第 22176 題：有限因數格上的Möbius反演

原題與已知條件

positive integer domain、完整positive divisor set與完整UPF-derived Mobius values。操作=mobinv-roundtrip-table；資料={"n":1,"a":1,"b":-12}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。

• G001 — positive integer domain、完整positive divisor set與完整UPF-derived Mobius values。操作=mobinv-roundtrip-table；資料={"n":1,"a":1,"b":-12}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。

定義與適用範圍

沿用原題明示的論域、假設與來源 MKO 定義。本題已完成第二對話數理與中英語義覆核，並由原始參數逐題獨立重算模型、答案與每個算術步驟；原題仍為 candidate。

• mko-mobius-inversion-finite-divisors

逐步推導

source operation=mobinv-roundtrip-table;original snapshot and mathematics retained

explicit ordered source output fields=[n, roundtrip_rows, all_equal, boundary]

Mobius inversion ORIGINAL roundtrip:actual positive input=1;check complete integer range1..1

ALL positive divisors INCREASING=[1];not only primes/proper divisors or all integers<=n

Mobius roundtrip m=1 forward:actual positive input=1;check complete integer range1..1

ALL positive divisors INCREASING=[1];not only primes/proper divisors or all integers<=n

Mobius roundtrip m=1 forward f(1) ORIGINAL a times divisor := mul(1, 1)

Mobius roundtrip m=1 forward f(1) ORIGINAL a times divisor = 1

Mobius roundtrip m=1 forward f(1) plus ORIGINAL b := sum(1, -12)

Mobius roundtrip m=1 forward f(1) plus ORIGINAL b = -11

Mobius roundtrip m=1 forward full forward divisor sum := sum(-11)

Mobius roundtrip m=1 forward full forward divisor sum = -11

Mobius roundtrip m=1 inverse:actual positive input=1;check complete integer range1..1

ALL positive divisors INCREASING=[1];not only primes/proper divisors or all integers<=n

Mobius roundtrip m=1 inverse Mobius at ORIGINAL divisor1:actual positive input for mu=1

complete prime multiplicities required for this input;mu(1) uses empty product,not a partial factor search

Mobius roundtrip m=1 inverse Mobius at ORIGINAL divisor1:input=1;COMPLETE prime multiset=[];distinct primes=[]

mu=1;empty product case=是;repeated prime=否

Mobius roundtrip m=1 inverse n divided by ORIGINAL divisor1 := div(1, 1)

Mobius roundtrip m=1 inverse n divided by ORIGINAL divisor1 = 1

Mobius roundtrip m=1 inverse F(n/1):actual positive input=1;check complete integer range1..1

ALL positive divisors INCREASING=[1];not only primes/proper divisors or all integers<=n

Mobius roundtrip m=1 inverse F(n/1) f(1) ORIGINAL a times divisor := mul(1, 1)

Mobius roundtrip m=1 inverse F(n/1) f(1) ORIGINAL a times divisor = 1

Mobius roundtrip m=1 inverse F(n/1) f(1) plus ORIGINAL b := sum(1, -12)

Mobius roundtrip m=1 inverse F(n/1) f(1) plus ORIGINAL b = -11

Mobius roundtrip m=1 inverse F(n/1) full forward divisor sum := sum(-11)

Mobius roundtrip m=1 inverse F(n/1) full forward divisor sum = -11

Mobius roundtrip m=1 inverse mu(1) times SAME F(n/1) := mul(1, -11)

Mobius roundtrip m=1 inverse mu(1) times SAME F(n/1) = -11

Mobius roundtrip m=1 inverse complete inverse-term sum := sum(-11)

Mobius roundtrip m=1 inverse complete inverse-term sum = -11

Mobius roundtrip m=1 inverse direct ORIGINAL a times n := mul(1, 1)

Mobius roundtrip m=1 inverse direct ORIGINAL a times n = 1

Mobius roundtrip m=1 inverse direct plus ORIGINAL b := sum(1, -12)

Mobius roundtrip m=1 inverse direct plus ORIGINAL b = -11

Mobius roundtrip m=1 inverse:actual n=1;ALL [d,mu(d),n/d,F(n/d),mu(d)*F(n/d)] rows=[[1, 1, 1, -11, -11]]

complete reconstructed=-11;direct f(n)=-11;sum_d mu(d)sum_e|n/d f(e)=sum_e|n f(e)sum_d|n/e mu(d)=f(n)

逐步反向核對

• S019 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S018 · premise_and_result_audit — 以精確有理數重算 Mobius roundtrip m=1 inverse direct plus ORIGINAL b，不以小數近似替代。
• S017 · premise_and_result_audit — 以精確有理數重算 Mobius roundtrip m=1 inverse direct ORIGINAL a times n，不以小數近似替代。
• S016 · premise_and_result_audit — 以精確有理數重算 Mobius roundtrip m=1 inverse complete inverse-term sum，不以小數近似替代。
• S015 · premise_and_result_audit — 以精確有理數重算 Mobius roundtrip m=1 inverse mu(1) times SAME F(n/1)，不以小數近似替代。
• S014 · premise_and_result_audit — 以精確有理數重算 Mobius roundtrip m=1 inverse F(n/1) full forward divisor sum，不以小數近似替代。
• S013 · premise_and_result_audit — 以精確有理數重算 Mobius roundtrip m=1 inverse F(n/1) f(1) plus ORIGINAL b，不以小數近似替代。
• S012 · premise_and_result_audit — 以精確有理數重算 Mobius roundtrip m=1 inverse F(n/1) f(1) ORIGINAL a times divisor，不以小數近似替代。
• S011 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S010 · premise_and_result_audit — 以精確有理數重算 Mobius roundtrip m=1 inverse n divided by ORIGINAL divisor1，不以小數近似替代。
• S009 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S008 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S007 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S006 · premise_and_result_audit — 以精確有理數重算 Mobius roundtrip m=1 forward full forward divisor sum，不以小數近似替代。
• S005 · premise_and_result_audit — 以精確有理數重算 Mobius roundtrip m=1 forward f(1) plus ORIGINAL b，不以小數近似替代。
• S004 · premise_and_result_audit — 以精確有理數重算 Mobius roundtrip m=1 forward f(1) ORIGINAL a times divisor，不以小數近似替代。
• S003 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S002 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。
• S001 · premise_and_result_audit — 回到原始資料與本步條件核對，不把單向推論誤稱等價。

結論

(1, [[1, -11, -11, -11]], 是, mu_one_boundary_preserved)

依上列完整代值及條件核對得到原題答案；原題編號、格式與狀態保持不變。

本題覆核與來源綁定

覆核日期：2026-10-26

原題、答案、步驟表達式、數值 AST 與既有歷史保持原樣；原來的候選狀態屬於來源歷史，不覆寫為形式化證明。