有限模型充分統計量基礎 · 脈衝 R05
本批已通過 Schema、去重、來源快照與獨立答案重算；仍未標記為人工審定。
本題庫已有對應的中英逐步詳解。原題的 candidate 與英文 ai_candidate 狀態保留；AI 覆核、有限計算與 Lean 形式證明分開標示。
batch-20261015-advance-20261116-r05-finite-sufficient-statistic-foundations · 2026-10-15 · 100 題
欄序為來源綁定的呈現補充；原始 JSONL 與數學答案不變。
欄序與來源綁定資料
1. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-fibers；資料={"theta_values":["a0","b0"],"samples":[0,1,2,3],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [samples, aligned_statistic, fibers, partition, certificate] 欄序回答。
查看答案與解釋
([0, 1, 2, 3], [0, 1, 0, 1], [[0, [0, 2]], [1, [1, 3]]], 是, total_statistic_fibers_partition_sample_space)
Wave6第十層核對=([0, 1, 2, 3], [0, 1, 0, 1], [[0, [0, 2]], [1, [1, 3]]], 是, total_statistic_fibers_partition_sample_space)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-fibers · candidate
2. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-fibers；資料={"theta_values":["a1","b1"],"samples":[10,11,12,13],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [samples, aligned_statistic, fibers, partition, certificate] 欄序回答。
查看答案與解釋
([10, 11, 12, 13], [0, 1, 0, 1], [[0, [10, 12]], [1, [11, 13]]], 是, total_statistic_fibers_partition_sample_space)
Wave6第十層核對=([10, 11, 12, 13], [0, 1, 0, 1], [[0, [10, 12]], [1, [11, 13]]], 是, total_statistic_fibers_partition_sample_space)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-fibers · candidate
3. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-fibers；資料={"theta_values":["a2","b2"],"samples":[20,21,22,23],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [samples, aligned_statistic, fibers, partition, certificate] 欄序回答。
查看答案與解釋
([20, 21, 22, 23], [0, 1, 0, 1], [[0, [20, 22]], [1, [21, 23]]], 是, total_statistic_fibers_partition_sample_space)
Wave6第十層核對=([20, 21, 22, 23], [0, 1, 0, 1], [[0, [20, 22]], [1, [21, 23]]], 是, total_statistic_fibers_partition_sample_space)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-fibers · candidate
4. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-fibers；資料={"theta_values":["a3","b3"],"samples":[30,31,32,33],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [samples, aligned_statistic, fibers, partition, certificate] 欄序回答。
查看答案與解釋
([30, 31, 32, 33], [0, 1, 0, 1], [[0, [30, 32]], [1, [31, 33]]], 是, total_statistic_fibers_partition_sample_space)
Wave6第十層核對=([30, 31, 32, 33], [0, 1, 0, 1], [[0, [30, 32]], [1, [31, 33]]], 是, total_statistic_fibers_partition_sample_space)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-fibers · candidate
5. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-fibers；資料={"theta_values":["a4","b4"],"samples":[40,41,42,43],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [samples, aligned_statistic, fibers, partition, certificate] 欄序回答。
查看答案與解釋
([40, 41, 42, 43], [0, 1, 0, 1], [[0, [40, 42]], [1, [41, 43]]], 是, total_statistic_fibers_partition_sample_space)
Wave6第十層核對=([40, 41, 42, 43], [0, 1, 0, 1], [[0, [40, 42]], [1, [41, 43]]], 是, total_statistic_fibers_partition_sample_space)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-fibers · candidate
6. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-fibers；資料={"theta_values":["a5","b5"],"samples":[50,51,52,53],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [samples, aligned_statistic, fibers, partition, certificate] 欄序回答。
查看答案與解釋
([50, 51, 52, 53], [0, 1, 0, 1], [[0, [50, 52]], [1, [51, 53]]], 是, total_statistic_fibers_partition_sample_space)
Wave6第十層核對=([50, 51, 52, 53], [0, 1, 0, 1], [[0, [50, 52]], [1, [51, 53]]], 是, total_statistic_fibers_partition_sample_space)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-fibers · candidate
7. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-fibers；資料={"theta_values":["a6","b6"],"samples":[60,61,62,63],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [samples, aligned_statistic, fibers, partition, certificate] 欄序回答。
查看答案與解釋
([60, 61, 62, 63], [0, 1, 0, 1], [[0, [60, 62]], [1, [61, 63]]], 是, total_statistic_fibers_partition_sample_space)
Wave6第十層核對=([60, 61, 62, 63], [0, 1, 0, 1], [[0, [60, 62]], [1, [61, 63]]], 是, total_statistic_fibers_partition_sample_space)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-fibers · candidate
8. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-fibers；資料={"theta_values":["a7","b7"],"samples":[70,71,72,73],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [samples, aligned_statistic, fibers, partition, certificate] 欄序回答。
查看答案與解釋
([70, 71, 72, 73], [0, 1, 0, 1], [[0, [70, 72]], [1, [71, 73]]], 是, total_statistic_fibers_partition_sample_space)
Wave6第十層核對=([70, 71, 72, 73], [0, 1, 0, 1], [[0, [70, 72]], [1, [71, 73]]], 是, total_statistic_fibers_partition_sample_space)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-fibers · candidate
9. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-fibers；資料={"theta_values":["a8","b8"],"samples":[80,81,82,83],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [samples, aligned_statistic, fibers, partition, certificate] 欄序回答。
查看答案與解釋
([80, 81, 82, 83], [0, 1, 0, 1], [[0, [80, 82]], [1, [81, 83]]], 是, total_statistic_fibers_partition_sample_space)
Wave6第十層核對=([80, 81, 82, 83], [0, 1, 0, 1], [[0, [80, 82]], [1, [81, 83]]], 是, total_statistic_fibers_partition_sample_space)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-fibers · candidate
10. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-fibers；資料={"theta_values":["a9","b9"],"samples":[90,91,92,93],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [samples, aligned_statistic, fibers, partition, certificate] 欄序回答。
查看答案與解釋
([90, 91, 92, 93], [0, 1, 0, 1], [[0, [90, 92]], [1, [91, 93]]], 是, total_statistic_fibers_partition_sample_space)
Wave6第十層核對=([90, 91, 92, 93], [0, 1, 0, 1], [[0, [90, 92]], [1, [91, 93]]], 是, total_statistic_fibers_partition_sample_space)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-fibers · candidate
11. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-fibers；資料={"theta_values":["a10","b10"],"samples":[100,101,102,103],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [samples, aligned_statistic, fibers, partition, certificate] 欄序回答。
查看答案與解釋
([100, 101, 102, 103], [0, 1, 0, 1], [[0, [100, 102]], [1, [101, 103]]], 是, total_statistic_fibers_partition_sample_space)
Wave6第十層核對=([100, 101, 102, 103], [0, 1, 0, 1], [[0, [100, 102]], [1, [101, 103]]], 是, total_statistic_fibers_partition_sample_space)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-fibers · candidate
12. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-fibers；資料={"theta_values":["a11","b11"],"samples":[110,111,112,113],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [samples, aligned_statistic, fibers, partition, certificate] 欄序回答。
查看答案與解釋
([110, 111, 112, 113], [0, 1, 0, 1], [[0, [110, 112]], [1, [111, 113]]], 是, total_statistic_fibers_partition_sample_space)
Wave6第十層核對=([110, 111, 112, 113], [0, 1, 0, 1], [[0, [110, 112]], [1, [111, 113]]], 是, total_statistic_fibers_partition_sample_space)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-fibers · candidate
13. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-fibers；資料={"theta_values":["a12","b12"],"samples":[120,121,122,123],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [samples, aligned_statistic, fibers, partition, certificate] 欄序回答。
查看答案與解釋
([120, 121, 122, 123], [0, 1, 0, 1], [[0, [120, 122]], [1, [121, 123]]], 是, total_statistic_fibers_partition_sample_space)
Wave6第十層核對=([120, 121, 122, 123], [0, 1, 0, 1], [[0, [120, 122]], [1, [121, 123]]], 是, total_statistic_fibers_partition_sample_space)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-fibers · candidate
14. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-fibers；資料={"theta_values":["a13","b13"],"samples":[130,131,132,133],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [samples, aligned_statistic, fibers, partition, certificate] 欄序回答。
查看答案與解釋
([130, 131, 132, 133], [0, 1, 0, 1], [[0, [130, 132]], [1, [131, 133]]], 是, total_statistic_fibers_partition_sample_space)
Wave6第十層核對=([130, 131, 132, 133], [0, 1, 0, 1], [[0, [130, 132]], [1, [131, 133]]], 是, total_statistic_fibers_partition_sample_space)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-fibers · candidate
15. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-fibers；資料={"theta_values":["a14","b14"],"samples":[140,141,142,143],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [samples, aligned_statistic, fibers, partition, certificate] 欄序回答。
查看答案與解釋
([140, 141, 142, 143], [0, 1, 0, 1], [[0, [140, 142]], [1, [141, 143]]], 是, total_statistic_fibers_partition_sample_space)
Wave6第十層核對=([140, 141, 142, 143], [0, 1, 0, 1], [[0, [140, 142]], [1, [141, 143]]], 是, total_statistic_fibers_partition_sample_space)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-fibers · candidate
16. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-fibers；資料={"theta_values":["a15","b15"],"samples":[150,151,152,153],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [samples, aligned_statistic, fibers, partition, certificate] 欄序回答。
查看答案與解釋
([150, 151, 152, 153], [0, 1, 0, 1], [[0, [150, 152]], [1, [151, 153]]], 是, total_statistic_fibers_partition_sample_space)
Wave6第十層核對=([150, 151, 152, 153], [0, 1, 0, 1], [[0, [150, 152]], [1, [151, 153]]], 是, total_statistic_fibers_partition_sample_space)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-fibers · candidate
17. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-fibers；資料={"theta_values":["a16","b16"],"samples":[160,161,162,163],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [samples, aligned_statistic, fibers, partition, certificate] 欄序回答。
查看答案與解釋
([160, 161, 162, 163], [0, 1, 0, 1], [[0, [160, 162]], [1, [161, 163]]], 是, total_statistic_fibers_partition_sample_space)
Wave6第十層核對=([160, 161, 162, 163], [0, 1, 0, 1], [[0, [160, 162]], [1, [161, 163]]], 是, total_statistic_fibers_partition_sample_space)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-fibers · candidate
18. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-fibers；資料={"theta_values":["a17","b17"],"samples":[170,171,172,173],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [samples, aligned_statistic, fibers, partition, certificate] 欄序回答。
查看答案與解釋
([170, 171, 172, 173], [0, 1, 0, 1], [[0, [170, 172]], [1, [171, 173]]], 是, total_statistic_fibers_partition_sample_space)
Wave6第十層核對=([170, 171, 172, 173], [0, 1, 0, 1], [[0, [170, 172]], [1, [171, 173]]], 是, total_statistic_fibers_partition_sample_space)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-fibers · candidate
19. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-fibers；資料={"theta_values":["a18","b18"],"samples":[180,181,182,183],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [samples, aligned_statistic, fibers, partition, certificate] 欄序回答。
查看答案與解釋
([180, 181, 182, 183], [0, 1, 0, 1], [[0, [180, 182]], [1, [181, 183]]], 是, total_statistic_fibers_partition_sample_space)
Wave6第十層核對=([180, 181, 182, 183], [0, 1, 0, 1], [[0, [180, 182]], [1, [181, 183]]], 是, total_statistic_fibers_partition_sample_space)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-fibers · candidate
20. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-fibers；資料={"theta_values":["a19","b19"],"samples":[190,191,192,193],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [samples, aligned_statistic, fibers, partition, certificate] 欄序回答。
查看答案與解釋
([190, 191, 192, 193], [0, 1, 0, 1], [[0, [190, 192]], [1, [191, 193]]], 是, total_statistic_fibers_partition_sample_space)
Wave6第十層核對=([190, 191, 192, 193], [0, 1, 0, 1], [[0, [190, 192]], [1, [191, 193]]], 是, total_statistic_fibers_partition_sample_space)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-fibers · candidate
21. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-fibers；資料={"theta_values":["a20","b20"],"samples":[200,201,202,203],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [samples, aligned_statistic, fibers, partition, certificate] 欄序回答。
查看答案與解釋
([200, 201, 202, 203], [0, 1, 0, 1], [[0, [200, 202]], [1, [201, 203]]], 是, total_statistic_fibers_partition_sample_space)
Wave6第十層核對=([200, 201, 202, 203], [0, 1, 0, 1], [[0, [200, 202]], [1, [201, 203]]], 是, total_statistic_fibers_partition_sample_space)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-fibers · candidate
22. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-fibers；資料={"theta_values":["a21","b21"],"samples":[210,211,212,213],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [samples, aligned_statistic, fibers, partition, certificate] 欄序回答。
查看答案與解釋
([210, 211, 212, 213], [0, 1, 0, 1], [[0, [210, 212]], [1, [211, 213]]], 是, total_statistic_fibers_partition_sample_space)
Wave6第十層核對=([210, 211, 212, 213], [0, 1, 0, 1], [[0, [210, 212]], [1, [211, 213]]], 是, total_statistic_fibers_partition_sample_space)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-fibers · candidate
23. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-fibers；資料={"theta_values":["a22","b22"],"samples":[220,221,222,223],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [samples, aligned_statistic, fibers, partition, certificate] 欄序回答。
查看答案與解釋
([220, 221, 222, 223], [0, 1, 0, 1], [[0, [220, 222]], [1, [221, 223]]], 是, total_statistic_fibers_partition_sample_space)
Wave6第十層核對=([220, 221, 222, 223], [0, 1, 0, 1], [[0, [220, 222]], [1, [221, 223]]], 是, total_statistic_fibers_partition_sample_space)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-fibers · candidate
24. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-fibers；資料={"theta_values":["a23","b23"],"samples":[230,231,232,233],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [samples, aligned_statistic, fibers, partition, certificate] 欄序回答。
查看答案與解釋
([230, 231, 232, 233], [0, 1, 0, 1], [[0, [230, 232]], [1, [231, 233]]], 是, total_statistic_fibers_partition_sample_space)
Wave6第十層核對=([230, 231, 232, 233], [0, 1, 0, 1], [[0, [230, 232]], [1, [231, 233]]], 是, total_statistic_fibers_partition_sample_space)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-fibers · candidate
25. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-fibers；資料={"theta_values":["a24","b24"],"samples":[240,241,242,243],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [samples, aligned_statistic, fibers, partition, certificate] 欄序回答。
查看答案與解釋
([240, 241, 242, 243], [0, 1, 0, 1], [[0, [240, 242]], [1, [241, 243]]], 是, total_statistic_fibers_partition_sample_space)
Wave6第十層核對=([240, 241, 242, 243], [0, 1, 0, 1], [[0, [240, 242]], [1, [241, 243]]], 是, total_statistic_fibers_partition_sample_space)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-fibers · candidate
26. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-conditional-table；資料={"theta_values":["a0","b0"],"samples":[0,1,2,3],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [conditional_cells, boundary] 欄序回答。
zero-mass cell的conditional law未定義，來源以null編碼，不是空表、零分布或可除以0的值。
查看答案與解釋
([[a0, 0, 4/5, [[0, 1/2], [2, 1/2]]], [a0, 1, 1/5, [[1, 1/2], [3, 1/2]]], [b0, 0, 1/5, [[0, 1/2], [2, 1/2]]], [b0, 1, 4/5, [[1, 1/2], [3, 1/2]]]], zero_mass_cells_remain_undefined)
Wave6第十層核對=([[a0, 0, 4/5, [[0, 1/2], [2, 1/2]]], [a0, 1, 1/5, [[1, 1/2], [3, 1/2]]], [b0, 0, 1/5, [[0, 1/2], [2, 1/2]]], [b0, 1, 4/5, [[1, 1/2], [3, 1/2]]]], zero_mass_cells_remain_undefined)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-conditional-table · candidate
27. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-conditional-table；資料={"theta_values":["a1","b1"],"samples":[10,11,12,13],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [conditional_cells, boundary] 欄序回答。
zero-mass cell的conditional law未定義，來源以null編碼，不是空表、零分布或可除以0的值。
查看答案與解釋
([[a1, 0, 4/5, [[10, 1/2], [12, 1/2]]], [a1, 1, 1/5, [[11, 1/2], [13, 1/2]]], [b1, 0, 1/5, [[10, 1/2], [12, 1/2]]], [b1, 1, 4/5, [[11, 1/2], [13, 1/2]]]], zero_mass_cells_remain_undefined)
Wave6第十層核對=([[a1, 0, 4/5, [[10, 1/2], [12, 1/2]]], [a1, 1, 1/5, [[11, 1/2], [13, 1/2]]], [b1, 0, 1/5, [[10, 1/2], [12, 1/2]]], [b1, 1, 4/5, [[11, 1/2], [13, 1/2]]]], zero_mass_cells_remain_undefined)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-conditional-table · candidate
28. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-conditional-table；資料={"theta_values":["a2","b2"],"samples":[20,21,22,23],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [conditional_cells, boundary] 欄序回答。
zero-mass cell的conditional law未定義，來源以null編碼，不是空表、零分布或可除以0的值。
查看答案與解釋
([[a2, 0, 4/5, [[20, 1/2], [22, 1/2]]], [a2, 1, 1/5, [[21, 1/2], [23, 1/2]]], [b2, 0, 1/5, [[20, 1/2], [22, 1/2]]], [b2, 1, 4/5, [[21, 1/2], [23, 1/2]]]], zero_mass_cells_remain_undefined)
Wave6第十層核對=([[a2, 0, 4/5, [[20, 1/2], [22, 1/2]]], [a2, 1, 1/5, [[21, 1/2], [23, 1/2]]], [b2, 0, 1/5, [[20, 1/2], [22, 1/2]]], [b2, 1, 4/5, [[21, 1/2], [23, 1/2]]]], zero_mass_cells_remain_undefined)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-conditional-table · candidate
29. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-conditional-table；資料={"theta_values":["a3","b3"],"samples":[30,31,32,33],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [conditional_cells, boundary] 欄序回答。
zero-mass cell的conditional law未定義，來源以null編碼，不是空表、零分布或可除以0的值。
查看答案與解釋
([[a3, 0, 4/5, [[30, 1/2], [32, 1/2]]], [a3, 1, 1/5, [[31, 1/2], [33, 1/2]]], [b3, 0, 1/5, [[30, 1/2], [32, 1/2]]], [b3, 1, 4/5, [[31, 1/2], [33, 1/2]]]], zero_mass_cells_remain_undefined)
Wave6第十層核對=([[a3, 0, 4/5, [[30, 1/2], [32, 1/2]]], [a3, 1, 1/5, [[31, 1/2], [33, 1/2]]], [b3, 0, 1/5, [[30, 1/2], [32, 1/2]]], [b3, 1, 4/5, [[31, 1/2], [33, 1/2]]]], zero_mass_cells_remain_undefined)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-conditional-table · candidate
30. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-conditional-table；資料={"theta_values":["a4","b4"],"samples":[40,41,42,43],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [conditional_cells, boundary] 欄序回答。
zero-mass cell的conditional law未定義，來源以null編碼，不是空表、零分布或可除以0的值。
查看答案與解釋
([[a4, 0, 4/5, [[40, 1/2], [42, 1/2]]], [a4, 1, 1/5, [[41, 1/2], [43, 1/2]]], [b4, 0, 1/5, [[40, 1/2], [42, 1/2]]], [b4, 1, 4/5, [[41, 1/2], [43, 1/2]]]], zero_mass_cells_remain_undefined)
Wave6第十層核對=([[a4, 0, 4/5, [[40, 1/2], [42, 1/2]]], [a4, 1, 1/5, [[41, 1/2], [43, 1/2]]], [b4, 0, 1/5, [[40, 1/2], [42, 1/2]]], [b4, 1, 4/5, [[41, 1/2], [43, 1/2]]]], zero_mass_cells_remain_undefined)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-conditional-table · candidate
31. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-conditional-table；資料={"theta_values":["a5","b5"],"samples":[50,51,52,53],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [conditional_cells, boundary] 欄序回答。
zero-mass cell的conditional law未定義，來源以null編碼，不是空表、零分布或可除以0的值。
查看答案與解釋
([[a5, 0, 4/5, [[50, 1/2], [52, 1/2]]], [a5, 1, 1/5, [[51, 1/2], [53, 1/2]]], [b5, 0, 1/5, [[50, 1/2], [52, 1/2]]], [b5, 1, 4/5, [[51, 1/2], [53, 1/2]]]], zero_mass_cells_remain_undefined)
Wave6第十層核對=([[a5, 0, 4/5, [[50, 1/2], [52, 1/2]]], [a5, 1, 1/5, [[51, 1/2], [53, 1/2]]], [b5, 0, 1/5, [[50, 1/2], [52, 1/2]]], [b5, 1, 4/5, [[51, 1/2], [53, 1/2]]]], zero_mass_cells_remain_undefined)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-conditional-table · candidate
32. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-conditional-table；資料={"theta_values":["a6","b6"],"samples":[60,61,62,63],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [conditional_cells, boundary] 欄序回答。
zero-mass cell的conditional law未定義，來源以null編碼，不是空表、零分布或可除以0的值。
查看答案與解釋
([[a6, 0, 4/5, [[60, 1/2], [62, 1/2]]], [a6, 1, 1/5, [[61, 1/2], [63, 1/2]]], [b6, 0, 1/5, [[60, 1/2], [62, 1/2]]], [b6, 1, 4/5, [[61, 1/2], [63, 1/2]]]], zero_mass_cells_remain_undefined)
Wave6第十層核對=([[a6, 0, 4/5, [[60, 1/2], [62, 1/2]]], [a6, 1, 1/5, [[61, 1/2], [63, 1/2]]], [b6, 0, 1/5, [[60, 1/2], [62, 1/2]]], [b6, 1, 4/5, [[61, 1/2], [63, 1/2]]]], zero_mass_cells_remain_undefined)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-conditional-table · candidate
33. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-conditional-table；資料={"theta_values":["a7","b7"],"samples":[70,71,72,73],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [conditional_cells, boundary] 欄序回答。
zero-mass cell的conditional law未定義，來源以null編碼，不是空表、零分布或可除以0的值。
查看答案與解釋
([[a7, 0, 4/5, [[70, 1/2], [72, 1/2]]], [a7, 1, 1/5, [[71, 1/2], [73, 1/2]]], [b7, 0, 1/5, [[70, 1/2], [72, 1/2]]], [b7, 1, 4/5, [[71, 1/2], [73, 1/2]]]], zero_mass_cells_remain_undefined)
Wave6第十層核對=([[a7, 0, 4/5, [[70, 1/2], [72, 1/2]]], [a7, 1, 1/5, [[71, 1/2], [73, 1/2]]], [b7, 0, 1/5, [[70, 1/2], [72, 1/2]]], [b7, 1, 4/5, [[71, 1/2], [73, 1/2]]]], zero_mass_cells_remain_undefined)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-conditional-table · candidate
34. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-conditional-table；資料={"theta_values":["a8","b8"],"samples":[80,81,82,83],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [conditional_cells, boundary] 欄序回答。
zero-mass cell的conditional law未定義，來源以null編碼，不是空表、零分布或可除以0的值。
查看答案與解釋
([[a8, 0, 4/5, [[80, 1/2], [82, 1/2]]], [a8, 1, 1/5, [[81, 1/2], [83, 1/2]]], [b8, 0, 1/5, [[80, 1/2], [82, 1/2]]], [b8, 1, 4/5, [[81, 1/2], [83, 1/2]]]], zero_mass_cells_remain_undefined)
Wave6第十層核對=([[a8, 0, 4/5, [[80, 1/2], [82, 1/2]]], [a8, 1, 1/5, [[81, 1/2], [83, 1/2]]], [b8, 0, 1/5, [[80, 1/2], [82, 1/2]]], [b8, 1, 4/5, [[81, 1/2], [83, 1/2]]]], zero_mass_cells_remain_undefined)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-conditional-table · candidate
35. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-conditional-table；資料={"theta_values":["a9","b9"],"samples":[90,91,92,93],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [conditional_cells, boundary] 欄序回答。
zero-mass cell的conditional law未定義，來源以null編碼，不是空表、零分布或可除以0的值。
查看答案與解釋
([[a9, 0, 4/5, [[90, 1/2], [92, 1/2]]], [a9, 1, 1/5, [[91, 1/2], [93, 1/2]]], [b9, 0, 1/5, [[90, 1/2], [92, 1/2]]], [b9, 1, 4/5, [[91, 1/2], [93, 1/2]]]], zero_mass_cells_remain_undefined)
Wave6第十層核對=([[a9, 0, 4/5, [[90, 1/2], [92, 1/2]]], [a9, 1, 1/5, [[91, 1/2], [93, 1/2]]], [b9, 0, 1/5, [[90, 1/2], [92, 1/2]]], [b9, 1, 4/5, [[91, 1/2], [93, 1/2]]]], zero_mass_cells_remain_undefined)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-conditional-table · candidate
36. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-conditional-table；資料={"theta_values":["a10","b10"],"samples":[100,101,102,103],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [conditional_cells, boundary] 欄序回答。
zero-mass cell的conditional law未定義，來源以null編碼，不是空表、零分布或可除以0的值。
查看答案與解釋
([[a10, 0, 4/5, [[100, 1/2], [102, 1/2]]], [a10, 1, 1/5, [[101, 1/2], [103, 1/2]]], [b10, 0, 1/5, [[100, 1/2], [102, 1/2]]], [b10, 1, 4/5, [[101, 1/2], [103, 1/2]]]], zero_mass_cells_remain_undefined)
Wave6第十層核對=([[a10, 0, 4/5, [[100, 1/2], [102, 1/2]]], [a10, 1, 1/5, [[101, 1/2], [103, 1/2]]], [b10, 0, 1/5, [[100, 1/2], [102, 1/2]]], [b10, 1, 4/5, [[101, 1/2], [103, 1/2]]]], zero_mass_cells_remain_undefined)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-conditional-table · candidate
37. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-conditional-table；資料={"theta_values":["a11","b11"],"samples":[110,111,112,113],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [conditional_cells, boundary] 欄序回答。
zero-mass cell的conditional law未定義，來源以null編碼，不是空表、零分布或可除以0的值。
查看答案與解釋
([[a11, 0, 4/5, [[110, 1/2], [112, 1/2]]], [a11, 1, 1/5, [[111, 1/2], [113, 1/2]]], [b11, 0, 1/5, [[110, 1/2], [112, 1/2]]], [b11, 1, 4/5, [[111, 1/2], [113, 1/2]]]], zero_mass_cells_remain_undefined)
Wave6第十層核對=([[a11, 0, 4/5, [[110, 1/2], [112, 1/2]]], [a11, 1, 1/5, [[111, 1/2], [113, 1/2]]], [b11, 0, 1/5, [[110, 1/2], [112, 1/2]]], [b11, 1, 4/5, [[111, 1/2], [113, 1/2]]]], zero_mass_cells_remain_undefined)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-conditional-table · candidate
38. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-conditional-table；資料={"theta_values":["a12","b12"],"samples":[120,121,122,123],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [conditional_cells, boundary] 欄序回答。
zero-mass cell的conditional law未定義，來源以null編碼，不是空表、零分布或可除以0的值。
查看答案與解釋
([[a12, 0, 4/5, [[120, 1/2], [122, 1/2]]], [a12, 1, 1/5, [[121, 1/2], [123, 1/2]]], [b12, 0, 1/5, [[120, 1/2], [122, 1/2]]], [b12, 1, 4/5, [[121, 1/2], [123, 1/2]]]], zero_mass_cells_remain_undefined)
Wave6第十層核對=([[a12, 0, 4/5, [[120, 1/2], [122, 1/2]]], [a12, 1, 1/5, [[121, 1/2], [123, 1/2]]], [b12, 0, 1/5, [[120, 1/2], [122, 1/2]]], [b12, 1, 4/5, [[121, 1/2], [123, 1/2]]]], zero_mass_cells_remain_undefined)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-conditional-table · candidate
39. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-conditional-table；資料={"theta_values":["a13","b13"],"samples":[130,131,132,133],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [conditional_cells, boundary] 欄序回答。
zero-mass cell的conditional law未定義，來源以null編碼，不是空表、零分布或可除以0的值。
查看答案與解釋
([[a13, 0, 4/5, [[130, 1/2], [132, 1/2]]], [a13, 1, 1/5, [[131, 1/2], [133, 1/2]]], [b13, 0, 1/5, [[130, 1/2], [132, 1/2]]], [b13, 1, 4/5, [[131, 1/2], [133, 1/2]]]], zero_mass_cells_remain_undefined)
Wave6第十層核對=([[a13, 0, 4/5, [[130, 1/2], [132, 1/2]]], [a13, 1, 1/5, [[131, 1/2], [133, 1/2]]], [b13, 0, 1/5, [[130, 1/2], [132, 1/2]]], [b13, 1, 4/5, [[131, 1/2], [133, 1/2]]]], zero_mass_cells_remain_undefined)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-conditional-table · candidate
40. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-conditional-table；資料={"theta_values":["a14","b14"],"samples":[140,141,142,143],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [conditional_cells, boundary] 欄序回答。
zero-mass cell的conditional law未定義，來源以null編碼，不是空表、零分布或可除以0的值。
查看答案與解釋
([[a14, 0, 4/5, [[140, 1/2], [142, 1/2]]], [a14, 1, 1/5, [[141, 1/2], [143, 1/2]]], [b14, 0, 1/5, [[140, 1/2], [142, 1/2]]], [b14, 1, 4/5, [[141, 1/2], [143, 1/2]]]], zero_mass_cells_remain_undefined)
Wave6第十層核對=([[a14, 0, 4/5, [[140, 1/2], [142, 1/2]]], [a14, 1, 1/5, [[141, 1/2], [143, 1/2]]], [b14, 0, 1/5, [[140, 1/2], [142, 1/2]]], [b14, 1, 4/5, [[141, 1/2], [143, 1/2]]]], zero_mass_cells_remain_undefined)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-conditional-table · candidate
41. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-conditional-table；資料={"theta_values":["a15","b15"],"samples":[150,151,152,153],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [conditional_cells, boundary] 欄序回答。
zero-mass cell的conditional law未定義，來源以null編碼，不是空表、零分布或可除以0的值。
查看答案與解釋
([[a15, 0, 4/5, [[150, 1/2], [152, 1/2]]], [a15, 1, 1/5, [[151, 1/2], [153, 1/2]]], [b15, 0, 1/5, [[150, 1/2], [152, 1/2]]], [b15, 1, 4/5, [[151, 1/2], [153, 1/2]]]], zero_mass_cells_remain_undefined)
Wave6第十層核對=([[a15, 0, 4/5, [[150, 1/2], [152, 1/2]]], [a15, 1, 1/5, [[151, 1/2], [153, 1/2]]], [b15, 0, 1/5, [[150, 1/2], [152, 1/2]]], [b15, 1, 4/5, [[151, 1/2], [153, 1/2]]]], zero_mass_cells_remain_undefined)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-conditional-table · candidate
42. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-conditional-table；資料={"theta_values":["a16","b16"],"samples":[160,161,162,163],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [conditional_cells, boundary] 欄序回答。
zero-mass cell的conditional law未定義，來源以null編碼，不是空表、零分布或可除以0的值。
查看答案與解釋
([[a16, 0, 4/5, [[160, 1/2], [162, 1/2]]], [a16, 1, 1/5, [[161, 1/2], [163, 1/2]]], [b16, 0, 1/5, [[160, 1/2], [162, 1/2]]], [b16, 1, 4/5, [[161, 1/2], [163, 1/2]]]], zero_mass_cells_remain_undefined)
Wave6第十層核對=([[a16, 0, 4/5, [[160, 1/2], [162, 1/2]]], [a16, 1, 1/5, [[161, 1/2], [163, 1/2]]], [b16, 0, 1/5, [[160, 1/2], [162, 1/2]]], [b16, 1, 4/5, [[161, 1/2], [163, 1/2]]]], zero_mass_cells_remain_undefined)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-conditional-table · candidate
43. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-conditional-table；資料={"theta_values":["a17","b17"],"samples":[170,171,172,173],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [conditional_cells, boundary] 欄序回答。
zero-mass cell的conditional law未定義，來源以null編碼，不是空表、零分布或可除以0的值。
查看答案與解釋
([[a17, 0, 4/5, [[170, 1/2], [172, 1/2]]], [a17, 1, 1/5, [[171, 1/2], [173, 1/2]]], [b17, 0, 1/5, [[170, 1/2], [172, 1/2]]], [b17, 1, 4/5, [[171, 1/2], [173, 1/2]]]], zero_mass_cells_remain_undefined)
Wave6第十層核對=([[a17, 0, 4/5, [[170, 1/2], [172, 1/2]]], [a17, 1, 1/5, [[171, 1/2], [173, 1/2]]], [b17, 0, 1/5, [[170, 1/2], [172, 1/2]]], [b17, 1, 4/5, [[171, 1/2], [173, 1/2]]]], zero_mass_cells_remain_undefined)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-conditional-table · candidate
44. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-conditional-table；資料={"theta_values":["a18","b18"],"samples":[180,181,182,183],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [conditional_cells, boundary] 欄序回答。
zero-mass cell的conditional law未定義，來源以null編碼，不是空表、零分布或可除以0的值。
查看答案與解釋
([[a18, 0, 4/5, [[180, 1/2], [182, 1/2]]], [a18, 1, 1/5, [[181, 1/2], [183, 1/2]]], [b18, 0, 1/5, [[180, 1/2], [182, 1/2]]], [b18, 1, 4/5, [[181, 1/2], [183, 1/2]]]], zero_mass_cells_remain_undefined)
Wave6第十層核對=([[a18, 0, 4/5, [[180, 1/2], [182, 1/2]]], [a18, 1, 1/5, [[181, 1/2], [183, 1/2]]], [b18, 0, 1/5, [[180, 1/2], [182, 1/2]]], [b18, 1, 4/5, [[181, 1/2], [183, 1/2]]]], zero_mass_cells_remain_undefined)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-conditional-table · candidate
45. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-conditional-table；資料={"theta_values":["a19","b19"],"samples":[190,191,192,193],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [conditional_cells, boundary] 欄序回答。
zero-mass cell的conditional law未定義，來源以null編碼，不是空表、零分布或可除以0的值。
查看答案與解釋
([[a19, 0, 4/5, [[190, 1/2], [192, 1/2]]], [a19, 1, 1/5, [[191, 1/2], [193, 1/2]]], [b19, 0, 1/5, [[190, 1/2], [192, 1/2]]], [b19, 1, 4/5, [[191, 1/2], [193, 1/2]]]], zero_mass_cells_remain_undefined)
Wave6第十層核對=([[a19, 0, 4/5, [[190, 1/2], [192, 1/2]]], [a19, 1, 1/5, [[191, 1/2], [193, 1/2]]], [b19, 0, 1/5, [[190, 1/2], [192, 1/2]]], [b19, 1, 4/5, [[191, 1/2], [193, 1/2]]]], zero_mass_cells_remain_undefined)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-conditional-table · candidate
46. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-conditional-table；資料={"theta_values":["a20","b20"],"samples":[200,201,202,203],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [conditional_cells, boundary] 欄序回答。
zero-mass cell的conditional law未定義，來源以null編碼，不是空表、零分布或可除以0的值。
查看答案與解釋
([[a20, 0, 4/5, [[200, 1/2], [202, 1/2]]], [a20, 1, 1/5, [[201, 1/2], [203, 1/2]]], [b20, 0, 1/5, [[200, 1/2], [202, 1/2]]], [b20, 1, 4/5, [[201, 1/2], [203, 1/2]]]], zero_mass_cells_remain_undefined)
Wave6第十層核對=([[a20, 0, 4/5, [[200, 1/2], [202, 1/2]]], [a20, 1, 1/5, [[201, 1/2], [203, 1/2]]], [b20, 0, 1/5, [[200, 1/2], [202, 1/2]]], [b20, 1, 4/5, [[201, 1/2], [203, 1/2]]]], zero_mass_cells_remain_undefined)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-conditional-table · candidate
47. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-conditional-table；資料={"theta_values":["a21","b21"],"samples":[210,211,212,213],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [conditional_cells, boundary] 欄序回答。
zero-mass cell的conditional law未定義，來源以null編碼，不是空表、零分布或可除以0的值。
查看答案與解釋
([[a21, 0, 4/5, [[210, 1/2], [212, 1/2]]], [a21, 1, 1/5, [[211, 1/2], [213, 1/2]]], [b21, 0, 1/5, [[210, 1/2], [212, 1/2]]], [b21, 1, 4/5, [[211, 1/2], [213, 1/2]]]], zero_mass_cells_remain_undefined)
Wave6第十層核對=([[a21, 0, 4/5, [[210, 1/2], [212, 1/2]]], [a21, 1, 1/5, [[211, 1/2], [213, 1/2]]], [b21, 0, 1/5, [[210, 1/2], [212, 1/2]]], [b21, 1, 4/5, [[211, 1/2], [213, 1/2]]]], zero_mass_cells_remain_undefined)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-conditional-table · candidate
48. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-conditional-table；資料={"theta_values":["a22","b22"],"samples":[220,221,222,223],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [conditional_cells, boundary] 欄序回答。
zero-mass cell的conditional law未定義，來源以null編碼，不是空表、零分布或可除以0的值。
查看答案與解釋
([[a22, 0, 4/5, [[220, 1/2], [222, 1/2]]], [a22, 1, 1/5, [[221, 1/2], [223, 1/2]]], [b22, 0, 1/5, [[220, 1/2], [222, 1/2]]], [b22, 1, 4/5, [[221, 1/2], [223, 1/2]]]], zero_mass_cells_remain_undefined)
Wave6第十層核對=([[a22, 0, 4/5, [[220, 1/2], [222, 1/2]]], [a22, 1, 1/5, [[221, 1/2], [223, 1/2]]], [b22, 0, 1/5, [[220, 1/2], [222, 1/2]]], [b22, 1, 4/5, [[221, 1/2], [223, 1/2]]]], zero_mass_cells_remain_undefined)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-conditional-table · candidate
49. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-conditional-table；資料={"theta_values":["a23","b23"],"samples":[230,231,232,233],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [conditional_cells, boundary] 欄序回答。
zero-mass cell的conditional law未定義，來源以null編碼，不是空表、零分布或可除以0的值。
查看答案與解釋
([[a23, 0, 4/5, [[230, 1/2], [232, 1/2]]], [a23, 1, 1/5, [[231, 1/2], [233, 1/2]]], [b23, 0, 1/5, [[230, 1/2], [232, 1/2]]], [b23, 1, 4/5, [[231, 1/2], [233, 1/2]]]], zero_mass_cells_remain_undefined)
Wave6第十層核對=([[a23, 0, 4/5, [[230, 1/2], [232, 1/2]]], [a23, 1, 1/5, [[231, 1/2], [233, 1/2]]], [b23, 0, 1/5, [[230, 1/2], [232, 1/2]]], [b23, 1, 4/5, [[231, 1/2], [233, 1/2]]]], zero_mass_cells_remain_undefined)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-conditional-table · candidate
50. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-conditional-table；資料={"theta_values":["a24","b24"],"samples":[240,241,242,243],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [conditional_cells, boundary] 欄序回答。
zero-mass cell的conditional law未定義，來源以null編碼，不是空表、零分布或可除以0的值。
查看答案與解釋
([[a24, 0, 4/5, [[240, 1/2], [242, 1/2]]], [a24, 1, 1/5, [[241, 1/2], [243, 1/2]]], [b24, 0, 1/5, [[240, 1/2], [242, 1/2]]], [b24, 1, 4/5, [[241, 1/2], [243, 1/2]]]], zero_mass_cells_remain_undefined)
Wave6第十層核對=([[a24, 0, 4/5, [[240, 1/2], [242, 1/2]]], [a24, 1, 1/5, [[241, 1/2], [243, 1/2]]], [b24, 0, 1/5, [[240, 1/2], [242, 1/2]]], [b24, 1, 4/5, [[241, 1/2], [243, 1/2]]]], zero_mass_cells_remain_undefined)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-conditional-table · candidate
51. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-invariance；資料={"theta_values":["a0","b0"],"samples":[0,1,2,3],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [fiber_invariance_rows, sufficient, certificate] 欄序回答。
查看答案與解釋
([[0, [[a0, [[0, 1/2], [2, 1/2]]], [b0, [[0, 1/2], [2, 1/2]]]], 是], [1, [[a0, [[1, 1/2], [3, 1/2]]], [b0, [[1, 1/2], [3, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)
Wave6第十層核對=([[0, [[a0, [[0, 1/2], [2, 1/2]]], [b0, [[0, 1/2], [2, 1/2]]]], 是], [1, [[a0, [[1, 1/2], [3, 1/2]]], [b0, [[1, 1/2], [3, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-invariance · candidate
52. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-invariance；資料={"theta_values":["a1","b1"],"samples":[10,11,12,13],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [fiber_invariance_rows, sufficient, certificate] 欄序回答。
查看答案與解釋
([[0, [[a1, [[10, 1/2], [12, 1/2]]], [b1, [[10, 1/2], [12, 1/2]]]], 是], [1, [[a1, [[11, 1/2], [13, 1/2]]], [b1, [[11, 1/2], [13, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)
Wave6第十層核對=([[0, [[a1, [[10, 1/2], [12, 1/2]]], [b1, [[10, 1/2], [12, 1/2]]]], 是], [1, [[a1, [[11, 1/2], [13, 1/2]]], [b1, [[11, 1/2], [13, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-invariance · candidate
53. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-invariance；資料={"theta_values":["a2","b2"],"samples":[20,21,22,23],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [fiber_invariance_rows, sufficient, certificate] 欄序回答。
查看答案與解釋
([[0, [[a2, [[20, 1/2], [22, 1/2]]], [b2, [[20, 1/2], [22, 1/2]]]], 是], [1, [[a2, [[21, 1/2], [23, 1/2]]], [b2, [[21, 1/2], [23, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)
Wave6第十層核對=([[0, [[a2, [[20, 1/2], [22, 1/2]]], [b2, [[20, 1/2], [22, 1/2]]]], 是], [1, [[a2, [[21, 1/2], [23, 1/2]]], [b2, [[21, 1/2], [23, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-invariance · candidate
54. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-invariance；資料={"theta_values":["a3","b3"],"samples":[30,31,32,33],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [fiber_invariance_rows, sufficient, certificate] 欄序回答。
查看答案與解釋
([[0, [[a3, [[30, 1/2], [32, 1/2]]], [b3, [[30, 1/2], [32, 1/2]]]], 是], [1, [[a3, [[31, 1/2], [33, 1/2]]], [b3, [[31, 1/2], [33, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)
Wave6第十層核對=([[0, [[a3, [[30, 1/2], [32, 1/2]]], [b3, [[30, 1/2], [32, 1/2]]]], 是], [1, [[a3, [[31, 1/2], [33, 1/2]]], [b3, [[31, 1/2], [33, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-invariance · candidate
55. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-invariance；資料={"theta_values":["a4","b4"],"samples":[40,41,42,43],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [fiber_invariance_rows, sufficient, certificate] 欄序回答。
查看答案與解釋
([[0, [[a4, [[40, 1/2], [42, 1/2]]], [b4, [[40, 1/2], [42, 1/2]]]], 是], [1, [[a4, [[41, 1/2], [43, 1/2]]], [b4, [[41, 1/2], [43, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)
Wave6第十層核對=([[0, [[a4, [[40, 1/2], [42, 1/2]]], [b4, [[40, 1/2], [42, 1/2]]]], 是], [1, [[a4, [[41, 1/2], [43, 1/2]]], [b4, [[41, 1/2], [43, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-invariance · candidate
56. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-invariance；資料={"theta_values":["a5","b5"],"samples":[50,51,52,53],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [fiber_invariance_rows, sufficient, certificate] 欄序回答。
查看答案與解釋
([[0, [[a5, [[50, 1/2], [52, 1/2]]], [b5, [[50, 1/2], [52, 1/2]]]], 是], [1, [[a5, [[51, 1/2], [53, 1/2]]], [b5, [[51, 1/2], [53, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)
Wave6第十層核對=([[0, [[a5, [[50, 1/2], [52, 1/2]]], [b5, [[50, 1/2], [52, 1/2]]]], 是], [1, [[a5, [[51, 1/2], [53, 1/2]]], [b5, [[51, 1/2], [53, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-invariance · candidate
57. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-invariance；資料={"theta_values":["a6","b6"],"samples":[60,61,62,63],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [fiber_invariance_rows, sufficient, certificate] 欄序回答。
查看答案與解釋
([[0, [[a6, [[60, 1/2], [62, 1/2]]], [b6, [[60, 1/2], [62, 1/2]]]], 是], [1, [[a6, [[61, 1/2], [63, 1/2]]], [b6, [[61, 1/2], [63, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)
Wave6第十層核對=([[0, [[a6, [[60, 1/2], [62, 1/2]]], [b6, [[60, 1/2], [62, 1/2]]]], 是], [1, [[a6, [[61, 1/2], [63, 1/2]]], [b6, [[61, 1/2], [63, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-invariance · candidate
58. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-invariance；資料={"theta_values":["a7","b7"],"samples":[70,71,72,73],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [fiber_invariance_rows, sufficient, certificate] 欄序回答。
查看答案與解釋
([[0, [[a7, [[70, 1/2], [72, 1/2]]], [b7, [[70, 1/2], [72, 1/2]]]], 是], [1, [[a7, [[71, 1/2], [73, 1/2]]], [b7, [[71, 1/2], [73, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)
Wave6第十層核對=([[0, [[a7, [[70, 1/2], [72, 1/2]]], [b7, [[70, 1/2], [72, 1/2]]]], 是], [1, [[a7, [[71, 1/2], [73, 1/2]]], [b7, [[71, 1/2], [73, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-invariance · candidate
59. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-invariance；資料={"theta_values":["a8","b8"],"samples":[80,81,82,83],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [fiber_invariance_rows, sufficient, certificate] 欄序回答。
查看答案與解釋
([[0, [[a8, [[80, 1/2], [82, 1/2]]], [b8, [[80, 1/2], [82, 1/2]]]], 是], [1, [[a8, [[81, 1/2], [83, 1/2]]], [b8, [[81, 1/2], [83, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)
Wave6第十層核對=([[0, [[a8, [[80, 1/2], [82, 1/2]]], [b8, [[80, 1/2], [82, 1/2]]]], 是], [1, [[a8, [[81, 1/2], [83, 1/2]]], [b8, [[81, 1/2], [83, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-invariance · candidate
60. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-invariance；資料={"theta_values":["a9","b9"],"samples":[90,91,92,93],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [fiber_invariance_rows, sufficient, certificate] 欄序回答。
查看答案與解釋
([[0, [[a9, [[90, 1/2], [92, 1/2]]], [b9, [[90, 1/2], [92, 1/2]]]], 是], [1, [[a9, [[91, 1/2], [93, 1/2]]], [b9, [[91, 1/2], [93, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)
Wave6第十層核對=([[0, [[a9, [[90, 1/2], [92, 1/2]]], [b9, [[90, 1/2], [92, 1/2]]]], 是], [1, [[a9, [[91, 1/2], [93, 1/2]]], [b9, [[91, 1/2], [93, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-invariance · candidate
61. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-invariance；資料={"theta_values":["a10","b10"],"samples":[100,101,102,103],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [fiber_invariance_rows, sufficient, certificate] 欄序回答。
查看答案與解釋
([[0, [[a10, [[100, 1/2], [102, 1/2]]], [b10, [[100, 1/2], [102, 1/2]]]], 是], [1, [[a10, [[101, 1/2], [103, 1/2]]], [b10, [[101, 1/2], [103, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)
Wave6第十層核對=([[0, [[a10, [[100, 1/2], [102, 1/2]]], [b10, [[100, 1/2], [102, 1/2]]]], 是], [1, [[a10, [[101, 1/2], [103, 1/2]]], [b10, [[101, 1/2], [103, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-invariance · candidate
62. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-invariance；資料={"theta_values":["a11","b11"],"samples":[110,111,112,113],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [fiber_invariance_rows, sufficient, certificate] 欄序回答。
查看答案與解釋
([[0, [[a11, [[110, 1/2], [112, 1/2]]], [b11, [[110, 1/2], [112, 1/2]]]], 是], [1, [[a11, [[111, 1/2], [113, 1/2]]], [b11, [[111, 1/2], [113, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)
Wave6第十層核對=([[0, [[a11, [[110, 1/2], [112, 1/2]]], [b11, [[110, 1/2], [112, 1/2]]]], 是], [1, [[a11, [[111, 1/2], [113, 1/2]]], [b11, [[111, 1/2], [113, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-invariance · candidate
63. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-invariance；資料={"theta_values":["a12","b12"],"samples":[120,121,122,123],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [fiber_invariance_rows, sufficient, certificate] 欄序回答。
查看答案與解釋
([[0, [[a12, [[120, 1/2], [122, 1/2]]], [b12, [[120, 1/2], [122, 1/2]]]], 是], [1, [[a12, [[121, 1/2], [123, 1/2]]], [b12, [[121, 1/2], [123, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)
Wave6第十層核對=([[0, [[a12, [[120, 1/2], [122, 1/2]]], [b12, [[120, 1/2], [122, 1/2]]]], 是], [1, [[a12, [[121, 1/2], [123, 1/2]]], [b12, [[121, 1/2], [123, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-invariance · candidate
64. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-invariance；資料={"theta_values":["a13","b13"],"samples":[130,131,132,133],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [fiber_invariance_rows, sufficient, certificate] 欄序回答。
查看答案與解釋
([[0, [[a13, [[130, 1/2], [132, 1/2]]], [b13, [[130, 1/2], [132, 1/2]]]], 是], [1, [[a13, [[131, 1/2], [133, 1/2]]], [b13, [[131, 1/2], [133, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)
Wave6第十層核對=([[0, [[a13, [[130, 1/2], [132, 1/2]]], [b13, [[130, 1/2], [132, 1/2]]]], 是], [1, [[a13, [[131, 1/2], [133, 1/2]]], [b13, [[131, 1/2], [133, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-invariance · candidate
65. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-invariance；資料={"theta_values":["a14","b14"],"samples":[140,141,142,143],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [fiber_invariance_rows, sufficient, certificate] 欄序回答。
查看答案與解釋
([[0, [[a14, [[140, 1/2], [142, 1/2]]], [b14, [[140, 1/2], [142, 1/2]]]], 是], [1, [[a14, [[141, 1/2], [143, 1/2]]], [b14, [[141, 1/2], [143, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)
Wave6第十層核對=([[0, [[a14, [[140, 1/2], [142, 1/2]]], [b14, [[140, 1/2], [142, 1/2]]]], 是], [1, [[a14, [[141, 1/2], [143, 1/2]]], [b14, [[141, 1/2], [143, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-invariance · candidate
66. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-invariance；資料={"theta_values":["a15","b15"],"samples":[150,151,152,153],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [fiber_invariance_rows, sufficient, certificate] 欄序回答。
查看答案與解釋
([[0, [[a15, [[150, 1/2], [152, 1/2]]], [b15, [[150, 1/2], [152, 1/2]]]], 是], [1, [[a15, [[151, 1/2], [153, 1/2]]], [b15, [[151, 1/2], [153, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)
Wave6第十層核對=([[0, [[a15, [[150, 1/2], [152, 1/2]]], [b15, [[150, 1/2], [152, 1/2]]]], 是], [1, [[a15, [[151, 1/2], [153, 1/2]]], [b15, [[151, 1/2], [153, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-invariance · candidate
67. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-invariance；資料={"theta_values":["a16","b16"],"samples":[160,161,162,163],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [fiber_invariance_rows, sufficient, certificate] 欄序回答。
查看答案與解釋
([[0, [[a16, [[160, 1/2], [162, 1/2]]], [b16, [[160, 1/2], [162, 1/2]]]], 是], [1, [[a16, [[161, 1/2], [163, 1/2]]], [b16, [[161, 1/2], [163, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)
Wave6第十層核對=([[0, [[a16, [[160, 1/2], [162, 1/2]]], [b16, [[160, 1/2], [162, 1/2]]]], 是], [1, [[a16, [[161, 1/2], [163, 1/2]]], [b16, [[161, 1/2], [163, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-invariance · candidate
68. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-invariance；資料={"theta_values":["a17","b17"],"samples":[170,171,172,173],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [fiber_invariance_rows, sufficient, certificate] 欄序回答。
查看答案與解釋
([[0, [[a17, [[170, 1/2], [172, 1/2]]], [b17, [[170, 1/2], [172, 1/2]]]], 是], [1, [[a17, [[171, 1/2], [173, 1/2]]], [b17, [[171, 1/2], [173, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)
Wave6第十層核對=([[0, [[a17, [[170, 1/2], [172, 1/2]]], [b17, [[170, 1/2], [172, 1/2]]]], 是], [1, [[a17, [[171, 1/2], [173, 1/2]]], [b17, [[171, 1/2], [173, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-invariance · candidate
69. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-invariance；資料={"theta_values":["a18","b18"],"samples":[180,181,182,183],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [fiber_invariance_rows, sufficient, certificate] 欄序回答。
查看答案與解釋
([[0, [[a18, [[180, 1/2], [182, 1/2]]], [b18, [[180, 1/2], [182, 1/2]]]], 是], [1, [[a18, [[181, 1/2], [183, 1/2]]], [b18, [[181, 1/2], [183, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)
Wave6第十層核對=([[0, [[a18, [[180, 1/2], [182, 1/2]]], [b18, [[180, 1/2], [182, 1/2]]]], 是], [1, [[a18, [[181, 1/2], [183, 1/2]]], [b18, [[181, 1/2], [183, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-invariance · candidate
70. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-invariance；資料={"theta_values":["a19","b19"],"samples":[190,191,192,193],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [fiber_invariance_rows, sufficient, certificate] 欄序回答。
查看答案與解釋
([[0, [[a19, [[190, 1/2], [192, 1/2]]], [b19, [[190, 1/2], [192, 1/2]]]], 是], [1, [[a19, [[191, 1/2], [193, 1/2]]], [b19, [[191, 1/2], [193, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)
Wave6第十層核對=([[0, [[a19, [[190, 1/2], [192, 1/2]]], [b19, [[190, 1/2], [192, 1/2]]]], 是], [1, [[a19, [[191, 1/2], [193, 1/2]]], [b19, [[191, 1/2], [193, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-invariance · candidate
71. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-invariance；資料={"theta_values":["a20","b20"],"samples":[200,201,202,203],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [fiber_invariance_rows, sufficient, certificate] 欄序回答。
查看答案與解釋
([[0, [[a20, [[200, 1/2], [202, 1/2]]], [b20, [[200, 1/2], [202, 1/2]]]], 是], [1, [[a20, [[201, 1/2], [203, 1/2]]], [b20, [[201, 1/2], [203, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)
Wave6第十層核對=([[0, [[a20, [[200, 1/2], [202, 1/2]]], [b20, [[200, 1/2], [202, 1/2]]]], 是], [1, [[a20, [[201, 1/2], [203, 1/2]]], [b20, [[201, 1/2], [203, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-invariance · candidate
72. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-invariance；資料={"theta_values":["a21","b21"],"samples":[210,211,212,213],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [fiber_invariance_rows, sufficient, certificate] 欄序回答。
查看答案與解釋
([[0, [[a21, [[210, 1/2], [212, 1/2]]], [b21, [[210, 1/2], [212, 1/2]]]], 是], [1, [[a21, [[211, 1/2], [213, 1/2]]], [b21, [[211, 1/2], [213, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)
Wave6第十層核對=([[0, [[a21, [[210, 1/2], [212, 1/2]]], [b21, [[210, 1/2], [212, 1/2]]]], 是], [1, [[a21, [[211, 1/2], [213, 1/2]]], [b21, [[211, 1/2], [213, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-invariance · candidate
73. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-invariance；資料={"theta_values":["a22","b22"],"samples":[220,221,222,223],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [fiber_invariance_rows, sufficient, certificate] 欄序回答。
查看答案與解釋
([[0, [[a22, [[220, 1/2], [222, 1/2]]], [b22, [[220, 1/2], [222, 1/2]]]], 是], [1, [[a22, [[221, 1/2], [223, 1/2]]], [b22, [[221, 1/2], [223, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)
Wave6第十層核對=([[0, [[a22, [[220, 1/2], [222, 1/2]]], [b22, [[220, 1/2], [222, 1/2]]]], 是], [1, [[a22, [[221, 1/2], [223, 1/2]]], [b22, [[221, 1/2], [223, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-invariance · candidate
74. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-invariance；資料={"theta_values":["a23","b23"],"samples":[230,231,232,233],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [fiber_invariance_rows, sufficient, certificate] 欄序回答。
查看答案與解釋
([[0, [[a23, [[230, 1/2], [232, 1/2]]], [b23, [[230, 1/2], [232, 1/2]]]], 是], [1, [[a23, [[231, 1/2], [233, 1/2]]], [b23, [[231, 1/2], [233, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)
Wave6第十層核對=([[0, [[a23, [[230, 1/2], [232, 1/2]]], [b23, [[230, 1/2], [232, 1/2]]]], 是], [1, [[a23, [[231, 1/2], [233, 1/2]]], [b23, [[231, 1/2], [233, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-invariance · candidate
75. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-invariance；資料={"theta_values":["a24","b24"],"samples":[240,241,242,243],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [fiber_invariance_rows, sufficient, certificate] 欄序回答。
查看答案與解釋
([[0, [[a24, [[240, 1/2], [242, 1/2]]], [b24, [[240, 1/2], [242, 1/2]]]], 是], [1, [[a24, [[241, 1/2], [243, 1/2]]], [b24, [[241, 1/2], [243, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)
Wave6第十層核對=([[0, [[a24, [[240, 1/2], [242, 1/2]]], [b24, [[240, 1/2], [242, 1/2]]]], 是], [1, [[a24, [[241, 1/2], [243, 1/2]]], [b24, [[241, 1/2], [243, 1/2]]]], 是]], 是, conditional_law_must_be_theta_independent_on_every_positive_mass_cell)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-invariance · candidate
76. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-nonsufficient-zero-boundary；資料={"mode":"nonsufficient","theta_values":["a0","b0"],"samples":[0,1,2,3],"probability_rows":[[[3,5],[1,10],[1,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [mode, fiber_invariance_rows, sufficient, zero_mass_cells, nonsufficiency_witness_or_null, injective_statistic, constant_statistic, theta_laws_equal, constant_equivalence_if_applicable, factorization_or_quality_claim, boundary] 欄序回答。
只比較每個fiber正質量theta；零質量cell保持null。constant_equivalence_if_applicable只在constant mode驗充分性與laws_equal的等價，其餘mode是來源保留的true，不是新定理。
查看答案與解釋
(nonsufficient, [[0, [[a0, [[0, 3/4], [2, 1/4]]], [b0, [[0, 1/2], [2, 1/2]]]], 否], [1, [[a0, [[1, 1/2], [3, 1/2]]], [b0, [[1, 1/2], [3, 1/2]]]], 是]], 否, [], [0, [[a0, [[0, 3/4], [2, 1/4]]], [b0, [[0, 1/2], [2, 1/2]]]], 否], 否, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)
Wave6第十層核對=(nonsufficient, [[0, [[a0, [[0, 3/4], [2, 1/4]]], [b0, [[0, 1/2], [2, 1/2]]]], 否], [1, [[a0, [[1, 1/2], [3, 1/2]]], [b0, [[1, 1/2], [3, 1/2]]]], 是]], 否, [], [0, [[a0, [[0, 3/4], [2, 1/4]]], [b0, [[0, 1/2], [2, 1/2]]]], 否], 否, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-nonsufficient-zero-boundary · candidate
77. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-nonsufficient-zero-boundary；資料={"mode":"zero_mass","theta_values":["a1","b1"],"samples":[10,11,12,13],"probability_rows":[[[1,2],0,[1,2],0],[0,[1,2],0,[1,2]]],"statistic":[0,1,0,1]}。請依 [mode, fiber_invariance_rows, sufficient, zero_mass_cells, nonsufficiency_witness_or_null, injective_statistic, constant_statistic, theta_laws_equal, constant_equivalence_if_applicable, factorization_or_quality_claim, boundary] 欄序回答。
只比較每個fiber正質量theta；零質量cell保持null。constant_equivalence_if_applicable只在constant mode驗充分性與laws_equal的等價，其餘mode是來源保留的true，不是新定理。
查看答案與解釋
(zero_mass, [[0, [[a1, [[10, 1/2], [12, 1/2]]]], 是], [1, [[b1, [[11, 1/2], [13, 1/2]]]], 是]], 是, [[a1, 1, 0, null], [b1, 0, 0, null]], null, 否, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)
Wave6第十層核對=(zero_mass, [[0, [[a1, [[10, 1/2], [12, 1/2]]]], 是], [1, [[b1, [[11, 1/2], [13, 1/2]]]], 是]], 是, [[a1, 1, 0, null], [b1, 0, 0, null]], null, 否, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-nonsufficient-zero-boundary · candidate
78. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-nonsufficient-zero-boundary；資料={"mode":"identity","theta_values":["a2","b2"],"samples":[20,21,22,23],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,2,3]}。請依 [mode, fiber_invariance_rows, sufficient, zero_mass_cells, nonsufficiency_witness_or_null, injective_statistic, constant_statistic, theta_laws_equal, constant_equivalence_if_applicable, factorization_or_quality_claim, boundary] 欄序回答。
只比較每個fiber正質量theta；零質量cell保持null。constant_equivalence_if_applicable只在constant mode驗充分性與laws_equal的等價，其餘mode是來源保留的true，不是新定理。
查看答案與解釋
(identity, [[0, [[a2, [[20, 1]]], [b2, [[20, 1]]]], 是], [1, [[a2, [[21, 1]]], [b2, [[21, 1]]]], 是], [2, [[a2, [[22, 1]]], [b2, [[22, 1]]]], 是], [3, [[a2, [[23, 1]]], [b2, [[23, 1]]]], 是]], 是, [], null, 是, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)
Wave6第十層核對=(identity, [[0, [[a2, [[20, 1]]], [b2, [[20, 1]]]], 是], [1, [[a2, [[21, 1]]], [b2, [[21, 1]]]], 是], [2, [[a2, [[22, 1]]], [b2, [[22, 1]]]], 是], [3, [[a2, [[23, 1]]], [b2, [[23, 1]]]], 是]], 是, [], null, 是, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-nonsufficient-zero-boundary · candidate
79. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-nonsufficient-zero-boundary；資料={"mode":"constant","theta_values":["a3","b3"],"samples":[30,31,32,33],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,0,0,0]}。請依 [mode, fiber_invariance_rows, sufficient, zero_mass_cells, nonsufficiency_witness_or_null, injective_statistic, constant_statistic, theta_laws_equal, constant_equivalence_if_applicable, factorization_or_quality_claim, boundary] 欄序回答。
只比較每個fiber正質量theta；零質量cell保持null。constant_equivalence_if_applicable只在constant mode驗充分性與laws_equal的等價，其餘mode是來源保留的true，不是新定理。
查看答案與解釋
(constant, [[0, [[a3, [[30, 2/5], [31, 1/10], [32, 2/5], [33, 1/10]]], [b3, [[30, 1/10], [31, 2/5], [32, 1/10], [33, 2/5]]]], 否]], 否, [], null, 否, 是, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)
Wave6第十層核對=(constant, [[0, [[a3, [[30, 2/5], [31, 1/10], [32, 2/5], [33, 1/10]]], [b3, [[30, 1/10], [31, 2/5], [32, 1/10], [33, 2/5]]]], 否]], 否, [], null, 否, 是, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-nonsufficient-zero-boundary · candidate
80. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-nonsufficient-zero-boundary；資料={"mode":"nonsufficient","theta_values":["a4","b4"],"samples":[40,41,42,43],"probability_rows":[[[3,5],[1,10],[1,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [mode, fiber_invariance_rows, sufficient, zero_mass_cells, nonsufficiency_witness_or_null, injective_statistic, constant_statistic, theta_laws_equal, constant_equivalence_if_applicable, factorization_or_quality_claim, boundary] 欄序回答。
只比較每個fiber正質量theta；零質量cell保持null。constant_equivalence_if_applicable只在constant mode驗充分性與laws_equal的等價，其餘mode是來源保留的true，不是新定理。
查看答案與解釋
(nonsufficient, [[0, [[a4, [[40, 3/4], [42, 1/4]]], [b4, [[40, 1/2], [42, 1/2]]]], 否], [1, [[a4, [[41, 1/2], [43, 1/2]]], [b4, [[41, 1/2], [43, 1/2]]]], 是]], 否, [], [0, [[a4, [[40, 3/4], [42, 1/4]]], [b4, [[40, 1/2], [42, 1/2]]]], 否], 否, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)
Wave6第十層核對=(nonsufficient, [[0, [[a4, [[40, 3/4], [42, 1/4]]], [b4, [[40, 1/2], [42, 1/2]]]], 否], [1, [[a4, [[41, 1/2], [43, 1/2]]], [b4, [[41, 1/2], [43, 1/2]]]], 是]], 否, [], [0, [[a4, [[40, 3/4], [42, 1/4]]], [b4, [[40, 1/2], [42, 1/2]]]], 否], 否, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-nonsufficient-zero-boundary · candidate
81. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-nonsufficient-zero-boundary；資料={"mode":"zero_mass","theta_values":["a5","b5"],"samples":[50,51,52,53],"probability_rows":[[[1,2],0,[1,2],0],[0,[1,2],0,[1,2]]],"statistic":[0,1,0,1]}。請依 [mode, fiber_invariance_rows, sufficient, zero_mass_cells, nonsufficiency_witness_or_null, injective_statistic, constant_statistic, theta_laws_equal, constant_equivalence_if_applicable, factorization_or_quality_claim, boundary] 欄序回答。
只比較每個fiber正質量theta；零質量cell保持null。constant_equivalence_if_applicable只在constant mode驗充分性與laws_equal的等價，其餘mode是來源保留的true，不是新定理。
查看答案與解釋
(zero_mass, [[0, [[a5, [[50, 1/2], [52, 1/2]]]], 是], [1, [[b5, [[51, 1/2], [53, 1/2]]]], 是]], 是, [[a5, 1, 0, null], [b5, 0, 0, null]], null, 否, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)
Wave6第十層核對=(zero_mass, [[0, [[a5, [[50, 1/2], [52, 1/2]]]], 是], [1, [[b5, [[51, 1/2], [53, 1/2]]]], 是]], 是, [[a5, 1, 0, null], [b5, 0, 0, null]], null, 否, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-nonsufficient-zero-boundary · candidate
82. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-nonsufficient-zero-boundary；資料={"mode":"identity","theta_values":["a6","b6"],"samples":[60,61,62,63],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,2,3]}。請依 [mode, fiber_invariance_rows, sufficient, zero_mass_cells, nonsufficiency_witness_or_null, injective_statistic, constant_statistic, theta_laws_equal, constant_equivalence_if_applicable, factorization_or_quality_claim, boundary] 欄序回答。
只比較每個fiber正質量theta；零質量cell保持null。constant_equivalence_if_applicable只在constant mode驗充分性與laws_equal的等價，其餘mode是來源保留的true，不是新定理。
查看答案與解釋
(identity, [[0, [[a6, [[60, 1]]], [b6, [[60, 1]]]], 是], [1, [[a6, [[61, 1]]], [b6, [[61, 1]]]], 是], [2, [[a6, [[62, 1]]], [b6, [[62, 1]]]], 是], [3, [[a6, [[63, 1]]], [b6, [[63, 1]]]], 是]], 是, [], null, 是, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)
Wave6第十層核對=(identity, [[0, [[a6, [[60, 1]]], [b6, [[60, 1]]]], 是], [1, [[a6, [[61, 1]]], [b6, [[61, 1]]]], 是], [2, [[a6, [[62, 1]]], [b6, [[62, 1]]]], 是], [3, [[a6, [[63, 1]]], [b6, [[63, 1]]]], 是]], 是, [], null, 是, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-nonsufficient-zero-boundary · candidate
83. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-nonsufficient-zero-boundary；資料={"mode":"constant","theta_values":["a7","b7"],"samples":[70,71,72,73],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,0,0,0]}。請依 [mode, fiber_invariance_rows, sufficient, zero_mass_cells, nonsufficiency_witness_or_null, injective_statistic, constant_statistic, theta_laws_equal, constant_equivalence_if_applicable, factorization_or_quality_claim, boundary] 欄序回答。
只比較每個fiber正質量theta；零質量cell保持null。constant_equivalence_if_applicable只在constant mode驗充分性與laws_equal的等價，其餘mode是來源保留的true，不是新定理。
查看答案與解釋
(constant, [[0, [[a7, [[70, 2/5], [71, 1/10], [72, 2/5], [73, 1/10]]], [b7, [[70, 1/10], [71, 2/5], [72, 1/10], [73, 2/5]]]], 否]], 否, [], null, 否, 是, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)
Wave6第十層核對=(constant, [[0, [[a7, [[70, 2/5], [71, 1/10], [72, 2/5], [73, 1/10]]], [b7, [[70, 1/10], [71, 2/5], [72, 1/10], [73, 2/5]]]], 否]], 否, [], null, 否, 是, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-nonsufficient-zero-boundary · candidate
84. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-nonsufficient-zero-boundary；資料={"mode":"nonsufficient","theta_values":["a8","b8"],"samples":[80,81,82,83],"probability_rows":[[[3,5],[1,10],[1,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [mode, fiber_invariance_rows, sufficient, zero_mass_cells, nonsufficiency_witness_or_null, injective_statistic, constant_statistic, theta_laws_equal, constant_equivalence_if_applicable, factorization_or_quality_claim, boundary] 欄序回答。
只比較每個fiber正質量theta；零質量cell保持null。constant_equivalence_if_applicable只在constant mode驗充分性與laws_equal的等價，其餘mode是來源保留的true，不是新定理。
查看答案與解釋
(nonsufficient, [[0, [[a8, [[80, 3/4], [82, 1/4]]], [b8, [[80, 1/2], [82, 1/2]]]], 否], [1, [[a8, [[81, 1/2], [83, 1/2]]], [b8, [[81, 1/2], [83, 1/2]]]], 是]], 否, [], [0, [[a8, [[80, 3/4], [82, 1/4]]], [b8, [[80, 1/2], [82, 1/2]]]], 否], 否, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)
Wave6第十層核對=(nonsufficient, [[0, [[a8, [[80, 3/4], [82, 1/4]]], [b8, [[80, 1/2], [82, 1/2]]]], 否], [1, [[a8, [[81, 1/2], [83, 1/2]]], [b8, [[81, 1/2], [83, 1/2]]]], 是]], 否, [], [0, [[a8, [[80, 3/4], [82, 1/4]]], [b8, [[80, 1/2], [82, 1/2]]]], 否], 否, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-nonsufficient-zero-boundary · candidate
85. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-nonsufficient-zero-boundary；資料={"mode":"zero_mass","theta_values":["a9","b9"],"samples":[90,91,92,93],"probability_rows":[[[1,2],0,[1,2],0],[0,[1,2],0,[1,2]]],"statistic":[0,1,0,1]}。請依 [mode, fiber_invariance_rows, sufficient, zero_mass_cells, nonsufficiency_witness_or_null, injective_statistic, constant_statistic, theta_laws_equal, constant_equivalence_if_applicable, factorization_or_quality_claim, boundary] 欄序回答。
只比較每個fiber正質量theta；零質量cell保持null。constant_equivalence_if_applicable只在constant mode驗充分性與laws_equal的等價，其餘mode是來源保留的true，不是新定理。
查看答案與解釋
(zero_mass, [[0, [[a9, [[90, 1/2], [92, 1/2]]]], 是], [1, [[b9, [[91, 1/2], [93, 1/2]]]], 是]], 是, [[a9, 1, 0, null], [b9, 0, 0, null]], null, 否, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)
Wave6第十層核對=(zero_mass, [[0, [[a9, [[90, 1/2], [92, 1/2]]]], 是], [1, [[b9, [[91, 1/2], [93, 1/2]]]], 是]], 是, [[a9, 1, 0, null], [b9, 0, 0, null]], null, 否, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-nonsufficient-zero-boundary · candidate
86. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-nonsufficient-zero-boundary；資料={"mode":"identity","theta_values":["a10","b10"],"samples":[100,101,102,103],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,2,3]}。請依 [mode, fiber_invariance_rows, sufficient, zero_mass_cells, nonsufficiency_witness_or_null, injective_statistic, constant_statistic, theta_laws_equal, constant_equivalence_if_applicable, factorization_or_quality_claim, boundary] 欄序回答。
只比較每個fiber正質量theta；零質量cell保持null。constant_equivalence_if_applicable只在constant mode驗充分性與laws_equal的等價，其餘mode是來源保留的true，不是新定理。
查看答案與解釋
(identity, [[0, [[a10, [[100, 1]]], [b10, [[100, 1]]]], 是], [1, [[a10, [[101, 1]]], [b10, [[101, 1]]]], 是], [2, [[a10, [[102, 1]]], [b10, [[102, 1]]]], 是], [3, [[a10, [[103, 1]]], [b10, [[103, 1]]]], 是]], 是, [], null, 是, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)
Wave6第十層核對=(identity, [[0, [[a10, [[100, 1]]], [b10, [[100, 1]]]], 是], [1, [[a10, [[101, 1]]], [b10, [[101, 1]]]], 是], [2, [[a10, [[102, 1]]], [b10, [[102, 1]]]], 是], [3, [[a10, [[103, 1]]], [b10, [[103, 1]]]], 是]], 是, [], null, 是, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-nonsufficient-zero-boundary · candidate
87. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-nonsufficient-zero-boundary；資料={"mode":"constant","theta_values":["a11","b11"],"samples":[110,111,112,113],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,0,0,0]}。請依 [mode, fiber_invariance_rows, sufficient, zero_mass_cells, nonsufficiency_witness_or_null, injective_statistic, constant_statistic, theta_laws_equal, constant_equivalence_if_applicable, factorization_or_quality_claim, boundary] 欄序回答。
只比較每個fiber正質量theta；零質量cell保持null。constant_equivalence_if_applicable只在constant mode驗充分性與laws_equal的等價，其餘mode是來源保留的true，不是新定理。
查看答案與解釋
(constant, [[0, [[a11, [[110, 2/5], [111, 1/10], [112, 2/5], [113, 1/10]]], [b11, [[110, 1/10], [111, 2/5], [112, 1/10], [113, 2/5]]]], 否]], 否, [], null, 否, 是, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)
Wave6第十層核對=(constant, [[0, [[a11, [[110, 2/5], [111, 1/10], [112, 2/5], [113, 1/10]]], [b11, [[110, 1/10], [111, 2/5], [112, 1/10], [113, 2/5]]]], 否]], 否, [], null, 否, 是, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-nonsufficient-zero-boundary · candidate
88. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-nonsufficient-zero-boundary；資料={"mode":"nonsufficient","theta_values":["a12","b12"],"samples":[120,121,122,123],"probability_rows":[[[3,5],[1,10],[1,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [mode, fiber_invariance_rows, sufficient, zero_mass_cells, nonsufficiency_witness_or_null, injective_statistic, constant_statistic, theta_laws_equal, constant_equivalence_if_applicable, factorization_or_quality_claim, boundary] 欄序回答。
只比較每個fiber正質量theta；零質量cell保持null。constant_equivalence_if_applicable只在constant mode驗充分性與laws_equal的等價，其餘mode是來源保留的true，不是新定理。
查看答案與解釋
(nonsufficient, [[0, [[a12, [[120, 3/4], [122, 1/4]]], [b12, [[120, 1/2], [122, 1/2]]]], 否], [1, [[a12, [[121, 1/2], [123, 1/2]]], [b12, [[121, 1/2], [123, 1/2]]]], 是]], 否, [], [0, [[a12, [[120, 3/4], [122, 1/4]]], [b12, [[120, 1/2], [122, 1/2]]]], 否], 否, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)
Wave6第十層核對=(nonsufficient, [[0, [[a12, [[120, 3/4], [122, 1/4]]], [b12, [[120, 1/2], [122, 1/2]]]], 否], [1, [[a12, [[121, 1/2], [123, 1/2]]], [b12, [[121, 1/2], [123, 1/2]]]], 是]], 否, [], [0, [[a12, [[120, 3/4], [122, 1/4]]], [b12, [[120, 1/2], [122, 1/2]]]], 否], 否, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-nonsufficient-zero-boundary · candidate
89. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-nonsufficient-zero-boundary；資料={"mode":"zero_mass","theta_values":["a13","b13"],"samples":[130,131,132,133],"probability_rows":[[[1,2],0,[1,2],0],[0,[1,2],0,[1,2]]],"statistic":[0,1,0,1]}。請依 [mode, fiber_invariance_rows, sufficient, zero_mass_cells, nonsufficiency_witness_or_null, injective_statistic, constant_statistic, theta_laws_equal, constant_equivalence_if_applicable, factorization_or_quality_claim, boundary] 欄序回答。
只比較每個fiber正質量theta；零質量cell保持null。constant_equivalence_if_applicable只在constant mode驗充分性與laws_equal的等價，其餘mode是來源保留的true，不是新定理。
查看答案與解釋
(zero_mass, [[0, [[a13, [[130, 1/2], [132, 1/2]]]], 是], [1, [[b13, [[131, 1/2], [133, 1/2]]]], 是]], 是, [[a13, 1, 0, null], [b13, 0, 0, null]], null, 否, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)
Wave6第十層核對=(zero_mass, [[0, [[a13, [[130, 1/2], [132, 1/2]]]], 是], [1, [[b13, [[131, 1/2], [133, 1/2]]]], 是]], 是, [[a13, 1, 0, null], [b13, 0, 0, null]], null, 否, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-nonsufficient-zero-boundary · candidate
90. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-nonsufficient-zero-boundary；資料={"mode":"identity","theta_values":["a14","b14"],"samples":[140,141,142,143],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,2,3]}。請依 [mode, fiber_invariance_rows, sufficient, zero_mass_cells, nonsufficiency_witness_or_null, injective_statistic, constant_statistic, theta_laws_equal, constant_equivalence_if_applicable, factorization_or_quality_claim, boundary] 欄序回答。
只比較每個fiber正質量theta；零質量cell保持null。constant_equivalence_if_applicable只在constant mode驗充分性與laws_equal的等價，其餘mode是來源保留的true，不是新定理。
查看答案與解釋
(identity, [[0, [[a14, [[140, 1]]], [b14, [[140, 1]]]], 是], [1, [[a14, [[141, 1]]], [b14, [[141, 1]]]], 是], [2, [[a14, [[142, 1]]], [b14, [[142, 1]]]], 是], [3, [[a14, [[143, 1]]], [b14, [[143, 1]]]], 是]], 是, [], null, 是, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)
Wave6第十層核對=(identity, [[0, [[a14, [[140, 1]]], [b14, [[140, 1]]]], 是], [1, [[a14, [[141, 1]]], [b14, [[141, 1]]]], 是], [2, [[a14, [[142, 1]]], [b14, [[142, 1]]]], 是], [3, [[a14, [[143, 1]]], [b14, [[143, 1]]]], 是]], 是, [], null, 是, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-nonsufficient-zero-boundary · candidate
91. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-nonsufficient-zero-boundary；資料={"mode":"constant","theta_values":["a15","b15"],"samples":[150,151,152,153],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,0,0,0]}。請依 [mode, fiber_invariance_rows, sufficient, zero_mass_cells, nonsufficiency_witness_or_null, injective_statistic, constant_statistic, theta_laws_equal, constant_equivalence_if_applicable, factorization_or_quality_claim, boundary] 欄序回答。
只比較每個fiber正質量theta；零質量cell保持null。constant_equivalence_if_applicable只在constant mode驗充分性與laws_equal的等價，其餘mode是來源保留的true，不是新定理。
查看答案與解釋
(constant, [[0, [[a15, [[150, 2/5], [151, 1/10], [152, 2/5], [153, 1/10]]], [b15, [[150, 1/10], [151, 2/5], [152, 1/10], [153, 2/5]]]], 否]], 否, [], null, 否, 是, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)
Wave6第十層核對=(constant, [[0, [[a15, [[150, 2/5], [151, 1/10], [152, 2/5], [153, 1/10]]], [b15, [[150, 1/10], [151, 2/5], [152, 1/10], [153, 2/5]]]], 否]], 否, [], null, 否, 是, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-nonsufficient-zero-boundary · candidate
92. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-nonsufficient-zero-boundary；資料={"mode":"nonsufficient","theta_values":["a16","b16"],"samples":[160,161,162,163],"probability_rows":[[[3,5],[1,10],[1,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [mode, fiber_invariance_rows, sufficient, zero_mass_cells, nonsufficiency_witness_or_null, injective_statistic, constant_statistic, theta_laws_equal, constant_equivalence_if_applicable, factorization_or_quality_claim, boundary] 欄序回答。
只比較每個fiber正質量theta；零質量cell保持null。constant_equivalence_if_applicable只在constant mode驗充分性與laws_equal的等價，其餘mode是來源保留的true，不是新定理。
查看答案與解釋
(nonsufficient, [[0, [[a16, [[160, 3/4], [162, 1/4]]], [b16, [[160, 1/2], [162, 1/2]]]], 否], [1, [[a16, [[161, 1/2], [163, 1/2]]], [b16, [[161, 1/2], [163, 1/2]]]], 是]], 否, [], [0, [[a16, [[160, 3/4], [162, 1/4]]], [b16, [[160, 1/2], [162, 1/2]]]], 否], 否, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)
Wave6第十層核對=(nonsufficient, [[0, [[a16, [[160, 3/4], [162, 1/4]]], [b16, [[160, 1/2], [162, 1/2]]]], 否], [1, [[a16, [[161, 1/2], [163, 1/2]]], [b16, [[161, 1/2], [163, 1/2]]]], 是]], 否, [], [0, [[a16, [[160, 3/4], [162, 1/4]]], [b16, [[160, 1/2], [162, 1/2]]]], 否], 否, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-nonsufficient-zero-boundary · candidate
93. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-nonsufficient-zero-boundary；資料={"mode":"zero_mass","theta_values":["a17","b17"],"samples":[170,171,172,173],"probability_rows":[[[1,2],0,[1,2],0],[0,[1,2],0,[1,2]]],"statistic":[0,1,0,1]}。請依 [mode, fiber_invariance_rows, sufficient, zero_mass_cells, nonsufficiency_witness_or_null, injective_statistic, constant_statistic, theta_laws_equal, constant_equivalence_if_applicable, factorization_or_quality_claim, boundary] 欄序回答。
只比較每個fiber正質量theta；零質量cell保持null。constant_equivalence_if_applicable只在constant mode驗充分性與laws_equal的等價，其餘mode是來源保留的true，不是新定理。
查看答案與解釋
(zero_mass, [[0, [[a17, [[170, 1/2], [172, 1/2]]]], 是], [1, [[b17, [[171, 1/2], [173, 1/2]]]], 是]], 是, [[a17, 1, 0, null], [b17, 0, 0, null]], null, 否, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)
Wave6第十層核對=(zero_mass, [[0, [[a17, [[170, 1/2], [172, 1/2]]]], 是], [1, [[b17, [[171, 1/2], [173, 1/2]]]], 是]], 是, [[a17, 1, 0, null], [b17, 0, 0, null]], null, 否, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-nonsufficient-zero-boundary · candidate
94. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-nonsufficient-zero-boundary；資料={"mode":"identity","theta_values":["a18","b18"],"samples":[180,181,182,183],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,2,3]}。請依 [mode, fiber_invariance_rows, sufficient, zero_mass_cells, nonsufficiency_witness_or_null, injective_statistic, constant_statistic, theta_laws_equal, constant_equivalence_if_applicable, factorization_or_quality_claim, boundary] 欄序回答。
只比較每個fiber正質量theta；零質量cell保持null。constant_equivalence_if_applicable只在constant mode驗充分性與laws_equal的等價，其餘mode是來源保留的true，不是新定理。
查看答案與解釋
(identity, [[0, [[a18, [[180, 1]]], [b18, [[180, 1]]]], 是], [1, [[a18, [[181, 1]]], [b18, [[181, 1]]]], 是], [2, [[a18, [[182, 1]]], [b18, [[182, 1]]]], 是], [3, [[a18, [[183, 1]]], [b18, [[183, 1]]]], 是]], 是, [], null, 是, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)
Wave6第十層核對=(identity, [[0, [[a18, [[180, 1]]], [b18, [[180, 1]]]], 是], [1, [[a18, [[181, 1]]], [b18, [[181, 1]]]], 是], [2, [[a18, [[182, 1]]], [b18, [[182, 1]]]], 是], [3, [[a18, [[183, 1]]], [b18, [[183, 1]]]], 是]], 是, [], null, 是, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-nonsufficient-zero-boundary · candidate
95. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-nonsufficient-zero-boundary；資料={"mode":"constant","theta_values":["a19","b19"],"samples":[190,191,192,193],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,0,0,0]}。請依 [mode, fiber_invariance_rows, sufficient, zero_mass_cells, nonsufficiency_witness_or_null, injective_statistic, constant_statistic, theta_laws_equal, constant_equivalence_if_applicable, factorization_or_quality_claim, boundary] 欄序回答。
只比較每個fiber正質量theta；零質量cell保持null。constant_equivalence_if_applicable只在constant mode驗充分性與laws_equal的等價，其餘mode是來源保留的true，不是新定理。
查看答案與解釋
(constant, [[0, [[a19, [[190, 2/5], [191, 1/10], [192, 2/5], [193, 1/10]]], [b19, [[190, 1/10], [191, 2/5], [192, 1/10], [193, 2/5]]]], 否]], 否, [], null, 否, 是, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)
Wave6第十層核對=(constant, [[0, [[a19, [[190, 2/5], [191, 1/10], [192, 2/5], [193, 1/10]]], [b19, [[190, 1/10], [191, 2/5], [192, 1/10], [193, 2/5]]]], 否]], 否, [], null, 否, 是, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-nonsufficient-zero-boundary · candidate
96. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-nonsufficient-zero-boundary；資料={"mode":"nonsufficient","theta_values":["a20","b20"],"samples":[200,201,202,203],"probability_rows":[[[3,5],[1,10],[1,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [mode, fiber_invariance_rows, sufficient, zero_mass_cells, nonsufficiency_witness_or_null, injective_statistic, constant_statistic, theta_laws_equal, constant_equivalence_if_applicable, factorization_or_quality_claim, boundary] 欄序回答。
只比較每個fiber正質量theta；零質量cell保持null。constant_equivalence_if_applicable只在constant mode驗充分性與laws_equal的等價，其餘mode是來源保留的true，不是新定理。
查看答案與解釋
(nonsufficient, [[0, [[a20, [[200, 3/4], [202, 1/4]]], [b20, [[200, 1/2], [202, 1/2]]]], 否], [1, [[a20, [[201, 1/2], [203, 1/2]]], [b20, [[201, 1/2], [203, 1/2]]]], 是]], 否, [], [0, [[a20, [[200, 3/4], [202, 1/4]]], [b20, [[200, 1/2], [202, 1/2]]]], 否], 否, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)
Wave6第十層核對=(nonsufficient, [[0, [[a20, [[200, 3/4], [202, 1/4]]], [b20, [[200, 1/2], [202, 1/2]]]], 否], [1, [[a20, [[201, 1/2], [203, 1/2]]], [b20, [[201, 1/2], [203, 1/2]]]], 是]], 否, [], [0, [[a20, [[200, 3/4], [202, 1/4]]], [b20, [[200, 1/2], [202, 1/2]]]], 否], 否, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-nonsufficient-zero-boundary · candidate
97. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-nonsufficient-zero-boundary；資料={"mode":"zero_mass","theta_values":["a21","b21"],"samples":[210,211,212,213],"probability_rows":[[[1,2],0,[1,2],0],[0,[1,2],0,[1,2]]],"statistic":[0,1,0,1]}。請依 [mode, fiber_invariance_rows, sufficient, zero_mass_cells, nonsufficiency_witness_or_null, injective_statistic, constant_statistic, theta_laws_equal, constant_equivalence_if_applicable, factorization_or_quality_claim, boundary] 欄序回答。
只比較每個fiber正質量theta；零質量cell保持null。constant_equivalence_if_applicable只在constant mode驗充分性與laws_equal的等價，其餘mode是來源保留的true，不是新定理。
查看答案與解釋
(zero_mass, [[0, [[a21, [[210, 1/2], [212, 1/2]]]], 是], [1, [[b21, [[211, 1/2], [213, 1/2]]]], 是]], 是, [[a21, 1, 0, null], [b21, 0, 0, null]], null, 否, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)
Wave6第十層核對=(zero_mass, [[0, [[a21, [[210, 1/2], [212, 1/2]]]], 是], [1, [[b21, [[211, 1/2], [213, 1/2]]]], 是]], 是, [[a21, 1, 0, null], [b21, 0, 0, null]], null, 否, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-nonsufficient-zero-boundary · candidate
98. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-nonsufficient-zero-boundary；資料={"mode":"identity","theta_values":["a22","b22"],"samples":[220,221,222,223],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,2,3]}。請依 [mode, fiber_invariance_rows, sufficient, zero_mass_cells, nonsufficiency_witness_or_null, injective_statistic, constant_statistic, theta_laws_equal, constant_equivalence_if_applicable, factorization_or_quality_claim, boundary] 欄序回答。
只比較每個fiber正質量theta；零質量cell保持null。constant_equivalence_if_applicable只在constant mode驗充分性與laws_equal的等價，其餘mode是來源保留的true，不是新定理。
查看答案與解釋
(identity, [[0, [[a22, [[220, 1]]], [b22, [[220, 1]]]], 是], [1, [[a22, [[221, 1]]], [b22, [[221, 1]]]], 是], [2, [[a22, [[222, 1]]], [b22, [[222, 1]]]], 是], [3, [[a22, [[223, 1]]], [b22, [[223, 1]]]], 是]], 是, [], null, 是, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)
Wave6第十層核對=(identity, [[0, [[a22, [[220, 1]]], [b22, [[220, 1]]]], 是], [1, [[a22, [[221, 1]]], [b22, [[221, 1]]]], 是], [2, [[a22, [[222, 1]]], [b22, [[222, 1]]]], 是], [3, [[a22, [[223, 1]]], [b22, [[223, 1]]]], 是]], 是, [], null, 是, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-nonsufficient-zero-boundary · candidate
99. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-nonsufficient-zero-boundary；資料={"mode":"constant","theta_values":["a23","b23"],"samples":[230,231,232,233],"probability_rows":[[[2,5],[1,10],[2,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,0,0,0]}。請依 [mode, fiber_invariance_rows, sufficient, zero_mass_cells, nonsufficiency_witness_or_null, injective_statistic, constant_statistic, theta_laws_equal, constant_equivalence_if_applicable, factorization_or_quality_claim, boundary] 欄序回答。
只比較每個fiber正質量theta；零質量cell保持null。constant_equivalence_if_applicable只在constant mode驗充分性與laws_equal的等價，其餘mode是來源保留的true，不是新定理。
查看答案與解釋
(constant, [[0, [[a23, [[230, 2/5], [231, 1/10], [232, 2/5], [233, 1/10]]], [b23, [[230, 1/10], [231, 2/5], [232, 1/10], [233, 2/5]]]], 否]], 否, [], null, 否, 是, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)
Wave6第十層核對=(constant, [[0, [[a23, [[230, 2/5], [231, 1/10], [232, 2/5], [233, 1/10]]], [b23, [[230, 1/10], [231, 2/5], [232, 1/10], [233, 2/5]]]], 否]], 否, [], null, 否, 是, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
本題逐步詳解（AI 二次覆核）
有限模型充分統計量 · qf-mod47-suff-nonsufficient-zero-boundary · candidate
100. 有限模型充分統計量
total statistic fibers與正質量conditional laws的完整theta-invariance責任。操作=suff-nonsufficient-zero-boundary；資料={"mode":"nonsufficient","theta_values":["a24","b24"],"samples":[240,241,242,243],"probability_rows":[[[3,5],[1,10],[1,5],[1,10]],[[1,10],[2,5],[1,10],[2,5]]],"statistic":[0,1,0,1]}。請依 [mode, fiber_invariance_rows, sufficient, zero_mass_cells, nonsufficiency_witness_or_null, injective_statistic, constant_statistic, theta_laws_equal, constant_equivalence_if_applicable, factorization_or_quality_claim, boundary] 欄序回答。
只比較每個fiber正質量theta；零質量cell保持null。constant_equivalence_if_applicable只在constant mode驗充分性與laws_equal的等價，其餘mode是來源保留的true，不是新定理。
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(nonsufficient, [[0, [[a24, [[240, 3/4], [242, 1/4]]], [b24, [[240, 1/2], [242, 1/2]]]], 否], [1, [[a24, [[241, 1/2], [243, 1/2]]], [b24, [[241, 1/2], [243, 1/2]]]], 是]], 否, [], [0, [[a24, [[240, 3/4], [242, 1/4]]], [b24, [[240, 1/2], [242, 1/2]]]], 否], 否, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)
Wave6第十層核對=(nonsufficient, [[0, [[a24, [[240, 3/4], [242, 1/4]]], [b24, [[240, 1/2], [242, 1/2]]]], 否], [1, [[a24, [[241, 1/2], [243, 1/2]]], [b24, [[241, 1/2], [243, 1/2]]]], 是]], 否, [], [0, [[a24, [[240, 3/4], [242, 1/4]]], [b24, [[240, 1/2], [242, 1/2]]]], 否], 否, 否, 否, 是, 否, identity_is_sufficient_constant_is_sufficient_exactly_when_theta_laws_match_no_factorization_or_estimator_quality_claim)；依完整明示資料獨立重算；zero-mass conditional保持undefined，nonsufficient需明示witness；identity/constant boundaries分開且不使用factorization theorem或宣稱估計品質。
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有限模型充分統計量 · qf-mod47-suff-nonsufficient-zero-boundary · candidate
原始題目 JSONL · 驗收報告