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第 23054 題:高階導數

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  1. 原題與已知條件
  2. 定義與適用範圍
  3. 逐步推導
  4. 逐步反向核對
  5. 結論
  6. 本題覆核與來源綁定

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← 逐題詳解目錄 · 原題批次

R0045-23054 · q-20261014-advance-20261111-r02-higher-order-derivative-0029

原題與已知條件

f^(0)=f且f^(n+1)=(f^n)'的逐階存在與n in natural including zero。操作=higher-polynomial-nth-derivative;資料={"coefficients":[4,8,12,16,20,24,28],"order":3,"point":1}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。

  • G001 — f^(0)=f且f^(n+1)=(f^n)'的逐階存在與n in natural including zero。操作=higher-polynomial-nth-derivative;資料={"coefficients":[4,8,12,16,20,24,28],"order":3,"point":1}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。

定義與適用範圍

沿用原題明示的論域、假設與來源 MKO 定義。本題已完成第二對話數理與中英語義覆核,並由原始參數逐題獨立重算模型、答案與每個算術步驟;原題仍為 candidate。

逐步推導

S001 · implies

操作前

source operation=higher-polynomial-nth-derivative;original snapshot and mathematics retained

操作後

explicit ordered source output fields=[coefficients, order, derivative_coefficients, point, value, certificate]

條件:無

原題快照保留歷史介面;此處直接列來源欄序,不依賴JavaScript。tag與No保聲稱範圍,固定來源排序不冒充數學證明。

步驟識別與依賴

規則:source_ordered_interface_explicit_without_javascript · 依賴:G001

S002 · implies

操作前

ORIGINAL low-to-high coefficients=[4, 8, 12, 16, 20, 24, 28];declared order=3

操作後

declared degree BOUND=6=ORIGINAL length-1;initialize derivative order0 with the UNTRIMMED original list

條件:無

長度減1是宣告上界,trailing zeros不先刪掉;order0就是原函數。單項式導數規則與有限和給多項式逐階存在,不是任意函數的無限外推。

步驟識別與依賴

規則:higher_ORIGINAL_low_to_high_coefficients_degree_BOUND_order0 · 依賴:G001, S001

S003 · calculation

操作前

Higher derivative level1 ORIGINAL power1 coefficient product := mul(8, 1)

操作後

Higher derivative level1 ORIGINAL power1 coefficient product = 8

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S002

S004 · calculation

操作前

Higher derivative level1 ORIGINAL power2 coefficient product := mul(12, 2)

操作後

Higher derivative level1 ORIGINAL power2 coefficient product = 24

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S003

S005 · calculation

操作前

Higher derivative level1 ORIGINAL power3 coefficient product := mul(16, 3)

操作後

Higher derivative level1 ORIGINAL power3 coefficient product = 48

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S004

S006 · calculation

操作前

Higher derivative level1 ORIGINAL power4 coefficient product := mul(20, 4)

操作後

Higher derivative level1 ORIGINAL power4 coefficient product = 80

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S005

S007 · calculation

操作前

Higher derivative level1 ORIGINAL power5 coefficient product := mul(24, 5)

操作後

Higher derivative level1 ORIGINAL power5 coefficient product = 120

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S006

S008 · calculation

操作前

Higher derivative level1 ORIGINAL power6 coefficient product := mul(28, 6)

操作後

Higher derivative level1 ORIGINAL power6 coefficient product = 168

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S007

S009 · implies

操作前

previous derivative order=0;actual low-to-high list=[4, 8, 12, 16, 20, 24, 28];drop ONLY its constant term

操作後

ALL [old_power,old_coefficient,multiplier,new_coefficient] rows=[[1, 8, 1, 8], [2, 12, 2, 24], [3, 16, 3, 48], [4, 20, 4, 80], [5, 24, 5, 120], [6, 28, 6, 168]];next raw list=[8, 24, 48, 80, 120, 168];all intermediate products SAFE

條件:無

每一層把舊power k乘原係數,再按低到高放到power k−1;原raw list耗盡後維持空,最後才以[0]表示零導數。英文來源要求所有中間乘積安全,不只最後結果。

步驟識別與依賴

規則:higher_EVERY_recursive_derivative_level_not_reordered · 依賴:G001, S008

S010 · calculation

操作前

Higher derivative level2 ORIGINAL power1 coefficient product := mul(24, 1)

操作後

Higher derivative level2 ORIGINAL power1 coefficient product = 24

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S009

S011 · calculation

操作前

Higher derivative level2 ORIGINAL power2 coefficient product := mul(48, 2)

操作後

Higher derivative level2 ORIGINAL power2 coefficient product = 96

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S010

S012 · calculation

操作前

Higher derivative level2 ORIGINAL power3 coefficient product := mul(80, 3)

操作後

Higher derivative level2 ORIGINAL power3 coefficient product = 240

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S011

S013 · calculation

操作前

Higher derivative level2 ORIGINAL power4 coefficient product := mul(120, 4)

操作後

Higher derivative level2 ORIGINAL power4 coefficient product = 480

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S012

S014 · calculation

操作前

Higher derivative level2 ORIGINAL power5 coefficient product := mul(168, 5)

操作後

Higher derivative level2 ORIGINAL power5 coefficient product = 840

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S013

S015 · implies

操作前

previous derivative order=1;actual low-to-high list=[8, 24, 48, 80, 120, 168];drop ONLY its constant term

操作後

ALL [old_power,old_coefficient,multiplier,new_coefficient] rows=[[1, 24, 1, 24], [2, 48, 2, 96], [3, 80, 3, 240], [4, 120, 4, 480], [5, 168, 5, 840]];next raw list=[24, 96, 240, 480, 840];all intermediate products SAFE

條件:無

每一層把舊power k乘原係數,再按低到高放到power k−1;原raw list耗盡後維持空,最後才以[0]表示零導數。英文來源要求所有中間乘積安全,不只最後結果。

步驟識別與依賴

規則:higher_EVERY_recursive_derivative_level_not_reordered · 依賴:G001, S014

S016 · calculation

操作前

Higher derivative level3 ORIGINAL power1 coefficient product := mul(96, 1)

操作後

Higher derivative level3 ORIGINAL power1 coefficient product = 96

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S015

S017 · calculation

操作前

Higher derivative level3 ORIGINAL power2 coefficient product := mul(240, 2)

操作後

Higher derivative level3 ORIGINAL power2 coefficient product = 480

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S016

S018 · calculation

操作前

Higher derivative level3 ORIGINAL power3 coefficient product := mul(480, 3)

操作後

Higher derivative level3 ORIGINAL power3 coefficient product = 1440

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S017

S019 · calculation

操作前

Higher derivative level3 ORIGINAL power4 coefficient product := mul(840, 4)

操作後

Higher derivative level3 ORIGINAL power4 coefficient product = 3360

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S018

S020 · implies

操作前

previous derivative order=2;actual low-to-high list=[24, 96, 240, 480, 840];drop ONLY its constant term

操作後

ALL [old_power,old_coefficient,multiplier,new_coefficient] rows=[[1, 96, 1, 96], [2, 240, 2, 480], [3, 480, 3, 1440], [4, 840, 4, 3360]];next raw list=[96, 480, 1440, 3360];all intermediate products SAFE

條件:無

每一層把舊power k乘原係數,再按低到高放到power k−1;原raw list耗盡後維持空,最後才以[0]表示零導數。英文來源要求所有中間乘積安全,不只最後結果。

步驟識別與依賴

規則:higher_EVERY_recursive_derivative_level_not_reordered · 依賴:G001, S019

S021 · implies

操作前

ORIGINAL coefficients=[4, 8, 12, 16, 20, 24, 28];order=3;declared degree bound=6

操作後

final derivative coefficients=[96, 480, 1440, 3360];for each original power k>=order multiplier=k*(k-1)*...*(k-order+1);lower powers vanish

條件:無

反覆微分給falling factorial,與原係數序一致;order超過宣告bound時必為0。這不聲稱一般可微函數analytic,也不把trailing-zero上界冒充最小degree。

步驟識別與依賴

規則:higher_falling_factorial_rule_all_orders_polynomial_only · 依賴:G001, S020

S022 · calculation

操作前

Higher derivative Horner power3 previous value times ORIGINAL point := mul(0, 1)

操作後

Higher derivative Horner power3 previous value times ORIGINAL point = 0

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S021

S023 · calculation

操作前

Higher derivative Horner power3 plus ORIGINAL derivative coefficient := sum(0, 3360)

操作後

Higher derivative Horner power3 plus ORIGINAL derivative coefficient = 3360

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S022

S024 · calculation

操作前

Higher derivative Horner power2 previous value times ORIGINAL point := mul(3360, 1)

操作後

Higher derivative Horner power2 previous value times ORIGINAL point = 3360

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S023

S025 · calculation

操作前

Higher derivative Horner power2 plus ORIGINAL derivative coefficient := sum(3360, 1440)

操作後

Higher derivative Horner power2 plus ORIGINAL derivative coefficient = 4800

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S024

S026 · calculation

操作前

Higher derivative Horner power1 previous value times ORIGINAL point := mul(4800, 1)

操作後

Higher derivative Horner power1 previous value times ORIGINAL point = 4800

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S025

S027 · calculation

操作前

Higher derivative Horner power1 plus ORIGINAL derivative coefficient := sum(4800, 480)

操作後

Higher derivative Horner power1 plus ORIGINAL derivative coefficient = 5280

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S026

S028 · calculation

操作前

Higher derivative Horner power0 previous value times ORIGINAL point := mul(5280, 1)

操作後

Higher derivative Horner power0 previous value times ORIGINAL point = 5280

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S027

S029 · calculation

操作前

Higher derivative Horner power0 plus ORIGINAL derivative coefficient := sum(5280, 96)

操作後

Higher derivative Horner power0 plus ORIGINAL derivative coefficient = 5376

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S028

逐步反向核對

  • S029 · premise_and_result_audit — 以精確有理數重算 Higher derivative Horner power0 plus ORIGINAL derivative coefficient,不以小數近似替代。
  • S028 · premise_and_result_audit — 以精確有理數重算 Higher derivative Horner power0 previous value times ORIGINAL point,不以小數近似替代。
  • S027 · premise_and_result_audit — 以精確有理數重算 Higher derivative Horner power1 plus ORIGINAL derivative coefficient,不以小數近似替代。
  • S026 · premise_and_result_audit — 以精確有理數重算 Higher derivative Horner power1 previous value times ORIGINAL point,不以小數近似替代。
  • S025 · premise_and_result_audit — 以精確有理數重算 Higher derivative Horner power2 plus ORIGINAL derivative coefficient,不以小數近似替代。
  • S024 · premise_and_result_audit — 以精確有理數重算 Higher derivative Horner power2 previous value times ORIGINAL point,不以小數近似替代。
  • S023 · premise_and_result_audit — 以精確有理數重算 Higher derivative Horner power3 plus ORIGINAL derivative coefficient,不以小數近似替代。
  • S022 · premise_and_result_audit — 以精確有理數重算 Higher derivative Horner power3 previous value times ORIGINAL point,不以小數近似替代。
  • S021 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。
  • S020 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。
  • S019 · premise_and_result_audit — 以精確有理數重算 Higher derivative level3 ORIGINAL power4 coefficient product,不以小數近似替代。
  • S018 · premise_and_result_audit — 以精確有理數重算 Higher derivative level3 ORIGINAL power3 coefficient product,不以小數近似替代。
  • S017 · premise_and_result_audit — 以精確有理數重算 Higher derivative level3 ORIGINAL power2 coefficient product,不以小數近似替代。
  • S016 · premise_and_result_audit — 以精確有理數重算 Higher derivative level3 ORIGINAL power1 coefficient product,不以小數近似替代。
  • S015 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。
  • S014 · premise_and_result_audit — 以精確有理數重算 Higher derivative level2 ORIGINAL power5 coefficient product,不以小數近似替代。
  • S013 · premise_and_result_audit — 以精確有理數重算 Higher derivative level2 ORIGINAL power4 coefficient product,不以小數近似替代。
  • S012 · premise_and_result_audit — 以精確有理數重算 Higher derivative level2 ORIGINAL power3 coefficient product,不以小數近似替代。
  • S011 · premise_and_result_audit — 以精確有理數重算 Higher derivative level2 ORIGINAL power2 coefficient product,不以小數近似替代。
  • S010 · premise_and_result_audit — 以精確有理數重算 Higher derivative level2 ORIGINAL power1 coefficient product,不以小數近似替代。
  • S009 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。
  • S008 · premise_and_result_audit — 以精確有理數重算 Higher derivative level1 ORIGINAL power6 coefficient product,不以小數近似替代。
  • S007 · premise_and_result_audit — 以精確有理數重算 Higher derivative level1 ORIGINAL power5 coefficient product,不以小數近似替代。
  • S006 · premise_and_result_audit — 以精確有理數重算 Higher derivative level1 ORIGINAL power4 coefficient product,不以小數近似替代。
  • S005 · premise_and_result_audit — 以精確有理數重算 Higher derivative level1 ORIGINAL power3 coefficient product,不以小數近似替代。
  • S004 · premise_and_result_audit — 以精確有理數重算 Higher derivative level1 ORIGINAL power2 coefficient product,不以小數近似替代。
  • S003 · premise_and_result_audit — 以精確有理數重算 Higher derivative level1 ORIGINAL power1 coefficient product,不以小數近似替代。
  • S002 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。
  • S001 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。

結論

([4, 8, 12, 16, 20, 24, 28], 3, [96, 480, 1440, 3360], 1, 5376, falling_factorial_coefficients_exact)

依上列完整代值及條件核對得到原題答案;原題編號、格式與狀態保持不變。

本題覆核與來源綁定

覆核日期:2026-10-26

原題、答案、步驟表達式、數值 AST 與既有歷史保持原樣;原來的候選狀態屬於來源歷史,不覆寫為形式化證明。

來源雜湊與覆核憑證
  • input commit: 0f7be61e2c22317a4075561dc822c87d881a50db
  • original question SHA-256: 1a88bbad6961a1db8cf0aa0fea6bd05753090c55986ebac77e536a576b76c170
  • candidate record SHA-256: b9d39b0bf07069a76e3e0ab805fdde979866a78fb9c709324f7f79484b12dfe1
  • semantic review receipt SHA-256: 357d7ad7a6726b2a757558d3b9586a408ade06526cc023da093719c292704438
  • question-first witness SHA-256: 99cefe17e98c7a74321801cf72df6d02fc95b6a6b78aa335accb7e11ed467b2a
  • Lean: NOT_RUN · human review: NOT_PERFORMED
同源完整 JSON