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第 23597 題:Hausdorff空間中的緊緻集為閉集

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  1. 原題與已知條件
  2. 定義與適用範圍
  3. 逐步推導
  4. 逐步反向核對
  5. 結論
  6. 本題覆核與來源綁定

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← 逐題詳解目錄 · 原題批次

R0046-23597 · q-20261014-advance-20261112-r03-compact-subset-closed-in-hausdorff-0097

原題與已知條件

ambient Hausdorff與compact subset的分離-有限subcover責任。操作=compactclosed-nonhausdorff-boundary;資料={"points":["o21","u21"],"topology":[["o21","u21"],["u21"],[]],"compact_subset":["u21"]}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。

  • G001 — ambient Hausdorff與compact subset的分離-有限subcover責任。操作=compactclosed-nonhausdorff-boundary;資料={"points":["o21","u21"],"topology":[["o21","u21"],["u21"],[]],"compact_subset":["u21"]}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。

定義與適用範圍

沿用原題明示的論域、假設與來源 MKO 定義。本題已完成第二對話數理與中英語義覆核,並由原始參數逐題獨立重算模型、答案與每個算術步驟;原題仍為 candidate。

逐步推導

S001 · implies

操作前

source operation=compactclosed-nonhausdorff-boundary;original snapshot and mathematics retained

操作後

explicit ordered source output fields=[points, compact_subset, complement, Hausdorff, compact, closed, boundary]

條件:無

保留原題介面快照,本頁直接列來源欄序,不需JavaScript。radius由原mode選6/11欄,不補欄;No與實際否定依來源責任分清。

步驟識別與依賴

規則:source_ordered_interface_explicit_without_javascript · 依賴:G001

S002 · implies

操作前

ORIGINAL carrier order=[o21, u21];ORIGINAL open-list order=[[o21, u21], [u21], []];point=o21;ALL given sets containing it have indices=[0]

操作後

candidate N(o21)=intersection of ALL those sets=[o21, u21];no original open-list reordering

條件:無

先由全部給定鄰域求交集候選,不先假設族已是拓撲;source保原open清單次序,內部元素才按UTF16排序。

步驟識別與依賴

規則:compactclosed_ALL_given_neighborhood_intersection_candidates · 依賴:G001, S001

S003 · implies

操作前

ORIGINAL carrier order=[o21, u21];ORIGINAL open-list order=[[o21, u21], [u21], []];point=u21;ALL given sets containing it have indices=[0, 1]

操作後

candidate N(u21)=intersection of ALL those sets=[u21];no original open-list reordering

條件:無

先由全部給定鄰域求交集候選,不先假設族已是拓撲;source保原open清單次序,內部元素才按UTF16排序。

步驟識別與依賴

規則:compactclosed_ALL_given_neighborhood_intersection_candidates · 依賴:G001, S002

S004 · implies

操作前

ORIGINAL ordered open masks=[3, 2, 0];ALL neighborhood-containment [x,y,N(y)_subset_N(x)] rows=[[o21, o21, 是], [o21, u21, 是], [u21, u21, 是]]

操作後

ALL carrier masks0..3 audited;EXACT qualifying U with every x in U having N(x) subset U=[0, 2, 3];given family equals this COMPLETE upset family

條件:無

有限拓撲的open恰是其最小鄰域的upsets;反向逐全部carrier子集合比對後,upsets在任意union及有限intersection下封閉,含空/全,故得到真正拓撲與N(x) open。這涵蓋全部open-pair責任,不只列取樣,也不必打印數百萬pairs。

步驟識別與依賴

規則:compactclosed_ALL_carrier_subsets_exact_neighborhood_upsets_topology · 依賴:G001, S003

S005 · implies

操作前

Compact-closed ORIGINAL pair index0-1:ORIGINAL distinct x=o21,y=u21;N(y)=[u21];open-list order=[[o21, u21], [u21], []]

操作後

ALL tested [U_index,U_intersect_N(y),disjoint_V_possible] rows=[[0, [u21], 否]];for FIRST possible U,ALL tested [V_index,intersection,disjoint] rows=[];FIRST ORIGINAL witness=null

條件:無

若U交N(y)非空,所有含y的open都含N(y),故不可能與U不交;若為空,N(y)本身是可用open,再按原V順序找首個。這與完整原U/V搜尋同一首見證,不是另選較小鄰域代答案。

步驟識別與依賴

規則:compactclosed_FIRST_original_separator_with_complete_neighborhood_screen · 依賴:G001, S004

S006 · implies

操作前

ORIGINAL points=[o21, u21];ALL original-index distinct-pair witnesses=[[o21, u21, null]];actual K=[u21]

操作後

Hausdorff=否;K compact=是 by finiteness:from ANY cover choose one member per K point;empty K needs no members;ambient complement=[o21],closed=否

條件:無

有限K的compact性不替代母空間Hausdorff責任;pair空域vacuous True。Closed查同一母空間的補集open,不擅自取相對補集。

步驟識別與依賴

規則:compactclosed_ALL_pairs_Hausdorff_and_finite_subset_compact_separate · 依賴:G001, S005

逐步反向核對

  • S006 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。
  • S005 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。
  • S004 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。
  • S003 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。
  • S002 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。
  • S001 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。

結論

([o21, u21], [u21], [o21], 否, 是, 否, Sierpinski_type_space_shows_Hausdorff_hypothesis_cannot_be_removed_and_converse_is_not_claimed)

依上列完整代值及條件核對得到原題答案;原題編號、格式與狀態保持不變。

本題覆核與來源綁定

覆核日期:2026-10-26

原題、答案、步驟表達式、數值 AST 與既有歷史保持原樣;原來的候選狀態屬於來源歷史,不覆寫為形式化證明。

來源雜湊與覆核憑證
  • input commit: 0f7be61e2c22317a4075561dc822c87d881a50db
  • original question SHA-256: 4dab81235876c89b92a3146acb74a76e0f4c1ab396d97b97740c6f3284b021e5
  • candidate record SHA-256: b93b660a1bd96b8ff0d1a93598216603877105a6acb53c06a35e4e43665d1466
  • semantic review receipt SHA-256: a7c0d888ade6d307703c4222c4137c78c0d2448babdcba2fa3446fe6fdd343c1
  • question-first witness SHA-256: c9571f97a37d503ad6a61034cc00108543a05c37ef246d1c4962f55136a3de02
  • Lean: NOT_RUN · human review: NOT_PERFORMED
同源完整 JSON