第 6739 題：候選階乘報告的兩個見證

原題與已知條件

N從0起；BigInt精確階乘；n=13，候選十進字串u=6227020801、v=87178291214。依序答 (真F(n), 真F(n+1), u−F(n), v−(n+1)u, 雙報告皆真是否)。

• G001 — N從0起；BigInt精確階乘；n=13，候選十進字串u=6227020801、v=87178291214。依序答 (真F(n), 真F(n+1), u−F(n), v−(n+1)u, 雙報告皆真是否)。

定義與適用範圍

沿用原題明示的論域、假設與來源 MKO 定義。本題已完成第二對話數理與中英語義覆核，並由原始參數逐題獨立重算模型、答案與每個算術步驟；原題仍為 candidate。

• mko-factorial

逐步推導

N includes0;F(0)=1;F(j)=j·F(j−1)

exact integer products,not floating values or a permutation proof

actual factorial:start at F(0)

F(0)=1

actual factorial through factor1 := mul(1, 1)

actual factorial through factor1 = 1

actual factorial through factor2 := mul(1, 2)

actual factorial through factor2 = 2

actual factorial through factor3 := mul(2, 3)

actual factorial through factor3 = 6

actual factorial through factor4 := mul(6, 4)

actual factorial through factor4 = 24

actual factorial through factor5 := mul(24, 5)

actual factorial through factor5 = 120

actual factorial through factor6 := mul(120, 6)

actual factorial through factor6 = 720

actual factorial through factor7 := mul(720, 7)

actual factorial through factor7 = 5040

actual factorial through factor8 := mul(5040, 8)

actual factorial through factor8 = 40320

actual factorial through factor9 := mul(40320, 9)

actual factorial through factor9 = 362880

actual factorial through factor10 := mul(362880, 10)

actual factorial through factor10 = 3628800

actual factorial through factor11 := mul(3628800, 11)

actual factorial through factor11 = 39916800

actual factorial through factor12 := mul(39916800, 12)

actual factorial through factor12 = 479001600

actual factorial through factor13 := mul(479001600, 13)

actual factorial through factor13 = 6227020800

true successor factorial := mul(14, 6227020800)

true successor factorial = 87178291200

reported u minus true factorial := sub(6227020801, 6227020800)

reported u minus true factorial = 1

successor predicted from reported u := mul(14, 6227020801)

successor predicted from reported u = 87178291214

reported successor recurrence defect := sub(87178291214, 87178291214)

reported successor recurrence defect = 0

true values=(6227020800,87178291200);reports=(6227020801,87178291214);defects=(1,0)

both reports true=否

逐步反向核對

• S020 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S019 · premise_and_result_audit — 以精確有理數重算 reported successor recurrence defect，不以小數近似替代。
• S018 · premise_and_result_audit — 以精確有理數重算 successor predicted from reported u，不以小數近似替代。
• S017 · premise_and_result_audit — 以精確有理數重算 reported u minus true factorial，不以小數近似替代。
• S016 · premise_and_result_audit — 以精確有理數重算 true successor factorial，不以小數近似替代。
• S015 · premise_and_result_audit — 以精確有理數重算 actual factorial through factor13，不以小數近似替代。
• S014 · premise_and_result_audit — 以精確有理數重算 actual factorial through factor12，不以小數近似替代。
• S013 · premise_and_result_audit — 以精確有理數重算 actual factorial through factor11，不以小數近似替代。
• S012 · premise_and_result_audit — 以精確有理數重算 actual factorial through factor10，不以小數近似替代。
• S011 · premise_and_result_audit — 以精確有理數重算 actual factorial through factor9，不以小數近似替代。
• S010 · premise_and_result_audit — 以精確有理數重算 actual factorial through factor8，不以小數近似替代。
• S009 · premise_and_result_audit — 以精確有理數重算 actual factorial through factor7，不以小數近似替代。
• S008 · premise_and_result_audit — 以精確有理數重算 actual factorial through factor6，不以小數近似替代。
• S007 · premise_and_result_audit — 以精確有理數重算 actual factorial through factor5，不以小數近似替代。
• S006 · premise_and_result_audit — 以精確有理數重算 actual factorial through factor4，不以小數近似替代。
• S005 · premise_and_result_audit — 以精確有理數重算 actual factorial through factor3，不以小數近似替代。
• S004 · premise_and_result_audit — 以精確有理數重算 actual factorial through factor2，不以小數近似替代。
• S003 · premise_and_result_audit — 以精確有理數重算 actual factorial through factor1，不以小數近似替代。
• S002 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S001 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。

結論

(6227020800, 87178291200, 1, 0, 否)

依上列完整代值及條件核對得到原題答案；原題編號、格式與狀態保持不變。

本題覆核與來源綁定

覆核日期：2026-10-26

原題、答案、步驟表達式、數值 AST 與既有歷史保持原樣；原來的候選狀態屬於來源歷史，不覆寫為形式化證明。