S001 · implies
操作前
source roles = [normal-conjugate-set-audit]
操作後
derived = [[subgroup, conjugate_rows, normal, certificate]]
條件:無
直接列來源完整欄序,不需JavaScript;原題、布林旗標、數學物件與非聲稱保持分層。
步驟識別與依賴
規則:source_ordered_fields_without_JS · 依賴:G001
R0048-24524 · q-20261015-advance-20261113-r01-finite-normal-subgroup-0049
完整Cayley table、完整subgroup資格與forall g的normality責任。操作=normal-conjugate-set-audit;資料={"group_table":[[6,7,8,9,0,1,2,3,4,5],[7,8,9,0,1,2,3,4,5,6],[8,9,0,1,2,3,4,5,6,7],[9,0,1,2,3,4,5,6,7,8],[0,1,2,3,4,5,6,7,8,9],[1,2,3,4,5,6,7,8,9,0],[2,3,4,5,6,7,8,9,0,1],[3,4,5,6,7,8,9,0,1,2],[4,5,6,7,8,9,0,1,2,3],[5,6,7,8,9,0,1,2,3,4]],"identity":4,"subset":[0,1,2,3,4,5,6,7,8,9]}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。
G001 — 完整Cayley table、完整subgroup資格與forall g的normality責任。操作=normal-conjugate-set-audit;資料={"group_table":[[6,7,8,9,0,1,2,3,4,5],[7,8,9,0,1,2,3,4,5,6],[8,9,0,1,2,3,4,5,6,7],[9,0,1,2,3,4,5,6,7,8],[0,1,2,3,4,5,6,7,8,9],[1,2,3,4,5,6,7,8,9,0],[2,3,4,5,6,7,8,9,0,1],[3,4,5,6,7,8,9,0,1,2],[4,5,6,7,8,9,0,1,2,3],[5,6,7,8,9,0,1,2,3,4]],"identity":4,"subset":[0,1,2,3,4,5,6,7,8,9]}。請依 exact_ordered_tuple_declared_by_interface 欄序回答。沿用原題明示的論域、假設與來源 MKO 定義。本題已完成第二對話數理與中英語義覆核,並由原始參數逐題獨立重算模型、答案與每個算術步驟;原題仍為 candidate。
操作前
source roles = [normal-conjugate-set-audit]
操作後
derived = [[subgroup, conjugate_rows, normal, certificate]]
條件:無
直接列來源完整欄序,不需JavaScript;原題、布林旗標、數學物件與非聲稱保持分層。
規則:source_ordered_fields_without_JS · 依賴:G001
操作前
source roles = [Normality ORIGINAL group, 32, [[6, 7, 8, 9, 0, 1, 2, 3, 4, 5], [7, 8, 9, 0, 1, 2, 3, 4, 5, 6], [8, 9, 0, 1, 2, 3, 4, 5, 6, 7], [9, 0, 1, 2, 3, 4, 5, 6, 7, 8], [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], [1, 2, 3, 4, 5, 6, 7, 8, 9, 0], [2, 3, 4, 5, 6, 7, 8, 9, 0, 1], [3, 4, 5, 6, 7, 8, 9, 0, 1, 2], [4, 5, 6, 7, 8, 9, 0, 1, 2, 3], [5, 6, 7, 8, 9, 0, 1, 2, 3, 4]], 4]
操作後
derived = [10, [[0, 0, 0, 0], [1, 1, 1, 1], [2, 2, 2, 2], [3, 3, 3, 3], [4, 4, 4, 4], [5, 5, 5, 5], [6, 6, 6, 6], [7, 7, 7, 7], [8, 8, 8, 8], [9, 9, 9, 9]], 是]
條件:無
先驗完整n×n閉合表與實際identity標籤,非預設0。mod44上限32,mod45上限64;同一carrier不能混入另一表。
規則:Group_complete_Cayley_signature_actual_identity · 依賴:G001, S001
操作前
source roles = [Normality ORIGINAL group, 10, FOR EVERY x,y,z in0..n-1]
操作後
derived = [[[是, 是, 是, 是, 是, 是, 是, 是, 是, 是], [是, 是, 是, 是, 是, 是, 是, 是, 是, 是], [是, 是, 是, 是, 是, 是, 是, 是, 是, 是], [是, 是, 是, 是, 是, 是, 是, 是, 是, 是], [是, 是, 是, 是, 是, 是, 是, 是, 是, 是], [是, 是, 是, 是, 是, 是, 是, 是, 是, 是], [是, 是, 是, 是, 是, 是, 是, 是, 是, 是], [是, 是, 是, 是, 是, 是, 是, 是, 是, 是], [是, 是, 是, 是, 是, 是, 是, 是, 是, 是], [是, 是, 是, 是, 是, 是, 是, 是, 是, 是]], 1000, 是]
條件:無
矩陣(x,y)逐全部z核(xy)z=x(yz),故涵蓋全部n³三元組,不是抽樣。表已在前步完整列出,不重印數百萬同義查表項。
規則:Group_ALL_associativity_triples_compact_complete_pair_matrix · 依賴:G001, S002
操作前
source roles = [Normality ORIGINAL group, 4]
操作後
derived = [[8, 7, 6, 5, 4, 3, 2, 1, 0, 9], [[0, 8, 4, 4], [1, 7, 4, 4], [2, 6, 4, 4], [3, 5, 4, 4], [4, 4, 4, 4], [5, 3, 4, 4], [6, 2, 4, 4], [7, 1, 4, 4], [8, 0, 4, 4], [9, 9, 4, 4]], 是]
條件:無
每個元素的左、右逆都要回到同一實際identity;結合律使兩側逆唯一。這才完成群前提。
規則:Group_ALL_two_sided_inverses · 依賴:G001, S003
操作前
source roles = [Normality ORIGINAL H, [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], 4]
操作後
derived = [是, [[0, 0, 6, 是], [0, 1, 7, 是], [0, 2, 8, 是], [0, 3, 9, 是], [0, 4, 0, 是], [0, 5, 1, 是], [0, 6, 2, 是], [0, 7, 3, 是], [0, 8, 4, 是], [0, 9, 5, 是], [1, 0, 7, 是], [1, 1, 8, 是], [1, 2, 9, 是], [1, 3, 0, 是], [1, 4, 1, 是], [1, 5, 2, 是], [1, 6, 3, 是], [1, 7, 4, 是], [1, 8, 5, 是], [1, 9, 6, 是], [2, 0, 8, 是], [2, 1, 9, 是], [2, 2, 0, 是], [2, 3, 1, 是], [2, 4, 2, 是], [2, 5, 3, 是], [2, 6, 4, 是], [2, 7, 5, 是], [2, 8, 6, 是], [2, 9, 7, 是], [3, 0, 9, 是], [3, 1, 0, 是], [3, 2, 1, 是], [3, 3, 2, 是], [3, 4, 3, 是], [3, 5, 4, 是], [3, 6, 5, 是], [3, 7, 6, 是], [3, 8, 7, 是], [3, 9, 8, 是], [4, 0, 0, 是], [4, 1, 1, 是], [4, 2, 2, 是], [4, 3, 3, 是], [4, 4, 4, 是], [4, 5, 5, 是], [4, 6, 6, 是], [4, 7, 7, 是], [4, 8, 8, 是], [4, 9, 9, 是], [5, 0, 1, 是], [5, 1, 2, 是], [5, 2, 3, 是], [5, 3, 4, 是], [5, 4, 5, 是], [5, 5, 6, 是], [5, 6, 7, 是], [5, 7, 8, 是], [5, 8, 9, 是], [5, 9, 0, 是], [6, 0, 2, 是], [6, 1, 3, 是], [6, 2, 4, 是], [6, 3, 5, 是], [6, 4, 6, 是], [6, 5, 7, 是], [6, 6, 8, 是], [6, 7, 9, 是], [6, 8, 0, 是], [6, 9, 1, 是], [7, 0, 3, 是], [7, 1, 4, 是], [7, 2, 5, 是], [7, 3, 6, 是], [7, 4, 7, 是], [7, 5, 8, 是], [7, 6, 9, 是], [7, 7, 0, 是], [7, 8, 1, 是], [7, 9, 2, 是], [8, 0, 4, 是], [8, 1, 5, 是], [8, 2, 6, 是], [8, 3, 7, 是], [8, 4, 8, 是], [8, 5, 9, 是], [8, 6, 0, 是], [8, 7, 1, 是], [8, 8, 2, 是], [8, 9, 3, 是], [9, 0, 5, 是], [9, 1, 6, 是], [9, 2, 7, 是], [9, 3, 8, 是], [9, 4, 9, 是], [9, 5, 0, 是], [9, 6, 1, 是], [9, 7, 2, 是], [9, 8, 3, 是], [9, 9, 4, 是]], 是, [[0, 8, 是], [1, 7, 是], [2, 6, 是], [3, 5, 是], [4, 4, 是], [5, 3, 是], [6, 2, 是], [7, 1, 是], [8, 0, 是], [9, 9, 是]], 是, 是]
條件:無
H非空且無重複;含identity、任兩元素乘積、每個逆元分別核全域,三者合取才可稱subgroup。order divisibility或有限性不足。
規則:Subgroup_identity_ALL_products_ALL_inverses_separate · 依賴:G001, S004
操作前
source roles = [Normality ORIGINAL H, 0, [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], 8]
操作後
derived = [[[0, 6, 8, 0], [1, 7, 8, 1], [2, 8, 8, 2], [3, 9, 8, 3], [4, 0, 8, 4], [5, 1, 8, 5], [6, 2, 8, 6], [7, 3, 8, 7], [8, 4, 8, 8], [9, 5, 8, 9]], [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], 是]
條件:無
按同一表先乘g*h,再乘g的右逆,遍歷全部h;再對全部g核集合等式,不由取樣或生成元猜normal。
規則:Subgroup_EVERY_g_entire_conjugate_set · 依賴:G001, S005
操作前
source roles = [Normality ORIGINAL H, 1, [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], 7]
操作後
derived = [[[0, 7, 7, 0], [1, 8, 7, 1], [2, 9, 7, 2], [3, 0, 7, 3], [4, 1, 7, 4], [5, 2, 7, 5], [6, 3, 7, 6], [7, 4, 7, 7], [8, 5, 7, 8], [9, 6, 7, 9]], [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], 是]
條件:無
按同一表先乘g*h,再乘g的右逆,遍歷全部h;再對全部g核集合等式,不由取樣或生成元猜normal。
規則:Subgroup_EVERY_g_entire_conjugate_set · 依賴:G001, S006
操作前
source roles = [Normality ORIGINAL H, 2, [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], 6]
操作後
derived = [[[0, 8, 6, 0], [1, 9, 6, 1], [2, 0, 6, 2], [3, 1, 6, 3], [4, 2, 6, 4], [5, 3, 6, 5], [6, 4, 6, 6], [7, 5, 6, 7], [8, 6, 6, 8], [9, 7, 6, 9]], [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], 是]
條件:無
按同一表先乘g*h,再乘g的右逆,遍歷全部h;再對全部g核集合等式,不由取樣或生成元猜normal。
規則:Subgroup_EVERY_g_entire_conjugate_set · 依賴:G001, S007
操作前
source roles = [Normality ORIGINAL H, 3, [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], 5]
操作後
derived = [[[0, 9, 5, 0], [1, 0, 5, 1], [2, 1, 5, 2], [3, 2, 5, 3], [4, 3, 5, 4], [5, 4, 5, 5], [6, 5, 5, 6], [7, 6, 5, 7], [8, 7, 5, 8], [9, 8, 5, 9]], [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], 是]
條件:無
按同一表先乘g*h,再乘g的右逆,遍歷全部h;再對全部g核集合等式,不由取樣或生成元猜normal。
規則:Subgroup_EVERY_g_entire_conjugate_set · 依賴:G001, S008
操作前
source roles = [Normality ORIGINAL H, 4, [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], 4]
操作後
derived = [[[0, 0, 4, 0], [1, 1, 4, 1], [2, 2, 4, 2], [3, 3, 4, 3], [4, 4, 4, 4], [5, 5, 4, 5], [6, 6, 4, 6], [7, 7, 4, 7], [8, 8, 4, 8], [9, 9, 4, 9]], [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], 是]
條件:無
按同一表先乘g*h,再乘g的右逆,遍歷全部h;再對全部g核集合等式,不由取樣或生成元猜normal。
規則:Subgroup_EVERY_g_entire_conjugate_set · 依賴:G001, S009
操作前
source roles = [Normality ORIGINAL H, 5, [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], 3]
操作後
derived = [[[0, 1, 3, 0], [1, 2, 3, 1], [2, 3, 3, 2], [3, 4, 3, 3], [4, 5, 3, 4], [5, 6, 3, 5], [6, 7, 3, 6], [7, 8, 3, 7], [8, 9, 3, 8], [9, 0, 3, 9]], [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], 是]
條件:無
按同一表先乘g*h,再乘g的右逆,遍歷全部h;再對全部g核集合等式,不由取樣或生成元猜normal。
規則:Subgroup_EVERY_g_entire_conjugate_set · 依賴:G001, S010
操作前
source roles = [Normality ORIGINAL H, 6, [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], 2]
操作後
derived = [[[0, 2, 2, 0], [1, 3, 2, 1], [2, 4, 2, 2], [3, 5, 2, 3], [4, 6, 2, 4], [5, 7, 2, 5], [6, 8, 2, 6], [7, 9, 2, 7], [8, 0, 2, 8], [9, 1, 2, 9]], [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], 是]
條件:無
按同一表先乘g*h,再乘g的右逆,遍歷全部h;再對全部g核集合等式,不由取樣或生成元猜normal。
規則:Subgroup_EVERY_g_entire_conjugate_set · 依賴:G001, S011
操作前
source roles = [Normality ORIGINAL H, 7, [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], 1]
操作後
derived = [[[0, 3, 1, 0], [1, 4, 1, 1], [2, 5, 1, 2], [3, 6, 1, 3], [4, 7, 1, 4], [5, 8, 1, 5], [6, 9, 1, 6], [7, 0, 1, 7], [8, 1, 1, 8], [9, 2, 1, 9]], [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], 是]
條件:無
按同一表先乘g*h,再乘g的右逆,遍歷全部h;再對全部g核集合等式,不由取樣或生成元猜normal。
規則:Subgroup_EVERY_g_entire_conjugate_set · 依賴:G001, S012
操作前
source roles = [Normality ORIGINAL H, 8, [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], 0]
操作後
derived = [[[0, 4, 0, 0], [1, 5, 0, 1], [2, 6, 0, 2], [3, 7, 0, 3], [4, 8, 0, 4], [5, 9, 0, 5], [6, 0, 0, 6], [7, 1, 0, 7], [8, 2, 0, 8], [9, 3, 0, 9]], [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], 是]
條件:無
按同一表先乘g*h,再乘g的右逆,遍歷全部h;再對全部g核集合等式,不由取樣或生成元猜normal。
規則:Subgroup_EVERY_g_entire_conjugate_set · 依賴:G001, S013
操作前
source roles = [Normality ORIGINAL H, 9, [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], 9]
操作後
derived = [[[0, 5, 9, 0], [1, 6, 9, 1], [2, 7, 9, 2], [3, 8, 9, 3], [4, 9, 9, 4], [5, 0, 9, 5], [6, 1, 9, 6], [7, 2, 9, 7], [8, 3, 9, 8], [9, 4, 9, 9]], [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], 是]
條件:無
按同一表先乘g*h,再乘g的右逆,遍歷全部h;再對全部g核集合等式,不由取樣或生成元猜normal。
規則:Subgroup_EVERY_g_entire_conjugate_set · 依賴:G001, S014
S015 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。S014 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。S013 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。S012 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。S011 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。S010 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。S009 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。S008 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。S007 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。S006 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。S005 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。S004 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。S003 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。S002 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。S001 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。([0, 1, 2, 3, 4, 5, 6, 7, 8, 9], [[0, [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], 是], [1, [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], 是], [2, [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], 是], [3, [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], 是], [4, [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], 是], [5, [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], 是], [6, [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], 是], [7, [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], 是], [8, [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], 是], [9, [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], 是]], 是, every_group_element_conjugates_H_to_itself)
依上列完整代值及條件核對得到原題答案;原題編號、格式與狀態保持不變。
覆核日期:2026-10-26
原題、答案、步驟表達式、數值 AST 與既有歷史保持原樣;原來的候選狀態屬於來源歷史,不覆寫為形式化證明。
input commit: 0f7be61e2c22317a4075561dc822c87d881a50dboriginal question SHA-256: d53610b228106903ff04e2b8d133feff0e398d7aaed8737966553d497e817e68candidate record SHA-256: eeb0b903a5bd8c0e651e32317423169cbe4d67582bfe786ebdd1365cbfb54e25semantic review receipt SHA-256: 049a9e07e69fead88d93b34f0937b9470a06d71c1a8d097058fc83554529bdd0question-first witness SHA-256: 0c71ebb418f3de347d232d159fc25e93036f4ab9166bcfb5ee5b4be86d5c55b9Lean: NOT_RUN · human review: NOT_PERFORMED