鄰域基礎 · 脈衝 R02

本批已通過 Schema、去重、來源快照與獨立答案重算;仍未標記為人工審定。

本題庫已有對應的中英逐步詳解。原題的 candidate 與英文 ai_candidate 狀態保留;AI 覆核、有限計算與 Lean 形式證明分開標示。

batch-20261013-advance-20261019-r02-neighborhood-foundations · 2026-10-13 · 100 題

1. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-witness;資料={"n":4,"opens":[[],[0],[0,1],[0,1,2],[0,1,2,3]],"x":0,"candidate":[0,1]}。請依 [n,x,point_qualified,candidate,open_witnesses_or_不求值,neighborhood_or_不求值] 欄序回答。

查看答案與解釋

(4, 0, 是, [0, 1], [[0], [0, 1]], 是)

第二批擴展核對=(4, 0, 是, [0, 1], [[0], [0, 1]], 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-witness · candidate

2. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-witness;資料={"n":4,"opens":[[],[1],[0,1],[0,1,2],[0,1,2,3]],"x":1,"candidate":[2]}。請依 [n,x,point_qualified,candidate,open_witnesses_or_不求值,neighborhood_or_不求值] 欄序回答。

查看答案與解釋

(4, 1, 是, [2], [], 否)

第二批擴展核對=(4, 1, 是, [2], [], 否);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-witness · candidate

3. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-witness;資料={"n":4,"opens":[[],[2],[0,2],[0,1,2],[0,1,2,3]],"x":2,"candidate":[0,2]}。請依 [n,x,point_qualified,candidate,open_witnesses_or_不求值,neighborhood_or_不求值] 欄序回答。

查看答案與解釋

(4, 2, 是, [0, 2], [[2], [0, 2]], 是)

第二批擴展核對=(4, 2, 是, [0, 2], [[2], [0, 2]], 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-witness · candidate

4. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-witness;資料={"n":4,"opens":[[],[3],[0,3],[0,1,3],[0,1,2,3]],"x":3,"candidate":[1,2]}。請依 [n,x,point_qualified,candidate,open_witnesses_or_不求值,neighborhood_or_不求值] 欄序回答。

查看答案與解釋

(4, 3, 是, [1, 2], [], 否)

第二批擴展核對=(4, 3, 是, [1, 2], [], 否);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-witness · candidate

5. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-witness;資料={"n":4,"opens":[[],[0],[0,2],[0,1,2],[0,1,2,3]],"x":-1,"candidate":[0,1,2]}。請依 [n,x,point_qualified,candidate,open_witnesses_or_不求值,neighborhood_or_不求值] 欄序回答。

查看答案與解釋

(4, -1, 否, [0, 1, 2], 不求值, 不求值)

第二批擴展核對=(4, -1, 否, [0, 1, 2], 不求值, 不求值);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-witness · candidate

6. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-witness;資料={"n":4,"opens":[[],[1],[1,2],[0,1,2],[0,1,2,3]],"x":1,"candidate":[3]}。請依 [n,x,point_qualified,candidate,open_witnesses_or_不求值,neighborhood_or_不求值] 欄序回答。

查看答案與解釋

(4, 1, 是, [3], [], 否)

第二批擴展核對=(4, 1, 是, [3], [], 否);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-witness · candidate

7. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-witness;資料={"n":4,"opens":[[],[2],[1,2],[0,1,2],[0,1,2,3]],"x":2,"candidate":[0,3]}。請依 [n,x,point_qualified,candidate,open_witnesses_or_不求值,neighborhood_or_不求值] 欄序回答。

查看答案與解釋

(4, 2, 是, [0, 3], [], 否)

第二批擴展核對=(4, 2, 是, [0, 3], [], 否);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-witness · candidate

8. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-witness;資料={"n":4,"opens":[[],[3],[1,3],[0,1,3],[0,1,2,3]],"x":3,"candidate":[1,3]}。請依 [n,x,point_qualified,candidate,open_witnesses_or_不求值,neighborhood_or_不求值] 欄序回答。

查看答案與解釋

(4, 3, 是, [1, 3], [[3], [1, 3]], 是)

第二批擴展核對=(4, 3, 是, [1, 3], [[3], [1, 3]], 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-witness · candidate

9. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-witness;資料={"n":4,"opens":[[],[0],[0,3],[0,1,3],[0,1,2,3]],"x":0,"candidate":[0,1,3]}。請依 [n,x,point_qualified,candidate,open_witnesses_or_不求值,neighborhood_or_不求值] 欄序回答。

查看答案與解釋

(4, 0, 是, [0, 1, 3], [[0], [0, 3], [0, 1, 3]], 是)

第二批擴展核對=(4, 0, 是, [0, 1, 3], [[0], [0, 3], [0, 1, 3]], 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-witness · candidate

10. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-witness;資料={"n":4,"opens":[[],[1],[1,3],[0,1,3],[0,1,2,3]],"x":-1,"candidate":[2,3]}。請依 [n,x,point_qualified,candidate,open_witnesses_or_不求值,neighborhood_or_不求值] 欄序回答。

查看答案與解釋

(4, -1, 否, [2, 3], 不求值, 不求值)

第二批擴展核對=(4, -1, 否, [2, 3], 不求值, 不求值);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-witness · candidate

11. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-witness;資料={"n":4,"opens":[[],[2],[2,3],[0,2,3],[0,1,2,3]],"x":2,"candidate":[0,2,3]}。請依 [n,x,point_qualified,candidate,open_witnesses_or_不求值,neighborhood_or_不求值] 欄序回答。

查看答案與解釋

(4, 2, 是, [0, 2, 3], [[2], [2, 3], [0, 2, 3]], 是)

第二批擴展核對=(4, 2, 是, [0, 2, 3], [[2], [2, 3], [0, 2, 3]], 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-witness · candidate

12. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-witness;資料={"n":4,"opens":[[],[3],[2,3],[0,2,3],[0,1,2,3]],"x":3,"candidate":[1,2,3]}。請依 [n,x,point_qualified,candidate,open_witnesses_or_不求值,neighborhood_or_不求值] 欄序回答。

查看答案與解釋

(4, 3, 是, [1, 2, 3], [[3], [2, 3]], 是)

第二批擴展核對=(4, 3, 是, [1, 2, 3], [[3], [2, 3]], 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-witness · candidate

13. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-witness;資料={"n":4,"opens":[[],[0],[0,1],[0,1,3],[0,1,2,3]],"x":0,"candidate":[0,1,2,3]}。請依 [n,x,point_qualified,candidate,open_witnesses_or_不求值,neighborhood_or_不求值] 欄序回答。

查看答案與解釋

(4, 0, 是, [0, 1, 2, 3], [[0], [0, 1], [0, 1, 3], [0, 1, 2, 3]], 是)

第二批擴展核對=(4, 0, 是, [0, 1, 2, 3], [[0], [0, 1], [0, 1, 3], [0, 1, 2, 3]], 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-witness · candidate

14. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-witness;資料={"n":4,"opens":[[],[1],[0,1],[0,1,3],[0,1,2,3]],"x":1,"candidate":[]}。請依 [n,x,point_qualified,candidate,open_witnesses_or_不求值,neighborhood_or_不求值] 欄序回答。

查看答案與解釋

(4, 1, 是, [], [], 否)

第二批擴展核對=(4, 1, 是, [], [], 否);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-witness · candidate

15. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-witness;資料={"n":4,"opens":[[],[2],[0,2],[0,2,3],[0,1,2,3]],"x":-1,"candidate":[0]}。請依 [n,x,point_qualified,candidate,open_witnesses_or_不求值,neighborhood_or_不求值] 欄序回答。

查看答案與解釋

(4, -1, 否, [0], 不求值, 不求值)

第二批擴展核對=(4, -1, 否, [0], 不求值, 不求值);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-witness · candidate

16. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-witness;資料={"n":4,"opens":[[],[3],[0,3],[0,2,3],[0,1,2,3]],"x":3,"candidate":[1]}。請依 [n,x,point_qualified,candidate,open_witnesses_or_不求值,neighborhood_or_不求值] 欄序回答。

查看答案與解釋

(4, 3, 是, [1], [], 否)

第二批擴展核對=(4, 3, 是, [1], [], 否);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-witness · candidate

17. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-witness;資料={"n":4,"opens":[[],[0],[0,2],[0,2,3],[0,1,2,3]],"x":0,"candidate":[0,1]}。請依 [n,x,point_qualified,candidate,open_witnesses_or_不求值,neighborhood_or_不求值] 欄序回答。

查看答案與解釋

(4, 0, 是, [0, 1], [[0]], 是)

第二批擴展核對=(4, 0, 是, [0, 1], [[0]], 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-witness · candidate

18. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-witness;資料={"n":4,"opens":[[],[1],[1,2],[1,2,3],[0,1,2,3]],"x":1,"candidate":[2]}。請依 [n,x,point_qualified,candidate,open_witnesses_or_不求值,neighborhood_or_不求值] 欄序回答。

查看答案與解釋

(4, 1, 是, [2], [], 否)

第二批擴展核對=(4, 1, 是, [2], [], 否);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-witness · candidate

19. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-witness;資料={"n":4,"opens":[[],[2],[1,2],[1,2,3],[0,1,2,3]],"x":2,"candidate":[0,2]}。請依 [n,x,point_qualified,candidate,open_witnesses_or_不求值,neighborhood_or_不求值] 欄序回答。

查看答案與解釋

(4, 2, 是, [0, 2], [[2]], 是)

第二批擴展核對=(4, 2, 是, [0, 2], [[2]], 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-witness · candidate

20. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-witness;資料={"n":4,"opens":[[],[3],[1,3],[1,2,3],[0,1,2,3]],"x":-1,"candidate":[1,2]}。請依 [n,x,point_qualified,candidate,open_witnesses_or_不求值,neighborhood_or_不求值] 欄序回答。

查看答案與解釋

(4, -1, 否, [1, 2], 不求值, 不求值)

第二批擴展核對=(4, -1, 否, [1, 2], 不求值, 不求值);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-witness · candidate

21. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-witness;資料={"n":4,"opens":[[],[0],[0,3],[0,2,3],[0,1,2,3]],"x":0,"candidate":[0,1,2]}。請依 [n,x,point_qualified,candidate,open_witnesses_or_不求值,neighborhood_or_不求值] 欄序回答。

查看答案與解釋

(4, 0, 是, [0, 1, 2], [[0]], 是)

第二批擴展核對=(4, 0, 是, [0, 1, 2], [[0]], 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-witness · candidate

22. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-witness;資料={"n":4,"opens":[[],[1],[1,3],[1,2,3],[0,1,2,3]],"x":1,"candidate":[3]}。請依 [n,x,point_qualified,candidate,open_witnesses_or_不求值,neighborhood_or_不求值] 欄序回答。

查看答案與解釋

(4, 1, 是, [3], [], 否)

第二批擴展核對=(4, 1, 是, [3], [], 否);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-witness · candidate

23. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-witness;資料={"n":4,"opens":[[],[2],[2,3],[1,2,3],[0,1,2,3]],"x":2,"candidate":[0,3]}。請依 [n,x,point_qualified,candidate,open_witnesses_or_不求值,neighborhood_or_不求值] 欄序回答。

查看答案與解釋

(4, 2, 是, [0, 3], [], 否)

第二批擴展核對=(4, 2, 是, [0, 3], [], 否);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-witness · candidate

24. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-witness;資料={"n":4,"opens":[[],[3],[2,3],[1,2,3],[0,1,2,3]],"x":3,"candidate":[1,3]}。請依 [n,x,point_qualified,candidate,open_witnesses_or_不求值,neighborhood_or_不求值] 欄序回答。

查看答案與解釋

(4, 3, 是, [1, 3], [[3]], 是)

第二批擴展核對=(4, 3, 是, [1, 3], [[3]], 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-witness · candidate

25. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-witness;資料={"n":3,"opens":[[],[0],[0,1],[0,1,2]],"x":-1,"candidate":[0,1]}。請依 [n,x,point_qualified,candidate,open_witnesses_or_不求值,neighborhood_or_不求值] 欄序回答。

查看答案與解釋

(3, -1, 否, [0, 1], 不求值, 不求值)

第二批擴展核對=(3, -1, 否, [0, 1], 不求值, 不求值);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-witness · candidate

26. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-qualification;資料={"n":4,"opens":[[],[0],[0,1],[0,1,2],[0,1,2,3]],"x":0,"candidate":[0,1]}。請依 [n,x,point_qualified,candidate,x_in_candidate,candidate_open,neighborhood] 欄序回答。

查看答案與解釋

(4, 0, 是, [0, 1], 是, 是, 是)

第二批擴展核對=(4, 0, 是, [0, 1], 是, 是, 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-qualification · candidate

27. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-qualification;資料={"n":4,"opens":[[],[1],[0,1],[0,1,2],[0,1,2,3]],"x":1,"candidate":[2]}。請依 [n,x,point_qualified,candidate,x_in_candidate,candidate_open,neighborhood] 欄序回答。

查看答案與解釋

(4, 1, 是, [2], 否, 否, 否)

第二批擴展核對=(4, 1, 是, [2], 否, 否, 否);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-qualification · candidate

28. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-qualification;資料={"n":4,"opens":[[],[2],[0,2],[0,1,2],[0,1,2,3]],"x":2,"candidate":[0,2]}。請依 [n,x,point_qualified,candidate,x_in_candidate,candidate_open,neighborhood] 欄序回答。

查看答案與解釋

(4, 2, 是, [0, 2], 是, 是, 是)

第二批擴展核對=(4, 2, 是, [0, 2], 是, 是, 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-qualification · candidate

29. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-qualification;資料={"n":4,"opens":[[],[3],[0,3],[0,1,3],[0,1,2,3]],"x":3,"candidate":[1,2]}。請依 [n,x,point_qualified,candidate,x_in_candidate,candidate_open,neighborhood] 欄序回答。

查看答案與解釋

(4, 3, 是, [1, 2], 否, 否, 否)

第二批擴展核對=(4, 3, 是, [1, 2], 否, 否, 否);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-qualification · candidate

30. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-qualification;資料={"n":4,"opens":[[],[0],[0,2],[0,1,2],[0,1,2,3]],"x":-1,"candidate":[0,1,2]}。請依 [n,x,point_qualified,candidate,x_in_candidate,candidate_open,neighborhood] 欄序回答。

查看答案與解釋

(4, -1, 否, [0, 1, 2], 不求值, 不求值, 不求值)

第二批擴展核對=(4, -1, 否, [0, 1, 2], 不求值, 不求值, 不求值);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-qualification · candidate

31. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-qualification;資料={"n":4,"opens":[[],[1],[1,2],[0,1,2],[0,1,2,3]],"x":1,"candidate":[3]}。請依 [n,x,point_qualified,candidate,x_in_candidate,candidate_open,neighborhood] 欄序回答。

查看答案與解釋

(4, 1, 是, [3], 否, 否, 否)

第二批擴展核對=(4, 1, 是, [3], 否, 否, 否);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-qualification · candidate

32. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-qualification;資料={"n":4,"opens":[[],[2],[1,2],[0,1,2],[0,1,2,3]],"x":2,"candidate":[0,3]}。請依 [n,x,point_qualified,candidate,x_in_candidate,candidate_open,neighborhood] 欄序回答。

查看答案與解釋

(4, 2, 是, [0, 3], 否, 否, 否)

第二批擴展核對=(4, 2, 是, [0, 3], 否, 否, 否);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-qualification · candidate

33. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-qualification;資料={"n":4,"opens":[[],[3],[1,3],[0,1,3],[0,1,2,3]],"x":3,"candidate":[1,3]}。請依 [n,x,point_qualified,candidate,x_in_candidate,candidate_open,neighborhood] 欄序回答。

查看答案與解釋

(4, 3, 是, [1, 3], 是, 是, 是)

第二批擴展核對=(4, 3, 是, [1, 3], 是, 是, 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-qualification · candidate

34. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-qualification;資料={"n":4,"opens":[[],[0],[0,3],[0,1,3],[0,1,2,3]],"x":0,"candidate":[0,1,3]}。請依 [n,x,point_qualified,candidate,x_in_candidate,candidate_open,neighborhood] 欄序回答。

查看答案與解釋

(4, 0, 是, [0, 1, 3], 是, 是, 是)

第二批擴展核對=(4, 0, 是, [0, 1, 3], 是, 是, 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-qualification · candidate

35. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-qualification;資料={"n":4,"opens":[[],[1],[1,3],[0,1,3],[0,1,2,3]],"x":-1,"candidate":[2,3]}。請依 [n,x,point_qualified,candidate,x_in_candidate,candidate_open,neighborhood] 欄序回答。

查看答案與解釋

(4, -1, 否, [2, 3], 不求值, 不求值, 不求值)

第二批擴展核對=(4, -1, 否, [2, 3], 不求值, 不求值, 不求值);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-qualification · candidate

36. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-qualification;資料={"n":4,"opens":[[],[2],[2,3],[0,2,3],[0,1,2,3]],"x":2,"candidate":[0,2,3]}。請依 [n,x,point_qualified,candidate,x_in_candidate,candidate_open,neighborhood] 欄序回答。

查看答案與解釋

(4, 2, 是, [0, 2, 3], 是, 是, 是)

第二批擴展核對=(4, 2, 是, [0, 2, 3], 是, 是, 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-qualification · candidate

37. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-qualification;資料={"n":4,"opens":[[],[3],[2,3],[0,2,3],[0,1,2,3]],"x":3,"candidate":[1,2,3]}。請依 [n,x,point_qualified,candidate,x_in_candidate,candidate_open,neighborhood] 欄序回答。

查看答案與解釋

(4, 3, 是, [1, 2, 3], 是, 否, 是)

第二批擴展核對=(4, 3, 是, [1, 2, 3], 是, 否, 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-qualification · candidate

38. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-qualification;資料={"n":4,"opens":[[],[0],[0,1],[0,1,3],[0,1,2,3]],"x":0,"candidate":[0,1,2,3]}。請依 [n,x,point_qualified,candidate,x_in_candidate,candidate_open,neighborhood] 欄序回答。

查看答案與解釋

(4, 0, 是, [0, 1, 2, 3], 是, 是, 是)

第二批擴展核對=(4, 0, 是, [0, 1, 2, 3], 是, 是, 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-qualification · candidate

39. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-qualification;資料={"n":4,"opens":[[],[1],[0,1],[0,1,3],[0,1,2,3]],"x":1,"candidate":[]}。請依 [n,x,point_qualified,candidate,x_in_candidate,candidate_open,neighborhood] 欄序回答。

查看答案與解釋

(4, 1, 是, [], 否, 是, 否)

第二批擴展核對=(4, 1, 是, [], 否, 是, 否);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-qualification · candidate

40. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-qualification;資料={"n":4,"opens":[[],[2],[0,2],[0,2,3],[0,1,2,3]],"x":-1,"candidate":[0]}。請依 [n,x,point_qualified,candidate,x_in_candidate,candidate_open,neighborhood] 欄序回答。

查看答案與解釋

(4, -1, 否, [0], 不求值, 不求值, 不求值)

第二批擴展核對=(4, -1, 否, [0], 不求值, 不求值, 不求值);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-qualification · candidate

41. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-qualification;資料={"n":4,"opens":[[],[3],[0,3],[0,2,3],[0,1,2,3]],"x":3,"candidate":[1]}。請依 [n,x,point_qualified,candidate,x_in_candidate,candidate_open,neighborhood] 欄序回答。

查看答案與解釋

(4, 3, 是, [1], 否, 否, 否)

第二批擴展核對=(4, 3, 是, [1], 否, 否, 否);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-qualification · candidate

42. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-qualification;資料={"n":4,"opens":[[],[0],[0,2],[0,2,3],[0,1,2,3]],"x":0,"candidate":[0,1]}。請依 [n,x,point_qualified,candidate,x_in_candidate,candidate_open,neighborhood] 欄序回答。

查看答案與解釋

(4, 0, 是, [0, 1], 是, 否, 是)

第二批擴展核對=(4, 0, 是, [0, 1], 是, 否, 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-qualification · candidate

43. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-qualification;資料={"n":4,"opens":[[],[1],[1,2],[1,2,3],[0,1,2,3]],"x":1,"candidate":[2]}。請依 [n,x,point_qualified,candidate,x_in_candidate,candidate_open,neighborhood] 欄序回答。

查看答案與解釋

(4, 1, 是, [2], 否, 否, 否)

第二批擴展核對=(4, 1, 是, [2], 否, 否, 否);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-qualification · candidate

44. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-qualification;資料={"n":4,"opens":[[],[2],[1,2],[1,2,3],[0,1,2,3]],"x":2,"candidate":[0,2]}。請依 [n,x,point_qualified,candidate,x_in_candidate,candidate_open,neighborhood] 欄序回答。

查看答案與解釋

(4, 2, 是, [0, 2], 是, 否, 是)

第二批擴展核對=(4, 2, 是, [0, 2], 是, 否, 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-qualification · candidate

45. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-qualification;資料={"n":4,"opens":[[],[3],[1,3],[1,2,3],[0,1,2,3]],"x":-1,"candidate":[1,2]}。請依 [n,x,point_qualified,candidate,x_in_candidate,candidate_open,neighborhood] 欄序回答。

查看答案與解釋

(4, -1, 否, [1, 2], 不求值, 不求值, 不求值)

第二批擴展核對=(4, -1, 否, [1, 2], 不求值, 不求值, 不求值);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-qualification · candidate

46. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-qualification;資料={"n":4,"opens":[[],[0],[0,3],[0,2,3],[0,1,2,3]],"x":0,"candidate":[0,1,2]}。請依 [n,x,point_qualified,candidate,x_in_candidate,candidate_open,neighborhood] 欄序回答。

查看答案與解釋

(4, 0, 是, [0, 1, 2], 是, 否, 是)

第二批擴展核對=(4, 0, 是, [0, 1, 2], 是, 否, 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-qualification · candidate

47. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-qualification;資料={"n":4,"opens":[[],[1],[1,3],[1,2,3],[0,1,2,3]],"x":1,"candidate":[3]}。請依 [n,x,point_qualified,candidate,x_in_candidate,candidate_open,neighborhood] 欄序回答。

查看答案與解釋

(4, 1, 是, [3], 否, 否, 否)

第二批擴展核對=(4, 1, 是, [3], 否, 否, 否);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-qualification · candidate

48. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-qualification;資料={"n":4,"opens":[[],[2],[2,3],[1,2,3],[0,1,2,3]],"x":2,"candidate":[0,3]}。請依 [n,x,point_qualified,candidate,x_in_candidate,candidate_open,neighborhood] 欄序回答。

查看答案與解釋

(4, 2, 是, [0, 3], 否, 否, 否)

第二批擴展核對=(4, 2, 是, [0, 3], 否, 否, 否);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-qualification · candidate

49. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-qualification;資料={"n":4,"opens":[[],[3],[2,3],[1,2,3],[0,1,2,3]],"x":3,"candidate":[1,3]}。請依 [n,x,point_qualified,candidate,x_in_candidate,candidate_open,neighborhood] 欄序回答。

查看答案與解釋

(4, 3, 是, [1, 3], 是, 否, 是)

第二批擴展核對=(4, 3, 是, [1, 3], 是, 否, 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-qualification · candidate

50. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-qualification;資料={"n":3,"opens":[[],[0],[0,1],[0,1,2]],"x":-1,"candidate":[0,1]}。請依 [n,x,point_qualified,candidate,x_in_candidate,candidate_open,neighborhood] 欄序回答。

查看答案與解釋

(3, -1, 否, [0, 1], 不求值, 不求值, 不求值)

第二批擴展核對=(3, -1, 否, [0, 1], 不求值, 不求值, 不求值);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-qualification · candidate

51. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-upward-closure;資料={"n":4,"opens":[[],[0],[0,1],[0,1,2],[0,1,2,3]],"x":0,"small":[0],"large":[0,1,2,3]}。請依 [n,x,point_qualified,small,large,small_subset_large,small_neighborhood,large_neighborhood] 欄序回答。

查看答案與解釋

(4, 0, 是, [0], [0, 1, 2, 3], 是, 是, 是)

第二批擴展核對=(4, 0, 是, [0], [0, 1, 2, 3], 是, 是, 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-upward-closure · candidate

52. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-upward-closure;資料={"n":4,"opens":[[],[1],[0,1],[0,1,2],[0,1,2,3]],"x":1,"small":[1],"large":[0,1,2,3]}。請依 [n,x,point_qualified,small,large,small_subset_large,small_neighborhood,large_neighborhood] 欄序回答。

查看答案與解釋

(4, 1, 是, [1], [0, 1, 2, 3], 是, 是, 是)

第二批擴展核對=(4, 1, 是, [1], [0, 1, 2, 3], 是, 是, 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-upward-closure · candidate

53. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-upward-closure;資料={"n":4,"opens":[[],[2],[0,2],[0,1,2],[0,1,2,3]],"x":2,"small":[2],"large":[0,1,2,3]}。請依 [n,x,point_qualified,small,large,small_subset_large,small_neighborhood,large_neighborhood] 欄序回答。

查看答案與解釋

(4, 2, 是, [2], [0, 1, 2, 3], 是, 是, 是)

第二批擴展核對=(4, 2, 是, [2], [0, 1, 2, 3], 是, 是, 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-upward-closure · candidate

54. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-upward-closure;資料={"n":4,"opens":[[],[3],[0,3],[0,1,3],[0,1,2,3]],"x":3,"small":[3],"large":[0,1,2,3]}。請依 [n,x,point_qualified,small,large,small_subset_large,small_neighborhood,large_neighborhood] 欄序回答。

查看答案與解釋

(4, 3, 是, [3], [0, 1, 2, 3], 是, 是, 是)

第二批擴展核對=(4, 3, 是, [3], [0, 1, 2, 3], 是, 是, 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-upward-closure · candidate

55. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-upward-closure;資料={"n":4,"opens":[[],[0],[0,2],[0,1,2],[0,1,2,3]],"x":-1,"small":[0],"large":[0,1,2,3]}。請依 [n,x,point_qualified,small,large,small_subset_large,small_neighborhood,large_neighborhood] 欄序回答。

查看答案與解釋

(4, -1, 否, [0], [0, 1, 2, 3], 是, 不求值, 不求值)

第二批擴展核對=(4, -1, 否, [0], [0, 1, 2, 3], 是, 不求值, 不求值);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-upward-closure · candidate

56. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-upward-closure;資料={"n":4,"opens":[[],[1],[1,2],[0,1,2],[0,1,2,3]],"x":1,"small":[1],"large":[0,1,2,3]}。請依 [n,x,point_qualified,small,large,small_subset_large,small_neighborhood,large_neighborhood] 欄序回答。

查看答案與解釋

(4, 1, 是, [1], [0, 1, 2, 3], 是, 是, 是)

第二批擴展核對=(4, 1, 是, [1], [0, 1, 2, 3], 是, 是, 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-upward-closure · candidate

57. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-upward-closure;資料={"n":4,"opens":[[],[2],[1,2],[0,1,2],[0,1,2,3]],"x":2,"small":[2],"large":[0,1,2,3]}。請依 [n,x,point_qualified,small,large,small_subset_large,small_neighborhood,large_neighborhood] 欄序回答。

查看答案與解釋

(4, 2, 是, [2], [0, 1, 2, 3], 是, 是, 是)

第二批擴展核對=(4, 2, 是, [2], [0, 1, 2, 3], 是, 是, 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-upward-closure · candidate

58. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-upward-closure;資料={"n":4,"opens":[[],[3],[1,3],[0,1,3],[0,1,2,3]],"x":3,"small":[3],"large":[0,1,2,3]}。請依 [n,x,point_qualified,small,large,small_subset_large,small_neighborhood,large_neighborhood] 欄序回答。

查看答案與解釋

(4, 3, 是, [3], [0, 1, 2, 3], 是, 是, 是)

第二批擴展核對=(4, 3, 是, [3], [0, 1, 2, 3], 是, 是, 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-upward-closure · candidate

59. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-upward-closure;資料={"n":4,"opens":[[],[0],[0,3],[0,1,3],[0,1,2,3]],"x":0,"small":[0],"large":[0,1,2,3]}。請依 [n,x,point_qualified,small,large,small_subset_large,small_neighborhood,large_neighborhood] 欄序回答。

查看答案與解釋

(4, 0, 是, [0], [0, 1, 2, 3], 是, 是, 是)

第二批擴展核對=(4, 0, 是, [0], [0, 1, 2, 3], 是, 是, 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-upward-closure · candidate

60. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-upward-closure;資料={"n":4,"opens":[[],[1],[1,3],[0,1,3],[0,1,2,3]],"x":-1,"small":[0,1,3],"large":[0,1,2,3]}。請依 [n,x,point_qualified,small,large,small_subset_large,small_neighborhood,large_neighborhood] 欄序回答。

查看答案與解釋

(4, -1, 否, [0, 1, 3], [0, 1, 2, 3], 是, 不求值, 不求值)

第二批擴展核對=(4, -1, 否, [0, 1, 3], [0, 1, 2, 3], 是, 不求值, 不求值);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-upward-closure · candidate

61. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-upward-closure;資料={"n":4,"opens":[[],[2],[2,3],[0,2,3],[0,1,2,3]],"x":2,"small":[2],"large":[0,1,2,3]}。請依 [n,x,point_qualified,small,large,small_subset_large,small_neighborhood,large_neighborhood] 欄序回答。

查看答案與解釋

(4, 2, 是, [2], [0, 1, 2, 3], 是, 是, 是)

第二批擴展核對=(4, 2, 是, [2], [0, 1, 2, 3], 是, 是, 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-upward-closure · candidate

62. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-upward-closure;資料={"n":4,"opens":[[],[3],[2,3],[0,2,3],[0,1,2,3]],"x":3,"small":[3],"large":[0,1,2,3]}。請依 [n,x,point_qualified,small,large,small_subset_large,small_neighborhood,large_neighborhood] 欄序回答。

查看答案與解釋

(4, 3, 是, [3], [0, 1, 2, 3], 是, 是, 是)

第二批擴展核對=(4, 3, 是, [3], [0, 1, 2, 3], 是, 是, 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-upward-closure · candidate

63. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-upward-closure;資料={"n":4,"opens":[[],[0],[0,1],[0,1,3],[0,1,2,3]],"x":0,"small":[0],"large":[0,1,2,3]}。請依 [n,x,point_qualified,small,large,small_subset_large,small_neighborhood,large_neighborhood] 欄序回答。

查看答案與解釋

(4, 0, 是, [0], [0, 1, 2, 3], 是, 是, 是)

第二批擴展核對=(4, 0, 是, [0], [0, 1, 2, 3], 是, 是, 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-upward-closure · candidate

64. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-upward-closure;資料={"n":4,"opens":[[],[1],[0,1],[0,1,3],[0,1,2,3]],"x":1,"small":[1],"large":[0,1,2,3]}。請依 [n,x,point_qualified,small,large,small_subset_large,small_neighborhood,large_neighborhood] 欄序回答。

查看答案與解釋

(4, 1, 是, [1], [0, 1, 2, 3], 是, 是, 是)

第二批擴展核對=(4, 1, 是, [1], [0, 1, 2, 3], 是, 是, 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-upward-closure · candidate

65. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-upward-closure;資料={"n":4,"opens":[[],[2],[0,2],[0,2,3],[0,1,2,3]],"x":-1,"small":[0,2],"large":[0,1,2,3]}。請依 [n,x,point_qualified,small,large,small_subset_large,small_neighborhood,large_neighborhood] 欄序回答。

查看答案與解釋

(4, -1, 否, [0, 2], [0, 1, 2, 3], 是, 不求值, 不求值)

第二批擴展核對=(4, -1, 否, [0, 2], [0, 1, 2, 3], 是, 不求值, 不求值);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-upward-closure · candidate

66. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-upward-closure;資料={"n":4,"opens":[[],[3],[0,3],[0,2,3],[0,1,2,3]],"x":3,"small":[3],"large":[0,1,2,3]}。請依 [n,x,point_qualified,small,large,small_subset_large,small_neighborhood,large_neighborhood] 欄序回答。

查看答案與解釋

(4, 3, 是, [3], [0, 1, 2, 3], 是, 是, 是)

第二批擴展核對=(4, 3, 是, [3], [0, 1, 2, 3], 是, 是, 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-upward-closure · candidate

67. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-upward-closure;資料={"n":4,"opens":[[],[0],[0,2],[0,2,3],[0,1,2,3]],"x":0,"small":[0],"large":[0,1,2,3]}。請依 [n,x,point_qualified,small,large,small_subset_large,small_neighborhood,large_neighborhood] 欄序回答。

查看答案與解釋

(4, 0, 是, [0], [0, 1, 2, 3], 是, 是, 是)

第二批擴展核對=(4, 0, 是, [0], [0, 1, 2, 3], 是, 是, 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-upward-closure · candidate

68. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-upward-closure;資料={"n":4,"opens":[[],[1],[1,2],[1,2,3],[0,1,2,3]],"x":1,"small":[1],"large":[0,1,2,3]}。請依 [n,x,point_qualified,small,large,small_subset_large,small_neighborhood,large_neighborhood] 欄序回答。

查看答案與解釋

(4, 1, 是, [1], [0, 1, 2, 3], 是, 是, 是)

第二批擴展核對=(4, 1, 是, [1], [0, 1, 2, 3], 是, 是, 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-upward-closure · candidate

69. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-upward-closure;資料={"n":4,"opens":[[],[2],[1,2],[1,2,3],[0,1,2,3]],"x":2,"small":[2],"large":[0,1,2,3]}。請依 [n,x,point_qualified,small,large,small_subset_large,small_neighborhood,large_neighborhood] 欄序回答。

查看答案與解釋

(4, 2, 是, [2], [0, 1, 2, 3], 是, 是, 是)

第二批擴展核對=(4, 2, 是, [2], [0, 1, 2, 3], 是, 是, 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-upward-closure · candidate

70. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-upward-closure;資料={"n":4,"opens":[[],[3],[1,3],[1,2,3],[0,1,2,3]],"x":-1,"small":[0,1,2,3],"large":[0,1,2,3]}。請依 [n,x,point_qualified,small,large,small_subset_large,small_neighborhood,large_neighborhood] 欄序回答。

查看答案與解釋

(4, -1, 否, [0, 1, 2, 3], [0, 1, 2, 3], 是, 不求值, 不求值)

第二批擴展核對=(4, -1, 否, [0, 1, 2, 3], [0, 1, 2, 3], 是, 不求值, 不求值);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-upward-closure · candidate

71. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-upward-closure;資料={"n":4,"opens":[[],[0],[0,3],[0,2,3],[0,1,2,3]],"x":0,"small":[0],"large":[0,1,2,3]}。請依 [n,x,point_qualified,small,large,small_subset_large,small_neighborhood,large_neighborhood] 欄序回答。

查看答案與解釋

(4, 0, 是, [0], [0, 1, 2, 3], 是, 是, 是)

第二批擴展核對=(4, 0, 是, [0], [0, 1, 2, 3], 是, 是, 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-upward-closure · candidate

72. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-upward-closure;資料={"n":4,"opens":[[],[1],[1,3],[1,2,3],[0,1,2,3]],"x":1,"small":[1],"large":[0,1,2,3]}。請依 [n,x,point_qualified,small,large,small_subset_large,small_neighborhood,large_neighborhood] 欄序回答。

查看答案與解釋

(4, 1, 是, [1], [0, 1, 2, 3], 是, 是, 是)

第二批擴展核對=(4, 1, 是, [1], [0, 1, 2, 3], 是, 是, 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-upward-closure · candidate

73. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-upward-closure;資料={"n":4,"opens":[[],[2],[2,3],[1,2,3],[0,1,2,3]],"x":2,"small":[2],"large":[0,1,2,3]}。請依 [n,x,point_qualified,small,large,small_subset_large,small_neighborhood,large_neighborhood] 欄序回答。

查看答案與解釋

(4, 2, 是, [2], [0, 1, 2, 3], 是, 是, 是)

第二批擴展核對=(4, 2, 是, [2], [0, 1, 2, 3], 是, 是, 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-upward-closure · candidate

74. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-upward-closure;資料={"n":4,"opens":[[],[3],[2,3],[1,2,3],[0,1,2,3]],"x":3,"small":[3],"large":[0,1,2,3]}。請依 [n,x,point_qualified,small,large,small_subset_large,small_neighborhood,large_neighborhood] 欄序回答。

查看答案與解釋

(4, 3, 是, [3], [0, 1, 2, 3], 是, 是, 是)

第二批擴展核對=(4, 3, 是, [3], [0, 1, 2, 3], 是, 是, 是);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-upward-closure · candidate

75. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-upward-closure;資料={"n":3,"opens":[[],[0],[0,1],[0,1,2]],"x":-1,"small":[0],"large":[0,1,2]}。請依 [n,x,point_qualified,small,large,small_subset_large,small_neighborhood,large_neighborhood] 欄序回答。

查看答案與解釋

(3, -1, 否, [0], [0, 1, 2], 是, 不求值, 不求值)

第二批擴展核對=(3, -1, 否, [0], [0, 1, 2], 是, 不求值, 不求值);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-upward-closure · candidate

76. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-complete-inventory;資料={"n":4,"opens":[[],[0],[0,1],[0,1,2],[0,1,2,3]],"x":0}。請依 [n,x,open_basis,all_neighborhoods] 欄序回答。

查看答案與解釋

(4, 0, [[0], [0, 1], [0, 1, 2], [0, 1, 2, 3]], [[0], [0, 1], [0, 2], [0, 1, 2], [0, 3], [0, 1, 3], [0, 2, 3], [0, 1, 2, 3]])

第二批擴展核對=(4, 0, [[0], [0, 1], [0, 1, 2], [0, 1, 2, 3]], [[0], [0, 1], [0, 2], [0, 1, 2], [0, 3], [0, 1, 3], [0, 2, 3], [0, 1, 2, 3]]);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-complete-inventory · candidate

77. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-complete-inventory;資料={"n":4,"opens":[[],[1],[0,1],[0,1,2],[0,1,2,3]],"x":1}。請依 [n,x,open_basis,all_neighborhoods] 欄序回答。

查看答案與解釋

(4, 1, [[1], [0, 1], [0, 1, 2], [0, 1, 2, 3]], [[1], [0, 1], [1, 2], [0, 1, 2], [1, 3], [0, 1, 3], [1, 2, 3], [0, 1, 2, 3]])

第二批擴展核對=(4, 1, [[1], [0, 1], [0, 1, 2], [0, 1, 2, 3]], [[1], [0, 1], [1, 2], [0, 1, 2], [1, 3], [0, 1, 3], [1, 2, 3], [0, 1, 2, 3]]);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-complete-inventory · candidate

78. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-complete-inventory;資料={"n":4,"opens":[[],[2],[0,2],[0,1,2],[0,1,2,3]],"x":2}。請依 [n,x,open_basis,all_neighborhoods] 欄序回答。

查看答案與解釋

(4, 2, [[2], [0, 2], [0, 1, 2], [0, 1, 2, 3]], [[2], [0, 2], [1, 2], [0, 1, 2], [2, 3], [0, 2, 3], [1, 2, 3], [0, 1, 2, 3]])

第二批擴展核對=(4, 2, [[2], [0, 2], [0, 1, 2], [0, 1, 2, 3]], [[2], [0, 2], [1, 2], [0, 1, 2], [2, 3], [0, 2, 3], [1, 2, 3], [0, 1, 2, 3]]);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-complete-inventory · candidate

79. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-complete-inventory;資料={"n":4,"opens":[[],[3],[0,3],[0,1,3],[0,1,2,3]],"x":3}。請依 [n,x,open_basis,all_neighborhoods] 欄序回答。

查看答案與解釋

(4, 3, [[3], [0, 3], [0, 1, 3], [0, 1, 2, 3]], [[3], [0, 3], [1, 3], [0, 1, 3], [2, 3], [0, 2, 3], [1, 2, 3], [0, 1, 2, 3]])

第二批擴展核對=(4, 3, [[3], [0, 3], [0, 1, 3], [0, 1, 2, 3]], [[3], [0, 3], [1, 3], [0, 1, 3], [2, 3], [0, 2, 3], [1, 2, 3], [0, 1, 2, 3]]);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-complete-inventory · candidate

80. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-complete-inventory;資料={"n":4,"opens":[[],[0],[0,2],[0,1,2],[0,1,2,3]],"x":0}。請依 [n,x,open_basis,all_neighborhoods] 欄序回答。

查看答案與解釋

(4, 0, [[0], [0, 2], [0, 1, 2], [0, 1, 2, 3]], [[0], [0, 1], [0, 2], [0, 1, 2], [0, 3], [0, 1, 3], [0, 2, 3], [0, 1, 2, 3]])

第二批擴展核對=(4, 0, [[0], [0, 2], [0, 1, 2], [0, 1, 2, 3]], [[0], [0, 1], [0, 2], [0, 1, 2], [0, 3], [0, 1, 3], [0, 2, 3], [0, 1, 2, 3]]);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-complete-inventory · candidate

81. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-complete-inventory;資料={"n":4,"opens":[[],[1],[1,2],[0,1,2],[0,1,2,3]],"x":1}。請依 [n,x,open_basis,all_neighborhoods] 欄序回答。

查看答案與解釋

(4, 1, [[1], [1, 2], [0, 1, 2], [0, 1, 2, 3]], [[1], [0, 1], [1, 2], [0, 1, 2], [1, 3], [0, 1, 3], [1, 2, 3], [0, 1, 2, 3]])

第二批擴展核對=(4, 1, [[1], [1, 2], [0, 1, 2], [0, 1, 2, 3]], [[1], [0, 1], [1, 2], [0, 1, 2], [1, 3], [0, 1, 3], [1, 2, 3], [0, 1, 2, 3]]);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-complete-inventory · candidate

82. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-complete-inventory;資料={"n":4,"opens":[[],[2],[1,2],[0,1,2],[0,1,2,3]],"x":2}。請依 [n,x,open_basis,all_neighborhoods] 欄序回答。

查看答案與解釋

(4, 2, [[2], [1, 2], [0, 1, 2], [0, 1, 2, 3]], [[2], [0, 2], [1, 2], [0, 1, 2], [2, 3], [0, 2, 3], [1, 2, 3], [0, 1, 2, 3]])

第二批擴展核對=(4, 2, [[2], [1, 2], [0, 1, 2], [0, 1, 2, 3]], [[2], [0, 2], [1, 2], [0, 1, 2], [2, 3], [0, 2, 3], [1, 2, 3], [0, 1, 2, 3]]);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-complete-inventory · candidate

83. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-complete-inventory;資料={"n":4,"opens":[[],[3],[1,3],[0,1,3],[0,1,2,3]],"x":3}。請依 [n,x,open_basis,all_neighborhoods] 欄序回答。

查看答案與解釋

(4, 3, [[3], [1, 3], [0, 1, 3], [0, 1, 2, 3]], [[3], [0, 3], [1, 3], [0, 1, 3], [2, 3], [0, 2, 3], [1, 2, 3], [0, 1, 2, 3]])

第二批擴展核對=(4, 3, [[3], [1, 3], [0, 1, 3], [0, 1, 2, 3]], [[3], [0, 3], [1, 3], [0, 1, 3], [2, 3], [0, 2, 3], [1, 2, 3], [0, 1, 2, 3]]);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-complete-inventory · candidate

84. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-complete-inventory;資料={"n":4,"opens":[[],[0],[0,3],[0,1,3],[0,1,2,3]],"x":0}。請依 [n,x,open_basis,all_neighborhoods] 欄序回答。

查看答案與解釋

(4, 0, [[0], [0, 3], [0, 1, 3], [0, 1, 2, 3]], [[0], [0, 1], [0, 2], [0, 1, 2], [0, 3], [0, 1, 3], [0, 2, 3], [0, 1, 2, 3]])

第二批擴展核對=(4, 0, [[0], [0, 3], [0, 1, 3], [0, 1, 2, 3]], [[0], [0, 1], [0, 2], [0, 1, 2], [0, 3], [0, 1, 3], [0, 2, 3], [0, 1, 2, 3]]);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-complete-inventory · candidate

85. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-complete-inventory;資料={"n":4,"opens":[[],[1],[1,3],[0,1,3],[0,1,2,3]],"x":0}。請依 [n,x,open_basis,all_neighborhoods] 欄序回答。

查看答案與解釋

(4, 0, [[0, 1, 3], [0, 1, 2, 3]], [[0, 1, 3], [0, 1, 2, 3]])

第二批擴展核對=(4, 0, [[0, 1, 3], [0, 1, 2, 3]], [[0, 1, 3], [0, 1, 2, 3]]);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-complete-inventory · candidate

86. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-complete-inventory;資料={"n":4,"opens":[[],[2],[2,3],[0,2,3],[0,1,2,3]],"x":2}。請依 [n,x,open_basis,all_neighborhoods] 欄序回答。

查看答案與解釋

(4, 2, [[2], [2, 3], [0, 2, 3], [0, 1, 2, 3]], [[2], [0, 2], [1, 2], [0, 1, 2], [2, 3], [0, 2, 3], [1, 2, 3], [0, 1, 2, 3]])

第二批擴展核對=(4, 2, [[2], [2, 3], [0, 2, 3], [0, 1, 2, 3]], [[2], [0, 2], [1, 2], [0, 1, 2], [2, 3], [0, 2, 3], [1, 2, 3], [0, 1, 2, 3]]);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-complete-inventory · candidate

87. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-complete-inventory;資料={"n":4,"opens":[[],[3],[2,3],[0,2,3],[0,1,2,3]],"x":3}。請依 [n,x,open_basis,all_neighborhoods] 欄序回答。

查看答案與解釋

(4, 3, [[3], [2, 3], [0, 2, 3], [0, 1, 2, 3]], [[3], [0, 3], [1, 3], [0, 1, 3], [2, 3], [0, 2, 3], [1, 2, 3], [0, 1, 2, 3]])

第二批擴展核對=(4, 3, [[3], [2, 3], [0, 2, 3], [0, 1, 2, 3]], [[3], [0, 3], [1, 3], [0, 1, 3], [2, 3], [0, 2, 3], [1, 2, 3], [0, 1, 2, 3]]);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-complete-inventory · candidate

88. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-complete-inventory;資料={"n":4,"opens":[[],[0],[0,1],[0,1,3],[0,1,2,3]],"x":0}。請依 [n,x,open_basis,all_neighborhoods] 欄序回答。

查看答案與解釋

(4, 0, [[0], [0, 1], [0, 1, 3], [0, 1, 2, 3]], [[0], [0, 1], [0, 2], [0, 1, 2], [0, 3], [0, 1, 3], [0, 2, 3], [0, 1, 2, 3]])

第二批擴展核對=(4, 0, [[0], [0, 1], [0, 1, 3], [0, 1, 2, 3]], [[0], [0, 1], [0, 2], [0, 1, 2], [0, 3], [0, 1, 3], [0, 2, 3], [0, 1, 2, 3]]);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-complete-inventory · candidate

89. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-complete-inventory;資料={"n":4,"opens":[[],[1],[0,1],[0,1,3],[0,1,2,3]],"x":1}。請依 [n,x,open_basis,all_neighborhoods] 欄序回答。

查看答案與解釋

(4, 1, [[1], [0, 1], [0, 1, 3], [0, 1, 2, 3]], [[1], [0, 1], [1, 2], [0, 1, 2], [1, 3], [0, 1, 3], [1, 2, 3], [0, 1, 2, 3]])

第二批擴展核對=(4, 1, [[1], [0, 1], [0, 1, 3], [0, 1, 2, 3]], [[1], [0, 1], [1, 2], [0, 1, 2], [1, 3], [0, 1, 3], [1, 2, 3], [0, 1, 2, 3]]);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-complete-inventory · candidate

90. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-complete-inventory;資料={"n":4,"opens":[[],[2],[0,2],[0,2,3],[0,1,2,3]],"x":0}。請依 [n,x,open_basis,all_neighborhoods] 欄序回答。

查看答案與解釋

(4, 0, [[0, 2], [0, 2, 3], [0, 1, 2, 3]], [[0, 2], [0, 1, 2], [0, 2, 3], [0, 1, 2, 3]])

第二批擴展核對=(4, 0, [[0, 2], [0, 2, 3], [0, 1, 2, 3]], [[0, 2], [0, 1, 2], [0, 2, 3], [0, 1, 2, 3]]);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-complete-inventory · candidate

91. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-complete-inventory;資料={"n":4,"opens":[[],[3],[0,3],[0,2,3],[0,1,2,3]],"x":3}。請依 [n,x,open_basis,all_neighborhoods] 欄序回答。

查看答案與解釋

(4, 3, [[3], [0, 3], [0, 2, 3], [0, 1, 2, 3]], [[3], [0, 3], [1, 3], [0, 1, 3], [2, 3], [0, 2, 3], [1, 2, 3], [0, 1, 2, 3]])

第二批擴展核對=(4, 3, [[3], [0, 3], [0, 2, 3], [0, 1, 2, 3]], [[3], [0, 3], [1, 3], [0, 1, 3], [2, 3], [0, 2, 3], [1, 2, 3], [0, 1, 2, 3]]);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-complete-inventory · candidate

92. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-complete-inventory;資料={"n":4,"opens":[[],[0],[0,2],[0,2,3],[0,1,2,3]],"x":0}。請依 [n,x,open_basis,all_neighborhoods] 欄序回答。

查看答案與解釋

(4, 0, [[0], [0, 2], [0, 2, 3], [0, 1, 2, 3]], [[0], [0, 1], [0, 2], [0, 1, 2], [0, 3], [0, 1, 3], [0, 2, 3], [0, 1, 2, 3]])

第二批擴展核對=(4, 0, [[0], [0, 2], [0, 2, 3], [0, 1, 2, 3]], [[0], [0, 1], [0, 2], [0, 1, 2], [0, 3], [0, 1, 3], [0, 2, 3], [0, 1, 2, 3]]);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-complete-inventory · candidate

93. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-complete-inventory;資料={"n":4,"opens":[[],[1],[1,2],[1,2,3],[0,1,2,3]],"x":1}。請依 [n,x,open_basis,all_neighborhoods] 欄序回答。

查看答案與解釋

(4, 1, [[1], [1, 2], [1, 2, 3], [0, 1, 2, 3]], [[1], [0, 1], [1, 2], [0, 1, 2], [1, 3], [0, 1, 3], [1, 2, 3], [0, 1, 2, 3]])

第二批擴展核對=(4, 1, [[1], [1, 2], [1, 2, 3], [0, 1, 2, 3]], [[1], [0, 1], [1, 2], [0, 1, 2], [1, 3], [0, 1, 3], [1, 2, 3], [0, 1, 2, 3]]);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-complete-inventory · candidate

94. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-complete-inventory;資料={"n":4,"opens":[[],[2],[1,2],[1,2,3],[0,1,2,3]],"x":2}。請依 [n,x,open_basis,all_neighborhoods] 欄序回答。

查看答案與解釋

(4, 2, [[2], [1, 2], [1, 2, 3], [0, 1, 2, 3]], [[2], [0, 2], [1, 2], [0, 1, 2], [2, 3], [0, 2, 3], [1, 2, 3], [0, 1, 2, 3]])

第二批擴展核對=(4, 2, [[2], [1, 2], [1, 2, 3], [0, 1, 2, 3]], [[2], [0, 2], [1, 2], [0, 1, 2], [2, 3], [0, 2, 3], [1, 2, 3], [0, 1, 2, 3]]);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-complete-inventory · candidate

95. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-complete-inventory;資料={"n":4,"opens":[[],[3],[1,3],[1,2,3],[0,1,2,3]],"x":0}。請依 [n,x,open_basis,all_neighborhoods] 欄序回答。

查看答案與解釋

(4, 0, [[0, 1, 2, 3]], [[0, 1, 2, 3]])

第二批擴展核對=(4, 0, [[0, 1, 2, 3]], [[0, 1, 2, 3]]);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-complete-inventory · candidate

96. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-complete-inventory;資料={"n":4,"opens":[[],[0],[0,3],[0,2,3],[0,1,2,3]],"x":0}。請依 [n,x,open_basis,all_neighborhoods] 欄序回答。

查看答案與解釋

(4, 0, [[0], [0, 3], [0, 2, 3], [0, 1, 2, 3]], [[0], [0, 1], [0, 2], [0, 1, 2], [0, 3], [0, 1, 3], [0, 2, 3], [0, 1, 2, 3]])

第二批擴展核對=(4, 0, [[0], [0, 3], [0, 2, 3], [0, 1, 2, 3]], [[0], [0, 1], [0, 2], [0, 1, 2], [0, 3], [0, 1, 3], [0, 2, 3], [0, 1, 2, 3]]);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-complete-inventory · candidate

97. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-complete-inventory;資料={"n":4,"opens":[[],[1],[1,3],[1,2,3],[0,1,2,3]],"x":1}。請依 [n,x,open_basis,all_neighborhoods] 欄序回答。

查看答案與解釋

(4, 1, [[1], [1, 3], [1, 2, 3], [0, 1, 2, 3]], [[1], [0, 1], [1, 2], [0, 1, 2], [1, 3], [0, 1, 3], [1, 2, 3], [0, 1, 2, 3]])

第二批擴展核對=(4, 1, [[1], [1, 3], [1, 2, 3], [0, 1, 2, 3]], [[1], [0, 1], [1, 2], [0, 1, 2], [1, 3], [0, 1, 3], [1, 2, 3], [0, 1, 2, 3]]);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-complete-inventory · candidate

98. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-complete-inventory;資料={"n":4,"opens":[[],[2],[2,3],[1,2,3],[0,1,2,3]],"x":2}。請依 [n,x,open_basis,all_neighborhoods] 欄序回答。

查看答案與解釋

(4, 2, [[2], [2, 3], [1, 2, 3], [0, 1, 2, 3]], [[2], [0, 2], [1, 2], [0, 1, 2], [2, 3], [0, 2, 3], [1, 2, 3], [0, 1, 2, 3]])

第二批擴展核對=(4, 2, [[2], [2, 3], [1, 2, 3], [0, 1, 2, 3]], [[2], [0, 2], [1, 2], [0, 1, 2], [2, 3], [0, 2, 3], [1, 2, 3], [0, 1, 2, 3]]);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-complete-inventory · candidate

99. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-complete-inventory;資料={"n":4,"opens":[[],[3],[2,3],[1,2,3],[0,1,2,3]],"x":3}。請依 [n,x,open_basis,all_neighborhoods] 欄序回答。

查看答案與解釋

(4, 3, [[3], [2, 3], [1, 2, 3], [0, 1, 2, 3]], [[3], [0, 3], [1, 3], [0, 1, 3], [2, 3], [0, 2, 3], [1, 2, 3], [0, 1, 2, 3]])

第二批擴展核對=(4, 3, [[3], [2, 3], [1, 2, 3], [0, 1, 2, 3]], [[3], [0, 3], [1, 3], [0, 1, 3], [2, 3], [0, 2, 3], [1, 2, 3], [0, 1, 2, 3]]);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-complete-inventory · candidate

100. 鄰域與開集見證

完整有限拓撲與指定點。操作=neighborhood-complete-inventory;資料={"n":3,"opens":[[],[0],[0,1],[0,1,2]],"x":0}。請依 [n,x,open_basis,all_neighborhoods] 欄序回答。

查看答案與解釋

(3, 0, [[0], [0, 1], [0, 1, 2]], [[0], [0, 1], [0, 2], [0, 1, 2]])

第二批擴展核對=(3, 0, [[0], [0, 1], [0, 1, 2]], [[0], [0, 1], [0, 2], [0, 1, 2]]);依完整明示資料重算;有限/合成資料核對不是一般形式證明;鄰域包含含點開集;鄰域本身不必開;域外點不求值。

本題逐步詳解(AI 二次覆核)

鄰域 · qf-ext19-neighborhood-complete-inventory · candidate

原始題目 JSONL · 驗收報告