緊緻集的連續像基礎 · 脈衝 R03
本批已通過 Schema、去重、來源快照與獨立答案重算；仍未標記為人工審定。
本題庫已有對應的中英逐步詳解。原題的 candidate 與英文 ai_candidate 狀態保留；AI 覆核、有限計算與 Lean 形式證明分開標示。
batch-20261014-advance-20261110-r03-continuous-image-of-compact-foundations · 2026-10-14 · 100 題
欄序為來源綁定的呈現補充；原始 JSONL 與數學答案不變。
欄序與來源綁定資料
1. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-image-set；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[0,0,0],"subset":[0,1,2]}。請依 [subset, map, image, finite_compactness_certificate, certificate] 欄序回答。
此步只算有限K的精確像及有限性compact證書；continuity由另一審核步驟判斷，不以有限像compact反推一般domain compact。
查看答案與解釋
([0, 1, 2], [0, 0, 0], [0], 是, finite_compact_source_subset_exact_image)
Wave6第四層核對=([0, 1, 2], [0, 0, 0], [0], 是, finite_compact_source_subset_exact_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-image-set · candidate
2. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-image-set；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[1,0,0],"subset":[0,1,2]}。請依 [subset, map, image, finite_compactness_certificate, certificate] 欄序回答。
此步只算有限K的精確像及有限性compact證書；continuity由另一審核步驟判斷，不以有限像compact反推一般domain compact。
查看答案與解釋
([0, 1, 2], [1, 0, 0], [0, 1], 是, finite_compact_source_subset_exact_image)
Wave6第四層核對=([0, 1, 2], [1, 0, 0], [0, 1], 是, finite_compact_source_subset_exact_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-image-set · candidate
3. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-image-set；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[2,0,0],"subset":[0,1,2]}。請依 [subset, map, image, finite_compactness_certificate, certificate] 欄序回答。
此步只算有限K的精確像及有限性compact證書；continuity由另一審核步驟判斷，不以有限像compact反推一般domain compact。
查看答案與解釋
([0, 1, 2], [2, 0, 0], [0, 2], 是, finite_compact_source_subset_exact_image)
Wave6第四層核對=([0, 1, 2], [2, 0, 0], [0, 2], 是, finite_compact_source_subset_exact_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-image-set · candidate
4. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-image-set；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[0,1,0],"subset":[0,1,2]}。請依 [subset, map, image, finite_compactness_certificate, certificate] 欄序回答。
此步只算有限K的精確像及有限性compact證書；continuity由另一審核步驟判斷，不以有限像compact反推一般domain compact。
查看答案與解釋
([0, 1, 2], [0, 1, 0], [0, 1], 是, finite_compact_source_subset_exact_image)
Wave6第四層核對=([0, 1, 2], [0, 1, 0], [0, 1], 是, finite_compact_source_subset_exact_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-image-set · candidate
5. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-image-set；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[1,1,0],"subset":[0,1,2]}。請依 [subset, map, image, finite_compactness_certificate, certificate] 欄序回答。
此步只算有限K的精確像及有限性compact證書；continuity由另一審核步驟判斷，不以有限像compact反推一般domain compact。
查看答案與解釋
([0, 1, 2], [1, 1, 0], [0, 1], 是, finite_compact_source_subset_exact_image)
Wave6第四層核對=([0, 1, 2], [1, 1, 0], [0, 1], 是, finite_compact_source_subset_exact_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-image-set · candidate
6. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-image-set；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[2,1,0],"subset":[0,1,2]}。請依 [subset, map, image, finite_compactness_certificate, certificate] 欄序回答。
此步只算有限K的精確像及有限性compact證書；continuity由另一審核步驟判斷，不以有限像compact反推一般domain compact。
查看答案與解釋
([0, 1, 2], [2, 1, 0], [0, 1, 2], 是, finite_compact_source_subset_exact_image)
Wave6第四層核對=([0, 1, 2], [2, 1, 0], [0, 1, 2], 是, finite_compact_source_subset_exact_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-image-set · candidate
7. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-image-set；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[0,2,0],"subset":[0,1,2]}。請依 [subset, map, image, finite_compactness_certificate, certificate] 欄序回答。
此步只算有限K的精確像及有限性compact證書；continuity由另一審核步驟判斷，不以有限像compact反推一般domain compact。
查看答案與解釋
([0, 1, 2], [0, 2, 0], [0, 2], 是, finite_compact_source_subset_exact_image)
Wave6第四層核對=([0, 1, 2], [0, 2, 0], [0, 2], 是, finite_compact_source_subset_exact_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-image-set · candidate
8. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-image-set；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[1,2,0],"subset":[0,1,2]}。請依 [subset, map, image, finite_compactness_certificate, certificate] 欄序回答。
此步只算有限K的精確像及有限性compact證書；continuity由另一審核步驟判斷，不以有限像compact反推一般domain compact。
查看答案與解釋
([0, 1, 2], [1, 2, 0], [0, 1, 2], 是, finite_compact_source_subset_exact_image)
Wave6第四層核對=([0, 1, 2], [1, 2, 0], [0, 1, 2], 是, finite_compact_source_subset_exact_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-image-set · candidate
9. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-image-set；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[2,2,0],"subset":[0,1,2]}。請依 [subset, map, image, finite_compactness_certificate, certificate] 欄序回答。
此步只算有限K的精確像及有限性compact證書；continuity由另一審核步驟判斷，不以有限像compact反推一般domain compact。
查看答案與解釋
([0, 1, 2], [2, 2, 0], [0, 2], 是, finite_compact_source_subset_exact_image)
Wave6第四層核對=([0, 1, 2], [2, 2, 0], [0, 2], 是, finite_compact_source_subset_exact_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-image-set · candidate
10. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-image-set；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[0,0,1],"subset":[0,1,2]}。請依 [subset, map, image, finite_compactness_certificate, certificate] 欄序回答。
此步只算有限K的精確像及有限性compact證書；continuity由另一審核步驟判斷，不以有限像compact反推一般domain compact。
查看答案與解釋
([0, 1, 2], [0, 0, 1], [0, 1], 是, finite_compact_source_subset_exact_image)
Wave6第四層核對=([0, 1, 2], [0, 0, 1], [0, 1], 是, finite_compact_source_subset_exact_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-image-set · candidate
11. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-image-set；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[1,0,1],"subset":[0,1,2]}。請依 [subset, map, image, finite_compactness_certificate, certificate] 欄序回答。
此步只算有限K的精確像及有限性compact證書；continuity由另一審核步驟判斷，不以有限像compact反推一般domain compact。
查看答案與解釋
([0, 1, 2], [1, 0, 1], [0, 1], 是, finite_compact_source_subset_exact_image)
Wave6第四層核對=([0, 1, 2], [1, 0, 1], [0, 1], 是, finite_compact_source_subset_exact_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-image-set · candidate
12. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-image-set；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[2,0,1],"subset":[0,1,2]}。請依 [subset, map, image, finite_compactness_certificate, certificate] 欄序回答。
此步只算有限K的精確像及有限性compact證書；continuity由另一審核步驟判斷，不以有限像compact反推一般domain compact。
查看答案與解釋
([0, 1, 2], [2, 0, 1], [0, 1, 2], 是, finite_compact_source_subset_exact_image)
Wave6第四層核對=([0, 1, 2], [2, 0, 1], [0, 1, 2], 是, finite_compact_source_subset_exact_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-image-set · candidate
13. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-image-set；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[0,1,1],"subset":[0,1,2]}。請依 [subset, map, image, finite_compactness_certificate, certificate] 欄序回答。
此步只算有限K的精確像及有限性compact證書；continuity由另一審核步驟判斷，不以有限像compact反推一般domain compact。
查看答案與解釋
([0, 1, 2], [0, 1, 1], [0, 1], 是, finite_compact_source_subset_exact_image)
Wave6第四層核對=([0, 1, 2], [0, 1, 1], [0, 1], 是, finite_compact_source_subset_exact_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-image-set · candidate
14. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-image-set；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[1,1,1],"subset":[0,1,2]}。請依 [subset, map, image, finite_compactness_certificate, certificate] 欄序回答。
此步只算有限K的精確像及有限性compact證書；continuity由另一審核步驟判斷，不以有限像compact反推一般domain compact。
查看答案與解釋
([0, 1, 2], [1, 1, 1], [1], 是, finite_compact_source_subset_exact_image)
Wave6第四層核對=([0, 1, 2], [1, 1, 1], [1], 是, finite_compact_source_subset_exact_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-image-set · candidate
15. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-image-set；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[2,1,1],"subset":[0,1,2]}。請依 [subset, map, image, finite_compactness_certificate, certificate] 欄序回答。
此步只算有限K的精確像及有限性compact證書；continuity由另一審核步驟判斷，不以有限像compact反推一般domain compact。
查看答案與解釋
([0, 1, 2], [2, 1, 1], [1, 2], 是, finite_compact_source_subset_exact_image)
Wave6第四層核對=([0, 1, 2], [2, 1, 1], [1, 2], 是, finite_compact_source_subset_exact_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-image-set · candidate
16. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-image-set；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[0,2,1],"subset":[0,1,2]}。請依 [subset, map, image, finite_compactness_certificate, certificate] 欄序回答。
此步只算有限K的精確像及有限性compact證書；continuity由另一審核步驟判斷，不以有限像compact反推一般domain compact。
查看答案與解釋
([0, 1, 2], [0, 2, 1], [0, 1, 2], 是, finite_compact_source_subset_exact_image)
Wave6第四層核對=([0, 1, 2], [0, 2, 1], [0, 1, 2], 是, finite_compact_source_subset_exact_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-image-set · candidate
17. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-image-set；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[1,2,1],"subset":[0,1,2]}。請依 [subset, map, image, finite_compactness_certificate, certificate] 欄序回答。
此步只算有限K的精確像及有限性compact證書；continuity由另一審核步驟判斷，不以有限像compact反推一般domain compact。
查看答案與解釋
([0, 1, 2], [1, 2, 1], [1, 2], 是, finite_compact_source_subset_exact_image)
Wave6第四層核對=([0, 1, 2], [1, 2, 1], [1, 2], 是, finite_compact_source_subset_exact_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-image-set · candidate
18. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-image-set；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[2,2,1],"subset":[0,1,2]}。請依 [subset, map, image, finite_compactness_certificate, certificate] 欄序回答。
此步只算有限K的精確像及有限性compact證書；continuity由另一審核步驟判斷，不以有限像compact反推一般domain compact。
查看答案與解釋
([0, 1, 2], [2, 2, 1], [1, 2], 是, finite_compact_source_subset_exact_image)
Wave6第四層核對=([0, 1, 2], [2, 2, 1], [1, 2], 是, finite_compact_source_subset_exact_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-image-set · candidate
19. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-image-set；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[0,0,2],"subset":[0,1,2]}。請依 [subset, map, image, finite_compactness_certificate, certificate] 欄序回答。
此步只算有限K的精確像及有限性compact證書；continuity由另一審核步驟判斷，不以有限像compact反推一般domain compact。
查看答案與解釋
([0, 1, 2], [0, 0, 2], [0, 2], 是, finite_compact_source_subset_exact_image)
Wave6第四層核對=([0, 1, 2], [0, 0, 2], [0, 2], 是, finite_compact_source_subset_exact_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-image-set · candidate
20. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-image-set；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[1,0,2],"subset":[0,1,2]}。請依 [subset, map, image, finite_compactness_certificate, certificate] 欄序回答。
此步只算有限K的精確像及有限性compact證書；continuity由另一審核步驟判斷，不以有限像compact反推一般domain compact。
查看答案與解釋
([0, 1, 2], [1, 0, 2], [0, 1, 2], 是, finite_compact_source_subset_exact_image)
Wave6第四層核對=([0, 1, 2], [1, 0, 2], [0, 1, 2], 是, finite_compact_source_subset_exact_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-image-set · candidate
21. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-image-set；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[2,0,2],"subset":[0,1,2]}。請依 [subset, map, image, finite_compactness_certificate, certificate] 欄序回答。
此步只算有限K的精確像及有限性compact證書；continuity由另一審核步驟判斷，不以有限像compact反推一般domain compact。
查看答案與解釋
([0, 1, 2], [2, 0, 2], [0, 2], 是, finite_compact_source_subset_exact_image)
Wave6第四層核對=([0, 1, 2], [2, 0, 2], [0, 2], 是, finite_compact_source_subset_exact_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-image-set · candidate
22. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-image-set；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[0,1,2],"subset":[0,1,2]}。請依 [subset, map, image, finite_compactness_certificate, certificate] 欄序回答。
此步只算有限K的精確像及有限性compact證書；continuity由另一審核步驟判斷，不以有限像compact反推一般domain compact。
查看答案與解釋
([0, 1, 2], [0, 1, 2], [0, 1, 2], 是, finite_compact_source_subset_exact_image)
Wave6第四層核對=([0, 1, 2], [0, 1, 2], [0, 1, 2], 是, finite_compact_source_subset_exact_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-image-set · candidate
23. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-image-set；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[1,1,2],"subset":[0,1,2]}。請依 [subset, map, image, finite_compactness_certificate, certificate] 欄序回答。
此步只算有限K的精確像及有限性compact證書；continuity由另一審核步驟判斷，不以有限像compact反推一般domain compact。
查看答案與解釋
([0, 1, 2], [1, 1, 2], [1, 2], 是, finite_compact_source_subset_exact_image)
Wave6第四層核對=([0, 1, 2], [1, 1, 2], [1, 2], 是, finite_compact_source_subset_exact_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-image-set · candidate
24. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-image-set；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[2,1,2],"subset":[0,1,2]}。請依 [subset, map, image, finite_compactness_certificate, certificate] 欄序回答。
此步只算有限K的精確像及有限性compact證書；continuity由另一審核步驟判斷，不以有限像compact反推一般domain compact。
查看答案與解釋
([0, 1, 2], [2, 1, 2], [1, 2], 是, finite_compact_source_subset_exact_image)
Wave6第四層核對=([0, 1, 2], [2, 1, 2], [1, 2], 是, finite_compact_source_subset_exact_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-image-set · candidate
25. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-image-set；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[0,2,2],"subset":[0,1,2]}。請依 [subset, map, image, finite_compactness_certificate, certificate] 欄序回答。
此步只算有限K的精確像及有限性compact證書；continuity由另一審核步驟判斷，不以有限像compact反推一般domain compact。
查看答案與解釋
([0, 1, 2], [0, 2, 2], [0, 2], 是, finite_compact_source_subset_exact_image)
Wave6第四層核對=([0, 1, 2], [0, 2, 2], [0, 2], 是, finite_compact_source_subset_exact_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-image-set · candidate
26. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-continuity-audit；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[0,0,0],"subset":[0,1,2]}。請依 [open_preimage_rows, continuous, certificate] 欄序回答。
查看答案與解釋
([[[], []], [[0], [0, 1, 2]], [[0, 1], [0, 1, 2]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [0, 1, 2]], [[1], []], [[1, 2], []], [[2], []]], 是, every_target_open_has_source_open_preimage)
Wave6第四層核對=([[[], []], [[0], [0, 1, 2]], [[0, 1], [0, 1, 2]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [0, 1, 2]], [[1], []], [[1, 2], []], [[2], []]], 是, every_target_open_has_source_open_preimage)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-continuity-audit · candidate
27. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-continuity-audit；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[1,0,0],"subset":[0,1,2]}。請依 [open_preimage_rows, continuous, certificate] 欄序回答。
查看答案與解釋
([[[], []], [[0], [1, 2]], [[0, 1], [0, 1, 2]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [1, 2]], [[1], [0]], [[1, 2], [0]], [[2], []]], 是, every_target_open_has_source_open_preimage)
Wave6第四層核對=([[[], []], [[0], [1, 2]], [[0, 1], [0, 1, 2]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [1, 2]], [[1], [0]], [[1, 2], [0]], [[2], []]], 是, every_target_open_has_source_open_preimage)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-continuity-audit · candidate
28. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-continuity-audit；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[2,0,0],"subset":[0,1,2]}。請依 [open_preimage_rows, continuous, certificate] 欄序回答。
查看答案與解釋
([[[], []], [[0], [1, 2]], [[0, 1], [1, 2]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [0, 1, 2]], [[1], []], [[1, 2], [0]], [[2], [0]]], 是, every_target_open_has_source_open_preimage)
Wave6第四層核對=([[[], []], [[0], [1, 2]], [[0, 1], [1, 2]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [0, 1, 2]], [[1], []], [[1, 2], [0]], [[2], [0]]], 是, every_target_open_has_source_open_preimage)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-continuity-audit · candidate
29. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-continuity-audit；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[0,1,0],"subset":[0,1,2]}。請依 [open_preimage_rows, continuous, certificate] 欄序回答。
查看答案與解釋
([[[], []], [[0], [0, 2]], [[0, 1], [0, 1, 2]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [0, 2]], [[1], [1]], [[1, 2], [1]], [[2], []]], 是, every_target_open_has_source_open_preimage)
Wave6第四層核對=([[[], []], [[0], [0, 2]], [[0, 1], [0, 1, 2]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [0, 2]], [[1], [1]], [[1, 2], [1]], [[2], []]], 是, every_target_open_has_source_open_preimage)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-continuity-audit · candidate
30. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-continuity-audit；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[1,1,0],"subset":[0,1,2]}。請依 [open_preimage_rows, continuous, certificate] 欄序回答。
查看答案與解釋
([[[], []], [[0], [2]], [[0, 1], [0, 1, 2]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [2]], [[1], [0, 1]], [[1, 2], [0, 1]], [[2], []]], 是, every_target_open_has_source_open_preimage)
Wave6第四層核對=([[[], []], [[0], [2]], [[0, 1], [0, 1, 2]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [2]], [[1], [0, 1]], [[1, 2], [0, 1]], [[2], []]], 是, every_target_open_has_source_open_preimage)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-continuity-audit · candidate
31. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-continuity-audit；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[2,1,0],"subset":[0,1,2]}。請依 [open_preimage_rows, continuous, certificate] 欄序回答。
查看答案與解釋
([[[], []], [[0], [2]], [[0, 1], [1, 2]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [0, 2]], [[1], [1]], [[1, 2], [0, 1]], [[2], [0]]], 是, every_target_open_has_source_open_preimage)
Wave6第四層核對=([[[], []], [[0], [2]], [[0, 1], [1, 2]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [0, 2]], [[1], [1]], [[1, 2], [0, 1]], [[2], [0]]], 是, every_target_open_has_source_open_preimage)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-continuity-audit · candidate
32. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-continuity-audit；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[0,2,0],"subset":[0,1,2]}。請依 [open_preimage_rows, continuous, certificate] 欄序回答。
查看答案與解釋
([[[], []], [[0], [0, 2]], [[0, 1], [0, 2]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [0, 1, 2]], [[1], []], [[1, 2], [1]], [[2], [1]]], 是, every_target_open_has_source_open_preimage)
Wave6第四層核對=([[[], []], [[0], [0, 2]], [[0, 1], [0, 2]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [0, 1, 2]], [[1], []], [[1, 2], [1]], [[2], [1]]], 是, every_target_open_has_source_open_preimage)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-continuity-audit · candidate
33. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-continuity-audit；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[1,2,0],"subset":[0,1,2]}。請依 [open_preimage_rows, continuous, certificate] 欄序回答。
查看答案與解釋
([[[], []], [[0], [2]], [[0, 1], [0, 2]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [1, 2]], [[1], [0]], [[1, 2], [0, 1]], [[2], [1]]], 是, every_target_open_has_source_open_preimage)
Wave6第四層核對=([[[], []], [[0], [2]], [[0, 1], [0, 2]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [1, 2]], [[1], [0]], [[1, 2], [0, 1]], [[2], [1]]], 是, every_target_open_has_source_open_preimage)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-continuity-audit · candidate
34. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-continuity-audit；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[2,2,0],"subset":[0,1,2]}。請依 [open_preimage_rows, continuous, certificate] 欄序回答。
查看答案與解釋
([[[], []], [[0], [2]], [[0, 1], [2]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [0, 1, 2]], [[1], []], [[1, 2], [0, 1]], [[2], [0, 1]]], 是, every_target_open_has_source_open_preimage)
Wave6第四層核對=([[[], []], [[0], [2]], [[0, 1], [2]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [0, 1, 2]], [[1], []], [[1, 2], [0, 1]], [[2], [0, 1]]], 是, every_target_open_has_source_open_preimage)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-continuity-audit · candidate
35. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-continuity-audit；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[0,0,1],"subset":[0,1,2]}。請依 [open_preimage_rows, continuous, certificate] 欄序回答。
查看答案與解釋
([[[], []], [[0], [0, 1]], [[0, 1], [0, 1, 2]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [0, 1]], [[1], [2]], [[1, 2], [2]], [[2], []]], 是, every_target_open_has_source_open_preimage)
Wave6第四層核對=([[[], []], [[0], [0, 1]], [[0, 1], [0, 1, 2]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [0, 1]], [[1], [2]], [[1, 2], [2]], [[2], []]], 是, every_target_open_has_source_open_preimage)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-continuity-audit · candidate
36. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-continuity-audit；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[1,0,1],"subset":[0,1,2]}。請依 [open_preimage_rows, continuous, certificate] 欄序回答。
查看答案與解釋
([[[], []], [[0], [1]], [[0, 1], [0, 1, 2]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [1]], [[1], [0, 2]], [[1, 2], [0, 2]], [[2], []]], 是, every_target_open_has_source_open_preimage)
Wave6第四層核對=([[[], []], [[0], [1]], [[0, 1], [0, 1, 2]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [1]], [[1], [0, 2]], [[1, 2], [0, 2]], [[2], []]], 是, every_target_open_has_source_open_preimage)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-continuity-audit · candidate
37. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-continuity-audit；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[2,0,1],"subset":[0,1,2]}。請依 [open_preimage_rows, continuous, certificate] 欄序回答。
查看答案與解釋
([[[], []], [[0], [1]], [[0, 1], [1, 2]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [0, 1]], [[1], [2]], [[1, 2], [0, 2]], [[2], [0]]], 是, every_target_open_has_source_open_preimage)
Wave6第四層核對=([[[], []], [[0], [1]], [[0, 1], [1, 2]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [0, 1]], [[1], [2]], [[1, 2], [0, 2]], [[2], [0]]], 是, every_target_open_has_source_open_preimage)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-continuity-audit · candidate
38. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-continuity-audit；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[0,1,1],"subset":[0,1,2]}。請依 [open_preimage_rows, continuous, certificate] 欄序回答。
查看答案與解釋
([[[], []], [[0], [0]], [[0, 1], [0, 1, 2]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [0]], [[1], [1, 2]], [[1, 2], [1, 2]], [[2], []]], 是, every_target_open_has_source_open_preimage)
Wave6第四層核對=([[[], []], [[0], [0]], [[0, 1], [0, 1, 2]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [0]], [[1], [1, 2]], [[1, 2], [1, 2]], [[2], []]], 是, every_target_open_has_source_open_preimage)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-continuity-audit · candidate
39. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-continuity-audit；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[1,1,1],"subset":[0,1,2]}。請依 [open_preimage_rows, continuous, certificate] 欄序回答。
查看答案與解釋
([[[], []], [[0], []], [[0, 1], [0, 1, 2]], [[0, 1, 2], [0, 1, 2]], [[0, 2], []], [[1], [0, 1, 2]], [[1, 2], [0, 1, 2]], [[2], []]], 是, every_target_open_has_source_open_preimage)
Wave6第四層核對=([[[], []], [[0], []], [[0, 1], [0, 1, 2]], [[0, 1, 2], [0, 1, 2]], [[0, 2], []], [[1], [0, 1, 2]], [[1, 2], [0, 1, 2]], [[2], []]], 是, every_target_open_has_source_open_preimage)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-continuity-audit · candidate
40. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-continuity-audit；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[2,1,1],"subset":[0,1,2]}。請依 [open_preimage_rows, continuous, certificate] 欄序回答。
查看答案與解釋
([[[], []], [[0], []], [[0, 1], [1, 2]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [0]], [[1], [1, 2]], [[1, 2], [0, 1, 2]], [[2], [0]]], 是, every_target_open_has_source_open_preimage)
Wave6第四層核對=([[[], []], [[0], []], [[0, 1], [1, 2]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [0]], [[1], [1, 2]], [[1, 2], [0, 1, 2]], [[2], [0]]], 是, every_target_open_has_source_open_preimage)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-continuity-audit · candidate
41. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-continuity-audit；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[0,2,1],"subset":[0,1,2]}。請依 [open_preimage_rows, continuous, certificate] 欄序回答。
查看答案與解釋
([[[], []], [[0], [0]], [[0, 1], [0, 2]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [0, 1]], [[1], [2]], [[1, 2], [1, 2]], [[2], [1]]], 是, every_target_open_has_source_open_preimage)
Wave6第四層核對=([[[], []], [[0], [0]], [[0, 1], [0, 2]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [0, 1]], [[1], [2]], [[1, 2], [1, 2]], [[2], [1]]], 是, every_target_open_has_source_open_preimage)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-continuity-audit · candidate
42. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-continuity-audit；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[1,2,1],"subset":[0,1,2]}。請依 [open_preimage_rows, continuous, certificate] 欄序回答。
查看答案與解釋
([[[], []], [[0], []], [[0, 1], [0, 2]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [1]], [[1], [0, 2]], [[1, 2], [0, 1, 2]], [[2], [1]]], 是, every_target_open_has_source_open_preimage)
Wave6第四層核對=([[[], []], [[0], []], [[0, 1], [0, 2]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [1]], [[1], [0, 2]], [[1, 2], [0, 1, 2]], [[2], [1]]], 是, every_target_open_has_source_open_preimage)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-continuity-audit · candidate
43. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-continuity-audit；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[2,2,1],"subset":[0,1,2]}。請依 [open_preimage_rows, continuous, certificate] 欄序回答。
查看答案與解釋
([[[], []], [[0], []], [[0, 1], [2]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [0, 1]], [[1], [2]], [[1, 2], [0, 1, 2]], [[2], [0, 1]]], 是, every_target_open_has_source_open_preimage)
Wave6第四層核對=([[[], []], [[0], []], [[0, 1], [2]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [0, 1]], [[1], [2]], [[1, 2], [0, 1, 2]], [[2], [0, 1]]], 是, every_target_open_has_source_open_preimage)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-continuity-audit · candidate
44. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-continuity-audit；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[0,0,2],"subset":[0,1,2]}。請依 [open_preimage_rows, continuous, certificate] 欄序回答。
查看答案與解釋
([[[], []], [[0], [0, 1]], [[0, 1], [0, 1]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [0, 1, 2]], [[1], []], [[1, 2], [2]], [[2], [2]]], 是, every_target_open_has_source_open_preimage)
Wave6第四層核對=([[[], []], [[0], [0, 1]], [[0, 1], [0, 1]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [0, 1, 2]], [[1], []], [[1, 2], [2]], [[2], [2]]], 是, every_target_open_has_source_open_preimage)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-continuity-audit · candidate
45. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-continuity-audit；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[1,0,2],"subset":[0,1,2]}。請依 [open_preimage_rows, continuous, certificate] 欄序回答。
查看答案與解釋
([[[], []], [[0], [1]], [[0, 1], [0, 1]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [1, 2]], [[1], [0]], [[1, 2], [0, 2]], [[2], [2]]], 是, every_target_open_has_source_open_preimage)
Wave6第四層核對=([[[], []], [[0], [1]], [[0, 1], [0, 1]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [1, 2]], [[1], [0]], [[1, 2], [0, 2]], [[2], [2]]], 是, every_target_open_has_source_open_preimage)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-continuity-audit · candidate
46. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-continuity-audit；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[2,0,2],"subset":[0,1,2]}。請依 [open_preimage_rows, continuous, certificate] 欄序回答。
查看答案與解釋
([[[], []], [[0], [1]], [[0, 1], [1]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [0, 1, 2]], [[1], []], [[1, 2], [0, 2]], [[2], [0, 2]]], 是, every_target_open_has_source_open_preimage)
Wave6第四層核對=([[[], []], [[0], [1]], [[0, 1], [1]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [0, 1, 2]], [[1], []], [[1, 2], [0, 2]], [[2], [0, 2]]], 是, every_target_open_has_source_open_preimage)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-continuity-audit · candidate
47. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-continuity-audit；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[0,1,2],"subset":[0,1,2]}。請依 [open_preimage_rows, continuous, certificate] 欄序回答。
查看答案與解釋
([[[], []], [[0], [0]], [[0, 1], [0, 1]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [0, 2]], [[1], [1]], [[1, 2], [1, 2]], [[2], [2]]], 是, every_target_open_has_source_open_preimage)
Wave6第四層核對=([[[], []], [[0], [0]], [[0, 1], [0, 1]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [0, 2]], [[1], [1]], [[1, 2], [1, 2]], [[2], [2]]], 是, every_target_open_has_source_open_preimage)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-continuity-audit · candidate
48. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-continuity-audit；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[1,1,2],"subset":[0,1,2]}。請依 [open_preimage_rows, continuous, certificate] 欄序回答。
查看答案與解釋
([[[], []], [[0], []], [[0, 1], [0, 1]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [2]], [[1], [0, 1]], [[1, 2], [0, 1, 2]], [[2], [2]]], 是, every_target_open_has_source_open_preimage)
Wave6第四層核對=([[[], []], [[0], []], [[0, 1], [0, 1]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [2]], [[1], [0, 1]], [[1, 2], [0, 1, 2]], [[2], [2]]], 是, every_target_open_has_source_open_preimage)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-continuity-audit · candidate
49. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-continuity-audit；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[2,1,2],"subset":[0,1,2]}。請依 [open_preimage_rows, continuous, certificate] 欄序回答。
查看答案與解釋
([[[], []], [[0], []], [[0, 1], [1]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [0, 2]], [[1], [1]], [[1, 2], [0, 1, 2]], [[2], [0, 2]]], 是, every_target_open_has_source_open_preimage)
Wave6第四層核對=([[[], []], [[0], []], [[0, 1], [1]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [0, 2]], [[1], [1]], [[1, 2], [0, 1, 2]], [[2], [0, 2]]], 是, every_target_open_has_source_open_preimage)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-continuity-audit · candidate
50. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-continuity-audit；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[0,2,2],"subset":[0,1,2]}。請依 [open_preimage_rows, continuous, certificate] 欄序回答。
查看答案與解釋
([[[], []], [[0], [0]], [[0, 1], [0]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [0, 1, 2]], [[1], []], [[1, 2], [1, 2]], [[2], [1, 2]]], 是, every_target_open_has_source_open_preimage)
Wave6第四層核對=([[[], []], [[0], [0]], [[0, 1], [0]], [[0, 1, 2], [0, 1, 2]], [[0, 2], [0, 1, 2]], [[1], []], [[1, 2], [1, 2]], [[2], [1, 2]]], 是, every_target_open_has_source_open_preimage)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-continuity-audit · candidate
51. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-cover-pullback；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[0,0,0],"subset":[0,1,2],"cover":[[0]]}。請依 [image, cover, relative_pullbacks, selected_indices, selected_target_opens, finite_subcover_certificate, certificate] 欄序回答。
relative_pullbacks是K內的逆像交集；selected_indices按最小數量再依遞增bitmask選首個，保留原cover索引而不聲稱唯一。
查看答案與解釋
([0], [[0]], [[0, 1, 2]], [0], [[0]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)
Wave6第四層核對=([0], [[0]], [[0, 1, 2]], [0], [[0]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-cover-pullback · candidate
52. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-cover-pullback；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[1,0,0],"subset":[0,1,2],"cover":[[0],[1]]}。請依 [image, cover, relative_pullbacks, selected_indices, selected_target_opens, finite_subcover_certificate, certificate] 欄序回答。
relative_pullbacks是K內的逆像交集；selected_indices按最小數量再依遞增bitmask選首個，保留原cover索引而不聲稱唯一。
查看答案與解釋
([0, 1], [[0], [1]], [[1, 2], [0]], [0, 1], [[0], [1]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)
Wave6第四層核對=([0, 1], [[0], [1]], [[1, 2], [0]], [0, 1], [[0], [1]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-cover-pullback · candidate
53. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-cover-pullback；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[2,0,0],"subset":[0,1,2],"cover":[[0],[2]]}。請依 [image, cover, relative_pullbacks, selected_indices, selected_target_opens, finite_subcover_certificate, certificate] 欄序回答。
relative_pullbacks是K內的逆像交集；selected_indices按最小數量再依遞增bitmask選首個，保留原cover索引而不聲稱唯一。
查看答案與解釋
([0, 2], [[0], [2]], [[1, 2], [0]], [0, 1], [[0], [2]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)
Wave6第四層核對=([0, 2], [[0], [2]], [[1, 2], [0]], [0, 1], [[0], [2]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-cover-pullback · candidate
54. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-cover-pullback；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[0,1,0],"subset":[0,1,2],"cover":[[0],[1]]}。請依 [image, cover, relative_pullbacks, selected_indices, selected_target_opens, finite_subcover_certificate, certificate] 欄序回答。
relative_pullbacks是K內的逆像交集；selected_indices按最小數量再依遞增bitmask選首個，保留原cover索引而不聲稱唯一。
查看答案與解釋
([0, 1], [[0], [1]], [[0, 2], [1]], [0, 1], [[0], [1]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)
Wave6第四層核對=([0, 1], [[0], [1]], [[0, 2], [1]], [0, 1], [[0], [1]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-cover-pullback · candidate
55. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-cover-pullback；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[1,1,0],"subset":[0,1,2],"cover":[[0],[1]]}。請依 [image, cover, relative_pullbacks, selected_indices, selected_target_opens, finite_subcover_certificate, certificate] 欄序回答。
relative_pullbacks是K內的逆像交集；selected_indices按最小數量再依遞增bitmask選首個，保留原cover索引而不聲稱唯一。
查看答案與解釋
([0, 1], [[0], [1]], [[2], [0, 1]], [0, 1], [[0], [1]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)
Wave6第四層核對=([0, 1], [[0], [1]], [[2], [0, 1]], [0, 1], [[0], [1]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-cover-pullback · candidate
56. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-cover-pullback；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[2,1,0],"subset":[0,1,2],"cover":[[0],[1],[2]]}。請依 [image, cover, relative_pullbacks, selected_indices, selected_target_opens, finite_subcover_certificate, certificate] 欄序回答。
relative_pullbacks是K內的逆像交集；selected_indices按最小數量再依遞增bitmask選首個，保留原cover索引而不聲稱唯一。
查看答案與解釋
([0, 1, 2], [[0], [1], [2]], [[2], [1], [0]], [0, 1, 2], [[0], [1], [2]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)
Wave6第四層核對=([0, 1, 2], [[0], [1], [2]], [[2], [1], [0]], [0, 1, 2], [[0], [1], [2]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-cover-pullback · candidate
57. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-cover-pullback；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[0,2,0],"subset":[0,1,2],"cover":[[0],[2]]}。請依 [image, cover, relative_pullbacks, selected_indices, selected_target_opens, finite_subcover_certificate, certificate] 欄序回答。
relative_pullbacks是K內的逆像交集；selected_indices按最小數量再依遞增bitmask選首個，保留原cover索引而不聲稱唯一。
查看答案與解釋
([0, 2], [[0], [2]], [[0, 2], [1]], [0, 1], [[0], [2]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)
Wave6第四層核對=([0, 2], [[0], [2]], [[0, 2], [1]], [0, 1], [[0], [2]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-cover-pullback · candidate
58. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-cover-pullback；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[1,2,0],"subset":[0,1,2],"cover":[[0],[1],[2]]}。請依 [image, cover, relative_pullbacks, selected_indices, selected_target_opens, finite_subcover_certificate, certificate] 欄序回答。
relative_pullbacks是K內的逆像交集；selected_indices按最小數量再依遞增bitmask選首個，保留原cover索引而不聲稱唯一。
查看答案與解釋
([0, 1, 2], [[0], [1], [2]], [[2], [0], [1]], [0, 1, 2], [[0], [1], [2]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)
Wave6第四層核對=([0, 1, 2], [[0], [1], [2]], [[2], [0], [1]], [0, 1, 2], [[0], [1], [2]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-cover-pullback · candidate
59. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-cover-pullback；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[2,2,0],"subset":[0,1,2],"cover":[[0],[2]]}。請依 [image, cover, relative_pullbacks, selected_indices, selected_target_opens, finite_subcover_certificate, certificate] 欄序回答。
relative_pullbacks是K內的逆像交集；selected_indices按最小數量再依遞增bitmask選首個，保留原cover索引而不聲稱唯一。
查看答案與解釋
([0, 2], [[0], [2]], [[2], [0, 1]], [0, 1], [[0], [2]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)
Wave6第四層核對=([0, 2], [[0], [2]], [[2], [0, 1]], [0, 1], [[0], [2]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-cover-pullback · candidate
60. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-cover-pullback；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[0,0,1],"subset":[0,1,2],"cover":[[0],[1]]}。請依 [image, cover, relative_pullbacks, selected_indices, selected_target_opens, finite_subcover_certificate, certificate] 欄序回答。
relative_pullbacks是K內的逆像交集；selected_indices按最小數量再依遞增bitmask選首個，保留原cover索引而不聲稱唯一。
查看答案與解釋
([0, 1], [[0], [1]], [[0, 1], [2]], [0, 1], [[0], [1]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)
Wave6第四層核對=([0, 1], [[0], [1]], [[0, 1], [2]], [0, 1], [[0], [1]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-cover-pullback · candidate
61. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-cover-pullback；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[1,0,1],"subset":[0,1,2],"cover":[[0],[1]]}。請依 [image, cover, relative_pullbacks, selected_indices, selected_target_opens, finite_subcover_certificate, certificate] 欄序回答。
relative_pullbacks是K內的逆像交集；selected_indices按最小數量再依遞增bitmask選首個，保留原cover索引而不聲稱唯一。
查看答案與解釋
([0, 1], [[0], [1]], [[1], [0, 2]], [0, 1], [[0], [1]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)
Wave6第四層核對=([0, 1], [[0], [1]], [[1], [0, 2]], [0, 1], [[0], [1]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-cover-pullback · candidate
62. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-cover-pullback；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[2,0,1],"subset":[0,1,2],"cover":[[0],[1],[2]]}。請依 [image, cover, relative_pullbacks, selected_indices, selected_target_opens, finite_subcover_certificate, certificate] 欄序回答。
relative_pullbacks是K內的逆像交集；selected_indices按最小數量再依遞增bitmask選首個，保留原cover索引而不聲稱唯一。
查看答案與解釋
([0, 1, 2], [[0], [1], [2]], [[1], [2], [0]], [0, 1, 2], [[0], [1], [2]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)
Wave6第四層核對=([0, 1, 2], [[0], [1], [2]], [[1], [2], [0]], [0, 1, 2], [[0], [1], [2]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-cover-pullback · candidate
63. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-cover-pullback；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[0,1,1],"subset":[0,1,2],"cover":[[0],[1]]}。請依 [image, cover, relative_pullbacks, selected_indices, selected_target_opens, finite_subcover_certificate, certificate] 欄序回答。
relative_pullbacks是K內的逆像交集；selected_indices按最小數量再依遞增bitmask選首個，保留原cover索引而不聲稱唯一。
查看答案與解釋
([0, 1], [[0], [1]], [[0], [1, 2]], [0, 1], [[0], [1]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)
Wave6第四層核對=([0, 1], [[0], [1]], [[0], [1, 2]], [0, 1], [[0], [1]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-cover-pullback · candidate
64. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-cover-pullback；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[1,1,1],"subset":[0,1,2],"cover":[[1]]}。請依 [image, cover, relative_pullbacks, selected_indices, selected_target_opens, finite_subcover_certificate, certificate] 欄序回答。
relative_pullbacks是K內的逆像交集；selected_indices按最小數量再依遞增bitmask選首個，保留原cover索引而不聲稱唯一。
查看答案與解釋
([1], [[1]], [[0, 1, 2]], [0], [[1]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)
Wave6第四層核對=([1], [[1]], [[0, 1, 2]], [0], [[1]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-cover-pullback · candidate
65. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-cover-pullback；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[2,1,1],"subset":[0,1,2],"cover":[[1],[2]]}。請依 [image, cover, relative_pullbacks, selected_indices, selected_target_opens, finite_subcover_certificate, certificate] 欄序回答。
relative_pullbacks是K內的逆像交集；selected_indices按最小數量再依遞增bitmask選首個，保留原cover索引而不聲稱唯一。
查看答案與解釋
([1, 2], [[1], [2]], [[1, 2], [0]], [0, 1], [[1], [2]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)
Wave6第四層核對=([1, 2], [[1], [2]], [[1, 2], [0]], [0, 1], [[1], [2]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-cover-pullback · candidate
66. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-cover-pullback；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[0,2,1],"subset":[0,1,2],"cover":[[0],[1],[2]]}。請依 [image, cover, relative_pullbacks, selected_indices, selected_target_opens, finite_subcover_certificate, certificate] 欄序回答。
relative_pullbacks是K內的逆像交集；selected_indices按最小數量再依遞增bitmask選首個，保留原cover索引而不聲稱唯一。
查看答案與解釋
([0, 1, 2], [[0], [1], [2]], [[0], [2], [1]], [0, 1, 2], [[0], [1], [2]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)
Wave6第四層核對=([0, 1, 2], [[0], [1], [2]], [[0], [2], [1]], [0, 1, 2], [[0], [1], [2]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-cover-pullback · candidate
67. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-cover-pullback；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[1,2,1],"subset":[0,1,2],"cover":[[1],[2]]}。請依 [image, cover, relative_pullbacks, selected_indices, selected_target_opens, finite_subcover_certificate, certificate] 欄序回答。
relative_pullbacks是K內的逆像交集；selected_indices按最小數量再依遞增bitmask選首個，保留原cover索引而不聲稱唯一。
查看答案與解釋
([1, 2], [[1], [2]], [[0, 2], [1]], [0, 1], [[1], [2]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)
Wave6第四層核對=([1, 2], [[1], [2]], [[0, 2], [1]], [0, 1], [[1], [2]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-cover-pullback · candidate
68. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-cover-pullback；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[2,2,1],"subset":[0,1,2],"cover":[[1],[2]]}。請依 [image, cover, relative_pullbacks, selected_indices, selected_target_opens, finite_subcover_certificate, certificate] 欄序回答。
relative_pullbacks是K內的逆像交集；selected_indices按最小數量再依遞增bitmask選首個，保留原cover索引而不聲稱唯一。
查看答案與解釋
([1, 2], [[1], [2]], [[2], [0, 1]], [0, 1], [[1], [2]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)
Wave6第四層核對=([1, 2], [[1], [2]], [[2], [0, 1]], [0, 1], [[1], [2]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-cover-pullback · candidate
69. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-cover-pullback；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[0,0,2],"subset":[0,1,2],"cover":[[0],[2]]}。請依 [image, cover, relative_pullbacks, selected_indices, selected_target_opens, finite_subcover_certificate, certificate] 欄序回答。
relative_pullbacks是K內的逆像交集；selected_indices按最小數量再依遞增bitmask選首個，保留原cover索引而不聲稱唯一。
查看答案與解釋
([0, 2], [[0], [2]], [[0, 1], [2]], [0, 1], [[0], [2]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)
Wave6第四層核對=([0, 2], [[0], [2]], [[0, 1], [2]], [0, 1], [[0], [2]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-cover-pullback · candidate
70. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-cover-pullback；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[1,0,2],"subset":[0,1,2],"cover":[[0],[1],[2]]}。請依 [image, cover, relative_pullbacks, selected_indices, selected_target_opens, finite_subcover_certificate, certificate] 欄序回答。
relative_pullbacks是K內的逆像交集；selected_indices按最小數量再依遞增bitmask選首個，保留原cover索引而不聲稱唯一。
查看答案與解釋
([0, 1, 2], [[0], [1], [2]], [[1], [0], [2]], [0, 1, 2], [[0], [1], [2]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)
Wave6第四層核對=([0, 1, 2], [[0], [1], [2]], [[1], [0], [2]], [0, 1, 2], [[0], [1], [2]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-cover-pullback · candidate
71. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-cover-pullback；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[2,0,2],"subset":[0,1,2],"cover":[[0],[2]]}。請依 [image, cover, relative_pullbacks, selected_indices, selected_target_opens, finite_subcover_certificate, certificate] 欄序回答。
relative_pullbacks是K內的逆像交集；selected_indices按最小數量再依遞增bitmask選首個，保留原cover索引而不聲稱唯一。
查看答案與解釋
([0, 2], [[0], [2]], [[1], [0, 2]], [0, 1], [[0], [2]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)
Wave6第四層核對=([0, 2], [[0], [2]], [[1], [0, 2]], [0, 1], [[0], [2]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-cover-pullback · candidate
72. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-cover-pullback；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[0,1,2],"subset":[0,1,2],"cover":[[0],[1],[2]]}。請依 [image, cover, relative_pullbacks, selected_indices, selected_target_opens, finite_subcover_certificate, certificate] 欄序回答。
relative_pullbacks是K內的逆像交集；selected_indices按最小數量再依遞增bitmask選首個，保留原cover索引而不聲稱唯一。
查看答案與解釋
([0, 1, 2], [[0], [1], [2]], [[0], [1], [2]], [0, 1, 2], [[0], [1], [2]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)
Wave6第四層核對=([0, 1, 2], [[0], [1], [2]], [[0], [1], [2]], [0, 1, 2], [[0], [1], [2]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-cover-pullback · candidate
73. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-cover-pullback；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[1,1,2],"subset":[0,1,2],"cover":[[1],[2]]}。請依 [image, cover, relative_pullbacks, selected_indices, selected_target_opens, finite_subcover_certificate, certificate] 欄序回答。
relative_pullbacks是K內的逆像交集；selected_indices按最小數量再依遞增bitmask選首個，保留原cover索引而不聲稱唯一。
查看答案與解釋
([1, 2], [[1], [2]], [[0, 1], [2]], [0, 1], [[1], [2]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)
Wave6第四層核對=([1, 2], [[1], [2]], [[0, 1], [2]], [0, 1], [[1], [2]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-cover-pullback · candidate
74. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-cover-pullback；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[2,1,2],"subset":[0,1,2],"cover":[[1],[2]]}。請依 [image, cover, relative_pullbacks, selected_indices, selected_target_opens, finite_subcover_certificate, certificate] 欄序回答。
relative_pullbacks是K內的逆像交集；selected_indices按最小數量再依遞增bitmask選首個，保留原cover索引而不聲稱唯一。
查看答案與解釋
([1, 2], [[1], [2]], [[1], [0, 2]], [0, 1], [[1], [2]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)
Wave6第四層核對=([1, 2], [[1], [2]], [[1], [0, 2]], [0, 1], [[1], [2]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-cover-pullback · candidate
75. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-cover-pullback；資料={"source_n":3,"target_n":3,"source_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"target_topology":[[],[0],[0,1],[0,1,2],[0,2],[1],[1,2],[2]],"map":[0,2,2],"subset":[0,1,2],"cover":[[0],[2]]}。請依 [image, cover, relative_pullbacks, selected_indices, selected_target_opens, finite_subcover_certificate, certificate] 欄序回答。
relative_pullbacks是K內的逆像交集；selected_indices按最小數量再依遞增bitmask選首個，保留原cover索引而不聲稱唯一。
查看答案與解釋
([0, 2], [[0], [2]], [[0], [1, 2]], [0, 1], [[0], [2]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)
Wave6第四層核對=([0, 2], [[0], [2]], [[0], [1, 2]], [0, 1], [[0], [2]], 是, finite_subcover_pulled_back_to_K_then_pushed_forward_to_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-cover-pullback · candidate
76. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-reverse-implication-boundary；資料={"left":-2,"right":2,"value":0}。請依 [left, right, constant_value, domain_compact, continuous, image_compact, reverse_implication_claim, boundary] 欄序回答。
查看答案與解釋
(-2, 2, 0, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)
Wave6第四層核對=(-2, 2, 0, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-reverse-implication-boundary · candidate
77. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-reverse-implication-boundary；資料={"left":-3,"right":3,"value":1}。請依 [left, right, constant_value, domain_compact, continuous, image_compact, reverse_implication_claim, boundary] 欄序回答。
查看答案與解釋
(-3, 3, 1, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)
Wave6第四層核對=(-3, 3, 1, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-reverse-implication-boundary · candidate
78. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-reverse-implication-boundary；資料={"left":-4,"right":4,"value":2}。請依 [left, right, constant_value, domain_compact, continuous, image_compact, reverse_implication_claim, boundary] 欄序回答。
查看答案與解釋
(-4, 4, 2, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)
Wave6第四層核對=(-4, 4, 2, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-reverse-implication-boundary · candidate
79. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-reverse-implication-boundary；資料={"left":-5,"right":5,"value":3}。請依 [left, right, constant_value, domain_compact, continuous, image_compact, reverse_implication_claim, boundary] 欄序回答。
查看答案與解釋
(-5, 5, 3, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)
Wave6第四層核對=(-5, 5, 3, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-reverse-implication-boundary · candidate
80. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-reverse-implication-boundary；資料={"left":-6,"right":6,"value":4}。請依 [left, right, constant_value, domain_compact, continuous, image_compact, reverse_implication_claim, boundary] 欄序回答。
查看答案與解釋
(-6, 6, 4, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)
Wave6第四層核對=(-6, 6, 4, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-reverse-implication-boundary · candidate
81. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-reverse-implication-boundary；資料={"left":-7,"right":7,"value":5}。請依 [left, right, constant_value, domain_compact, continuous, image_compact, reverse_implication_claim, boundary] 欄序回答。
查看答案與解釋
(-7, 7, 5, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)
Wave6第四層核對=(-7, 7, 5, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-reverse-implication-boundary · candidate
82. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-reverse-implication-boundary；資料={"left":-8,"right":8,"value":6}。請依 [left, right, constant_value, domain_compact, continuous, image_compact, reverse_implication_claim, boundary] 欄序回答。
查看答案與解釋
(-8, 8, 6, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)
Wave6第四層核對=(-8, 8, 6, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-reverse-implication-boundary · candidate
83. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-reverse-implication-boundary；資料={"left":-9,"right":9,"value":7}。請依 [left, right, constant_value, domain_compact, continuous, image_compact, reverse_implication_claim, boundary] 欄序回答。
查看答案與解釋
(-9, 9, 7, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)
Wave6第四層核對=(-9, 9, 7, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-reverse-implication-boundary · candidate
84. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-reverse-implication-boundary；資料={"left":-10,"right":10,"value":8}。請依 [left, right, constant_value, domain_compact, continuous, image_compact, reverse_implication_claim, boundary] 欄序回答。
查看答案與解釋
(-10, 10, 8, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)
Wave6第四層核對=(-10, 10, 8, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-reverse-implication-boundary · candidate
85. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-reverse-implication-boundary；資料={"left":-11,"right":11,"value":9}。請依 [left, right, constant_value, domain_compact, continuous, image_compact, reverse_implication_claim, boundary] 欄序回答。
查看答案與解釋
(-11, 11, 9, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)
Wave6第四層核對=(-11, 11, 9, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-reverse-implication-boundary · candidate
86. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-reverse-implication-boundary；資料={"left":-12,"right":12,"value":10}。請依 [left, right, constant_value, domain_compact, continuous, image_compact, reverse_implication_claim, boundary] 欄序回答。
查看答案與解釋
(-12, 12, 10, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)
Wave6第四層核對=(-12, 12, 10, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-reverse-implication-boundary · candidate
87. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-reverse-implication-boundary；資料={"left":-13,"right":13,"value":11}。請依 [left, right, constant_value, domain_compact, continuous, image_compact, reverse_implication_claim, boundary] 欄序回答。
查看答案與解釋
(-13, 13, 11, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)
Wave6第四層核對=(-13, 13, 11, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-reverse-implication-boundary · candidate
88. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-reverse-implication-boundary；資料={"left":-14,"right":14,"value":12}。請依 [left, right, constant_value, domain_compact, continuous, image_compact, reverse_implication_claim, boundary] 欄序回答。
查看答案與解釋
(-14, 14, 12, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)
Wave6第四層核對=(-14, 14, 12, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-reverse-implication-boundary · candidate
89. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-reverse-implication-boundary；資料={"left":-15,"right":15,"value":13}。請依 [left, right, constant_value, domain_compact, continuous, image_compact, reverse_implication_claim, boundary] 欄序回答。
查看答案與解釋
(-15, 15, 13, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)
Wave6第四層核對=(-15, 15, 13, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-reverse-implication-boundary · candidate
90. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-reverse-implication-boundary；資料={"left":-16,"right":16,"value":14}。請依 [left, right, constant_value, domain_compact, continuous, image_compact, reverse_implication_claim, boundary] 欄序回答。
查看答案與解釋
(-16, 16, 14, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)
Wave6第四層核對=(-16, 16, 14, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-reverse-implication-boundary · candidate
91. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-reverse-implication-boundary；資料={"left":-17,"right":17,"value":15}。請依 [left, right, constant_value, domain_compact, continuous, image_compact, reverse_implication_claim, boundary] 欄序回答。
查看答案與解釋
(-17, 17, 15, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)
Wave6第四層核對=(-17, 17, 15, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-reverse-implication-boundary · candidate
92. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-reverse-implication-boundary；資料={"left":-18,"right":18,"value":16}。請依 [left, right, constant_value, domain_compact, continuous, image_compact, reverse_implication_claim, boundary] 欄序回答。
查看答案與解釋
(-18, 18, 16, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)
Wave6第四層核對=(-18, 18, 16, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-reverse-implication-boundary · candidate
93. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-reverse-implication-boundary；資料={"left":-19,"right":19,"value":17}。請依 [left, right, constant_value, domain_compact, continuous, image_compact, reverse_implication_claim, boundary] 欄序回答。
查看答案與解釋
(-19, 19, 17, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)
Wave6第四層核對=(-19, 19, 17, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-reverse-implication-boundary · candidate
94. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-reverse-implication-boundary；資料={"left":-20,"right":20,"value":18}。請依 [left, right, constant_value, domain_compact, continuous, image_compact, reverse_implication_claim, boundary] 欄序回答。
查看答案與解釋
(-20, 20, 18, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)
Wave6第四層核對=(-20, 20, 18, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-reverse-implication-boundary · candidate
95. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-reverse-implication-boundary；資料={"left":-21,"right":21,"value":19}。請依 [left, right, constant_value, domain_compact, continuous, image_compact, reverse_implication_claim, boundary] 欄序回答。
查看答案與解釋
(-21, 21, 19, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)
Wave6第四層核對=(-21, 21, 19, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-reverse-implication-boundary · candidate
96. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-reverse-implication-boundary；資料={"left":-22,"right":22,"value":20}。請依 [left, right, constant_value, domain_compact, continuous, image_compact, reverse_implication_claim, boundary] 欄序回答。
查看答案與解釋
(-22, 22, 20, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)
Wave6第四層核對=(-22, 22, 20, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-reverse-implication-boundary · candidate
97. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-reverse-implication-boundary；資料={"left":-23,"right":23,"value":21}。請依 [left, right, constant_value, domain_compact, continuous, image_compact, reverse_implication_claim, boundary] 欄序回答。
查看答案與解釋
(-23, 23, 21, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)
Wave6第四層核對=(-23, 23, 21, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-reverse-implication-boundary · candidate
98. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-reverse-implication-boundary；資料={"left":-24,"right":24,"value":22}。請依 [left, right, constant_value, domain_compact, continuous, image_compact, reverse_implication_claim, boundary] 欄序回答。
查看答案與解釋
(-24, 24, 22, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)
Wave6第四層核對=(-24, 24, 22, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-reverse-implication-boundary · candidate
99. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-reverse-implication-boundary；資料={"left":-25,"right":25,"value":23}。請依 [left, right, constant_value, domain_compact, continuous, image_compact, reverse_implication_claim, boundary] 欄序回答。
查看答案與解釋
(-25, 25, 23, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)
Wave6第四層核對=(-25, 25, 23, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-reverse-implication-boundary · candidate
100. 緊緻集的連續像
compact K、完整來源與目標拓撲以及total continuous map。操作=compactimg-reverse-implication-boundary；資料={"left":-26,"right":26,"value":24}。請依 [left, right, constant_value, domain_compact, continuous, image_compact, reverse_implication_claim, boundary] 欄序回答。
查看答案與解釋
(-26, 26, 24, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)
Wave6第四層核對=(-26, 26, 24, 否, 是, 是, 否, constant_continuous_map_from_noncompact_open_interval_has_compact_singleton_image)；依完整明示資料獨立重算；對image open cover先拉回K取得finite subcover再推回image；不需injective或surjective；compact image不反推domain compact，preimage compact與image closed皆需額外假設。
本題逐步詳解（AI 二次覆核）
緊緻集的連續像 · qf-mod41-compactimg-reverse-implication-boundary · candidate
原始題目 JSONL · 驗收報告