可測函數密度:逆像集合律、常值映射與來源sigma細化基礎 · 脈衝 R05

本批已通過 Schema、去重、來源快照與獨立答案重算;仍未標記為人工審定。

本題庫已有對應的中英逐步詳解。原題的 candidate 與英文 ai_candidate 狀態保留;AI 覆核、有限計算與 Lean 形式證明分開標示。

batch-20261013-advance-20261025-r05-measurable-function-foundations · 2026-10-13 · 100 題

1. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-complement-law;資料={"source_n":4,"target_n":4,"mapping":[0,0,0,0],"event":[0,1]}。請依 [mapping,event,target_complement,preimage,source_complement,preimage_of_complement,equal] 欄序回答。

查看答案與解釋

([0, 0, 0, 0], [0, 1], [2, 3], [0, 1, 2, 3], [], [], 是)

收束波核對=([0, 0, 0, 0], [0, 1], [2, 3], [0, 1, 2, 3], [], [], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-complement-law · candidate

2. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-complement-law;資料={"source_n":4,"target_n":4,"mapping":[1,0,0,0],"event":[1,2]}。請依 [mapping,event,target_complement,preimage,source_complement,preimage_of_complement,equal] 欄序回答。

查看答案與解釋

([1, 0, 0, 0], [1, 2], [0, 3], [0], [1, 2, 3], [1, 2, 3], 是)

收束波核對=([1, 0, 0, 0], [1, 2], [0, 3], [0], [1, 2, 3], [1, 2, 3], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-complement-law · candidate

3. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-complement-law;資料={"source_n":4,"target_n":4,"mapping":[2,0,0,0],"event":[2,3]}。請依 [mapping,event,target_complement,preimage,source_complement,preimage_of_complement,equal] 欄序回答。

查看答案與解釋

([2, 0, 0, 0], [2, 3], [0, 1], [0], [1, 2, 3], [1, 2, 3], 是)

收束波核對=([2, 0, 0, 0], [2, 3], [0, 1], [0], [1, 2, 3], [1, 2, 3], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-complement-law · candidate

4. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-complement-law;資料={"source_n":4,"target_n":4,"mapping":[3,0,0,0],"event":[0,3]}。請依 [mapping,event,target_complement,preimage,source_complement,preimage_of_complement,equal] 欄序回答。

查看答案與解釋

([3, 0, 0, 0], [0, 3], [1, 2], [0, 1, 2, 3], [], [], 是)

收束波核對=([3, 0, 0, 0], [0, 3], [1, 2], [0, 1, 2, 3], [], [], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-complement-law · candidate

5. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-complement-law;資料={"source_n":4,"target_n":4,"mapping":[0,1,0,0],"event":[0,1]}。請依 [mapping,event,target_complement,preimage,source_complement,preimage_of_complement,equal] 欄序回答。

查看答案與解釋

([0, 1, 0, 0], [0, 1], [2, 3], [0, 1, 2, 3], [], [], 是)

收束波核對=([0, 1, 0, 0], [0, 1], [2, 3], [0, 1, 2, 3], [], [], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-complement-law · candidate

6. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-complement-law;資料={"source_n":4,"target_n":4,"mapping":[1,1,0,0],"event":[1,2]}。請依 [mapping,event,target_complement,preimage,source_complement,preimage_of_complement,equal] 欄序回答。

查看答案與解釋

([1, 1, 0, 0], [1, 2], [0, 3], [0, 1], [2, 3], [2, 3], 是)

收束波核對=([1, 1, 0, 0], [1, 2], [0, 3], [0, 1], [2, 3], [2, 3], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-complement-law · candidate

7. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-complement-law;資料={"source_n":4,"target_n":4,"mapping":[2,1,0,0],"event":[2,3]}。請依 [mapping,event,target_complement,preimage,source_complement,preimage_of_complement,equal] 欄序回答。

查看答案與解釋

([2, 1, 0, 0], [2, 3], [0, 1], [0], [1, 2, 3], [1, 2, 3], 是)

收束波核對=([2, 1, 0, 0], [2, 3], [0, 1], [0], [1, 2, 3], [1, 2, 3], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-complement-law · candidate

8. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-complement-law;資料={"source_n":4,"target_n":4,"mapping":[3,1,0,0],"event":[0,3]}。請依 [mapping,event,target_complement,preimage,source_complement,preimage_of_complement,equal] 欄序回答。

查看答案與解釋

([3, 1, 0, 0], [0, 3], [1, 2], [0, 2, 3], [1], [1], 是)

收束波核對=([3, 1, 0, 0], [0, 3], [1, 2], [0, 2, 3], [1], [1], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-complement-law · candidate

9. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-complement-law;資料={"source_n":4,"target_n":4,"mapping":[0,2,0,0],"event":[0,1]}。請依 [mapping,event,target_complement,preimage,source_complement,preimage_of_complement,equal] 欄序回答。

查看答案與解釋

([0, 2, 0, 0], [0, 1], [2, 3], [0, 2, 3], [1], [1], 是)

收束波核對=([0, 2, 0, 0], [0, 1], [2, 3], [0, 2, 3], [1], [1], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-complement-law · candidate

10. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-complement-law;資料={"source_n":4,"target_n":4,"mapping":[1,2,0,0],"event":[1,2]}。請依 [mapping,event,target_complement,preimage,source_complement,preimage_of_complement,equal] 欄序回答。

查看答案與解釋

([1, 2, 0, 0], [1, 2], [0, 3], [0, 1], [2, 3], [2, 3], 是)

收束波核對=([1, 2, 0, 0], [1, 2], [0, 3], [0, 1], [2, 3], [2, 3], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-complement-law · candidate

11. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-complement-law;資料={"source_n":4,"target_n":4,"mapping":[2,2,0,0],"event":[2,3]}。請依 [mapping,event,target_complement,preimage,source_complement,preimage_of_complement,equal] 欄序回答。

查看答案與解釋

([2, 2, 0, 0], [2, 3], [0, 1], [0, 1], [2, 3], [2, 3], 是)

收束波核對=([2, 2, 0, 0], [2, 3], [0, 1], [0, 1], [2, 3], [2, 3], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-complement-law · candidate

12. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-complement-law;資料={"source_n":4,"target_n":4,"mapping":[3,2,0,0],"event":[0,3]}。請依 [mapping,event,target_complement,preimage,source_complement,preimage_of_complement,equal] 欄序回答。

查看答案與解釋

([3, 2, 0, 0], [0, 3], [1, 2], [0, 2, 3], [1], [1], 是)

收束波核對=([3, 2, 0, 0], [0, 3], [1, 2], [0, 2, 3], [1], [1], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-complement-law · candidate

13. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-complement-law;資料={"source_n":4,"target_n":4,"mapping":[0,3,0,0],"event":[0,1]}。請依 [mapping,event,target_complement,preimage,source_complement,preimage_of_complement,equal] 欄序回答。

查看答案與解釋

([0, 3, 0, 0], [0, 1], [2, 3], [0, 2, 3], [1], [1], 是)

收束波核對=([0, 3, 0, 0], [0, 1], [2, 3], [0, 2, 3], [1], [1], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-complement-law · candidate

14. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-complement-law;資料={"source_n":4,"target_n":4,"mapping":[1,3,0,0],"event":[1,2]}。請依 [mapping,event,target_complement,preimage,source_complement,preimage_of_complement,equal] 欄序回答。

查看答案與解釋

([1, 3, 0, 0], [1, 2], [0, 3], [0], [1, 2, 3], [1, 2, 3], 是)

收束波核對=([1, 3, 0, 0], [1, 2], [0, 3], [0], [1, 2, 3], [1, 2, 3], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-complement-law · candidate

15. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-complement-law;資料={"source_n":4,"target_n":4,"mapping":[2,3,0,0],"event":[2,3]}。請依 [mapping,event,target_complement,preimage,source_complement,preimage_of_complement,equal] 欄序回答。

查看答案與解釋

([2, 3, 0, 0], [2, 3], [0, 1], [0, 1], [2, 3], [2, 3], 是)

收束波核對=([2, 3, 0, 0], [2, 3], [0, 1], [0, 1], [2, 3], [2, 3], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-complement-law · candidate

16. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-complement-law;資料={"source_n":4,"target_n":4,"mapping":[3,3,0,0],"event":[0,3]}。請依 [mapping,event,target_complement,preimage,source_complement,preimage_of_complement,equal] 欄序回答。

查看答案與解釋

([3, 3, 0, 0], [0, 3], [1, 2], [0, 1, 2, 3], [], [], 是)

收束波核對=([3, 3, 0, 0], [0, 3], [1, 2], [0, 1, 2, 3], [], [], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-complement-law · candidate

17. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-complement-law;資料={"source_n":4,"target_n":4,"mapping":[0,0,1,0],"event":[0,1]}。請依 [mapping,event,target_complement,preimage,source_complement,preimage_of_complement,equal] 欄序回答。

查看答案與解釋

([0, 0, 1, 0], [0, 1], [2, 3], [0, 1, 2, 3], [], [], 是)

收束波核對=([0, 0, 1, 0], [0, 1], [2, 3], [0, 1, 2, 3], [], [], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-complement-law · candidate

18. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-complement-law;資料={"source_n":4,"target_n":4,"mapping":[1,0,1,0],"event":[1,2]}。請依 [mapping,event,target_complement,preimage,source_complement,preimage_of_complement,equal] 欄序回答。

查看答案與解釋

([1, 0, 1, 0], [1, 2], [0, 3], [0, 2], [1, 3], [1, 3], 是)

收束波核對=([1, 0, 1, 0], [1, 2], [0, 3], [0, 2], [1, 3], [1, 3], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-complement-law · candidate

19. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-complement-law;資料={"source_n":4,"target_n":4,"mapping":[2,0,1,0],"event":[2,3]}。請依 [mapping,event,target_complement,preimage,source_complement,preimage_of_complement,equal] 欄序回答。

查看答案與解釋

([2, 0, 1, 0], [2, 3], [0, 1], [0], [1, 2, 3], [1, 2, 3], 是)

收束波核對=([2, 0, 1, 0], [2, 3], [0, 1], [0], [1, 2, 3], [1, 2, 3], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-complement-law · candidate

20. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-complement-law;資料={"source_n":4,"target_n":4,"mapping":[3,0,1,0],"event":[0,3]}。請依 [mapping,event,target_complement,preimage,source_complement,preimage_of_complement,equal] 欄序回答。

查看答案與解釋

([3, 0, 1, 0], [0, 3], [1, 2], [0, 1, 3], [2], [2], 是)

收束波核對=([3, 0, 1, 0], [0, 3], [1, 2], [0, 1, 3], [2], [2], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-complement-law · candidate

21. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-complement-law;資料={"source_n":4,"target_n":4,"mapping":[0,1,1,0],"event":[0,1]}。請依 [mapping,event,target_complement,preimage,source_complement,preimage_of_complement,equal] 欄序回答。

查看答案與解釋

([0, 1, 1, 0], [0, 1], [2, 3], [0, 1, 2, 3], [], [], 是)

收束波核對=([0, 1, 1, 0], [0, 1], [2, 3], [0, 1, 2, 3], [], [], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-complement-law · candidate

22. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-complement-law;資料={"source_n":4,"target_n":4,"mapping":[1,1,1,0],"event":[1,2]}。請依 [mapping,event,target_complement,preimage,source_complement,preimage_of_complement,equal] 欄序回答。

查看答案與解釋

([1, 1, 1, 0], [1, 2], [0, 3], [0, 1, 2], [3], [3], 是)

收束波核對=([1, 1, 1, 0], [1, 2], [0, 3], [0, 1, 2], [3], [3], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-complement-law · candidate

23. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-complement-law;資料={"source_n":4,"target_n":4,"mapping":[2,1,1,0],"event":[2,3]}。請依 [mapping,event,target_complement,preimage,source_complement,preimage_of_complement,equal] 欄序回答。

查看答案與解釋

([2, 1, 1, 0], [2, 3], [0, 1], [0], [1, 2, 3], [1, 2, 3], 是)

收束波核對=([2, 1, 1, 0], [2, 3], [0, 1], [0], [1, 2, 3], [1, 2, 3], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-complement-law · candidate

24. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-complement-law;資料={"source_n":4,"target_n":4,"mapping":[3,1,1,0],"event":[0,3]}。請依 [mapping,event,target_complement,preimage,source_complement,preimage_of_complement,equal] 欄序回答。

查看答案與解釋

([3, 1, 1, 0], [0, 3], [1, 2], [0, 3], [1, 2], [1, 2], 是)

收束波核對=([3, 1, 1, 0], [0, 3], [1, 2], [0, 3], [1, 2], [1, 2], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-complement-law · candidate

25. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-complement-law;資料={"source_n":4,"target_n":4,"mapping":[0,2,1,0],"event":[0,1]}。請依 [mapping,event,target_complement,preimage,source_complement,preimage_of_complement,equal] 欄序回答。

查看答案與解釋

([0, 2, 1, 0], [0, 1], [2, 3], [0, 2, 3], [1], [1], 是)

收束波核對=([0, 2, 1, 0], [0, 1], [2, 3], [0, 2, 3], [1], [1], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-complement-law · candidate

26. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-union-law;資料={"source_n":4,"target_n":4,"mapping":[0,0,0,0],"left_event":[0],"right_event":[1,2]}。請依 [mapping,left,right,union,left_preimage,right_preimage,union_preimage,preimage_union,equal] 欄序回答。

查看答案與解釋

([0, 0, 0, 0], [0], [1, 2], [0, 1, 2], [0, 1, 2, 3], [], [0, 1, 2, 3], [0, 1, 2, 3], 是)

收束波核對=([0, 0, 0, 0], [0], [1, 2], [0, 1, 2], [0, 1, 2, 3], [], [0, 1, 2, 3], [0, 1, 2, 3], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-union-law · candidate

27. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-union-law;資料={"source_n":4,"target_n":4,"mapping":[1,0,0,0],"left_event":[1],"right_event":[2,3]}。請依 [mapping,left,right,union,left_preimage,right_preimage,union_preimage,preimage_union,equal] 欄序回答。

查看答案與解釋

([1, 0, 0, 0], [1], [2, 3], [1, 2, 3], [0], [], [0], [0], 是)

收束波核對=([1, 0, 0, 0], [1], [2, 3], [1, 2, 3], [0], [], [0], [0], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-union-law · candidate

28. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-union-law;資料={"source_n":4,"target_n":4,"mapping":[2,0,0,0],"left_event":[2],"right_event":[0,3]}。請依 [mapping,left,right,union,left_preimage,right_preimage,union_preimage,preimage_union,equal] 欄序回答。

查看答案與解釋

([2, 0, 0, 0], [2], [0, 3], [0, 2, 3], [0], [1, 2, 3], [0, 1, 2, 3], [0, 1, 2, 3], 是)

收束波核對=([2, 0, 0, 0], [2], [0, 3], [0, 2, 3], [0], [1, 2, 3], [0, 1, 2, 3], [0, 1, 2, 3], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-union-law · candidate

29. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-union-law;資料={"source_n":4,"target_n":4,"mapping":[3,0,0,0],"left_event":[3],"right_event":[0,1]}。請依 [mapping,left,right,union,left_preimage,right_preimage,union_preimage,preimage_union,equal] 欄序回答。

查看答案與解釋

([3, 0, 0, 0], [3], [0, 1], [0, 1, 3], [0], [1, 2, 3], [0, 1, 2, 3], [0, 1, 2, 3], 是)

收束波核對=([3, 0, 0, 0], [3], [0, 1], [0, 1, 3], [0], [1, 2, 3], [0, 1, 2, 3], [0, 1, 2, 3], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-union-law · candidate

30. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-union-law;資料={"source_n":4,"target_n":4,"mapping":[0,1,0,0],"left_event":[0],"right_event":[1,2]}。請依 [mapping,left,right,union,left_preimage,right_preimage,union_preimage,preimage_union,equal] 欄序回答。

查看答案與解釋

([0, 1, 0, 0], [0], [1, 2], [0, 1, 2], [0, 2, 3], [1], [0, 1, 2, 3], [0, 1, 2, 3], 是)

收束波核對=([0, 1, 0, 0], [0], [1, 2], [0, 1, 2], [0, 2, 3], [1], [0, 1, 2, 3], [0, 1, 2, 3], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-union-law · candidate

31. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-union-law;資料={"source_n":4,"target_n":4,"mapping":[1,1,0,0],"left_event":[1],"right_event":[2,3]}。請依 [mapping,left,right,union,left_preimage,right_preimage,union_preimage,preimage_union,equal] 欄序回答。

查看答案與解釋

([1, 1, 0, 0], [1], [2, 3], [1, 2, 3], [0, 1], [], [0, 1], [0, 1], 是)

收束波核對=([1, 1, 0, 0], [1], [2, 3], [1, 2, 3], [0, 1], [], [0, 1], [0, 1], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-union-law · candidate

32. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-union-law;資料={"source_n":4,"target_n":4,"mapping":[2,1,0,0],"left_event":[2],"right_event":[0,3]}。請依 [mapping,left,right,union,left_preimage,right_preimage,union_preimage,preimage_union,equal] 欄序回答。

查看答案與解釋

([2, 1, 0, 0], [2], [0, 3], [0, 2, 3], [0], [2, 3], [0, 2, 3], [0, 2, 3], 是)

收束波核對=([2, 1, 0, 0], [2], [0, 3], [0, 2, 3], [0], [2, 3], [0, 2, 3], [0, 2, 3], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-union-law · candidate

33. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-union-law;資料={"source_n":4,"target_n":4,"mapping":[3,1,0,0],"left_event":[3],"right_event":[0,1]}。請依 [mapping,left,right,union,left_preimage,right_preimage,union_preimage,preimage_union,equal] 欄序回答。

查看答案與解釋

([3, 1, 0, 0], [3], [0, 1], [0, 1, 3], [0], [1, 2, 3], [0, 1, 2, 3], [0, 1, 2, 3], 是)

收束波核對=([3, 1, 0, 0], [3], [0, 1], [0, 1, 3], [0], [1, 2, 3], [0, 1, 2, 3], [0, 1, 2, 3], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-union-law · candidate

34. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-union-law;資料={"source_n":4,"target_n":4,"mapping":[0,2,0,0],"left_event":[0],"right_event":[1,2]}。請依 [mapping,left,right,union,left_preimage,right_preimage,union_preimage,preimage_union,equal] 欄序回答。

查看答案與解釋

([0, 2, 0, 0], [0], [1, 2], [0, 1, 2], [0, 2, 3], [1], [0, 1, 2, 3], [0, 1, 2, 3], 是)

收束波核對=([0, 2, 0, 0], [0], [1, 2], [0, 1, 2], [0, 2, 3], [1], [0, 1, 2, 3], [0, 1, 2, 3], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-union-law · candidate

35. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-union-law;資料={"source_n":4,"target_n":4,"mapping":[1,2,0,0],"left_event":[1],"right_event":[2,3]}。請依 [mapping,left,right,union,left_preimage,right_preimage,union_preimage,preimage_union,equal] 欄序回答。

查看答案與解釋

([1, 2, 0, 0], [1], [2, 3], [1, 2, 3], [0], [1], [0, 1], [0, 1], 是)

收束波核對=([1, 2, 0, 0], [1], [2, 3], [1, 2, 3], [0], [1], [0, 1], [0, 1], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-union-law · candidate

36. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-union-law;資料={"source_n":4,"target_n":4,"mapping":[2,2,0,0],"left_event":[2],"right_event":[0,3]}。請依 [mapping,left,right,union,left_preimage,right_preimage,union_preimage,preimage_union,equal] 欄序回答。

查看答案與解釋

([2, 2, 0, 0], [2], [0, 3], [0, 2, 3], [0, 1], [2, 3], [0, 1, 2, 3], [0, 1, 2, 3], 是)

收束波核對=([2, 2, 0, 0], [2], [0, 3], [0, 2, 3], [0, 1], [2, 3], [0, 1, 2, 3], [0, 1, 2, 3], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-union-law · candidate

37. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-union-law;資料={"source_n":4,"target_n":4,"mapping":[3,2,0,0],"left_event":[3],"right_event":[0,1]}。請依 [mapping,left,right,union,left_preimage,right_preimage,union_preimage,preimage_union,equal] 欄序回答。

查看答案與解釋

([3, 2, 0, 0], [3], [0, 1], [0, 1, 3], [0], [2, 3], [0, 2, 3], [0, 2, 3], 是)

收束波核對=([3, 2, 0, 0], [3], [0, 1], [0, 1, 3], [0], [2, 3], [0, 2, 3], [0, 2, 3], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-union-law · candidate

38. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-union-law;資料={"source_n":4,"target_n":4,"mapping":[0,3,0,0],"left_event":[0],"right_event":[1,2]}。請依 [mapping,left,right,union,left_preimage,right_preimage,union_preimage,preimage_union,equal] 欄序回答。

查看答案與解釋

([0, 3, 0, 0], [0], [1, 2], [0, 1, 2], [0, 2, 3], [], [0, 2, 3], [0, 2, 3], 是)

收束波核對=([0, 3, 0, 0], [0], [1, 2], [0, 1, 2], [0, 2, 3], [], [0, 2, 3], [0, 2, 3], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-union-law · candidate

39. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-union-law;資料={"source_n":4,"target_n":4,"mapping":[1,3,0,0],"left_event":[1],"right_event":[2,3]}。請依 [mapping,left,right,union,left_preimage,right_preimage,union_preimage,preimage_union,equal] 欄序回答。

查看答案與解釋

([1, 3, 0, 0], [1], [2, 3], [1, 2, 3], [0], [1], [0, 1], [0, 1], 是)

收束波核對=([1, 3, 0, 0], [1], [2, 3], [1, 2, 3], [0], [1], [0, 1], [0, 1], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-union-law · candidate

40. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-union-law;資料={"source_n":4,"target_n":4,"mapping":[2,3,0,0],"left_event":[2],"right_event":[0,3]}。請依 [mapping,left,right,union,left_preimage,right_preimage,union_preimage,preimage_union,equal] 欄序回答。

查看答案與解釋

([2, 3, 0, 0], [2], [0, 3], [0, 2, 3], [0], [1, 2, 3], [0, 1, 2, 3], [0, 1, 2, 3], 是)

收束波核對=([2, 3, 0, 0], [2], [0, 3], [0, 2, 3], [0], [1, 2, 3], [0, 1, 2, 3], [0, 1, 2, 3], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-union-law · candidate

41. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-union-law;資料={"source_n":4,"target_n":4,"mapping":[3,3,0,0],"left_event":[3],"right_event":[0,1]}。請依 [mapping,left,right,union,left_preimage,right_preimage,union_preimage,preimage_union,equal] 欄序回答。

查看答案與解釋

([3, 3, 0, 0], [3], [0, 1], [0, 1, 3], [0, 1], [2, 3], [0, 1, 2, 3], [0, 1, 2, 3], 是)

收束波核對=([3, 3, 0, 0], [3], [0, 1], [0, 1, 3], [0, 1], [2, 3], [0, 1, 2, 3], [0, 1, 2, 3], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-union-law · candidate

42. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-union-law;資料={"source_n":4,"target_n":4,"mapping":[0,0,1,0],"left_event":[0],"right_event":[1,2]}。請依 [mapping,left,right,union,left_preimage,right_preimage,union_preimage,preimage_union,equal] 欄序回答。

查看答案與解釋

([0, 0, 1, 0], [0], [1, 2], [0, 1, 2], [0, 1, 3], [2], [0, 1, 2, 3], [0, 1, 2, 3], 是)

收束波核對=([0, 0, 1, 0], [0], [1, 2], [0, 1, 2], [0, 1, 3], [2], [0, 1, 2, 3], [0, 1, 2, 3], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-union-law · candidate

43. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-union-law;資料={"source_n":4,"target_n":4,"mapping":[1,0,1,0],"left_event":[1],"right_event":[2,3]}。請依 [mapping,left,right,union,left_preimage,right_preimage,union_preimage,preimage_union,equal] 欄序回答。

查看答案與解釋

([1, 0, 1, 0], [1], [2, 3], [1, 2, 3], [0, 2], [], [0, 2], [0, 2], 是)

收束波核對=([1, 0, 1, 0], [1], [2, 3], [1, 2, 3], [0, 2], [], [0, 2], [0, 2], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-union-law · candidate

44. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-union-law;資料={"source_n":4,"target_n":4,"mapping":[2,0,1,0],"left_event":[2],"right_event":[0,3]}。請依 [mapping,left,right,union,left_preimage,right_preimage,union_preimage,preimage_union,equal] 欄序回答。

查看答案與解釋

([2, 0, 1, 0], [2], [0, 3], [0, 2, 3], [0], [1, 3], [0, 1, 3], [0, 1, 3], 是)

收束波核對=([2, 0, 1, 0], [2], [0, 3], [0, 2, 3], [0], [1, 3], [0, 1, 3], [0, 1, 3], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-union-law · candidate

45. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-union-law;資料={"source_n":4,"target_n":4,"mapping":[3,0,1,0],"left_event":[3],"right_event":[0,1]}。請依 [mapping,left,right,union,left_preimage,right_preimage,union_preimage,preimage_union,equal] 欄序回答。

查看答案與解釋

([3, 0, 1, 0], [3], [0, 1], [0, 1, 3], [0], [1, 2, 3], [0, 1, 2, 3], [0, 1, 2, 3], 是)

收束波核對=([3, 0, 1, 0], [3], [0, 1], [0, 1, 3], [0], [1, 2, 3], [0, 1, 2, 3], [0, 1, 2, 3], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-union-law · candidate

46. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-union-law;資料={"source_n":4,"target_n":4,"mapping":[0,1,1,0],"left_event":[0],"right_event":[1,2]}。請依 [mapping,left,right,union,left_preimage,right_preimage,union_preimage,preimage_union,equal] 欄序回答。

查看答案與解釋

([0, 1, 1, 0], [0], [1, 2], [0, 1, 2], [0, 3], [1, 2], [0, 1, 2, 3], [0, 1, 2, 3], 是)

收束波核對=([0, 1, 1, 0], [0], [1, 2], [0, 1, 2], [0, 3], [1, 2], [0, 1, 2, 3], [0, 1, 2, 3], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-union-law · candidate

47. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-union-law;資料={"source_n":4,"target_n":4,"mapping":[1,1,1,0],"left_event":[1],"right_event":[2,3]}。請依 [mapping,left,right,union,left_preimage,right_preimage,union_preimage,preimage_union,equal] 欄序回答。

查看答案與解釋

([1, 1, 1, 0], [1], [2, 3], [1, 2, 3], [0, 1, 2], [], [0, 1, 2], [0, 1, 2], 是)

收束波核對=([1, 1, 1, 0], [1], [2, 3], [1, 2, 3], [0, 1, 2], [], [0, 1, 2], [0, 1, 2], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-union-law · candidate

48. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-union-law;資料={"source_n":4,"target_n":4,"mapping":[2,1,1,0],"left_event":[2],"right_event":[0,3]}。請依 [mapping,left,right,union,left_preimage,right_preimage,union_preimage,preimage_union,equal] 欄序回答。

查看答案與解釋

([2, 1, 1, 0], [2], [0, 3], [0, 2, 3], [0], [3], [0, 3], [0, 3], 是)

收束波核對=([2, 1, 1, 0], [2], [0, 3], [0, 2, 3], [0], [3], [0, 3], [0, 3], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-union-law · candidate

49. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-union-law;資料={"source_n":4,"target_n":4,"mapping":[3,1,1,0],"left_event":[3],"right_event":[0,1]}。請依 [mapping,left,right,union,left_preimage,right_preimage,union_preimage,preimage_union,equal] 欄序回答。

查看答案與解釋

([3, 1, 1, 0], [3], [0, 1], [0, 1, 3], [0], [1, 2, 3], [0, 1, 2, 3], [0, 1, 2, 3], 是)

收束波核對=([3, 1, 1, 0], [3], [0, 1], [0, 1, 3], [0], [1, 2, 3], [0, 1, 2, 3], [0, 1, 2, 3], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-union-law · candidate

50. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-preimage-union-law;資料={"source_n":4,"target_n":4,"mapping":[0,2,1,0],"left_event":[0],"right_event":[1,2]}。請依 [mapping,left,right,union,left_preimage,right_preimage,union_preimage,preimage_union,equal] 欄序回答。

查看答案與解釋

([0, 2, 1, 0], [0], [1, 2], [0, 1, 2], [0, 3], [1, 2], [0, 1, 2, 3], [0, 1, 2, 3], 是)

收束波核對=([0, 2, 1, 0], [0], [1, 2], [0, 1, 2], [0, 3], [1, 2], [0, 1, 2, 3], [0, 1, 2, 3], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-preimage-union-law · candidate

51. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-constant-map-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[0],[1,2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"value":0}。請依 [source_n,target_n,value,mapping,preimage_rows,measurable] 欄序回答。

查看答案與解釋

(4, 4, 0, [0, 0, 0, 0], [[[], [], 是], [[0], [0, 1, 2, 3], 是], [[1], [], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=(4, 4, 0, [0, 0, 0, 0], [[[], [], 是], [[0], [0, 1, 2, 3], 是], [[1], [], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-constant-map-audit · candidate

52. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-constant-map-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[1],[0,2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"value":1}。請依 [source_n,target_n,value,mapping,preimage_rows,measurable] 欄序回答。

查看答案與解釋

(4, 4, 1, [1, 1, 1, 1], [[[], [], 是], [[0], [], 是], [[1], [0, 1, 2, 3], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [], 是], [[1, 2], [0, 1, 2, 3], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [], 是], [[1, 3], [0, 1, 2, 3], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [], 是], [[1, 2, 3], [0, 1, 2, 3], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=(4, 4, 1, [1, 1, 1, 1], [[[], [], 是], [[0], [], 是], [[1], [0, 1, 2, 3], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [], 是], [[1, 2], [0, 1, 2, 3], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [], 是], [[1, 3], [0, 1, 2, 3], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [], 是], [[1, 2, 3], [0, 1, 2, 3], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-constant-map-audit · candidate

53. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-constant-map-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[0,1],[2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"value":2}。請依 [source_n,target_n,value,mapping,preimage_rows,measurable] 欄序回答。

查看答案與解釋

(4, 4, 2, [2, 2, 2, 2], [[[], [], 是], [[0], [], 是], [[1], [], 是], [[0, 1], [], 是], [[2], [0, 1, 2, 3], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [0, 1, 2, 3], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [], 是], [[1, 3], [], 是], [[0, 1, 3], [], 是], [[2, 3], [0, 1, 2, 3], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1, 2, 3], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=(4, 4, 2, [2, 2, 2, 2], [[[], [], 是], [[0], [], 是], [[1], [], 是], [[0, 1], [], 是], [[2], [0, 1, 2, 3], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [0, 1, 2, 3], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [], 是], [[1, 3], [], 是], [[0, 1, 3], [], 是], [[2, 3], [0, 1, 2, 3], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1, 2, 3], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-constant-map-audit · candidate

54. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-constant-map-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[2],[0,1,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"value":3}。請依 [source_n,target_n,value,mapping,preimage_rows,measurable] 欄序回答。

查看答案與解釋

(4, 4, 3, [3, 3, 3, 3], [[[], [], 是], [[0], [], 是], [[1], [], 是], [[0, 1], [], 是], [[2], [], 是], [[0, 2], [], 是], [[1, 2], [], 是], [[0, 1, 2], [], 是], [[3], [0, 1, 2, 3], 是], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [0, 1, 2, 3], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [0, 1, 2, 3], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1, 2, 3], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=(4, 4, 3, [3, 3, 3, 3], [[[], [], 是], [[0], [], 是], [[1], [], 是], [[0, 1], [], 是], [[2], [], 是], [[0, 2], [], 是], [[1, 2], [], 是], [[0, 1, 2], [], 是], [[3], [0, 1, 2, 3], 是], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [0, 1, 2, 3], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [0, 1, 2, 3], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1, 2, 3], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-constant-map-audit · candidate

55. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-constant-map-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[0,2],[1,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"value":0}。請依 [source_n,target_n,value,mapping,preimage_rows,measurable] 欄序回答。

查看答案與解釋

(4, 4, 0, [0, 0, 0, 0], [[[], [], 是], [[0], [0, 1, 2, 3], 是], [[1], [], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=(4, 4, 0, [0, 0, 0, 0], [[[], [], 是], [[0], [0, 1, 2, 3], 是], [[1], [], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-constant-map-audit · candidate

56. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-constant-map-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[1,2],[0,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"value":1}。請依 [source_n,target_n,value,mapping,preimage_rows,measurable] 欄序回答。

查看答案與解釋

(4, 4, 1, [1, 1, 1, 1], [[[], [], 是], [[0], [], 是], [[1], [0, 1, 2, 3], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [], 是], [[1, 2], [0, 1, 2, 3], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [], 是], [[1, 3], [0, 1, 2, 3], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [], 是], [[1, 2, 3], [0, 1, 2, 3], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=(4, 4, 1, [1, 1, 1, 1], [[[], [], 是], [[0], [], 是], [[1], [0, 1, 2, 3], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [], 是], [[1, 2], [0, 1, 2, 3], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [], 是], [[1, 3], [0, 1, 2, 3], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [], 是], [[1, 2, 3], [0, 1, 2, 3], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-constant-map-audit · candidate

57. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-constant-map-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[0,1,2],[3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"value":2}。請依 [source_n,target_n,value,mapping,preimage_rows,measurable] 欄序回答。

查看答案與解釋

(4, 4, 2, [2, 2, 2, 2], [[[], [], 是], [[0], [], 是], [[1], [], 是], [[0, 1], [], 是], [[2], [0, 1, 2, 3], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [0, 1, 2, 3], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [], 是], [[1, 3], [], 是], [[0, 1, 3], [], 是], [[2, 3], [0, 1, 2, 3], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1, 2, 3], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=(4, 4, 2, [2, 2, 2, 2], [[[], [], 是], [[0], [], 是], [[1], [], 是], [[0, 1], [], 是], [[2], [0, 1, 2, 3], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [0, 1, 2, 3], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [], 是], [[1, 3], [], 是], [[0, 1, 3], [], 是], [[2, 3], [0, 1, 2, 3], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1, 2, 3], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-constant-map-audit · candidate

58. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-constant-map-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[0],[1,2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"value":3}。請依 [source_n,target_n,value,mapping,preimage_rows,measurable] 欄序回答。

查看答案與解釋

(4, 4, 3, [3, 3, 3, 3], [[[], [], 是], [[0], [], 是], [[1], [], 是], [[0, 1], [], 是], [[2], [], 是], [[0, 2], [], 是], [[1, 2], [], 是], [[0, 1, 2], [], 是], [[3], [0, 1, 2, 3], 是], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [0, 1, 2, 3], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [0, 1, 2, 3], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1, 2, 3], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=(4, 4, 3, [3, 3, 3, 3], [[[], [], 是], [[0], [], 是], [[1], [], 是], [[0, 1], [], 是], [[2], [], 是], [[0, 2], [], 是], [[1, 2], [], 是], [[0, 1, 2], [], 是], [[3], [0, 1, 2, 3], 是], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [0, 1, 2, 3], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [0, 1, 2, 3], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1, 2, 3], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-constant-map-audit · candidate

59. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-constant-map-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[1],[0,2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"value":0}。請依 [source_n,target_n,value,mapping,preimage_rows,measurable] 欄序回答。

查看答案與解釋

(4, 4, 0, [0, 0, 0, 0], [[[], [], 是], [[0], [0, 1, 2, 3], 是], [[1], [], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=(4, 4, 0, [0, 0, 0, 0], [[[], [], 是], [[0], [0, 1, 2, 3], 是], [[1], [], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-constant-map-audit · candidate

60. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-constant-map-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[0,1],[2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"value":1}。請依 [source_n,target_n,value,mapping,preimage_rows,measurable] 欄序回答。

查看答案與解釋

(4, 4, 1, [1, 1, 1, 1], [[[], [], 是], [[0], [], 是], [[1], [0, 1, 2, 3], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [], 是], [[1, 2], [0, 1, 2, 3], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [], 是], [[1, 3], [0, 1, 2, 3], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [], 是], [[1, 2, 3], [0, 1, 2, 3], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=(4, 4, 1, [1, 1, 1, 1], [[[], [], 是], [[0], [], 是], [[1], [0, 1, 2, 3], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [], 是], [[1, 2], [0, 1, 2, 3], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [], 是], [[1, 3], [0, 1, 2, 3], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [], 是], [[1, 2, 3], [0, 1, 2, 3], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-constant-map-audit · candidate

61. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-constant-map-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[2],[0,1,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"value":2}。請依 [source_n,target_n,value,mapping,preimage_rows,measurable] 欄序回答。

查看答案與解釋

(4, 4, 2, [2, 2, 2, 2], [[[], [], 是], [[0], [], 是], [[1], [], 是], [[0, 1], [], 是], [[2], [0, 1, 2, 3], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [0, 1, 2, 3], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [], 是], [[1, 3], [], 是], [[0, 1, 3], [], 是], [[2, 3], [0, 1, 2, 3], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1, 2, 3], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=(4, 4, 2, [2, 2, 2, 2], [[[], [], 是], [[0], [], 是], [[1], [], 是], [[0, 1], [], 是], [[2], [0, 1, 2, 3], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [0, 1, 2, 3], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [], 是], [[1, 3], [], 是], [[0, 1, 3], [], 是], [[2, 3], [0, 1, 2, 3], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1, 2, 3], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-constant-map-audit · candidate

62. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-constant-map-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[0,2],[1,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"value":3}。請依 [source_n,target_n,value,mapping,preimage_rows,measurable] 欄序回答。

查看答案與解釋

(4, 4, 3, [3, 3, 3, 3], [[[], [], 是], [[0], [], 是], [[1], [], 是], [[0, 1], [], 是], [[2], [], 是], [[0, 2], [], 是], [[1, 2], [], 是], [[0, 1, 2], [], 是], [[3], [0, 1, 2, 3], 是], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [0, 1, 2, 3], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [0, 1, 2, 3], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1, 2, 3], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=(4, 4, 3, [3, 3, 3, 3], [[[], [], 是], [[0], [], 是], [[1], [], 是], [[0, 1], [], 是], [[2], [], 是], [[0, 2], [], 是], [[1, 2], [], 是], [[0, 1, 2], [], 是], [[3], [0, 1, 2, 3], 是], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [0, 1, 2, 3], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [0, 1, 2, 3], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1, 2, 3], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-constant-map-audit · candidate

63. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-constant-map-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[1,2],[0,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"value":0}。請依 [source_n,target_n,value,mapping,preimage_rows,measurable] 欄序回答。

查看答案與解釋

(4, 4, 0, [0, 0, 0, 0], [[[], [], 是], [[0], [0, 1, 2, 3], 是], [[1], [], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=(4, 4, 0, [0, 0, 0, 0], [[[], [], 是], [[0], [0, 1, 2, 3], 是], [[1], [], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-constant-map-audit · candidate

64. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-constant-map-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[0,1,2],[3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"value":1}。請依 [source_n,target_n,value,mapping,preimage_rows,measurable] 欄序回答。

查看答案與解釋

(4, 4, 1, [1, 1, 1, 1], [[[], [], 是], [[0], [], 是], [[1], [0, 1, 2, 3], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [], 是], [[1, 2], [0, 1, 2, 3], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [], 是], [[1, 3], [0, 1, 2, 3], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [], 是], [[1, 2, 3], [0, 1, 2, 3], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=(4, 4, 1, [1, 1, 1, 1], [[[], [], 是], [[0], [], 是], [[1], [0, 1, 2, 3], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [], 是], [[1, 2], [0, 1, 2, 3], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [], 是], [[1, 3], [0, 1, 2, 3], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [], 是], [[1, 2, 3], [0, 1, 2, 3], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-constant-map-audit · candidate

65. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-constant-map-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[0],[1,2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"value":2}。請依 [source_n,target_n,value,mapping,preimage_rows,measurable] 欄序回答。

查看答案與解釋

(4, 4, 2, [2, 2, 2, 2], [[[], [], 是], [[0], [], 是], [[1], [], 是], [[0, 1], [], 是], [[2], [0, 1, 2, 3], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [0, 1, 2, 3], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [], 是], [[1, 3], [], 是], [[0, 1, 3], [], 是], [[2, 3], [0, 1, 2, 3], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1, 2, 3], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=(4, 4, 2, [2, 2, 2, 2], [[[], [], 是], [[0], [], 是], [[1], [], 是], [[0, 1], [], 是], [[2], [0, 1, 2, 3], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [0, 1, 2, 3], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [], 是], [[1, 3], [], 是], [[0, 1, 3], [], 是], [[2, 3], [0, 1, 2, 3], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1, 2, 3], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-constant-map-audit · candidate

66. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-constant-map-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[1],[0,2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"value":3}。請依 [source_n,target_n,value,mapping,preimage_rows,measurable] 欄序回答。

查看答案與解釋

(4, 4, 3, [3, 3, 3, 3], [[[], [], 是], [[0], [], 是], [[1], [], 是], [[0, 1], [], 是], [[2], [], 是], [[0, 2], [], 是], [[1, 2], [], 是], [[0, 1, 2], [], 是], [[3], [0, 1, 2, 3], 是], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [0, 1, 2, 3], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [0, 1, 2, 3], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1, 2, 3], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=(4, 4, 3, [3, 3, 3, 3], [[[], [], 是], [[0], [], 是], [[1], [], 是], [[0, 1], [], 是], [[2], [], 是], [[0, 2], [], 是], [[1, 2], [], 是], [[0, 1, 2], [], 是], [[3], [0, 1, 2, 3], 是], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [0, 1, 2, 3], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [0, 1, 2, 3], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1, 2, 3], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-constant-map-audit · candidate

67. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-constant-map-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[0,1],[2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"value":0}。請依 [source_n,target_n,value,mapping,preimage_rows,measurable] 欄序回答。

查看答案與解釋

(4, 4, 0, [0, 0, 0, 0], [[[], [], 是], [[0], [0, 1, 2, 3], 是], [[1], [], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=(4, 4, 0, [0, 0, 0, 0], [[[], [], 是], [[0], [0, 1, 2, 3], 是], [[1], [], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-constant-map-audit · candidate

68. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-constant-map-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[2],[0,1,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"value":1}。請依 [source_n,target_n,value,mapping,preimage_rows,measurable] 欄序回答。

查看答案與解釋

(4, 4, 1, [1, 1, 1, 1], [[[], [], 是], [[0], [], 是], [[1], [0, 1, 2, 3], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [], 是], [[1, 2], [0, 1, 2, 3], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [], 是], [[1, 3], [0, 1, 2, 3], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [], 是], [[1, 2, 3], [0, 1, 2, 3], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=(4, 4, 1, [1, 1, 1, 1], [[[], [], 是], [[0], [], 是], [[1], [0, 1, 2, 3], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [], 是], [[1, 2], [0, 1, 2, 3], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [], 是], [[1, 3], [0, 1, 2, 3], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [], 是], [[1, 2, 3], [0, 1, 2, 3], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-constant-map-audit · candidate

69. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-constant-map-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[0,2],[1,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"value":2}。請依 [source_n,target_n,value,mapping,preimage_rows,measurable] 欄序回答。

查看答案與解釋

(4, 4, 2, [2, 2, 2, 2], [[[], [], 是], [[0], [], 是], [[1], [], 是], [[0, 1], [], 是], [[2], [0, 1, 2, 3], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [0, 1, 2, 3], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [], 是], [[1, 3], [], 是], [[0, 1, 3], [], 是], [[2, 3], [0, 1, 2, 3], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1, 2, 3], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=(4, 4, 2, [2, 2, 2, 2], [[[], [], 是], [[0], [], 是], [[1], [], 是], [[0, 1], [], 是], [[2], [0, 1, 2, 3], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [0, 1, 2, 3], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [], 是], [[1, 3], [], 是], [[0, 1, 3], [], 是], [[2, 3], [0, 1, 2, 3], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1, 2, 3], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-constant-map-audit · candidate

70. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-constant-map-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[1,2],[0,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"value":3}。請依 [source_n,target_n,value,mapping,preimage_rows,measurable] 欄序回答。

查看答案與解釋

(4, 4, 3, [3, 3, 3, 3], [[[], [], 是], [[0], [], 是], [[1], [], 是], [[0, 1], [], 是], [[2], [], 是], [[0, 2], [], 是], [[1, 2], [], 是], [[0, 1, 2], [], 是], [[3], [0, 1, 2, 3], 是], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [0, 1, 2, 3], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [0, 1, 2, 3], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1, 2, 3], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=(4, 4, 3, [3, 3, 3, 3], [[[], [], 是], [[0], [], 是], [[1], [], 是], [[0, 1], [], 是], [[2], [], 是], [[0, 2], [], 是], [[1, 2], [], 是], [[0, 1, 2], [], 是], [[3], [0, 1, 2, 3], 是], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [0, 1, 2, 3], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [0, 1, 2, 3], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1, 2, 3], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-constant-map-audit · candidate

71. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-constant-map-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[0,1,2],[3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"value":0}。請依 [source_n,target_n,value,mapping,preimage_rows,measurable] 欄序回答。

查看答案與解釋

(4, 4, 0, [0, 0, 0, 0], [[[], [], 是], [[0], [0, 1, 2, 3], 是], [[1], [], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=(4, 4, 0, [0, 0, 0, 0], [[[], [], 是], [[0], [0, 1, 2, 3], 是], [[1], [], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-constant-map-audit · candidate

72. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-constant-map-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[0],[1,2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"value":1}。請依 [source_n,target_n,value,mapping,preimage_rows,measurable] 欄序回答。

查看答案與解釋

(4, 4, 1, [1, 1, 1, 1], [[[], [], 是], [[0], [], 是], [[1], [0, 1, 2, 3], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [], 是], [[1, 2], [0, 1, 2, 3], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [], 是], [[1, 3], [0, 1, 2, 3], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [], 是], [[1, 2, 3], [0, 1, 2, 3], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=(4, 4, 1, [1, 1, 1, 1], [[[], [], 是], [[0], [], 是], [[1], [0, 1, 2, 3], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [], 是], [[1, 2], [0, 1, 2, 3], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [], 是], [[1, 3], [0, 1, 2, 3], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [], 是], [[1, 2, 3], [0, 1, 2, 3], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-constant-map-audit · candidate

73. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-constant-map-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[1],[0,2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"value":2}。請依 [source_n,target_n,value,mapping,preimage_rows,measurable] 欄序回答。

查看答案與解釋

(4, 4, 2, [2, 2, 2, 2], [[[], [], 是], [[0], [], 是], [[1], [], 是], [[0, 1], [], 是], [[2], [0, 1, 2, 3], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [0, 1, 2, 3], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [], 是], [[1, 3], [], 是], [[0, 1, 3], [], 是], [[2, 3], [0, 1, 2, 3], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1, 2, 3], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=(4, 4, 2, [2, 2, 2, 2], [[[], [], 是], [[0], [], 是], [[1], [], 是], [[0, 1], [], 是], [[2], [0, 1, 2, 3], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [0, 1, 2, 3], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [], 是], [[1, 3], [], 是], [[0, 1, 3], [], 是], [[2, 3], [0, 1, 2, 3], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1, 2, 3], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-constant-map-audit · candidate

74. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-constant-map-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[0,1],[2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"value":3}。請依 [source_n,target_n,value,mapping,preimage_rows,measurable] 欄序回答。

查看答案與解釋

(4, 4, 3, [3, 3, 3, 3], [[[], [], 是], [[0], [], 是], [[1], [], 是], [[0, 1], [], 是], [[2], [], 是], [[0, 2], [], 是], [[1, 2], [], 是], [[0, 1, 2], [], 是], [[3], [0, 1, 2, 3], 是], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [0, 1, 2, 3], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [0, 1, 2, 3], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1, 2, 3], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=(4, 4, 3, [3, 3, 3, 3], [[[], [], 是], [[0], [], 是], [[1], [], 是], [[0, 1], [], 是], [[2], [], 是], [[0, 2], [], 是], [[1, 2], [], 是], [[0, 1, 2], [], 是], [[3], [0, 1, 2, 3], 是], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [0, 1, 2, 3], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [0, 1, 2, 3], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1, 2, 3], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-constant-map-audit · candidate

75. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-constant-map-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[2],[0,1,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"value":0}。請依 [source_n,target_n,value,mapping,preimage_rows,measurable] 欄序回答。

查看答案與解釋

(4, 4, 0, [0, 0, 0, 0], [[[], [], 是], [[0], [0, 1, 2, 3], 是], [[1], [], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=(4, 4, 0, [0, 0, 0, 0], [[[], [], 是], [[0], [0, 1, 2, 3], 是], [[1], [], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-constant-map-audit · candidate

76. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-source-sigma-refinement-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[0],[1,2,3],[0,1,2,3]],"refined_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"mapping":[0,0,0,0]}。請依 [mapping,is_refinement,before_rows,before_measurable,after_rows,after_measurable] 欄序回答。

查看答案與解釋

([0, 0, 0, 0], 是, [[[], [], 是], [[0], [0, 1, 2, 3], 是], [[1], [], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是, [[[], [], 是], [[0], [0, 1, 2, 3], 是], [[1], [], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=([0, 0, 0, 0], 是, [[[], [], 是], [[0], [0, 1, 2, 3], 是], [[1], [], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是, [[[], [], 是], [[0], [0, 1, 2, 3], 是], [[1], [], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-source-sigma-refinement-audit · candidate

77. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-source-sigma-refinement-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[1],[0,2,3],[0,1,2,3]],"refined_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"mapping":[1,0,0,0]}。請依 [mapping,is_refinement,before_rows,before_measurable,after_rows,after_measurable] 欄序回答。

查看答案與解釋

([1, 0, 0, 0], 是, [[[], [], 是], [[0], [1, 2, 3], 否], [[1], [0], 否], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [1, 2, 3], 否], [[1, 2], [0], 否], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [1, 2, 3], 否], [[1, 3], [0], 否], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [1, 2, 3], 否], [[1, 2, 3], [0], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [1, 2, 3], 是], [[1], [0], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [1, 2, 3], 是], [[1, 2], [0], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [1, 2, 3], 是], [[1, 3], [0], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [1, 2, 3], 是], [[1, 2, 3], [0], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=([1, 0, 0, 0], 是, [[[], [], 是], [[0], [1, 2, 3], 否], [[1], [0], 否], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [1, 2, 3], 否], [[1, 2], [0], 否], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [1, 2, 3], 否], [[1, 3], [0], 否], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [1, 2, 3], 否], [[1, 2, 3], [0], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [1, 2, 3], 是], [[1], [0], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [1, 2, 3], 是], [[1, 2], [0], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [1, 2, 3], 是], [[1, 3], [0], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [1, 2, 3], 是], [[1, 2, 3], [0], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-source-sigma-refinement-audit · candidate

78. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-source-sigma-refinement-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[0,1],[2,3],[0,1,2,3]],"refined_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"mapping":[2,0,0,0]}。請依 [mapping,is_refinement,before_rows,before_measurable,after_rows,after_measurable] 欄序回答。

查看答案與解釋

([2, 0, 0, 0], 是, [[[], [], 是], [[0], [1, 2, 3], 否], [[1], [], 是], [[0, 1], [1, 2, 3], 否], [[2], [0], 否], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [0], 否], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [1, 2, 3], 否], [[1, 3], [], 是], [[0, 1, 3], [1, 2, 3], 否], [[2, 3], [0], 否], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [1, 2, 3], 是], [[1], [], 是], [[0, 1], [1, 2, 3], 是], [[2], [0], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [0], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [1, 2, 3], 是], [[1, 3], [], 是], [[0, 1, 3], [1, 2, 3], 是], [[2, 3], [0], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=([2, 0, 0, 0], 是, [[[], [], 是], [[0], [1, 2, 3], 否], [[1], [], 是], [[0, 1], [1, 2, 3], 否], [[2], [0], 否], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [0], 否], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [1, 2, 3], 否], [[1, 3], [], 是], [[0, 1, 3], [1, 2, 3], 否], [[2, 3], [0], 否], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [1, 2, 3], 是], [[1], [], 是], [[0, 1], [1, 2, 3], 是], [[2], [0], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [0], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [1, 2, 3], 是], [[1, 3], [], 是], [[0, 1, 3], [1, 2, 3], 是], [[2, 3], [0], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-source-sigma-refinement-audit · candidate

79. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-source-sigma-refinement-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[2],[0,1,3],[0,1,2,3]],"refined_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"mapping":[3,0,0,0]}。請依 [mapping,is_refinement,before_rows,before_measurable,after_rows,after_measurable] 欄序回答。

查看答案與解釋

([3, 0, 0, 0], 是, [[[], [], 是], [[0], [1, 2, 3], 否], [[1], [], 是], [[0, 1], [1, 2, 3], 否], [[2], [], 是], [[0, 2], [1, 2, 3], 否], [[1, 2], [], 是], [[0, 1, 2], [1, 2, 3], 否], [[3], [0], 否], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [0], 否], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [0], 否], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [1, 2, 3], 是], [[1], [], 是], [[0, 1], [1, 2, 3], 是], [[2], [], 是], [[0, 2], [1, 2, 3], 是], [[1, 2], [], 是], [[0, 1, 2], [1, 2, 3], 是], [[3], [0], 是], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [0], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [0], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=([3, 0, 0, 0], 是, [[[], [], 是], [[0], [1, 2, 3], 否], [[1], [], 是], [[0, 1], [1, 2, 3], 否], [[2], [], 是], [[0, 2], [1, 2, 3], 否], [[1, 2], [], 是], [[0, 1, 2], [1, 2, 3], 否], [[3], [0], 否], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [0], 否], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [0], 否], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [1, 2, 3], 是], [[1], [], 是], [[0, 1], [1, 2, 3], 是], [[2], [], 是], [[0, 2], [1, 2, 3], 是], [[1, 2], [], 是], [[0, 1, 2], [1, 2, 3], 是], [[3], [0], 是], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [0], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [0], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-source-sigma-refinement-audit · candidate

80. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-source-sigma-refinement-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[0,2],[1,3],[0,1,2,3]],"refined_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"mapping":[0,1,0,0]}。請依 [mapping,is_refinement,before_rows,before_measurable,after_rows,after_measurable] 欄序回答。

查看答案與解釋

([0, 1, 0, 0], 是, [[[], [], 是], [[0], [0, 2, 3], 否], [[1], [1], 否], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [0, 2, 3], 否], [[1, 2], [1], 否], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 2, 3], 否], [[1, 3], [1], 否], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [0, 2, 3], 否], [[1, 2, 3], [1], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [0, 2, 3], 是], [[1], [1], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [0, 2, 3], 是], [[1, 2], [1], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 2, 3], 是], [[1, 3], [1], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [0, 2, 3], 是], [[1, 2, 3], [1], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=([0, 1, 0, 0], 是, [[[], [], 是], [[0], [0, 2, 3], 否], [[1], [1], 否], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [0, 2, 3], 否], [[1, 2], [1], 否], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 2, 3], 否], [[1, 3], [1], 否], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [0, 2, 3], 否], [[1, 2, 3], [1], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [0, 2, 3], 是], [[1], [1], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [0, 2, 3], 是], [[1, 2], [1], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 2, 3], 是], [[1, 3], [1], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [0, 2, 3], 是], [[1, 2, 3], [1], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-source-sigma-refinement-audit · candidate

81. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-source-sigma-refinement-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[1,2],[0,3],[0,1,2,3]],"refined_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"mapping":[1,1,0,0]}。請依 [mapping,is_refinement,before_rows,before_measurable,after_rows,after_measurable] 欄序回答。

查看答案與解釋

([1, 1, 0, 0], 是, [[[], [], 是], [[0], [2, 3], 否], [[1], [0, 1], 否], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [2, 3], 否], [[1, 2], [0, 1], 否], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [2, 3], 否], [[1, 3], [0, 1], 否], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [2, 3], 否], [[1, 2, 3], [0, 1], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [2, 3], 是], [[1], [0, 1], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [2, 3], 是], [[1, 2], [0, 1], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [2, 3], 是], [[1, 3], [0, 1], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [2, 3], 是], [[1, 2, 3], [0, 1], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=([1, 1, 0, 0], 是, [[[], [], 是], [[0], [2, 3], 否], [[1], [0, 1], 否], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [2, 3], 否], [[1, 2], [0, 1], 否], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [2, 3], 否], [[1, 3], [0, 1], 否], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [2, 3], 否], [[1, 2, 3], [0, 1], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [2, 3], 是], [[1], [0, 1], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [2, 3], 是], [[1, 2], [0, 1], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [2, 3], 是], [[1, 3], [0, 1], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [2, 3], 是], [[1, 2, 3], [0, 1], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-source-sigma-refinement-audit · candidate

82. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-source-sigma-refinement-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[0,1,2],[3],[0,1,2,3]],"refined_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"mapping":[2,1,0,0]}。請依 [mapping,is_refinement,before_rows,before_measurable,after_rows,after_measurable] 欄序回答。

查看答案與解釋

([2, 1, 0, 0], 是, [[[], [], 是], [[0], [2, 3], 否], [[1], [1], 否], [[0, 1], [1, 2, 3], 否], [[2], [0], 否], [[0, 2], [0, 2, 3], 否], [[1, 2], [0, 1], 否], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [2, 3], 否], [[1, 3], [1], 否], [[0, 1, 3], [1, 2, 3], 否], [[2, 3], [0], 否], [[0, 2, 3], [0, 2, 3], 否], [[1, 2, 3], [0, 1], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [2, 3], 是], [[1], [1], 是], [[0, 1], [1, 2, 3], 是], [[2], [0], 是], [[0, 2], [0, 2, 3], 是], [[1, 2], [0, 1], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [2, 3], 是], [[1, 3], [1], 是], [[0, 1, 3], [1, 2, 3], 是], [[2, 3], [0], 是], [[0, 2, 3], [0, 2, 3], 是], [[1, 2, 3], [0, 1], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=([2, 1, 0, 0], 是, [[[], [], 是], [[0], [2, 3], 否], [[1], [1], 否], [[0, 1], [1, 2, 3], 否], [[2], [0], 否], [[0, 2], [0, 2, 3], 否], [[1, 2], [0, 1], 否], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [2, 3], 否], [[1, 3], [1], 否], [[0, 1, 3], [1, 2, 3], 否], [[2, 3], [0], 否], [[0, 2, 3], [0, 2, 3], 否], [[1, 2, 3], [0, 1], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [2, 3], 是], [[1], [1], 是], [[0, 1], [1, 2, 3], 是], [[2], [0], 是], [[0, 2], [0, 2, 3], 是], [[1, 2], [0, 1], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [2, 3], 是], [[1, 3], [1], 是], [[0, 1, 3], [1, 2, 3], 是], [[2, 3], [0], 是], [[0, 2, 3], [0, 2, 3], 是], [[1, 2, 3], [0, 1], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-source-sigma-refinement-audit · candidate

83. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-source-sigma-refinement-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[0],[1,2,3],[0,1,2,3]],"refined_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"mapping":[3,1,0,0]}。請依 [mapping,is_refinement,before_rows,before_measurable,after_rows,after_measurable] 欄序回答。

查看答案與解釋

([3, 1, 0, 0], 是, [[[], [], 是], [[0], [2, 3], 否], [[1], [1], 否], [[0, 1], [1, 2, 3], 是], [[2], [], 是], [[0, 2], [2, 3], 否], [[1, 2], [1], 否], [[0, 1, 2], [1, 2, 3], 是], [[3], [0], 是], [[0, 3], [0, 2, 3], 否], [[1, 3], [0, 1], 否], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [0], 是], [[0, 2, 3], [0, 2, 3], 否], [[1, 2, 3], [0, 1], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [2, 3], 是], [[1], [1], 是], [[0, 1], [1, 2, 3], 是], [[2], [], 是], [[0, 2], [2, 3], 是], [[1, 2], [1], 是], [[0, 1, 2], [1, 2, 3], 是], [[3], [0], 是], [[0, 3], [0, 2, 3], 是], [[1, 3], [0, 1], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [0], 是], [[0, 2, 3], [0, 2, 3], 是], [[1, 2, 3], [0, 1], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=([3, 1, 0, 0], 是, [[[], [], 是], [[0], [2, 3], 否], [[1], [1], 否], [[0, 1], [1, 2, 3], 是], [[2], [], 是], [[0, 2], [2, 3], 否], [[1, 2], [1], 否], [[0, 1, 2], [1, 2, 3], 是], [[3], [0], 是], [[0, 3], [0, 2, 3], 否], [[1, 3], [0, 1], 否], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [0], 是], [[0, 2, 3], [0, 2, 3], 否], [[1, 2, 3], [0, 1], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [2, 3], 是], [[1], [1], 是], [[0, 1], [1, 2, 3], 是], [[2], [], 是], [[0, 2], [2, 3], 是], [[1, 2], [1], 是], [[0, 1, 2], [1, 2, 3], 是], [[3], [0], 是], [[0, 3], [0, 2, 3], 是], [[1, 3], [0, 1], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [0], 是], [[0, 2, 3], [0, 2, 3], 是], [[1, 2, 3], [0, 1], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-source-sigma-refinement-audit · candidate

84. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-source-sigma-refinement-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[1],[0,2,3],[0,1,2,3]],"refined_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"mapping":[0,2,0,0]}。請依 [mapping,is_refinement,before_rows,before_measurable,after_rows,after_measurable] 欄序回答。

查看答案與解釋

([0, 2, 0, 0], 是, [[[], [], 是], [[0], [0, 2, 3], 是], [[1], [], 是], [[0, 1], [0, 2, 3], 是], [[2], [1], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [1], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 2, 3], 是], [[1, 3], [], 是], [[0, 1, 3], [0, 2, 3], 是], [[2, 3], [1], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [1], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是, [[[], [], 是], [[0], [0, 2, 3], 是], [[1], [], 是], [[0, 1], [0, 2, 3], 是], [[2], [1], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [1], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 2, 3], 是], [[1, 3], [], 是], [[0, 1, 3], [0, 2, 3], 是], [[2, 3], [1], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [1], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=([0, 2, 0, 0], 是, [[[], [], 是], [[0], [0, 2, 3], 是], [[1], [], 是], [[0, 1], [0, 2, 3], 是], [[2], [1], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [1], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 2, 3], 是], [[1, 3], [], 是], [[0, 1, 3], [0, 2, 3], 是], [[2, 3], [1], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [1], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是, [[[], [], 是], [[0], [0, 2, 3], 是], [[1], [], 是], [[0, 1], [0, 2, 3], 是], [[2], [1], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [1], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 2, 3], 是], [[1, 3], [], 是], [[0, 1, 3], [0, 2, 3], 是], [[2, 3], [1], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [1], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-source-sigma-refinement-audit · candidate

85. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-source-sigma-refinement-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[0,1],[2,3],[0,1,2,3]],"refined_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"mapping":[1,2,0,0]}。請依 [mapping,is_refinement,before_rows,before_measurable,after_rows,after_measurable] 欄序回答。

查看答案與解釋

([1, 2, 0, 0], 是, [[[], [], 是], [[0], [2, 3], 是], [[1], [0], 否], [[0, 1], [0, 2, 3], 否], [[2], [1], 否], [[0, 2], [1, 2, 3], 否], [[1, 2], [0, 1], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [2, 3], 是], [[1, 3], [0], 否], [[0, 1, 3], [0, 2, 3], 否], [[2, 3], [1], 否], [[0, 2, 3], [1, 2, 3], 否], [[1, 2, 3], [0, 1], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [2, 3], 是], [[1], [0], 是], [[0, 1], [0, 2, 3], 是], [[2], [1], 是], [[0, 2], [1, 2, 3], 是], [[1, 2], [0, 1], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [2, 3], 是], [[1, 3], [0], 是], [[0, 1, 3], [0, 2, 3], 是], [[2, 3], [1], 是], [[0, 2, 3], [1, 2, 3], 是], [[1, 2, 3], [0, 1], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=([1, 2, 0, 0], 是, [[[], [], 是], [[0], [2, 3], 是], [[1], [0], 否], [[0, 1], [0, 2, 3], 否], [[2], [1], 否], [[0, 2], [1, 2, 3], 否], [[1, 2], [0, 1], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [2, 3], 是], [[1, 3], [0], 否], [[0, 1, 3], [0, 2, 3], 否], [[2, 3], [1], 否], [[0, 2, 3], [1, 2, 3], 否], [[1, 2, 3], [0, 1], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [2, 3], 是], [[1], [0], 是], [[0, 1], [0, 2, 3], 是], [[2], [1], 是], [[0, 2], [1, 2, 3], 是], [[1, 2], [0, 1], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [2, 3], 是], [[1, 3], [0], 是], [[0, 1, 3], [0, 2, 3], 是], [[2, 3], [1], 是], [[0, 2, 3], [1, 2, 3], 是], [[1, 2, 3], [0, 1], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-source-sigma-refinement-audit · candidate

86. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-source-sigma-refinement-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[2],[0,1,3],[0,1,2,3]],"refined_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"mapping":[2,2,0,0]}。請依 [mapping,is_refinement,before_rows,before_measurable,after_rows,after_measurable] 欄序回答。

查看答案與解釋

([2, 2, 0, 0], 是, [[[], [], 是], [[0], [2, 3], 否], [[1], [], 是], [[0, 1], [2, 3], 否], [[2], [0, 1], 否], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [0, 1], 否], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [2, 3], 否], [[1, 3], [], 是], [[0, 1, 3], [2, 3], 否], [[2, 3], [0, 1], 否], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [2, 3], 是], [[1], [], 是], [[0, 1], [2, 3], 是], [[2], [0, 1], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [0, 1], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [2, 3], 是], [[1, 3], [], 是], [[0, 1, 3], [2, 3], 是], [[2, 3], [0, 1], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=([2, 2, 0, 0], 是, [[[], [], 是], [[0], [2, 3], 否], [[1], [], 是], [[0, 1], [2, 3], 否], [[2], [0, 1], 否], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [0, 1], 否], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [2, 3], 否], [[1, 3], [], 是], [[0, 1, 3], [2, 3], 否], [[2, 3], [0, 1], 否], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [2, 3], 是], [[1], [], 是], [[0, 1], [2, 3], 是], [[2], [0, 1], 是], [[0, 2], [0, 1, 2, 3], 是], [[1, 2], [0, 1], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [2, 3], 是], [[1, 3], [], 是], [[0, 1, 3], [2, 3], 是], [[2, 3], [0, 1], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-source-sigma-refinement-audit · candidate

87. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-source-sigma-refinement-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[0,2],[1,3],[0,1,2,3]],"refined_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"mapping":[3,2,0,0]}。請依 [mapping,is_refinement,before_rows,before_measurable,after_rows,after_measurable] 欄序回答。

查看答案與解釋

([3, 2, 0, 0], 是, [[[], [], 是], [[0], [2, 3], 否], [[1], [], 是], [[0, 1], [2, 3], 否], [[2], [1], 否], [[0, 2], [1, 2, 3], 否], [[1, 2], [1], 否], [[0, 1, 2], [1, 2, 3], 否], [[3], [0], 否], [[0, 3], [0, 2, 3], 否], [[1, 3], [0], 否], [[0, 1, 3], [0, 2, 3], 否], [[2, 3], [0, 1], 否], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [2, 3], 是], [[1], [], 是], [[0, 1], [2, 3], 是], [[2], [1], 是], [[0, 2], [1, 2, 3], 是], [[1, 2], [1], 是], [[0, 1, 2], [1, 2, 3], 是], [[3], [0], 是], [[0, 3], [0, 2, 3], 是], [[1, 3], [0], 是], [[0, 1, 3], [0, 2, 3], 是], [[2, 3], [0, 1], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=([3, 2, 0, 0], 是, [[[], [], 是], [[0], [2, 3], 否], [[1], [], 是], [[0, 1], [2, 3], 否], [[2], [1], 否], [[0, 2], [1, 2, 3], 否], [[1, 2], [1], 否], [[0, 1, 2], [1, 2, 3], 否], [[3], [0], 否], [[0, 3], [0, 2, 3], 否], [[1, 3], [0], 否], [[0, 1, 3], [0, 2, 3], 否], [[2, 3], [0, 1], 否], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [2, 3], 是], [[1], [], 是], [[0, 1], [2, 3], 是], [[2], [1], 是], [[0, 2], [1, 2, 3], 是], [[1, 2], [1], 是], [[0, 1, 2], [1, 2, 3], 是], [[3], [0], 是], [[0, 3], [0, 2, 3], 是], [[1, 3], [0], 是], [[0, 1, 3], [0, 2, 3], 是], [[2, 3], [0, 1], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-source-sigma-refinement-audit · candidate

88. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-source-sigma-refinement-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[1,2],[0,3],[0,1,2,3]],"refined_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"mapping":[0,3,0,0]}。請依 [mapping,is_refinement,before_rows,before_measurable,after_rows,after_measurable] 欄序回答。

查看答案與解釋

([0, 3, 0, 0], 是, [[[], [], 是], [[0], [0, 2, 3], 否], [[1], [], 是], [[0, 1], [0, 2, 3], 否], [[2], [], 是], [[0, 2], [0, 2, 3], 否], [[1, 2], [], 是], [[0, 1, 2], [0, 2, 3], 否], [[3], [1], 否], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [1], 否], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [1], 否], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [1], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [0, 2, 3], 是], [[1], [], 是], [[0, 1], [0, 2, 3], 是], [[2], [], 是], [[0, 2], [0, 2, 3], 是], [[1, 2], [], 是], [[0, 1, 2], [0, 2, 3], 是], [[3], [1], 是], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [1], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [1], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [1], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=([0, 3, 0, 0], 是, [[[], [], 是], [[0], [0, 2, 3], 否], [[1], [], 是], [[0, 1], [0, 2, 3], 否], [[2], [], 是], [[0, 2], [0, 2, 3], 否], [[1, 2], [], 是], [[0, 1, 2], [0, 2, 3], 否], [[3], [1], 否], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [1], 否], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [1], 否], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [1], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [0, 2, 3], 是], [[1], [], 是], [[0, 1], [0, 2, 3], 是], [[2], [], 是], [[0, 2], [0, 2, 3], 是], [[1, 2], [], 是], [[0, 1, 2], [0, 2, 3], 是], [[3], [1], 是], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [1], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [1], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [1], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-source-sigma-refinement-audit · candidate

89. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-source-sigma-refinement-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[0,1,2],[3],[0,1,2,3]],"refined_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"mapping":[1,3,0,0]}。請依 [mapping,is_refinement,before_rows,before_measurable,after_rows,after_measurable] 欄序回答。

查看答案與解釋

([1, 3, 0, 0], 是, [[[], [], 是], [[0], [2, 3], 否], [[1], [0], 否], [[0, 1], [0, 2, 3], 否], [[2], [], 是], [[0, 2], [2, 3], 否], [[1, 2], [0], 否], [[0, 1, 2], [0, 2, 3], 否], [[3], [1], 否], [[0, 3], [1, 2, 3], 否], [[1, 3], [0, 1], 否], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [1], 否], [[0, 2, 3], [1, 2, 3], 否], [[1, 2, 3], [0, 1], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [2, 3], 是], [[1], [0], 是], [[0, 1], [0, 2, 3], 是], [[2], [], 是], [[0, 2], [2, 3], 是], [[1, 2], [0], 是], [[0, 1, 2], [0, 2, 3], 是], [[3], [1], 是], [[0, 3], [1, 2, 3], 是], [[1, 3], [0, 1], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [1], 是], [[0, 2, 3], [1, 2, 3], 是], [[1, 2, 3], [0, 1], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=([1, 3, 0, 0], 是, [[[], [], 是], [[0], [2, 3], 否], [[1], [0], 否], [[0, 1], [0, 2, 3], 否], [[2], [], 是], [[0, 2], [2, 3], 否], [[1, 2], [0], 否], [[0, 1, 2], [0, 2, 3], 否], [[3], [1], 否], [[0, 3], [1, 2, 3], 否], [[1, 3], [0, 1], 否], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [1], 否], [[0, 2, 3], [1, 2, 3], 否], [[1, 2, 3], [0, 1], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [2, 3], 是], [[1], [0], 是], [[0, 1], [0, 2, 3], 是], [[2], [], 是], [[0, 2], [2, 3], 是], [[1, 2], [0], 是], [[0, 1, 2], [0, 2, 3], 是], [[3], [1], 是], [[0, 3], [1, 2, 3], 是], [[1, 3], [0, 1], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [1], 是], [[0, 2, 3], [1, 2, 3], 是], [[1, 2, 3], [0, 1], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-source-sigma-refinement-audit · candidate

90. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-source-sigma-refinement-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[0],[1,2,3],[0,1,2,3]],"refined_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"mapping":[2,3,0,0]}。請依 [mapping,is_refinement,before_rows,before_measurable,after_rows,after_measurable] 欄序回答。

查看答案與解釋

([2, 3, 0, 0], 是, [[[], [], 是], [[0], [2, 3], 否], [[1], [], 是], [[0, 1], [2, 3], 否], [[2], [0], 是], [[0, 2], [0, 2, 3], 否], [[1, 2], [0], 是], [[0, 1, 2], [0, 2, 3], 否], [[3], [1], 否], [[0, 3], [1, 2, 3], 是], [[1, 3], [1], 否], [[0, 1, 3], [1, 2, 3], 是], [[2, 3], [0, 1], 否], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [2, 3], 是], [[1], [], 是], [[0, 1], [2, 3], 是], [[2], [0], 是], [[0, 2], [0, 2, 3], 是], [[1, 2], [0], 是], [[0, 1, 2], [0, 2, 3], 是], [[3], [1], 是], [[0, 3], [1, 2, 3], 是], [[1, 3], [1], 是], [[0, 1, 3], [1, 2, 3], 是], [[2, 3], [0, 1], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=([2, 3, 0, 0], 是, [[[], [], 是], [[0], [2, 3], 否], [[1], [], 是], [[0, 1], [2, 3], 否], [[2], [0], 是], [[0, 2], [0, 2, 3], 否], [[1, 2], [0], 是], [[0, 1, 2], [0, 2, 3], 否], [[3], [1], 否], [[0, 3], [1, 2, 3], 是], [[1, 3], [1], 否], [[0, 1, 3], [1, 2, 3], 是], [[2, 3], [0, 1], 否], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [2, 3], 是], [[1], [], 是], [[0, 1], [2, 3], 是], [[2], [0], 是], [[0, 2], [0, 2, 3], 是], [[1, 2], [0], 是], [[0, 1, 2], [0, 2, 3], 是], [[3], [1], 是], [[0, 3], [1, 2, 3], 是], [[1, 3], [1], 是], [[0, 1, 3], [1, 2, 3], 是], [[2, 3], [0, 1], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-source-sigma-refinement-audit · candidate

91. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-source-sigma-refinement-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[1],[0,2,3],[0,1,2,3]],"refined_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"mapping":[3,3,0,0]}。請依 [mapping,is_refinement,before_rows,before_measurable,after_rows,after_measurable] 欄序回答。

查看答案與解釋

([3, 3, 0, 0], 是, [[[], [], 是], [[0], [2, 3], 否], [[1], [], 是], [[0, 1], [2, 3], 否], [[2], [], 是], [[0, 2], [2, 3], 否], [[1, 2], [], 是], [[0, 1, 2], [2, 3], 否], [[3], [0, 1], 否], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [0, 1], 否], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [0, 1], 否], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [2, 3], 是], [[1], [], 是], [[0, 1], [2, 3], 是], [[2], [], 是], [[0, 2], [2, 3], 是], [[1, 2], [], 是], [[0, 1, 2], [2, 3], 是], [[3], [0, 1], 是], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [0, 1], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [0, 1], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=([3, 3, 0, 0], 是, [[[], [], 是], [[0], [2, 3], 否], [[1], [], 是], [[0, 1], [2, 3], 否], [[2], [], 是], [[0, 2], [2, 3], 否], [[1, 2], [], 是], [[0, 1, 2], [2, 3], 否], [[3], [0, 1], 否], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [0, 1], 否], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [0, 1], 否], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [2, 3], 是], [[1], [], 是], [[0, 1], [2, 3], 是], [[2], [], 是], [[0, 2], [2, 3], 是], [[1, 2], [], 是], [[0, 1, 2], [2, 3], 是], [[3], [0, 1], 是], [[0, 3], [0, 1, 2, 3], 是], [[1, 3], [0, 1], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [0, 1], 是], [[0, 2, 3], [0, 1, 2, 3], 是], [[1, 2, 3], [0, 1], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-source-sigma-refinement-audit · candidate

92. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-source-sigma-refinement-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[0,1],[2,3],[0,1,2,3]],"refined_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"mapping":[0,0,1,0]}。請依 [mapping,is_refinement,before_rows,before_measurable,after_rows,after_measurable] 欄序回答。

查看答案與解釋

([0, 0, 1, 0], 是, [[[], [], 是], [[0], [0, 1, 3], 否], [[1], [2], 否], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [0, 1, 3], 否], [[1, 2], [2], 否], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 1, 3], 否], [[1, 3], [2], 否], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [0, 1, 3], 否], [[1, 2, 3], [2], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [0, 1, 3], 是], [[1], [2], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [0, 1, 3], 是], [[1, 2], [2], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 1, 3], 是], [[1, 3], [2], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [0, 1, 3], 是], [[1, 2, 3], [2], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=([0, 0, 1, 0], 是, [[[], [], 是], [[0], [0, 1, 3], 否], [[1], [2], 否], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [0, 1, 3], 否], [[1, 2], [2], 否], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 1, 3], 否], [[1, 3], [2], 否], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [0, 1, 3], 否], [[1, 2, 3], [2], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [0, 1, 3], 是], [[1], [2], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [0, 1, 3], 是], [[1, 2], [2], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 1, 3], 是], [[1, 3], [2], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [0, 1, 3], 是], [[1, 2, 3], [2], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-source-sigma-refinement-audit · candidate

93. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-source-sigma-refinement-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[2],[0,1,3],[0,1,2,3]],"refined_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"mapping":[1,0,1,0]}。請依 [mapping,is_refinement,before_rows,before_measurable,after_rows,after_measurable] 欄序回答。

查看答案與解釋

([1, 0, 1, 0], 是, [[[], [], 是], [[0], [1, 3], 否], [[1], [0, 2], 否], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [1, 3], 否], [[1, 2], [0, 2], 否], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [1, 3], 否], [[1, 3], [0, 2], 否], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [1, 3], 否], [[1, 2, 3], [0, 2], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [1, 3], 是], [[1], [0, 2], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [1, 3], 是], [[1, 2], [0, 2], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [1, 3], 是], [[1, 3], [0, 2], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [1, 3], 是], [[1, 2, 3], [0, 2], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=([1, 0, 1, 0], 是, [[[], [], 是], [[0], [1, 3], 否], [[1], [0, 2], 否], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [1, 3], 否], [[1, 2], [0, 2], 否], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [1, 3], 否], [[1, 3], [0, 2], 否], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [1, 3], 否], [[1, 2, 3], [0, 2], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [1, 3], 是], [[1], [0, 2], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [1, 3], 是], [[1, 2], [0, 2], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [1, 3], 是], [[1, 3], [0, 2], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [1, 3], 是], [[1, 2, 3], [0, 2], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-source-sigma-refinement-audit · candidate

94. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-source-sigma-refinement-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[0,2],[1,3],[0,1,2,3]],"refined_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"mapping":[2,0,1,0]}。請依 [mapping,is_refinement,before_rows,before_measurable,after_rows,after_measurable] 欄序回答。

查看答案與解釋

([2, 0, 1, 0], 是, [[[], [], 是], [[0], [1, 3], 是], [[1], [2], 否], [[0, 1], [1, 2, 3], 否], [[2], [0], 否], [[0, 2], [0, 1, 3], 否], [[1, 2], [0, 2], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [1, 3], 是], [[1, 3], [2], 否], [[0, 1, 3], [1, 2, 3], 否], [[2, 3], [0], 否], [[0, 2, 3], [0, 1, 3], 否], [[1, 2, 3], [0, 2], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [1, 3], 是], [[1], [2], 是], [[0, 1], [1, 2, 3], 是], [[2], [0], 是], [[0, 2], [0, 1, 3], 是], [[1, 2], [0, 2], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [1, 3], 是], [[1, 3], [2], 是], [[0, 1, 3], [1, 2, 3], 是], [[2, 3], [0], 是], [[0, 2, 3], [0, 1, 3], 是], [[1, 2, 3], [0, 2], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=([2, 0, 1, 0], 是, [[[], [], 是], [[0], [1, 3], 是], [[1], [2], 否], [[0, 1], [1, 2, 3], 否], [[2], [0], 否], [[0, 2], [0, 1, 3], 否], [[1, 2], [0, 2], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [1, 3], 是], [[1, 3], [2], 否], [[0, 1, 3], [1, 2, 3], 否], [[2, 3], [0], 否], [[0, 2, 3], [0, 1, 3], 否], [[1, 2, 3], [0, 2], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [1, 3], 是], [[1], [2], 是], [[0, 1], [1, 2, 3], 是], [[2], [0], 是], [[0, 2], [0, 1, 3], 是], [[1, 2], [0, 2], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [1, 3], 是], [[1, 3], [2], 是], [[0, 1, 3], [1, 2, 3], 是], [[2, 3], [0], 是], [[0, 2, 3], [0, 1, 3], 是], [[1, 2, 3], [0, 2], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-source-sigma-refinement-audit · candidate

95. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-source-sigma-refinement-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[1,2],[0,3],[0,1,2,3]],"refined_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"mapping":[3,0,1,0]}。請依 [mapping,is_refinement,before_rows,before_measurable,after_rows,after_measurable] 欄序回答。

查看答案與解釋

([3, 0, 1, 0], 是, [[[], [], 是], [[0], [1, 3], 否], [[1], [2], 否], [[0, 1], [1, 2, 3], 否], [[2], [], 是], [[0, 2], [1, 3], 否], [[1, 2], [2], 否], [[0, 1, 2], [1, 2, 3], 否], [[3], [0], 否], [[0, 3], [0, 1, 3], 否], [[1, 3], [0, 2], 否], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [0], 否], [[0, 2, 3], [0, 1, 3], 否], [[1, 2, 3], [0, 2], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [1, 3], 是], [[1], [2], 是], [[0, 1], [1, 2, 3], 是], [[2], [], 是], [[0, 2], [1, 3], 是], [[1, 2], [2], 是], [[0, 1, 2], [1, 2, 3], 是], [[3], [0], 是], [[0, 3], [0, 1, 3], 是], [[1, 3], [0, 2], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [0], 是], [[0, 2, 3], [0, 1, 3], 是], [[1, 2, 3], [0, 2], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=([3, 0, 1, 0], 是, [[[], [], 是], [[0], [1, 3], 否], [[1], [2], 否], [[0, 1], [1, 2, 3], 否], [[2], [], 是], [[0, 2], [1, 3], 否], [[1, 2], [2], 否], [[0, 1, 2], [1, 2, 3], 否], [[3], [0], 否], [[0, 3], [0, 1, 3], 否], [[1, 3], [0, 2], 否], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [0], 否], [[0, 2, 3], [0, 1, 3], 否], [[1, 2, 3], [0, 2], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [1, 3], 是], [[1], [2], 是], [[0, 1], [1, 2, 3], 是], [[2], [], 是], [[0, 2], [1, 3], 是], [[1, 2], [2], 是], [[0, 1, 2], [1, 2, 3], 是], [[3], [0], 是], [[0, 3], [0, 1, 3], 是], [[1, 3], [0, 2], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [0], 是], [[0, 2, 3], [0, 1, 3], 是], [[1, 2, 3], [0, 2], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-source-sigma-refinement-audit · candidate

96. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-source-sigma-refinement-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[0,1,2],[3],[0,1,2,3]],"refined_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"mapping":[0,1,1,0]}。請依 [mapping,is_refinement,before_rows,before_measurable,after_rows,after_measurable] 欄序回答。

查看答案與解釋

([0, 1, 1, 0], 是, [[[], [], 是], [[0], [0, 3], 否], [[1], [1, 2], 否], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [0, 3], 否], [[1, 2], [1, 2], 否], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 3], 否], [[1, 3], [1, 2], 否], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [0, 3], 否], [[1, 2, 3], [1, 2], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [0, 3], 是], [[1], [1, 2], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [0, 3], 是], [[1, 2], [1, 2], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 3], 是], [[1, 3], [1, 2], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [0, 3], 是], [[1, 2, 3], [1, 2], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=([0, 1, 1, 0], 是, [[[], [], 是], [[0], [0, 3], 否], [[1], [1, 2], 否], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [0, 3], 否], [[1, 2], [1, 2], 否], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 3], 否], [[1, 3], [1, 2], 否], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [0, 3], 否], [[1, 2, 3], [1, 2], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [0, 3], 是], [[1], [1, 2], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [0, 3], 是], [[1, 2], [1, 2], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 3], 是], [[1, 3], [1, 2], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [0, 3], 是], [[1, 2, 3], [1, 2], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-source-sigma-refinement-audit · candidate

97. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-source-sigma-refinement-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[0],[1,2,3],[0,1,2,3]],"refined_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"mapping":[1,1,1,0]}。請依 [mapping,is_refinement,before_rows,before_measurable,after_rows,after_measurable] 欄序回答。

查看答案與解釋

([1, 1, 1, 0], 是, [[[], [], 是], [[0], [3], 否], [[1], [0, 1, 2], 否], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [3], 否], [[1, 2], [0, 1, 2], 否], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [3], 否], [[1, 3], [0, 1, 2], 否], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [3], 否], [[1, 2, 3], [0, 1, 2], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [3], 是], [[1], [0, 1, 2], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [3], 是], [[1, 2], [0, 1, 2], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [3], 是], [[1, 3], [0, 1, 2], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [3], 是], [[1, 2, 3], [0, 1, 2], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=([1, 1, 1, 0], 是, [[[], [], 是], [[0], [3], 否], [[1], [0, 1, 2], 否], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [3], 否], [[1, 2], [0, 1, 2], 否], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [3], 否], [[1, 3], [0, 1, 2], 否], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [3], 否], [[1, 2, 3], [0, 1, 2], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [3], 是], [[1], [0, 1, 2], 是], [[0, 1], [0, 1, 2, 3], 是], [[2], [], 是], [[0, 2], [3], 是], [[1, 2], [0, 1, 2], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [3], 是], [[1, 3], [0, 1, 2], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [], 是], [[0, 2, 3], [3], 是], [[1, 2, 3], [0, 1, 2], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-source-sigma-refinement-audit · candidate

98. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-source-sigma-refinement-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[1],[0,2,3],[0,1,2,3]],"refined_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"mapping":[2,1,1,0]}。請依 [mapping,is_refinement,before_rows,before_measurable,after_rows,after_measurable] 欄序回答。

查看答案與解釋

([2, 1, 1, 0], 是, [[[], [], 是], [[0], [3], 否], [[1], [1, 2], 否], [[0, 1], [1, 2, 3], 否], [[2], [0], 否], [[0, 2], [0, 3], 否], [[1, 2], [0, 1, 2], 否], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [3], 否], [[1, 3], [1, 2], 否], [[0, 1, 3], [1, 2, 3], 否], [[2, 3], [0], 否], [[0, 2, 3], [0, 3], 否], [[1, 2, 3], [0, 1, 2], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [3], 是], [[1], [1, 2], 是], [[0, 1], [1, 2, 3], 是], [[2], [0], 是], [[0, 2], [0, 3], 是], [[1, 2], [0, 1, 2], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [3], 是], [[1, 3], [1, 2], 是], [[0, 1, 3], [1, 2, 3], 是], [[2, 3], [0], 是], [[0, 2, 3], [0, 3], 是], [[1, 2, 3], [0, 1, 2], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=([2, 1, 1, 0], 是, [[[], [], 是], [[0], [3], 否], [[1], [1, 2], 否], [[0, 1], [1, 2, 3], 否], [[2], [0], 否], [[0, 2], [0, 3], 否], [[1, 2], [0, 1, 2], 否], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [3], 否], [[1, 3], [1, 2], 否], [[0, 1, 3], [1, 2, 3], 否], [[2, 3], [0], 否], [[0, 2, 3], [0, 3], 否], [[1, 2, 3], [0, 1, 2], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [3], 是], [[1], [1, 2], 是], [[0, 1], [1, 2, 3], 是], [[2], [0], 是], [[0, 2], [0, 3], 是], [[1, 2], [0, 1, 2], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [3], 是], [[1, 3], [1, 2], 是], [[0, 1, 3], [1, 2, 3], 是], [[2, 3], [0], 是], [[0, 2, 3], [0, 3], 是], [[1, 2, 3], [0, 1, 2], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-source-sigma-refinement-audit · candidate

99. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-source-sigma-refinement-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[0,1],[2,3],[0,1,2,3]],"refined_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"mapping":[3,1,1,0]}。請依 [mapping,is_refinement,before_rows,before_measurable,after_rows,after_measurable] 欄序回答。

查看答案與解釋

([3, 1, 1, 0], 是, [[[], [], 是], [[0], [3], 否], [[1], [1, 2], 否], [[0, 1], [1, 2, 3], 否], [[2], [], 是], [[0, 2], [3], 否], [[1, 2], [1, 2], 否], [[0, 1, 2], [1, 2, 3], 否], [[3], [0], 否], [[0, 3], [0, 3], 否], [[1, 3], [0, 1, 2], 否], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [0], 否], [[0, 2, 3], [0, 3], 否], [[1, 2, 3], [0, 1, 2], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [3], 是], [[1], [1, 2], 是], [[0, 1], [1, 2, 3], 是], [[2], [], 是], [[0, 2], [3], 是], [[1, 2], [1, 2], 是], [[0, 1, 2], [1, 2, 3], 是], [[3], [0], 是], [[0, 3], [0, 3], 是], [[1, 3], [0, 1, 2], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [0], 是], [[0, 2, 3], [0, 3], 是], [[1, 2, 3], [0, 1, 2], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=([3, 1, 1, 0], 是, [[[], [], 是], [[0], [3], 否], [[1], [1, 2], 否], [[0, 1], [1, 2, 3], 否], [[2], [], 是], [[0, 2], [3], 否], [[1, 2], [1, 2], 否], [[0, 1, 2], [1, 2, 3], 否], [[3], [0], 否], [[0, 3], [0, 3], 否], [[1, 3], [0, 1, 2], 否], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [0], 否], [[0, 2, 3], [0, 3], 否], [[1, 2, 3], [0, 1, 2], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [3], 是], [[1], [1, 2], 是], [[0, 1], [1, 2, 3], 是], [[2], [], 是], [[0, 2], [3], 是], [[1, 2], [1, 2], 是], [[0, 1, 2], [1, 2, 3], 是], [[3], [0], 是], [[0, 3], [0, 3], 是], [[1, 3], [0, 1, 2], 是], [[0, 1, 3], [0, 1, 2, 3], 是], [[2, 3], [0], 是], [[0, 2, 3], [0, 3], 是], [[1, 2, 3], [0, 1, 2], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-source-sigma-refinement-audit · candidate

100. 可測函數密度

完整有限sigma代數與總映射。操作=measdeep-source-sigma-refinement-audit;資料={"source_n":4,"target_n":4,"source_sigma":[[],[2],[0,1,3],[0,1,2,3]],"refined_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"target_sigma":[[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,2],[3],[0,3],[1,3],[0,1,3],[2,3],[0,2,3],[1,2,3],[0,1,2,3]],"mapping":[0,2,1,0]}。請依 [mapping,is_refinement,before_rows,before_measurable,after_rows,after_measurable] 欄序回答。

查看答案與解釋

([0, 2, 1, 0], 是, [[[], [], 是], [[0], [0, 3], 否], [[1], [2], 是], [[0, 1], [0, 2, 3], 否], [[2], [1], 否], [[0, 2], [0, 1, 3], 是], [[1, 2], [1, 2], 否], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 3], 否], [[1, 3], [2], 是], [[0, 1, 3], [0, 2, 3], 否], [[2, 3], [1], 否], [[0, 2, 3], [0, 1, 3], 是], [[1, 2, 3], [1, 2], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [0, 3], 是], [[1], [2], 是], [[0, 1], [0, 2, 3], 是], [[2], [1], 是], [[0, 2], [0, 1, 3], 是], [[1, 2], [1, 2], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 3], 是], [[1, 3], [2], 是], [[0, 1, 3], [0, 2, 3], 是], [[2, 3], [1], 是], [[0, 2, 3], [0, 1, 3], 是], [[1, 2, 3], [1, 2], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是)

收束波核對=([0, 2, 1, 0], 是, [[[], [], 是], [[0], [0, 3], 否], [[1], [2], 是], [[0, 1], [0, 2, 3], 否], [[2], [1], 否], [[0, 2], [0, 1, 3], 是], [[1, 2], [1, 2], 否], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 3], 否], [[1, 3], [2], 是], [[0, 1, 3], [0, 2, 3], 否], [[2, 3], [1], 否], [[0, 2, 3], [0, 1, 3], 是], [[1, 2, 3], [1, 2], 否], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 否, [[[], [], 是], [[0], [0, 3], 是], [[1], [2], 是], [[0, 1], [0, 2, 3], 是], [[2], [1], 是], [[0, 2], [0, 1, 3], 是], [[1, 2], [1, 2], 是], [[0, 1, 2], [0, 1, 2, 3], 是], [[3], [], 是], [[0, 3], [0, 3], 是], [[1, 3], [2], 是], [[0, 1, 3], [0, 2, 3], 是], [[2, 3], [1], 是], [[0, 2, 3], [0, 1, 3], 是], [[1, 2, 3], [1, 2], 是], [[0, 1, 2, 3], [0, 1, 2, 3], 是]], 是);依完整明示資料重算;精確有限切片不自動升格為一般無限結論;集合律一律由逆像核對;不推出連續可積保測或無限空間結論。

本題逐步詳解(AI 二次覆核)

可測函數 · qf-mod25-measdeep-source-sigma-refinement-audit · candidate

原始題目 JSONL · 驗收報告