逐步推導
S001 · implies
操作前
source roles = [qf-quadratic-exact-roots, exact_roots]
操作後
derived = [[increasing_reduced_positive_denominator_root_SET_retaining1]]
條件:無
此頁明列本題scalar/label/set/point或mode欄序,不強套現代tuple。舊題domain與operation底線格式按原資料,分數整數亦保/1;原中英快照不改。
步驟識別與依賴
規則:source_answer_roles_or_ordered_fields_without_JS · 依賴:G001
S002 · calculation
操作前
Legacy quadratic ORIGINAL b squared := mul(0, 0)
操作後
Legacy quadratic ORIGINAL b squared = 0
條件:無
按原始角色精確代值,不作浮點近似或換操作數;額外教學等式不另縮原題域。
步驟識別與依賴
規則:exact_rational_arithmetic · 依賴:G001, S001
S003 · calculation
操作前
Legacy quadratic ORIGINAL a times c := mul(6, -6)
操作後
Legacy quadratic ORIGINAL a times c = -36
條件:無
按原始角色精確代值,不作浮點近似或換操作數;額外教學等式不另縮原題域。
步驟識別與依賴
規則:exact_rational_arithmetic · 依賴:G001, S002
S004 · calculation
操作前
Legacy quadratic ORIGINAL four times ac := mul(4, -36)
操作後
Legacy quadratic ORIGINAL four times ac = -144
條件:無
按原始角色精確代值,不作浮點近似或換操作數;額外教學等式不另縮原題域。
步驟識別與依賴
規則:exact_rational_arithmetic · 依賴:G001, S003
S005 · calculation
操作前
Legacy quadratic ORIGINAL b squared minus fourac := sub(0, -144)
操作後
Legacy quadratic ORIGINAL b squared minus fourac = 144
條件:無
按原始角色精確代值,不作浮點近似或換操作數;額外教學等式不另縮原題域。
步驟識別與依賴
規則:exact_rational_arithmetic · 依賴:G001, S004
S006 · implies
操作前
source roles = [6, 0, -6, 144]
操作後
derived = [4a*(a*x^2+b*x+c)=(2a*x+b)^2-D, 2]
條件:無
a非0使4a可逆,方程等價(2ax+b)²=D。D<0無實根,D0一個值,D>0兩個相異值;重根只算一次,D為不設衍生SAFE上限的BigInt。
步驟識別與依賴
規則:Legacy_quadratic_GENERAL_complete_square_iff_DISTINCT_real_roots · 依賴:G001, S005
S007 · calculation
操作前
Legacy quadratic DERIVED discriminant exact midpoint square0 := mul(72, 72)
操作後
Legacy quadratic DERIVED discriminant exact midpoint square0 = 5184
條件:無
按原始角色精確代值,不作浮點近似或換操作數;額外教學等式不另縮原題域。
步驟識別與依賴
規則:exact_rational_arithmetic · 依賴:G001, S006
S008 · implies
操作前
source roles = [Legacy quadratic DERIVED discriminant, 144, 0, [0, 145], 72]
操作後
derived = [5184, 否, 0, 72]
條件:無
在非負整數上square單調,保持low²<=n<high²;mid是BigInt floor((low+high)/2),不用浮點sqrt,嚴格縮小整數bracket。衍生值不重套SAFE。
步驟識別與依賴
規則:Legacy_isqrt_EACH_BigInt_integer_midpoint_bracket · 依賴:G001, S007
S009 · calculation
操作前
Legacy quadratic DERIVED discriminant exact midpoint square1 := mul(36, 36)
操作後
Legacy quadratic DERIVED discriminant exact midpoint square1 = 1296
條件:無
按原始角色精確代值,不作浮點近似或換操作數;額外教學等式不另縮原題域。
步驟識別與依賴
規則:exact_rational_arithmetic · 依賴:G001, S008
S010 · implies
操作前
source roles = [Legacy quadratic DERIVED discriminant, 144, 1, [0, 72], 36]
操作後
derived = [1296, 否, 0, 36]
條件:無
在非負整數上square單調,保持low²<=n<high²;mid是BigInt floor((low+high)/2),不用浮點sqrt,嚴格縮小整數bracket。衍生值不重套SAFE。
步驟識別與依賴
規則:Legacy_isqrt_EACH_BigInt_integer_midpoint_bracket · 依賴:G001, S009
S011 · calculation
操作前
Legacy quadratic DERIVED discriminant exact midpoint square2 := mul(18, 18)
操作後
Legacy quadratic DERIVED discriminant exact midpoint square2 = 324
條件:無
按原始角色精確代值,不作浮點近似或換操作數;額外教學等式不另縮原題域。
步驟識別與依賴
規則:exact_rational_arithmetic · 依賴:G001, S010
S012 · implies
操作前
source roles = [Legacy quadratic DERIVED discriminant, 144, 2, [0, 36], 18]
操作後
derived = [324, 否, 0, 18]
條件:無
在非負整數上square單調,保持low²<=n<high²;mid是BigInt floor((low+high)/2),不用浮點sqrt,嚴格縮小整數bracket。衍生值不重套SAFE。
步驟識別與依賴
規則:Legacy_isqrt_EACH_BigInt_integer_midpoint_bracket · 依賴:G001, S011
S013 · calculation
操作前
Legacy quadratic DERIVED discriminant exact midpoint square3 := mul(9, 9)
操作後
Legacy quadratic DERIVED discriminant exact midpoint square3 = 81
條件:無
按原始角色精確代值,不作浮點近似或換操作數;額外教學等式不另縮原題域。
步驟識別與依賴
規則:exact_rational_arithmetic · 依賴:G001, S012
S014 · implies
操作前
source roles = [Legacy quadratic DERIVED discriminant, 144, 3, [0, 18], 9]
操作後
derived = [81, 是, 9, 18]
條件:無
在非負整數上square單調,保持low²<=n<high²;mid是BigInt floor((low+high)/2),不用浮點sqrt,嚴格縮小整數bracket。衍生值不重套SAFE。
步驟識別與依賴
規則:Legacy_isqrt_EACH_BigInt_integer_midpoint_bracket · 依賴:G001, S013
S015 · calculation
操作前
Legacy quadratic DERIVED discriminant exact midpoint square4 := mul(13, 13)
操作後
Legacy quadratic DERIVED discriminant exact midpoint square4 = 169
條件:無
按原始角色精確代值,不作浮點近似或換操作數;額外教學等式不另縮原題域。
步驟識別與依賴
規則:exact_rational_arithmetic · 依賴:G001, S014
S016 · implies
操作前
source roles = [Legacy quadratic DERIVED discriminant, 144, 4, [9, 18], 13]
操作後
derived = [169, 否, 9, 13]
條件:無
在非負整數上square單調,保持low²<=n<high²;mid是BigInt floor((low+high)/2),不用浮點sqrt,嚴格縮小整數bracket。衍生值不重套SAFE。
步驟識別與依賴
規則:Legacy_isqrt_EACH_BigInt_integer_midpoint_bracket · 依賴:G001, S015
S017 · calculation
操作前
Legacy quadratic DERIVED discriminant exact midpoint square5 := mul(11, 11)
操作後
Legacy quadratic DERIVED discriminant exact midpoint square5 = 121
條件:無
按原始角色精確代值,不作浮點近似或換操作數;額外教學等式不另縮原題域。
步驟識別與依賴
規則:exact_rational_arithmetic · 依賴:G001, S016
S018 · implies
操作前
source roles = [Legacy quadratic DERIVED discriminant, 144, 5, [9, 13], 11]
操作後
derived = [121, 是, 11, 13]
條件:無
在非負整數上square單調,保持low²<=n<high²;mid是BigInt floor((low+high)/2),不用浮點sqrt,嚴格縮小整數bracket。衍生值不重套SAFE。
步驟識別與依賴
規則:Legacy_isqrt_EACH_BigInt_integer_midpoint_bracket · 依賴:G001, S017
S019 · calculation
操作前
Legacy quadratic DERIVED discriminant exact midpoint square6 := mul(12, 12)
操作後
Legacy quadratic DERIVED discriminant exact midpoint square6 = 144
條件:無
按原始角色精確代值,不作浮點近似或換操作數;額外教學等式不另縮原題域。
步驟識別與依賴
規則:exact_rational_arithmetic · 依賴:G001, S018
S020 · implies
操作前
source roles = [Legacy quadratic DERIVED discriminant, 144, 6, [11, 13], 12]
操作後
derived = [144, 是, 12, 13]
條件:無
在非負整數上square單調,保持low²<=n<high²;mid是BigInt floor((low+high)/2),不用浮點sqrt,嚴格縮小整數bracket。衍生值不重套SAFE。
步驟識別與依賴
規則:Legacy_isqrt_EACH_BigInt_integer_midpoint_bracket · 依賴:G001, S019
S021 · calculation
操作前
Legacy quadratic DERIVED discriminant terminal root square := mul(12, 12)
操作後
Legacy quadratic DERIVED discriminant terminal root square = 144
條件:無
按原始角色精確代值,不作浮點近似或換操作數;額外教學等式不另縮原題域。
步驟識別與依賴
規則:exact_rational_arithmetic · 依賴:G001, S020
S022 · calculation
操作前
Legacy quadratic DERIVED discriminant terminal successor square := mul(13, 13)
操作後
Legacy quadratic DERIVED discriminant terminal successor square = 169
條件:無
按原始角色精確代值,不作浮點近似或換操作數;額外教學等式不另縮原題域。
步驟識別與依賴
規則:exact_rational_arithmetic · 依賴:G001, S021
S023 · implies
操作前
source roles = [Legacy quadratic DERIVED discriminant, 144, 12, 13]
操作後
derived = [144, 169]
條件:無
相鄰整數bracket證floor sqrt=low;exact root另核low²=n,主平方根只取非負分支。
步驟識別與依賴
規則:Legacy_isqrt_terminal_floor_and_single_nonnegative_branch · 依賴:G001, S022
S024 · calculation
操作前
Legacy quadratic ORIGINAL negated b := sub(0, 0)
操作後
Legacy quadratic ORIGINAL negated b = 0
條件:無
按原始角色精確代值,不作浮點近似或換操作數;額外教學等式不另縮原題域。
步驟識別與依賴
規則:exact_rational_arithmetic · 依賴:G001, S023
S025 · calculation
操作前
Legacy quadratic ORIGINAL minus numerator := sub(0, 12)
操作後
Legacy quadratic ORIGINAL minus numerator = -12
條件:無
按原始角色精確代值,不作浮點近似或換操作數;額外教學等式不另縮原題域。
步驟識別與依賴
規則:exact_rational_arithmetic · 依賴:G001, S024
S026 · calculation
操作前
Legacy quadratic ORIGINAL plus numerator := sum(0, 12)
操作後
Legacy quadratic ORIGINAL plus numerator = 12
條件:無
按原始角色精確代值,不作浮點近似或換操作數;額外教學等式不另縮原題域。
步驟識別與依賴
規則:exact_rational_arithmetic · 依賴:G001, S025
S027 · calculation
操作前
Legacy quadratic ORIGINAL denominator2a := mul(2, 6)
操作後
Legacy quadratic ORIGINAL denominator2a = 12
條件:無
按原始角色精確代值,不作浮點近似或換操作數;額外教學等式不另縮原題域。
步驟識別與依賴
規則:exact_rational_arithmetic · 依賴:G001, S026
S028 · calculation
操作前
Legacy quadratic ORIGINAL raw rational branch0 := div(-12, 12)
操作後
Legacy quadratic ORIGINAL raw rational branch0 = -1
條件:無
按原始角色精確代值,不作浮點近似或換操作數;額外教學等式不另縮原題域。
步驟識別與依賴
規則:exact_rational_arithmetic · 依賴:G001, S027
S029 · implies
操作前
source roles = [0, -12, 12]
操作後
derived = [-1, 1, -1/1]
條件:無
對每個原branch normalize分母正號與gcd;原den2a可負,衍生num/den不重套SAFE,整數仍顯示p/1。
步驟識別與依賴
規則:Legacy_quadratic_EACH_raw_branch_positive_den_gcd_normalization · 依賴:G001, S028
S030 · calculation
操作前
Legacy quadratic ORIGINAL raw rational branch1 := div(12, 12)
操作後
Legacy quadratic ORIGINAL raw rational branch1 = 1
條件:無
按原始角色精確代值,不作浮點近似或換操作數;額外教學等式不另縮原題域。
步驟識別與依賴
規則:exact_rational_arithmetic · 依賴:G001, S029
S031 · implies
操作前
source roles = [1, 12, 12]
操作後
derived = [1, 1, 1/1]
條件:無
對每個原branch normalize分母正號與gcd;原den2a可負,衍生num/den不重套SAFE,整數仍顯示p/1。
步驟識別與依賴
規則:Legacy_quadratic_EACH_raw_branch_positive_den_gcd_normalization · 依賴:G001, S030
S032 · implies
操作前
source roles = [6, 144, [-1/1, 1/1]]
操作後
derived = [[-1/1, 1/1], {-1/1, 1/1}]條件:無
按有理數實值/cross products排序,不能lexical或假設minus branch一定較小(a負會反向)。D0的兩個branch同值只列一次;完整square iff也證沒有漏根。
步驟識別與依賴
規則:Legacy_quadratic_EXACT_numeric_sort_and_D0_set_dedup · 依賴:G001, S031