依機率收斂基礎 · 脈衝 R07
本批已通過 Schema、去重、來源快照與獨立答案重算;仍未標記為人工審定。
本題庫已有對應的中英逐步詳解。原題的 candidate 與英文 ai_candidate 狀態保留;AI 覆核、有限計算與 Lean 形式證明分開標示。
batch-20261014-advance-20261030-r07-convergence-in-probability-foundations · 2026-10-14 · 100 題
1. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability;資料={"numerator":1,"shift":2,"n":1}。請依 [numerator,shift,n,probability] 欄序回答。
查看答案與解釋
(1, 2, 1, 1/3)
Wave4第四層核對=(1, 2, 1, 1/3);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-deviation-probability · candidate
2. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability;資料={"numerator":2,"shift":3,"n":2}。請依 [numerator,shift,n,probability] 欄序回答。
查看答案與解釋
(2, 3, 2, 2/5)
Wave4第四層核對=(2, 3, 2, 2/5);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-deviation-probability · candidate
3. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability;資料={"numerator":3,"shift":4,"n":3}。請依 [numerator,shift,n,probability] 欄序回答。
查看答案與解釋
(3, 4, 3, 3/7)
Wave4第四層核對=(3, 4, 3, 3/7);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-deviation-probability · candidate
4. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability;資料={"numerator":4,"shift":5,"n":4}。請依 [numerator,shift,n,probability] 欄序回答。
查看答案與解釋
(4, 5, 4, 4/9)
Wave4第四層核對=(4, 5, 4, 4/9);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-deviation-probability · candidate
5. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability;資料={"numerator":5,"shift":6,"n":5}。請依 [numerator,shift,n,probability] 欄序回答。
查看答案與解釋
(5, 6, 5, 5/11)
Wave4第四層核對=(5, 6, 5, 5/11);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-deviation-probability · candidate
6. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability;資料={"numerator":1,"shift":7,"n":6}。請依 [numerator,shift,n,probability] 欄序回答。
查看答案與解釋
(1, 7, 6, 1/13)
Wave4第四層核對=(1, 7, 6, 1/13);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-deviation-probability · candidate
7. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability;資料={"numerator":2,"shift":8,"n":7}。請依 [numerator,shift,n,probability] 欄序回答。
查看答案與解釋
(2, 8, 7, 2/15)
Wave4第四層核對=(2, 8, 7, 2/15);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-deviation-probability · candidate
8. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability;資料={"numerator":3,"shift":2,"n":8}。請依 [numerator,shift,n,probability] 欄序回答。
查看答案與解釋
(3, 2, 8, 3/10)
Wave4第四層核對=(3, 2, 8, 3/10);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-deviation-probability · candidate
9. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability;資料={"numerator":4,"shift":3,"n":9}。請依 [numerator,shift,n,probability] 欄序回答。
查看答案與解釋
(4, 3, 9, 1/3)
Wave4第四層核對=(4, 3, 9, 1/3);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-deviation-probability · candidate
10. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability;資料={"numerator":5,"shift":4,"n":10}。請依 [numerator,shift,n,probability] 欄序回答。
查看答案與解釋
(5, 4, 10, 5/14)
Wave4第四層核對=(5, 4, 10, 5/14);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-deviation-probability · candidate
11. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability;資料={"numerator":1,"shift":5,"n":11}。請依 [numerator,shift,n,probability] 欄序回答。
查看答案與解釋
(1, 5, 11, 1/16)
Wave4第四層核對=(1, 5, 11, 1/16);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-deviation-probability · candidate
12. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability;資料={"numerator":2,"shift":6,"n":12}。請依 [numerator,shift,n,probability] 欄序回答。
查看答案與解釋
(2, 6, 12, 1/9)
Wave4第四層核對=(2, 6, 12, 1/9);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-deviation-probability · candidate
13. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability;資料={"numerator":3,"shift":7,"n":13}。請依 [numerator,shift,n,probability] 欄序回答。
查看答案與解釋
(3, 7, 13, 3/20)
Wave4第四層核對=(3, 7, 13, 3/20);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-deviation-probability · candidate
14. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability;資料={"numerator":4,"shift":8,"n":14}。請依 [numerator,shift,n,probability] 欄序回答。
查看答案與解釋
(4, 8, 14, 2/11)
Wave4第四層核對=(4, 8, 14, 2/11);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-deviation-probability · candidate
15. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability;資料={"numerator":5,"shift":2,"n":15}。請依 [numerator,shift,n,probability] 欄序回答。
查看答案與解釋
(5, 2, 15, 5/17)
Wave4第四層核對=(5, 2, 15, 5/17);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-deviation-probability · candidate
16. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability;資料={"numerator":1,"shift":3,"n":16}。請依 [numerator,shift,n,probability] 欄序回答。
查看答案與解釋
(1, 3, 16, 1/19)
Wave4第四層核對=(1, 3, 16, 1/19);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-deviation-probability · candidate
17. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability;資料={"numerator":2,"shift":4,"n":17}。請依 [numerator,shift,n,probability] 欄序回答。
查看答案與解釋
(2, 4, 17, 2/21)
Wave4第四層核對=(2, 4, 17, 2/21);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-deviation-probability · candidate
18. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability;資料={"numerator":3,"shift":5,"n":18}。請依 [numerator,shift,n,probability] 欄序回答。
查看答案與解釋
(3, 5, 18, 3/23)
Wave4第四層核對=(3, 5, 18, 3/23);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-deviation-probability · candidate
19. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability;資料={"numerator":4,"shift":6,"n":19}。請依 [numerator,shift,n,probability] 欄序回答。
查看答案與解釋
(4, 6, 19, 4/25)
Wave4第四層核對=(4, 6, 19, 4/25);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-deviation-probability · candidate
20. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability;資料={"numerator":5,"shift":7,"n":20}。請依 [numerator,shift,n,probability] 欄序回答。
查看答案與解釋
(5, 7, 20, 5/27)
Wave4第四層核對=(5, 7, 20, 5/27);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-deviation-probability · candidate
21. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability;資料={"numerator":1,"shift":8,"n":21}。請依 [numerator,shift,n,probability] 欄序回答。
查看答案與解釋
(1, 8, 21, 1/29)
Wave4第四層核對=(1, 8, 21, 1/29);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-deviation-probability · candidate
22. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability;資料={"numerator":2,"shift":2,"n":22}。請依 [numerator,shift,n,probability] 欄序回答。
查看答案與解釋
(2, 2, 22, 1/12)
Wave4第四層核對=(2, 2, 22, 1/12);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-deviation-probability · candidate
23. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability;資料={"numerator":3,"shift":3,"n":23}。請依 [numerator,shift,n,probability] 欄序回答。
查看答案與解釋
(3, 3, 23, 3/26)
Wave4第四層核對=(3, 3, 23, 3/26);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-deviation-probability · candidate
24. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability;資料={"numerator":4,"shift":4,"n":24}。請依 [numerator,shift,n,probability] 欄序回答。
查看答案與解釋
(4, 4, 24, 1/7)
Wave4第四層核對=(4, 4, 24, 1/7);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-deviation-probability · candidate
25. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-deviation-probability;資料={"numerator":5,"shift":5,"n":25}。請依 [numerator,shift,n,probability] 欄序回答。
查看答案與解釋
(5, 5, 25, 1/6)
Wave4第四層核對=(5, 5, 25, 1/6);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-deviation-probability · candidate
26. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness;資料={"numerator":1,"shift":2,"delta":[1,10]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。
查看答案與解釋
(1, 2, 1/10, 9, 1/11, 是, forall_n_ge_N_tail_bound)
Wave4第四層核對=(1, 2, 1/10, 9, 1/11, 是, forall_n_ge_N_tail_bound);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate
27. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness;資料={"numerator":2,"shift":3,"delta":[1,11]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。
查看答案與解釋
(2, 3, 1/11, 20, 2/23, 是, forall_n_ge_N_tail_bound)
Wave4第四層核對=(2, 3, 1/11, 20, 2/23, 是, forall_n_ge_N_tail_bound);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate
28. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness;資料={"numerator":3,"shift":4,"delta":[1,12]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。
查看答案與解釋
(3, 4, 1/12, 33, 3/37, 是, forall_n_ge_N_tail_bound)
Wave4第四層核對=(3, 4, 1/12, 33, 3/37, 是, forall_n_ge_N_tail_bound);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate
29. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness;資料={"numerator":4,"shift":5,"delta":[1,13]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。
查看答案與解釋
(4, 5, 1/13, 48, 4/53, 是, forall_n_ge_N_tail_bound)
Wave4第四層核對=(4, 5, 1/13, 48, 4/53, 是, forall_n_ge_N_tail_bound);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate
30. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness;資料={"numerator":5,"shift":6,"delta":[1,14]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。
查看答案與解釋
(5, 6, 1/14, 65, 5/71, 是, forall_n_ge_N_tail_bound)
Wave4第四層核對=(5, 6, 1/14, 65, 5/71, 是, forall_n_ge_N_tail_bound);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate
31. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness;資料={"numerator":1,"shift":7,"delta":[1,15]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。
查看答案與解釋
(1, 7, 1/15, 9, 1/16, 是, forall_n_ge_N_tail_bound)
Wave4第四層核對=(1, 7, 1/15, 9, 1/16, 是, forall_n_ge_N_tail_bound);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate
32. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness;資料={"numerator":2,"shift":8,"delta":[1,16]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。
查看答案與解釋
(2, 8, 1/16, 25, 2/33, 是, forall_n_ge_N_tail_bound)
Wave4第四層核對=(2, 8, 1/16, 25, 2/33, 是, forall_n_ge_N_tail_bound);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate
33. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness;資料={"numerator":3,"shift":2,"delta":[1,17]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。
查看答案與解釋
(3, 2, 1/17, 50, 3/52, 是, forall_n_ge_N_tail_bound)
Wave4第四層核對=(3, 2, 1/17, 50, 3/52, 是, forall_n_ge_N_tail_bound);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate
34. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness;資料={"numerator":4,"shift":3,"delta":[1,18]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。
查看答案與解釋
(4, 3, 1/18, 70, 4/73, 是, forall_n_ge_N_tail_bound)
Wave4第四層核對=(4, 3, 1/18, 70, 4/73, 是, forall_n_ge_N_tail_bound);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate
35. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness;資料={"numerator":5,"shift":4,"delta":[1,19]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。
查看答案與解釋
(5, 4, 1/19, 92, 5/96, 是, forall_n_ge_N_tail_bound)
Wave4第四層核對=(5, 4, 1/19, 92, 5/96, 是, forall_n_ge_N_tail_bound);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate
36. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness;資料={"numerator":1,"shift":5,"delta":[1,20]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。
查看答案與解釋
(1, 5, 1/20, 16, 1/21, 是, forall_n_ge_N_tail_bound)
Wave4第四層核對=(1, 5, 1/20, 16, 1/21, 是, forall_n_ge_N_tail_bound);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate
37. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness;資料={"numerator":2,"shift":6,"delta":[1,21]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。
查看答案與解釋
(2, 6, 1/21, 37, 2/43, 是, forall_n_ge_N_tail_bound)
Wave4第四層核對=(2, 6, 1/21, 37, 2/43, 是, forall_n_ge_N_tail_bound);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate
38. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness;資料={"numerator":3,"shift":7,"delta":[1,22]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。
查看答案與解釋
(3, 7, 1/22, 60, 3/67, 是, forall_n_ge_N_tail_bound)
Wave4第四層核對=(3, 7, 1/22, 60, 3/67, 是, forall_n_ge_N_tail_bound);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate
39. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness;資料={"numerator":4,"shift":8,"delta":[1,23]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。
查看答案與解釋
(4, 8, 1/23, 85, 4/93, 是, forall_n_ge_N_tail_bound)
Wave4第四層核對=(4, 8, 1/23, 85, 4/93, 是, forall_n_ge_N_tail_bound);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate
40. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness;資料={"numerator":5,"shift":2,"delta":[1,24]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。
查看答案與解釋
(5, 2, 1/24, 119, 5/121, 是, forall_n_ge_N_tail_bound)
Wave4第四層核對=(5, 2, 1/24, 119, 5/121, 是, forall_n_ge_N_tail_bound);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate
41. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness;資料={"numerator":1,"shift":3,"delta":[1,25]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。
查看答案與解釋
(1, 3, 1/25, 23, 1/26, 是, forall_n_ge_N_tail_bound)
Wave4第四層核對=(1, 3, 1/25, 23, 1/26, 是, forall_n_ge_N_tail_bound);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate
42. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness;資料={"numerator":2,"shift":4,"delta":[1,26]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。
查看答案與解釋
(2, 4, 1/26, 49, 2/53, 是, forall_n_ge_N_tail_bound)
Wave4第四層核對=(2, 4, 1/26, 49, 2/53, 是, forall_n_ge_N_tail_bound);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate
43. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness;資料={"numerator":3,"shift":5,"delta":[1,27]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。
查看答案與解釋
(3, 5, 1/27, 77, 3/82, 是, forall_n_ge_N_tail_bound)
Wave4第四層核對=(3, 5, 1/27, 77, 3/82, 是, forall_n_ge_N_tail_bound);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate
44. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness;資料={"numerator":4,"shift":6,"delta":[1,28]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。
查看答案與解釋
(4, 6, 1/28, 107, 4/113, 是, forall_n_ge_N_tail_bound)
Wave4第四層核對=(4, 6, 1/28, 107, 4/113, 是, forall_n_ge_N_tail_bound);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate
45. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness;資料={"numerator":5,"shift":7,"delta":[1,29]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。
查看答案與解釋
(5, 7, 1/29, 139, 5/146, 是, forall_n_ge_N_tail_bound)
Wave4第四層核對=(5, 7, 1/29, 139, 5/146, 是, forall_n_ge_N_tail_bound);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate
46. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness;資料={"numerator":1,"shift":8,"delta":[1,30]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。
查看答案與解釋
(1, 8, 1/30, 23, 1/31, 是, forall_n_ge_N_tail_bound)
Wave4第四層核對=(1, 8, 1/30, 23, 1/31, 是, forall_n_ge_N_tail_bound);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate
47. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness;資料={"numerator":2,"shift":2,"delta":[1,31]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。
查看答案與解釋
(2, 2, 1/31, 61, 2/63, 是, forall_n_ge_N_tail_bound)
Wave4第四層核對=(2, 2, 1/31, 61, 2/63, 是, forall_n_ge_N_tail_bound);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate
48. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness;資料={"numerator":3,"shift":3,"delta":[1,32]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。
查看答案與解釋
(3, 3, 1/32, 94, 3/97, 是, forall_n_ge_N_tail_bound)
Wave4第四層核對=(3, 3, 1/32, 94, 3/97, 是, forall_n_ge_N_tail_bound);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate
49. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness;資料={"numerator":4,"shift":4,"delta":[1,33]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。
查看答案與解釋
(4, 4, 1/33, 129, 4/133, 是, forall_n_ge_N_tail_bound)
Wave4第四層核對=(4, 4, 1/33, 129, 4/133, 是, forall_n_ge_N_tail_bound);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate
50. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-epsilon-witness;資料={"numerator":5,"shift":5,"delta":[1,34]}。請依 [numerator,shift,delta,N,bound,pass,certificate] 欄序回答。
查看答案與解釋
(5, 5, 1/34, 166, 5/171, 是, forall_n_ge_N_tail_bound)
Wave4第四層核對=(5, 5, 1/34, 166, 5/171, 是, forall_n_ge_N_tail_bound);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-epsilon-witness · candidate
51. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary;資料={"numerator":1,"shift":2,"prefix_length":1}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。
查看答案與解釋
(1, 2, 1, [1/2], 否, finite_prefix_not_convergence_certificate)
Wave4第四層核對=(1, 2, 1, [1/2], 否, finite_prefix_not_convergence_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate
52. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary;資料={"numerator":2,"shift":3,"prefix_length":2}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。
查看答案與解釋
(2, 3, 2, [2/3, 1/2], 否, finite_prefix_not_convergence_certificate)
Wave4第四層核對=(2, 3, 2, [2/3, 1/2], 否, finite_prefix_not_convergence_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate
53. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary;資料={"numerator":3,"shift":4,"prefix_length":3}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。
查看答案與解釋
(3, 4, 3, [3/4, 3/5, 1/2], 否, finite_prefix_not_convergence_certificate)
Wave4第四層核對=(3, 4, 3, [3/4, 3/5, 1/2], 否, finite_prefix_not_convergence_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate
54. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary;資料={"numerator":4,"shift":5,"prefix_length":4}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。
查看答案與解釋
(4, 5, 4, [4/5, 2/3, 4/7, 1/2], 否, finite_prefix_not_convergence_certificate)
Wave4第四層核對=(4, 5, 4, [4/5, 2/3, 4/7, 1/2], 否, finite_prefix_not_convergence_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate
55. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary;資料={"numerator":5,"shift":6,"prefix_length":5}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。
查看答案與解釋
(5, 6, 5, [5/6, 5/7, 5/8, 5/9, 1/2], 否, finite_prefix_not_convergence_certificate)
Wave4第四層核對=(5, 6, 5, [5/6, 5/7, 5/8, 5/9, 1/2], 否, finite_prefix_not_convergence_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate
56. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary;資料={"numerator":1,"shift":7,"prefix_length":6}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。
查看答案與解釋
(1, 7, 6, [1/7, 1/8, 1/9, 1/10, 1/11, 1/12], 否, finite_prefix_not_convergence_certificate)
Wave4第四層核對=(1, 7, 6, [1/7, 1/8, 1/9, 1/10, 1/11, 1/12], 否, finite_prefix_not_convergence_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate
57. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary;資料={"numerator":2,"shift":8,"prefix_length":7}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。
查看答案與解釋
(2, 8, 7, [1/4, 2/9, 1/5, 2/11, 1/6, 2/13, 1/7], 否, finite_prefix_not_convergence_certificate)
Wave4第四層核對=(2, 8, 7, [1/4, 2/9, 1/5, 2/11, 1/6, 2/13, 1/7], 否, finite_prefix_not_convergence_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate
58. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary;資料={"numerator":3,"shift":3,"prefix_length":8}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。
查看答案與解釋
(3, 3, 8, [1, 3/4, 3/5, 1/2, 3/7, 3/8, 1/3, 3/10], 否, finite_prefix_not_convergence_certificate)
Wave4第四層核對=(3, 3, 8, [1, 3/4, 3/5, 1/2, 3/7, 3/8, 1/3, 3/10], 否, finite_prefix_not_convergence_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate
59. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary;資料={"numerator":4,"shift":4,"prefix_length":9}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。
查看答案與解釋
(4, 4, 9, [1, 4/5, 2/3, 4/7, 1/2, 4/9, 2/5, 4/11, 1/3], 否, finite_prefix_not_convergence_certificate)
Wave4第四層核對=(4, 4, 9, [1, 4/5, 2/3, 4/7, 1/2, 4/9, 2/5, 4/11, 1/3], 否, finite_prefix_not_convergence_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate
60. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary;資料={"numerator":5,"shift":5,"prefix_length":10}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。
查看答案與解釋
(5, 5, 10, [1, 5/6, 5/7, 5/8, 5/9, 1/2, 5/11, 5/12, 5/13, 5/14], 否, finite_prefix_not_convergence_certificate)
Wave4第四層核對=(5, 5, 10, [1, 5/6, 5/7, 5/8, 5/9, 1/2, 5/11, 5/12, 5/13, 5/14], 否, finite_prefix_not_convergence_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate
61. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary;資料={"numerator":1,"shift":5,"prefix_length":11}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。
查看答案與解釋
(1, 5, 11, [1/5, 1/6, 1/7, 1/8, 1/9, 1/10, 1/11, 1/12, 1/13, 1/14, 1/15], 否, finite_prefix_not_convergence_certificate)
Wave4第四層核對=(1, 5, 11, [1/5, 1/6, 1/7, 1/8, 1/9, 1/10, 1/11, 1/12, 1/13, 1/14, 1/15], 否, finite_prefix_not_convergence_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate
62. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary;資料={"numerator":2,"shift":6,"prefix_length":12}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。
查看答案與解釋
(2, 6, 12, [1/3, 2/7, 1/4, 2/9, 1/5, 2/11, 1/6, 2/13, 1/7, 2/15, 1/8, 2/17], 否, finite_prefix_not_convergence_certificate)
Wave4第四層核對=(2, 6, 12, [1/3, 2/7, 1/4, 2/9, 1/5, 2/11, 1/6, 2/13, 1/7, 2/15, 1/8, 2/17], 否, finite_prefix_not_convergence_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate
63. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary;資料={"numerator":3,"shift":7,"prefix_length":13}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。
查看答案與解釋
(3, 7, 13, [3/7, 3/8, 1/3, 3/10, 3/11, 1/4, 3/13, 3/14, 1/5, 3/16, 3/17, 1/6, 3/19], 否, finite_prefix_not_convergence_certificate)
Wave4第四層核對=(3, 7, 13, [3/7, 3/8, 1/3, 3/10, 3/11, 1/4, 3/13, 3/14, 1/5, 3/16, 3/17, 1/6, 3/19], 否, finite_prefix_not_convergence_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate
64. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary;資料={"numerator":4,"shift":8,"prefix_length":14}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。
查看答案與解釋
(4, 8, 14, [1/2, 4/9, 2/5, 4/11, 1/3, 4/13, 2/7, 4/15, 1/4, 4/17, 2/9, 4/19, 1/5, 4/21], 否, finite_prefix_not_convergence_certificate)
Wave4第四層核對=(4, 8, 14, [1/2, 4/9, 2/5, 4/11, 1/3, 4/13, 2/7, 4/15, 1/4, 4/17, 2/9, 4/19, 1/5, 4/21], 否, finite_prefix_not_convergence_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate
65. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary;資料={"numerator":5,"shift":5,"prefix_length":15}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。
查看答案與解釋
(5, 5, 15, [1, 5/6, 5/7, 5/8, 5/9, 1/2, 5/11, 5/12, 5/13, 5/14, 1/3, 5/16, 5/17, 5/18, 5/19], 否, finite_prefix_not_convergence_certificate)
Wave4第四層核對=(5, 5, 15, [1, 5/6, 5/7, 5/8, 5/9, 1/2, 5/11, 5/12, 5/13, 5/14, 1/3, 5/16, 5/17, 5/18, 5/19], 否, finite_prefix_not_convergence_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate
66. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary;資料={"numerator":1,"shift":3,"prefix_length":16}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。
查看答案與解釋
(1, 3, 16, [1/3, 1/4, 1/5, 1/6, 1/7, 1/8, 1/9, 1/10, 1/11, 1/12, 1/13, 1/14, 1/15, 1/16, 1/17, 1/18], 否, finite_prefix_not_convergence_certificate)
Wave4第四層核對=(1, 3, 16, [1/3, 1/4, 1/5, 1/6, 1/7, 1/8, 1/9, 1/10, 1/11, 1/12, 1/13, 1/14, 1/15, 1/16, 1/17, 1/18], 否, finite_prefix_not_convergence_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate
67. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary;資料={"numerator":2,"shift":4,"prefix_length":17}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。
查看答案與解釋
(2, 4, 17, [1/2, 2/5, 1/3, 2/7, 1/4, 2/9, 1/5, 2/11, 1/6, 2/13, 1/7, 2/15, 1/8, 2/17, 1/9, 2/19, 1/10], 否, finite_prefix_not_convergence_certificate)
Wave4第四層核對=(2, 4, 17, [1/2, 2/5, 1/3, 2/7, 1/4, 2/9, 1/5, 2/11, 1/6, 2/13, 1/7, 2/15, 1/8, 2/17, 1/9, 2/19, 1/10], 否, finite_prefix_not_convergence_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate
68. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary;資料={"numerator":3,"shift":5,"prefix_length":18}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。
查看答案與解釋
(3, 5, 18, [3/5, 1/2, 3/7, 3/8, 1/3, 3/10, 3/11, 1/4, 3/13, 3/14, 1/5, 3/16, 3/17, 1/6, 3/19, 3/20, 1/7, 3/22], 否, finite_prefix_not_convergence_certificate)
Wave4第四層核對=(3, 5, 18, [3/5, 1/2, 3/7, 3/8, 1/3, 3/10, 3/11, 1/4, 3/13, 3/14, 1/5, 3/16, 3/17, 1/6, 3/19, 3/20, 1/7, 3/22], 否, finite_prefix_not_convergence_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate
69. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary;資料={"numerator":4,"shift":6,"prefix_length":19}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。
查看答案與解釋
(4, 6, 19, [2/3, 4/7, 1/2, 4/9, 2/5, 4/11, 1/3, 4/13, 2/7, 4/15, 1/4, 4/17, 2/9, 4/19, 1/5, 4/21, 2/11, 4/23, 1/6], 否, finite_prefix_not_convergence_certificate)
Wave4第四層核對=(4, 6, 19, [2/3, 4/7, 1/2, 4/9, 2/5, 4/11, 1/3, 4/13, 2/7, 4/15, 1/4, 4/17, 2/9, 4/19, 1/5, 4/21, 2/11, 4/23, 1/6], 否, finite_prefix_not_convergence_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate
70. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary;資料={"numerator":5,"shift":7,"prefix_length":20}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。
查看答案與解釋
(5, 7, 20, [5/7, 5/8, 5/9, 1/2, 5/11, 5/12, 5/13, 5/14, 1/3, 5/16, 5/17, 5/18, 5/19, 1/4, 5/21, 5/22, 5/23, 5/24, 1/5, 5/26], 否, finite_prefix_not_convergence_certificate)
Wave4第四層核對=(5, 7, 20, [5/7, 5/8, 5/9, 1/2, 5/11, 5/12, 5/13, 5/14, 1/3, 5/16, 5/17, 5/18, 5/19, 1/4, 5/21, 5/22, 5/23, 5/24, 1/5, 5/26], 否, finite_prefix_not_convergence_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate
71. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary;資料={"numerator":1,"shift":8,"prefix_length":21}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。
查看答案與解釋
(1, 8, 21, [1/8, 1/9, 1/10, 1/11, 1/12, 1/13, 1/14, 1/15, 1/16, 1/17, 1/18, 1/19, 1/20, 1/21, 1/22, 1/23, 1/24, 1/25, 1/26, 1/27, 1/28], 否, finite_prefix_not_convergence_certificate)
Wave4第四層核對=(1, 8, 21, [1/8, 1/9, 1/10, 1/11, 1/12, 1/13, 1/14, 1/15, 1/16, 1/17, 1/18, 1/19, 1/20, 1/21, 1/22, 1/23, 1/24, 1/25, 1/26, 1/27, 1/28], 否, finite_prefix_not_convergence_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate
72. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary;資料={"numerator":2,"shift":2,"prefix_length":22}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。
查看答案與解釋
(2, 2, 22, [1, 2/3, 1/2, 2/5, 1/3, 2/7, 1/4, 2/9, 1/5, 2/11, 1/6, 2/13, 1/7, 2/15, 1/8, 2/17, 1/9, 2/19, 1/10, 2/21, 1/11, 2/23], 否, finite_prefix_not_convergence_certificate)
Wave4第四層核對=(2, 2, 22, [1, 2/3, 1/2, 2/5, 1/3, 2/7, 1/4, 2/9, 1/5, 2/11, 1/6, 2/13, 1/7, 2/15, 1/8, 2/17, 1/9, 2/19, 1/10, 2/21, 1/11, 2/23], 否, finite_prefix_not_convergence_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate
73. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary;資料={"numerator":3,"shift":3,"prefix_length":23}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。
查看答案與解釋
(3, 3, 23, [1, 3/4, 3/5, 1/2, 3/7, 3/8, 1/3, 3/10, 3/11, 1/4, 3/13, 3/14, 1/5, 3/16, 3/17, 1/6, 3/19, 3/20, 1/7, 3/22, 3/23, 1/8, 3/25], 否, finite_prefix_not_convergence_certificate)
Wave4第四層核對=(3, 3, 23, [1, 3/4, 3/5, 1/2, 3/7, 3/8, 1/3, 3/10, 3/11, 1/4, 3/13, 3/14, 1/5, 3/16, 3/17, 1/6, 3/19, 3/20, 1/7, 3/22, 3/23, 1/8, 3/25], 否, finite_prefix_not_convergence_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate
74. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary;資料={"numerator":4,"shift":4,"prefix_length":24}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。
查看答案與解釋
(4, 4, 24, [1, 4/5, 2/3, 4/7, 1/2, 4/9, 2/5, 4/11, 1/3, 4/13, 2/7, 4/15, 1/4, 4/17, 2/9, 4/19, 1/5, 4/21, 2/11, 4/23, 1/6, 4/25, 2/13, 4/27], 否, finite_prefix_not_convergence_certificate)
Wave4第四層核對=(4, 4, 24, [1, 4/5, 2/3, 4/7, 1/2, 4/9, 2/5, 4/11, 1/3, 4/13, 2/7, 4/15, 1/4, 4/17, 2/9, 4/19, 1/5, 4/21, 2/11, 4/23, 1/6, 4/25, 2/13, 4/27], 否, finite_prefix_not_convergence_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate
75. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-finite-prefix-boundary;資料={"numerator":5,"shift":5,"prefix_length":25}。請依 [numerator,shift,prefix_length,values,convergence_proved,boundary] 欄序回答。
查看答案與解釋
(5, 5, 25, [1, 5/6, 5/7, 5/8, 5/9, 1/2, 5/11, 5/12, 5/13, 5/14, 1/3, 5/16, 5/17, 5/18, 5/19, 1/4, 5/21, 5/22, 5/23, 5/24, 1/5, 5/26, 5/27, 5/28, 5/29], 否, finite_prefix_not_convergence_certificate)
Wave4第四層核對=(5, 5, 25, [1, 5/6, 5/7, 5/8, 5/9, 1/2, 5/11, 5/12, 5/13, 5/14, 1/3, 5/16, 5/17, 5/18, 5/19, 1/4, 5/21, 5/22, 5/23, 5/24, 1/5, 5/26, 5/27, 5/28, 5/29], 否, finite_prefix_not_convergence_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-finite-prefix-boundary · candidate
76. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality;資料={"settling_index":1,"n":0}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。
查看答案與解釋
(1, 0, not_yet_zero, 是, eventual_equality_universal_tail_certificate)
Wave4第四層核對=(1, 0, not_yet_zero, 是, eventual_equality_universal_tail_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-eventual-equality · candidate
77. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality;資料={"settling_index":2,"n":1}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。
查看答案與解釋
(2, 1, not_yet_zero, 是, eventual_equality_universal_tail_certificate)
Wave4第四層核對=(2, 1, not_yet_zero, 是, eventual_equality_universal_tail_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-eventual-equality · candidate
78. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality;資料={"settling_index":3,"n":2}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。
查看答案與解釋
(3, 2, not_yet_zero, 是, eventual_equality_universal_tail_certificate)
Wave4第四層核對=(3, 2, not_yet_zero, 是, eventual_equality_universal_tail_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-eventual-equality · candidate
79. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality;資料={"settling_index":4,"n":4}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。
查看答案與解釋
(4, 4, 0, 是, eventual_equality_universal_tail_certificate)
Wave4第四層核對=(4, 4, 0, 是, eventual_equality_universal_tail_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-eventual-equality · candidate
80. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality;資料={"settling_index":5,"n":5}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。
查看答案與解釋
(5, 5, 0, 是, eventual_equality_universal_tail_certificate)
Wave4第四層核對=(5, 5, 0, 是, eventual_equality_universal_tail_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-eventual-equality · candidate
81. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality;資料={"settling_index":6,"n":6}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。
查看答案與解釋
(6, 6, 0, 是, eventual_equality_universal_tail_certificate)
Wave4第四層核對=(6, 6, 0, 是, eventual_equality_universal_tail_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-eventual-equality · candidate
82. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality;資料={"settling_index":7,"n":8}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。
查看答案與解釋
(7, 8, 0, 是, eventual_equality_universal_tail_certificate)
Wave4第四層核對=(7, 8, 0, 是, eventual_equality_universal_tail_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-eventual-equality · candidate
83. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality;資料={"settling_index":8,"n":9}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。
查看答案與解釋
(8, 9, 0, 是, eventual_equality_universal_tail_certificate)
Wave4第四層核對=(8, 9, 0, 是, eventual_equality_universal_tail_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-eventual-equality · candidate
84. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality;資料={"settling_index":9,"n":10}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。
查看答案與解釋
(9, 10, 0, 是, eventual_equality_universal_tail_certificate)
Wave4第四層核對=(9, 10, 0, 是, eventual_equality_universal_tail_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-eventual-equality · candidate
85. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality;資料={"settling_index":10,"n":12}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。
查看答案與解釋
(10, 12, 0, 是, eventual_equality_universal_tail_certificate)
Wave4第四層核對=(10, 12, 0, 是, eventual_equality_universal_tail_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-eventual-equality · candidate
86. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality;資料={"settling_index":11,"n":13}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。
查看答案與解釋
(11, 13, 0, 是, eventual_equality_universal_tail_certificate)
Wave4第四層核對=(11, 13, 0, 是, eventual_equality_universal_tail_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-eventual-equality · candidate
87. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality;資料={"settling_index":12,"n":14}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。
查看答案與解釋
(12, 14, 0, 是, eventual_equality_universal_tail_certificate)
Wave4第四層核對=(12, 14, 0, 是, eventual_equality_universal_tail_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-eventual-equality · candidate
88. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality;資料={"settling_index":13,"n":16}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。
查看答案與解釋
(13, 16, 0, 是, eventual_equality_universal_tail_certificate)
Wave4第四層核對=(13, 16, 0, 是, eventual_equality_universal_tail_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-eventual-equality · candidate
89. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality;資料={"settling_index":14,"n":17}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。
查看答案與解釋
(14, 17, 0, 是, eventual_equality_universal_tail_certificate)
Wave4第四層核對=(14, 17, 0, 是, eventual_equality_universal_tail_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-eventual-equality · candidate
90. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality;資料={"settling_index":15,"n":18}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。
查看答案與解釋
(15, 18, 0, 是, eventual_equality_universal_tail_certificate)
Wave4第四層核對=(15, 18, 0, 是, eventual_equality_universal_tail_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-eventual-equality · candidate
91. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality;資料={"settling_index":16,"n":20}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。
查看答案與解釋
(16, 20, 0, 是, eventual_equality_universal_tail_certificate)
Wave4第四層核對=(16, 20, 0, 是, eventual_equality_universal_tail_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-eventual-equality · candidate
92. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality;資料={"settling_index":17,"n":21}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。
查看答案與解釋
(17, 21, 0, 是, eventual_equality_universal_tail_certificate)
Wave4第四層核對=(17, 21, 0, 是, eventual_equality_universal_tail_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-eventual-equality · candidate
93. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality;資料={"settling_index":18,"n":22}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。
查看答案與解釋
(18, 22, 0, 是, eventual_equality_universal_tail_certificate)
Wave4第四層核對=(18, 22, 0, 是, eventual_equality_universal_tail_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-eventual-equality · candidate
94. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality;資料={"settling_index":19,"n":24}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。
查看答案與解釋
(19, 24, 0, 是, eventual_equality_universal_tail_certificate)
Wave4第四層核對=(19, 24, 0, 是, eventual_equality_universal_tail_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-eventual-equality · candidate
95. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality;資料={"settling_index":20,"n":25}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。
查看答案與解釋
(20, 25, 0, 是, eventual_equality_universal_tail_certificate)
Wave4第四層核對=(20, 25, 0, 是, eventual_equality_universal_tail_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-eventual-equality · candidate
96. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality;資料={"settling_index":21,"n":26}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。
查看答案與解釋
(21, 26, 0, 是, eventual_equality_universal_tail_certificate)
Wave4第四層核對=(21, 26, 0, 是, eventual_equality_universal_tail_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-eventual-equality · candidate
97. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality;資料={"settling_index":22,"n":28}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。
查看答案與解釋
(22, 28, 0, 是, eventual_equality_universal_tail_certificate)
Wave4第四層核對=(22, 28, 0, 是, eventual_equality_universal_tail_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-eventual-equality · candidate
98. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality;資料={"settling_index":23,"n":29}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。
查看答案與解釋
(23, 29, 0, 是, eventual_equality_universal_tail_certificate)
Wave4第四層核對=(23, 29, 0, 是, eventual_equality_universal_tail_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-eventual-equality · candidate
99. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality;資料={"settling_index":24,"n":30}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。
查看答案與解釋
(24, 30, 0, 是, eventual_equality_universal_tail_certificate)
Wave4第四層核對=(24, 30, 0, 是, eventual_equality_universal_tail_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-eventual-equality · candidate
100. 依機率收斂
共同機率空間與forall epsilon tail責任。操作=convprob-eventual-equality;資料={"settling_index":25,"n":32}。請依 [settling_index,n,deviation_probability,converges,certificate] 欄序回答。
查看答案與解釋
(25, 32, 0, 是, eventual_equality_universal_tail_certificate)
Wave4第四層核對=(25, 32, 0, 是, eventual_equality_universal_tail_certificate);依完整明示資料重算;完整有限/symbolic tail證書不自動升格為未聲明的一般定理;finite prefix不足且只接受symbolic tail或eventual equality;不混同almost sure Lp或distribution convergence。
本題逐步詳解(AI 二次覆核)
依機率收斂 · qf-mod30-convprob-eventual-equality · candidate
原始題目 JSONL · 驗收報告