
查看答案與解釋
([2, 3, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)
Wave6第二層核對=([2, 3, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-ambient-boundary · candidate
96. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-ambient-boundary；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,1,2,4],[0,2,4],[0,4]],"subset":[1,3,4],"candidate":[1,3,4]}。請依 [candidate, relative_open, ambient_open, intersection_certificate, boundary] 欄序回答。
查看答案與解釋
([1, 3, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)
Wave6第二層核對=([1, 3, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-ambient-boundary · candidate
97. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-ambient-boundary；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,2,3,4],[0,2,4],[0,4]],"subset":[1,3,4],"candidate":[1,3,4]}。請依 [candidate, relative_open, ambient_open, intersection_certificate, boundary] 欄序回答。
查看答案與解釋
([1, 3, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)
Wave6第二層核對=([1, 3, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-ambient-boundary · candidate
98. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-ambient-boundary；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,1,3,4],[0,3,4],[0,4]],"subset":[1,2,4],"candidate":[1,2,4]}。請依 [candidate, relative_open, ambient_open, intersection_certificate, boundary] 欄序回答。
查看答案與解釋
([1, 2, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)
Wave6第二層核對=([1, 2, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-ambient-boundary · candidate
99. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-ambient-boundary；資料={"n":5,"parent_topology":[[],[0],[0,1,2,3,4],[0,2,3,4],[0,3,4],[0,4]],"subset":[1,2,4],"candidate":[1,2,4]}。請依 [candidate, relative_open, ambient_open, intersection_certificate, boundary] 欄序回答。
查看答案與解釋
([1, 2, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)
Wave6第二層核對=([1, 2, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-ambient-boundary · candidate
100. 子空間拓撲
完整有限母拓撲、明示Y subset X與相對全集Y。操作=subtop-ambient-boundary；資料={"n":5,"parent_topology":[[],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4],[1]],"subset":[0,3,4],"candidate":[0,3,4]}。請依 [candidate, relative_open, ambient_open, intersection_certificate, boundary] 欄序回答。
查看答案與解釋
([0, 3, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)
Wave6第二層核對=([0, 3, 4], 是, 否, 是, O_intersect_Y_not_O_subset_Y)；依完整明示資料獨立重算；tau_Y恰為全部U intersect Y；relative open不必ambient open且不要求U subset Y；relative closed以Y內補集或F intersect Y判定；重複與空交集須正規化。
本題逐步詳解（AI 二次覆核）
子空間拓撲 · qf-mod39-subtop-ambient-boundary · candidate
原始題目 JSONL · 驗收報告