S001 · calculation
操作前
quotient ring parent modulus divided by ideal generator := div(8, 4)
操作後
quotient ring parent modulus divided by ideal generator = 2
條件:無
依原始角色及已核中間量精確計算,保留索引、符號、分母與運算所在載體。
步驟識別與依賴
規則:exact_rational_arithmetic · 依賴:G001
R0030-15953 · q-20261014-advance-20261031-r04-finite-quotient-ring-0053
Z_n與proper雙邊理想的全部加法cosets。操作=quotring-multiply;資料={"n":8,"d":4,"a":2,"b":5}。請依 [class_a,class_b,parent_result,result_class,law] 欄序回答。
G001 — Z_n與proper雙邊理想的全部加法cosets。操作=quotring-multiply;資料={"n":8,"d":4,"a":2,"b":5}。請依 [class_a,class_b,parent_result,result_class,law] 欄序回答。沿用原題明示的論域、假設與來源 MKO 定義。本題已完成第二對話數理與中英語義覆核,並由原始參數逐題獨立重算模型、答案與每個算術步驟;原題仍為 candidate。
操作前
quotient ring parent modulus divided by ideal generator := div(8, 4)
操作後
quotient ring parent modulus divided by ideal generator = 2
條件:無
依原始角色及已核中間量精確計算,保留索引、符號、分母與運算所在載體。
規則:exact_rational_arithmetic · 依賴:G001
操作前
same declared parent Z_8;generator d=4;n/d=2;ideal multiples=[0, 4]
操作後
I=kernel of residue map Z_8 to Z_4;proper two-sided ideal=是;zero ideal allowed when d=n
條件:無
因d整除n,整數代表改加n仍不改mod d,π:Z_n→Z_d良定且保加乘。核I由d倍數組成,加法差封閉且左右乘任意母環元素仍在I。d≥2使1不在I,故proper;d=n可得零理想,不把它排除。
規則:quotient_ring_actual_parent_proper_two_sided_ideal · 依賴:G001, S001
操作前
complete parent residues=[0, 1, 2, 3, 4, 5, 6, 7];same ideal I=[0, 4]
操作後
all additive cosets in representative order0..d-1=[[0, 4], [1, 5], [2, 6], [3, 7]];quotient size=4;no field conclusion
條件:無
每個加法coset列全體同餘mod d的母環元素,按代表0..d−1排序;它們互斥且覆蓋Z_n。商元素是整類,輸出class標籤只是索引,不因有限商環就宣稱域。
規則:quotient_ring_full_cosets_not_representative_carrier · 依賴:G001, S002
操作前
first input coset exact quotient fraction := div(2, 4)
操作後
first input coset exact quotient fraction = 1/2
條件:無
依原始角色及已核中間量精確計算,保留索引、符號、分母與運算所在載體。
規則:exact_rational_arithmetic · 依賴:G001, S003
操作前
first input coset:integer value=2;positive modulus=4;exact ratio=1/2
操作後
floor quotient=0;quotient<=ratio<quotient+1
條件:無
先取有理商再取向下整數商q,不能把有理除法本身當餘數;正模數下q≤value/m<q+1,故後續減去qm得到0至m−1。
規則:modular_Euclidean_floor_not_rational_division_result · 依賴:G001, S004
操作前
first input coset quotient multiple := mul(0, 4)
操作後
first input coset quotient multiple = 0
條件:無
依原始角色及已核中間量精確計算,保留索引、符號、分母與運算所在載體。
規則:exact_rational_arithmetic · 依賴:G001, S005
操作前
first input coset canonical nonnegative residue := sub(2, 0)
操作後
first input coset canonical nonnegative residue = 2
條件:無
依原始角色及已核中間量精確計算,保留索引、符號、分母與運算所在載體。
規則:exact_rational_arithmetic · 依賴:G001, S006
操作前
second input coset exact quotient fraction := div(5, 4)
操作後
second input coset exact quotient fraction = 5/4
條件:無
依原始角色及已核中間量精確計算,保留索引、符號、分母與運算所在載體。
規則:exact_rational_arithmetic · 依賴:G001, S007
操作前
second input coset:integer value=5;positive modulus=4;exact ratio=5/4
操作後
floor quotient=1;quotient<=ratio<quotient+1
條件:無
先取有理商再取向下整數商q,不能把有理除法本身當餘數;正模數下q≤value/m<q+1,故後續減去qm得到0至m−1。
規則:modular_Euclidean_floor_not_rational_division_result · 依賴:G001, S008
操作前
second input coset quotient multiple := mul(1, 4)
操作後
second input coset quotient multiple = 4
條件:無
依原始角色及已核中間量精確計算,保留索引、符號、分母與運算所在載體。
規則:exact_rational_arithmetic · 依賴:G001, S009
操作前
second input coset canonical nonnegative residue := sub(5, 4)
操作後
second input coset canonical nonnegative residue = 1
條件:無
依原始角色及已核中間量精確計算,保留索引、符號、分母與運算所在載體。
規則:exact_rational_arithmetic · 依賴:G001, S010
操作前
selected quotient operation integer multiplication := mul(2, 5)
操作後
selected quotient operation integer multiplication = 10
條件:無
依原始角色及已核中間量精確計算,保留索引、符號、分母與運算所在載體。
規則:exact_rational_arithmetic · 依賴:G001, S011
操作前
selected quotient operation parent mod n exact quotient fraction := div(10, 8)
操作後
selected quotient operation parent mod n exact quotient fraction = 5/4
條件:無
依原始角色及已核中間量精確計算,保留索引、符號、分母與運算所在載體。
規則:exact_rational_arithmetic · 依賴:G001, S012
操作前
selected quotient operation parent mod n:integer value=10;positive modulus=8;exact ratio=5/4
操作後
floor quotient=1;quotient<=ratio<quotient+1
條件:無
先取有理商再取向下整數商q,不能把有理除法本身當餘數;正模數下q≤value/m<q+1,故後續減去qm得到0至m−1。
規則:modular_Euclidean_floor_not_rational_division_result · 依賴:G001, S013
操作前
selected quotient operation parent mod n quotient multiple := mul(1, 8)
操作後
selected quotient operation parent mod n quotient multiple = 8
條件:無
依原始角色及已核中間量精確計算,保留索引、符號、分母與運算所在載體。
規則:exact_rational_arithmetic · 依賴:G001, S014
操作前
selected quotient operation parent mod n canonical nonnegative residue := sub(10, 8)
操作後
selected quotient operation parent mod n canonical nonnegative residue = 2
條件:無
依原始角色及已核中間量精確計算,保留索引、符號、分母與運算所在載體。
規則:exact_rational_arithmetic · 依賴:G001, S015
操作前
selected quotient operation quotient class mod d exact quotient fraction := div(2, 4)
操作後
selected quotient operation quotient class mod d exact quotient fraction = 1/2
條件:無
依原始角色及已核中間量精確計算,保留索引、符號、分母與運算所在載體。
規則:exact_rational_arithmetic · 依賴:G001, S016
操作前
selected quotient operation quotient class mod d:integer value=2;positive modulus=4;exact ratio=1/2
操作後
floor quotient=0;quotient<=ratio<quotient+1
條件:無
先取有理商再取向下整數商q,不能把有理除法本身當餘數;正模數下q≤value/m<q+1,故後續減去qm得到0至m−1。
規則:modular_Euclidean_floor_not_rational_division_result · 依賴:G001, S017
操作前
selected quotient operation quotient class mod d quotient multiple := mul(0, 4)
操作後
selected quotient operation quotient class mod d quotient multiple = 0
條件:無
依原始角色及已核中間量精確計算,保留索引、符號、分母與運算所在載體。
規則:exact_rational_arithmetic · 依賴:G001, S018
操作前
selected quotient operation quotient class mod d canonical nonnegative residue := sub(2, 0)
操作後
selected quotient operation quotient class mod d canonical nonnegative residue = 2
條件:無
依原始角色及已核中間量精確計算,保留索引、符號、分母與運算所在載體。
規則:exact_rational_arithmetic · 依賴:G001, S019
操作前
selected quotient operation:original parent representatives=[2, 5];integer result=10;parent modulus=8
操作後
parent result=2;quotient class label=2;class modulus=4
條件:無
先在指定母環mod n運算,再取mod d的商類;兩層欄位可能不同,不可跳成同一個餘數,也不能把標籤當商元素全體內容。
規則:quotient_operation_parent_result_separate_from_class · 依賴:G001, S020
操作前
same parent Z_8;same proper two-sided ideal I=[0, 4];input class labels=[2, 1]
操作後
quotient operation law=[a][b]=[ab];result class label=2
條件:無
加法陪集來自加法子群;乘法亦須兩側理想吸收才能與代表無關。本題在已核同一理想下用這條法則,不由任意商集合自動引入運算。
規則:quotient_ring_operation_uses_ideal_not_arbitrary_equivalence · 依賴:G001, S021
S022 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。S021 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。S020 · premise_and_result_audit — 以精確有理數重算 selected quotient operation quotient class mod d canonical nonnegative residue,不以小數近似替代。S019 · premise_and_result_audit — 以精確有理數重算 selected quotient operation quotient class mod d quotient multiple,不以小數近似替代。S018 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。S017 · premise_and_result_audit — 以精確有理數重算 selected quotient operation quotient class mod d exact quotient fraction,不以小數近似替代。S016 · premise_and_result_audit — 以精確有理數重算 selected quotient operation parent mod n canonical nonnegative residue,不以小數近似替代。S015 · premise_and_result_audit — 以精確有理數重算 selected quotient operation parent mod n quotient multiple,不以小數近似替代。S014 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。S013 · premise_and_result_audit — 以精確有理數重算 selected quotient operation parent mod n exact quotient fraction,不以小數近似替代。S012 · premise_and_result_audit — 以精確有理數重算 selected quotient operation integer multiplication,不以小數近似替代。S011 · premise_and_result_audit — 以精確有理數重算 second input coset canonical nonnegative residue,不以小數近似替代。S010 · premise_and_result_audit — 以精確有理數重算 second input coset quotient multiple,不以小數近似替代。S009 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。S008 · premise_and_result_audit — 以精確有理數重算 second input coset exact quotient fraction,不以小數近似替代。S007 · premise_and_result_audit — 以精確有理數重算 first input coset canonical nonnegative residue,不以小數近似替代。S006 · premise_and_result_audit — 以精確有理數重算 first input coset quotient multiple,不以小數近似替代。S005 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。S004 · premise_and_result_audit — 以精確有理數重算 first input coset exact quotient fraction,不以小數近似替代。S003 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。S002 · premise_and_result_audit — 回到原始資料與本步條件核對,不把單向推論誤稱等價。S001 · premise_and_result_audit — 以精確有理數重算 quotient ring parent modulus divided by ideal generator,不以小數近似替代。(2, 1, 2, 2, [a][b]=[ab])
依上列完整代值及條件核對得到原題答案;原題編號、格式與狀態保持不變。
覆核日期:2026-10-26
原題、答案、步驟表達式、數值 AST 與既有歷史保持原樣;原來的候選狀態屬於來源歷史,不覆寫為形式化證明。
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