同胚基礎 · 脈衝 R05

本批已通過 Schema、去重、來源快照與獨立答案重算;仍未標記為人工審定。

本題庫已有對應的中英逐步詳解。原題的 candidate 與英文 ai_candidate 狀態保留;AI 覆核、有限計算與 Lean 形式證明分開標示。

batch-20261014-advance-20261105-r05-homeomorphism-foundations · 2026-10-14 · 100 題

欄序為來源綁定的呈現補充;原始 JSONL 與數學答案不變。

欄序與來源綁定資料

1. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-topology-audit;資料={"n":5,"source_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,3,4],[1,2],[1,2,3,4],[3,4]],"target_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,3,4],[1,2],[1,2,3,4],[3,4]],"map":[0,1,2,3,4]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, certificate] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit)

Wave5第五層核對=(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-topology-audit · candidate

2. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-topology-audit;資料={"n":5,"source_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,3,4],[1,2],[1,2,3,4],[3,4]],"target_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,3,4],[1,2],[1,2,3,4],[3,4]],"map":[0,1,2,4,3]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, certificate] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit)

Wave5第五層核對=(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-topology-audit · candidate

3. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-topology-audit;資料={"n":5,"source_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,3,4],[1,2],[1,2,3,4],[3,4]],"target_topology":[[],[0],[0,1,2,3,4],[0,1,3],[0,2,4],[1,2,3,4],[1,3],[2,4]],"map":[0,1,3,2,4]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, certificate] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit)

Wave5第五層核對=(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-topology-audit · candidate

4. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-topology-audit;資料={"n":5,"source_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,3,4],[1,2],[1,2,3,4],[3,4]],"target_topology":[[],[0],[0,1,2,3,4],[0,1,3],[0,2,4],[1,2,3,4],[1,3],[2,4]],"map":[0,1,3,4,2]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, certificate] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit)

Wave5第五層核對=(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-topology-audit · candidate

5. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-topology-audit;資料={"n":5,"source_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,3,4],[1,2],[1,2,3,4],[3,4]],"target_topology":[[],[0],[0,1,2,3,4],[0,1,4],[0,2,3],[1,2,3,4],[1,4],[2,3]],"map":[0,1,4,2,3]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, certificate] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit)

Wave5第五層核對=(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-topology-audit · candidate

6. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-topology-audit;資料={"n":5,"source_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,3,4],[1,2],[1,2,3,4],[3,4]],"target_topology":[[],[0],[0,1,2,3,4],[0,1,4],[0,2,3],[1,2,3,4],[1,4],[2,3]],"map":[0,1,4,3,2]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, certificate] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit)

Wave5第五層核對=(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-topology-audit · candidate

7. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-topology-audit;資料={"n":5,"source_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,3,4],[1,2],[1,2,3,4],[3,4]],"target_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,3,4],[1,2],[1,2,3,4],[3,4]],"map":[0,2,1,3,4]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, certificate] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit)

Wave5第五層核對=(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-topology-audit · candidate

8. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-topology-audit;資料={"n":5,"source_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,3,4],[1,2],[1,2,3,4],[3,4]],"target_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,3,4],[1,2],[1,2,3,4],[3,4]],"map":[0,2,1,4,3]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, certificate] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit)

Wave5第五層核對=(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-topology-audit · candidate

9. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-topology-audit;資料={"n":5,"source_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,3,4],[1,2],[1,2,3,4],[3,4]],"target_topology":[[],[0],[0,1,2,3,4],[0,1,4],[0,2,3],[1,2,3,4],[1,4],[2,3]],"map":[0,2,3,1,4]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, certificate] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit)

Wave5第五層核對=(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-topology-audit · candidate

10. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-topology-audit;資料={"n":5,"source_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,3,4],[1,2],[1,2,3,4],[3,4]],"target_topology":[[],[0],[0,1,2,3,4],[0,1,4],[0,2,3],[1,2,3,4],[1,4],[2,3]],"map":[0,2,3,4,1]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, certificate] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit)

Wave5第五層核對=(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-topology-audit · candidate

11. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-topology-audit;資料={"n":5,"source_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,3,4],[1,2],[1,2,3,4],[3,4]],"target_topology":[[],[0],[0,1,2,3,4],[0,1,3],[0,2,4],[1,2,3,4],[1,3],[2,4]],"map":[0,2,4,1,3]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, certificate] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit)

Wave5第五層核對=(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-topology-audit · candidate

12. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-topology-audit;資料={"n":5,"source_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,3,4],[1,2],[1,2,3,4],[3,4]],"target_topology":[[],[0],[0,1,2,3,4],[0,1,3],[0,2,4],[1,2,3,4],[1,3],[2,4]],"map":[0,2,4,3,1]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, certificate] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit)

Wave5第五層核對=(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-topology-audit · candidate

13. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-topology-audit;資料={"n":5,"source_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,3,4],[1,2],[1,2,3,4],[3,4]],"target_topology":[[],[0],[0,1,2,3,4],[0,1,3],[0,2,4],[1,2,3,4],[1,3],[2,4]],"map":[0,3,1,2,4]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, certificate] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit)

Wave5第五層核對=(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-topology-audit · candidate

14. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-topology-audit;資料={"n":5,"source_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,3,4],[1,2],[1,2,3,4],[3,4]],"target_topology":[[],[0],[0,1,2,3,4],[0,1,3],[0,2,4],[1,2,3,4],[1,3],[2,4]],"map":[0,3,1,4,2]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, certificate] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit)

Wave5第五層核對=(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-topology-audit · candidate

15. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-topology-audit;資料={"n":5,"source_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,3,4],[1,2],[1,2,3,4],[3,4]],"target_topology":[[],[0],[0,1,2,3,4],[0,1,4],[0,2,3],[1,2,3,4],[1,4],[2,3]],"map":[0,3,2,1,4]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, certificate] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit)

Wave5第五層核對=(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-topology-audit · candidate

16. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-topology-audit;資料={"n":5,"source_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,3,4],[1,2],[1,2,3,4],[3,4]],"target_topology":[[],[0],[0,1,2,3,4],[0,1,4],[0,2,3],[1,2,3,4],[1,4],[2,3]],"map":[0,3,2,4,1]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, certificate] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit)

Wave5第五層核對=(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-topology-audit · candidate

17. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-topology-audit;資料={"n":5,"source_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,3,4],[1,2],[1,2,3,4],[3,4]],"target_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,3,4],[1,2],[1,2,3,4],[3,4]],"map":[0,3,4,1,2]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, certificate] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit)

Wave5第五層核對=(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-topology-audit · candidate

18. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-topology-audit;資料={"n":5,"source_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,3,4],[1,2],[1,2,3,4],[3,4]],"target_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,3,4],[1,2],[1,2,3,4],[3,4]],"map":[0,3,4,2,1]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, certificate] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit)

Wave5第五層核對=(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-topology-audit · candidate

19. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-topology-audit;資料={"n":5,"source_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,3,4],[1,2],[1,2,3,4],[3,4]],"target_topology":[[],[0],[0,1,2,3,4],[0,1,4],[0,2,3],[1,2,3,4],[1,4],[2,3]],"map":[0,4,1,2,3]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, certificate] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit)

Wave5第五層核對=(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-topology-audit · candidate

20. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-topology-audit;資料={"n":5,"source_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,3,4],[1,2],[1,2,3,4],[3,4]],"target_topology":[[],[0],[0,1,2,3,4],[0,1,4],[0,2,3],[1,2,3,4],[1,4],[2,3]],"map":[0,4,1,3,2]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, certificate] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit)

Wave5第五層核對=(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-topology-audit · candidate

21. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-topology-audit;資料={"n":5,"source_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,3,4],[1,2],[1,2,3,4],[3,4]],"target_topology":[[],[0],[0,1,2,3,4],[0,1,3],[0,2,4],[1,2,3,4],[1,3],[2,4]],"map":[0,4,2,1,3]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, certificate] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit)

Wave5第五層核對=(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-topology-audit · candidate

22. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-topology-audit;資料={"n":5,"source_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,3,4],[1,2],[1,2,3,4],[3,4]],"target_topology":[[],[0],[0,1,2,3,4],[0,1,3],[0,2,4],[1,2,3,4],[1,3],[2,4]],"map":[0,4,2,3,1]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, certificate] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit)

Wave5第五層核對=(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-topology-audit · candidate

23. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-topology-audit;資料={"n":5,"source_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,3,4],[1,2],[1,2,3,4],[3,4]],"target_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,3,4],[1,2],[1,2,3,4],[3,4]],"map":[0,4,3,1,2]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, certificate] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit)

Wave5第五層核對=(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-topology-audit · candidate

24. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-topology-audit;資料={"n":5,"source_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,3,4],[1,2],[1,2,3,4],[3,4]],"target_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,3,4],[1,2],[1,2,3,4],[3,4]],"map":[0,4,3,2,1]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, certificate] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit)

Wave5第五層核對=(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-topology-audit · candidate

25. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-topology-audit;資料={"n":5,"source_topology":[[],[0],[0,1,2],[0,1,2,3,4],[0,3,4],[1,2],[1,2,3,4],[3,4]],"target_topology":[[],[0,1,2],[0,1,2,3,4],[0,2],[0,2,3,4],[1],[1,3,4],[3,4]],"map":[1,0,2,3,4]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, certificate] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit)

Wave5第五層核對=(是, 是, 是, 是, 是, 是, complete_open_set_preimage_audit);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-topology-audit · candidate

26. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-continuous-bijection-boundary;資料={"n":5,"source_topology":[[],[0],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4],[0,1,2,4],[0,1,3],[0,1,3,4],[0,1,4],[0,2],[0,2,3],[0,2,3,4],[0,2,4],[0,3],[0,3,4],[0,4],[1],[1,2],[1,2,3],[1,2,3,4],[1,2,4],[1,3],[1,3,4],[1,4],[2],[2,3],[2,3,4],[2,4],[3],[3,4],[4]],"target_topology":[[],[0,1,2,3,4]],"map":[0,1,2,3,4]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required)

Wave5第五層核對=(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-continuous-bijection-boundary · candidate

27. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-continuous-bijection-boundary;資料={"n":5,"source_topology":[[],[0],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4],[0,1,2,4],[0,1,3],[0,1,3,4],[0,1,4],[0,2],[0,2,3],[0,2,3,4],[0,2,4],[0,3],[0,3,4],[0,4],[1],[1,2],[1,2,3],[1,2,3,4],[1,2,4],[1,3],[1,3,4],[1,4],[2],[2,3],[2,3,4],[2,4],[3],[3,4],[4]],"target_topology":[[],[0,1,2,3,4]],"map":[0,1,2,4,3]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required)

Wave5第五層核對=(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-continuous-bijection-boundary · candidate

28. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-continuous-bijection-boundary;資料={"n":5,"source_topology":[[],[0],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4],[0,1,2,4],[0,1,3],[0,1,3,4],[0,1,4],[0,2],[0,2,3],[0,2,3,4],[0,2,4],[0,3],[0,3,4],[0,4],[1],[1,2],[1,2,3],[1,2,3,4],[1,2,4],[1,3],[1,3,4],[1,4],[2],[2,3],[2,3,4],[2,4],[3],[3,4],[4]],"target_topology":[[],[0,1,2,3,4]],"map":[0,1,3,2,4]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required)

Wave5第五層核對=(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-continuous-bijection-boundary · candidate

29. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-continuous-bijection-boundary;資料={"n":5,"source_topology":[[],[0],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4],[0,1,2,4],[0,1,3],[0,1,3,4],[0,1,4],[0,2],[0,2,3],[0,2,3,4],[0,2,4],[0,3],[0,3,4],[0,4],[1],[1,2],[1,2,3],[1,2,3,4],[1,2,4],[1,3],[1,3,4],[1,4],[2],[2,3],[2,3,4],[2,4],[3],[3,4],[4]],"target_topology":[[],[0,1,2,3,4]],"map":[0,1,3,4,2]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required)

Wave5第五層核對=(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-continuous-bijection-boundary · candidate

30. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-continuous-bijection-boundary;資料={"n":5,"source_topology":[[],[0],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4],[0,1,2,4],[0,1,3],[0,1,3,4],[0,1,4],[0,2],[0,2,3],[0,2,3,4],[0,2,4],[0,3],[0,3,4],[0,4],[1],[1,2],[1,2,3],[1,2,3,4],[1,2,4],[1,3],[1,3,4],[1,4],[2],[2,3],[2,3,4],[2,4],[3],[3,4],[4]],"target_topology":[[],[0,1,2,3,4]],"map":[0,1,4,2,3]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required)

Wave5第五層核對=(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-continuous-bijection-boundary · candidate

31. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-continuous-bijection-boundary;資料={"n":5,"source_topology":[[],[0],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4],[0,1,2,4],[0,1,3],[0,1,3,4],[0,1,4],[0,2],[0,2,3],[0,2,3,4],[0,2,4],[0,3],[0,3,4],[0,4],[1],[1,2],[1,2,3],[1,2,3,4],[1,2,4],[1,3],[1,3,4],[1,4],[2],[2,3],[2,3,4],[2,4],[3],[3,4],[4]],"target_topology":[[],[0,1,2,3,4]],"map":[0,1,4,3,2]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required)

Wave5第五層核對=(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-continuous-bijection-boundary · candidate

32. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-continuous-bijection-boundary;資料={"n":5,"source_topology":[[],[0],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4],[0,1,2,4],[0,1,3],[0,1,3,4],[0,1,4],[0,2],[0,2,3],[0,2,3,4],[0,2,4],[0,3],[0,3,4],[0,4],[1],[1,2],[1,2,3],[1,2,3,4],[1,2,4],[1,3],[1,3,4],[1,4],[2],[2,3],[2,3,4],[2,4],[3],[3,4],[4]],"target_topology":[[],[0,1,2,3,4]],"map":[0,2,1,3,4]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required)

Wave5第五層核對=(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-continuous-bijection-boundary · candidate

33. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-continuous-bijection-boundary;資料={"n":5,"source_topology":[[],[0],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4],[0,1,2,4],[0,1,3],[0,1,3,4],[0,1,4],[0,2],[0,2,3],[0,2,3,4],[0,2,4],[0,3],[0,3,4],[0,4],[1],[1,2],[1,2,3],[1,2,3,4],[1,2,4],[1,3],[1,3,4],[1,4],[2],[2,3],[2,3,4],[2,4],[3],[3,4],[4]],"target_topology":[[],[0,1,2,3,4]],"map":[0,2,1,4,3]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required)

Wave5第五層核對=(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-continuous-bijection-boundary · candidate

34. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-continuous-bijection-boundary;資料={"n":5,"source_topology":[[],[0],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4],[0,1,2,4],[0,1,3],[0,1,3,4],[0,1,4],[0,2],[0,2,3],[0,2,3,4],[0,2,4],[0,3],[0,3,4],[0,4],[1],[1,2],[1,2,3],[1,2,3,4],[1,2,4],[1,3],[1,3,4],[1,4],[2],[2,3],[2,3,4],[2,4],[3],[3,4],[4]],"target_topology":[[],[0,1,2,3,4]],"map":[0,2,3,1,4]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required)

Wave5第五層核對=(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-continuous-bijection-boundary · candidate

35. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-continuous-bijection-boundary;資料={"n":5,"source_topology":[[],[0],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4],[0,1,2,4],[0,1,3],[0,1,3,4],[0,1,4],[0,2],[0,2,3],[0,2,3,4],[0,2,4],[0,3],[0,3,4],[0,4],[1],[1,2],[1,2,3],[1,2,3,4],[1,2,4],[1,3],[1,3,4],[1,4],[2],[2,3],[2,3,4],[2,4],[3],[3,4],[4]],"target_topology":[[],[0,1,2,3,4]],"map":[0,2,3,4,1]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required)

Wave5第五層核對=(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-continuous-bijection-boundary · candidate

36. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-continuous-bijection-boundary;資料={"n":5,"source_topology":[[],[0],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4],[0,1,2,4],[0,1,3],[0,1,3,4],[0,1,4],[0,2],[0,2,3],[0,2,3,4],[0,2,4],[0,3],[0,3,4],[0,4],[1],[1,2],[1,2,3],[1,2,3,4],[1,2,4],[1,3],[1,3,4],[1,4],[2],[2,3],[2,3,4],[2,4],[3],[3,4],[4]],"target_topology":[[],[0,1,2,3,4]],"map":[0,2,4,1,3]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required)

Wave5第五層核對=(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-continuous-bijection-boundary · candidate

37. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-continuous-bijection-boundary;資料={"n":5,"source_topology":[[],[0],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4],[0,1,2,4],[0,1,3],[0,1,3,4],[0,1,4],[0,2],[0,2,3],[0,2,3,4],[0,2,4],[0,3],[0,3,4],[0,4],[1],[1,2],[1,2,3],[1,2,3,4],[1,2,4],[1,3],[1,3,4],[1,4],[2],[2,3],[2,3,4],[2,4],[3],[3,4],[4]],"target_topology":[[],[0,1,2,3,4]],"map":[0,2,4,3,1]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required)

Wave5第五層核對=(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-continuous-bijection-boundary · candidate

38. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-continuous-bijection-boundary;資料={"n":5,"source_topology":[[],[0],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4],[0,1,2,4],[0,1,3],[0,1,3,4],[0,1,4],[0,2],[0,2,3],[0,2,3,4],[0,2,4],[0,3],[0,3,4],[0,4],[1],[1,2],[1,2,3],[1,2,3,4],[1,2,4],[1,3],[1,3,4],[1,4],[2],[2,3],[2,3,4],[2,4],[3],[3,4],[4]],"target_topology":[[],[0,1,2,3,4]],"map":[0,3,1,2,4]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required)

Wave5第五層核對=(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-continuous-bijection-boundary · candidate

39. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-continuous-bijection-boundary;資料={"n":5,"source_topology":[[],[0],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4],[0,1,2,4],[0,1,3],[0,1,3,4],[0,1,4],[0,2],[0,2,3],[0,2,3,4],[0,2,4],[0,3],[0,3,4],[0,4],[1],[1,2],[1,2,3],[1,2,3,4],[1,2,4],[1,3],[1,3,4],[1,4],[2],[2,3],[2,3,4],[2,4],[3],[3,4],[4]],"target_topology":[[],[0,1,2,3,4]],"map":[0,3,1,4,2]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required)

Wave5第五層核對=(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-continuous-bijection-boundary · candidate

40. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-continuous-bijection-boundary;資料={"n":5,"source_topology":[[],[0],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4],[0,1,2,4],[0,1,3],[0,1,3,4],[0,1,4],[0,2],[0,2,3],[0,2,3,4],[0,2,4],[0,3],[0,3,4],[0,4],[1],[1,2],[1,2,3],[1,2,3,4],[1,2,4],[1,3],[1,3,4],[1,4],[2],[2,3],[2,3,4],[2,4],[3],[3,4],[4]],"target_topology":[[],[0,1,2,3,4]],"map":[0,3,2,1,4]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required)

Wave5第五層核對=(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-continuous-bijection-boundary · candidate

41. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-continuous-bijection-boundary;資料={"n":5,"source_topology":[[],[0],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4],[0,1,2,4],[0,1,3],[0,1,3,4],[0,1,4],[0,2],[0,2,3],[0,2,3,4],[0,2,4],[0,3],[0,3,4],[0,4],[1],[1,2],[1,2,3],[1,2,3,4],[1,2,4],[1,3],[1,3,4],[1,4],[2],[2,3],[2,3,4],[2,4],[3],[3,4],[4]],"target_topology":[[],[0,1,2,3,4]],"map":[0,3,2,4,1]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required)

Wave5第五層核對=(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-continuous-bijection-boundary · candidate

42. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-continuous-bijection-boundary;資料={"n":5,"source_topology":[[],[0],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4],[0,1,2,4],[0,1,3],[0,1,3,4],[0,1,4],[0,2],[0,2,3],[0,2,3,4],[0,2,4],[0,3],[0,3,4],[0,4],[1],[1,2],[1,2,3],[1,2,3,4],[1,2,4],[1,3],[1,3,4],[1,4],[2],[2,3],[2,3,4],[2,4],[3],[3,4],[4]],"target_topology":[[],[0,1,2,3,4]],"map":[0,3,4,1,2]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required)

Wave5第五層核對=(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-continuous-bijection-boundary · candidate

43. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-continuous-bijection-boundary;資料={"n":5,"source_topology":[[],[0],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4],[0,1,2,4],[0,1,3],[0,1,3,4],[0,1,4],[0,2],[0,2,3],[0,2,3,4],[0,2,4],[0,3],[0,3,4],[0,4],[1],[1,2],[1,2,3],[1,2,3,4],[1,2,4],[1,3],[1,3,4],[1,4],[2],[2,3],[2,3,4],[2,4],[3],[3,4],[4]],"target_topology":[[],[0,1,2,3,4]],"map":[0,3,4,2,1]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required)

Wave5第五層核對=(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-continuous-bijection-boundary · candidate

44. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-continuous-bijection-boundary;資料={"n":5,"source_topology":[[],[0],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4],[0,1,2,4],[0,1,3],[0,1,3,4],[0,1,4],[0,2],[0,2,3],[0,2,3,4],[0,2,4],[0,3],[0,3,4],[0,4],[1],[1,2],[1,2,3],[1,2,3,4],[1,2,4],[1,3],[1,3,4],[1,4],[2],[2,3],[2,3,4],[2,4],[3],[3,4],[4]],"target_topology":[[],[0,1,2,3,4]],"map":[0,4,1,2,3]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required)

Wave5第五層核對=(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-continuous-bijection-boundary · candidate

45. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-continuous-bijection-boundary;資料={"n":5,"source_topology":[[],[0],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4],[0,1,2,4],[0,1,3],[0,1,3,4],[0,1,4],[0,2],[0,2,3],[0,2,3,4],[0,2,4],[0,3],[0,3,4],[0,4],[1],[1,2],[1,2,3],[1,2,3,4],[1,2,4],[1,3],[1,3,4],[1,4],[2],[2,3],[2,3,4],[2,4],[3],[3,4],[4]],"target_topology":[[],[0,1,2,3,4]],"map":[0,4,1,3,2]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required)

Wave5第五層核對=(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-continuous-bijection-boundary · candidate

46. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-continuous-bijection-boundary;資料={"n":5,"source_topology":[[],[0],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4],[0,1,2,4],[0,1,3],[0,1,3,4],[0,1,4],[0,2],[0,2,3],[0,2,3,4],[0,2,4],[0,3],[0,3,4],[0,4],[1],[1,2],[1,2,3],[1,2,3,4],[1,2,4],[1,3],[1,3,4],[1,4],[2],[2,3],[2,3,4],[2,4],[3],[3,4],[4]],"target_topology":[[],[0,1,2,3,4]],"map":[0,4,2,1,3]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required)

Wave5第五層核對=(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-continuous-bijection-boundary · candidate

47. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-continuous-bijection-boundary;資料={"n":5,"source_topology":[[],[0],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4],[0,1,2,4],[0,1,3],[0,1,3,4],[0,1,4],[0,2],[0,2,3],[0,2,3,4],[0,2,4],[0,3],[0,3,4],[0,4],[1],[1,2],[1,2,3],[1,2,3,4],[1,2,4],[1,3],[1,3,4],[1,4],[2],[2,3],[2,3,4],[2,4],[3],[3,4],[4]],"target_topology":[[],[0,1,2,3,4]],"map":[0,4,2,3,1]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required)

Wave5第五層核對=(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-continuous-bijection-boundary · candidate

48. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-continuous-bijection-boundary;資料={"n":5,"source_topology":[[],[0],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4],[0,1,2,4],[0,1,3],[0,1,3,4],[0,1,4],[0,2],[0,2,3],[0,2,3,4],[0,2,4],[0,3],[0,3,4],[0,4],[1],[1,2],[1,2,3],[1,2,3,4],[1,2,4],[1,3],[1,3,4],[1,4],[2],[2,3],[2,3,4],[2,4],[3],[3,4],[4]],"target_topology":[[],[0,1,2,3,4]],"map":[0,4,3,1,2]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required)

Wave5第五層核對=(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-continuous-bijection-boundary · candidate

49. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-continuous-bijection-boundary;資料={"n":5,"source_topology":[[],[0],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4],[0,1,2,4],[0,1,3],[0,1,3,4],[0,1,4],[0,2],[0,2,3],[0,2,3,4],[0,2,4],[0,3],[0,3,4],[0,4],[1],[1,2],[1,2,3],[1,2,3,4],[1,2,4],[1,3],[1,3,4],[1,4],[2],[2,3],[2,3,4],[2,4],[3],[3,4],[4]],"target_topology":[[],[0,1,2,3,4]],"map":[0,4,3,2,1]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required)

Wave5第五層核對=(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-continuous-bijection-boundary · candidate

50. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-continuous-bijection-boundary;資料={"n":5,"source_topology":[[],[0],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4],[0,1,2,4],[0,1,3],[0,1,3,4],[0,1,4],[0,2],[0,2,3],[0,2,3,4],[0,2,4],[0,3],[0,3,4],[0,4],[1],[1,2],[1,2,3],[1,2,3,4],[1,2,4],[1,3],[1,3,4],[1,4],[2],[2,3],[2,3,4],[2,4],[3],[3,4],[4]],"target_topology":[[],[0,1,2,3,4]],"map":[1,0,2,3,4]}。請依 [source_topology_valid, target_topology_valid, bijection, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required)

Wave5第五層核對=(是, 是, 是, 是, 否, 否, continuous_bijection_inverse_continuity_required);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-continuous-bijection-boundary · candidate

51. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-discrete-bijection;資料={"n":5,"map":[0,1,2,3,4]}。請依 [vertex_count, map, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(5, [0, 1, 2, 3, 4], 是, 是, 是, finite_discrete_scope_only)

Wave5第五層核對=(5, [0, 1, 2, 3, 4], 是, 是, 是, finite_discrete_scope_only);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-discrete-bijection · candidate

52. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-discrete-bijection;資料={"n":5,"map":[0,1,2,4,3]}。請依 [vertex_count, map, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(5, [0, 1, 2, 4, 3], 是, 是, 是, finite_discrete_scope_only)

Wave5第五層核對=(5, [0, 1, 2, 4, 3], 是, 是, 是, finite_discrete_scope_only);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-discrete-bijection · candidate

53. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-discrete-bijection;資料={"n":5,"map":[0,1,3,2,4]}。請依 [vertex_count, map, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(5, [0, 1, 3, 2, 4], 是, 是, 是, finite_discrete_scope_only)

Wave5第五層核對=(5, [0, 1, 3, 2, 4], 是, 是, 是, finite_discrete_scope_only);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-discrete-bijection · candidate

54. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-discrete-bijection;資料={"n":5,"map":[0,1,3,4,2]}。請依 [vertex_count, map, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(5, [0, 1, 3, 4, 2], 是, 是, 是, finite_discrete_scope_only)

Wave5第五層核對=(5, [0, 1, 3, 4, 2], 是, 是, 是, finite_discrete_scope_only);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-discrete-bijection · candidate

55. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-discrete-bijection;資料={"n":5,"map":[0,1,4,2,3]}。請依 [vertex_count, map, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(5, [0, 1, 4, 2, 3], 是, 是, 是, finite_discrete_scope_only)

Wave5第五層核對=(5, [0, 1, 4, 2, 3], 是, 是, 是, finite_discrete_scope_only);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-discrete-bijection · candidate

56. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-discrete-bijection;資料={"n":5,"map":[0,1,4,3,2]}。請依 [vertex_count, map, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(5, [0, 1, 4, 3, 2], 是, 是, 是, finite_discrete_scope_only)

Wave5第五層核對=(5, [0, 1, 4, 3, 2], 是, 是, 是, finite_discrete_scope_only);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-discrete-bijection · candidate

57. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-discrete-bijection;資料={"n":5,"map":[0,2,1,3,4]}。請依 [vertex_count, map, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(5, [0, 2, 1, 3, 4], 是, 是, 是, finite_discrete_scope_only)

Wave5第五層核對=(5, [0, 2, 1, 3, 4], 是, 是, 是, finite_discrete_scope_only);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-discrete-bijection · candidate

58. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-discrete-bijection;資料={"n":5,"map":[0,2,1,4,3]}。請依 [vertex_count, map, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(5, [0, 2, 1, 4, 3], 是, 是, 是, finite_discrete_scope_only)

Wave5第五層核對=(5, [0, 2, 1, 4, 3], 是, 是, 是, finite_discrete_scope_only);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-discrete-bijection · candidate

59. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-discrete-bijection;資料={"n":5,"map":[0,2,3,1,4]}。請依 [vertex_count, map, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(5, [0, 2, 3, 1, 4], 是, 是, 是, finite_discrete_scope_only)

Wave5第五層核對=(5, [0, 2, 3, 1, 4], 是, 是, 是, finite_discrete_scope_only);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-discrete-bijection · candidate

60. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-discrete-bijection;資料={"n":5,"map":[0,2,3,4,1]}。請依 [vertex_count, map, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(5, [0, 2, 3, 4, 1], 是, 是, 是, finite_discrete_scope_only)

Wave5第五層核對=(5, [0, 2, 3, 4, 1], 是, 是, 是, finite_discrete_scope_only);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-discrete-bijection · candidate

61. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-discrete-bijection;資料={"n":5,"map":[0,2,4,1,3]}。請依 [vertex_count, map, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(5, [0, 2, 4, 1, 3], 是, 是, 是, finite_discrete_scope_only)

Wave5第五層核對=(5, [0, 2, 4, 1, 3], 是, 是, 是, finite_discrete_scope_only);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-discrete-bijection · candidate

62. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-discrete-bijection;資料={"n":5,"map":[0,2,4,3,1]}。請依 [vertex_count, map, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(5, [0, 2, 4, 3, 1], 是, 是, 是, finite_discrete_scope_only)

Wave5第五層核對=(5, [0, 2, 4, 3, 1], 是, 是, 是, finite_discrete_scope_only);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-discrete-bijection · candidate

63. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-discrete-bijection;資料={"n":5,"map":[0,3,1,2,4]}。請依 [vertex_count, map, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(5, [0, 3, 1, 2, 4], 是, 是, 是, finite_discrete_scope_only)

Wave5第五層核對=(5, [0, 3, 1, 2, 4], 是, 是, 是, finite_discrete_scope_only);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-discrete-bijection · candidate

64. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-discrete-bijection;資料={"n":5,"map":[0,3,1,4,2]}。請依 [vertex_count, map, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(5, [0, 3, 1, 4, 2], 是, 是, 是, finite_discrete_scope_only)

Wave5第五層核對=(5, [0, 3, 1, 4, 2], 是, 是, 是, finite_discrete_scope_only);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-discrete-bijection · candidate

65. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-discrete-bijection;資料={"n":5,"map":[0,3,2,1,4]}。請依 [vertex_count, map, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(5, [0, 3, 2, 1, 4], 是, 是, 是, finite_discrete_scope_only)

Wave5第五層核對=(5, [0, 3, 2, 1, 4], 是, 是, 是, finite_discrete_scope_only);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-discrete-bijection · candidate

66. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-discrete-bijection;資料={"n":5,"map":[0,3,2,4,1]}。請依 [vertex_count, map, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(5, [0, 3, 2, 4, 1], 是, 是, 是, finite_discrete_scope_only)

Wave5第五層核對=(5, [0, 3, 2, 4, 1], 是, 是, 是, finite_discrete_scope_only);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-discrete-bijection · candidate

67. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-discrete-bijection;資料={"n":5,"map":[0,3,4,1,2]}。請依 [vertex_count, map, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(5, [0, 3, 4, 1, 2], 是, 是, 是, finite_discrete_scope_only)

Wave5第五層核對=(5, [0, 3, 4, 1, 2], 是, 是, 是, finite_discrete_scope_only);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-discrete-bijection · candidate

68. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-discrete-bijection;資料={"n":5,"map":[0,3,4,2,1]}。請依 [vertex_count, map, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(5, [0, 3, 4, 2, 1], 是, 是, 是, finite_discrete_scope_only)

Wave5第五層核對=(5, [0, 3, 4, 2, 1], 是, 是, 是, finite_discrete_scope_only);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-discrete-bijection · candidate

69. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-discrete-bijection;資料={"n":5,"map":[0,4,1,2,3]}。請依 [vertex_count, map, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(5, [0, 4, 1, 2, 3], 是, 是, 是, finite_discrete_scope_only)

Wave5第五層核對=(5, [0, 4, 1, 2, 3], 是, 是, 是, finite_discrete_scope_only);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-discrete-bijection · candidate

70. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-discrete-bijection;資料={"n":5,"map":[0,4,1,3,2]}。請依 [vertex_count, map, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(5, [0, 4, 1, 3, 2], 是, 是, 是, finite_discrete_scope_only)

Wave5第五層核對=(5, [0, 4, 1, 3, 2], 是, 是, 是, finite_discrete_scope_only);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-discrete-bijection · candidate

71. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-discrete-bijection;資料={"n":5,"map":[0,4,2,1,3]}。請依 [vertex_count, map, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(5, [0, 4, 2, 1, 3], 是, 是, 是, finite_discrete_scope_only)

Wave5第五層核對=(5, [0, 4, 2, 1, 3], 是, 是, 是, finite_discrete_scope_only);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-discrete-bijection · candidate

72. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-discrete-bijection;資料={"n":5,"map":[0,4,2,3,1]}。請依 [vertex_count, map, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(5, [0, 4, 2, 3, 1], 是, 是, 是, finite_discrete_scope_only)

Wave5第五層核對=(5, [0, 4, 2, 3, 1], 是, 是, 是, finite_discrete_scope_only);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-discrete-bijection · candidate

73. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-discrete-bijection;資料={"n":5,"map":[0,4,3,1,2]}。請依 [vertex_count, map, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(5, [0, 4, 3, 1, 2], 是, 是, 是, finite_discrete_scope_only)

Wave5第五層核對=(5, [0, 4, 3, 1, 2], 是, 是, 是, finite_discrete_scope_only);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-discrete-bijection · candidate

74. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-discrete-bijection;資料={"n":5,"map":[0,4,3,2,1]}。請依 [vertex_count, map, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(5, [0, 4, 3, 2, 1], 是, 是, 是, finite_discrete_scope_only)

Wave5第五層核對=(5, [0, 4, 3, 2, 1], 是, 是, 是, finite_discrete_scope_only);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-discrete-bijection · candidate

75. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-finite-discrete-bijection;資料={"n":5,"map":[1,0,2,3,4]}。請依 [vertex_count, map, forward_continuous, inverse_continuous, homeomorphism, boundary] 欄序回答。

查看答案與解釋

(5, [1, 0, 2, 3, 4], 是, 是, 是, finite_discrete_scope_only)

Wave5第五層核對=(5, [1, 0, 2, 3, 4], 是, 是, 是, finite_discrete_scope_only);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-finite-discrete-bijection · candidate

76. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-metric-nonimplication;資料={"n":5,"map":[0,1,2,3,4],"source_scale":1,"target_scale":2}。請依 [vertex_count, homeomorphic, equal_scale_parameters, source_scale, target_scale, boundary] 欄序回答。

第三欄只比較兩個尺度參數;單點空間的等距性不由這一欄的否來否證。

查看答案與解釋

(5, 是, 否, 1, 2, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence)

Wave5第五層核對=(5, 是, 否, 1, 2, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-metric-nonimplication · candidate

77. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-metric-nonimplication;資料={"n":5,"map":[0,1,2,4,3],"source_scale":2,"target_scale":3}。請依 [vertex_count, homeomorphic, equal_scale_parameters, source_scale, target_scale, boundary] 欄序回答。

第三欄只比較兩個尺度參數;單點空間的等距性不由這一欄的否來否證。

查看答案與解釋

(5, 是, 否, 2, 3, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence)

Wave5第五層核對=(5, 是, 否, 2, 3, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-metric-nonimplication · candidate

78. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-metric-nonimplication;資料={"n":5,"map":[0,1,3,2,4],"source_scale":3,"target_scale":4}。請依 [vertex_count, homeomorphic, equal_scale_parameters, source_scale, target_scale, boundary] 欄序回答。

第三欄只比較兩個尺度參數;單點空間的等距性不由這一欄的否來否證。

查看答案與解釋

(5, 是, 否, 3, 4, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence)

Wave5第五層核對=(5, 是, 否, 3, 4, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-metric-nonimplication · candidate

79. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-metric-nonimplication;資料={"n":5,"map":[0,1,3,4,2],"source_scale":4,"target_scale":5}。請依 [vertex_count, homeomorphic, equal_scale_parameters, source_scale, target_scale, boundary] 欄序回答。

第三欄只比較兩個尺度參數;單點空間的等距性不由這一欄的否來否證。

查看答案與解釋

(5, 是, 否, 4, 5, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence)

Wave5第五層核對=(5, 是, 否, 4, 5, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-metric-nonimplication · candidate

80. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-metric-nonimplication;資料={"n":5,"map":[0,1,4,2,3],"source_scale":5,"target_scale":6}。請依 [vertex_count, homeomorphic, equal_scale_parameters, source_scale, target_scale, boundary] 欄序回答。

第三欄只比較兩個尺度參數;單點空間的等距性不由這一欄的否來否證。

查看答案與解釋

(5, 是, 否, 5, 6, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence)

Wave5第五層核對=(5, 是, 否, 5, 6, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-metric-nonimplication · candidate

81. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-metric-nonimplication;資料={"n":5,"map":[0,1,4,3,2],"source_scale":6,"target_scale":7}。請依 [vertex_count, homeomorphic, equal_scale_parameters, source_scale, target_scale, boundary] 欄序回答。

第三欄只比較兩個尺度參數;單點空間的等距性不由這一欄的否來否證。

查看答案與解釋

(5, 是, 否, 6, 7, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence)

Wave5第五層核對=(5, 是, 否, 6, 7, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-metric-nonimplication · candidate

82. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-metric-nonimplication;資料={"n":5,"map":[0,2,1,3,4],"source_scale":7,"target_scale":8}。請依 [vertex_count, homeomorphic, equal_scale_parameters, source_scale, target_scale, boundary] 欄序回答。

第三欄只比較兩個尺度參數;單點空間的等距性不由這一欄的否來否證。

查看答案與解釋

(5, 是, 否, 7, 8, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence)

Wave5第五層核對=(5, 是, 否, 7, 8, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-metric-nonimplication · candidate

83. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-metric-nonimplication;資料={"n":5,"map":[0,2,1,4,3],"source_scale":8,"target_scale":9}。請依 [vertex_count, homeomorphic, equal_scale_parameters, source_scale, target_scale, boundary] 欄序回答。

第三欄只比較兩個尺度參數;單點空間的等距性不由這一欄的否來否證。

查看答案與解釋

(5, 是, 否, 8, 9, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence)

Wave5第五層核對=(5, 是, 否, 8, 9, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-metric-nonimplication · candidate

84. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-metric-nonimplication;資料={"n":5,"map":[0,2,3,1,4],"source_scale":9,"target_scale":10}。請依 [vertex_count, homeomorphic, equal_scale_parameters, source_scale, target_scale, boundary] 欄序回答。

第三欄只比較兩個尺度參數;單點空間的等距性不由這一欄的否來否證。

查看答案與解釋

(5, 是, 否, 9, 10, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence)

Wave5第五層核對=(5, 是, 否, 9, 10, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-metric-nonimplication · candidate

85. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-metric-nonimplication;資料={"n":5,"map":[0,2,3,4,1],"source_scale":10,"target_scale":11}。請依 [vertex_count, homeomorphic, equal_scale_parameters, source_scale, target_scale, boundary] 欄序回答。

第三欄只比較兩個尺度參數;單點空間的等距性不由這一欄的否來否證。

查看答案與解釋

(5, 是, 否, 10, 11, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence)

Wave5第五層核對=(5, 是, 否, 10, 11, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-metric-nonimplication · candidate

86. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-metric-nonimplication;資料={"n":5,"map":[0,2,4,1,3],"source_scale":11,"target_scale":12}。請依 [vertex_count, homeomorphic, equal_scale_parameters, source_scale, target_scale, boundary] 欄序回答。

第三欄只比較兩個尺度參數;單點空間的等距性不由這一欄的否來否證。

查看答案與解釋

(5, 是, 否, 11, 12, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence)

Wave5第五層核對=(5, 是, 否, 11, 12, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-metric-nonimplication · candidate

87. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-metric-nonimplication;資料={"n":5,"map":[0,2,4,3,1],"source_scale":12,"target_scale":13}。請依 [vertex_count, homeomorphic, equal_scale_parameters, source_scale, target_scale, boundary] 欄序回答。

第三欄只比較兩個尺度參數;單點空間的等距性不由這一欄的否來否證。

查看答案與解釋

(5, 是, 否, 12, 13, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence)

Wave5第五層核對=(5, 是, 否, 12, 13, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-metric-nonimplication · candidate

88. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-metric-nonimplication;資料={"n":5,"map":[0,3,1,2,4],"source_scale":13,"target_scale":14}。請依 [vertex_count, homeomorphic, equal_scale_parameters, source_scale, target_scale, boundary] 欄序回答。

第三欄只比較兩個尺度參數;單點空間的等距性不由這一欄的否來否證。

查看答案與解釋

(5, 是, 否, 13, 14, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence)

Wave5第五層核對=(5, 是, 否, 13, 14, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-metric-nonimplication · candidate

89. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-metric-nonimplication;資料={"n":5,"map":[0,3,1,4,2],"source_scale":14,"target_scale":15}。請依 [vertex_count, homeomorphic, equal_scale_parameters, source_scale, target_scale, boundary] 欄序回答。

第三欄只比較兩個尺度參數;單點空間的等距性不由這一欄的否來否證。

查看答案與解釋

(5, 是, 否, 14, 15, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence)

Wave5第五層核對=(5, 是, 否, 14, 15, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-metric-nonimplication · candidate

90. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-metric-nonimplication;資料={"n":5,"map":[0,3,2,1,4],"source_scale":15,"target_scale":16}。請依 [vertex_count, homeomorphic, equal_scale_parameters, source_scale, target_scale, boundary] 欄序回答。

第三欄只比較兩個尺度參數;單點空間的等距性不由這一欄的否來否證。

查看答案與解釋

(5, 是, 否, 15, 16, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence)

Wave5第五層核對=(5, 是, 否, 15, 16, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-metric-nonimplication · candidate

91. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-metric-nonimplication;資料={"n":5,"map":[0,3,2,4,1],"source_scale":16,"target_scale":17}。請依 [vertex_count, homeomorphic, equal_scale_parameters, source_scale, target_scale, boundary] 欄序回答。

第三欄只比較兩個尺度參數;單點空間的等距性不由這一欄的否來否證。

查看答案與解釋

(5, 是, 否, 16, 17, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence)

Wave5第五層核對=(5, 是, 否, 16, 17, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-metric-nonimplication · candidate

92. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-metric-nonimplication;資料={"n":5,"map":[0,3,4,1,2],"source_scale":17,"target_scale":18}。請依 [vertex_count, homeomorphic, equal_scale_parameters, source_scale, target_scale, boundary] 欄序回答。

第三欄只比較兩個尺度參數;單點空間的等距性不由這一欄的否來否證。

查看答案與解釋

(5, 是, 否, 17, 18, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence)

Wave5第五層核對=(5, 是, 否, 17, 18, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-metric-nonimplication · candidate

93. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-metric-nonimplication;資料={"n":5,"map":[0,3,4,2,1],"source_scale":18,"target_scale":19}。請依 [vertex_count, homeomorphic, equal_scale_parameters, source_scale, target_scale, boundary] 欄序回答。

第三欄只比較兩個尺度參數;單點空間的等距性不由這一欄的否來否證。

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(5, 是, 否, 18, 19, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence)

Wave5第五層核對=(5, 是, 否, 18, 19, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-metric-nonimplication · candidate

94. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-metric-nonimplication;資料={"n":5,"map":[0,4,1,2,3],"source_scale":19,"target_scale":20}。請依 [vertex_count, homeomorphic, equal_scale_parameters, source_scale, target_scale, boundary] 欄序回答。

第三欄只比較兩個尺度參數;單點空間的等距性不由這一欄的否來否證。

查看答案與解釋

(5, 是, 否, 19, 20, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence)

Wave5第五層核對=(5, 是, 否, 19, 20, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-metric-nonimplication · candidate

95. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-metric-nonimplication;資料={"n":5,"map":[0,4,1,3,2],"source_scale":20,"target_scale":21}。請依 [vertex_count, homeomorphic, equal_scale_parameters, source_scale, target_scale, boundary] 欄序回答。

第三欄只比較兩個尺度參數;單點空間的等距性不由這一欄的否來否證。

查看答案與解釋

(5, 是, 否, 20, 21, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence)

Wave5第五層核對=(5, 是, 否, 20, 21, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-metric-nonimplication · candidate

96. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-metric-nonimplication;資料={"n":5,"map":[0,4,2,1,3],"source_scale":21,"target_scale":22}。請依 [vertex_count, homeomorphic, equal_scale_parameters, source_scale, target_scale, boundary] 欄序回答。

第三欄只比較兩個尺度參數;單點空間的等距性不由這一欄的否來否證。

查看答案與解釋

(5, 是, 否, 21, 22, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence)

Wave5第五層核對=(5, 是, 否, 21, 22, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-metric-nonimplication · candidate

97. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-metric-nonimplication;資料={"n":5,"map":[0,4,2,3,1],"source_scale":22,"target_scale":23}。請依 [vertex_count, homeomorphic, equal_scale_parameters, source_scale, target_scale, boundary] 欄序回答。

第三欄只比較兩個尺度參數;單點空間的等距性不由這一欄的否來否證。

查看答案與解釋

(5, 是, 否, 22, 23, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence)

Wave5第五層核對=(5, 是, 否, 22, 23, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-metric-nonimplication · candidate

98. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-metric-nonimplication;資料={"n":5,"map":[0,4,3,1,2],"source_scale":23,"target_scale":24}。請依 [vertex_count, homeomorphic, equal_scale_parameters, source_scale, target_scale, boundary] 欄序回答。

第三欄只比較兩個尺度參數;單點空間的等距性不由這一欄的否來否證。

查看答案與解釋

(5, 是, 否, 23, 24, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence)

Wave5第五層核對=(5, 是, 否, 23, 24, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-metric-nonimplication · candidate

99. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-metric-nonimplication;資料={"n":5,"map":[0,4,3,2,1],"source_scale":24,"target_scale":25}。請依 [vertex_count, homeomorphic, equal_scale_parameters, source_scale, target_scale, boundary] 欄序回答。

第三欄只比較兩個尺度參數;單點空間的等距性不由這一欄的否來否證。

查看答案與解釋

(5, 是, 否, 24, 25, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence)

Wave5第五層核對=(5, 是, 否, 24, 25, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-metric-nonimplication · candidate

100. 同胚

完整有限來源與目標拓撲、雙射及全部開集逆像。操作=homeo-metric-nonimplication;資料={"n":5,"map":[1,0,2,3,4],"source_scale":25,"target_scale":26}。請依 [vertex_count, homeomorphic, equal_scale_parameters, source_scale, target_scale, boundary] 欄序回答。

第三欄只比較兩個尺度參數;單點空間的等距性不由這一欄的否來否證。

查看答案與解釋

(5, 是, 否, 25, 26, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence)

Wave5第五層核對=(5, 是, 否, 25, 26, homeomorphism_does_not_imply_isometry_diffeomorphism_or_congruence);依完整明示資料獨立重算;homeomorphism同時要求f連續及逆映射連續;一般continuous bijection不足;有限離散雙射結論不得外推,也不推出等距、可微或幾何全等。

本題逐步詳解(AI 二次覆核)

同胚 · qf-mod36-homeo-metric-nonimplication · candidate

原始題目 JSONL · 驗收報告