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第 23087 題:高階導數

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  1. 原題與已知條件
  2. 定義與適用範圍
  3. 逐步推導
  4. 逐步反向核對
  5. 結論
  6. 本題覆核與來源綁定

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← 逐題詳解目錄 · 原題批次

R0045-23087 · q-20261014-advance-20261111-r02-higher-order-derivative-0062

原題與已知條件

f^(0)=f且f^(n+1)=(f^n)'的逐階存在與n in natural including zero。操作=higher-zero-beyond-degree;資料={"coefficients":[12,24,36,48,60,72,84],"order":9,"point":-1}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。

  • G001 — f^(0)=f且f^(n+1)=(f^n)'的逐階存在與n in natural including zero。操作=higher-zero-beyond-degree;資料={"coefficients":[12,24,36,48,60,72,84],"order":9,"point":-1}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。

定義與適用範圍

沿用原題明示的論域、假設與來源 MKO 定義。本題已完成第二對話數理與中英語義覆核,並由原始參數逐題獨立重算模型、答案與每個算術步驟;原題仍為 candidate。

逐步推導

S001 · implies

操作前

source operation=higher-zero-beyond-degree;original snapshot and mathematics retained

操作後

explicit ordered source output fields=[declared_degree_bound, order, derivative_coefficients, point, value, zero_derivative_certificate, certificate]

條件:無

原題快照保留歷史介面;此處直接列來源欄序,不依賴JavaScript。tag與No保聲稱範圍,固定來源排序不冒充數學證明。

步驟識別與依賴

規則:source_ordered_interface_explicit_without_javascript · 依賴:G001

S002 · implies

操作前

ORIGINAL low-to-high coefficients=[12, 24, 36, 48, 60, 72, 84];declared order=9

操作後

declared degree BOUND=6=ORIGINAL length-1;initialize derivative order0 with the UNTRIMMED original list

條件:無

長度減1是宣告上界,trailing zeros不先刪掉;order0就是原函數。單項式導數規則與有限和給多項式逐階存在,不是任意函數的無限外推。

步驟識別與依賴

規則:higher_ORIGINAL_low_to_high_coefficients_degree_BOUND_order0 · 依賴:G001, S001

S003 · calculation

操作前

Higher derivative level1 ORIGINAL power1 coefficient product := mul(24, 1)

操作後

Higher derivative level1 ORIGINAL power1 coefficient product = 24

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S002

S004 · calculation

操作前

Higher derivative level1 ORIGINAL power2 coefficient product := mul(36, 2)

操作後

Higher derivative level1 ORIGINAL power2 coefficient product = 72

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S003

S005 · calculation

操作前

Higher derivative level1 ORIGINAL power3 coefficient product := mul(48, 3)

操作後

Higher derivative level1 ORIGINAL power3 coefficient product = 144

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S004

S006 · calculation

操作前

Higher derivative level1 ORIGINAL power4 coefficient product := mul(60, 4)

操作後

Higher derivative level1 ORIGINAL power4 coefficient product = 240

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S005

S007 · calculation

操作前

Higher derivative level1 ORIGINAL power5 coefficient product := mul(72, 5)

操作後

Higher derivative level1 ORIGINAL power5 coefficient product = 360

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S006

S008 · calculation

操作前

Higher derivative level1 ORIGINAL power6 coefficient product := mul(84, 6)

操作後

Higher derivative level1 ORIGINAL power6 coefficient product = 504

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S007

S009 · implies

操作前

previous derivative order=0;actual low-to-high list=[12, 24, 36, 48, 60, 72, 84];drop ONLY its constant term

操作後

ALL [old_power,old_coefficient,multiplier,new_coefficient] rows=[[1, 24, 1, 24], [2, 36, 2, 72], [3, 48, 3, 144], [4, 60, 4, 240], [5, 72, 5, 360], [6, 84, 6, 504]];next raw list=[24, 72, 144, 240, 360, 504];all intermediate products SAFE

條件:無

每一層把舊power k乘原係數,再按低到高放到power k−1;原raw list耗盡後維持空,最後才以[0]表示零導數。英文來源要求所有中間乘積安全,不只最後結果。

步驟識別與依賴

規則:higher_EVERY_recursive_derivative_level_not_reordered · 依賴:G001, S008

S010 · calculation

操作前

Higher derivative level2 ORIGINAL power1 coefficient product := mul(72, 1)

操作後

Higher derivative level2 ORIGINAL power1 coefficient product = 72

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S009

S011 · calculation

操作前

Higher derivative level2 ORIGINAL power2 coefficient product := mul(144, 2)

操作後

Higher derivative level2 ORIGINAL power2 coefficient product = 288

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S010

S012 · calculation

操作前

Higher derivative level2 ORIGINAL power3 coefficient product := mul(240, 3)

操作後

Higher derivative level2 ORIGINAL power3 coefficient product = 720

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S011

S013 · calculation

操作前

Higher derivative level2 ORIGINAL power4 coefficient product := mul(360, 4)

操作後

Higher derivative level2 ORIGINAL power4 coefficient product = 1440

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S012

S014 · calculation

操作前

Higher derivative level2 ORIGINAL power5 coefficient product := mul(504, 5)

操作後

Higher derivative level2 ORIGINAL power5 coefficient product = 2520

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S013

S015 · implies

操作前

previous derivative order=1;actual low-to-high list=[24, 72, 144, 240, 360, 504];drop ONLY its constant term

操作後

ALL [old_power,old_coefficient,multiplier,new_coefficient] rows=[[1, 72, 1, 72], [2, 144, 2, 288], [3, 240, 3, 720], [4, 360, 4, 1440], [5, 504, 5, 2520]];next raw list=[72, 288, 720, 1440, 2520];all intermediate products SAFE

條件:無

每一層把舊power k乘原係數,再按低到高放到power k−1;原raw list耗盡後維持空,最後才以[0]表示零導數。英文來源要求所有中間乘積安全,不只最後結果。

步驟識別與依賴

規則:higher_EVERY_recursive_derivative_level_not_reordered · 依賴:G001, S014

S016 · calculation

操作前

Higher derivative level3 ORIGINAL power1 coefficient product := mul(288, 1)

操作後

Higher derivative level3 ORIGINAL power1 coefficient product = 288

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S015

S017 · calculation

操作前

Higher derivative level3 ORIGINAL power2 coefficient product := mul(720, 2)

操作後

Higher derivative level3 ORIGINAL power2 coefficient product = 1440

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S016

S018 · calculation

操作前

Higher derivative level3 ORIGINAL power3 coefficient product := mul(1440, 3)

操作後

Higher derivative level3 ORIGINAL power3 coefficient product = 4320

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S017

S019 · calculation

操作前

Higher derivative level3 ORIGINAL power4 coefficient product := mul(2520, 4)

操作後

Higher derivative level3 ORIGINAL power4 coefficient product = 10080

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S018

S020 · implies

操作前

previous derivative order=2;actual low-to-high list=[72, 288, 720, 1440, 2520];drop ONLY its constant term

操作後

ALL [old_power,old_coefficient,multiplier,new_coefficient] rows=[[1, 288, 1, 288], [2, 720, 2, 1440], [3, 1440, 3, 4320], [4, 2520, 4, 10080]];next raw list=[288, 1440, 4320, 10080];all intermediate products SAFE

條件:無

每一層把舊power k乘原係數,再按低到高放到power k−1;原raw list耗盡後維持空,最後才以[0]表示零導數。英文來源要求所有中間乘積安全,不只最後結果。

步驟識別與依賴

規則:higher_EVERY_recursive_derivative_level_not_reordered · 依賴:G001, S019

S021 · calculation

操作前

Higher derivative level4 ORIGINAL power1 coefficient product := mul(1440, 1)

操作後

Higher derivative level4 ORIGINAL power1 coefficient product = 1440

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S020

S022 · calculation

操作前

Higher derivative level4 ORIGINAL power2 coefficient product := mul(4320, 2)

操作後

Higher derivative level4 ORIGINAL power2 coefficient product = 8640

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S021

S023 · calculation

操作前

Higher derivative level4 ORIGINAL power3 coefficient product := mul(10080, 3)

操作後

Higher derivative level4 ORIGINAL power3 coefficient product = 30240

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S022

S024 · implies

操作前

previous derivative order=3;actual low-to-high list=[288, 1440, 4320, 10080];drop ONLY its constant term

操作後

ALL [old_power,old_coefficient,multiplier,new_coefficient] rows=[[1, 1440, 1, 1440], [2, 4320, 2, 8640], [3, 10080, 3, 30240]];next raw list=[1440, 8640, 30240];all intermediate products SAFE

條件:無

每一層把舊power k乘原係數,再按低到高放到power k−1;原raw list耗盡後維持空,最後才以[0]表示零導數。英文來源要求所有中間乘積安全,不只最後結果。

步驟識別與依賴

規則:higher_EVERY_recursive_derivative_level_not_reordered · 依賴:G001, S023

S025 · calculation

操作前

Higher derivative level5 ORIGINAL power1 coefficient product := mul(8640, 1)

操作後

Higher derivative level5 ORIGINAL power1 coefficient product = 8640

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S024

S026 · calculation

操作前

Higher derivative level5 ORIGINAL power2 coefficient product := mul(30240, 2)

操作後

Higher derivative level5 ORIGINAL power2 coefficient product = 60480

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S025

S027 · implies

操作前

previous derivative order=4;actual low-to-high list=[1440, 8640, 30240];drop ONLY its constant term

操作後

ALL [old_power,old_coefficient,multiplier,new_coefficient] rows=[[1, 8640, 1, 8640], [2, 30240, 2, 60480]];next raw list=[8640, 60480];all intermediate products SAFE

條件:無

每一層把舊power k乘原係數,再按低到高放到power k−1;原raw list耗盡後維持空,最後才以[0]表示零導數。英文來源要求所有中間乘積安全,不只最後結果。

步驟識別與依賴

規則:higher_EVERY_recursive_derivative_level_not_reordered · 依賴:G001, S026

S028 · calculation

操作前

Higher derivative level6 ORIGINAL power1 coefficient product := mul(60480, 1)

操作後

Higher derivative level6 ORIGINAL power1 coefficient product = 60480

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S027

S029 · implies

操作前

previous derivative order=5;actual low-to-high list=[8640, 60480];drop ONLY its constant term

操作後

ALL [old_power,old_coefficient,multiplier,new_coefficient] rows=[[1, 60480, 1, 60480]];next raw list=[60480];all intermediate products SAFE

條件:無

每一層把舊power k乘原係數,再按低到高放到power k−1;原raw list耗盡後維持空,最後才以[0]表示零導數。英文來源要求所有中間乘積安全,不只最後結果。

步驟識別與依賴

規則:higher_EVERY_recursive_derivative_level_not_reordered · 依賴:G001, S028

S030 · implies

操作前

previous derivative order=6;actual low-to-high list=[60480];drop ONLY its constant term

操作後

ALL [old_power,old_coefficient,multiplier,new_coefficient] rows=[];next raw list=[];all intermediate products SAFE

條件:無

每一層把舊power k乘原係數,再按低到高放到power k−1;原raw list耗盡後維持空,最後才以[0]表示零導數。英文來源要求所有中間乘積安全,不只最後結果。

步驟識別與依賴

規則:higher_EVERY_recursive_derivative_level_not_reordered · 依賴:G001, S029

S031 · implies

操作前

previous derivative order=7;actual low-to-high list=[];drop ONLY its constant term

操作後

ALL [old_power,old_coefficient,multiplier,new_coefficient] rows=[];next raw list=[];all intermediate products SAFE

條件:無

每一層把舊power k乘原係數,再按低到高放到power k−1;原raw list耗盡後維持空,最後才以[0]表示零導數。英文來源要求所有中間乘積安全,不只最後結果。

步驟識別與依賴

規則:higher_EVERY_recursive_derivative_level_not_reordered · 依賴:G001, S030

S032 · implies

操作前

previous derivative order=8;actual low-to-high list=[];drop ONLY its constant term

操作後

ALL [old_power,old_coefficient,multiplier,new_coefficient] rows=[];next raw list=[];all intermediate products SAFE

條件:無

每一層把舊power k乘原係數,再按低到高放到power k−1;原raw list耗盡後維持空,最後才以[0]表示零導數。英文來源要求所有中間乘積安全,不只最後結果。

步驟識別與依賴

規則:higher_EVERY_recursive_derivative_level_not_reordered · 依賴:G001, S031

S033 · implies

操作前

ORIGINAL coefficients=[12, 24, 36, 48, 60, 72, 84];order=9;declared degree bound=6

操作後

final derivative coefficients=[0];for each original power k>=order multiplier=k*(k-1)*...*(k-order+1);lower powers vanish

條件:無

反覆微分給falling factorial,與原係數序一致;order超過宣告bound時必為0。這不聲稱一般可微函數analytic,也不把trailing-zero上界冒充最小degree。

步驟識別與依賴

規則:higher_falling_factorial_rule_all_orders_polynomial_only · 依賴:G001, S032

S034 · calculation

操作前

Higher derivative Horner power0 previous value times ORIGINAL point := mul(0, -1)

操作後

Higher derivative Horner power0 previous value times ORIGINAL point = 0

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S033

S035 · calculation

操作前

Higher derivative Horner power0 plus ORIGINAL derivative coefficient := sum(0, 0)

操作後

Higher derivative Horner power0 plus ORIGINAL derivative coefficient = 0

條件:無

依本題原始角色、次序與已核中間量精確代值,不用浮點近似或另一題的資料。

步驟識別與依賴

規則:exact_rational_arithmetic · 依賴:G001, S034

逐步反向核對

  • S035 · premise_and_result_audit — 以精確有理數重算 Higher derivative Horner power0 plus ORIGINAL derivative coefficient,不以小數近似替代。
  • S034 · premise_and_result_audit — 以精確有理數重算 Higher derivative Horner power0 previous value times ORIGINAL point,不以小數近似替代。
  • S033 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。
  • S032 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。
  • S031 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。
  • S030 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。
  • S029 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。
  • S028 · premise_and_result_audit — 以精確有理數重算 Higher derivative level6 ORIGINAL power1 coefficient product,不以小數近似替代。
  • S027 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。
  • S026 · premise_and_result_audit — 以精確有理數重算 Higher derivative level5 ORIGINAL power2 coefficient product,不以小數近似替代。
  • S025 · premise_and_result_audit — 以精確有理數重算 Higher derivative level5 ORIGINAL power1 coefficient product,不以小數近似替代。
  • S024 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。
  • S023 · premise_and_result_audit — 以精確有理數重算 Higher derivative level4 ORIGINAL power3 coefficient product,不以小數近似替代。
  • S022 · premise_and_result_audit — 以精確有理數重算 Higher derivative level4 ORIGINAL power2 coefficient product,不以小數近似替代。
  • S021 · premise_and_result_audit — 以精確有理數重算 Higher derivative level4 ORIGINAL power1 coefficient product,不以小數近似替代。
  • S020 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。
  • S019 · premise_and_result_audit — 以精確有理數重算 Higher derivative level3 ORIGINAL power4 coefficient product,不以小數近似替代。
  • S018 · premise_and_result_audit — 以精確有理數重算 Higher derivative level3 ORIGINAL power3 coefficient product,不以小數近似替代。
  • S017 · premise_and_result_audit — 以精確有理數重算 Higher derivative level3 ORIGINAL power2 coefficient product,不以小數近似替代。
  • S016 · premise_and_result_audit — 以精確有理數重算 Higher derivative level3 ORIGINAL power1 coefficient product,不以小數近似替代。
  • S015 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。
  • S014 · premise_and_result_audit — 以精確有理數重算 Higher derivative level2 ORIGINAL power5 coefficient product,不以小數近似替代。
  • S013 · premise_and_result_audit — 以精確有理數重算 Higher derivative level2 ORIGINAL power4 coefficient product,不以小數近似替代。
  • S012 · premise_and_result_audit — 以精確有理數重算 Higher derivative level2 ORIGINAL power3 coefficient product,不以小數近似替代。
  • S011 · premise_and_result_audit — 以精確有理數重算 Higher derivative level2 ORIGINAL power2 coefficient product,不以小數近似替代。
  • S010 · premise_and_result_audit — 以精確有理數重算 Higher derivative level2 ORIGINAL power1 coefficient product,不以小數近似替代。
  • S009 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。
  • S008 · premise_and_result_audit — 以精確有理數重算 Higher derivative level1 ORIGINAL power6 coefficient product,不以小數近似替代。
  • S007 · premise_and_result_audit — 以精確有理數重算 Higher derivative level1 ORIGINAL power5 coefficient product,不以小數近似替代。
  • S006 · premise_and_result_audit — 以精確有理數重算 Higher derivative level1 ORIGINAL power4 coefficient product,不以小數近似替代。
  • S005 · premise_and_result_audit — 以精確有理數重算 Higher derivative level1 ORIGINAL power3 coefficient product,不以小數近似替代。
  • S004 · premise_and_result_audit — 以精確有理數重算 Higher derivative level1 ORIGINAL power2 coefficient product,不以小數近似替代。
  • S003 · premise_and_result_audit — 以精確有理數重算 Higher derivative level1 ORIGINAL power1 coefficient product,不以小數近似替代。
  • S002 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。
  • S001 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。

結論

(6, 9, [0], -1, 0, 是, orders_above_polynomial_degree_are_zero_without_analyticity_claim)

依上列完整代值及條件核對得到原題答案;原題編號、格式與狀態保持不變。

本題覆核與來源綁定

覆核日期:2026-10-26

原題、答案、步驟表達式、數值 AST 與既有歷史保持原樣;原來的候選狀態屬於來源歷史,不覆寫為形式化證明。

來源雜湊與覆核憑證
  • input commit: 0f7be61e2c22317a4075561dc822c87d881a50db
  • original question SHA-256: b677432ba139740c54d0588306ee6509dac6425c8dbf986177d289975a369db3
  • candidate record SHA-256: 425c8aad28c2f8fc1d48738fa2cc21cec2771d02155b962663e989f448aa1426
  • semantic review receipt SHA-256: 357d7ad7a6726b2a757558d3b9586a408ade06526cc023da093719c292704438
  • question-first witness SHA-256: 99cefe17e98c7a74321801cf72df6d02fc95b6a6b78aa335accb7e11ed467b2a
  • Lean: NOT_RUN · human review: NOT_PERFORMED
同源完整 JSON